The center of mass of an irregularly shaped object 10 m long that is placed with each end on a scale from the left is 5.57 m
Let the object length be L.
L = 10 m
Let the distance from center of mass to the right end be x. The irregular shaped object exerts an upward force on both left and right side.
Fl = 74 N
Fr = 93 N
Since the object is at rest,
τ = 0
Fr * x - Fl ( L - x ) = 0
93 x = 74 ( 10 - x )
93 x = 740 - 74 x
167 x = 740
x = 4.43 m
Distance from left end = L - x
d = 10 - 4.43
d = 5.57 m
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you pull up a 75 N bucket using a fixed pulley. the rope does not stretch, so the effort and resistance are the same. however you must exert an 80 N force because of friction. find the efficiency.
Answer: 94% efficiency
Explanation:
The equation needed:
Efficiency = Energy Output/Energy Input | (Eo)/(Ei)75N = Output | 80N = Input(75)/(80) = 0.9375Simplify = 0.94Convert to Percentage 0.94 = 94% (Move two decimals to the right)Please HELPPPP!!! Describe the frequency and wavelength range of this type of electromagnetic wave. IM uses X-Ray which uses Ionizing radiation.
The frequency range of electromagnetic waves of X-ray is 3 ×10¹⁶ Hz to 3 ×10¹⁹ Hz. The wavelength range of electromagnetic waves of X-ray is 0.01 nm t0 10 nm.
What is the electromagnetic spectrum?The electromagnetic spectrum of electromagnetic waves can be described as the range of frequencies of electromagnetic radiation and its wavelengths and photon energies. The electromagnetic spectrum have range from one Hertz to above 10²⁵ Hertz.
The wavelength of electromagnetic radiation lies in between 380 to 760 nm and is detected by the human eye and characterized as visible light.
Electromagnetic waves of each frequency band are known by different names; starting at the low frequency (long wavelength) end of the spectrum these are radio waves, microwaves, infrared (IR), visible light, UV, X-rays, and gamma rays at the high-frequency (short wavelength) end.
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suppose you found a star with the same mass as the sun moving back and forth within a period of 16 months. a) what could you conclude? b) explain the reasons for your conclusion scientifically.
It has a planet orbiting at a distance larger than 1 AU when you discover a star that rotates back and forth every 16 months and has the same mass as the sun.
How can a planet's orbit move inward due to a gravitational collision?How can a planet's orbit move inward due to a gravitational collision? Another object receives both energy and angular momentum from it.
Which of the following is true regarding the transit method of finding exoplanets?There are two fundamental obstacles to directly finding exoplanets. One is that as we go farther away from the earth, the angular size of planets decreases and is no longer able to be resolved in a picture.
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review conceptual example 5 as an aid in understanding this question. an inductor and a capacitor are connected in parallel across the terminals of an ac generator. does the current from the generator decrease, remain the same, or increase as the frequency becomes (a) very large and (b) very small?
The answer to the question is that both the current and the frequency will grow as they become increasingly high and low, respectively.
What purpose does a capacitor serve?A capacitor is an electrical energy storage device made up of two conductors that are isolated from one another and placed near to one another. A straightforward illustration of one such backup system is a parallel-plate capacitor.
A capacitor: a type of battery?A capacitor is a passive component that holds static charge in an electric field, whereas a batteries is an electronic device that transforms chemical energy into electricity to create a stable electrical charge for power.
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what is the classification of bodies like pluto and eris, which are large enough to be round and have orbits beyond neptune? why are they not considered to be planets?
Given their position, Pluto , Eris are sometimes known as trans-Neptunian objects and dwarf planets (TNOs).
A dwarf planet outside of Neptune's orbit is referred to as a plutoid. As a result of their small size and extremely frigid surface temperatures, Plutoids are also sometimes referred to as "ice dwarfs." One of our solar system's largest dwarf planets is Eris. Despite being three times farther from the Sun, it is roughly the same size as Pluto.
Pluto was downgraded to a dwarf planet by the International Astronomical Union (IAU) because it did not meet the three requirements for a full-sized planet. In essence, Pluto satisfies all the requirements save for the fact that it "has not cleared its neighboring region of other objects."
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The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is?.
The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is 0.8N
What is drag?Everywhere we look, there is the drag force. In a ball of fluids, we survive (air and water). Any time there is motion in a fluid, such as air, water, or another one, drag forces become present.
Drag forces are resistive forces that are present when things move through fluids (a gas or a liquid).
Always acting in opposition to fluid flow is the drag force. Aerodynamic drag is the motion of the body in the fluid-like air. Additionally, it is known as hydrodynamic drag if the fluid is water.
What is vertical velocity?The element of vertical velocity (motion). Forecasting areas of dynamic weather requires careful analysis of regions with an upward vertical velocity.
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a child sprays her sister with water from a garden hose. the water is supplied to the hose at a rate of 0.123 l/s, and the diameter of the nozzle is 5.43 mm. at what speed ???? does the water exit the nozzle?
The water exists the nozzle at the speed of 5.315 m/s when rate of flow and diameter is given.
What is the water flow rate?Your water flow rate is the measurement of how many gallons of water could potentially come out of your kitchen faucet or bathtub per minute.
Given, Rate of flow= 0.123 l/s = 0.000123 m^3/s
and d= 5.43 mm= 0.00543m
r= 2.715 * 10^-3
Flow rate= water velocity * area of the nozzle
Area of nozzle = π* r²
= 3.14 *( 2.715 * 10^-3)²
= 2.314 * 10^-5
0.000123 = V * 2.314 * 10^-5
Speed at which the water exits= 5.315 m/s
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two wires have the same length, but the second has twice the diameter of the first. find the resistance of the second wire if the resistance of the first is 4ω.
2ω is the resistance of the second wire if the resistance of the first is 4ω if two wires have the same length, but the second has twice the diameter of the first.
R= 4ω.
R = ρl/A
2d=r
R2=2ω
Resistance is the capacity of a conductor to obstruct the passage of an electric current through it. It is controlled by the interaction of the applied voltage and the electric current passing through it.
Conductors have very little resistance, whereas insulators have a significant amount of resistance. The resistance increases as the current flow decreases. Resistance is influenced by the properties and dimensions of the material (area of cross section)
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the zero gravity research facility at nasa-operated glenn research center in ohio is used to test the behavior of fluids, flames, equipment and other objects in free fall. it consists of a 467-foot long, 12-foot diameter, steel vacuum chamber. the steel chamber resides inside of a concrete lined shaft which extends 510 feet below ground level. objects falling through the tower experience free fall over a distance of 130 meters (426 feet) before being brought to a halt. a. Determine the falling time for objects dropped from rest. Info b. Determine the final speed of the objects before the braking period begins. Final Speed Info
The falling time for objects dropped from rest is 5.19 s. The final speed of the objects before the braking period begins is 50.9 m/s.
falling time for objects is 5.19s
s = ut + - 1/2at²
(d) = (0m/s)t+1/2(g)t²
(-132 m) =
(-9.81 m/s² )T\t²
t = 5.19 s
v = u+ at
v = (0 m/s) +(g)t
v = (-9.81 m/s2 ) (5.19 s)
v=-50.91 m/s
The speed of an item, which is a scalar number in daily use and kinematics, is the size of the change in that object's position over time or the size of change in that object's position .
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Question 8 of 25
**
force of friction and air resistance
normal contact force from the road
driving force from the engine
weight of the car
Hide score
The diagram below shows the different forces acting on a car. Which label below the diagram goes
with arrow A?
off
Reduce contrast
D
7✔ 100%
74%
1007
NICE
Answer:
Explanation:
The diagram shows four forces acting on a plane in flight. direction of flight. (b) (i). Which arrow represents air resistance?
a grunting porpoise emits sound at 57 hz. what is the wavelength of this sound in water, where the speed of sound is 1500 m/s? (in m)
The wavelength of this sound in water, where the speed of sound is 1500 m/s is 26.31 m.
What is wavelength ?
The wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.
[tex]V=n \lambda[/tex]
where λ is wave length, n frequency and V velocity of sound
[tex]\lambda=\frac{V}{n}=\frac{1500}{57}=26.315 \mathrm{~m}[/tex]
The frequency f = 57 Hz of the sound that the purpoiseemits is the same in water as it was in its original medium. If thevelocity of sound in water is v = 1500 m/s, the relationship between velocity, wavelength λ and frequencyis:
[tex]v=f \lambda[/tex]
[tex]\lambda=\frac{v}{f}[/tex]
[tex]\lambda=\frac{1500}{57}[/tex]= 26.31 m
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a skydiver leaps from a plane and accelerates toward the surface of the earth. earth’s acceleration toward the skydiver is:
Skydiver's acceleration is substantially greater than Earth's acceleration in its direction.
What is acceleration?
The rate at which velocity, measured in terms of speed and direction, changes over time is known as acceleration. Anything is said to have been accelerated when it goes faster or slower in a straight line.
You fall, your descent to the ground quickening. Until the drag from her falling speed due to wind resistance equals the acceleration induced by gravity, this acceleration will continue. Because air resistance, sometimes referred to as drag force, is typically far lower than the normal force of a body, he should continue to accelerate downward. When these forces are balanced, she will attain "terminal velocity," at which point she will cease gaining speed.
He will continue to descend until he opens his chute at the same pace, although the acceleration he experiences at first is due to gravity.
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what is the wavelength of the electromagnetic wave produced by your cell phone, if the frequency of that wave is 900 mhzmhz ? express your answer with the appropriate units.
The wavelength of the electromagnetic wave is 0.33m
The study of electromagnetic radiation is known as electrodynamics, and electromagnetic radiation itself, or EM, is a physical phenomenon connected to the idea of electrodynamics. The properties of superposition apply to electric and magnetic fields as well. A field produced by a specific particle or a time-varying magnetic or electric field, then, contributes to the other fields that are present in the same space due to other causes. In addition, all magnetic and electric field vectors combine together using the vector addition formula because they are vector fields. For instance, in optics, two or more coherent light waves may interact and, through destructive or constructive interference, produce a resultant irradiance that is different from the sum of the component irradiances of the individual light waves.Frequency = 900 x 10⁶Hz
[tex]Frequency=speed/wavelength[/tex]
[tex]Wavelength=speed/frequency[/tex]
=3 x 10⁸/900 x 10⁶
=0.33m
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focal animal sampling on the focal animal sampling sheet record the data of a chosen primate from the video provided. you will collect data at 2-minute intervals. this is your time-interval. you will record the behavior at ever 2-minute interval that the animal is portraying. it is best to set the timer to beep at every 2 minutes. for example, at 2.00 the animal is walking quadrupedally on a branch. remember you are just recording the behavior of the animal at the time-interval. you must have a minimum of 10 items.
Specific focal animal codes are also provided for specific activities.
For these above mentioned sampling techniques, it is said to collect various data of the primates from a particular video within 2 minutes of time interval.
These data are of context (general activity), position, social behaviour, substrate, food (type of eating) for focal animal sampling and feeding, resting, travelling, social for scan sampling. For focal animal sampling the total time is one-half hour and for scan sampling it is 20 minute which we have to devide by 2 minutes of intervals.
For example if the video is of 6 minutes then it would be as follows:
0:00 - 2:00 = Context, position, etc.
2:00 - 4:00 = Context, position, etc.
4:00 - 6:00 = Context, position, etc.
Specific focal animal codes are also provided for specific activities.
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True or False. When light passes from one medium to another the speed stays constat
When light passes from one medium to another the speed of the light changes. Therefore, the given statement is false.
What is refraction?Refraction takes place when the light travels from one medium to another medium it changes its speed. Refraction can be defined as the redirection of light as it passes from one medium to another.
The redirection of the light ray causes by the change in the speed of the wave or by a change in the medium. Refraction of light can be observed for sound waves and water also experiences refraction.
Refraction of light obeys Snell's law, according to which the ratio of the sines of the angle of incidence and angle of refraction must be equal to the ratio of the refractive indices of the two media.
[tex]{\displaystyle {\frac{Sin \theta_1}{Sin \theta_2} =\frac{n_2}{n_1}[/tex]
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as a crude model, assume that an α particle consists of two pointlike protons attracted by a hooke's-law spring with spring constant k , and ignore the neutrons. assume further that in the absence of other forces, the spring has an equilibrium separation of zero. write an expression for the potential energy when the protons are separated by distance d .
Potential energy (PE) is the energy that a body has due to its position or compressed state; it has the formula PE=MGH, where M stands for mass, G for the force of gravity.
What is potential energy, and what does it look like?Work done to the object is equal to force times displacement. Here is the formula for potential energy. According to the rule of conservation of energy, since the amount of work an item does is equal to mgh, the energy gained by the object is equal to mgh, which in this case is the potential energy E.
What does energy express itself as?Joules (J), commonly known as Newton-meters, is the SI unit of energy.
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the role of the mouth in sound the prodution of sound during speech or singing is a complicated process lets concentrate on the mouth a typcal depth for the huamn mouth is about 8 cm although this number can vary. (Check it against your own mouth.) We can model the mouth as an organ pipe that is open at the back of the throat. What are the wavelengths and frequencies of the first four harmonics you can produce if your mouth is (a) open, (b) closed? Use .v=354 m/s
When open mouth the wavelengths and the frequencies of the first four harmonics you can produce are 0.16 m and 2,212.5 Hz, 0.08 m and 4,425 Hz, 0.053 m and 6,637.5 Hz, 0.04 m and 8,850 Hz.
When closed mouth the wavelengths and the frequencies of the first four harmonics you can produce are 0.32 m and 1,106.25 Hz, 0.1067 m and 3,318.75 Hz, 0.064 m and 5,531.25 Hz, 0.0457 m and 7,743.75 Hz.
If we open our mouth it will create a tube that opens at both ends.
The wavelengthFor the first harmonic
[tex]\lambda_1 = \frac{2L}{1}[/tex]For the second harmonic
[tex]\lambda_2 = \frac{2L}{2}[/tex]For the third harmonic
[tex]\lambda_3 = \frac{2L}{3}[/tex]For the fourth harmonic
[tex]\lambda_4 = \frac{2L}{4}[/tex]If we closed our mouth it will create a tube that one end opens and the other end closed.
The wavelengthFor the first harmonic
[tex]\lambda_1 = \frac{4L}{1}[/tex]For the second harmonic
[tex]\lambda_2 = \frac{4L}{3}[/tex]For the third harmonic
[tex]\lambda_3 = \frac{4L}{5}[/tex]For the fourth harmonic
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study smarter the plutonium isotope 239pu has a half-life of 24,000 years and decays by the emission of a 5.2 mev alpha particle. plutonium is not especially dangerous if handled because the activity is low and the alpha radiation doesn't penetrate the skin. however, there are serious health concerns if even the tiniest speck of plutonium is inhaled and lodges deep in the lungs. this could happen following any kind of fire or explosion that disperses plutonium as dust.
Therefore, the number of ²³⁹Pu atoms in 1.0 mm diameter particle is 2.6*10⁷
The half-life of the is ²³⁹Pu=2400 yrs
The radius of soot particles is r =1*10⁻⁶m/0=0.5*10⁻⁶m
The density of Plutonium is ρ=19800kg/m³
The number of ²³⁹Pu atoms in a diameter particle is
N=(m/Ma)Na
=ρ4πr³Na/3Ma
Substitute the given values to get number of atoms in particle
N=19.8*4π*(0.5*10⁻⁶)³*6.02*10²³/3*239*10⁻³
=2.6*10⁷
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6. A bird drops a feather from the roof of a 13.1 m tall building. The feather is blown
48.6 m west before falling to the ground. What is the resultant displacement of
the balloon?
The resultant displacement of the feather be 50.33 m.
What is displacement?
The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place.
For instance, if an object shifts from location A to position B, its position changes. Displacement is the term used to describe this shift in an object's position.
Given that: A bird drops a feather from the roof of a 13.1 m tall building. The feather is blown 48.6 m west before falling to the ground.
So, the resultant displacement of the feather be = √(13.1² + 48.6²) m = 50.33 m.
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the left end of a long glass rod 9.00 cmcm in diameter, with an index of refraction 1.56, is ground and polished to a convex hemispherical surface with a radius of 4.50 cmcm . an object in the form of an arrow 1.49 mmmm tall, at right angles to the axis of the rod, is located on the axis 23.0 cmcm to the left of the vertex of the convex surface.Find the position and height of the image of the arrow formed by paraxial rays incident on the convex surface. Is the image erect or inverted?
S' = 14.77 cm height of image = 0.577 mm is the computed response. It is inverted because magnification is negative.
Where radius (R) is positive because it is facing the same direction as the refracted light, and index of refraction (n1) = 1 for air and index of refraction for glass (n2) = 1.60, object distance from vertex to spherical surface (s) is 24 cm, or 0.24 meters, and image distance from vertex to spherical surface (s') is 4 cm, or 0.04 meters.
Height of object = y = 1.5 mm = 0.0015 m Height of image = y'
For a spherical reflecting surface, the object-image formula is:
According to the magnifying formula:
It is inverted because magnification is negative.
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suppose identical amounts of heat transfer into different masses of mercury and water, causing identical changes in temperature. what is the ratio of the mass of mercury to water?
Assume that similar quantities of heat are transferred into various masses or mercury and water, resulting in equivalent temperature variations. Mercury's mass is 0.033 times that of water.
What makes Mercury so unique?Of such eight moons of jupiter, Mercury is the smallest and one that is closest to the Sun. Mercury completes three spins of its axis for each of the two circuits it makes around the Sun, so takes around 96 Earth days. This rotation is exclusive to the solar system and is gravitationally locked.
Briefing :According to the statement we have Mass of mercury = M(Hg), and
Mass of Water = M(H₂O)
M(cu) / M(H₂O) , heat transfer and mass are related as we have the formula : Q=mcΔT
according to the formula we have , Q(Hg) = M(Hg) C(Hg)ΔT(Hg)...........(1)
for water , Q(H₂O)= M(H₂O) C(H₂O)ΔT(H₂O)..............................(2)
therefore dividing by specific heat in the temperature = C T from both sides .
we Get : [tex]\frac{ Q(Hg)}{CT} =[/tex][tex]\frac{ M(Hg) C(Hg)ΔT(Hg)}{CT}[/tex] , [tex]\frac{Q(H2O) }{CT} =[/tex] [tex]\frac{C(H2O) Δ TH2O}{CT}[/tex]
∴ Q(Hg)=[tex]\frac{Q(Hg)}{Q(Hg)ΔT(Hg)}[/tex] , Q(H₂O)= [tex]\frac{ Q(H2O)}{C(H2O)ΔTH2O)}[/tex]
by solving we get = Q(Hg)/C(Hg)ΔT(Hg)/Q(H₂O) / C(H₂O)ΔT(H₂O)
= Q(Hg)/C(Hg)ΔT(Hg) × C(H₂O)ΔT(H₂O)/Q(H₂O)
= [tex]\frac{C(H2O)}{C(Hg)}[/tex]= M(Hg)/M(H₂O)
specific heat of water = 4184 J/kg
and specific heat of mercury = 139 J/kg
therefore we get 4184/139 = 0.033 ans or 3:100 in ratio
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in comparing two unequal forces on a rigid body, is it possible to have the larger force produce less torque than the smaller force?
Yes, it is feasible for the larger force to induce less torque than smaller force when two unequal forces are applied to a rigid body.
What exactly is contact force?Objects making contact each other exert a force on one another known as contact force. The region of direct contact of two objects is where the contact force acts. This force may be brief in the guise of an impulse or it may be continuous as both a continuous force. Newton's Law covers contact force.
Briefing:Torque = rFsin(θ)
It is feasible for a larger force to generate less torque than a smaller force if it acts at a closer distance than that of the smaller force.
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according to this graph, the minimum size of an object that could cause a mass extinction is a little less than _____
According to this graph, the minimum size of an object that could cause a mass extinction is a little less than 10 km.
Answer is in the graph, min size of object that could cause a mass exinction is a little less than 10 km.
When a significant portion of biodiversity, such as separate species of bacteria, fungi, plants, mammals, birds, reptiles, amphibians, fish, or invertebrates, goes out during a brief period of geological time, this is referred to as a mass extinction. Impacts from comets and asteroids, extensive volcanism, climate changes,bacteria,abrupt shifts in the topography and ocean currents, or a combination of these elements may be the cause of mass extinction events. At least 75 percent of all species become extinct during major extinctions, which typically last three million years. Some experts think that, if things continue as they are, we may be able to remove that number within a few centuries.
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dirk pushes on a packing box with a horizontal force of 75.0 n as he slides it along the floor. the average friction force acting on the box is 5.0 n. how much total work is done on the box in moving it 2.50 m along the floor?
Total work done to be done on the box in moving it 2.50 m along the floor is 175 j.
Friction force is an opposing force of motion. It comes into play when an object moves over the surface of another object.
We can find the friction force using formula,
[tex]F_{friction[/tex] = µ • [tex]F_{normal[/tex]
Where,
[tex]F_{friction[/tex] = friction force
µ = coefficient of friction
[tex]F_{norm[/tex] = normal force.
In question given is
Horizontal force(F) = 75 N
Average friction force (f) = 5.0 N
displacement = 2.50 m
[tex]F_{net[/tex] = F-f
= 75- 5 N = 70 N
Work done by the force is
W = [tex]F_{net[/tex] × S
= 70 × 2.50 j
= 175 j
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A friend asks you how much pressure is in your car tires. You know that the tire manufacturer recommends 30 psi, but it’s been a while since you’ve checked. You can’t find a tire gauge in the car, but you just finished taking physics and so you tell your friend, "I don’t know, but I can figure it out." From the owner’s manual you find that the car’s mass is 1700 kg . It It seems reasonable to assume that each tire supports one-fourth of the weight. Using a ruler, you find that the tires are 16 cm wide and the flattened bottom segment of the tire is 15 cm long. Your observation of the tire tread pattern suggests that two-thirds of this segment is in actual contact with the road.
What answer—in psi—will you give your friend?
To calculate the pressure in the car tires, we can use the equation $P = \frac{F}{A}$, where $P$ is the pressure, $F$ is the force acting on the area, and $A$ is the area over which the force is applied. In this case, the force acting on the tire is the weight of the car, and the area is the portion of the tire that is in contact with the road.
First, we need to calculate the weight of the car. The weight of the car is given by the equation $W = mg$, where $m$ is the mass of the car and $g$ is the acceleration due to gravity. We are given that the mass of the car is 1700 kg, so the weight is $W = 1700 \text{ kg} \times 9.8 \text{ m/s}^2 = 16786 \text{ N}$.
Next, we need to calculate the force acting on each tire. Since the weight of the car is distributed evenly among the four tires, each tire supports one-fourth of the total weight, or $F = \frac{1}{4} \times 16786 \text{ N} = 4196.5 \text{ N}$.
Now we need to calculate the area of the tire that is in contact with the road. The width of the tire is 16 cm, and we are given that two-thirds of the flattened bottom segment is in contact with the road.
This means that the length of the segment in contact with the road is $\frac{2}{3} \times 15 \text{ cm} = 10 \text{ cm}$. The area of the tire in contact with the road is therefore $A = 16 \text{ cm} \times 10 \text{ cm} = 160 \text{ cm}^2$.
Finally, we can use the equation $P = \frac{F}{A}$ to calculate the pressure in the tires. Plugging in the values for the force and the area, we get
$$P = \frac{F}{A} = \frac{4196.5 \text{ N}}{160 \text{ cm}^2} = 26.2 \text{ Pa}$$
Since 1 psi is equivalent to 6894.757 Pa, the pressure in the tires is approximately
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Teenagers Sam and Tom are playing chicken in their rockets. As the figure(Figure 1) shows, an experimenter on earth sees that each is traveling at 0.95c as he approaches the other. Sam fires a laser beam toward Tom. What is the speed of the laser beam relative to Sam? What is the speed of the laser beam relative to Tom?
The speed of the laser beam relative to Tom is 2.95c.
The teenager Sam and Tom are approaching each other with a speed of 0.95c while playing chicken in their rocket.
Sa fires a laser from his rocket towards Tom.
The speed of the laser will be equal to c because it will have the speed of light.
Now, the speed of the the rocket of Sam from the rocket of Tom will be,
V = 0.95c-(-0.95c)
V = 1.95c.
Now, because the laser is fired towards Tom, speed of the laser with respect to Tom will be,
V' = 1.95c - (-c)
V' = 2.95c.
So, the speed of the laser beam relative to Tom is 2.95c.
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if an astronaut knocks a wrench off the outside of the space shuttle (while in space) while she is doing a repair job, the wrench will continue moving in the same direction. which of newton's laws of motion will the wrench demonstrate?
The Newton's first law is demonstrated over here.
If the wrench is thrown then that wrench will keep on moving in the space.
As we all no space has no gravity and since there is no gravity, hence, no force is applied on that body.
The wrench will move freely in the space and will continue to move in same direction until there is some external force is applied to stop or change its direction.
This shows that over here the Newton's first law is applied.
The Newton's first law states that the body will continue to be in the same state or motion and will not change until the external force is applied on it.
This Newton's first law is also known as law of inertia.
Therefore, the wrench will continue to move in the same direction under the influence of Newton's first law.
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why have so many kuiper belt objects been discovered during the last two decades but not before then?
The Kuiper Belt has been known since the 1950s, but it wasn't until the 1990s that technology advanced enough to provide astronomers with the means to observe and detect Kuiper Belt objects.
Advances in telescope and imaging technology made it possible to detect faint and distant objects, and the use of powerful computers enabled the analysis of vast amounts of data. The discovery of the first Kuiper Belt object, 1992 QB1, in 1992, marked the beginning of a new era of exploration and discovery of the Kuiper Belt.
What is the Kuiper Belt?Is a region of the outer solar system beyond the orbit of Neptune that is home to thousands of icy small bodies, including dwarf planets like Pluto. It is believed to contain the source material for comets that originate in the outer solar system.
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A soccer ball is kicked horizontally. what is the average speed if its displacement is 21 m after 4 sec
When a soccer ball is kicked horizontally, then the average speed is calculated to be 5.25 m/s.
What is displacement?The term displacement means that an object has moved, or has been displaced. Change in position of an object is displacement. Standard unit of displacement in the International System of Units is meter. Displacement is usually measured along a straight line
Distance is a scalar quantity that refers to how much ground an object has covered during motion whereas displacement is a vector quantity that means how far out of place an object is.
Given displacement is 21m
and time = 4sec
Therefore average speed= 21/4
= 5.25 m/s
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An arrow in a bow has 100 j of potential energy. Assuming no loss of heat (no friction), how much kinetic energy will it have after it has been shot?.
We can conclude that the kinetic energy of the arrow after it is being shot is 70 J.
What is kinetic energy?
The energy an item has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.
Given data:
The magnitude of potential energy is, U = 70 J.
Since, it is given that there is no net loss of energy, which definitely in accordance with the conservation of energy. As per the law of conservation of energy, "The total energy of the system remain conserved. The energy can change it's form or can transfer form from one system to another".
So, the entire potential energy of the arrow will get converted into the kinetic energy. That is,
U = KE
KE = 70 J
Thus, we can conclude that the kinetic energy of the arrow after it is being shot is 70 J.
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