The following relationship is true T1 < T2.
An ideal gas is defined as a gas in which all collisions between atoms or molecules are perfectly elastic and no intermolecular attractive forces occur. It can be thought of as a collection of perfectly rigid spheres that collide but do not interact.
The volume of gas particles is negligible. Gas particles are the same size and have no intermolecular forces as other gas particles. Gas particles move randomly according to Newton's laws of motion. Gas particles undergo perfectly elastic collisions without losing energy. This is the relationship between four variables and describes the state of the gas.
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PLEASE HURRY
Part A:Two football players run at each other. One has a mass of 75 kg and is moving at 6 m/s.
The second has a mass of 100 kg and is moving at 8 m/s. Calculate the momentum of each
football player.
Part B:The two football players collide. What is the total momentum of the football players?
Part C:What is the velocity of the football players after the collision?
A: The momentum of the first player be 450 kg.m/s.
The momentum of the second player be 800 kg.m/s.
B: The total momentum of the football players be 1250 kg.m/s.
C: The velocity of the football players after the collision be 7.14 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
One has a mass of 75 kg and is moving at 6 m/s.
The second has a mass of 100 kg and is moving at 8 m/s
So, momentum of the first player = mass * velocity
= 75×6 kg.m/s
= 450 kg.m/s.
The momentum of the second player = mass * velocity
= 100×8 kg.m/s
= 800 kg.m/s.
If the two football players collide, the total momentum of the football players be = 450 kg.m/s + 800 kg.m/s = 1250 kg.m/s.
The velocity of the football players after the collision be = total momentum/total mass = 1250 kg.m/s./(75+100)kg = 7.14 m/s.
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a force of 20n is applied toa screwdriver to pry the lid off a paint can. the screwdriver applies 65n of force to the lids. what is the mechanical advantage of the screwdriver
The screwdriver being described above has a mechanical advantage of 65 N. Accordingly, this straightforward device would exert 65N of force on the can's lid for every 20N of force applied to the screwdriver.
How can you improve a screwdriver's mechanical advantage?A screwdriver's handle can have its torque increased by increasing the diameter of the handle. The force exerted by a person's hand on the handle must be farther away from the screwdriver's shaft in order to increase the torque that is applied to the screw by the tool.
The mechanical advantage and force that a screw can exert for a given applied force increase as the distance between its threads decreases. However, since most real screws have high levels of friction, the mechanical advantage they provide is less than that predicted by the previous equation.
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the transfer of electrical energy from one circuit to another without the aid of a conductor is called:
Answer:
Inductance or mutual inductance
Energy produced in one circuit induces energy in another
(such as high voltage produced by a coil from input by say, a 12V battery)
a metal sphere of radius 15 cm has a net charge of 7.0 10-8 c. (a) what is the electric field at the sphere's surface?
Answer:
Electric field on the surface of the ball 28 kV/m
Explanation:
Given:
R = 15 cm = 0.15 m
q = 7.0·10⁻⁸ C
________________
E - ?
Electric field on the surface of the ball:
E = k·q / R²
E = 9·10⁹·7.0·10⁻⁸ / (0.15)² ≈ 28 000 V/m or E = 28 kV/m
an object is to the left of a thin lens. the lens forms an image on a screen that is 2.70 mm to the right of the object. the height of the image is 2.60 times the height of the object. part a is the image upright or inverted? is the image upright or inverted? the image is inverte
The image is inverted and real because the question tells us that the image was formed on a screen.
How to know if an image is real and inverted?When the rays come together, a true image is created. A virtual image is always formed above the principal axis, therefore it is always upright, as opposed to a real image, which is always formed below the principal axis and is always inverted.
An image that can be projected onto a screen is a real image. Behind the lens, a virtual image appears to emerge.
The image is inverted, magnified, and real for an object that is between one and two focal lengths from the lens.
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two 1-kg stationary cue balls are struck by cue sticks. the cues exert the forces shown. which ball has the greater final speed?
Both balls have the same final speed.
What is speed?The distance traveled by an object per unit time is defined as its speed. Speed is a scalar quantity because it has no direction and only magnitude. The SI unit is meter/second.Based on Newton's second law of motion,
Second Law of Motion of Newton (Force) The acceleration of an object is determined by its mass and the amount of force applied.force = momentum/time change
Momentum change = force time
(force time)/mass = change in speed
When two 1.0 kg stationary cue balls are struck by cue sticks with equal force and time.
Therefore both stationary cube balls will have the same final speed.
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. an object is launched straight up into the air from the ground with an initial vertical velocity of 30 m/s. the object rises to a highest point approximately 45 m above the ground in 3 seconds; it then falls back to the ground in 3 more seconds, impacting with a speed of 30 m/s. (a) the average speed of the object during the 6-second interval is closest to (a) 0 m/s. (b) 5 m/s. (c) 15 m/s. (d) 30 m/s. (b) the magnitude of the average velocity during the 6-second interval is closest to (a) 0 m/s. (b) 5 m/s. (c) 15 m/s. (d) 30 m/s
In the first case, the average speed of the object is 15 m/s.
Hence, Option C is correct.
In the second case the average velocity is 0 m/s.
Hence, Option A is correct.
Explain
a) avg. speed=total distance travelled/total time taken.
which is (45+45)/(3+3)=15m/sec.
b)avg. velocity= total displacement/total time taken.
which is (45+(-45))/(3+3)=0 m/sec.
Here the -ve sign indicates the change in direction(opposite).
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a plane flying with a constant speed of 300 km!h passes over a ground radar station at an altitude of 1 km and climbs at an angle of 30 . at what rate is the distance from the plane to the radar station increasing a minute later?
The rate of the distance from planar to radar is 150m.
A 300 mph aircraft will have traveled 300 miles in 30 minutes. The distance between the plane and the interceptor, which takes off a half-hour later, is 500 miles if we deduct the 300 miles from the 800 miles. The combined speeds of the two aircraft are what we need to look at next. 600 mph multiplied by 400 mph equals 1000 mph. Flying the remaining 500 miles will only take 30 minutes at those combined speeds.[tex]Distance= S\alpha sin\beta[/tex]=300 sin30
= 300 x 0.5
=150m
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1. A 50 kg carton slides at 4 m/s across an icy surface.
The sliding carton skids onto a rough surface and
stops in 3 seconds. Calculate the force of friction it
encounters.
Answer:
A carton of mass 50-kg slides across an icy surface at a speed of 4 m/s. Conclusion : The momentum of a carton of given mass moving with a particular velocity is 200 kg−m/s .
what is the frequency of the second overtone if the fundamental frequency is 308 hz
A. 154hz
B. 924hz
C. 308hz
D 616hz
The frequency of the second overtone if the fundamental frequency is 308 Hz is equal to 1540 Hz.
What is overtone?An overtone can be described as any resonant frequency above the fundamental frequency of a sound. Overtones can be defined as all pitches higher than the lowest pitch within an individual sound. While the fundamental can be described as usually heard most prominently, overtones are present in any pitch except a true sine wave.
The lowest normal frequency is called the fundamental frequency, while the higher frequencies are known as overtones.
Given, the fundamental frequency, f₀ = 30 8 Hz
The relationship between the fundamental frequency and the second overtone is given by
f₂ = 5 f₀
f₂ = 5 × 308 = 1540 Hz
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suppose you observe a star-like object in the sky. how can you determine whether it is actually a star or a quasar?
Consider the light spectrum. The maximum Doppler shift for spectral lines from stars is a few hundred km/s. The lines of even the nearest quasars are significantly more redshifted.
Describe the spectrum of light.
The term "light spectrum" refers to the range of various wavelengths that a light source emits. Light is measured in nanometers (nm). Each nanometer corresponds to a wavelength of light or a band of light energy. Visible light is the portion of the spectrum between 380 and 780 nanometers (nm).
What kind of light spectrum does that entail?
The frequency of the light determines the hue of the light in the visible spectrum. A rainbow or the split light from a prism always has the same visible spectrum.
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the mass of earth is 5.972 * 1024 kg, and the radius of earth is 6,371 km. a 750 kg satellite orbits 35,800 km above earth in a perfectly circular orbit. if the gravitational force is acting as the centripetal force to keep the satellite in orbit, what is the tangential velocity of the satellite in its orbit?
The speed or the tangential velocity of the satellite to keep it in its orbit is 3,073.5 meters per second.
The gravitational force between two objects is given by:
F = GMm/r²
Where:
G = constant of gravity = 6.674 x 10⁻¹¹ N.m²/kg²
M, m = mass of each object
r = distance between objects
Parameters given in the problem:
M = 5.972 x 10²⁴ kg
m = 750 kg
r = 6371 + 35,800 = 42,171 km = 42,171,000 m
Hence,
F = 6.674 x 10⁻¹¹ x 5.972 x 10²⁴ x 750 / 42,171,000²
= 168.1 N
This is equal to centripetal force:
F = m . v² / r
168.1 = 750 . v² / 42,171,000
v² = 9,446,304
v = 3,073.5 m/s
Hence, the tangential velocity of the satellite to keep it in its orbit is 3,073.5 m/s
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a 4 lb b ball is traveling around a circle of radius r1 = 3 feet quickly v1 = 6 ft/s. if the attached rope is pulled down the hole with constant speed vr = 2 ft/s
Answer:
ur gay
Explanation:
i said so
comets travel around the sun in elliptical orbits with large eccentricities. if a comet has speed 2.0×104 m/s when at a distance of 2.4×1011 m from the center of the sun, what is its speed when at a distance of 5.2×1010 m . express your answer in meters per second.
Comets are small asteroid-like bodies when they are far from the Sun, traveling in highly ellipical orbits about the Sun. Comets go around the Sun in a highly elliptical orbit
How to find speed of a comet?
Speed of the comet can be determined by using conversation of energy = initial kinetic energy + initial potential energy of comet = final kinetic energy + final potential energy of comet
We know,
M = mass of sun = 1.989 x 1030 kg
m = mass of comet
vi = initial speed of comet = 20000 m/s
ri = initial distance from center of sun = 2.4 x 1011 m
vf = final speed of comet = ?
rf = final distance from center of sun = 5.2x 1010 m
Using conservation of energy
initial kinetic energy + initial potential energy of comet = final kinetic energy + final potential energy of comet
(0.5) m vi2 - GMm/ri = (0.5) m vf2 - GMm/rf
(0.5) vi2 - GM/ri = (0.5) vf2 - GM/rf
(0.5) (20000)2 - (6.67 x 10-11)(1.989 x 1030)/(2.4 x 1011) = (0.5) vf2 - (6.67 x 10-11)(1.989 x 1030)/(5.2x 1010)
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a bucket full of sand has a mass of 30 kg (including the bucket and the sand). the bucket is to be lifted to the top of a building 15 meters tall by a rope of negligible weight. however, the bucket has a hole in it, and leaks 0.1 kgs of sand each meter it is lifted. find the work done lifting the bucket to the top of the building.
The Total work done lifting the bucket to the top of the building is 405 kg m
What is work?
Work in physics is the energy that is transmitted to or from a object when a force is applied along a displacement. In its simplest form, it equals the goods of the force's magnitude and the distance travelled for a constant force directed in the same direction as the motion. When a force is applied, it is said to have a component that points inside the direction of a displacement of the application point.
The work done lifting the bucket to the top of the building can be calculated by multiplying the force of the weight of the bucket by the distance it is moved. In this case, the force is equal to the mass of the bucket and sand, which is 30 kg, and the distance is 15 m. So, the work done is:
Work = Force x Distance
= 30 kg x 15 m
= 450 kg m
However, as the bucket is leaking sand, the mass of the bucket and sand is decreasing as it is being lifted. The mass of the bucket and sand at the top of the building will be less than 30 kg and the amount of work done will be less than 450 kg m.
To calculate the work done lifting the bucket to the top of the building, we need to calculate the mass of the bucket and sand at the top of the building. We can do this by subtracting the amount of sand lost from the initial mass of the bucket and sand. As the bucket leaks 0.1 kg of sand each meter it is lifted, the mass of the bucket and sand at the top of the building can be calculated as:
Mass at top of building = 30 kg - 0.1 kg x 15 m
= 27 kg
Now, we can calculate the work done lifting the bucket to the top of the building by multiplying the force of the weight of the bucket and sand at the top of the building by the distance it is moved. In this case, the force is equal to the mass of the bucket and sand at the top of the building, which is 27 kg, and the distance is 15 m. So, the work done is:
Work = Force x Distance
= 27 kg x 15 m
= 405 kg m
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what is the escape speed on a spherical asteroid whose radius is 823 km and whose gravitational acceleration at th surface is 1.38 m/s^2.
A spherical asteroid with a radius of 823 km has an escape speed of 4 103 m/s.
Explain about the gravitational acceleration?Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational force acting on it. Its symbol is "g," and its unit is m/s2. Gravitational acceleration is a vector quantity, having a magnitude and a direction.
(a) The given values are
[tex]$$r=500 \mathrm{~km}$$[/tex]
[tex]$$\Rightarrow a=3.0 \mathrm{~ms}^{-2}$$[/tex]
[tex]$$\Rightarrow v=1000 \mathrm{~ms}^{-1}$$[/tex]
[tex]$$\Rightarrow h=1000 \mathrm{~km}$$[/tex]
We know that the formula for gravitational acceleration is given as
[tex]$$a_g=\frac{G M}{r^2}$$[/tex]
And the formula for the escape velocity is given by
[tex]$$v=\sqrt{\frac{2 G M}{r}}$$[/tex]
Substituting for gravitational acceleration in the above formula we get
[tex]& \Rightarrow v=\sqrt{\frac{2 a_g r^2}{r}} \\[/tex]
[tex]& \Rightarrow v=\sqrt{2 a_g r}[/tex]
Substituting the given values for the radius and gravitational acceleration.
[tex]$$\Rightarrow v=\sqrt{2(3.0)\left(500 \times 10^3\right)}$$[/tex]
[tex]& \therefore v=1.732 \times 10^3 \mathrm{~ms}^{-1}[/tex]
The complete question is,
(a) What is the escape speed on a spherical asteroid whose radius is 5 (lind whose gravitational acceleration at the surface is 3.0 [tex]\mathrm{~ms}^{-2}$[/tex]
(b) How far from the surface will a particle go if it leaves the asteroid's surface with a radial speed of[tex]$1000 \mathrm{~ms}^{-1}$[/tex]
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estimate the amount of mass that is converted to energy when a proton combines with a deuterium nucleus to form 3he.
Answer:7.99
Explanation:
The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.
The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.terminal velocity is 0.8 N .
Simply put, what is terminal velocity?As a result, a object achieves terminal velocity when its acceleration (or deceleration) are zero and its speed is no longer increasing or decreasing.
What is the Earth's terminal velocity?around 53 m/s Unaffected by its mass, an item in free fall inside a vacuum would accelerate at a velocity of about 9.8 m/s2 close to the Earth's surface.When an object is dropped, air resistance causes it to finally achieve its terminal velocity, which for a human skydiver is about 53 m/s (190 km/h or 118 mph).
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how was the third law of motion discovered
Answer:
how was the third law of motion discovered
Explanation:
Isaac Newton discovered this law by exerting pressure on one object against another. The first object's force is felt and equally replicated by the second body. Thus, Isaac Newton proved that it's impossible to exert pressure on a single object without a similar reaction from the second object.
f. What happens if the Physics student is standing on ice?
g. What is the force between the student and the ground called?
Answer:
Explanation:
f. Student slips on ice
g. The force is called sliding friction force
at what speed does a 1600 kg compact car have the same kinetic energy as a 20000 kg truck going 24 km/h ? express your answer in kilometers per hour.
A 1600 kilogram small vehicle and a 20 000 kg truck traveling at a speed of 84.74 km/h have same amounts of kinetic energy .
What causes kinetic energy to move?A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, gets done on it by exerting a net force.
Briefing :
Kinetic energy is that which is due to the movement of bodies and is calculated like this:
K = (1/2)mv² Formula (1)
Data for the truck
m = 20000 kg
v = 24 km/h
= 24 *(1000m)/ (3600s)
v = 6.66m/s
Calculation of the kinetic energy of the truck
We replace data in the formula (1)
K = (1/2)mv²
K = (1/2)(20000)(6.66)²
K = 443556J
Data for the compact car
K = 443556 J
= 443556 (N*m)
m = 1600 kg
Calculation of the speed of the compact car
We replace data in the formula (1)
K = (1/2)mv²
443556 = (1/2)( 1600)(v)²
443556 = ( 800)(v)²
v² = 443556/ (800)
[tex]v=\sqrt{\frac{443556}{800} }[/tex]
v = 23.54m/s
1 km = 1000 m
1 h = 3600 s
v =23.54*(3600/1000)km/h
v =84.74 km/h
Therefore , speed of car is is 84.74 km/h
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the velocity of an object is given v(t), and the acceleration is given by a(t). what is the relationship between the total
The rate at which velocity changes is called acceleration. (Attensity exists when velocity varies.) If a moving object changes speed.
Why does time accelerate the rate at which velocity changes?
A motion's acceleration is the rate at which it changes from one velocity to another. A velocity's rate of change with respect to time is referred to as its acceleration. The amount and direction of acceleration are both properties of a vector quantity.
A change in velocity is known as what?
A velocity change's acceleration is measured. Acceleration is the measure of how quickly a velocity changes with time. The acceleration measure used in SI is M/s2.
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During soccer practice one of your teammates sprains her ankle. You take an instant cold pack from the first aid kit to use on her ankle. It is not at all cold when you take it out. The instructions on the cold pack tell you to punch the pack so that you break open a sake of chemicals inside it. When you do that, you notice that the cold pack rapidly becomes quite cold. What happened?.
When you punch the pack of ice, you notice that cold pack rapidly becomes quite cold. This is because, chemical reaction took place absorbing thermal energy from the pack.
What is the absorption of thermal energy?Chemical reactions that absorb energy are called endothermic. In an endothermic reactions, more energy is absorbed when the bonds in the reactants are broken than it is released when new bonds are formed.
The process in making the cold pack is the physical act of dissolving. When ammonium nitrate is dissolved in water, that process is endothermic and thus producing the cold pack. All the reaction absorb energy, for example thermal energy from heat for its activation.
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uniform circular motion what is the direction of the force that acts on the clothes in the spin cycle of a washing machine? what exerts the force?
The direction of the force that acts on clothes in the spin cycle of a washing machine is inwards. if the force would have been acting outwards then the clothes would have flown off, but this is not the case.
What is uniform circular motion?
when an object moves in a circle at a consistent speed in a motion, it is said to be in a uniform circular motion.
What is an example of uniform circular motion?
A satellite made by man is an example of uniform circular motion. Apart from that another example of uniform circular motion is a rotating ceiling fan, also a wheel of a moving car is an example of uniform circular motion.
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deep in the forest a 0.017kg leaf falls from a tree and drops straight to the ground. if its initial height was 5.3 m and its speed on landing was 1.3 m/s, how much nonconservative work was done on the leaf? what force does this nonconservative work?
So work done by non-conservative forces = -0.868 joules.
As per the data given in the question,
It is given that:
Weight of leaf = 0.017 Kg = 17 grams.
Initial height was 5.3 m
Speed on landing was 1.3 m/s,
So, to find the total non conservative work we will apply the work-energy theorem
The work-energy theorem states that the net work done on a system is equal to the change in kinetic energy, or that the work done by the sum of all forces acting on a particle equals the change in kinetic energy of the particle.
So, the value of energy lost [tex]=-\left(mgh-\frac{1}{2} m v^2\right)[/tex]
[tex]=-\left(17 \times 10^{-3} \times 9.8 \times 5.3-\frac{1}{2} \times 17 \times 10^{-3} \times(1-3)^2\right) \\& =-\left(882.98 \times 10^{-3}-14.365 \times 10^{-3}\right) \\& =-0.868 \mathrm{~J}[/tex]
Forces = -0.868 joules.
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A laser used to weld detached retinas emits light with a wavelength of 658 nm in pulses that are 25.0 ms in duration. The average power expended during each pulse is 0.600 W.1) How much energy is in each pulse, in joules?2)How much energy is in each pulse, in electron volts?3)What is the energy of one photon in joules?4)What is the energy of one photon in electron volts?5)How many photons are in each pulse?
1) The energy in each pulse is 15 × [tex]10^{-3}[/tex] J 2) The energy in each pulse is E is 9.375 × [tex]10^{16}[/tex] eV 3) The energy of each photon in electron volt is 3.303 ×[tex]10^{-19}[/tex] J.
Wave length of the light λ = 658 nm = 658 × [tex]10^{-9}[/tex]
Time t = 25 ms = 25 × [tex]10^{-3}[/tex]
The energy in each pulse is E = power × time = (0.600) × ( 25 × [tex]10^{-3}[/tex])
E = 15 × [tex]10^{-3}[/tex] J
The energy in each pulse is E = 15 × [tex]10^{-3}[/tex] J = 9.375 × [tex]10^{16}[/tex] eV
The energy of each photon in electron volt is,
E = hc/V = (6.625 × [tex]10^{-34}[/tex]) ( 3 ×[tex]10^{8}[/tex]) / 658 × [tex]10^{-9}[/tex] = 3.303 ×[tex]10^{-19}[/tex] J
The energy of the photon in electron volts is
E = 3.303 ×[tex]10^{-19}[/tex] J = 3.303 ×[tex]10^{-19}[/tex] J(1/1.6 × [tex]10^{-19}[/tex] = 2.06 eV
Energy is characterized as having the "ability to accomplish work, which is the capacity to apply a force sufficient to move an object." Despite this unclear definition, the concept is actually quite straightforward: energy is just the force that moves objects. Potential and kinetic energy are the two different categories. The best approach to understand them is to think of potential energy as occurring before an action and kinetic energy as occurring during an action. Consider raising your physics textbook in the air. Simply due of its elevated elevation, it could fall. If you drop the textbook, the potential energy is converted into kinetic energy, which is the energy that drives the movement.
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beats: the little brown bat is a common bat species in north america. it emits echolocation pulses at a frequency of 40 khz, well above the range of human hearing. to allow observers to "hear" these bats, an electronic bat detector combines the bat’s sound wave at a frequency f 1 with a wave of frequency f 2 from a tunable oscillator. the resulting beat frequency is isolated, amplified, and then played through a speaker. to what frequency f 2 should the oscillator be set in order to produce an audible beat frequency of 3.0 khz? hint: there are two possible oscillator frequencies
Beyond the audible range of humans, most bat echolocation occurs. Depending on their age, people have a hearing range of 20 Hz to 15-20 kHz. 9 kHz to 200 kHz is the frequency range for bat calls.
What is Bat Echolocation?Bats are able to see just as well as humans, but they have developed an advanced echolocation technique that allows them to move around and find food in the dark. Using their mouth or nose to emit high frequency sound pulses and listening for the echoes, bats use echolocation to find prey. The bat uses this echo to assess the size, shape, and texture of objects in its environment. Bat echolocation is so advanced that these animals can find something as small as a human hair.Shouting bats and whispering bats are two general descriptions of bats based on their echolocation calls. If we could hear them, big brown bats and little brown bats would be shouting at 110 decibels, which is about as loud as a smoke alarm. Northern long-eared bats have 60 decibel whispering voices. While whisperers collect insects from tree foliage and forage in the crowded conditions of forest interiors, shouters typically hunt for food in open areas.To Learn more About bat echolocation refer to:
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does the pa-28 have an alternate static source? if so, how is it activated and what actions are necessary to acquire the most accurate reading?
Optional equipment includes an alternate static source.
What is alternate static source?When the alternate static source is used, the instrument indications should differ as follows: The altimeter will show a higher altitude than the actual altitude, and the airspeed will show a higher speed than the actual airspeed.The airspeed will be higher than the actual speed. The altimeter will show a marginally higher altitude.Whenever the primary source of static air pressure is unavailable, use the alternate static air source.The most important rule to remember when using an alternate static air source is to always consult the owner's manual, POH, or AFM for information and limitations.The alternate static air source is simple to test. Activate the system with the appropriate control and monitor the VSI and altimeter for changes. As the lower static air pressure enters the system, the VSI will rise briefly and the altimeter will rise a few feet.To learn more about alternate static source refer to :
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as an ideal fluid flows vertically upward through a uniform (constant radius) pipe, what happens to the fluid speed and fluid pressure?
A pipe's pressure is essentially comprised of two pressures: a kinetic pressure that is measured in the flow's center and a static pressure that is determined precisely at the pipe wall's interior.
What means fluid pressure?the force a fluid applies to any point inside of it. The sum of the difference in height, their density, and the rate of free fall determines the difference in pressure between two levels.
Why does fluid pressure exist?Similar to the air from the inside of a tire, all liquids exert pressure. Fluid particles constantly and randomly move in all directions. The particles constantly collide with one another and anything else that crosses their path as they advance. Pressure is produced by these impacts, and it is applied uniformly in all directions.
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block a has weight of 40 lb and vlock b has weight of 8 lb.the coefficient of kinetic friction between all surfaces of contact is u_k = 0.15. Knowing theta = 20 and P = 50 lb, determine (a) the acceleration of block B, (b) the tension in the cord.
The acceleration of block B is 0.5 and tension is 42.8 lb.
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
mass = 40 lb
u_k = 0.15.
P = 50 lb
theta = 10
Length of the rope
L=s + s+ Constant + s,
differentiate with respect to time
0=2a,+a,
a = 2a, (magnitude only)
a=0.5
At equilibrium, V = 0
N =40 + 8
N = 48 lb
K=μk
f, =0.15%48 = 7.2 1b
D Alembert principle
Σ F x = ma
P-T-T-f₁ = (40+8/32.2)a
50 - 2T - 7.2 = 1.4907a
2T +1.4907a, = 42.8
2T +1.4907x0.5a, = 42.8 lb
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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