An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample of 8 school districts is selected, and the daily salaries are 60, 56, 60, 55, 70, 55, 60, and 55. Is there enough evidence to support the educator’s claim at 10% level of significance? (HELP: The sample mean is 58.88, and the sample standard deviation is 5.08)

Answers

Answer 1

Answer:

[tex]t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=8-1=7[/tex]  

The p value would be given by:

[tex]p_v =P(t_{(7)}<-0.626)=0.275[/tex]  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

[tex]\bar X= \frac{\sum_{i=1}^n X_i}{n}[/tex]

[tex]s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]

Replacing we got:

[tex]\bar X=58.875[/tex] represent the mean

[tex]s=5.083[/tex] represent the sample standard deviation for the sample  

[tex]n=8[/tex] sample size  

[tex]\mu_o =60[/tex] represent the value that we want to test

[tex]\alpha=0.1[/tex] represent the significance level

t would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \geq 60[/tex]  

Alternative hypothesis:[tex]\mu < 60[/tex]  

The statistic would be given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

Replacing the info we got:

[tex]t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=8-1=7[/tex]  

The p value would be given by:

[tex]p_v =P(t_{(7)}<-0.626)=0.275[/tex]  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60


Related Questions

Decide whether the sets are equivalent {d: d is a month of the year} and {g : g is a state in the United States}

Answers

Answer:

Non equivalent

Step-by-step explanation:

The equivalent between sets is determined by the number of elements. If two sets have the same number of elements, then they are equivalent sets.

In this case, a year has 12 months, and the US has 50 states. So, one month is not equal to 1 state because they have different natures and they represent a different proportion. A month represents 1/12 of a year and a state represents 1/50 of the total number of states.

Factor completely 2x3y + 18xy - 10x2y - 90y. I need this done today in a few minutes.

Answers

Answer:

2y (x^2+9) ( x-5)

Step-by-step explanation:

2x^3y + 18xy - 10x^2y - 90y

Factor out the common factor of 2y

2y(x^3+9x-5x^2-45)

Then factor by grouping

2y(x^3+9x     -5x^2-45)

Taking x from the first group and -5 from the second

2y( x (x^2+9)  -5(x^2+9))

Now factor out (x^2+9)

2y (x^2+9) ( x-5)

can someone help me solve this problem​

Answers

Answer:

18 and 40

Step-by-step explanation:

Let x be the age of Claire and y the age of her mother

Claire's mother is 4 years more than twice Claire's age

y = 2x+4

The sum of their ages are is 58

x+y = 58

the system is:

[tex]\left \{ {{y=2x-4} \atop {y+x=58}} \right.[/tex]  

Multiply (y+x = 58) by -1 and then add it to (y = 2x+4) to eliminate y

-y-x = -58 -y-x+y = 2x+4-58 -x -2x = -54-3x = -54x = 54/3x = 18

y= 58-18 = 40

so claire's mother is 40 years old and claire is 18

The answer is 18 and 4

which figure has the same order of rotational symmetry as a rectangle

Answers

can you attach the figures?

Answer:

rhombus

Step-by-step explanation:

on edge

The area of a rectangular horse pasture is 268,500 square yards. The length of the pasture is 5 yards less than three times the width. What is the width of the pasture in yards? Do not include units in your answer. Please help right away! Thank you very much!

Answers

Answer:  width = 300

Step-by-step explanation:

Area (A) = Length (L) x width (w)

Given: A = 268,500

           L = 3w - 5

           w = w

268,500 = (3w - 5) x (w)

268,500 = 3w² - 5w

            0 = 3w² - 5w - 268,500

            0 = (3w + 895) (w - 300)

   0 = 3w + 895        0 = w - 300

  -985/3 = w             300 = w

Since width cannot be negative, disregard w = -985/3

So the only valid answer is: w = 300

   

You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately σ = 58.2 σ=58.2. You would like to be 99% confident that your estimate is within 1 of the true population mean. How large of a sample size is required? Do not round mid-calculation.

Answers

Answer:

[tex]n=(\frac{2.58(58.2)}{1})^2 =22546.82 \approx 22547[/tex]

So the answer for this case would be n=22547 rounded up to the nearest integer

Step-by-step explanation:

Let's define some notation

[tex]\bar X[/tex] represent the sample mean

[tex]\mu[/tex] population mean (variable of interest)

[tex]\sigma=58.2[/tex] represent the population standard deviation

n represent the sample size  

[tex] ME =1[/tex] represent the margin of error desire

The margin of error is given by this formula:

[tex] ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]    (a)

And on this case we have that ME =+1 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

[tex]n=(\frac{z_{\alpha/2} \sigma}{ME})^2[/tex]   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance would be [tex]\alpha=0.01[/tex] and the critical value [tex]z_{\alpha/2}=2.58[/tex], replacing into formula (b) we got:

[tex]n=(\frac{2.58(58.2)}{1})^2 =22546.82 \approx 22547[/tex]

So the answer for this case would be n=22547 rounded up to the nearest integer

Clara writes the following proof for the theorem: If the diagonals of a quadrilateral bisect each other, the quadrilateral is a parallelogram: ​

Answers

Answer:

  CPCTC

Step-by-step explanation:

Statements 3 and 4 show the top and bottom triangles are congruent, and the left and right triangles are congruent. Statement 5 is making use of these facts to claim that the alternate interior angles are congruent. This claim is valid because ...

  Corresponding Parts of Congruent Triangles are Congruent (CPCTC)

What is the equation of a circle with center (−8, 3) and radius 8?

Answers

Answer:

(x + 8)² + (y - 3)² = 64

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (- 8, 3) and r = 8 , thus

(x - (- 8))² + (y - 3)² = 8² , that is

(x + 8)² + (y - 3)² = 64

Answer:

See below.

Step-by-step explanation:

The equation for a circle is:

[tex](x-h)^2+(y-k)^2=r^2[/tex], where (h,k) is the center and r is the radius.

Plug in what we know. (-8,3) for (h,k) respectively and 8 for the radius:

[tex](x-(-8))^2+(y-(3))^2=(8)^2[/tex]

[tex](x+8)^2+(y-3)^2=64[/tex]

What is the value of x in the equation 0.7 x - 1.4 = -3.5

Answers

Answer:

x=12.5

Step-by-step explanation:

0.7x times (-1.4)=-3.5

-0.28x=-3.5 (divide both sides)

Ans:12.5

Irvin buys a car for ​$21 comma 804. It depreciates 25​% each year that he owns it. What is the depreciated value of the car after 1​ yr? after 2​ yr? The depreciated value of the car after 1 yr is ​$? The depreciated value of the car after 2 yr is ​$?

Answers

Answer:

The depreciated value of the car after 1 yr is ​$16,353

The depreciated value of the car after 2 yr is ​$12,264.75

Step-by-step explanation:

Given

purchase amount P= $21,804

rate of depreciation R= 25%

applying the formula for the car deprecation we have

[tex]A= P*(1-\frac{R}{100} )^n[/tex]

Where,

A is the value of the car after n years,

P is the purchase amount,

R is the percentage rate of depreciation per annum,

n is the number of years after the purchase.

1. The depreciated value of the car after 1 yr is ​

n=1

[tex]A= 21,804*(1-\frac{25}{100} )^1\\\\A= 21,804*(1-0.25 )^1\\\\A= 21,804*0.75\\\\A= 16353[/tex]

The depreciated value of the car after 1 yr is ​$16,353

2. The depreciated value of the car after 2 yr is ​

n=2

[tex]A= 21,804*(1-\frac{25}{100} )^2\\\\A= 21,804*(1-0.25 )^2\\\\A= 21,804*0.75^2\\\\A= 21,804*0.5625\\\\A= 12264.75[/tex]

The depreciated value of the car after 2 yr is ​$12,264.75

The amount of time it takes a bat to eat a frog was recorded for each bat in a random sample of 12 bats. The resulting sample mean and standard deviation were 21.9 minutes and 7.7 minutes, respectively. Assuming it is reasonable to believe that the population distribution of bat mealtimes of frogs is approximately normal, a. Construct a 95% confidence interval for the mean time for a bat to eat a frog. b. Construct a 95% confidence interval for the variance of the time for a bat to eat a frog.

Answers

Answer: a. CI for the mean: 17.327 < μ < 26.473

b. CI for variance: 29.7532 ≤ [tex]\sigma^{2}[/tex] ≤ 170.9093

Step-by-step explanation:

a. To construct a 95% confidence interval for the mean:

The given data are:

mean = 21.9

s = 7.7

n = 12

df = 12 - 1 = 11

1 - α = 0.05

[tex]\frac{\alpha}{2}[/tex] = 0.025

t-score = [tex]t_{0.025,11}[/tex] = 2.2001

Note: since the sample population is less than 30, it is used a t-score.

The formula for interval:

mean ± [tex]t.\frac{s}{\sqrt{n} }[/tex]

Substituing values:

21.9 ± 2.200.[tex]\frac{7.7}{\sqrt{12} }[/tex]

21.9 ± 4.573

The interval is: 17.327 < μ < 26.473

b. A 95% confidence interval for the variance:

The given values are:

[tex]s^{2}[/tex] = [tex]7.7^{2}[/tex]

[tex]s^{2}[/tex] = 59.29

α = 0.05

[tex]\frac{\alpha}{2}[/tex] = 0.025

[tex]1-\frac{\alpha}{2}[/tex] = 0.975

[tex]\chi^{2}_{0.025,11}[/tex] = 21.92

[tex]\chi^{2}_{0.975,11}[/tex] = 3.816

Note: To find the values for [tex]\chi^{2}_{\alpha/2,n-1}[/tex] and [tex]\chi^{2}_{1-\alpha/2,n-1}[/tex], look for them at the chi-square table

The formula to calculate interval:

([tex]\frac{(n-1).s^{2}}{\chi^{2}_{\alpha/2,n-1}} , \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2,n-1}}[/tex])

are the lower and upper limits, respectively.

Substituing values:

([tex]\frac{11.59.29}{21.92} , \frac{11.59.29}{3.816}[/tex])

(29.7532, 170.9093)

The interval for variance is: 29.7532 ≤ [tex]\sigma^{2}[/tex] ≤ 170.9093

Consider circle T with radius 24 in. and θ = StartFraction 5 pi Over 6 EndFraction radians. Circle T is shown. Line segments S T and V T are radii with lengths of 24 inches. Angle S T V is theta. What is the length of minor arc SV?

Answers

Answer:

20π in

Step-by-step explanation:

Length of an arc is expressed as [tex]L = \frac{\theta}{2\pi } * 2\pi r\\[/tex]. Given;

[tex]\theta = \frac{5\pi }{6} rad\\ radius = 24in\\[/tex]

The length of the minor arc SV is expressed as:

[tex]L = \frac{\frac{5\pi }{6} }{2\pi } * 2\pi (24)\\L = \frac{5\pi }{12\pi } * 48\pi \\L = \frac{5}{12} * 48\pi \\L = \frac{240\pi }{12} \\L = 20\pi \ in[/tex]

Hence, The length  of the arc SV is 20π in

Answer:

20 pi

Step-by-step explanation:

Suppose the sequence StartSet a Subscript n Baseline EndSet is defined by the recurrence relation a Subscript n plus 1equalsnegative 2na Subscript n​, for nequals​1, ​2, 3,..., where a1equals5. Write out the first five terms of the sequence.

Answers

Answer:

-10, 40, -240, 1,920 and -19, 200

Step-by-step explanation:

Given the recurrence relation of the sequence defined as aₙ₊₁ = -2naₙ for n = 1, 2, 3... where a₁ = 5, to get the first five terms of the sequence, we will find the values for when n = 1 to n =5.

when n= 1;

aₙ₊₁ = -2naₙ

a₁₊₁ = -2(1)a₁

a₂ = -2(1)(5)

a₂ = -10

when n = 2;

a₂₊₁ = -2(2)a₂

a₃ = -2(2)(-10)

a₃ = 40

when n = 3;

a₃₊₁ = -2(3)a₃

a₄ = -2(3)(40)

a₄ = -240

when n= 4;

a₄₊₁ = -2(4)a₄

a₅ = -2(4)(-240)

a₅ = 1,920

when n = 5;

a₅₊₁ = -2(5)a₅

a₆ = -2(5)(1920)

a₆ = -19,200

Hence, the first five terms of the sequence is -10, 40, -240, 1,920 and -19, 200

Diagramming Percents
Percents
Total
An item was marked down 60% from its original price.
The amount of the discount was $30. Fill in the
numbers that belong in the diagram to find the original
price
20%
20%
20%
20%
20%
A=
B=
C=





Answers

Answer:

see below

Step-by-step explanation:

Let x be the original price

x* discount rate = discount

x * 60% = 30

Change to decimal form

x * .60 = 30

Divide each side by .60

x = 30/.60

x =50

The original price was 50 dollars

Answer:

A-30     B-20    C-50

Step-by-step explanation:

find the LCM and solve, it's very very urgent. ​

Answers

Answers:

1. 10502. 12003. 12004. 33605. 10806. 480

please see the attached picture for full solution..

Hope it helps....

Good luck on your assignment...

Refer to the accompanying data set and construct a 90​% confidence interval estimate of the mean pulse rate of adult​ females; then do the same for adult males. Compare the results.

Male/Females
81 82
77 94
53 60
59 66
53 53
60 81
54 78
76 83
52 87
64 53
73 34
57 64
65 83
78 74
79 81
66 66
69 65
94 76
45 61
89 64
71 82
66 80
70 71
74 77
52 88
68 90
56 87
79 91
75 89
62 93
66 68
96 87
60 83
65 81
55 74
57 56
70 101
70 71
83 74
57 77

Answers

The required 90% confidence interval for adult males is

[tex]\text {CI} = (64.2, \: 70.6)\\\\[/tex]

The required 90% confidence interval for adult females is

[tex]\text {CI} = (72, \: 79.2)\\\\[/tex]

The confidence interval of male and female pulse rates do not overlap since the mean pulse rate of female is way greater than the mean pulse rate of males.

Step-by-step explanation:

We are given the pulse rates of adult females and adult males and we have to construct the 90% confidence interval of the mean pulse rate for males and females.

Let us first compute the mean and standard deviation of the given pulse rates data.

Using Excel,  

=AVERAGE(number1, number2,....)  

The mean pulse rate of adult males is found to be

[tex]\bar{x}_{male} = 67.4[/tex]

The mean pulse rate of adult females is found to be

[tex]\bar{x}_{female} = 75.6[/tex]

Using Excel,  

=STDEV(number1, number2,....)    

The standard deviation for adult male pulse rate is found to be

 [tex]s_{male} = 11.9[/tex]

The standard deviation for adult female pulse rate is found to be  

 [tex]s_{female} = 13.5[/tex]

The confidence interval is given by

[tex]$ \text {CI} = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $\\\\[/tex]

Where [tex]\bar{x}[/tex] is the sample mean, n is the sample size, s is the sample standard deviation and   [tex]t_{\alpha/2}[/tex] is the t-score corresponding to a 90% confidence level.  

The t-score corresponding to a 90% confidence level is  

Significance level = α = 1 - 0.90 = 0.10/2 = 0.05  

Degree of freedom = n - 1 = 40 - 1 = 39

From the t-table at α = 0.05 and DoF = 39

t-score =  1.685

The required 90% confidence interval for adult males is

[tex]\text {CI} = 67.4 \pm 1.685\cdot \frac{11.9}{\sqrt{40} } \\\\\text {CI} = 67.4 \pm 1.685\cdot 1.882\\\\\text {CI} = 67.4 \pm 3.17\\\\\text {CI} = 67.4 - 3.17, \: 67.4 + 3.17\\\\\text {CI} = (64.2, \: 70.6)\\\\[/tex]

Therefore, we are 90% confident that the actual mean pulse rate of adult male is within the range of 64.2 to 70.6 bpm

The required 90% confidence interval for adult females is

[tex]\text {CI} = 75.6 \pm 1.685\cdot \frac{13.5}{\sqrt{40} } \\\\\text {CI} = 75.6 \pm 1.685\cdot 2.1345\\\\\text {CI} = 75.6 \pm 3.60\\\\\text {CI} = 75.6 - 3.60, \: 75.6 + 3.60\\\\\text {CI} = (72, \: 79.2)\\\\[/tex]

Therefore, we are 90% confident that the actual mean pulse rate of adult female is within the range of 72 to 79.2 bpm

Comparison:

The confidence interval of male and female pulse rates do not overlap since the mean pulse rate of female is way greater than the mean pulse rate of males.

what is the value of n?

Answers

Answer:

the answer is D

Step-by-step explanation:

Answer:

95°

Step-by-step explanation:

To get the value of n° we must get the values of the traingle angle's sides

and to do that :

180°-144°=36° the first one 180°-121°= 59° the second one 180°-(59°+36°)= 85 the third one n) = 180-85° = 95°

What is the discontinuity of x2+7x+1/x2+2x-15?

Answers

The discontinuity occurs when x is either -5 or 3.

That is determined by solving denominator = 0 quadratic equation for x.

Hope this helps.

A fair die is rolled repeatedly. Calculate to at least two decimal places:__________
a) the chance that the first 6 appears before the tenth roll
b) the chance that the third 6 appears on the tenth roll
c) the chance of seeing three 6's among the first ten rolls given that there were six 6's among the first twenty roles.
d) the expected number of rolls until six 6's appear
e) the expected number of rolls until all six faces appear

Answers

Answer:

a. 0.34885

b. 0.04651

c. 0.02404

d. 36

e. 14.7, say 15 trials

Step-by-step explanation:

Q17070205

Note:  

1. In order to be applicable to established probability distributions, each roll is considered a Bernouilli trial, i.e. has only two outcomes, success or failure, and are all independent of each other.

2. use R to find the probability values from the respective distributions.

a) the chance that the first 6 appears before the tenth roll

This means that a six appears exactly once between the first and the nineth roll.

Using binomial distribution, p=1/6, n=9, x=1

dbinom(1,9,1/6) = 0.34885

b) the chance that the third 6 appears on the tenth roll

This means exactly two six's appear between the first and 9th rolls, and the tenth roll is a six.

Again, we have a binomial distribution of p=1/6, n=9, x=2

p1 = dbinom(2,9,1/6) = 0.27908

The probability of the tenth roll being a 6 is, evidently, p2 = 1/6.

Thus the probability of both happening, by the multiplication rule, assuming independence  

P(third on the tenth roll) = p1*p2 = 0.04651

c) the chance of seeing three 6's among the first ten rolls given that there were six 6's among the first twenty roles.

Again, using binomial distribution, probability of 3-6's in the first 10 rolls,

p1 = dbinom(3,10,1/6) = 0.15504

Probability of 3-6's in the NEXT 10 rolls

p1 = dbinom(3,10,1/6) = 0.15504

Probability of both happening  (multiplication rule, assuming both events are independent)

= p1 *  p1 = 0.02404

d) the expected number of rolls until six 6's appear

Using the negative binomial distribution, the expected number of failures before n=6 successes, with probability p = 1/6

=  n(1-p)/p

Total number of rolls by adding n  

= n(1-p)/p + n = n(1-p+p)/p = n/p = 6/(1/6) = 36

e) the expected number of rolls until all six faces appear

P1 = 6/6 because the firs trial (roll) can be any face with probability 1

P2 = 6/5 because the second trial for a different face has probability 5/6, so requires 6/5 trials

P3 = 6/4 ...

P4 = 6/3

P5 = 6/2

P6 = 6/1

So the total mean (expected) number of trials is 6/6+6/5+6/4+6/3+6/2+6/1 = 14.7, say 15 trials

Which expression is equivalent to -3(2m - 1) - n? 6m - n - 3 6m - n + 3 -6m - n - 3 -6m - n +3

Answers

Answer:

-6m+3

Step-by-step explanation:

Answer:

An equivalent value is -6m -n +3

Step-by-step explanation:

Given

-3(2m-1)-n   expand

=-6m+3-n

(also equals -6m -n +3 by commutativity)

Which of the following is represented by MN?

Answers

A- radius of circle, half of a diameter

Answer: MN represents the radius of the circle.

Step-by-step explanation:

The radius is the distance from the center to the outside of the circle.

Perform the operation 3/a^2+2/ab^2

Answers

Answer:

Step-by-step explanation:

Least common denominator = a²b²

[tex]\frac{3}{a^{2}}+\frac{2}{ab^{2}}=\frac{3*b^{2}}{a^{2}*b^{2}}+\frac{2*a}{ab^{2}*a}\\\\=\frac{3b^{2}}{a^{2}b^{2}}+\frac{2a}{a^{2}b^{2}}\\\\=\frac{3b^{2}+2a}{a^{2}b^{2}}[/tex]

f(x)=1/3x g(x)= 1/3x f(g(x))= Are they inverses? Please explain.

Answers

Answer:

no

Step-by-step explanation:

f(g(x))= x if they are inverses

(x)=1/3x

g(x)= 1/3x

f(g(x)) = 1/3 (g(x) = 1/3 (1/3x) = 1/9x

This is not x so they are not inverse functions

The Beer Institute reported that monthly consumption of beer in is 1.7 gallons per person. A random sample of 36 adults was selected. Using a population standard deviation of 0.5 gallons per month per person, what is the probability that the sample mean was between 1.6 and 1.8 gallons per month per person?

Answers

Answer:

.7698

Step-by-step explanation:

The book was purchased for $8 and half of its price. How much does the book cost?

Answers

Answer:

16$

Step-by-step explanation:

8*2=16

HOPE THIS HELPS :)

Answer: $16

Step-by-step explanation:

As the book was purchased for half its price plus 8 you can create the equation 1/2x + 8 = x.  Then, simplifying the expression you get x = 16.  Thus, the book costs 16 dollars.

Convert into the following unit into 30 cm into miter​

Answers

Answer:

it we'll be 0.3

Step-by-step explanation:

trust me man I like to explain but it's long

Answer:

0.3 meter or 3/10 meter

Step-by-step explanation:

As there are 100cm in 1 meter and you want to find 30cm in terms of meters.

It will be as

100cm = 1 meter     (rule/lax)

100/100 cm = 1/100  meter   (divide both sides of equation with 100)

1 cm = 1/100 meter

1 *30 cm = (1/100)*30  meter    (multiply both sides with 30)

30 cm = 30/100 meter

30/100 more shortly can be written as  3/10 meter or in decimals 0.3 meter.

Reese needs to understand the integer laws to complete his homework. As he recites his rules, he is overheard saying "a positive plus a positive is positive, a negative plus a negative is negative, and a positive plus a negative is a negative". Is he right? Explain why or why not?

Answers

Answer:

No

Step-by-step explanation:

Let's check the first statement with an example. 2 and 3 are positive numbers and their sum (5) is also positive so his first statement is true.

To check the second statement let's look at the negative numbers -1 and -8 for example. Their sum (-9) is also negative so his second statement is true.

To check the third statement let's look at the numbers 9 and -5. One is positive and one is negative, but their sum (4) is positive, so his third statement is false. However if we look at the numbers 4 and -7, their sum is negative so the third statement is partially false.

find the value of k if x minus 2 is a factor of P of X that is X square + X + k​

Answers

Answer:

k = -6

Step-by-step explanation:

hello

saying that (x-2) is a factor of [tex]x^2+x+k[/tex]

means that 2 is a zero of

[tex]x^2+x+k=0 \ so\\2^2+2+k=0\\<=> 4+2+k=0\\<=> 6+k =0\\<=> k = -6[/tex]

and we can verify as

[tex](x^2+x-6)=(x-2)(x+3)[/tex]

so it is all good

hope this helps

y-9=-2(x-8) what is the slope?

Answers

Answer:

-2

Step-by-step explanation:

Write in slope intercept form.

y - 9 = -2(x - 8)

y - 9 = -2x + 16

y = -2x + 16 + 9

y = -2x + 25

y = mx + b

The m is the slope, b is the y-intercept.

y = -2 x + 25

The slope is -2.

The Aluminum Association reports that the average American uses 56.8 pounds of aluminum in a year. A random sample of 51 households is monitored for one year to determine aluminum usage. If the population standard deviation of annual usage is 12.2 pounds, what is the probability that the sample mean will be each of the following? Appendix A Statistical Tables a. More than 61 pounds

Answers

Answer:

0.007

Step-by-step explanation:

We were told in the above question that a random sample of 51 households is monitored for one year to determine aluminum usage

Step 1

We would have to find the sample standard deviation.

We use the formula = σ/√n

σ = 12.2 pounds

n = number of house holds = 51

= 12.2/√51

Sample Standard deviation = 1.7083417025.

Step 2

We find the z score for when the sample mean is more than 61

z-score formula is z = (x-μ)/σ

where:

x = raw score = 61 pounds

μ = the population mean = 56.8 pounds

σ = the sample standard deviation = 1.7083417025

z = (x-μ)/σ

z = (61 - 56.8)/ 1.7083417025

z = 2.45852

Finding the Probability using the z score table

P(z = 2.45852) = 0.99302

P(x>61) = 1 - P(z = 2.45852) = 0.0069755

≈ 0.007

Therefore,the probability that the sample mean will be more than 61 pounds is 0.007

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