Answer:
13830.74 W
Explanation:
Applying
P = W/t.................... Equation 1
Where P = Power produce in the engine, W = Work done by the engine, t = time.
But,
W = F×d................... Equation 2
Where F = force, d = distance.
Substitute equation 2 into equation 1
P = (F×d)/t...................... Equation 3
From the question,
Given: F = 2230 N, d = 58.3 m, t = 9.4 s
Substitute these values into equation 3
P = (2230×58.3)/9.4
P = 130009/9.4
P = 13830.74 W
Please help in one minute will mark brainlist
Answer: Different types of telescopes usually don't take simultaneous readings. Space is a dynamic system, so an image taken at one time is not necessarily the precise equivalent of an image of the same phenomena taken at a later time. And often, there is barely enough time for one kind of telescope to observe extremely short-lived phenomena like gamma-ray bursts. By the time other telescopes point to the object, it has grown too faint to be detected.
Explanation: Trust me
oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student observes that a particular spring-mass system has a frequency of oscillation of 10 Hz. the spring constant of the spring is 250 N/m. what is the mass?
Answer:
0.063 Kg
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 10 Hz
Spring constant (K) = 250 N/m
Mass (m) =?
Next, we shall determine the period of oscillation. This can be obtained as follow:
Frequency (f) = 10 Hz
Period (T) =?
T = 1/f
T = 1/10
T = 0.1 s
Finally, we shall determine the mass of the spring. This can be obtained as follow:
Spring constant (K) = 250 N/m
Period (T) = 0.1 s
Pi (π) = 3.14
Mass (m) =?
T = 2π√(m/K)
0.1 = 2 × 3.14 × √(m/250)
0.1 = 6.28 × √(m/250)
Divide both side by 6.28
0.1 / 6.28 = √(m/250)
Take the square of both side.
(0.1 / 6.28)² = m/250
Cross multiply
m = (0.1 / 6.28)² × 250
m = 0.063 Kg
Therefore, the mass of the spring is 0.063 Kg.
The table provided shows the masses and volumes of four liquids. A student has a mystery liquid with a density of 3 g/mL. Which liquid does the student have?
Liquid 1
Liquid 2
Liquid 3
Liquid 4
Answer: Liquid 2, if it's 3 g/mL and liquid 2 has 6gs and 2 mLs than it's 3g/mL
Please select the word from the list that best fits the definition
location of most volcanoes
Island arc
Lava
Basalt
Magma
Hotspot
Plate boundaries
Answer:
The answer is E., or "Plate Boundaries".
The word best describes the definition of the location of volcanoes is "plate boundaries". Therefore, option (E) is correct.
What are plate boundaries?The lithosphere is broken into tectonic plates that undergo some large motions and the boundary regions between plates are called plate boundaries. Based on their motions there are three kinds of plate boundaries: divergent, convergent, and transform.
Divergent boundaries are moving away from one another and separate, they form a rift. As the gap widens, the underlying layer may be soft for molten lava underneath to push upward and resulting in the formation of volcanic islands.
Convergent boundaries move towards one another and collide, subduction usually takes place. The denser plate goes underneath the less dense one and the plate boundaries also experience buckling.
Transform boundaries slide alongside one another and are exposed to huge amounts of stress and strain and are momentarily held in place. The two plates succeed in moving with respect to one another and cause earthquakes.
Learn more about plate boundaries, here:
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What is an appraisal of an employee's performance in the workplace?
A. consensus
B. evaluation
C. procedure
D. metacognition
Answer:
B. evaluation
Explanation:
An employee can be defined as an individual who is employed by an employer of labor to perform specific tasks, duties or functions in an organization.
Basically, an employee is saddled with the responsibility of providing specific services to the organization or company where he is currently employed while being paid a certain amount of money hourly, daily, weekly, or monthly depending on the contractual agreement between the two parties (employer and employee).
Hence, while an employer may be the owner of a business firm or company, an employee is a subordinate employed to provide unwavering services to the employer while also, being professional and diligent at all times.
Human resources management (HRM) can be defined as an art of managing, controlling and improving the number of people (employees or workers), functions, evaluation of employees, activities which are being used effectively and efficiently by an organization.
Hence, human resources managers are saddled with the responsibility of recruiting, evaluating, managing and improving the welfare and working conditions of the employees working in an organization.
Basically, the human resources manager carry out appraisals on the performance of the various employees working in an organization. These informations about employees are typically used for promotional purposes, allowances and other benefits or form of rewards.
On a distance-time graph, what is shown when the curve is flat going from left to the right?
A. a negative speed
B. no speed
C. a positive speed
D. It does not mean anything.
Please help me !!im on a test
Se transmiten ondas transversales en una cuerda tensada orientada sobre el eje x. La función de ondas correspondientes es y= 5.00 sen(6.05x + 5.19t + 1.57). Donde y y x están en metros y t en segundos. Cual es la rapidez de las ondas que se transmiten en dicha cuerda?
Answer:
Explanation:
Whats the entire question?
A state trooper is traveling down the interstate at 20 m/s. He sees a speeder traveling at 50 m/s approaching from behind. At the moment the speeder passes the trooper, the trooper hits the gas and gives chase at a constant acceleration of 2.5 m/s^2.
Required:
a. Assuming that the speeder continues at 60 m/s , how long will it take the trooper to catch up to the speeder?
b. How far down the highway will the trooper travel before catching up to the speeder?
Answer:
Explanation:
From the given information;
Let assume that the distance travelled by the speeder prior to the time the trooper catches with it to be = d
the time interval to be = t
Then, the speeder speed = distance/time
Making distance the subject; then:
distance (d) = speed × time
d = (50 m/s)t
d = 50 t --- (1)
Now, for the trooper; Using the equation of motion:
[tex]d = ut + \dfrac{1}{2}at^2[/tex]
[tex]d = (20)t+\dfrac{1}{2}(2.5)t^2[/tex]
d = 20t + 1.25t²
Replace the value of d in (1) to the above equation, we have:
50 t = 20 t + 1.25t²
50t - 20t = 1.25t²
30t = 1.25t²
30 = 1.25t
[tex]t = \dfrac{30}{1.25}[/tex]
t = 24 seconds
From (1), the distance far down the highway the trooper will travel prior to the time it catches up with the speeder is:
= 50t
= 50(24)
= 1200 seconds
Consider two antennas separated by 9.00 m that radiate in phase at 120 MHz, as described in Exercise 35.3. A receiver placed 150 m from both antennas measures an intensity I0 . The receiver is moved so that it is 1.8 m closer to one antenna than to the other. (a) What is the phase difference f between the two radio waves produced by this path difference
Answer:
[tex]\phi=4.52 rad[/tex]
Explanation:
From the question we are told that
Distance b/e antenna's [tex]d=9.00m[/tex]
Frequency of antenna Radiation[tex]F_r=120 MHz \approx 120*10^6Hz[/tex]
Distance from receiver [tex]d_r=150m[/tex]
Intensity of Receiver [tex]i= 10[/tex]
Distance difference of the receiver b/w antenna's [tex](r^2-r^1)=1.8m[/tex]
Generally the equation for Phase difference [tex]\phi[/tex] is mathematically given by
[tex]\phi=\frac{2\pi}{\frac{c}{f_r}} *(r^2-r^1)[/tex]
[tex]\phi=\frac{2*\pi}{\frac{3*10^{8}}{120*10^6}} *1.8[/tex]
[tex]\phi=\frac{4\pi}{5} *1.8[/tex]
[tex]\phi=4.52 rad[/tex]Therefore phase difference f between the two radio waves produced by this path difference is given as
[tex]\phi=4.52 rad[/tex]
anyone know the 4 digit code?
Answer:
the ans is 5934
Explanation:
3+2=5
+ + +
1 +3=4
= = =
4 +5=9
A pendulum swings past it's pole 20 times in 18 seconds, what is the period of the pendulum?
Answer: 0.9
Explanation:
If frequency equals the amount of oscillations in one second then 20/18 = f = 1.11 and to find period (T) then we use the equation T= 1/f or in this case 1/1.11 = 0.9
Types of government
Answer:
Explanation:
The different types of government include a direct democracy, a representative democracy, socialism, communism, a monarchy, an oligarchy, and an autocracy
what is the difference between kinetic and potential energy
Answer:
Kinetic energy is energy possessed by a body by virtue of its movement. Potential energy is the energy possessed by a body by virtue of its position or state. While kinetic energy of an object is relative to the state of other objects in its environment, potential energy is completely independent of its environment. Hence the acceleration of an object is not evident in the movement of one object, where other objects in the same environment are also in motion. For example, a bullet whizzing past a person who is standing possesses kinetic energy, but the bullet has no kinetic energy with respect to a train moving alongside.
I think this answer is helped you
Answer:
the what state does alduos is 500 stack of ml tayo the little man ♂️ jajao
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4. What is the distance between two electrons, when the force between them is 0.50 N?
Explanation:
[tex]from \: coulombs \: law \: of \: electrostatics \\ F = \frac{k {q}^{2} }{ {r}^{2} } \\ 0.5 = \frac{(9 \times {10}^{9} ) \times (1.6 \times {10}^{ - 19} ) {}^{2} }{ {r}^{2} } \\ 0.5 {r}^{2} = 2.304 \times {10}^{ - 28} \\ {r}^{2} = 4.608 \times {10}^{ - 28} \\ r = \sqrt{4.608 \times {10}^{ - 28} } \\ r = 2.15 \times {10}^{ - 14} \: m[/tex]
Tom wanted to buy a hunting dog with a waterproof undercoat and a good sense of smell. Which type of genetic engineering would help Tom find the right dog?
a. GMO
b. biomedical research
C. Selective breeding
D. Mutation research
Count the equivalent resistance.
[tex]\huge{ \mathfrak{ \underline{question : }}}[/tex]
Find the equivalent resistance .....
[tex]\huge{ \mathfrak{ \underline{ Answer \: \: ✓ }}}[/tex]
Equivalent resistance :
[tex] \dfrac{1}{ R _ t} = \dfrac{1}{3 + 3} + \dfrac{1}{3} [/tex][tex]\dfrac{1}{ R _ t} = \dfrac{1}{6} + \dfrac{1}{3} [/tex][tex]\dfrac{1}{ R _ t} = \dfrac{1 + 2}{6} [/tex][tex]\dfrac{1}{ R _ t} = \dfrac{3}{6} [/tex][tex] R _ t = 2 [/tex]Equivalent resistance = 2 ohms
[tex]\#TeeNForeveR [/tex]
A 4.00-kg block hangs by a light string that passes over a massless, frictionless pulley and is connected to a 6.00-kg block that rests on a frictionless shelf. The 6.00-kg block is pushed against a spring to which it is not attached. The spring has a spring constant of 180 N/m, and it is compressed by 30.0 cm. Find the speed of the block after the spring is released and the 4.00-kg block has fallen a distance of 40.0 cm.
Answer:
v = 2.82 m/s
Explanation:
For this exercise we can use the conservation of energy relations.
We place our reference system at the point where block 1 of m₁ = 4 kg
starting point. With the spring compressed
Em₀ = K_e + U₂ = ½ k x² + m₂ g y₂
final point. When block 1 has descended y = - 0.400 m
Em_f = K₂ + U₂ + U₁ = ½ m₂ v² + m₂ g y₂ + m₁ g y
as there is no friction, the energy is conserved
Em₀ = Em_f
½ k x² + m₂ g y₂ = ½ m₂ v² + m₂ g y₂ + m₁ g y
½ k x² - m₁ g y = ½ m₂ v²
v² = [tex]\frac{k}{m_2} x^2 - 2 \frac{m_1}{m_2} \ g y[/tex]
let's calculate
v² = [tex]\frac{180}{6.00} \ 0.300^2 - 2 \ \frac{4.00}{6.00} \ 9.8 \ (- 0.400)[/tex]
v² = 2.7 + 5.23
v = √7.927
v = 2,815 m / s
using of significant figures
v = 2.82 m/s
If m1 is 80g, and the meter stick is 60g, then what must m2 be to put the stick in equilibrium?
Answer:
Explanation:
Elaborate them
What essential nutrient is so important and makes up approximately 80% of the body.
Protein
it's the main component of muscles, bones, organs ext.
what unit is used to measure resistance
Answer:
Ohms
Explanation:
The unit of resistance is ohms.
Hypothesis what is it
Explanation:
hope it helps.
stay safe healthy and happy.These waves are most harmful for living things.
What waves are most harmful for living things?
A radio
B microwaves
C infrared
D visible
E ultraviolet
F x-rays
G gamma rays
Explanation:
G. gamma rays because they are produced by the hottest and most energetic objects in the universe, such as neutron stars and pulsars, supernova explosions, and regions around black holes.
hope this helps you
have a nice day:)
What will happen when you slide the sponges in different directions?
Answer:Transform boundary
is the answer from stemscopes
Explanation:
Answer: Well if you slide them in diffrenent directions then the sponges will contract
Explanation:
th sponges aren't going twords each other
What would the circuit resistance be if a 7.5 Amp draw was present with the engine running and the charging system producing 15 Volts?
Answer:
2 ohms
Explanation:
Hi there!
Ohm's law states that [tex]V=IR[/tex] where V is the voltage, I is the current and R is the resistance.
Plug in the given information (I=7.5, V=15) and solve for R
[tex]V=IR\\15=(7.5)R[/tex]
Divide both sides by 7.5 to isolate R
[tex]\frac{15}{7.5}= \frac{7.5R}{7.5} \\2=R[/tex]
Therefore, the circuit resistance would be 2 ohms.
I hope this helps!
For the circuit in the previous part, what happens to the maximum current if the frequency is doubled and the inductance is halved
Answer:
Following are the responses to these question:
Explanation:
Since the [tex]max^{m}[/tex] is the current of ckt which depend on the reactance which inductor that also enables the ckt and inductor resistance [tex](X_L)[/tex] for capacities
[tex]\to X_{C}=\frac{1}{W L}[/tex]
for
[tex]\to X_{L}=wL[/tex]
When [tex]w \longrightarrow 2w[/tex]
[tex]L\longrightarrow \frac{L}{2}[/tex]
then
[tex]\to X_{L}=2 w \times \frac{L}{2}=wL[/tex]
therefore, [tex]X_{L}[/tex] remains at the same so, the maximum current remains the in same ckt.
girl is sitting on a tire swing that is attached with a rope that is 2.1 m in length. Her dad pushes
her with a speed of 3.0 m/s. If the centripetal force is 88 N, what is the mass of the girl?
pls help
Answer:
m=29.6kg
Explanation:
your welcome:) have a great day
If you dropped a ball off the roof, and could neglect air resistance, the impact velocity of the ball on the sidewalk would be 102 miles per hour [mph]. Calculate the height of the building in units of feet.
Answer:
h = 105.98 m
Explanation:
We will use the third equation of motion here:
[tex]2gh= v_f^2-v_i^2[/tex]
where,
g = acceleration due to gravity = 9.81 m/s²
h = height = ?
vf = final speed = (102 mi/h)(1 h/3600 s)(1609.34 m/1 mi) = 45.6 m/s
vi = initial speed = 0 m/s
Therefore,
[tex]2(9.81\ m/s^2)h = (45.6\ m/s)^2-(0\ m/s)^2\\\\h = \frac{ (45.6\ m/s)^2}{2(9.81\ m/s^2)}[/tex]
h = 105.98 m
Calculate the speed of your cat as it runs towards its food bowl 14.7m away in 4.5 s. Give answer in mph.
Answer:
3.26mph
Explanation:
To calculate speed, use the formula distance/time. In this case, just divide 14.7 by 4.5.
The speed with which the cat runs towards its food bowl is 7.3 Miles per hour.
Given the data in the question
Distance of cat from it's food bowl; [tex]s = 14.7m[/tex]Time taken for the cat to reach the food bowl; [tex]t = 4.5s[/tex]Speed of the cat; [tex]v = \ ?[/tex]
Speed is the time rate at which an object is moving along a path
Speed is the time rate at which an object is displaced.
Speed = Distance / Time
[tex]v = s / t[/tex]
We substitute our values into the equation
[tex]v = \frac{14.7m}{4.5s}\\\\v = 3.267 m/s\\\\v = 7.3mph[/tex]
Therefore, the speed with which the cat runs towards its food bowl is 7.3 Miles per hour.
Learn more: https://brainly.com/question/680492
A block of wood has mass 4kg, what is the density of the wood if the mass of water is 3kg and its volume is half that of the block of the block of wood ?
In the physics lab, a block of mass M slides down a frictionless incline from a height of 35cm. At the bottom of the incline it elastically strikes another block that is only one-half its mass. Find the velocity of block M at the bottom of the incline before the collision with the small block m.
Solution :
Given :
M = 0.35 kg
[tex]$m=\frac{M}{2}=0.175 \ kg$[/tex]
Total mechanical energy = constant
or [tex]$K.E._{top}+P.E._{top} = K.E._{bottom}+P.E._{bottom}$[/tex]
But [tex]$K.E._{top} = 0$[/tex] and [tex]$P.E._{bottom} = 0$[/tex]
Therefore, potential energy at the top = kinetic energy at the bottom
[tex]$\Rightarrow mgh = \frac{1}{2}mv^2$[/tex]
[tex]$\Rightarrow v = \sqrt{2gh}$[/tex]
[tex]$=\sqrt{2 \times 9.8 \times 0.35}$[/tex] (h = 35 cm = 0.35 m)
= 2.62 m/s
It is the velocity of M just before collision of 'm' at the bottom.
We know that in elastic collision velocity after collision is given by :
[tex]$v_1=\frac{m_1-m_2}{m_1+m_2}v_1+ \frac{2m_2v_2}{m_1+m_2}$[/tex]
here, [tex]$m_1=M, m_2 = m, v_1 = 2.62 m/s, v_2 = 0$[/tex]
∴ [tex]$v_1=\frac{0.35-0.175}{0.5250}+\frac{2 \times 0.175 \times 0}{0.525}[/tex]
[tex]$=\frac{0.175}{0.525}+0$[/tex]
= 0.33 m/s
Therefore, velocity after the collision of mass M = 0.33 m/s