An envelope has an area of 40 square inches and a perimeter of 28 inches. What are the dimensions of the envelope?

Answer:

40

Step-by-step explanation:

the line in the middle shows the median

Answer:

952

Step-by-step explanation:

If you have anything else that has to do with donuts it goes straight to me.

Answer:

102 more donuts

Step-by-step explanation

when dealing with how much percent increase you multiply the amount by the percent in decimal form . So 850x0.12 is 102.

Answer:

Step-by-step explanation:

After enlargement,

Parallel  sides are: 6*3 = 18 cm  & 10*3 = 30cm

Altitude = 5 *3 = 15 cm

Area =[ (sum of the length of parallel sides)*height] ÷2

      [tex]= \frac{(18+30)*15}{2}\\= \frac{48*15}{2}\\\\= 24 *15\\\\= 360[/tex]

Answer:

360 cm²

Step-by-step explanation:

The area (A) of the trapezoid is calculated as

A = [tex]\frac{1}{2}[/tex] h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ are the parallel bases

Here h = 5 , b₁ = 10, b₂ = 6 , then

A = [tex]\frac{1}{2}[/tex] × 5 × (10 + 6) = 2.5 × 16 = 40 cm²

Enlarging by a scale factor of 3 means the area is increased by a factor

3² = 9

area of scaled copy = 9 × 40 cm² = 360 cm²

Answer:

2(13x – 7)

Step-by-step explanation:

Answer:

A grizzly bear's normal heart rate when not hibernating is about 50 beats per minute.

Step-by-step explanation:

10÷50=.20

Answer:

78.54

Step-by-step explanation:

[tex]A = \pi r^{2} \\A = \pi 5^{2} \\A = 78.54[/tex]

Answer:

20

Step-by-step explanation:

320 = 16x

Our objective here is to isolate the variable (x) using inverse operations

First we want to get rid of 16

16x is the same as 16 times x( which is multiplication)

The inverse of multiplication is division so to get rid of the 16 we divide by 16 ( but note: whatever you do to one side you must do to the other ) so we divide both sides by 16

320/16=20

16x/16 = x

We would be left with x = 20

This meaning that they would need 20 first grade classes

Answer:

The school will need 20 first grade classes

Step-by-step explanation:

So think about it. There are 320 first grade students and each class can have 16 students which represents the equation 16x=320

All you need to do is solve the equation 16x=320

The equation is multplication. To undo multiplication you need to do division

So, x=320/16

x=20

So overall, your awnser is 20.

Step-by-step explanation:

RAMS SALARY=RS.200×20%

=40+200

=RS.240.00

ANSWER IS OPTION B

Answer:

x = [tex]\frac{3+\sqrt{105} }{8} , \frac{3-\sqrt{105} }{8} x=1.655,-0.905[/tex]

Step-by-step explanation:

3x+6 = 4x^2

4x^2 -3x -6 = 0

x = [tex]\frac{3+\sqrt{105} }{8} , \frac{3-\sqrt{105} }{8} x=1.655,-0.905[/tex]

Answer:

see screenshot

general formula is

r² = (x - x-center)² + (y - y-center)²

Answer:

25

Step-by-step explanation:

Answer:

x = 25

Step-by-step explanation:

Okay so as you can see there is an x shape and whenever you have that it means they are verticle angles. So we can conclude that 25 is verticle to x and so x is equal to 25.

Answer:

25.2 in.

Step-by-step explanation:

Given:

RQ = 7 in.

QL = 24 in.

LK = 3 in.

Required:

Length of diagonal RK

Solution:

Apply the extension of the Pythagorean theorem which is:

d² = x² + y² + z²

Where,

d = RK

x = RQ = 7 in.

y = QL = 24 in.

z = LK = 3 in.

Plug in the values

d² = 7² + 24² + 3²

d² = 634

d = √634

d = 25.1793566 ≈ 25.2 in. (nearest tenth)

Answer:

14/15 :]

Step-by-step explanation:

you dont have to follow me buts its appreciated!

Answer:

55 sq. in.

Step-by-step explanation:

Area of figure

= area of triangle + area of rectangle

height of triangle = 6 in.

base of triangle = 6/(sqrt(3)/3) = 18/sqrt(3)

Area of triangle = 6*18/sqrt(3) /2 = 54/sqrt(3) = 31.18 sq. in.

Area of rectangle = 6 * 4 = 24 sq. in

Area of figure = 31.18+24 = 55.18 sq. in

[tex]55[/tex]

The answer is b

Answer:

Since i don't know what formula is mentioned. I just used the easiest way to solve :)

Step-by-step explanation:

[tex](3x^2 + 3)^3 = (3x^2)^3 + 3^3 + 3((3x^2)^2)(3) + 3(3x^2)(3^2)[/tex]

              [tex]= 27x^6 + 27 + 3(9x^4 \times 3) + 3(3x^2 \times 9)\\\\=27x^6 + 27 + 81x^4 + 81x^2\\\\=27x^6 + 81x^4 + 81x^2 + 27\\\\[/tex]

[tex]\int\limits {(3x^2+3)^3} \, dx = \int\limits {27x^6 + 81x^4+81x^2 + 27} \, dx[/tex]

                      [tex]= \frac{27}{7}x^7 + \frac{81}{5}x^5+\frac{81}{3}x^3 + 27x +C\\\\= \frac{27}{7}x^7 + \frac{81}{5}x^5+27x^3 + 27x +C\\\\[/tex]

Answer:

6^10

Step-by-step explanation:

6^2 * 6^11

-----------------

6^3

First simplify the numerator.  We know a^b*a^c = a^(b+c)

6^(2+11)

-----------------

6^3

6^(13)

-----------------

6^3

Then a^b / a^c = a^(b-c)

6^(13-3) = 6^10

Answer:

6^10

Step-by-step explanation:

To solve this you need to remember 2 things.

First off, multipication is addition with exponents.

And secondly, division is subtraction with expoinents.

So on the top we have 6^2*6^11

So this is really 6^11+2

=

6^13

Now we need to divide by 6^3:

6^13/6^3

And this would tecnically be:

6^13-3

=

6^10

So the expression 6^10 is your answer.

Hope this helps!

line y = − x / 5 + 4 / 5

slope( m1) = -1/5

Slope of required line( m2) = 5

[as it is perpendicular to given eqn of line

m1×m2= -1

m2=1/m1= 5]

y-4= 5(x+3)

y-4=5x+15

y=5x+19

Answer:

y = 1/4x

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

take any point

i am taking F

coordinate of F is (5 , 3)

F' is (10,6)

so use formula

(x , y) = (kx , ky)

(5 , 3) = (5k , 3k) = (10 , 6)

compare corresponding elements

5k = 10

k = 10/5

k = 2

3k = 6

k = 6/3

k = 2

note here k means scale factor

Answer:

[tex]x=100\\y=60[/tex]

Step-by-step explanation:

The shape of the figure is quadrilateral, that means overall it will be 360 degrees.....

Angle of straight line to find x:

[tex]x+80=180[/tex]

[tex]x=180-80[/tex]

[tex]x=100[/tex]

Now, both the values of x will be 100

Find the value of y:

[tex]y+100+120+80=360[/tex]

[tex]y+300=360[/tex]

[tex]y=360-300[/tex]

[tex]y=60[/tex]

Therefore, [tex]x=100[/tex] and [tex]y=60[/tex]

hope this helps, have a good day.....

f(-6) = 5

Just look at the graph when x= -6 , y = 5

Answer:

Step-by-step explanation:

See image -->Answer

Answer: $775.50

explanation: I just looked it up and another website had the same question but also had the answer

Answer:

Step-by-step explanation:

D) Has a five sided shape as a base so its a pentagon-based pyramid

E)Two pentagons and retangular sides Pentagonal Prism

F)All sides and bases are rectangular so Rectangular Prism

G) Eight sided base and triangle shaped sides, Octogon-based Cone

Let G be some point on the diagonal line away from point E.

Angle DEG represents angle 1.

We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.

----------------

Extra side notes:

If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.

If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.

Answer:

a + b + c = 12

Step-by-step explanation:

The given information are;

a² + b² + c² = 138

a·b + b·c + c·a = 3

The required data = a + b + c

Using an online tool, we have;

(a + b + c)² = (a + b + c) × (a + b + c) = 2·a·b + 2·b·c + 2·c·a + a² + b² + c²

∴ (a + b + c)² = 2·(a·b + b·c + c·a) + (a² + b² + c²)

Where;

a·b + b·c + c·a = 3, and a² + b² + c² = 138, we have;

(a + b + c)² = 2 × 3 + 138 = 144

(a + b + c)² = 144

(a + b + c) = √144 = 12

a + b + c = 12.

Answer:

Step-by-step explanation:

y = (x + 5)(x - 5)

  = x² - 5²

 = x² - 25

Degree of this polynomial is 2.

Highest power of the variable x will be the degree of the polynomial.

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

Answer:

6

Step-by-step explanation:

Answer:

1/18

Step-by-step explanation:

I took the test :)

Answer:

B

Step-by-step explanation:

4 scores add all together divided by 4 needs to be greater or equal to his goal

Answer:

-8

Step-by-step explanation:

(7)*(-8) = -56

(-56) - (-8) = -48

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