an eager puppy runs in a straight line. its motion is shown on the following graph of horizontal position X vs time. What is the instantaneous speed of the puppy at t = 2s?

Answers

Answer 1

Answer: 0.25m/s

Explanation:

Answer 2

Answer:

Explanation:

Blab balh its 0.25 m/s


Related Questions

Protons are found only in the atomic nucleus.
TRUE
FALSE

Answers

Answer:

true

Explanation:

Protons and neutrons are found in the nucleus

A runner moves at an average speed of 3.0 m/s and covers 9.5 km. In seconds, how long does the run take?

28.5 s
29.0 s
3.16 s
3200 s

Answers

Answer:

3200 seconds

Explanation:

If he ran at 3 m/s for 28.5 seconds, he would have run 85.5 meters

29 seconds would be 87 meters run not 9.5 km

3200 s is the right answer

A toy car rolls down a hill starting from rest. After 4.2 seconds its velocity is 18 meters per second. What is the acceleration of the car ?

SOMEONE PLZ HELP :(
WILL MARK BRAILIEST

Answers

Answer: if this is the same question I think it’s 24

Explanation:

An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west. It starts at the 14-inch mark, crawls to the 20-inch mark, then moves to the 16-inch mark. What was the total distance the ant traveled?

Answers

Given :

An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west.

It starts at the 14-inch mark, crawls to the 20-inch mark, then moves to the 16-inch mark.

To Find :

The total distance the ant traveled.

Solution :

Total distance travelled by ant = (distance between 14 and 20 inch mark) +

                                                      (distance between 20 and 16 inch mark)

Total distance = (20-14 ) + ( 20-16) = 6 + 4 = 10 inch.

Therefore, total distance the ant traveled is 10 inch.

Hence, this is the required solution.

If you run east for 38m, stop suddenly, run another 27m east, then you run west for 47
m, what is your total displacement?
how to answer: #m, direction

Answers

Answer:

Total Displacement = -18m

Explanation:

Given

East Movement = 38m and 27m

West Movement = 47m

Required

Determine the total displacement

To answer this, we consider east as negative direction and the west as positive (using logics of number line).

Total Displacement = East Movement + West Movement

Total Displacement = -38m - 27m + 47m

Total Displacement = -18m

Hence, the total displacement is 18m towards East

The photo shows dew drops that formed on the grass when temperatures
cooled during the night. Which change of state happened to form the dew?
A. Liquid to gas
B. Gas to liquid
C. Solid to gas
D. Gas to solid

Answers

Gas to a liquid
This is because of condensation
gas to liquid is the answer

A water skier is towing by motorboat at a constant velocity of magnitude 15 km /h. The boat speed up, and after a short interval the skier is towed at a new constant velocity of magnitude 20 km/h. What is the net force on the skier when she is moving at 15 km/h? And at 20 km/h?

Answers

Answer:

The skier is experimenting a net force of 0 newtons in both cases. ([tex]v_{1} = 15\,\frac{km}{h}[/tex], [tex]v_{2} = 20\,\frac{km}{h}[/tex])

Explanation:

According to Newton's First Law, an object is in equilibrium when it is either at rest or moving at constant velocity, which means that net force is equal to 0 newtons.

Therefore, the skier is experimenting a net force of 0 newtons in both cases.

What 2 gases make up most of the atmosphere?

Answers

Answer:

nitrogen oxygen carbon dioxideand argon

Explanation:

#7 If the Moon’s mass was suddenly tripled, what would occur to the gravitational force between the Earth and the Moon?
(A) Gravitational force would increase by a factor of 3.
(B) Gravitational force would decrease by a factor of 3.
(C) Gravitational force would increase by a factor of 9.
(D) Gravitational force would decrease by a factor of 9.

Answers

Answer:

well it would be (A) Gravitational force would increase by a factor of 3.

Explanation:

because the moon is the only thing that gained mass not the Earth

A student fires a cannonball vertically upwards. The cannonball returns to the
ground after a 4.60s flight. Determine all unknowns and answer the following
questions. Neglect drag and the initial height and horizontal motion of the
cannonball. Use regular metric units (ie. meters).
How long did the cannonball rise?
unit
What was the cannonball's initial speed?
unit
What was the cannonball's maximum height?
unit
V

Answers

Answer:

(a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

Explanation:

Given that,

Time = 4.60 s

We need to calculate the initial velocity

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into the formula

[tex]0=u-9.8\times4.60[/tex]

[tex]u=45.0\ m/s[/tex]

We need to calculate the distance

Using formula of distance

[tex]d=v\times t[/tex]

Put the value into the formula

[tex]d=45\times4.60[/tex]

[tex]d=207\ m[/tex]

We need to calculate the maximum height

Using equation of motion

[tex]v^2=u^2-2gh[/tex]

Put the value into the formula

[tex]0=(45.0)^2-2\times9.8\times h[/tex]

[tex]h=\dfrac{(45.0)^2}{2\times9.8}[/tex]

[tex]h=103.3\ m[/tex]

Hence, (a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

what does the galaxy made of ?​

Answers

Galaxies are sprawling systems of dust, gas, dark matter, and anywhere from a million to a trillion stars that are held together by gravity. Nearly all large galaxies are thought to also contain supermassive black holes at their centers.

A force of 75 N at an angle of 15° to the direction of motion moves a chair 3 m. Which change would result in more work being done on the chair?

Answers

Answer:

Decreasing the angle to 10

Explanation:

Edge 2020

How are velocity, wavelength, and frequency related

Answers

Answer:

The wave velocity and the wavelength are related to the wave's frequency and period by vw=λT or vw=fλ. The time for one complete wave cycle is the period T. The number of waves per unit time is the frequency ƒ. The wave frequency and the period are inversely related to one another.

Explanation:

What will be acceleration due to gravity of a feather and coin if
they are dropped in vacuum?​

Answers

Explanation:

Hey there!

We know that the objects in vacuum falls equally on the surface or bottom. As there is no air resistance in vacuum, the objects has equal stabdard acceleration. (i.e g = 9.8m/s^2)

So, the acceleration due to gravity is 9.8m/s^2.

Hope it helps....

which of the following is the same as 1 second

Answers

Answer:

theres no

Explanation:

picture or anything so... ur question doesnt make sense

There’s no picture or anything :(

At a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2. What can the staff member estimate for the original speed of the race car if it came to a stop during the skid?

Answers

Answer:

27.1 m/s

Explanation:

Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.

Using third equation of motion,

V^2 = U^2 + 2aS

Since the car is decelerating, the final velocity V = 0

Substitute all the parameter into the equation above,

0 = U^2 - 2 * 40.52 * 9.06

U^2 = 734.22

U = [tex]\sqrt{734.22}[/tex]

U = 27.096

U = 27.1 m/s  approximately

Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid

Question 4 of 20
Luke wraps a magnetized steel nail with several coils of insulated wire and
then connects the loose ends of the wire to a 10 W lightbulb. Which step
could he take next to get the lightbulb to light up?
O A. Replace the magnetized nail with a nonmagnetic metal to cause
an electric current to flow in the wire.
O B. Remove the magnetized nail from the wire coil to induce a
magnetic field that will flow through the wire.
C. Move the magnetized nail back and forth within the wire coil to
induce an electric current in the wire.
D. Add several more coils of the wire around the magnetized nail to
make a stronger electric current.
SUBMIT

Answers

Answer:

C. Move the magnetized nail back and forth within the wire coil to induce an electric current in the wire.

Hope this helps.

The moon euphoria is in a circular orbit around Jupiter. Which of the following describes the direction of the centripetal force acting on euphoria.
A) pointing hand into the path of its orbit
B) pointing towards the sun
C)Pointing away from Jupiter
D) pointing towards Jupiter

Answers

I think it’s A I’m not sure love but hope this helps sorry if it’s not since a Centripetal Force is a a force that acts on a body moving in a circular path and is directed toward the center around which the body is moving. You can think which one is pointing towards the center and and an object moving in a circular turn

A rocket takes off from Earth. It travels 825km in 75 seconds. What is the
speed of the rocket?
0 1 km/s
11 km/s
O 1.1 km/s
O 111 km/s

Answers

Answer:

11 km/s

Explanation:

v=s/t

v=825km/75s

v=11km/s

Which of the following would be best for absorbing light?

a A mirror

b A black shirt

c glass

d concrete

Answers

B.) a black shirt


Explanation:
A black object absorbs all the light; it doesn’t reflect any color

5 grams is thes than greater than or equal too 508mg

Answers

Answer:

yes 5 is greater

Explanation:

Answer: 5 grams is greater than 508 milligrams. Even though the number '508' is larger than '5,' you need to look at the units.

Which model of the atom has electrons traveling in specific paths around the nucleus? Bohr's model Rutherford's model Thomson's model Dalton's model

Answers

Answer:

A, Bohr's model

Explanation:

Took the quiz, hope it's right for you.

(The other three did have something to do with it they just didn't create that specific model)

The model of the atom that has electrons traveling in specific paths around the nucleus is Rutherford's model.

Therefore, the correct answer is option B

J. J Thomson proposed that the atom is a sphere of positively charged matter in which negatively charged electron are embedded.

In Rutherford's model of atomic structure, the electrons moves in orbits by electrostatic attraction to the positively charged nucleus.

According to Dalton's atomic theory, atom were indestructible and indivisible  solid particle.

Bohr's model made assumption that electron can only exist in circular orbits of definite quantum energy.  

According to the question, the model of the atom that has electrons traveling in specific paths around the nucleus is Rutherford's model.

Therefore, the correct answer is option B

Learn more here : https://brainly.com/question/16776207

How do electromagnetic waves affect you?

Answers

Answer:

At low frequencies, external electric and magnetic fields induce small circulating currents within the body. ... The main effect of radiofrequency electromagnetic fields is heating of body tissues. There is no doubt that short-term exposure to very high levels of electromagnetic fields can be harmful to health.

1 point
1)A 1 kg brick is carried to up the Eiffel Tower to the 275 m platform. How
much gravitational potential energy does it acquire?

Answers

Answer:

The gravitational potential energy is 2,750 Joules

Explanation:

Given the following data;

Mass of brick = 1kg

Height of Eiffel Tower = 275m

Potential energy can be defined as the energy possessed by an object due to its position.

Mathematically, potential energy is;

[tex] P = mgh[/tex]

Also, we know acceleration due to gravity = 10m/s2

[tex] P = mgh[/tex]

[tex] P = 1 * 275 * 10 [/tex]

P = 2750 Joules.

Hence, the gravitational potential energy the brick acquired is 2750 Joules.

List out Units For: Acceleration

Answers

Acceleration units : M/s squared

Unit for Acceleration is m/s² or ms raised to -2

please help im dying

Answers

This is the answer hope you get it:)

Dos pilotos suicidas, que están inicialmente a una distancia de 500 m entre sí, deciden chocar directamente de frente arrancando ambos desde el reposo. Ambos autos pueden desarrollar una aceleración máxima constante de 15 m/s2 . Si el piloto A arranca un segundo antes que el piloto B, encuentra: a) la posición donde los autos chocan, medida a partir de la posición donde arranca el piloto A, y b) la rapidez relativa de la colisión (la rapidez de B con respecto a A justo antes de la colisión, ó viceversa).

Answers

Answer:

a) El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A es de aproximadamente 293,14 metros.

b) La velocidad del automóvil A, en relación con la velocidad del automóvil B, es de 15 m / s

Explanation:

Los parámetros del movimiento son;

La distancia entre ambos coches = 500 m

La aceleración de ambos coches = 15 m / s²

La dirección de movimiento de ambos coches = uno hacia el otro

La hora de inicio del conductor A = Un segundo antes de la hora de inicio del conductor B

Por lo tanto, de la ecuación de movimiento, tenemos;

s = u · t + 1/2 · a · t²

v² = u² + 2 · a · s

Dónde;

u = La velocidad inicial de los autos = 0 (los autos parten del reposo)

t = El tiempo de movimiento de una aceleración dada

a = La aceleración = 15 m / s²

s = La distancia recorrida en el tiempo t

Por lo tanto, para el controlador A, tenemos;

s₁ = 0 × (t + 1) + 1/2 × 15 × (t + 1) ² = 7.5 × (t + 1) ²

s₁ = 7.5 × (t + 1) ²

Para el conductor B, tenemos;

s₂ = 0 × t + 1/2 × 15 × t² = 7.5 × t²

s₂ = 7,5 × t²

Dado que ambos chocan a lo largo del camino de 500 m, tenemos;

s₁ + s₂ = 500 metros

∴ 7.5 × (t + 1) ² + 7.5 × t² = 500

∵ s₁ + s₂ = 7.5 × (t + 1) ² + 7.5 × t²

Lo que da;

15 · t² + 15 · t + 7.5 = 500

15 · t² + 15 · t - 492,5 = 0

Resolver usando la aplicación en línea da; t = -6,25181 o t = 5,25181

Dado que t es un número natural, tenemos el valor correcto para t = 5.25181 segundos

a) Por tanto, el punto de colisión de los dos coches desde donde parte el conductor del coche A es;

s₁ = 7.5 × (t + 1) ² = 7.5 × (5.25181 + 1) ² ≈ 293.14 metros

El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A ≈ 293,14 metros

b) La semilla de A en el punto de colisión se da de la siguiente manera

Velocidad, v₁ = u + a × (t + 1) = 0 + 15 × (5.25181 + 1) ≈ 93.78

v₁ ≈ 93,78 m / s

La semilla de B en el punto de colisión también se da de la siguiente manera

Velocidad, v = u + a × (t) = 0 + 15 × 5.25181 ≈ 78.78

v₁ ≈ 78,78 m / s

Por lo tanto, la velocidad del automóvil A, en relación con la velocidad del automóvil B, [tex]v_{relative}[/tex] se da como sigue;

 = v₁ - v₂ = 93,78 m / s - 78,78 m / s = 15 m / s

la velocidad del automóvil A, relativa a la velocidad del automóvil B = 15 m/s.

A dog is 60 m away while moving at a constant velocity of 10 m/s towards you. How Long will it be before the dog is close enough to your face?

Answers

Answer:

6 seconds

Explanation:

The answer is 6 because if the dog is going 10 m/s it will take 6 seconds to get from 60 meters away to you.

how much force is needed to accelerate 300 kg at a rate of 4 m/s/s​

Answers

Answer:

1200

Explanation:

Force = Mass x Acceleration

Answer:

[tex]\boxed {\tt 1,200 \ Newtons }[/tex]

Explanation:

Force can be found by multiplying the mass by the acceleration.

[tex]F=m*a[/tex]

The mass is 300 kilograms.

The acceleration is 4 meters per second squared.

[tex]m= 300 \ kg\\a= 4 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]F= 300 \ kg * 4 \ m/s^2[/tex]

Multiply.

[tex]F= 1200 \ kg * m/s^2[/tex]

1 Newton is equal to 1 kilograms meters per second squared, so our current answer of 1200 kg m/s² is equal to 1200 Newtons.

[tex]F= 1200 \ N[/tex]

The force needed is 1,200 Newtons.

Why does sonar use ultrasound rather than sound?

Answers

Answer;  Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances.

Answer:

Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances

Explanation:

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