An individual is planning to take an 800-mile trip between two large cities. Three pos-sibilities exist: air, rail, or auto. The person is willing to pay $25 for every hour savedin making the trip. The trip by air costs $600 and travel time is 8 hours, by rail the costis $450 and travel time is 16 hours, and by auto the cost is $200 and travel time is 20 hours.
(a) Which mode is the best choice?
(b) What factors other than cost might influence the decision regarding which mode to use?

Answers

Answer 1

Answer:

1. Auto is the best mode since it is the cheapest

2. Safety, reliability, convenience should be considered

Explanation:

1.

This person is willing to pay $25 per hour.

To get the mode, which is the best choice I used this formula

Cost of trip + 25T

T = time or number of hours

By air travel

Cost = $600, T = 8 hours

600+25(8)

= 600+200

= 800 dollars

By rail,

Cost = $450

T = 16 hours

450+25(16)

= 450+400

= 850 dollars

By auto,

Cost = $200

T = 20 hours

200+25(20)

= 200+500

= 700 dollars

From these calculations the cost of Traveling by auto is the cheapest so it is the best mode.

2. Other factors to consider when choosing an alternative mode of transport

A. Safety: this transportation material should be able to get to it's destination without any form of damages happening

B. Reliability: the material should be able to fulfill it's requirements

C. Convenience: in terms of availability per day and also the frequency of traveling time


Related Questions

A square isothermal chip is of width w 5 mm on a side and is mounted in a substrate such that its side and back surfaces are well insulated; the front surface is exposed to the flow of a coolant at T 15 C. From reliability considerations, the chip temperature must not exceed T 85 C. If the coolant is air and the corresponding convection coefficient is h 200 W/m2 K, what is the maximum allowable chip power

Answers

Solution :

All of the electrical power dissipated in the chip is transferred by the convection to the coolant.

So P = q

and from the Newton's law of cooling,

[tex]$P = hA(T-T_ \infty) = hW^2(T-T_ \infty)$[/tex]

And in air,

[tex]$P_{max} = 200 \ W/m^2 . K (0.005 \ m)^2(85 - 15)^\circ C$[/tex]

         = 0.35 W

In the dielectric liquid,

[tex]$P_{max} = 300 \ W/m^2 . K (0.005 \ m)^2(85 - 15)^\circ C$[/tex]

         = 5.25 W

Relative to the liquids, the air is considered a poor heat transfer agent. So, in the air the chip are able to dissipate far less of energy than in the dielectric liquid.

The maximum allowable chip power is 0.35W.

To solve this question, we need to apply Newton's law of cooling.

Newton's law of cooling

This states that the rate of heat loss of a body is directly proportional to the difference in temperature between the body and its environment.

Mathematically; P∝ AΔT

[tex]P=hA(T-T_o)\\P=hw^2(T-T_o)\\[/tex]

Let's substitute the values into the above equation.

[tex]P_m_a_x=(200)(5*10^-^3)^2*(85-15)\\P_m_a_x=0.005*70\\P_m_a_x=0.35W[/tex]

From the calculation above, the maximum allowable chip power is 0.35W

Learn more on Newton's law of cooling here

https://brainly.com/question/11464125

Harlin is designing a new car engine that does not create pollution. Which technological design factor is probably the most
important for his design?
OA.
appearance
ОВ.
how easy it is to drive
OC.
environmental impact
OD.
cost

Answers

Answer: environmental impact

Explanation:

From the question, we are informed that Harlin is designing a new car engine that does not create pollution.

The technological design factor which is probably the most important for the design is the impact on the environment.

Pollution has a negative effect on the environment a d doing this shows that emphasis is placed on how the environmental issue of pollution can be tackled.

Suppose your bathroom sink is clogged and you have decided to try and unclog it by pushing a wire into the drain. You have several types of wire available around the house, some insulated and some not. Which of the following wire characteristics would you need to consider in selecting a wire for the job?

The wire characteristics are listed as follows:

a. Immunity to electrical noise
b. Color of the insulation
c. Resistance of the insulation to salt water
d. Resistance of the insulation to fire
e. Cost
f. Stiffness
g. Ease of stripping the insulation -
h. Weight
i. Availability
j. Strength
k. Resistance to high temperatures
l. Resistance to stretching

Answers

Answer:

stiffness ( f )

weight ( h )

availability ( i )

strength ( j )

resistance to stretching ( l )

Explanation:

The wire characteristics to be considered for the job would be the mechanical characteristics only . therefore the characteristics to consider are :

stiffness: since you want to use the wire to unclog the sink it is necessary you consider the flexibility of the wire in order to achieve what you want weight: the lighter the wire the easier it can be used for the jobAvailability : the wire has to be very close and readily available for the job it will be used forStrength: The wire has to be strong enough so that it doesn't break inside the sinkResistance to stretching : The wire needs to have a high ductility

In the planning process of the product development life cycle what is it important to inventory
A. Goals, mission, costs, and strengths
B. Goals, mission, capabilities, and constraints
C. Goals, mission, capabilities, cost, and strengths
D. Goals, mission, capabilities, cost and constraints

Answers

Your Answer would be A I believe.

Technician A says that a component may be grounded through its mounting to a major metal part. Technician B says that some components must be grounded by connecting its positive terminal to a metal frame

Answers

Answer:

Technician B is correct

Explanation:

Grounding of component can be done by either connecting its positive  terminal  to a metal frame and then connecting its negative wire to the ground  and not  by mounting it on a major metal part hence Technician B is correct while Technician B is incorrect .

Electrical grounding is an alternate route created to allow excess current entering an equipment to go the ground without destroying the component

It is common to specify battery capacity, the amount of stored energy, with units of ampere-hours (Ah). A particular 12 V lead acid battery has a capacity of 80 Ah. That is, the battery stores enough energy to supply 1 A for 80 hours, or 80 A for 1 hour, or 20 A for 4 hours, and so on. Note that amperes times hours give units of charge, not energy, so specifying energy in this way requires knowledge of the nominal voltage of the battery in order to be meaningful.

The fully-charged, 12 V, 80 Ah battery is used to drive a motorized hoist to lift a 150 lb person into the air. The electromechanical energy conversion process, accounting for battery, motor, and mechanical losses, has an efficiency of 85%.

Required:
a. If the battery is fully-discharged during the lifting process, how high can the person be lifted? Assume constant battery voltage and no height limitation on the hoist.
b. The maximum allowable battery current is 15 A. How long will it take to lift the person to the height determined in part a?
c. What is the battery's output power during the lift? You may assume that the battery voltage remains constant.

Answers

Answer:

a)   4401.7 m

b)  5.3 hours

c) 180 watts

Explanation:

a) Determine how high a person can be lifted

since energy = voltage * amperes

                     = 12v * 80Ah = 960 watt h

960 watt h ≈ 960 * 3600 J

                  = 3456 KJ

next we will calculate the gravitational potential energy

Gpe = mass of person * g * h

       = (150*0.454)kg * 9.8 * h

Gpe  = 667.38 * h  ------ ( 1 )

since efficiency is = 85% = 0.85

E (out ) from machine = energy * efficiency ------ ( 2 )

                                    = 3456 * 0.85 = 2937.6 KJ  

To determine (h) equate equation 1 and equation 2

667.38 * h = 2937.6 KJ

h = 2937.6 / 667.38

  = 4401.7 m

b) Time taken to reach the height in part A

Eout = Gpe

Eout = ( 12v * 15A * x * 3600J * 0.85 )

Gpe  = 667.38 * h = 667.38 * 4401.7 = 2937606.55

during the lift : 550800 x = 2937606.55

time taken  x = 5.3 hours

c) Determine battery output power during lift

15A * 12v

= 180 watts

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