An electromagnetic wave moves through electric and magnetic fields. How might the movement of the wave be described?
A.
The vibrations of the fields are perpendicular to the direction in which the wave moves.
B.
The wave moves back and forth through the fields.
C.
The vibrations of the fields are parallel to the direction in which the wave moves.
close
D.
The wave moves through the fields in a random motion.

Answers

Answer 1

A. The vibrations of the fields are perpendicular to the direction in which the wave moves.

Answer 2

An electromagnetic wave moves through electric and magnetic fields, and the movement of the wave can be described as the vibrations of the fields being perpendicular to the direction in which the wave moves, as in option A.

What is the significance of an electromagnetic wave?

Electromagnetic waves have many applications, including the transmission of information and energy, and they are also used in other technologies such as radio, television, hospitals, wireless communications, and so on. Other different rays, such as microwaves, infrared radiation, visible light, ultraviolet radiation, etc., are used in different fields, such as X-rays for imaging, etc.

Hence, an electromagnetic wave moves through electric and magnetic fields, and the movement of the wave can be described as the vibrations of the fields being perpendicular to the direction in which the wave moves, as in option A.

Learn more about the electromagnetic wave here.

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Related Questions

a mass of 0.8kg at the end of a rope 0.5m long is whirled round ina horizontal circle at an angular speed of 10 rads^-1. what is it's angular momentum?​

Answers

Answer:

L = 2 J.s

Explanation:

The angular momentum of an object travelling in a horizontal circle is given by the following formula:

[tex]L = mvr[/tex]

where,

L = Angular momentum = ?

m = mass = 0.8 kg

v = linear speed = rω

r = radius of circular path = length of rope = 0.5 m

ω = Angular Speed = 10 rad/s

therefore,

[tex]L = mr^2\omega\\L = (0.8\ kg)(0.5\ m)^2(10\ rad/s)\\[/tex]

L = 2 J.s

Oberon is a moon of Uranus. It has a mass of 3.01 x 1021 kg and is 761.4 km away from Uranus. If the force of gravity
of Uranus is pulling 3.00 x 1025 N on Oberon, what is the mass of Uranus? (6 points)

Answers

Answer:

acc to formula= F= G m1m2/rsq

mass of Uranus= F×r sq/G×m

M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21

=3×10^25-8×7614×7614/667×301×10^-2-11+21-2

=173918988×10^11/200767

=866×10^11(approx)

If 11,550 J heat is absorbed by a copper object when it is heated from 20.0°C to 30.0°C,
what is the mass of the copper?
The specific heat of copper is 385 J/kgK.

Answers

Answer:

The mass of the copper is 3.00kg

Explanation:

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