An arrow is shot upward at a rate of 220 feet per second. Use the projectile formula h=−16t^2+v_0t to determine when the height of the arrow will be 400 feet. Round your answer to the nearest tenth.

Answers

Answer 1

Answer:Explanatory help v

Step-by-step explanation:The question gives you V0 as 220, so plug that in first.

h=-16t2+220t.

Then it says to find the time (solve for t), when the height is 400 ft. Plug 400 ft in as h and solve for t.

400=-16t2+220t.

To solve this, set the quadratic equal to 0 by subtracting 400 from both sides (0=-16t2+220t-400) and use the quadratic formula!

Answer 2

Answer:

The arrow reaches 400 feet in its way up at about 2.2 seconds after being launched.

Step-by-step explanation:

Since we want to find the time at which the arrow will reach 400 feet, we use this information in the equation for the height;

[tex]400=-16\,t^2+220\,t\\16\,t^2-220\,t+400=0[/tex]

and now use the quadratic equation to solve for the unknown time (t). Notice that been a quadratic equation we expect up to two answers, and then we will need to decide which answer to pick.

[tex]t=\frac{220}{2\,(16)} +/- \frac{\sqrt{(-220)^2-4 \,(16)(400)}}{2\,(16)} \\ \\t= 2.156\,sec\,\,\,or\,\,\, t=11.594\,sec[/tex]

This means that as the arrow goes up, it takes 2.156 seconds to reach 400 feet, and afterwards, after the arrow reaches it maximum height, it falls back due to acceleration of gravity, going through the same 400 feet height before reaching the ground.

We round the answer to the nearest tenth as requested.


Related Questions

Write the equation of a line through the given point with the given slope (0,6);m undefined

Answers

Answer:

x=0

Step-by-step explanation:

If the slope is undefined, the line is vertical

vertical lines are of the form

x =

Since the point is (0,6)

x=0

These are the weekly wages paid to staff in a hotel. £245 £140 £525 £163 £195 £174 £140 What is the range of these wages? £ What is the mean wage?

Answers

Answer:

Range of wages is £140 to £525.

Mean wage = £226

Step-by-step explanation:

Given:

Weekly wages paid to the staff are :

£245, £140, £525, £163, £195, £174 and £140.

To find:

Range of these wages = ?

Mean wage = ?

Solution:

First of all, let us learn about the range of wages and mean wage.

Range of wages has a minimum pay and a maximum pay.

Here, if we have a look £140 is the minimum pay and

£525 is the maximum pay.

So, range of wages is £140 to £525.

Mean wage means the average of all the wages given to the staff.

Mean is defined as the formula:

[tex]\text{Average/Mean =} \dfrac{\text{Sum of all the observations}}{\text{Number of observations}}[/tex]

Here, Sum of all observations mean sum of the wages of all the staff members.

Number of observations mean the number of staff members i.e. 7 here.

Applying the formula:

[tex]\text{Average/Mean =} \dfrac{\text{245+140+525+163+195+174+140}}{\text{7}} \\\Rightarrow \text{Average/Mean =} \dfrac{\text{1582}}{\text{7}}\\\Rightarrow \text{Average/Mean =} 226[/tex]

So, the answer is:

Range of wages is £140 to £525.

Mean wage = £226

Select the correct answer.
What are the x-intercepts of this function?
g(x) = -0.25x2 – 0.25x + 5
O
(-20,0) and (-4,0)
(4,0) and (20,0)
(5,0) and (-4,0)
(-5,0) and (4,0)

Answers

Answer:

[tex]\large \boxed{\sf \ \ (-5,0) \ and \ (4,0) \ \ }[/tex]

Step-by-step explanation:

Hello,

We need to find the zeroes of

[tex]-0.25x^2-0.25x+5=0\\\\\text{*** multiply by -4 ***} \\ \\x^2+x-20=0\\\\\text{*** the sum of the zeroes is -1 and the product -20=-5x4 ***}\\\\x^2+5x-4x-20=x(x+5)-4(x+5)=(x+5)(x-4)=0\\\\x=4 \ or \ x=-5[/tex]

and then g(4)=0 and g(-5)=0

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:(-5,0) (4,0)

I took the test hope it helps you (:

Explain how to use the vertex and the value of “A” to determine the range of an absolute value function. PLEASE HELP!!

Answers

Answer:

First, a absolute value function is something like:

y = f(x) = IxI

remember how this work:

if x ≥ 0, IxI = x

if x ≤ 0, IxI = -x

Notice that I0I = 0.

And the range of this function is all the possible values of y.

For example for the parent function IxI, the range will be all the positive reals and the zero.

First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.

Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:

y ≥ A

Or all the real values equal to or larger than A.

if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:

y ≤ A

Or "All the real values equal to or smaller than A"

A survey of 181 registered voters in one state reveals that 112 of them favor approval of a bill before the legislature. Construct a 98% confidence interval for the true proportion of all voters in the state who favor approval of the bill. Give your answers as decimals, rounded to 3 places after the decimal point (if necessary). 98% confidence interval for p: ( , )

Answers

Answer:

Hence the approximate 98% confidence interval for the voters in favor of the approval of the bill is  ( 0.541 , 0.683)

Step-by-step explanation:

The sample proportion is = p = 112/181 = 0.61878= 0.612

q = 1-p = 1- 0.612= 0.388

The degree of confidence is 98 % so z₀.₀₂₅= 1.96  taking α = 5 at 95 %

The interval X~± 0.98  is a random variable because X does not have a particular value but takes different values in different samples.

In repeated samples of size 16 from a normal distribution with standard deviation 2 the interval X~± 0.98 will contain true unknown value of mean about 95 percent of the time .

p ± z ( base alpha by 2) √pq/n

Substituting the values

0.612 ± 1.96√0.612*0.388/181

Multiplying p and q

= 0.612 ± 1.96 √0.237456/181

Solving the square root

=0.612 ± 1.96( 0.03622)

Multiplying  value of z with the value of square root

=0.612 ±  0.07099

Adding or subtracting will give   0.683, 0.541

Hence the approximate 98% confidence interval for the voters in favor of the approval of the bill is  ( 0.541 , 0.683)

The population, p, in thousands of a resort community is given by P(t)=700t/4t[tex]x^{2}[/tex]+9

Answers

Answer:

Step-by-step explanation:

pt=700 is basically evaluate it form the bottom to the top and u must mark me as brainly

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Answers

Answer:

First answer.

Step-by-step explanation:

Multiply everything by 10, to get rid of the decimals.

Use Demoivres Theorem to find (-square root 3 +i)^6

Answers

Answer:

[tex]z=(-\sqrt{3}+i)^6[/tex] = -64

Step-by-step explanation:

You have the following complex number:

[tex]z=(-\sqrt{3}+i)^6[/tex]       (1)

The Demoivres theorem stables the following:

[tex]z^n=r^n(cos(n\theta)+i sin(n\theta))[/tex]      (2)

In this case you have n=6

In order to use the theorem you first find r and θ, as follow:

[tex]r=\sqrt{3+1}=2\\\\\theta=tan^{-1}(\frac{1}{\sqrt{3}})=30\°[/tex]

Next, you replace these values into the equation (2) with n=6:

[tex]z^6=(2)^6[cos(6*30\°)+isin(6*30\°)]\\\\z^6=64[-1+i0]=-64[/tex]

Then, the solution is -64

Answer:

A) -64

Step-by-step explanation:

Edge 2021

The amount of flow through a solenoid valve in an automobile's pollution-control system is an important characteristic. An experiment was carried out to study how flow rate depended on three factors: armature length, spring load, and bobbin depth. Four different levels (low, fair, moderate, and high) of each factor were chosen, and a single observation on flow was made for each combination of levels.A) The resulting data set consisted of how many observations?

B) Is this an enumerative or analytic study? Explain.

Answers

Answer:

A) 64 observations

B) analytic study

Step-by-step explanation:

Given:  

There are 3 number of factors i.e. armature length, spring load, and bobbin depth.

There are 4 levels i.e. low, fair, moderate, and high

There is a single i.e. 1 observation on flow made for each combination of levels.

A)

To find:

Number of observations.

There are 4 levels so these 4 levels are to be considered for each factor.

Number of observations = 4.4.4 = 64

For example if we represent low fair moderate and high as L,F,M,H

and factors armature length, spring load, and bobbin depth as a,s,b

Then one of the observations can be [tex]L_{a} F_{s} H_{b}[/tex]

So resulting data set has 64 observations.  

B)

This is analytic study.

The study basically "analyses" the amount of flow through a solenoid valve in an automobiles pollution control system. This study is conducted in order to obtain information from this existing process/experiment and this study focuses on improvement of the process, which created the results being analysed. So the goal is to improve amount of flow through a solenoid valve practice in the future. Also you can see that there is no sampling frame here so if the study was enumerative that it should focus on collecting data specific items in the frame so it shows that its not enumerative but it is analytic study.

a store specializing in mountain bikes is to open in one of two malls if the first mall is selected the store anticipates a yearly profit of $825,000 if successful a yearly loss of 275,000 otherwise the probability of success is 1/2 if the second mall is selected it is an estimated that the yearly profit will be 550,000 if successful otherwise the annual loss will be 165,000 the probability of success at the second mall is three Force​

Answers

Complete question :

a store specializing in mountain bikes is to open in one of two malls if the first mall is selected the store anticipates a yearly profit of $825,000 if successful a yearly loss of 275,000 otherwise the probability of success is 1/2 if the second mall is selected it is an estimated that the yearly profit will be 550,000 if successful otherwise the annual loss will be 165,000 the probability of success at the second mall is three Fourth (3/4).

What is the expected profit of thesecond mall?

Answer:

$453,750

Step-by-step explanation:

Given the following :

First mall:

Profit if successful = $825,000

Loss if otherwise = $275000

Probability of success = 1/2

Second mall:

Profit if successful = $550,000

Loss if otherwise = $165,000

Probability of success = 3/4

Expected profit of second mall:

If probability of profit ' P(profit)' = 3/4

Then,

Probability of loss P(loss) = 1 - P(profit)

P(loss) = 1 - 3/4 = 1/4

Expected profit:

[P(profit) * profit] + [P(loss) * loss])

(0.75 * $550,000) + (0.25 * (-$165,000))

$412,500 - $41,250 = $453,750

Plzzzzzzzzzzzzzzzzzzzzzz find the hcf of 15a²b² and -24ab

Answers

Let's take a look at each term separately.

15a^2b^2:

15 has factors 1, 3, 5, 15

a x a

b x b

-24ab

-24 has factors 1, 2, 3, 4, 6, 8, 12, 24

a

b

Now, we can see what each of these terms has in common. Both have a 3 in their factor lists, as well as one a and one b.

Therefore, the greatest common factor is 3ab.

Hope this helps!! :)

Answer:

3ab

Step-by-step explanation:

[tex]15a^{2} b^{2} - 24ab[/tex] is divided by 3

[tex]5a^{2} b^{2} - 8ab[/tex] take away a and b once

hope this helped!!!

[tex]5ab - 8[/tex]

= 3ab

The equation of the line of best fit is y=15.621x+8.83 Based on the line of best fit, Approximately how many pages are predicted To be in a book with eight chapters

Answers

Answer:

[tex] y = 15.621x +8.83[/tex]

We assume that y represent the number of pages predicted and x the number of chapters.

And we want to find the predicted value for a book of x =8 chapters. S replacing we got:

[tex] y = 15.621*8 + 8.83= 133.798[/tex]

And we can conclude that approximately we would have between 133 and 134 pages for a book of 8 chapters

Step-by-step explanation:

For this case we have the following model given:

[tex] y = 15.621x +8.83[/tex]

We assume that y represent the number of pages predicted and x the number of chapters.

And we want to find the predicted value for a book of x =8 chapters. S replacing we got:

[tex] y = 15.621*8 + 8.83= 133.798[/tex]

And we can conclude that approximately we would have between 133 and 134 pages for a book of 8 chapters

Write an equation for the line that passes through the point ​(4,5​) and is perpendicular to−7x+y=2. Use​ slope-intercept form.

Answers

Answer:

y= -1/7x + 39/7

Step-by-step explanation:

Slope - intercept form is:

y= mx +b, where m represents the slope of the line

Given the line:

- 7x +y= 2,

which can be shown as:

y= 7x+2 if we add 7x to both sides of equation

We need to write an equation for the line that it perpendicular to the given line and passes through the point (4,5)

As we know, perpendicular line has a slope opposite-reciprocal to the given, so the slope is:

m= - 1/7

and the form of the line is:

y= -1/7x +b

We can find b, by using the point (4, 5), which means x=4 and y=5:

5= -1/7 * 4 + b ⇒ b= 5+ 4/7= 5 4/7 = 39/7

And the equation for this line is:

y= -1/7x + 39/7

x =x=x, equals ^\circ ∘

Answers

Answer:

x = 64

Step-by-step explanation:

A circle equal 360 degrees

180 + 90 + x + 26 = 360

Combine like terms

296+x = 360

Subtract 296 from each side

296+x-296 = 360-296

x = 64

g Suppose that three hypothesis tests are carried out, each using significance level 0.05. What is the worst-case probability of a type I error in at least one of these tests?

Answers

Answer:

The worst-case probability is 0.05

Step-by-step explanation:

The given significance level ([tex]\alpha[/tex]) = 0.05

since Probability of a type I error is [tex]\alpha[/tex]

∴ P (type I error) = 0.05

0.05 will be the worst-case probability of a type I error in at least one of the tests.

In this exercise, we estimate the rate at which the total personal income is rising in a metropolitan area. In 1999, the population of this area was 924,900, and the population was increasing at roughly 9400 people per year. The average annual income was $30,388 per capita, and this average was increasing at about $1400 per year (a little above the national average of about $1225 yearly). Use the Product Rule and these figures to estimate the rate at which total personal income was rising in the area in 1999.

Answers

Answer:

the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

Step-by-step explanation:

From the given information:

Let consider y to represent the number of years after 1999

Then the population in time (y) can be expressed as:

P(y) = 9400y + 924900

The average annual income can be written as:

A(y) = 1400y + 30388

The total personal income = P(y)  ×  A(y)

The rate at which the total personal income is rising is T'(y) :

T'(y) = P'(y)  ×  A(y)  + P(y)  ×  A'(y)

T'(y) = (9400y + 924900)' (1400y + 30388) + (9400y + 924900) (1400y + 30388)'

T'(y) = 9400(1400y + 30388) + (9400y + 924900) 1400

Since in 1999 y =0

Then:

T'(0) = 9400(1400(0) + 30388) + (9400(0) + 924900) 1400

T'(0) = 9400(30388) + (924900)1400

T'(0) = $1,580,507,200 billion

Therefore; the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

Find the coordinate vector [Bold x ]Subscript Upper B of x relative to the given basis BequalsStartSet Bold b 1 comma Bold b 2 comma Bold b 3 EndSet

Answers

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

In the question equation is missing so, the equation and its solution can be defined as follows:

[tex]B={b_1,b_2}\\\\b_1= \left[\begin{array}{c}5&5\end{array}\right] \ \ \ \ \b_2= \left[\begin{array}{c}2&-5\end{array}\right] \ \ \ \ \x= \left[\begin{array}{c}-7&-35\end{array}\right][/tex]

[tex]\left[\begin{array}{c}a&c\end{array}\right] =?[/tex]

[tex]\to \left[\begin{array}{c}-7&-35\end{array}\right]= a\left[\begin{array}{c}5&5\end{array}\right]+c \left[\begin{array}{c}2&-5\end{array}\right] \\[/tex]

[tex]\to \left[\begin{array}{c}-7&-35\end{array}\right]= \left[\begin{array}{c}5a+2c&5a-5c\end{array}\right]\\\\\to 5a+2c=-7....(1)\\\\\to 5a-5c=-35....(2)\\\\[/tex]

subtract equation 1 from equation 2:

[tex]\to 7c=28\\\\\to c=\frac{28}{7}\\\\\to c= 4\\\\[/tex]

put the value of c in equation 1

[tex]\to 5a+2(4)=-7\\\to 5a+8=-7\\\to 5a=-7-8\\\to 5a=-15\\\to a= -3[/tex]

coordinate  value is [-3,4].

A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed of the film and believes that this can be achieved by reducing the thickness of the film to 20 mils. Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured. For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09 *Note: An increase in film speed would lower the value of the observation in microjoules per square inch. We may also assume the speeds of the film follow a normal distribution. Use this information to construct a 98% interval estimate for the difference in mean speed of the films. Does decreasing the thickness of the film increase the speed of the film?

Answers

Answer:

A 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Step-by-step explanation:

We are given that Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured.

For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 and For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09.

Firstly, the pivotal quantity for finding the confidence interval for the difference in population mean is given by;

                     P.Q.  =  [tex]\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex]  ~  [tex]t__n_1_+_n_2_-_2[/tex]

where, [tex]\bar X_1[/tex] = sample mean speed for the 25-mil film = 1.15

[tex]\bar X_1[/tex] = sample mean speed for the 20-mil film = 1.06

[tex]s_1[/tex] = sample standard deviation for the 25-mil film = 0.11

[tex]s_2[/tex] = sample standard deviation for the 20-mil film = 0.09

[tex]n_1[/tex] = sample of 25-mil film = 8

[tex]n_2[/tex] = sample of 20-mil film = 8

[tex]\mu_1[/tex] = population mean speed for the 25-mil film

[tex]\mu_2[/tex] = population mean speed for the 20-mil film

Also,  [tex]s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} }[/tex] = [tex]\sqrt{\frac{(8-1)\times 0.11^{2}+ (8-1)\times 0.09^{2}}{8+8-2} }[/tex] = 0.1005

Here for constructing a 98% confidence interval we have used a Two-sample t-test statistics because we don't know about population standard deviations.

So, 98% confidence interval for the difference in population means, ([tex]\mu_1-\mu_2[/tex]) is;

P(-2.624 < [tex]t_1_4[/tex] < 2.624) = 0.98  {As the critical value of t at 14 degrees of

                                             freedom are -2.624 & 2.624 with P = 1%}  

P(-2.624 < [tex]\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < 2.624) = 0.98

P( [tex]-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < [tex]2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] <  ) = 0.98

P( [tex](\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < ([tex]\mu_1-\mu_2[/tex]) < [tex](\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ) = 0.98

98% confidence interval for ([tex]\mu_1-\mu_2[/tex]) = [ [tex](\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] , [tex](\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ]

= [ [tex](1.15-1.06)-2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }[/tex] , [tex](1.15-1.06)+2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }[/tex] ]

 = [-0.042, 0.222]

Therefore, a 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Since the above interval contains 0; this means that decreasing the thickness of the film doesn't increase the speed of the film.

A publisher requires 2∕3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest whole page, how many pages of the magazine are advertisements?

Answers

Answer:

[tex]\boxed{13}[/tex] pages

Step-by-step explanation:

Divide the total number of pages by 5 to get how many sets of every 5 pages will contain 2/3 of a page of advertisements.

[tex]\frac{98}{5} = 19.6[/tex]

Multiply this value by [tex]\frac{2}{3}[/tex] to get the total number of pages.

[tex]19.6 * \frac{2}{3} \approxeq 13[/tex] pages

During the summer months Terry makes and sells necklaces on the beach. Last summer he sold the necklaces for $10 each and his sales averaged 20 per day. When he increased the price by $1, he found that the average decreased by two sales per day. If the material for each necklace costs Terry $6, what should the selling price be to maximize his profit?

Answers

Answer:

The selling price in other to maximize his profit is $13

Step-by-step explanation:

In the above question we are given the following information:

Cost of material per necklace = $6

Firstly, terry sold 20 necklaces per day

= $10 each

Later he increased he increased the prices by 1 dollar and the number of necklaces he sold reduced by 2

Mathematically

18 necklaces = $11 each

Step 1

We find the Cost function C(x)

Let's assume that x = number of necklaces sold

If each material cost $6 , then

C(x) = 6 × x = 6x

Step 2

P(Profit) = R(x) - C(x)

R(x) = Revenue

Where Revenue = x × p(x)

Since p(20) = 10 and p(18) = 11

p(x) = -1/2x + 20

P(Profit) = x ( -1/2x + 20) - C(x)

C(x) = 6x

P = x(-1/2x + 20) - 6x

P = -1/2x² + 20x - 6x

P = -1/2x² + 14x

Step 3

We maximise the profit by differentiating P

P = Profit

P = -1/2x² + 14x

We differentiate P to find x

∆P/∆x = dp/dx = -x + 14

-x + 14 = 0

-x = -14

x = 14

Hence, we substitute 14 for x in the price function

p(x) = - 1/2x + 20

since , x = 14

p(14) = - 1/2 × 14 + 20

= -7 + 20

= $13

Therefore, the selling price function to maximize his profit is $13

Above question the given data:  

Cost of material per necklace = $6 Terry sold 20 necklaces per day = $10 each Price increase by 1 dollar Number of necklaces  sold reduced by 2  

1.Cost function C(x)

Let's assume that x = number of necklaces sold

If each material cost $6 , then

C(x) = 6 × x

C(x) = 6x  

2.P(Profit) = R(x) - C(x)

R(x) = Revenue ,Where Revenue = x × p(x)

Given data:

p(20) = 10

p(18) = 11

p(x) = -1/2x + 20

P(Profit) = R(x) - C(x)

P(Profit) = x ( -1/2x + 20) - C(x)

P = x(-1/2x + 20) - 6x

P = -1/2x² + 20x - 6x

P = -1/2x² + 14x

 

3.Maximise Profit

P = Profit  

P = -1/2x² + 14x

We differentiate P to find x

∆P/∆x = dp/dx = -x + 14

-x + 14 = 0

-x = -14

x = 14

Now, we will substitute 14 for x in the price function

Now ,p(x) = - 1/2x + 20

since , x = 14

p(14) = - 1/2 × 14 + 20  

p(14)= -7 + 20  

p(14)= $13

Thus, the selling price function to maximize his profit is $13.

Learn more :

https://brainly.com/question/24710158?referrer=searchResults

verify sin4x - sin2x = cos4x-cos2x

Answers

Answer:

sin⁴x - sin²x = cos⁴x - cos²x

Solve the right hand side of the equation

That's

sin⁴x - sin²x

From trigonometric identities

sin²x = 1 - cos²x

So we have

sin⁴x - ( 1 - cos²x)

sin⁴x - 1 + cos²x

sin⁴x = ( sin²x)(sin²x)

That is

( sin²x)(sin²x)

So we have

( 1 - cos²x)(1 - cos²x) - 1 + cos²x

Expand

1 - cos²x - cos²x + cos⁴x - 1 + cos²x

1 - 2cos²x + cos⁴x - 1 + cos²x

Group like terms

That's

cos⁴x - 2cos²x + cos²x + 1 - 1

Simplify

We have the final answer as

cos⁴x - cos²x

So we have

cos⁴x - cos²x = cos⁴x - cos²x

Since the right hand side is equal to the left hand side the identity is true

Hope this helps you

Identify the type of hypothesis test below. H0:X=10.2, Ha:X>10.2 Select the correct answer below: The hypothesis test is two-tailed. The hypothesis test is left-tailed. The hypothesis test is right-tailed.

Answers

Answer:

The hypothesis test is right-tailed

Step-by-step explanation:

To identify a one tailed test, the claim in the case study tests for the either of the two options of greater or less than the mean value in the null hypothesis.

While for a two tailed test, the claim always test for both options: greater and less than the mean value.

Thus given this: H0:X=10.2, Ha:X>10.2, there is only the option of > in the alternative claim thus it is a one tailed hypothesis test and right tailed.

A test with the greater than option is right tailed while that with the less than option is left tailed.

Answer:

Please help with questions on my profile somebody

Step-by-step explanation:

Simplify the expression:
4w + 10(7w+1)

Answers

Answer:

74w+10

Step-by-step explanation:

That's the answer

4w+70w+10. 74w+10. You multiply and then add them and you have the answer. It is 74w+10.

Find the area of the triangle. Round the answer to the nearest tenth. A. 4.4 square units B. 5.2 square units C. 6.8 square units D. 8.8 square units

Answers

Answer:

A. 4.4 units²

Step-by-step explanation:

Area of a Triangle: A = 1/2bh

sin∅ = opposite/hypotenuse

cos∅ = adjacent/hypotenuse

Step 1: Draw the altitude down the center of the triangle

- We should get a perpendicular bisector that creates 90° ∠ and JM = KM

- We should also see that we use sin∅ to find the h height of the triangle and that we use cos∅ to find length of JM to find b base of the triangle

Step 2: Find h

sin70° = h/3.7

3.7sin70° = h

h = 3.47686

Step 3: Find b

cos70° = JM/3.7

3.7cos70° = JM

JM = 1.26547

Step 4: Find entire length base JK

JM + KM = JK

JM = KM (Definition of Perpendicular bisector)

2(JM) = JK

2(1.26547) = 2.53095

b = 2.53095

Step 5: Find area

A = 1/2(3.47686)(2.53095)

A = 4.39988

A ≈ 4.4


Jamie's dog eats 3/4 pound of dog food each day. How many pounds of dog
food does Jamie's dog eat in 4 days?

Answers

Answer:

The dog will eat 3 lbs

Step-by-step explanation:

Take the amount eaten per day and multiply by the number of days

3/4 * 4 = 3

The dog will eat 3 lbs

Answer:

3 pounds

Step-by-step explanation:

Multiply the amount of dog food per day with the number of days.

[tex]\frac{3}{4} \times 4[/tex]

[tex]\frac{12}{4} =3[/tex]

In 4 days, Jamie's dog will eat 3 pounds of dog food.

A study is done to see if the average age a "child" moves permanently out of his parents' home in the United States is at most 23. 43 U.S. Adults were surveyed. The sample average age was 24.2 with a standard deviation of 3.7. The p-value is

Answers

Answer:

The p-value is 2.1%.

Step-by-step explanation:

We are given that a study is done to see if the average age a "child" moves permanently out of his parents' home in the United States is at most 23. 43 U.S. Adults were surveyed.

The sample average age was 24.2 with a standard deviation of 3.7.

Let [tex]\mu[/tex] = true average age a "child" moves permanently out of his parents' home in the United States.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] 23      {means that the average age a "child" moves permanently out of his parents' home in the United States is at most 23}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > 23      {means that the average age a "child" moves permanently out of his parents' home in the United States is greater than 23}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

                            T.S.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample average age = 24.2

            s = sample standard deviation =3.7

            n = sample of U.S. Adults = 43

So, the test statistics =  [tex]\frac{24.2-23}{\frac{3.7}{\sqrt{43} } }[/tex]  ~  [tex]t_4_2[/tex]

                                    =  2.127

The value of t-test statistics is 2.127.

Now, the p-value of the test statistics is given by;

         P-value = P( [tex]t_4_2[/tex] > 2.127) = 0.021 or 2.1%

Select the correct answer. Consider the function f(x) = 3x and the function g, which is shown below. How will the graph of g differ from the graph of f? The graph of g is the graph of f shifted to the right by 3 units. The graph of g is the graph of f shifted down by 3 units. The graph of g is the graph of f shifted to the left by 3 units. The graph of g is the graph of f shifted up by 3 units.

Answers

Answer:

The graph of g is the graph of f shifted up by 3 units.

Step-by-step explanation:

Consider the graph of a function r with real numbers k and h.

Transformation Effect

r(x) + k shifts the graph up k units

r(x) - k shifts the graph down k units

r(x + h) shifts the graph to the left h units

r(x - h) shifts the graph to the right h units

It is given that g(x) = f(x) + 3. Therefore, the graph of g is the graph of f shifted up by 3 units.

PLEASE HELP----- T.A. =

Answers

Answer:

vol = 96

Step-by-step explanation:

Area of a triangle = 1/2 * b * h

b = 4

h = 6

A = 0.5 * 4 * 6

A = 12

length = 8

vol = Area * length

vol = 12 * 8

vol = 96

Answer:

(104 + 16 sqrt 13)

Step-by-step explanation:

i did this on my school, it was correct

If we assume that asset X has an expected return of 10 and a variance of 10, then its coefficient of variation is:

Answers

Answer: Its coefficient of variation = 0.316

Step-by-step explanation:

The formula to find the coefficient of variations:

Coefficient of variation: [tex](\dfrac{\sqrt{\text{variance}}}{\text{return}})[/tex]

Given: Asset X has

Variance = 10

Expected return = 10

then, coefficient of variation [tex]=\dfrac{\sqrt{10}}{10}=\dfrac{1}{\sqrt{10}}\approx0.316[/tex]

Hence, its coefficient of variation = 0.316

-6+4q+(-6q)−6+4q+(−6q)minus, 6, plus, 4, q, plus, left parenthesis, minus, 6, q, right parenthesis ?

Answers

Answer:

-16-5q

Step-by-step explanation:

-6+4q-6q-6+4q-6q-6+4q-6q= -18-6q

Answer:C

Step-by-step explanation: 100% correct I did it on Khan Academy

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