In an explosion a 6 g piece comes out of the right end and a 4 g piece comes out of the left end at twice the speed of the 6 g piece and the third piece comes out of the right end.
Initially all three balls are at rest so u = 0
Given m1 = 6g and m2=4g where m is the mass of balls
Let v1 be the velocity of the first ball = v(i) (denoted as (i) since the right end points to the positive X axis)
Let velocity v2 of second ball = 2(v)(-i) (denoted as (-i) since left end points negative X axis)
Mass of the third ball m3 = m and its velocity v3 = v'
By applying conservation of momentum
m1(u1) + m2(u2) + m3(u3) = m1(v1) + m2(v2) + m3(v3)
Since all balls are initially at rest u1 = u2 = u3 = u = 0
0 = (6×10⁻³)(v)(i) + (4×10⁻³)(2v)(-i) + m(v')
m(v') = (2×10⁻³)(v)(i)
v’ = (2×10⁻³)(v)(i)/(m)
So positive (i) indicates right end
So the third ball comes from the right end.
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a substance absorbs wavelengths of light in the range of 550 - 750 nm. a) approximately what wavelength range in the visible region is being transmitted?
The wavelengths of visible light are really not interfere constructively affected with by reflected waves.
What does constructive interference entail?When the maximum of two waves are combined together in a way that makes the amplitude of the resulting constructive wave equal to the sum of the separate waves, this is known as constructive interference, or doppler effect is the interference.
Briefing :
The constructive interference for two waves, in same phase can be find out as,
λ = [tex]\frac{2'nd}{m}[/tex]
Here, m=1,2,3,....
The range of wavelengths of visible light given from 550 nm to 750 nm. It has to be found out that, for which visible wavelengths of light, do the reflected waves interfere constructively,
Visible wavelength of light is a range of electromagnetic spectrum, which can be visible by human eyes. This ranges from 550 nm to 700 nm (approx). In the problem given, the range of wavelengths of visible light is from 550 nm to 750 nm.
Put the value of the 2nd wavelength (750 nm) in the above formula for m equal to 1 as,
λ = [tex]\frac{750}{1}[/tex]
λ = 750nm
For m equal to 2,
λ =[tex]\frac{750}{2}[/tex]
λ = 375nm
Both the values does not fall under the range of visible light. Hence, The visible wavelengths of light do not reflected waves interfere constructively.
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an object of mass m is launched at speed at angle with respect to the horizontal from a height h. find the horizontal velocity component when the object is at its maximum height g
The horizontal velocity component when the object is at its maximum height Hmax = [tex]u^{2} sin^{2}[/tex]θ /2g
The vertical and horizontal components of motion are separated into two parts for solving velocity problems in physics. When solving problems involving a trajectory's angle, vertical velocity is used. When an object moves horizontally, its horizontal velocity becomes crucial. Any mathematical solution will consider the horizontal and vertical elements independently because they are not reliant on one another. Horizontal velocity, which can be expressed in terms of meters per second or miles per hour, is typically defined as horizontal displacement divided by time. The distance that an object has traveled since leaving a starting position is known as displacement.
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for a current ratio with a value greater than or equal to 1.0, the current ratio will increase if:
If a company's current ratio is larger than 1, it implies that its current liabilities exceed its current assets; conversely, if it is or less 1, it means that its current assets exceed its current liabilities.
What does an current ratio less than 1 indicate?If the ratio is less than 1, it means that the firm has more obligations due in the next year or less than it does in cash or other brief assets that are anticipated to be converted into money in the next year or less.
What ratio results from a reduction in current obligations and assets?Now The ratio would rise to 2.25:1 if current obligations and assets were both decreased by $1,000.
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Choose a device or machine that you use regularly. What do you do to make sure it works efficiently?
laptop is a device which is used regularly andto make it work properly we should follow some precautions.
what is the efficiency of a device?
The efficiency of a device is the proportion of the energy supplied that is transferred in useful ways. The work out of a device divided by the work into the device is defined as efficiency.
precautions to make laptop work efficiently
Always shut down your laptop when you are done with your work instead of in sleep mode.Always clean temp files from your laptop to make them more efficient.Keep up to date you have recommendedDon’t use unsecured websites it may risk your laptopPlace the laptop on some wooden or another material platform for better heat exchangeClean the screen and laptop so dust will not enter the processorRemove the battery plug when it is fully chargedUse the license version software instead of crack versionreduce heat lossTo know more about efficiency of the device, check out:
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how was the third law of motion discovered
Answer:
how was the third law of motion discovered
Explanation:
Isaac Newton discovered this law by exerting pressure on one object against another. The first object's force is felt and equally replicated by the second body. Thus, Isaac Newton proved that it's impossible to exert pressure on a single object without a similar reaction from the second object.
. an object is launched straight up into the air from the ground with an initial vertical velocity of 30 m/s. the object rises to a highest point approximately 45 m above the ground in 3 seconds; it then falls back to the ground in 3 more seconds, impacting with a speed of 30 m/s. (a) the average speed of the object during the 6-second interval is closest to (a) 0 m/s. (b) 5 m/s. (c) 15 m/s. (d) 30 m/s. (b) the magnitude of the average velocity during the 6-second interval is closest to (a) 0 m/s. (b) 5 m/s. (c) 15 m/s. (d) 30 m/s
In the first case, the average speed of the object is 15 m/s.
Hence, Option C is correct.
In the second case the average velocity is 0 m/s.
Hence, Option A is correct.
Explain
a) avg. speed=total distance travelled/total time taken.
which is (45+45)/(3+3)=15m/sec.
b)avg. velocity= total displacement/total time taken.
which is (45+(-45))/(3+3)=0 m/sec.
Here the -ve sign indicates the change in direction(opposite).
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a coin is placed on a flat, horizontal turntable which makes 3 revolutions in 3.14s. a. what is the speed of the coin when it rides without slipping at a distance of 5.0cm from the center of the turntable?
The speed of the coin when it rides without slipping at a distance of 5.0cm from the center of the turntable is 0.49 m/s.
No of revolutions made in 3.14s = 3rev
No of revolutions made in 1s = 3/3.14 = 0.96rev
Frequency = 0.96Hz
Time period T = 1/f = 1/0.96 = 1.05s
Angular velocity ω = 2π / T = 2π / 1.05 = 5.98 rad/s
Speed v = rω = 0.05 * 5.98 = 0.49m/s
The distance traveled rel.ative to the time it took to travel that distance is how fast s0mething is moving. As it just has a direction and no magnitude, speed is a scalar quantity. When an object travels an identical distance in an identical amount of time, it is said to be moving at uniform speed.
If an object travels a varied distance at regular intervals while maintaining the same speed, the speed is said to be variable.
Average speed is the average speed that is determined by the ratio of an object's total distance traveled to its total time traveled.
Instantaneous speed is the speed of an object while it is travelling at any given moment at a changeable pace.
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with what tension must a rope with length 2.10 mm and mass 0.120 kgkg be stretched for transverse waves of frequency 45.0 hzhz to have a wavelength of 0.790 mm ?
The tension of a rope of length 2.10 mm and mass 0.120 kg which is stretched for transverse waves of frequency 45.0 hzhz to have a wavelength of 0.790 mm is 51.4 N
What is frequency ?
The quantity of waves that pass a set location in a predetermined period of time is known as frequency.
From the given information -
length =2.10 mm
mass = 0.120 kg
frequency = 45.0 Hz
wavelength = 0.790 mm
V = sqrt (T/u)
V = 40 *0.79 = 31.6 m/s
T/u = 900
Tension = 900* 0.12/2.1
Tension = 51.4 N
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two horizontal forces act on a wagon, 150 n forward and 700 n backward. what force is needed to produce a net force of zero?
Answer: When two horizontal forces act on a wagon, 150 n forward and 700 n backward. 550 n force is needed to produce a net force of zero
Explanation:
According to Newton's first law of motion, unless pushed to alter its condition by the operation of an external force, every object will continue to be at rest or in uniform motion along a straight line.Net force is the sum of all the forces from all the direction which are applied on the object.For the net force to be zero two force from opposite direction should be equal so that they will cancel out each other.
150 N→ Wagon ←700
← 550
Net force in current state is 550 in backward direction.
So to cancel out the additional force, same amount of force has to be applied from the backward direction.
150 N+ 550 N → Wagon ←700 N ⇒ Net force = 0
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f. What happens if the Physics student is standing on ice?
g. What is the force between the student and the ground called?
Answer:
Explanation:
f. Student slips on ice
g. The force is called sliding friction force
who is responsible for testing electrical conductor insulation and keeping the test records?
The resistance to insulation is measured using an IR tester. This is a portable device that resembles an ohmmeter in many ways and has a built-in generator for creating a high DC voltage.
How do you test a conductor for insulation?An IR tester is used to assess insulation resistance. This is a portable device that resembles an ohmmeter in many ways and has a built-in generator for creating a high DC voltage. A current moves across the surface of the insulation as a result of the voltage, which is normally at least 500V.
Insulation testers evaluate the resistance in wires and motor windings using a high voltage, low current DC charge to find current leakage and defective or damaged insulation, which can result in arc faults, blown circuits, and the possibility of electrical shock or fire.
To help prevent risks like electric shock and short circuits created when the insulation in electrical devices, parts, and equipment is compromised, portable insulation resistance testers and megohmmeters are available.
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c) calculate the magnitude f of the force due to the water on a viewing port of the submarine at this depth if the viewing port has a surface area of 0.0100 m2.
If a submarine's viewing port has a surface area of 0.0100 m2, the force exerted by the water on it at this depth will be 416,000 N in magnitude.
Pgauge is equal to F/A 412(1.01 x 105) = F/0.01 F = 416,000 N.
The two fluid pressures that are in play are the internal atmospheric air pressure and the external water pressure, which includes the atmosphere operating on it at the surface. The net force due to fluid pressure can be calculated by using the gauge pressure of the water since the atmospheric pressure acts both internally and is also included in the water pressure and the air pressures virtually cancel each other out.
A force is an influence that has the power to alter how an object moves. A force can cause an object with mass to accelerate and change its velocity (for example, moving from a state of rest). Force can also be conce.ptualized as a push or a pull. A force is a vector quantity since it has b0th magnitude and direction. It is calculated using newtons as the SI unit of mea.sure (N). F stands for force (formerly P).
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comets travel around the sun in elliptical orbits with large eccentricities. if a comet has speed 2.0×104 m/s when at a distance of 2.4×1011 m from the center of the sun, what is its speed when at a distance of 5.2×1010 m . express your answer in meters per second.
Comets are small asteroid-like bodies when they are far from the Sun, traveling in highly ellipical orbits about the Sun. Comets go around the Sun in a highly elliptical orbit
How to find speed of a comet?
Speed of the comet can be determined by using conversation of energy = initial kinetic energy + initial potential energy of comet = final kinetic energy + final potential energy of comet
We know,
M = mass of sun = 1.989 x 1030 kg
m = mass of comet
vi = initial speed of comet = 20000 m/s
ri = initial distance from center of sun = 2.4 x 1011 m
vf = final speed of comet = ?
rf = final distance from center of sun = 5.2x 1010 m
Using conservation of energy
initial kinetic energy + initial potential energy of comet = final kinetic energy + final potential energy of comet
(0.5) m vi2 - GMm/ri = (0.5) m vf2 - GMm/rf
(0.5) vi2 - GM/ri = (0.5) vf2 - GM/rf
(0.5) (20000)2 - (6.67 x 10-11)(1.989 x 1030)/(2.4 x 1011) = (0.5) vf2 - (6.67 x 10-11)(1.989 x 1030)/(5.2x 1010)
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what is the allowable ampacity for each of the following conductors, if all conductors are to be installed in the same raceway? (assume all conductors to be current carrying thwn copper) qty: (2)
Ampacity can be calculated by dividing the Wattage by the rated voltage.
What is the ampacity of each conductor?
The highest continuous current that a conductor may carry under normal use settings without going above its temperature rating is known as ampacity. The unit of measurement for current is one amp. To avoid the wire overheating, you must choose the proper size wire for the circuit's current (load) requirements.
Divide the Wattage by the rated voltage to get the ampacity. The predicted Amperage of the circuit is the quotient. Many times, a circuit's particular application correction factors (as mentioned above) will make ampacity necessary.
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When a 0.650-kg mass oscillates on an ideal spring, the frequency is 1.95 Hz. What will the frequency be if 0.160 kg are added to the original mass? Try to solve this problem without finding the force constant of the spring.
The frequency will be 1.74 Hz if 0.160 kg are added to the original mass.
What is frequency?
In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.
After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration. See also basic harmonic motion and angular velocity.
Frequency (f) of a spring is inversely proportional to square root of its mass. So,
f₁√m₁ = f₂√m₂
⇒ f₂ = f₁√m₁ /√m₂
= 1.95√(0.650/0.810) Hz = 1.74 Hz.
Hence, the frequency will be 1.74 Hz if 0.160 kg are added to the original mass.
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the velocity of an object is given v(t), and the acceleration is given by a(t). what is the relationship between the total
The rate at which velocity changes is called acceleration. (Attensity exists when velocity varies.) If a moving object changes speed.
Why does time accelerate the rate at which velocity changes?
A motion's acceleration is the rate at which it changes from one velocity to another. A velocity's rate of change with respect to time is referred to as its acceleration. The amount and direction of acceleration are both properties of a vector quantity.
A change in velocity is known as what?
A velocity change's acceleration is measured. Acceleration is the measure of how quickly a velocity changes with time. The acceleration measure used in SI is M/s2.
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as an ideal fluid flows vertically upward through a uniform (constant radius) pipe, what happens to the fluid speed and fluid pressure?
A pipe's pressure is essentially comprised of two pressures: a kinetic pressure that is measured in the flow's center and a static pressure that is determined precisely at the pipe wall's interior.
What means fluid pressure?the force a fluid applies to any point inside of it. The sum of the difference in height, their density, and the rate of free fall determines the difference in pressure between two levels.
Why does fluid pressure exist?Similar to the air from the inside of a tire, all liquids exert pressure. Fluid particles constantly and randomly move in all directions. The particles constantly collide with one another and anything else that crosses their path as they advance. Pressure is produced by these impacts, and it is applied uniformly in all directions.
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4. what happens to the orbital period as the star-planet distance increases? why do you think there is a relationship?
If Moto moved farther from the star, its orbital speed would slow down and it would have a wider orbit to travel, increasing the orbital period.
Why does orbital period lengthen as we travel farther?Since the Sun's gravitational pull on a planet farther away is weaker, it not only travels a greater distance than a planet closest to it, but it also moves more slowly. Therefore, a planet takes longer to complete its orbit the larger it is.
What is orbital period of earth?As seen from above the Northern Hemisphere, the Earth circles the Sun at an average distance of 149.60 million kilometers (92.96 million miles), counterclockwise. In 365.256 days (1 sidereal year), the Earth completes one orbit, covering 940 million kilometers (584 million mi).
What is gravitational pull?The force that attracts all masses in the universe, particularly theat attracts all masses in the universe, particularly the earth's mass's attraction to anything close to its surface. Gravitation, gravitational force, and similar terms.
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an object is to the left of a thin lens. the lens forms an image on a screen that is 2.70 mm to the right of the object. the height of the image is 2.60 times the height of the object. part a is the image upright or inverted? is the image upright or inverted? the image is inverte
The image is inverted and real because the question tells us that the image was formed on a screen.
How to know if an image is real and inverted?When the rays come together, a true image is created. A virtual image is always formed above the principal axis, therefore it is always upright, as opposed to a real image, which is always formed below the principal axis and is always inverted.
An image that can be projected onto a screen is a real image. Behind the lens, a virtual image appears to emerge.
The image is inverted, magnified, and real for an object that is between one and two focal lengths from the lens.
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at what speed does a 1600 kg compact car have the same kinetic energy as a 20000 kg truck going 24 km/h ? express your answer in kilometers per hour.
A 1600 kilogram small vehicle and a 20 000 kg truck traveling at a speed of 84.74 km/h have same amounts of kinetic energy .
What causes kinetic energy to move?A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, gets done on it by exerting a net force.
Briefing :
Kinetic energy is that which is due to the movement of bodies and is calculated like this:
K = (1/2)mv² Formula (1)
Data for the truck
m = 20000 kg
v = 24 km/h
= 24 *(1000m)/ (3600s)
v = 6.66m/s
Calculation of the kinetic energy of the truck
We replace data in the formula (1)
K = (1/2)mv²
K = (1/2)(20000)(6.66)²
K = 443556J
Data for the compact car
K = 443556 J
= 443556 (N*m)
m = 1600 kg
Calculation of the speed of the compact car
We replace data in the formula (1)
K = (1/2)mv²
443556 = (1/2)( 1600)(v)²
443556 = ( 800)(v)²
v² = 443556/ (800)
[tex]v=\sqrt{\frac{443556}{800} }[/tex]
v = 23.54m/s
1 km = 1000 m
1 h = 3600 s
v =23.54*(3600/1000)km/h
v =84.74 km/h
Therefore , speed of car is is 84.74 km/h
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the image shows a pendulum that is released from rest at point a. an illustration of a pendulum at 5 different positions. the central position, the equilibrium position is labeled c. the two positions on the left are labeled a and b respectively. the two positions on the right are labeled d and e respectively. all positions are equally spaced. which pair of labels is correct? a: maximum kinetic energy c: maximum gravitational potential energy b: maximum kinetic energy d: maximum gravitational potential energy a: maximum gravitational potential energy c: maximum kinetic energy b: maximum gravitational potential energy d: maximum kinetic energy
The appropriate energy transformations are:
Kinetic energy changes into center of gravity from A to C.
Gravitational acceleration energy is converted into kinetic energy from C to E.
What is Kinetic energy?
Kinetic energy is a type of power that a moving object or particle possesses. An object gains kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. A moving object as well as particle has kinetic energy, which depends on both its mass and its rate of motion. Any combination of motions, including translation, rotation about in an axis, and vibration, may be the type of motion.
A body's translational kinetic energy, or 1/2mv2, is determined by multiplying its mass, m, by the square of it's own velocity, v.
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The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.
The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.terminal velocity is 0.8 N .
Simply put, what is terminal velocity?As a result, a object achieves terminal velocity when its acceleration (or deceleration) are zero and its speed is no longer increasing or decreasing.
What is the Earth's terminal velocity?around 53 m/s Unaffected by its mass, an item in free fall inside a vacuum would accelerate at a velocity of about 9.8 m/s2 close to the Earth's surface.When an object is dropped, air resistance causes it to finally achieve its terminal velocity, which for a human skydiver is about 53 m/s (190 km/h or 118 mph).
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beats: the little brown bat is a common bat species in north america. it emits echolocation pulses at a frequency of 40 khz, well above the range of human hearing. to allow observers to "hear" these bats, an electronic bat detector combines the bat’s sound wave at a frequency f 1 with a wave of frequency f 2 from a tunable oscillator. the resulting beat frequency is isolated, amplified, and then played through a speaker. to what frequency f 2 should the oscillator be set in order to produce an audible beat frequency of 3.0 khz? hint: there are two possible oscillator frequencies
Beyond the audible range of humans, most bat echolocation occurs. Depending on their age, people have a hearing range of 20 Hz to 15-20 kHz. 9 kHz to 200 kHz is the frequency range for bat calls.
What is Bat Echolocation?Bats are able to see just as well as humans, but they have developed an advanced echolocation technique that allows them to move around and find food in the dark. Using their mouth or nose to emit high frequency sound pulses and listening for the echoes, bats use echolocation to find prey. The bat uses this echo to assess the size, shape, and texture of objects in its environment. Bat echolocation is so advanced that these animals can find something as small as a human hair.Shouting bats and whispering bats are two general descriptions of bats based on their echolocation calls. If we could hear them, big brown bats and little brown bats would be shouting at 110 decibels, which is about as loud as a smoke alarm. Northern long-eared bats have 60 decibel whispering voices. While whisperers collect insects from tree foliage and forage in the crowded conditions of forest interiors, shouters typically hunt for food in open areas.To Learn more About bat echolocation refer to:
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A laser used to weld detached retinas emits light with a wavelength of 658 nm in pulses that are 25.0 ms in duration. The average power expended during each pulse is 0.600 W.1) How much energy is in each pulse, in joules?2)How much energy is in each pulse, in electron volts?3)What is the energy of one photon in joules?4)What is the energy of one photon in electron volts?5)How many photons are in each pulse?
1) The energy in each pulse is 15 × [tex]10^{-3}[/tex] J 2) The energy in each pulse is E is 9.375 × [tex]10^{16}[/tex] eV 3) The energy of each photon in electron volt is 3.303 ×[tex]10^{-19}[/tex] J.
Wave length of the light λ = 658 nm = 658 × [tex]10^{-9}[/tex]
Time t = 25 ms = 25 × [tex]10^{-3}[/tex]
The energy in each pulse is E = power × time = (0.600) × ( 25 × [tex]10^{-3}[/tex])
E = 15 × [tex]10^{-3}[/tex] J
The energy in each pulse is E = 15 × [tex]10^{-3}[/tex] J = 9.375 × [tex]10^{16}[/tex] eV
The energy of each photon in electron volt is,
E = hc/V = (6.625 × [tex]10^{-34}[/tex]) ( 3 ×[tex]10^{8}[/tex]) / 658 × [tex]10^{-9}[/tex] = 3.303 ×[tex]10^{-19}[/tex] J
The energy of the photon in electron volts is
E = 3.303 ×[tex]10^{-19}[/tex] J = 3.303 ×[tex]10^{-19}[/tex] J(1/1.6 × [tex]10^{-19}[/tex] = 2.06 eV
Energy is characterized as having the "ability to accomplish work, which is the capacity to apply a force sufficient to move an object." Despite this unclear definition, the concept is actually quite straightforward: energy is just the force that moves objects. Potential and kinetic energy are the two different categories. The best approach to understand them is to think of potential energy as occurring before an action and kinetic energy as occurring during an action. Consider raising your physics textbook in the air. Simply due of its elevated elevation, it could fall. If you drop the textbook, the potential energy is converted into kinetic energy, which is the energy that drives the movement.
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A hockey puck has a coefficient of kinetic friction of = .20. If the puck feels a normal force of 5 N, what is the frictional force that acts on the puck?
Answer: 5 N
Explanation:
Friction is a force that prevents two solid objects from rolling or sliding over one another. Although frictional forces, like the traction required to walk without slipping, may be advantageous, they also pose a significant amount of resistance to motion.
The given parameters;
coefficient of kinetic friction, μk = 0.1normal force of the puck, Fₙ = 5 NBy multiplying the normal force and the coefficient of kinetic friction, the frictional force acting on the puck is calculated.
The frictional force that acts on the puck is calculated as follows;
F= u*f
Substitute the given parameters in the above equation and solve the frictional force.
F=0.2*5
F= 1 N
Thus, the frictional force that acts on the puck is 1 N.
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estimate the amount of mass that is converted to energy when a proton combines with a deuterium nucleus to form 3he.
Answer:7.99
Explanation:
At what rate will a pendulum clock run on uranus, where the acceleration due to gravity is 9. 01 m/s2, if it keeps time accurately on earth? that is, find the time (in hours) it takes the clock's minute hand to make one revolution on uranus.
The time taken in hours for the clock's minute hand to make one revolution on Uranus is 0.0174 hours.
It is given to us that -
Acceleration due to gravity in Uranus = [tex]9.01 m/s^{2}[/tex]
Time on Earth = 1 minute = 0.0167 hours
We have to find out time taken in hours for the clock's minute hand to make one revolution on Uranus.
We know that period of oscillation observed in Earth can be given as -
[tex]T_{E}=2\pi \sqrt{\frac{l}{g_{E} } }[/tex] ----- (1)
where,
[tex]T_{E}[/tex] = 0.0167 hours (given)
[tex]l[/tex] = length of the pendulum
[tex]g_{E}[/tex] = acceleration due to gravity of Earth
According to the given information, the length of the pendulum will be equivalent on Uranus. This implies that the period of oscillation observed in Uranus can be given as -
[tex]T_{U}=2\pi \sqrt{\frac{l}{g_{U} } }[/tex] ----- (2)
where,
[tex]l[/tex] = length of the pendulum
[tex]g_{U}[/tex] = acceleration due to gravity of Uranus = [tex]9.01 m/s^{2}[/tex] (given)
Now, from equations (1) and (2),
[tex]\frac{T_{U} }{T_{E} }= \frac{ 2\pi \sqrt{\frac{l}{g_{U} } }}{2\pi \sqrt{\frac{l}{g_{E} } }} \\= > \frac{T_{U} }{T_{E} }=\sqrt{\frac{g_{E}}{g_{U} } } \\= > \frac{T_{U} }{0.0167 }=\sqrt{\frac{9.81}{9.01 } } \\= > T_{U} = 0.0167 * 1.0434\\ = > T_{U} =0.0174 hours[/tex]
Thus, the time taken in hours for the clock's minute hand to make one revolution on Uranus is 0.0174 hours.
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a noisy machine in a factory produces a decibel rating of 77 db. how many identical machines could you add to the factory without exceeding the 85 db limit?
A noisy machine in a factory produces a decibel rating of 77 dB. The Number of 10 machines add to the factory without exceeding the 85 db limit.
sound level in decibels is
β dB = 10 log ( I / I₀ )
where I is the intensity of sound
I₀ is the relative intensity
80 = 10 log ( I ÷ 10⁻¹² )
8 = log ( I ÷ 10⁻¹² )
10⁸ = I ÷ 10⁻¹²
I = 10⁸ × 10⁻¹² = 10⁻⁴ W /m2
if the sound level is 90 dB, the number of identical machines is n.
90 = 10 log ( n × I / I₀)
90 = 10 log ( n × 10⁻⁴ / 10⁻¹²)
9 = log ( n × 10⁸)
10⁹ = n × 10⁸
n = 10
Therefore, a number of 10 machines add to the factory without exceeding the 85 db limit.
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uniform circular motion what is the direction of the force that acts on the clothes in the spin cycle of a washing machine? what exerts the force?
The direction of the force that acts on clothes in the spin cycle of a washing machine is inwards. if the force would have been acting outwards then the clothes would have flown off, but this is not the case.
What is uniform circular motion?
when an object moves in a circle at a consistent speed in a motion, it is said to be in a uniform circular motion.
What is an example of uniform circular motion?
A satellite made by man is an example of uniform circular motion. Apart from that another example of uniform circular motion is a rotating ceiling fan, also a wheel of a moving car is an example of uniform circular motion.
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a particular am radio station broadcasts at a frequency of 1040 kilohertz. what is the wavelength of this electromagnetic radiation?
Answer:
1040 Kilohertz = 1.04E6 /sec
Speed of electromagnetic waves = 3.00E8 m/s
3.00E8 / 1.04E6 = 288 m (a λ/4 antenna still requires 72 m)