Answer:
The force they will exert on each other is 1.6*10⁻¹⁰ N
Explanation:
The electromagnetic force is the interaction that occurs between bodies that have an electric charge. When the charges are at rest, the interaction between them is called the electrostatic force. Depending on the sign of the interacting charges, the electrostatic force can be attractive or repulsive. The electrostatic interaction between charges of the same sign is repulsive, while the interaction between charges of the opposite sign is attractive.
Coulomb's law is used to calculate the electric force acting between two charges at rest. This force depends on the distance "r" between the electrons and the charge of both.
Coulomb's law is represented by:
[tex]F=k*\frac{q1*q2}{r^{2} }[/tex]
where:
F = electric force of attraction or repulsion in Newtons (N). Like charges repel and opposite charges attract. k = is the Coulomb constant or electrical constant of proportionality. q = value of the electric charges measured in Coulomb (C). r = distance that separates the charges and that is measured in meters (m).In this case:
k= 9*10⁹ [tex]\frac{N*m^{2} }{C^{2} }[/tex]q1= 1.602*10⁻¹⁹ Cq2= 1.602*10⁻¹⁹ Cr= 1.2*10⁻⁹ mReplacing:
[tex]F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{1.602*10^{-19} C*1.602*10^{-19} C}{(1.2*10^{-9} )^{2} }[/tex]
and solving you get:
F=1.6*10⁻¹⁰ N
The force they will exert on each other is 1.6*10⁻¹⁰ N
can someone pls tell me what a force diagram is
An Atwood's machine consists of two masses, m1 and m2, connected by a string that passes over a pulley. If the pulley is a disk of radius R and mass M , find the acceleration of the masses. Express your answer in terms of the variables m1, m2, R, M, and appropriate constants.
Answer:
Explanation:
Suppose m₂ is greater than m₁ and it is going down . m₁ will be going up.
Let tension in string be T₁ and T₂ . Let common acceleration of system be a
For motion of m₁
T₁-m₁g = m₁a ----- (1)
For motion of m₂
m₂g- T₂ = m₂a ------- (2)
For motion of pulley
(T₂-T₁ )R represents net torque
(T₂-T₁ )R = I x α where I is moment of inertia of disc and α is angular acceleration of disc
(T₂-T₁ )R = 1/2 M R² x a / R
(T₂-T₁ ) = M a /2
Adding (1) and (2)
(m₂-m₁)g = (m₂+m₁)a + (T₂-T₁ )
(m₂-m₁)g = (m₂+m₁)a + Ma/2
(m₂-m₁)g = (m₂+m₁+ 0.5M)a
a = (m₂-m₁)g / ( (m₂+m₁+ 0.5M)
The acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].
Given to us
Masses = m₁, m₂
The radius of the pulley = R
Mass of the pulley = M
Assumption
Let the mass m₁ > m₂. therefore, the mass m₁ is going down due to its weight while m₂ is going up.Assuming the tension in the string be T₁ and T₂, respectively.Also, the common acceleration in the system is a.Tensions in stringsWe know the acceleration due to gravity is denoted by g,
Tension in string 1, T₁[tex]T_1 = m_1(a+g)[/tex]......... equation 1
Tension in string 2, T₂[tex]T_2 = m_2(a-g)[/tex]......... equation 2
Inertia and acceleration of the pulleyThe inertia of the pulley, [tex]I = \dfrac{1}{2}MR^2[/tex]
Acceleration of the pulley, [tex]a = {\alpha }\times {R}[/tex]
Torque in the pulley[tex](T_2-T_1)R = I \times \alpha \\\\[/tex]
Substitute the values we get,
[tex][m_2(a-g)-m_1(a+g)]R = \dfrac{1}{2} MR^2 \times \dfrac{a}{R}\\\\[/tex]
[tex][m_2a-m_2g-m_1a-m_1g]R= \dfrac{1}{2} MR \times a[/tex]
[tex]m_2a-m_1a-m_2g-m_1g= \dfrac{1}{2} M \times a[/tex]
[tex]a(m_2-m_1)-g(m_2+m_1)= 0.5M \times a[/tex]
[tex]a(m_2-m_1)-0.5Ma=g(m_2+m_1)\\\\a(m_2-m_1-0.5M) = g(m_2+m_1)\\\\a = \dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex]
Hence, the acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].
Learn more about Tension in strings:
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Ashley decides to enter her pet turtle in a race. She knows her turtle can travel at a rate of 2 meters per hour. The race track measures 5 meters from start to finish. How long will it take Ashley’s turtle to finish the race?
A) 3 hours
B) 10 hours
C) .4 hours
D) 2.5 hours
Thanks for the help! And if it’s not a bother could you please explain how you got the answer? However it’s not necessary if you don’t want to.
PLEASE HELP ASAP!!!
A car is sitting on a hill which is 25 m higher than ground level. What is the mass of the car if it contains 360,800 J of potential energy?
Answer:
14,432 g
Explanation:
PE=mh
360,800 J = (m)(25)
[tex]\frac{360,800 J}{25 m}[/tex] = m
14,432 g = m
POSSIBLE POINTS: 1
After the Frisbee falls to the ground, you throw one of them back up into the tree, where it comes to rest on a branch.
Compared to when the Frisbee was on the ground, which of the following is true about the potential energy of the system?
Answer:
the effect on energy is due to the force applied to the frisbee to throw it back in the tree.
Explanation:
A 744 N force is applied to an object to reach an acceleration of 24 m/s2. What is the objects mass?
31kg
Explanation:
F = ma
m = F/a
m = 744N/24m/s^2
m = 31kg
(*Newton's Second Law*)
In which regions can the gravitational field strength due to the two planets be zero? Explain.
A. None
B. A, B and C
C. A and C
D. B
Answer:
I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong
Explanation:
None of the regions can the gravitational field strength due to the two planets be zero.
What is gravitational field?
A gravitational field is a model used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies. Consequently, a gravitational field, which is measured in newtons per kilogram, is employed to describe gravitational processes.
Field due to given masses can not be zero in the given region they do not cancel each other.
None of the regions can the gravitational field strength due to the two planets be zero.
To learn more about gravitational field refer to the link:
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A person drops a pebble of mass m1 from a height h, and it hits the floor with kinetic energy KE. The person drops another pebble of mass m2 from a height of 4h, and it hits the floor with the same kinetic energy KE. How do the masses of the pebbles compare
Hello,
QUESTION)✔ We have: KE = PE (potential energy)
PE = m x g x h
The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2
PE1 = PE2 ⇔ PE1/PE2 = 1
[tex]\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\ \frac{m_1}{m_2\times 4} = 1 \\ \\ \frac{m_1}{m_2} = 4[/tex]
The mass m1 is therefore 4 times greater than that of the stone of mass m2.
BRAINLEST FOR CORRECT ANSWER PLEASE
Which has more momentum: a 3 kg sledgehammer swung at 1.5 m/s OR a 4 kg sledgehammer swung at 0.9 m/s? SHOW YOUR WORK
Answer:
Sledgehammer A has more momentum
Explanation:
Given:
Mass of Sledgehammer A = 3 Kg
Swing speed = 1.5 m/s
Mass of Sledgehammer B = 4 Kg
Swing speed = 0.9 m/s
Find:
More momentum
Computation:
Momentum = mv
Momentum sledgehammer A = 3 x 1.5
Momentum sledgehammer A = 4.5 kg⋅m/s
Momentum sledgehammer B = 4 x 0.9
Momentum sledgehammer B = 3.6 kg⋅m/s
Sledgehammer A has more momentum
Would this be C ?? Please tell me if I’m wrong ..
Answer:
yes its c
Explanation:
took it already
An airplane of mass 13300 kg is flying in a straight line at a constant altitude and with a speed of 560.0 km/hr. The force that keeps the airplane in the air is provided entirely by the aerodynamic lift generated by the wings. The direction of this force is perpendicular to the wing surface. Calculate the magnitude of the lift generated by the wings of this airplane.
Answer:
The magnitude of the lift generated by the wings of the airplane is 130,340 N.
Explanation:
Given;
mass of the airplane, m = 13,300 kg
speed of the airplane, v = 560 km/h = 155.56 m/s
The magnitude of the lift generated by the wings of the airplane is calculated as;
[tex]F_l = mg\\\\where;\\\\F_l \ is \ the \ magnitude \ of \ the \ lift \ generated\\g \ is \ acceleration \ due \ to \ gravity = 9.8 \ m/s^2\\\\F_l = 13,300 \times \ 9.8\\\\F_l = 130,340 \ N[/tex]
Therefore, the magnitude of the lift generated by the wings of the airplane is 130,340 N.
The way you change the speed of a wave is to:
a
Change it's medium
b
Change it's energy
c
Transfer it to a new position
d
Apply a force
Answer:
transfer it to a new position
An object that weighs 500 kg is rolling along the road at 3.5 m/s, what is the momentum of the object?
Answer:
momentum=mass x velocity= 500 x 3.5 = 1750kgm/s
Kyle lays a mirror flat on the floor and aims a laser at the mirror. The laser beam reflects off the mirror and strikes an adjacent wall. The plane of the incident and reflected beams is perpendicular to the wall. The beam from the laser strikes the mirror at a distance a=60.1 cm from the wall. The reflected beam strikes the wall at a height b=31.3 cmabove the surface of the mirror.Find the angle of incidence θiat which the laser beam strikes the mirror.
Answer:
62.5 °
Explanation:
✓From law of reflection, angle of incidence equals angles of reflection .
✓the angle between the reflected ray can be determined using trigonometry, we know that
horizontal distance x =60.1 cm
the vertical distance is y =31.3
Then
tan( θ) =( y / x)
If we substitute the values we have,
tan θ = 31.3 / 60.1
θ = tan⁻¹ (0.5208)
θ = 27.5°
This angle is been measured using x-axis (horizontal)BBut in optics we can measured with respect to y-axis then angle becomes
θ = 90 - 27.5
θr = 62.5 °
θr = θi= 62.5°
the angle of incidence θiat which the laser beam strikes the mirror is 62.5°
The energy that a substance contains is
a. equilibrium
b. heat
c. thermal energy
d. entropy
The energy that a substance contains is known as heat. Thus, the correct option for this question is B.
What is Entropy?Entropy may be characterized as the measurement of the degree of randomness or in other words, it is the increase in the disorganization within a system. It is the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.
Equilibrium is a state of balance between opposing forces or actions that is either static or dynamic. It symbolizes the circumstance of being balanced in nature.
Thermal energy is a type of energy that is significantly contained within a system that is responsible for its temperature. Heat is the flow of thermal energy.
Therefore, the energy that a substance contains is known as heat. Thus, the correct option for this question is B.
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Snell's law describes the relationship between the angle a light ray makes as it leaves a surface, the angle it makes incident on the surface, and the indices of refraction on both sides of the surface. If light incident in air at angle of 30 degrees from the normal onto glass with an index of refraction of 1.5 --Pick those answers that applya) Inside the material, the light leaving the surface is closer to the surface, makes a bigger angle with the normal, than the entering light makes in air.b) The light inside the glass is closer to the normal, makes a bigger angle with the surface, than the incident lightc) There is light reflected back into the air from the surfaced) The angle is too steep for light to refract and it is all reflected.
Answer:
b) and c)
Explanation:
Snell's law states that there exists a fixed relationship between the sine of the angle that makes with the normal an incident ray on the separation surface of two transparent media, the sine of the angle that is refracted off the surface, and the indexes of refraction of both media, as follows:[tex]\frac{sin_{\theta i}}{sin_{\theta r} } =\frac{n_{2} }{n_{1} } (1)[/tex]
Givens: θi = 30º n₁ = 1 (air) n₂= 1.5 (glass)Since sin 30º = 0.5, we can solve for sin r, as follows:[tex]sin \theta r = \frac{sin_{\theta i}}{n_{2}} = \frac{0.5}{1.5} = 0.333 (2)[/tex]As the sin r is lower than sin i, this implies that the angle that makes with the normal is lower than i, which means that it makes a bigger angle with the surface, as stated by b).Also there is some light that is reflected by the surface, making an angle with the normal equal to the incident ray, as stated by c). So, b) and c) are the right choices.how much work is done if a force of 20 N moves an object a distance of 6 m?
Explanation:
W=F×s
w=20N×6m=120J
W=120J
Which of the following would produce the most power?
b
ОООО
A mass of 10 kilograms lifted 10 meters in 10 seconds
A mass of 5 kilograms lifted 10 meters in 5 seconds
A mass of 10 kilograms lifted 10 meters in 5 seconds
A mass of 5 kilograms lifted 5 meters in 10 seconds
d
Answer:
A mass of 10 kilograms lifted 10 meters in 5 seconds.
Explanation:
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
[tex] Power = \frac {Energy}{time} [/tex]
But Energy = mgh
Substituting into the equation, we have
[tex] Power = \frac {mgh}{time} [/tex]
Given the following data;
Mass = 10kg
Height = 10m
Time = 5 seconds
We know that acceleration due to gravity is equal to 9.8 m/s²
[tex] Power = \frac {10*9.8*10}{5} = 490 Watts [/tex]
Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.
A forward honzontal force of 50 N is applied to a crate. A second horizontal force o
180 N is applied to the crate in the opposite direction. Determine the magnitude and
direction of the resultant force acting on the crate
Answer:
Explanation:
magnitude: 180-50=130N
Direction: in the direction same as the second horizontal force
Tom has a mass of 50,000 g and runs up a flight of stairs 4 m high in 12.5 seconds.
Calculate Tom’s power. (g = 10 m/s2)
Answer:
160 watts.
Explanation:
Remark
Power = Work / Time
Work = F * d
Note: Since he is running up stairs he is doing work against gravity.
Givens
m = 50000 g kg / 1000 grmsm = 50000 / 1000 = 50 kgh = 4 mtime = 12.5 secondsg = 10 m/s^2Formula
P = W * d/tW = m*g *d / tSolution
P = 50kg * 10 m/s^2 * 4 m / 12.5 P = 160 watts.
can someone help with me 1,2,3 please I will mark brainless .
Answer:
1) A. .33 hr
2) B. 6ft
3) A. 58mi/hr
Which best explains why we are able to accelerate forward when starting to run? A) The runner's upper body quickly leans forward, causing the entire body to begin accelerating forward. B) As one leg moves backward, it provides an opposite force for the other foot to move forward. C) The foot not touching the ground propels the entire body as it swings forward. D) The striking foot pushes backward against the ground. The friction with the ground provides an equal and opposite force forward.
Answer:
D.The striking foot pushes backward against the ground. The friction with the ground provides an equal and opposite force forward
Answer:
d
Explanation:
The velocity of a car changes from 15 m/s south to 5 m/s south in 2
seconds. What is the acceleration of the car?
A. 5 m/s2 north
B. 10 m/s2 north
C. 10 m/s2 south
D. 5 m/s2 south
Answer:
Acceleration of car = -5 m/s south
Explanation:
Given:
Initial velocity = 15 m/s
Final velocity = 5 m/s
Time taken = 2 sec
Find:
Acceleration of car
Computation:
Acceleration = Change in velocity / time
Acceleration of car = [5-15] / 2
Acceleration of car = -5 m/s south
50 points help please
Answer:
C?
Explanation:
Yep,It's C all right.
Answer:
Yep,It's C all right.
Explanation:
At the end of the previous experiment, aclumsy scientist drops the coil, while still in the magnetic field, and still oriented with its plane perpendicular to the magnetic field, denting it and changing its shape to a semi-circle. The new shape has the same perimeter, but a different area, and it takes 0.036s to deform. What isthe average induced EMF during this mishap
Answer:
hello your question has some missing parts below are the missing parts
A Circular, 10-turn coil has a radius of 10.7 cm and is oriented with its plane perpendicular to a 0.2-T magnetic field.
answer : 1 volt
Explanation:
Determine the Average induced EMF during this mishap
A' = A/2 ( for a semi circle )
where A = [tex]\frac{\pi r^2}{2}[/tex]
To determine the Average induced EMF apply the relation below
| E | = η * [tex]\frac{\beta A}{T}[/tex] ----- ( 1 )
Replace A in equation 1 with A = [tex]\frac{\pi r^2}{2}[/tex]
hence equation becomes : | E | = η * βπr^2 / 2T'
where : T' = 0.0365 , β = 0.2 , η = 10 , r = 0.107
∴| E | = 0.999 ≈ 1volts
Calculate the amount of torque of an object being pushed by 6 N force along a circular path of a radius of 1x10^-2 mat 30 degree angle.
Answer:
The amount of torque is 0.03 N.m.
Explanation:
To find the amount of torque we need to use the following equation:
[tex] \tau = \vec {r} \times \vec{F} = rFsin(\theta) [/tex] (1)
Where:
r: is the radius = 1x10⁻² m
F: is the force = 6 N
θ: is the angle = 30°
By entering the above values into equation (1) we have:
[tex]\tau = 1 \cdot 10^{-2} m*6 N*sin(30) = 0.03 N.m[/tex]
Therefore, the amount of torque is 0.03 N.m.
I hope it helps you!
Badll
Which of the following is an example of
the Law of Inertia?
A. Sitting in a chair and breaking it
B. Throwing a ball in outer space and it goes on forever
unless acted upon by another force
C. Eating a salad to bring chemical energy into the body
D. Driving a car on a track
What is law of conservation of energy?
Energy can neither be created nor be destroyed.
Answer:
the law of conservation of energy states that the total energy of an isolated system remains constant.
3. A record 0.30 cm in diameter rotates 33.5 times per minute.
a. What is its frequency?
b. What is its period?
c. What is the linear speed of a point on its rim?
d. What is the centripetal acceleration of a point on its rim?
Explanation:
The diameter of a record, d = 0.3 cm
Radius, r = 0.15 cm
It rotates 33.5 times per minute.
(a) Frequency, f = 33.5 rotation/minute
= (33.5/60) rotation/second
= 0.55 rotation/second
(b) Time period,
T = 1/f
So,
[tex]T=\dfrac{1}{0.55}\\\\T=1.81\ s[/tex]
(c) Linear speed of a point on its rim,
[tex]v=r\omega\\\\v=0.15\times 10^{-2}\times 2\pi \times 0.55\\\\v=5.18\times 10^{-3}\ m/s[/tex]
(d) Centripetal acceleration,
[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(5.18\times 10^{-3})^2}{0.15\times 10^{-2}}\\\\a=0.017\ m/s^2[/tex]
Hence, this is the required solution.
A beam of protons is directed in a straight line along the z direction through a region of space in which there are crossed electric and magnetic fields The electric field is 550 V m in the y direction and the protons move at a constant speed of 105 m s 1 What must be the magnitude of the magnetic field such that the beam of protons continues along its straight line trajectory Express your answer using two significant figures
Answer:
B = 5.23 T
Explanation:
Given that,
Electric field, E = 550 V/m
The speed of the proton, v = 105 m/s
We need to find the magnitude of the magnetic field such that the beam of protons continues along its straight-line trajectory.
To move in a straight line, the magnitude of the electric force from the field and the magnetic field must be equal i.e.
[tex]qE=qvB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{550}{105}\\\\B=5.23\ T[/tex]
So, the magnitude of the magnetic field is equal to 5.23 T.