An F-1 ____________ may be authorized by the DSO to participate in a curricular practical training program that is an__________ part of an established curriculum. Curricular practical training is defined to be alternative work/study, internship, cooperative education, or any other type of required internship or practicum that is offered by sponsoring employers through cooperative _____________ with the school. Students who have received one year or more of full time curricular practical training are ineligible for post-completion academic training. Exceptions to the one academic year requirement are provided for students enrolled in _____________ studies that require immediate participation in curricular practical training. A request for authorization for curricular practical training must be made to the DSO. A student may begin curricular practical training only after receiving his or her Form I-20 with the __________ endorsement.

Answer:

The factors to consider when building a solution for optical workflow for car accident are the type of claim to be modelled, also to examine the level of automation in vehicles.

Some of the software solutions that meet the requirements are the A1 Tracker  which is very effective to the enterprise business and small business working with insurance. we also have the Mutual expert, Ninja Quote.

Explanation:

Solution

In suggesting an optical workflow for the car accident claim process it is of importance to understand the following factors such as, the type of claim to be modelled, it will be determined by the policy that the clients have for their cars. this will assist in classifying the workflow and giving a clear path of the design.

The number of expected claims is also a very important factor that should be added in the design. Another important factor to examine  the level of automation of the vehicles, this can be very useful in collecting the accident data in a more efficient way and also making it simple to design the model.

Presently there are several workflow softwares in the insurance that have encouraged a great deal and have made the workflow in the insurance companies more greater.

Some of the soft wares are the A1 Tracker  which are very effective and efficient in are highly applicable to the enterprise business and small business working with insurance, the software is convenient in monitoring the work progress in the company.

The other soft wares that have been quite useful in the industry for example the Insly, ISI enterprise, Mutual expert, Ninja Quoter among others. These software are some of the best soft wares available in the market that have met the workflow requirement in the insurance sector.

Answer:

true

Explanation:

else if used so I think it's true

Answer:

it's a

Explanation:

Answer:

The program is written in python and it doesn't make use of any comment;

(See explanation section for line by line explanation)

def getN(num):

     fact = 1

     for i in range(1, 1 + num):

           fact = fact * i

     print("Factorial: ",fact)

num = int(input("Number: "))

if num < 0:

     print("Invalid")

else:

     getN(num)

Explanation:

The function getNum is defined here

def getN(num):

Initialize the result of the factorial to 1

     fact = 1

Get an iteration from 1 to the user input number

     for i in range(1, 1 + num):

Multiply each number that makes the iteration

           fact = fact * i

Print result

     print("Factorial: ",fact)

Ths line prompts user to input number

num = int(input("Number: "))

This line checks if user input is less than 0; If yes, the program prints "Invalid"

if num < 0:

     print("Invalid")

If otherwise, the program calls the getN function

else:

     getN(num)

Answer:

In this sense, the different types of computers would range from Desktop to Laptops, to iPads, then Mobile Phones. Somewhere in-between the phone and the iPad is the phablet.

A phablet is a group of mobile devices with the combined functionality and size of a smartphone and a tablet.

On the balance of probabilities, Jan is trying to replace her laptop.

Cheers!

Answer:

The overview including its problem is listed in the explanation segment following.

Explanation:

The subsequent weather system seems to be close to something like a moving warmer front.

So that the above seems to be the right answer.

Hi there! Hopefully this helps!

--------------------------------------------------------------------------------------------------

The answer is A, testing the circuit at the power source.

Answer:

The programming language is not stated;

However, I'll answer this question using Java Programming Language;

The method is as follows;

   public static void isPalindrome(String userinput)

    {

       String reverse = "";

       int lent = userinput.length();

int j = lent - 1;

while(j >= 0)

       {

           reverse = reverse + userinput.charAt(j);

           j--;

       }

       if(reverse.equalsIgnoreCase(userinput))

       {

           System.out.println("True");

       }

       else

       {

           System.out.println("False");

       }    

    }

Explanation:

This line defines the method isPalindrome with a string parameter userinput

public static void isPalindrome(String userinput) {

This line initializes a string variable

       String reverse = "";

This line gets the length of the userinput

       int len = userinput.length();

The following while-loop gets the reverse of userinput and saved the reversed string in reverse

int j = lent - 1;

while(j >= 0)

       {

           reverse = reverse + userinput.charAt(j);

           j--;

       }

The following if statement checks if userinput and reverse are equal (cases are ignored)

       if(reverse.equalsIgnoreCase(userinput))

       {

           System.out.println("True"); This line is executed if the if condition is true

       }

       else

       {

           System.out.println("False"); This line is executed if otherwise

       }  

    } The method ends here

Answer:

=OR(B2>=60, C2>=60)

Explanation:

If you want to check if at least one of the scores is equal to or greater than 60, you should use the OR function. The OR function tests multiple conditions and returns TRUE if at least one is met. Therefore, the function in cell D2 would be:

= OR(B2>=60, C2>=60)

In other to obtain the boolean value True if one of two or more conditions are met, the OR operator is used. Hence, the appropriate function is =OR(B2>=60, C2>=60)

Hence, the appropriate function is =OR(B2>=60, C2>=60).

Learn more : https://brainly.com/question/20702793

Answer:

c is the answer I'm pretty sure but wait for more

Answer:

3. Timestamp and Validation schedulers guarantee serializability.

Explanation:

Timestamp is a sequence of information encoded when a certain event occurs at a given time that information is decoded and message is identified. Time schedulers is optimistic scheduler and it removes physically unrealizable behavior. Timestamp cannot guarantee serializability.  It can detect unrealizable behavior.

Answer:

d) 0 1 1 2

The above piece of code prints the Fibonacci series.

Explanation:

def a(n):

   if n == 0:

       return 0

   elif n == 1:

       return 1

   else:

       return a(n-1)+a(n-2)

for i in range(0,4):

   print(a(i),end=" ")

Answer:

a) struct GroceryItem{

string name;

float cost;  };

b) GroceryItem apple;

apple.name = "Granny Smith";

apple.cost = 0.79;

c) GroceryItem inventory[20];

d) inventory[5].name = "Cheese";

   inventory[10].cost = 3.50;

Explanation:

a) GroceryItem is the name of the structure and struct is a keyword which is used to create GroceryItem structure.

The structure has two members one is name of type string which means its holds the name strings of items. The other is cost which is a float type variable which supports floating point numbers and its holds the cost of item.

b) GroceryItem apple statement means that a variable apple is created which is of type GroceryItem

apple.name = "Granny Smith" This statement uses the apple to access the member variable name of GroceryItem  structure and sets the apples's name to Granny Smith.  The dot between apple variable and member variable name is basically used to access the member variable name of GroceryItem .  

apple.cost = 0.79; This statement uses the apple variable to access the member variable cost of GroceryItem  structure in order to set the apples's cost to 0.79.  The dot between apple variable and member variable cost is basically used to access the member variable cost of structure.

c) GroceryItem inventory[20];  This statement creates an array of GroceryItem structure. The array name is inventory and [20] is basically specifies the size of this array which is 20.

d) inventory[5].name = "Cheese";  This statement uses inventory array and access the name member of the structure GroceryItem to set the name of the 6th GroceryItem in inventory array to "Cheese". .Here [5] is the index of the 6th item of the inventory array as the array locations start from 0. So inventory[20] can contains 20 elements from 0 index to 19 index. So to set the name of 6th item 5th index is specified.

inventory[10].cost = 3.50;  This statement uses inventory array and access the cost member of the structure GroceryItem to set the cost of the 11th GroceryItem in inventory array to "3.50". Here [10] is the index of the 11th item of the inventory array as the array locations start from 0. So inventory[20] can contains 20 elements from 0 index to 19 index. So to set the cost of 11th item 10th index is specified

Answer:

Option A (Implementing a site-to-site VPN for server access) seems to be the correct choice.

Explanation:

Other choices are not related to the given instance. So that Option A would be the right one.

Answer:

a. Remove the affected servers from the network.

Explanation:

An organization's incident response process (IRP) can be defined as all of the process involved in the cleanup and recovery of data when they fall victim to an attack or cybersecurity breach. The incident response process comprises of six (6) important stages and these are;

1. Preparation.

2. Detection and analysis (identification).

3. Containment.

4. Eradication.

5. Recovery.

6. Review of incident activities.

When an organization's IRP prioritizes containment over eradication and an incident is discovered, where an attacker outside the organization installed a crypto-currency mining software on the organization's web servers. Given the organization's stated priorities, the cybersecurity engineer should remove the affected servers from the network.

A containment process is focused on taking steps to eliminate or contain the attack. It basically involves acting swiftly in response to the attack, so as to prevent it from spreading across board or in order to mitigate the damage already caused.

In this context, the cybersecurity engineer should remove the affected servers from the network in accordance with the organization's IRP priority (containment).

Furthermore, he could take a step further to contain the attack by installing a firewall and updating their policies in the Intrusion Prevention System (IPS) of the organization.

Answer:

Here are the stub functions get_user_num() and compute_avg()

def get_user_num():

   print('FIXME: Finish get_user_num()')

   return -1  

def compute_avg(user_num1, user_num2):

   print('FIXME: Finish compute_avg()')

   return -1

Explanation:

A stub is a small function or a piece of code which is sometimes used in program to test a function before its fully implemented. It can also be used for a longer program that is to be loaded later. It is also used for a long function or program that is remotely located. It is used to test or simulate the functionality of the program.  

The first stub for the function get_user_num() displays FIXME: Finish get_user_num() and then it returns -1.

The seconds stub for the function compute_avg() displays the FIXME: Finish compute_avg() and then it returns -1.

Here with each print statement, there is function name after this FIXME: Finish line. The first function name is get_user_num and the second is compute_avg().

Next the function get_user_num() is called twice and function compute_avg() followed by a print statement: print('Avg:', avg_result) which prints the result. So the program as a whole is given below:

def get_user_num():

   print('FIXME: Finish get_user_num()')

   return -1  

def compute_avg(user_num1, user_num2):

   print('FIXME: Finish compute_avg()')

   return -1  

user_num1 = 0  # the variables are initialized to 0

user_num2 = 0

avg_result = 0  

user_num1 = get_user_num()  #calls get_user_num method

user_num2 = get_user_num()

avg_result = compute_avg(user_num1, user_num2)  

print('Avg:', avg_result)

The method get_user_num() is called twice so the line FIXME: Finish get_user_num() is printed twice on the output screen. The method compute_avg() is called once in this statement avg_result = compute_avg(user_num1, user_num2)   so the line FIXME: Finish compute_avg() is printed once on the output screen. Next the statement print('Avg:', avg_result) displays Avg: -1. You can see in the above program that avg_result = compute_avg(user_num1, user_num2)   and compute_avg function returns -1 so Avg= -1. The program along with the produced outcome is attached.

Answer:

Are highly portable.

Explanation:

Java is a object oriented and class-based programming language. It was developed by Sun Microsystems on the 23rd of May, 1995.

Java was designed by a software engineer called James Gosling and it is originally owned by Oracle. Also, worthy of mention is the fact that Java was originally known as Oak.

Generally, Java as a software application usually are developed having a ".jar", ".class" or ".java" filename extensions.

Because Java byte code is the same on all computers, compiled Java programs are highly portable. This simply means that, the Java byte code was designed such that it has very few implementation dependency, thus, once the code is written, it can run on all computer platforms that supports the Java programming language.

Hence, the Java byte code is a write once, run anywhere software program.

The Java byte code instructions are read and executed by a computer program known as a Java Virtual Machine (JVM).

Additionally, Java program is used for developing varieties of applications such as, mobile, desktop, games, web and application servers etc.

Answer:

(a). as the combination of IP address and port number to allow an application within a computer to set up a connection with another application in another computer without ambiguity.

Explanation:

The explanation is in the answer.

Answer:

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

Answer:

i will send you the answers in the next 10minute

Explanation:

In my opinion this is computer assisted legal search

Answer:  

I am writing a Python program:

For taking input from user:

user_input = input() # takes input from user

short_names = user_input.split() #splits user_input into list of strings

short_names.pop(0) # removes the first element of the list i.e. Gertrude

short_names[-1] = "Joe" #sets the last element to Joe

print(short_names)    #prints modified list of Sam Ann Joe

If you do not want to take input from user:  

short_names=['Gertrude', 'Sam', 'Ann', 'Joseph']  #list of 4 elements

short_names=short_names[1:]  # removes the first element Gertrude

short_names.pop()  # removes last element i.e. Joseph from list

short_names.append('Joe')  #adds Joe to the end of the list

print(short_names) #prints modified list Sam Ann Joe

If you do not want to use pop() and append() methods:

short_names = ['Gertrude', 'Sam', 'Ann', 'Joseph']  #creates list of 4 values

short_names = short_names[1:]  # removes first value i.e. Gertrude from list

short_names[-1] = "Joe"  #set the last element to Joe

print(short_names) #prints modified list Sam Ann Joe

Explanation:

The first program takes the names from the user, splits them into list of strings, then pop(0) has given index value 0 which means 1st value in the list. So it removes and returns first value from the list. Next statement sets the last value of list to Joe.

The second program has a hard coded list ['Gertrude', 'Sam', 'Ann', 'Joseph']  

short_names = short_names[1:] removes the first value of the short_names list i.e. Gertrude. Next pop() removes and returns last value in the list i.e. Joseph from list. Last statement append('Joe') adds Joe to the end of the list.

The third program has a list of 4 elements. short_names = short_names[1:]   removes first value i.e. Gertrude from list and short_names[-1] = "Joe"  sets the last element to Joe.

The function was implemented using the JavaScript language, the shift, pop and push function was used to get the desired output

The function bellow is written in JavaScript

function shortName (short_names){

short_names.shift() // The first element "Gertrude" was removed

short_names.pop() //The last element "Joseph" was removes

short_names.push("joe") //"Joe" is added to the new list

return short_names //The new list is returned as output

}

Learn more about array operation here:

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Answer:

the answer is A avoid drinking 10 Tips to Avoid Driving Drunk

Explanation:

Give someone your keys. Find someone trustworthy who isn't drinking and hand over your keys for the night. ...

Don't drink on an empty stomach. ...

Know your body and pace yourself. ...

Take public transit. ...

Spend the night. ...

Wait an hour or two. ...

Stop drinking 90 minutes before you plan to leave. ...

Take the night off from drinking. hope this helps you :)

Answer:

Explanation:

Given that:

number of surfaces on a hard disk = 4

number of sectors = 2048 sectors

number of tracks per surface = 131, 072 (2^17)

a block holds 512 bytes.

Since, 'The disk is not "zoned.".....

then, Number of bytes / sector = 512

a) What is the total capacity of this disk?

The total capacity of the disk is:[tex]= 4 \ surfaces \times 131072 \dfrac{tracks}{surfaces} \times 2048 \dfrac{sector}{tracks} \times 512 \dfrac{bytes}{sector}[/tex]

[tex]= 5.49755814\times 10^{11} \ bytes[/tex]

= 549755814 KB ( kilobytes)

= 549755.814 MB (megabytes)

=549.755814  GB (gigabytes)

b. Given the disk in Part 1, how much data can be accessed without moving the disk heads. (i.e what is the capacity of one cylinder?)

The capacity of one cylinder can be estimated by determining the capacity of one surface and the capacity of one track.

The capacity of one surface = [tex]131072\dfrac{tracks}{surface} \times 2048 \dfrac{sector}{tracks} \times 512\dfrac{bytes}{sector}[/tex]

The capacity of one surface = [tex]1.37438953 \times 10^{11[/tex] byte = 137.44 GB

Capacity of one track = 2048 sectors/track × 512 bytes/sector

Capacity of one track = 1048576 Bytes/track

Capacity of one track =1048 KB/track

Capacity of one track ≅ 1 MB/track

Since the hard disk contains four surfaces

∴

capacity of one cylinder = 1 MB/track × 4 track/cylinder

capacity of one cylinder  = 4 MB

Answer:

Here is the SwapArrayEnds()

//function with two parameters; the array and array size

void SwapArrayEnds(int sortArray[],int SORT_ARR_SIZE){  

int temp;   //temporary variable to hold the first element of sortArray

if(SORT_ARR_SIZE > 1){   //if sortArray size is greater than 1

temp = sortArray[0];   // set value of temp to the first element of sortArrray

sortArray[0] = sortArray[SORT_ARR_SIZE-1];   // set the value of first element of sortArray to the last element of sortArray

sortArray[SORT_ARR_SIZE-1] = temp;  }  } // set last element  value to temp

Explanation:

Lets understand the working of the above function with the help of an example. Suppose the sortArray has the following elements: {10,20,30,40}. So the size of this array is 4.

if(SORT_ARR_SIZE > 1) has an if statement which checks if the array size is greater than 1. This condition evaluates to true as 4 > 1. So the body of if condition executes.

Next the statement temp = sortArray[0];   sets the value of temp variable to the value of first element of sortArray. As sortArray[0] means the element at 0-th index position of the sortArray. So using the above example the first element of the array is 10. So temp = 10.

Next the statement sortArray[0] = sortArray[SORT_ARR_SIZE-1];   sets the last element of the sortArray to the position of first element of the sortArray.

SORT_ARR_SIZE-1 is the position of last element of the array. As the size of sortArray is 4, so 4-1 = 3 which points to the last element. Now this element is moved to the first position of the array. This means that the value of first element of array becomes 40 as the element at 3-th index of the sortArray is 40.

Next the statement sortArray[SORT_ARR_SIZE-1] = temp moves the value in temp variable to the last position of the sortArray. As we know that the value of temp= 10. So this element 10 of the sortArray is positioned at SORT_ARR_SIZE-1 position of sortArray which is 4-1 = 3-th index of sortArray. This simply means that 10 is moved to the last position of sortArray.

So now the final sortArray becomes: 40,20,30,10 as the first and last element of the array are swapped using above function SwapArrayEnds().

The program along with the output is attached in screenshot.

Functions are collection of codes or instructions merged together to act as one.

The function, where comments are used to explain each line is as follows:

//This defines the function

void SwapArrayEnds(int sortArray[],int SORT_ARR_SIZE){  

//This increments the array element at index 0

       sortArray[0] += sortArray[SORT_ARR_SIZE-1];

//This replaces the last element with the first

       sortArray[SORT_ARR_SIZE-1]= sortArray[0]- sortArray[SORT_ARR_SIZE-1];

//This replaces the first element with the last

       sortArray[0]= sortArray[0]- sortArray[SORT_ARR_SIZE-1];

}

At the end of the function, the first and the last elements of the array are swapped.

Read more about similar programs at:

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Answer:

The Encryption solution that best prevents a competitor from receiving confidential information is the SSL(secure Socket Layer) Or TLS(Transport Layer Security).

Explanation:

Solution:

From my own perspective the encryption solution that i will use that prevents s a competitor from receiving confidential information and justify the recommendation is the SSL(secure Socket Layer) Or TLS(Transport Layer Security).

This is because in this case we have to share data confidentially (information need to be hidden from Unauthorized  security access. also these provides the Transport Layer security that we needed in above example above.

The purpose of these protocol is to provide server and client authentication, Data confidentiality,and Data integrity (protected from unauthorized change). Application Layer client/server program such as HTTP that uses the service of TCP can encapsulate their data in SSL Packets.

SSL (Secure Socket Layer): is defined as the normal technology for protecting an internet connection secure and defend any sensitive data that is being sent between two systems, and not allowing criminals from reading and changing any information sent, including potential personal details.

TLS (Transport Layer security): It is a procedure that allows  data integrity  and privacy over Internet communications.

Answer:

Following are the algorithm to this question:

y = 0 //  initialize variable y that assigns the value  0

p = 1 // initialize value 1 in the variable p which also known as starting position

init num = 1//define variable num that assign value 1

for j = 1 to n: //defining loop

y = m[j] - m[p]

if (y > 10) //defining if block

num++;  //increment num variable

p=i; //holding loop value in p variable

y= 0//assign value 0 in y variable

Explanation:

Following are the runtime analysis of the above-given algorithm:

The above-provided algorithm is greedy, but if it doesn't exceed the scope, it operates by greedily choosing its next object. Therefore the algorithm selects the fewest number of pens.

Running time:

This algorithm merely iterates once over all the points. The run-time is therefore O(n).

Question:

"The correct syntax for passing an array as an argument to a method when a method is called and an array is passed to it is: "

A) a[0]..a[a.length]

B) a()

C) a

D) a[]  

Answer:

The correct answer is A.

An example is given in the attachment.

Cheers!

Answer:

Following are the answer to this question:

Explanation:

A)

The memory size is 1 Giga Bytes which is equal to [tex]2^{30}[/tex]

[tex]\texttt{Number of address bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ Number of addresses}\\\\ \ \ \ \ 30 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2^{30}= 1073741824[/tex]

B) [tex]\texttt{I \ \ \ Opcode \ \ \ Register address \ \ \ Immediate operand \ \ \ Memory address}\\\\\\\textt{1 \ bit \ \ \ \ \ \ 128 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 24 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 30 \ bits}\\\\\\[/tex]            [tex]= 2^7 \\\\ = 7 \ bits[/tex]

calculating the register Bits:

[tex]= 64-(1+7+24+30)\\\\=64 -62\ \ bits\\\\= 2\ \ bits\\[/tex]

C)

Immediate value size while merging the additional benefit with the address field:

[tex]= 2^{24} + 2^{30}\\\\= 2^{54}\\\\[/tex][tex]\texttt{Range before combining(-,+) 24 bits \ \ \ \ \ \ Range after combining( -,+)54bits}\\\\[/tex]                         [tex]\textt{-2^{12} from + (2^{12}-1) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -2^{27} from + (2^{27}- 1)}[/tex]

[tex]= \frac{24}{2} = 12\\\\= \frac{54}{2} = 27[/tex]

The range is accomplished by dividing the bits by 2 into the two sides of the o and the number is one short to 0.

Answer:

I am writing a Python program:

def string_type(string):

   if string=="":  //if the string is empty

       return "empty"

   elif string.count(".")>1:  #if the period sign occurs more than once in string

       if string.count("\n"):  #checks if the new line occurs in the string

           return "page"  #if both the above cases are true then its a page

       return "paragraph"  # if the period sign condition is true then its a para

   elif string.count(" ")>=1:  #if no of spaces in string occur more than once

       return "sentence"  #returns sentence

   elif len(string)==1:  # if length of the string is 1 this

       return "character"  #returns character

   else:  #if none of the above conditions is true then its a word

       return "word" #returns word

Explanation:

def string_type(string):  this is the definition of method string_type which takes a string as argument and determines whether the type of string is a word, paragraph, page, sentence or empty.

if string=="" this if condition checks if the string is empty. If this condition is true then the method returns "empty"

elif string.count(".")>1  This condition checks if the string type is a paragragh

string.count(".")>1   and if string.count("\n") both statements check if the string type is a page.

Here the count() method is used which is used to return the number of times a specified string or character appears in the given string.

Suppose the string is "Paragraphs need to have multiple sentences. It's true.\n However, two is enough. Yes, two sentences can make a paragraph."

The if condition first checks if count(".")>1 which means it counts the occurrence of period i.e. "." in the string. If the period occurs more than once this means it could be a page. But it could also be a paragraph so in order to determine the correct string type another if statement if string.count("\n") inside elif statement determines if the string is a page or not. This statement checks the number of times a new line appears in the string. So this distinguishes the string type paragraph from string type page.

elif string.count(" ")>=1: statement determines if the string is a sentence. For example if the string is "i love to eat apples." count() method counts the number of times " " space appears in the string. If the space appears more than once this means this cannot be a single word or a character and it has more than one words. So this means its a sentence.

  elif len(string)==1:  this else if condition checks the length of the string. If the length of the string is 1 this means the string only has a single character. Suppose string is "!" Then the len (string) = 1 as it only contains exclamation mark character. So the method returns "character" . If none of the above if and elif conditions evaluates to true then this means the string type is a word.

Answer:

def string_type(string):

  if string=="":  //if the string is empty

      return "empty"

  elif string.count(".")>1:  #if the period sign occurs more than once in string

      if string.count("\n"):  #checks if the new line occurs in the string

          return "page"  #if both the above cases are true then its a page

      return "paragraph"  # if the period sign condition is true then its a para

  elif string.count(" ")>=1:  #if no of spaces in string occur more than once

      return "sentence"  #returns sentence

Explanation: