Answer:
Vf=Vi
Explanation:
when speed is constant final velocoty is equal to initial velocity
A foam square has a mass of 62 g and a volume of 72 cm'. What is the density?
True or False?
There are equal numbers of protons and electrons in neutral atoms.
Brianna is rowing a small boat across a pond. The air is calm; there is no wind
blowing.
a. What type of friction is resisting her motion?
b. If two friends join her in the boat, will the friction force change? Why or why not?
PLEASE I NEEEED HEEEEEEEEEEEELP.
An air bubble of volume 20 cm³ is at the bottom of a lake 40 m deep, where the temperature is 4.0°c. the bubble rises to the surface, which is at a temperature of 20°c. take the temperature of the bubble’s air to be the same as that of the surrounding water. just as the bubble reaches the surface
A. Fluid Friction B. Yes, there is more mass on the boat.
Explanation:
Not very sure about B but goodluck.
WASSCE
11. An incident ray is reflected normally by a
plane mirror onto a screen where it forms
a bright spot. The mirror and the screen
are parallel and 1 m apart. If the mirror is
rotated through 5°, calculate the
displacement of the spot.
A. 8.7 cm.
B. 10.0 cm.
C. 15.4 cm.
D. 17.6 cm.
WASSCE
Answer:
i think the answer is letter c
1. Why did Asteroid 2019 OK cause concern among scientists? * The asteroid was not detected until it was extremely close to Earth. It's the largest known near-Earth asteroid ever discovered. The asteroid's path was aimed directly at the moon. The asteroid was too large to be deflected away from Earth
Answer:
The asteroid was not detected until it was extremely close to Earth.
Explanation:
According to data from NASA, the Asteroid named 'Astriod 2019 OK', was detected when it was extremely close to earth with just about an estimated distance of 73,000 kilometers (45,000 miles) from the Earth.
Scientists were concerned at the proximity of this space object to the Earth before it was discovered, and it brought about a cause of concern that since it was not extremely large (estimated 57 to 130 meters wide) it creates a potential for other smaller asteroids to escape detection and struck the earth.
plz help meh and explain how to do it i suck at physics...
The variables with the subscript "i" refer to the initial masses (m) and velocities (v) of the shark and fish.
[tex]m_{1,i}[/tex] = 10 kg
[tex]m_{2,i}[/tex] = 0.5 kg
[tex]v_{1,i}[/tex] = 5 m/s
[tex]v_{2,i}[/tex] = 0 m/s
The variables with "f" refer to the final masses and velocities. Use the law of conservation of momentum to calculate these. The law says that the total momentum of the shark and fish before the fish is eaten should be equal to the momentum after the fish is eaten. We have
[tex]m_1v_1[/tex] = (10 kg) (5 m/s) = 50 kg • m/s
[tex]m_2v_2[/tex] = (0.5 kg) (0 m/s) = 0 kg • m/s
so the total momentum before the fish gets eaten is 50 kg • m/s.
When the shark eats the fish, its mass increases by 0.5 kg. So
[tex]m_{1,f}v_{1,f}[/tex] = (10.5 kg) [tex]v_{1,f}[/tex] = 50 kg • m/s
Solve for [tex]v_{1,f}[/tex] by dividing both sides by 50.5 kg to get
[tex]v_{1,f}[/tex] = (50 kg • m/s) / (50.5 kg) ≈ 4.76 m/s
A person slides a box down a ramp. The box starts from rest 2m above the lowest point. The ramp is frictionless. Once the box reaches the bottom there is friction. For every 1m the box travels on the flat part increases by 100 J. Where does the box stop? The box has mass of 5 kg.
Answer:
.98m
Explanation:
Vf=Vi+2at
(V F)^2+2 ( change in distance )
X f= i ( change in V & T )
EK=1/2Mv^2,EG=mgh
This question involves the concepts of the law of conservation of energy, work done, Newton's Second law of motion, and equation of motion.
The box stops at a distance of "1.02 m".
First, we will use the law of conservation of energy to find out the final velocity when the box reaches the flat part.
[tex]Loss\ of\ Potential\ Energy=Gain\ in\ Potential\ Energy\\mgh=\frac{1}{2}mv^2\\\\2gh=v\\v=\sqrt{2gh}[/tex]
where,
v = speed = ?
g = 9.81 m/s²
h = height = 2 m
Therefore,
[tex]v=\sqrt{(2)(9.81\ m/s^2)(2\ m)}[/tex]
v = 6.26 m/s
Now, we will use the formula of work done to find out the force applied to the box to stop the motion:
[tex]W = Fd[/tex]
where,
W = Work Done = 100 J
F = Force applied = ?
d = displacement = 1 m
Therefore,
[tex]100\ J = F(1\ m)\\F = 100\ N\\[/tex]
Now, we will use Newton's Second Law of Motion to find out the deceleration of the person:
[tex]F=ma[/tex]
where,
m = mass = 5 kg
a = decceleration =?
Therefore,
[tex]100\ N = (5\ kg)a\\\\a=\frac{100\ N}{5\ kg}\\\\a = - 20\ m/s^2[/tex]
negative sign shows deceleration.
Now, we will use the third equation of motion to find the distance at which the box stops.
[tex]2as=v_f^2-v_i^2\\2(-20\ m/s^2)s=(0\ m/s)^2-(6.26\ m/s)^2\\\\s=\frac{40\ m/s^2}{39.24\ m^2/s^2}[/tex]
s = 1.02 m
Learn more about equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion in the horizontal and vertical directions.
7. The night of desest is very cold and the day is very
hot
Give reason
Answer:
1) Sand cannot hold the heat. It acts like a mirror to the sun. During the daytime, it stays warm, and when the Sun is absent it loses all its heat making the nights colder. There's nothing in the desert that can either absorb heat from the sun or hold it on the surface when the sun is set.
2) Deserts are hot primarily because of a lack of water. When the sun shines on the ground, all of the absorbed sunlight goes into raising the ground's temperature. DESERTS ARE COLD AT NIGHT:Because of the lack of water in the ground, and little water vapor in the air, most deserts can get quite cool at night.
3) The temperature in the desert can change drastically from day to night because the air is so dry that heat escapes rapidly at night. The daytime temperature averages 38°C while in some deserts it can get down to -4°C at night. The temperature also varies greatly depending on the location of the desert.
Which change to an object would reduce its potential energy by half?
A. Increasing its height to twice its original value
OB. Reducing its mass to one-quarter of its original value
O C. Increasing its mass to twice its original value
O D. Reducing its height to one-half of its original value
Answer:
It is D
Explanation:
Make sure you read the question carefully because people get different variations
In a tug of war , two teams pull on the rope with a certain force. If team A pulls on it with a force of 225 N and team B pulls on it with a force of 360 N, what is the magnitude of the resultant force on the rope?
Answer:
135 N
Explanation:
Given that:
In a tug of war, team A pulls the rope with a force of 225 N; &
Team B also pulls with a force of 360 N
The magnitude of the resultant force is the difference between the two forces since they are positioned in the opposite direction.
Thus;
The magnitude = 360 N - 225 N
So, magnitude of resultant force on the rope = 135 N