An astronaut has a mass of 70kg.
The force of gravity on the Moon is approximately 1.5N/kg.
Calculate the weight of the astronaut when they are on the Moon.

Weight = .............................................................. N

Answers

Answer 1

Answer:

Weight = 105 Newton

Explanation:

Given the following data;

Mass = 70kg

Force of gravity = 1.5N/kg

To find the weight;

Weight = mass * force of gravity

Substituting into the equation, we have;

Weight = 70 * 1.5

Weight = 105 Newton

Therefore, the weight of the astronaut when they are on the Moon is 105 Newton.


Related Questions

Which one of the following best describes a fuse?

Answers

A material that allows current to travel through a circuit

The answer to anyones problems-

Answers

Answer:

POGGGGGGGGGGGGGGG

Explanation:





4. A substance is cut into several piece and compared to the density of the
original sample. The density of each piece will be:-
areater
bl the same​

Answers

Answer:

The density pf each piece will be the same, since density is defined as a mass per unit volume, so even when you cut an object it will not change

4. Determine the net force for the free-body
diagram
Fnorm = 40N
Ffrict =28N
Fapp =44N
Fgrav = 40N

Answers

Answer:

Fapp =44N is the correct answer

Explanation:

Please mark brainliest

HELP please!!!!!!!!!!!!!!!​

Answers

Nolur acil lütfen yalvarırım sana

What do seismic waves and sound waves have in common?

Answers

They're both a type of mechanical wave, which require a medium for propagation.

An electric iron is connected to the mains power supply of 220 V. When the electric iron is

adjusted at 'minimum heating' it consumes a power of 360 W but at 'maximum heating' it takes a

power of 840 W. Calculate the current and resistance in each case.​

Answers

Answer:

Given: V = 220V, Pmin = 360W, Pmax = 840W

For minimum heating case:

We know that

Pmin = VI

360 = 220 X I

I = 1.63 amp

R = V/I

R = 220/1.63

R = 134.96ohms

For maximum heating case:

We know that

Pmax = VI

840 = 220 X I

I = 3.81 amp

R = V/I

R = 220/3.81

R = 57.74 ohms

which event involves throwing a spherical weight from the shoulder?
a. discus throw
b. hammer throw
c. shot put​

Answers

Answer:

c. shot put

Explanation:

cause the shot is a ball

Shot put!!!!! C:shot put

examples of non viscous liquid​

Answers

The fluids that have no resistance or zero resistance to internal friction are known as non- viscous fluids. • The fluid which has more resistance to flow is called viscous fluid. Viscosity is a property of a fluid, which is a degree of the amount of resistance between the fluid layers.

Which graph shows a vehicle traveling at a constant speed?
(look at the attached photo)

Answers

b because it’s a straight line

IF you are in Space and push a bowling what happens to you and the bowling ball?

Answers

Answer:

The bowling ball did not change size or shape- the only thing that changed was the amount of gravity that pulls on it. But the mass of the bowling ball would never change. A bowling ball with a mass of 12 pounds on earth will have the mass of 12 pounds on the moon! Mass is the amount of atoms that a space fills.

Explanation:

I hope this helps! :D

Below is a diagram of the orbits of the inner planets examine the diagram and answer questions three and four 

Answers

Answer:

C is the answer

Explanation:

Earth is the third planet from the sun

you are cheating on your test, I know

Answer:

C..

Explanation:

I'm not sure about answer...

The final velocity of a car is 30m/s. The car is accelerating at a rate of 2.5m/s2
over an 2.8m/s2
8 second period of time. What is the initial velocity of the car?

Answers

Answer:

10m/s

Explanation:

Vf=v0+at

30m/s=v0+2.5m/s^2*8s

Solve for v0=10m/s

Sorry for the vague explanation I'm on my phone right now. Hope this still helps!

Initial velocity of the car where final velocity of a car is 30m/s and it is accelerating at a rate of 2.5 [tex]m/s^{2}[/tex] over an 2.8 [tex]m/s^{2}[/tex] 8 second period of time is 10 m/s.

To find the initial velocity of the car, we can use the kinematic equation:

Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)).

Given the final velocity (v) as 30 m/s, acceleration (a) as 2.5 [tex]m/s^{2}[/tex], and time (t) as 8 seconds, we can plug these values into the equation:

30 m/s = u + (2.5 [tex]m/s^{2}[/tex] * 8 s).

Now, solve for the initial velocity (u):

30 m/s = u + 20 m/s.

Subtract 20 m/s from both sides:

u = 30 m/s - 20 m/s = 10 m/s.

Therefore, the initial velocity of the car is 10 m/s.

To know more about Initial velocity, here

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1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
a.) Maximum height of the projectile.
b.) The time it takes to reach the maximum height
c.) Time of flight
d.) Range

Answers

Answer:

a.) Maximum height of the projectile. =32.5m

b.) The time it takes to reach the maximum height=2.6s

c.) Time of flight=2.6s

d.) Range=99.5m

Explanation:

Why does it take a long time for the earth to rotate?

Answers

24hrs or i full year as in 365 days

Answer:

earth takes a long time to rotate due to the tidal effects the moon has on earth's rotation

Explanation:

I hope this helps!

. A boy wishes to throw a ball through a house via two small openings, one in the front and the other in

the back window, the second window being directly behind the first. If the boy stands at a distance of 5m

in front of the house and the house is 6m deep and if the opening in the front window is 5m above him

and that in the back window 2m higher, calculate the velocity and the angle of projection of the ball that

will enable him to accomplish his desire.

Answers

Answer:

1) The angle of projection of the ball is approximately 52.496° above the horizontal

2) The velocity with which the boy throws the ball to enable him accomplish his desire is approximately 14.769 m/s

Explanation:

In the projectile motion of the ball, the parameters are;

The distance the boy stands from the front of the house = 5 m

The depth of the house, front to back = 6 m

The height of the opening of the front window above him = 5 m

The height of the back window = 2 m higher than the front window

Therefore, the height of the back window = 5 m + 2 m = 7 m

1) The general formula for the vertical height of a parabolic projectile motion is given as follows;

y = a·x² + b·x + c

At y = 0, x = 0, therefore, c = 0

At y = 5, x = 5, we have;

5 = a·5² + b·5

∴ 5 = 25·a + 5·b...(1)

At y = 7, x = 11, we have;

7 = a·11² + b·11

7 = 121·a + 11·b...(2)

Making 'a' the subject of equation (1) and (2) and equating both values of 'a' gives;

For equation (1);

a = (5 - 5·b)/25 = 1/5 - b/5

a = 1/5 - b/5

For equation (2);

a = (7 - 11·b)/121 = 7/121 - b/11

a = 7/121 - b/11

∴ 1/5 - b/5 = 7/121 - b/11

1/5 - 7/121 = b/5 - b/11

86/605 = 6·b/55

b = (86/605) × (55/6) = 43/33

b = 43/33

a = 1/5 - b/5 = 1/5 - (43/33)/5 = -2/33

∴ y = (-2/33)·x² + (43/33)·x

The slope of the curve = dy/dx = d((-2/33)·x² + (43/33)·x)/dx = -4/33·x + 43/33

The slope of the curve at any point on the projectile = -4/33·x + 43/33

The slope at the origin is given by plugging x = 0  as follows

The slope at the origin = -4/33 × 0 + 43/33 = 43/33

The slope at the origin = tan(θ) = 43/33

Where;

θ = The angle of projection of the ball

∴ θ = arctan(43/33) ≈ 52.496°

The angle of projection of the ball, θ ≈ 52.496° above the horizontal

2) At the back widow, the equation for the vertical height, 'h', is given as follows;

[tex]h = (tan \angle \theta) \cdot x - \left(\dfrac{g}{2 \cdot v_1^2 \cdot cos^2 \angle \theta } \right )\cdot x^2[/tex]

Where;

h = The vertical height of the back window = 7 m

tan∠θ = 43/33

x = The horizontal distance of the back window from the boy = 5 m + 6 m = 11 m

g = The acceleration due to gravity = 9.8 m/s²

v₁ = The velocity with which the boy throws the ball

cos²∠θ = cos²(arctan(43/33)) = 1089/2938

Plugging in the values gives;

[tex]7 = \left (\dfrac{43}{33} \right) \times 11 - \left(\dfrac{9.8}{2 \cdot v_1^2 \cdot \dfrac{1089}{2938} } \right )\cdot 11^2[/tex]

[tex]\therefore v_1^2 = \dfrac{71981}{330}[/tex]

[tex]\therefore v_1 = \sqrt{\dfrac{71981}{330}} \approx \pm14.769[/tex]

The velocity with which the boy throws the ball to enable him accomplish his desire, v₁ ≈ 14.769 m/s.


6. What is the measure of the amount of energy released in an earthquake?
a. Earthquake
B. Magnitude
C. epicenter
D. Intensity​

Answers

Answer:

Magnitude

Explanation:

B is the answer

Answer:

its B

Explanation:

what are the 3 types of family goals​

Answers

be healthy, nice bond, achieving goals

SOMEONE HELP ME PLEASE
Free is the movement of an object towards earth solely because of gravity.

What is freefall? Free fall is when objects falling near earth’s surface accelerate downward at rate of 9.8 m/s2.

Give an example of an object in free fall

Answers

A box falling off a building is in free fall.

Which of these is not a scalar quantity?

Answers

Answer:

options?!?

Explanation:

give us some options

write down the expressions for the heat produced per second in a resistor in terms of potential difference and resistance​

Answers

Answer:

[tex]H=\frac{V^2}{R}[/tex]

Explanation:

Let H be  heat produced per sec

Time, t=1 sec

Resistance of resistor=R ohm

We have to write down the expression for the  heat produced per second in a resistor in terms of potential difference and resistance​.

We know that

Heat, [tex]H=I^2 Rt=\frac{V^2}{R}t[/tex]

Substitute the value

Then, we get

Heat,[tex]H=\frac{V^2}{R}\times 1[/tex]

[tex]H=\frac{V^2}{R}[/tex]

This is required expression for the heat produced per second in a resistor  in terms of potential difference and resistance​.

1/2 means that the voltage (or charge) of the system will increase to half more of what is left in a time equal to t1/2 seconds. Therefore if a system is already at half charge (t1/2 seconds after starting) then after t1/2 more seconds the system will be charged to 50% plus half of 50%. That is 25% more, or 75% of the entire charge. Let's say that four t1/2's have gone by. That means that the charge (or voltage) is at (50% + 1/2*50% + 1/2*1/2*50% + 1/2*1/2*1/2*50%) = 93.75% of maximum charge. Yikes! Now look in your manual for a more simple mathematical derivation of this concept. Given t1/2 to be 0.4406 seconds, how long should it take to reach 75% of maximum charge? answer in seconds.

Answers

Answer:

The answer is "0.047".

Explanation:

Given value:

[tex]\to t_{\frac{1}{2}}= 0.4406\\\\\to V=0.9375 V_{max}[/tex]

Calculating the capacitance:

[tex]\to V=V_{max} (1-e^{\frac{-t}{Rc}})[/tex]

In this, the t = time, which is taken to calculates its maximum voltage.

[tex]\to 0.9375 V_{max} = V_{max}(1-e^{- \frac{t}{103\times(165.279\times10^{-6})}})\\\\\to e^{- \frac{t}{103\times(165.279\times10^{-6})}}= 0.0625\\\\\to - \frac{t}{103\times(165.279\times10^{-6})} = \ln(0.0625)\\\\\to -t= 0.01702\times(-2.77258) \\\\ \to -t = -0.04719 \\\\ \to t= 0.04719 \approx 0.047 \ s[/tex]

Which has more potential energy: a baseball held 1 m above the ground or a baseball held 2 m above the ground?

Answers

a baseball 1m above the ground i'm pretty sure

The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.  

The potential energy can be calculated with the following equation:

[tex] E_{p} = mgh [/tex]

Where:

m: is the mass of the baseball

g: is the acceleration due to gravity

h: is the height

We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:

Potential energy above 1 m

[tex] E_{p_{1}} = mg*1 = mg [/tex]  (1)

Potential energy above 2 m

[tex] E_{p_{2}} = mg*2 = 2mg [/tex]   (2)

By entering equation (1) into 2 we have:

[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]

Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.

Therefore, the baseball held 2 m above the ground has more potential energy.

You can learn more about potential energy here: https://brainly.com/question/15813853?referrer=searchResults

I hope it helps you!

Anna pours herself some room-temperature soda from a bottle and adds four ice cubes. In a few minutes the ice cubes are smaller and the soda is much colder. Which of the following best explains the change in temperature of the soda?



A. Heat flowed from the soda to the ice cube and caused it to partially melt.

B. Coldness flowed from the ice cube to the soda, making the soda cooler.

C. The cold water from the melting ice went into the soda, replacing the warmer water that was in the soda

D. The water from the melting ice makes the soda more dilute, and the lower concentration makes the temperature lower.

Answers

Answer:

A.

Explanation:

That's the answer

Which of the following determines the identity of an atom?

A. atomic mass

B. mass number

C. atomic number

D. charge

Answers

I believe the answer is C

What happens when an object becomes cold?
Energy is added to it.
Mass is removed from it.
Cold is added to it.
Heat is removed from it.

Answers

Answer:

Heat is removed from it.

Explanation:

A object will become cold when it loses its heat to its surroundings. I would look up the 3 Principles of Heat Transfer.

I hope this helped! :)

Question 6 of 59
A wave has a wavelength of 5 m and a speed of 65 m/s. What is the frequency of this wave in Hz?

Answers

Answer:

13 Hz Ans..

Explanation:

Data:

wavelength = 5 m

v = 65 m\s

f = ?

Formula:

v = f w

f= v\w

Solution:

f = 65 \ 5

f = 13 Hz Ans .........

in a nuclear plant, 1 * 10 ^27 J of energy is available from mass conversion How much mass was lost ?

Answers

Answer:

[tex]1.2\times 10^{10}\ kg[/tex]

Explanation:

Given that,

The energy of the nuclear plant, [tex]E=10^{27}\ J[/tex]

We need to find how much mass wast lost.

The relation between energy and mass is given by :

[tex]E=mc^2[/tex]

Where

c is speed of light

[tex]m=\dfrac{E}{c^2}\\\\m=\dfrac{10^{27}}{(3\times 10^8)^2}\\\\m=1.2\times 10^{10}\ kg[/tex]

So, [tex]1.2\times 10^{10}\ kg[/tex] of mass was lost.

The cooling system of an automobile motor contains 20.0 kg of water. What is the Δt of the water if the engine operates until 836,000 J of heat have been added to the water?

Answers

Answer: 10 c

Explanation:

The cooling system of an automobile motor contains 20 kg of water, then the temperature change of the water is 10 °C.

What is heat?

Heat is the result of the movement of kinetic energy from one substance or item to another, or from an energy source to a substance or object. Radiation, conduction, and convection are three different ways that this energy can be transferred.

The calorie (cal), the primary unit of heat in the International System of Units (SI), is the quantity of energy transfer necessary to raise the temperature of one gram of liquid from water by one degree's Centigrade, provided that the water's temperature is both higher than the freezing point and lesser than the boiling point.

The given data in the question is,

Heat, Q = 836000 J

Volume, V = 20 L

Mass, m = 20 kg

ΔT = Q/m[tex]C_p[/tex]

ΔT = (836000)/(20 × 4180)

ΔT = 10 °C

Therefore, the change in temperature will be equal to  10 °C.

To know more about heat:

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Can someone help me with this answer the question pls don’t guess and actually help me I’ll give brainliest

Answers

Answer: clastic sedimentary rock

Explanation: Hope this helps!

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