An B flat is played on a french horn, whose frequency is 466Hz.
1. what is the period of one vibration of this tone?
2. as the sound leaves the instrument at a speed of 343m/s, what is the wavelength?

Answer:

the step that the student should change is step 7

Explanation:

The movement of the spring with block is a simple harmonic type movement, so the procedure proposed by the student is correct, but we must take some care.

Step 3 is important since each movement will be started with similar conditions, also if any displacement is very large we can get out of the linear approximation of Hooke's law, for which we need to know the equilibrium point, since from this point displacements will be measured.

Step 6 should be changed to measure various oscillations to find the average period and thus decrease the error in the time reading.

Step 7 is wrong since the objective of the experiment is to analyze the effect of different masses in the period of oscillation and this step prevents this objective from being carried out.

In conclusion, the step that the student should change is step 7

The step that should be revised to make the determination is c. Step 6, because the stopwatch should be used only to measure the time it takes for the system to make 1 complete oscillation.

The student is trying to find the effect of the mass of the block on the period of oscillation in different vertical displacements.

The best way to do this is to measure the time taken per oscillation as this would show a much clearer picture to find the effect of the mass on the oscillation. Timing 10 oscillations will yield incorrect results.

In conclusion, option C is correct.

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Answer:

distance

hope it helps

Explanation:

-

Answer:

x = 45 cm

Explanation:

Given that,

The length of a rod, L = 50 cm

Mass, m₁ = 0.2 kg

It is at 40cm from the left end of the rod.

We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.

The centre of mass of the rod is at 25 cm.

Taking moments of both masses such that,

[tex]15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm[/tex]

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

Answer:

They will speed up, and decrease in density.

Explanation:

This is because, when water is heated, the molecules will spread apart, and bounce off each other. It gives them more space, and they are less tight packed, so it can move around freely.

Answer:

166.6 N

Explanation:

Given that,

Force, F₁ = 20 N

Area, A₁ = 10 dm² = 1000 cm²

We need to find the new force if the area of the larger piston is 120 cm². According to Pascal's law,

[tex]F_1A_1=F_2A_2\\\\F_2=\dfrac{F_1A_1}{A_2}\\\\F_2=\dfrac{20\times 1000}{120}\\\\F_2=166.7\ N[/tex]

So, the force on the larger piston is equal to 166.7 N.

Answer:

[tex]22.4 \: {dm}^{3} \: are \: occupied \: by \: 1 \: mole \\ 12 \: {dm}^{3} \: will \: be \: occupied \: by \: ( \frac{12}{22.4} ) \: moles \\ = 0.536 \: moles[/tex]

Number of moles of water molecules in 12 dm^3 of water =667 moles

A mole is defined as the amount of a substance that contain exactly 6.022 * 10 ^23 elementary entities of the given substance

1 dm ^3 = 1 L

12 dm^3 = 12 L

density of water = mass / volume

             mass = 1000kg/m^3 * 0.012 m^3

             mass = 12 kg = 12 * 10 ^ 3 g

moles = mass / molar mass

moles =  12 * 10 ^ (3 ) g / 18 g/mole

          = 0.667 *10 ^ (3 )

          = 667 moles

Number of moles of water molecules in 12 dm^3 of water =667 moles

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Answer:

correct  is C

Explanation:

In this exercise we will use the rotational equilibrium relationships. Let's set the datum at the pivot point and counterclockwise rotations as positive

as the bar is uniform its center of mass coincides with its geometric center

          x_{cm} = 0.25 cm

the distance from the fulcrum is

          x₁ = 0.40 - xcm

          x₁ = 0.40 - 0.25

          x₁ = 0.15 m

         Στ = 0

         w_bar 0.15 - W x = 0

         x = 0.15 w_bar / W

         x = 0.15 m_{bar} / M

let's calculate

         x = 0.15 0.2 /0.6

         x = 0.05 m

this distance is measured from the pivot point of the positive side, if we measure from the left end of the bar

          X = 0.4 + 0.05

          X = 0.45 m = 45 cm

correct  is C

Answer:

Swimmer A

Explanation:

The time required for a swimmer to cross a river is equal to the width of the river which is divided by the magnitude of the component of the velocity which is parallel to the width of the river.

In the given context, all the three swimmers A, B and C swims in a different angle relative to the direction of the flow of river. The swimmer A swims straight at a direction perpendicular to the direction of current of the river across the width of the river, so A will have the largest velocity component which is parallel to the width of the river. So the time taken by swimmer A will be the least to cross the river.

Answer:

it's frequency

Explanation:

hope this helps :)

Answer:

its probably its frequency

Explanation:

-

Explanation:

f=v/wavelength

=200/5

=40Hz

Answer:

Cuboid?

Explanation:

Answer:

0.43622 seconds

0.9158 foot

-4.43 ffot/sec

Explanation:

we first find the period of oscillation

= 2π√w/gk

= 2π√4000/32x2600

= 2π√0.00481

= 2π0.0694

= 0.43622

b. we find the angular velocity

2π/T

= 2π/0.43622

= 14.41 rad/sec

we find displacement

rom the calculation in the attachment

Ф = -144.1

initial condition

1*cos(-144.1 rad)

= 0.9158 foot

initial velocity of the car

= (-1)(14.41)sin(ω(0)-144.1)

= -4.44 foot/sec

Answer:An object that absorbs ALL radiation falling on it, at all wavelengths, is called a blackbody. When a blackbody is at a uniform temperature, its emission has a characteristic frequency distribution that depends on the temperature. ... As its temperature increases further it becomes yellow, white, and ultimately blue-white

Explanation:

Answer:

The emf source acts as a charge pump, moving negative charges from the positive terminal to the negative terminal to maintain the potential difference. This increases the potential energy of the charges and, therefore, the electric potential of the charges.

Explanation:

MARK AS BRAINLEST!!

Answer:

B. 686N

Explanation:

well do not write this because of I made a big mistake in my calculations

The tension on Box A if the acceleration of the system is provided clockwise is 686N.

The tension is the force of pulling in the linear objects.

Given is the system of two masses hung over a pulley with a string. Mass of block A, M(A) =35kg, M(B) = 20kg and the acceleration clockwise a =-2.67 m/s²

The tension in the string of each block = T =m(g-a)

Substitute the values, we get

T = 35 x (9.81-(-2.67)) +20(9.81 +2.67)

T =436.8 N + 249.6

T = 686.4 N

Thus, the tension in the the block A will be approximately 686N.

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Answer:

because of gravity the ball falls

Answer:

Gravity

Explanation:

Gravity is the force the world gives which I magnetic and yeah-

Answer:

Since Force is Mass * Acceleration, the equation would be:

5kg * 2m^2 = 10N

(10N is less than 65N)

Therefore, it would not be enough force for the bag to break.

Answer:

a)  t = 0.90 s, b)  t = 0.815 s, c)  t = 0.90 s, d)  x = 3.6 m, e)  t = 0.639 s

Explanation:

all these exercises are about kinematics

a) The body is released from rest,  

           y = y₀ + v₀ t - ½ g t²

in this case when reaching the ground y = 0 and its initial velocity is vo = 0

           0 = y₀ + 0 - ½ g t²

           t² = 2 y₀ / g

           t² = 2 4 /9.81

           t² = 0.815

            t = √0.815

           t = 0.90 s

b) It is thrown upwards at v₀ = 4 m / s

         y = y₀ + v₀ t - ½ g t²

in this case the initial and final height is the same

        y = y₀ = 0

        0 = v₀ t -1/2 g t²

        t = 2 v₀ / g

        t = 2 4 /9.81

        t = 0.815 s

c) the ball is at y₀ = 4 m and its initial velocity is horizontal v₀ = 4 m / s

        y = y₀ + v_{oy} t - ½ g t²

        0 = y₀ + 0 - ½ g t²

        t² = 2 i / g

        t² = 2 4 / 9.81

        t² = 0.815

        t = 0.90 s

d) the horizontal distance traveled is

        x = v₀ₓ t

        x = 4 0.90

        x = 3.6 m

e) We can calculate the time to fall from I = 2 m

        y = y₀ + v_{oy} t - ½ g t²

        0 = y₀ + 0 - ½ g t²

        t² = 2 y₀i / g

        t² = 2 2 /9.81

        t² = 0.4077

        t = 0.639 s

Therefore, when making measurements, you should find readings around this value.

Answer:

166.67 N

Explanation:

Applying Pascal's principle,

Presure in the smaller piston(P') = Pressure in the bigger piston(P)

But,

Pressure = Force/Area

Pressure in the smaller piston(P') = Force applied to the smaller piston(F')/Area of the smaller piston(A')

Pressure in the bigger piston(P) =  Force applied to the bigger piston(F)/Area of the bigger piston(A)

F'/A' = F/A.................. Equation 1

Make F the subject of the equation

F = F'A/A'.............. Equation 2

From the question,

Given: F' = 20 N, A = 120 cm², A' = 10 dm² = (10×100) = 1000 cm²

Substitute these values into equation 2

F = 20(1000)/120

F = 166.67 N

Dense because food do be dense tho

Answer:

A)  attached below

B) attached below

C) Anti-clockwise

D) 3.27 secs

Explanation:

A) Diagram of the gyroscope indicating direction of

attached below

B) Diagram of torque due to gravity about support point

Attached below

C) The direction the gyroscope will precess is ANTICLOCKWISE

D) Time required for one precession of the gyroscope

 use the relation below

MgL = ΔIw / Δt  

∴ Δt = ΔIw / MgL

       =( 1/2 * 2 * 0.25^2 * 2π * 2000 ) / ( 2 * 10 * 0.2 * 60 )

       = 3.27 secs

Answer:

896.5 m/s

Explanation:

Given that :

Length of metal bar, λ= 5 m

Velocity in air, v = 343 m/s

Change in air frequency : = λ / v

f = 5 / 343 = 0.0145772 s = 14.5772 ms

Seperation time = 9ms

Change in time, t = 14.5772 - 9 = 5.5772 ms

Recall :

Velocity = Distance / time

V = 5m / 5.5772 * 10^-3 s

V = 896.50720 m/s

Velocity = 896.5 m/s

Answer:

A. it contains ultraviolet, visible, and infrared light

Answer:

It is divided into seven ranges of wavelengths

Explanation:

i took the test

Answer:

fusion

Explanation:

The nuclear reactions inside convert hydrogen into helium by means of a process known as fusion. It is this nuclear reaction that gives a star its energy. Fusion takes place when the nuclei of hydrogen atoms with one proton each fuse together to form helium atoms with two protons.

Answer:

The centre of gravity (COG) of the human body is a hypothetical point around which the force of gravity appears to act. It is a point at which the combined mass of the body appears to be concentrated.

The centre of gravity (COG) of an object is the point at which weight is evenly dispersed and all sides are in balance. A human's centre of gravity can change as he takes on different positions, but in many other objects, it's a fixed location.

Answer:

otinni oSame lage ta dili pud ko ka comment sa live Ni madamstin

Answer:

it can be used to locate underwater objects

Answer:

A tuner is a subsystem that receives radio frequency (RF) transmissions and converts the selected carrier frequency and its associated bandwidth into a fixed frequency that is suitable for further processing, usually because a lower frequency is used on the output.

hope it helps ya mate.

Answer:

The tuner selects only the signal of a specific frequency and rejects the rest.

Explanation:

pf