An aluminium bar 600mm long1 with diameter 40mm, has a hole drilled in the centre of the bar. The hole is 30mm in diameter and is 100mm long. If the modulus of elasticity for the aluminium is 85GN/M^2 Calculate the total contraction on the bar due to a compressive load of 180KN

Answer: c.mesosphere

Explanation: Temperatures can reach lows of -90 degrees Celsius in the mesosphere, making it the coldest layer of the earth's atmosphere. The mesosphere extends above the stratosphere and ranges from 50 km to 87 km above the surface.

Answer:

kinetic energy is proportional to the velocity squared, increases in velocity will have an exponentially greater effect on translational kinetic energy. Doubling the mass of an object will only double its kinetic energy, but doubling the velocity of the object will quadruple its velocity.

pls mark as branliest

Answer:Covalent bond

Explanation:

Answer: it is called a open circuit

Explanation:

Answer:

No. of Cars = 8

Explanation:

In order to find the no. of buses that can be cleared by the daredevil, we first need to find the distance he will cover during its motion. Since, the motion is projectile, therefore, the horizontal distance will be equal to range of the projectile:

R = V² Sin 2θ/g

where,

R = Range = ?

V = launch speed = 43 m/s

θ = angle with horizontal = 30°

g = 9.8 m/s²

Therefore,

R = (43 m/s)² Sin 60°/(9.8 m/s²)

R = 163.4 m

Now, for the number of cars cleared, we use the following formula:

No. of Cars = R/Length of single bus

No. of Cars = 163.4 m/20 m

No. of Cars = 8.17

No. of Cars = 8

Answer:

83.33s

Explanation:

velocity=300km/hr ,acceleration =1m/s2

But before we can make this calculation,we have to make sure that both the acceleration and velocity are in the same units.So I decided to Chang the velocity to m/s.

Converting 300km/hr into m/s;

Changing 300km into m=300000m

Changing 1hr into secs=3600sec

Velocity in m/s=83.33m/s

But Time =velocity/acceleration

=83.33/1

=83.33sec

You have to decide what you want.  Your question says "Find the average velocity", but the choices you listed are all times, not velocities.

(300 km/hr) x (1 hr / 3600 sec) = 83.33 meters/sec

-- If the airplane starts from rest and accelerates uniformly at 1 m/s², it'll take 83.33 seconds to reach takeoff speed.

-- If it starts from rest and accelerates uniformly to 83.33 m/s, then its average speed is 41.67 m/s no matter what its acceleration may be.

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Answer: angle of incidence

Answer:

A) angle of incidence

Explanation:

Answer:

a.) L = 2.64 kgm^2/s

b.) V = 4.4 m/s

Explanation: Jessica stretches her arms out 0.60 m from the center of her body. This will be considered as radius.

So,

Radius r = 0.6 m

Mass M = 2 kg

Velocity V = 1.1 m/s

Angular momentum L can be expressed as;

L = MVr

Substitute all the parameters into the formula

L = 2 × 1.1 × 0.6 = 1.32kgm^2s^-1

the combined angular momentum of the masses will be 2 × 1.32 = 2.64 kgm^2s-1

b. If she pulls her arms into 0.15 m,

New radius = 0.15 m

Using the same formula again

L = 2( MVr)

2.64 = 2( 2 × V × 0.15 )

1.32 = 0.3 V

V = 1.32/0.3

V = 4.4 m/s

Her new linear speed will be 4.4 m/s

Answer:

this relationship to be true the value  x ’must be positive, so it must move to the right.

Explanation:

En este ejercicio debemos utilizar la relacion de equilibrio rotacional.

Fijemos un sistema de referencia situado en el eje de jiro del sistema y la rotación antihoraria es positiva.

Las esferas estan a la izquierda y el contrapeso ala derecha

                W d = w_contrapeso  x

donde W es el peso de las esferas de d su distancia hasta eleje de giro

Ahora colocamos la carga negativa debajo de la esfera A, como las cargas son de diferente signo  las dos esferas se atraen, lo que crea una fuerza hacia bajos de magnitud

       F =k q₁ q₂/r²

       F =8,9 10⁹  1 2/ (2d)²

       F = 4,45/d²  N

volvamos escribir la ecuación de equilibrio rotacional con esta fuerza

          F d + W d = W_contrapeso (x+x’)

          (4,45 10⁹ /d²) d + W d = W_conrapeso x+ W contrapesos x’

en la primera ecuación vimos que  dos terminos se igualan ,por lo cual se anulan quedando  

          4,45 10⁹/d = W contrapeso x’

para que esta relación sea cierta el valor e x’ debe ser positivo, por lo cual debe moverse a la derecha.  

Traduction

In this exercise we must use the relationship of rotational equilibrium.

Let's fix a frame of reference located on the system's axis of rotation and the counterclockwise rotation is positive.

The spheres are on the left and the counterweight on the right

                W d = w_counterweight x

where W is the weight of the spheres of d its distance to the turning axis

Now we place the negative charge under sphere A, as the charges are of different sign the two spheres attract, which creates a downward force of magnitude

       F = k q₁ q₂ / r²

       F = 8.9 10⁹ 1  2 / (2d)²

       F = 4.45 / d² N

let's rewrite the rotational equilibrium equation with this force

          F d + W d = W_ counterweight (x + x ’)

          (4.45 10⁹ / d²) d + W d = W_counterweight x + W counterweights x’

In the first equation we saw that two tenunos are equal, which is why they cancel, leaving

          4.45 10⁹ / d = W counterweight  x ’

for this relationship to be true the value  x ’must be positive, so it must move to the right.

Answer:

i. + 22.5 m ii. 4.0 m

Explanation:

i. Image distance

Using the lens formula

1/u + 1/v = 1/f where f = focal length = + 18.0 m, u = object distance = distance of shark away from lens = + 90.0 m and v = image distance from lens = unknown

So, we find v

1/v = 1/f - 1/u

= 1/+18 - 1/+90

= (5 - 1)/90

= 4/90

v = 90/4

= + 22.5 m

So the image is real and formed 22.5 m away on the other side of the lens.

ii Length of Shark

Using the magnification formula, m = image height/object height = image distance/object distance. image height = 1.0 m where object height = length of shark.

m = image distance/object distance

= v/u

= +22.5/+90

= 0.25

0.25 = image height/object height

So,

object height = image height/0.25

= 1.0 m/0.25

= 4.0 m

So, the length of the shark is 4.0 m

Answer:

78 cm³

Explanation:

The Volume Immersed = (density of object/ density of fluid) x Volume of Object

Vi = (7800/13600) x 136 = 78 cm³

Answer:

The temperature remains constant

Explanation:

From the radiation law, the net energy radiated P = Power radiated - Power absorbed

Now, let the body be at a temperature T₁ above its surroundings, the rate at which energy is given of is  P₁ = σεAT₁⁴

let T₂ be the temperature of its surroundings, the rate at which energy is absorbed is P₂ = σεAT₂⁴

The net energy radiated (Power radiated) P = P₂ - P₁ = σεAT₂⁴ - σεAT₁⁴ = σεA(T₂⁴ - T₁⁴)

Now, if the object absorbs energy at the same rate it gives off energy, P₁ = P₂ and P = 0.

So, σεA(T₂⁴ - T₁⁴) = 0

Since σεA ≠ 0 then (T₂⁴ - T₁⁴) = 0 ⇒ T₂ = T₁

Since there is no temperature difference, the temperature of the object remains constant.

Answer & explanation:

Answer: 0.625N

Explanation:

Given the following:

Magnetic field Force = 0.25N

Length of wire = 8cm

Current = 3.0 ampere

The force that the same field will exert on another wire 20cm long carrying the same current will be :

Since current 'I' is the same ;

0.25 Force = 8cm

x force = 20cm

Cross multiply:

8x = (20 × 0.25)

x = (20 × 0.25) / 8

x = 5 / 8

x = 0.625

Force = 0.625N

Answer:

A magnetic field exerts a force of 0.25 N on an 8.0 cm length of wire carrying a current of 3.0 A at right angles to the field. Calculate the force that the same field would exert on another wire 20 cm long carrying the same current. I WILL GIVE BRAINLY

Explanation:

Answer:

mass of the solid is 10.8kg

Explanation:

Weight of the solid=w=18.36N

Force of gravity on the surface of the moon=g=1.71Nkg^-1

Mass of the solid on the moon=m=?

as we know that

weight=mass×force of gravity

here we have to find the mass

[tex]\frac{weight}{force of gravity}[/tex]=mass

mass=[tex]\frac{18.36N}{1.7Nkg^-1}[/tex]

Mass of the solid=10.8kg

i hope it will help you

Answer:

Check Explanation

The fission reactions include

239 Pu + n → Ce + Kr + 2n

And

295 Am + in → 154 La + 95 Sr + 3 n

Explanation:

A fission reaction is a radioactive reaction in which an atom with a heavy nuclei splits into atoms with smaller or lighter nuclei usually brought about by the attack of a fundamental particle and accompanied by the release of some fundamental particles (neutrons mostly) and energy.

Although, the reactions to be examined aren't totally clear, we can still guess which element is which and know which of the reactions has a heavier nuclei splitting into smaller ones.

1) H + H → He + 2n

Two hydrogen atoms combine to give an helium atom and release neutrons too, showing that here, smaller molecules combine to form a bigger one. Hence, this isn't a fission reaction, rather, it's a fusion reaction.

2) 239 Pu + n → Ce + Kr + 2n

Here, Pu (Plutonium, atomic mass 239), a heavy nuclei that splits into smaller nuclei, Ce (Cerium, atomic mass 140) and Kr (Krypton, atomic mass 84) together with some neutrons to fit the definition of a fission reaction. Hence, this reaction is a fission reaction.

3) 295 Am + n → 154 La + 95 Sr + 3 n

Here, Pu (Americium, atomic mass 295), a heavy nuclei that splits into smaller nuclei, Ce (Lamthanium, atomic mass 154) and Sr (Strontium, atomic mass 95) together with some neutrons to fit the definition of a fission reaction. Hence, this reaction is a fission reaction.

4) 13C + H → 14N

Carbon 13 combines with a hydrogen element to mutate and give nitrogen-14, a heavier nuclei, showing all signs of a nuclear fission and not fission.

Hope this Helps!!!

Answer:

b and c

Explanation:

got it correct on edg

Answer:

The correct answer to the following question will be "An ecosystem".

Explanation:

So that the above seems to be the right answer.

Answer:

Option A

Explanation:

A. A ball is dropped from a height and hits the ground with a high speed. As this is a ball, it has elastic energy, so upon impact on the ground the kinetic energy can 1. go into making sound upon impact, or 2. go into making the ball bounce upward again. There may by more possible energy transfers, but this is what should occur in like conditions. Now it didn't mention that the ball transfers energy as such, only that the ball hits the ground at high speed. Thus, this statement does not explicitly describe a transfer of energy.

_______________________________________________________

Just to confirm that this is the correct answer, take a look at the other options. Option B states that the energy from the collision is transferred to heat, not in those exact words but still is given. Option C states that the plane increases speed, most likely transferring energy to the atmosphere, in the form sound. In option d the electricity causes the fan to turn, an explicit statement of the transfer of energy.

Hope that helps!

Answer:

Approximately [tex]2.31\; \rm m \cdot s^{-2}[/tex] (assuming that the acceleration due to gravity is[tex]g = 9.81\; \rm m \cdot s^{-2}[/tex].)

Explanation:

Assuming that [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex] the weight on this 72-kg skydiver would be [tex]W = m \cdot g = 72 \; \rm kg \times 9.81\; \rm m \cdot s^{-2} = 706.32\; \rm N[/tex] (points downwards.)

Air resistance is supposed to act in the opposite direction of the motion. Since this skydiver is moving downwards, the air resistance on the skydiver would point upwards.

Therefore, the net force on this skydiver should be the difference between the weight and the air resistance on the skydiver:

[tex]\begin{aligned}F(\text{net force}) &= W - F(\text{air resistance})\\ &= 706.32\; \rm N - 540\; \rm N =166.32\; \rm N \end{aligned}[/tex].

Apply Newton's Second Law of motion to find the acceleration of this skydiver:

[tex]\begin{aligned}a &= \frac{F(\text{net force})}{m} \\ &= \frac{166.32\; \rm N}{72\; \rm kg} = 2.31\; \rm m \cdot s^{-2} \end{aligned}[/tex].

Answer:

a) The baseball spends 0.674 seconds in the air

b) The horizontal distance from the roof edge to the point where the baseball lands on the ground = 2.02 m

Explanation:

The ball's initial speed, u = 3.8 m/s

θ = 38°

The edge of the roof has a height, H = 3.30 m

The vertical motion of the baseball can be given by the equation:

[tex]H = U_{y} t + 0.5a_{y} t^{2}[/tex].........(1)

Vertical acceleration of the baseball, [tex]a_y = 9.8 m/s^2[/tex]

The vertical component of the initial speed can be calculated by:

[tex]U_y = Usin \theta\\U_y = 3.8 sin 38\\U_y = 2.34 m/s[/tex]

Substituting the appropriate values into equation (1):

[tex]3.8 = 2.34 t + 0.5(9.8)} t^{2}\\4.9t^2 + 2.34t - 3.8 = 0[/tex]

Solving for t in the quadratic equation above:

t = 0.674 s

To calculate the horizontal distance, S, use the formula below:

[tex]S = U_xt + 0.5a_xt^2[/tex]

Horizontal acceleration of the baseball, [tex]a_x = 0 m/s^2[/tex]

The horizontal component of the initial speed can be calculated as:

[tex]U_x = Ucos \theta\\U_x = 3.8 cos 38\\ U_x = 2.99 m/s[/tex]

S = 2.99(0.674) + 0.5(0)

S = 2.02 m

Answer:

35.5 ml

Explanation:

The other guy made me get the question wrong lol here ya go good luck

Answer:

Compression

Explanation:

I would think it would be compression because you are compressing the marshmallow, and pushing it down until its compact.

Answer: Compression, I to had to get an answer for this but imma help you out :)

Answer:

m = 3 kg

Explanation:

It is given that,

Initial speed of a ball is 5 m/s, u = 5 m/s

Final speed of a ball is 4 m/s, v = 4 m/s (as it bounces)

Impulse provided by the wall is -3 N-m (impulse is provided in opposite direction)

We need to find the mass of the ball. Impulse provided to an object is given by the change in its momentum as :

J = m(v-u)

m is mass of the ball

[tex]m=\dfrac{J}{(v-u)}\\\\m=\dfrac{-3}{(4-5)} \\\\m=3\ kg[/tex]

So, the mass of the ball is 3 kg.

Answer: It is the product of the (force)multiplied by the (perpendicular) distance from the line of action of the force to the pivot

Explanation:

Answer:

Yes, the fuse will blow.

Explanation:

We'll begin by converting 50000mA to amperes (A) .this is illustrated below:

1000mA = 1A

Therefore, 50000mA = 50000/1000 = 50A.

From the question given above, the plug can only accommodate 5A. Now if 50000mA i.e 50A is passed through the plug, the plug will blow because the 50A is higher than what the plug can accommodate.

Answer: I maybe wrong but i'm pretty sure its C) Kinetic energy

Answer:yess

Explanation:as weather balloons travels from the earth's surface, the air pressure around ballons decreases slowly.As the air gets thinner,the gallons casing gets tighter.

This is due to gas expanding within balloon.The expanding gas causes the balloons to reach maximum height and it burst.

Answer:

880,000 J

Explanation:

P = W/t

4400 W = W / 200 s

W = 880,000 J

Answer:

880,000 J

Explanation:

Answer:

1. factor that is dependent on the length of the material.

2. factor that is dependent on the area of the material

Explanation:

Resistance R is directly proportional to its length L of an object and it is inversely proportional to the crossectional area of that object.

Mathematically, this is represented as:

a) Resistance R is directly proportional to its length L of an object

R ∝ L ......... Equation 1

b) Resistance R is inversely proportional to the crossectional area (A) of an object

R ∝ 1/A ............ Equation 2

Combining the two equations together, we have:

Resistance R is directly proportional to its length L of an object

R ∝ L/A .......... Equation 3

Resistivity of a material is the natural or inherent or intrinsic property that a material has. The Resistivity of a material is not dependent on the length or crossectional area of such material. It is only temperature dependent.

The resistance of a material is also dependent on the resistivity of the material. This means the resistance of a material is directly proportional to the resistivity of the material.

R ∝ ρ........Equation 4

Combining Equation 4 and 3 together, we have:

R = ρL/A

Where:

R = Resistance

ρ = Resistivity

L = Length of the material

A = Crossectional area of the material

Resistance and resistivity are related by a factor that is dependent on the length of the material a factor that is dependent on the area of the material