Answer:
After 8 minutes ; altitude = 22,400 feet
Step-by-step explanation:
s1 = 2800t
s2 = -3200t + 48 000
2800t = -3200t + 48 000
28t = -32t + 480
7t = -8t + 120
7t + 8t = 120
15t = 120
15/15 t = 120/15
t = 8 minutes
s = 8 * (2800) = 22400 feet
16 divided by the sum of 2 and 6
Answer:
Step-by-step explanation:
16/(2+6)
16/8=2
Review the proof. Step 1 / cos(2x) =1-2sin2x
Which step contains an error?step 2/ step 4/ step 6/ step 8
Answer:
Step 6 is wrong
36 is 40% of what number?
[tex]\fbox{90}[/tex]
In order to find 36 is 40% of what number, we will need to use the following formula:
[tex]number\times100/Percent[/tex]
[tex]\frac{36\times100}{40}[/tex]
[tex]36\times100=3,600[/tex]
[tex]3,600\div40[/tex]
[tex]=90[/tex]
The solution of the number in the expression ''40% of a number is 36'' is 90.
Given that,
To find the solution for 40% of that number is 36.
Used the concpet of percentage which stated that,
A number or ratio that can be expressed as a fraction of 100 or a relative value indicating the hundredth part of any quantity is called a percentage.
Let us assume that the solution of the given condition is x.
So, it can be written as,
[tex]40\% \times x = 36[/tex]
[tex]\dfrac{40}{100} \times x = 36[/tex]
Multiply both sides by 100,
[tex]40x = 36 \times 100[/tex]
[tex]40x = 3600[/tex]
Divide both sides by 40,
[tex]x = \dfrac{3600}{40}[/tex]
[tex]x = 90[/tex]
So, the solution for the number is 90.
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Find the nth term for 13 8 3 -2 -7 and the 100th term
Answer:
see explanation
Step-by-step explanation:
there is a common difference between consecutive terms in the sequence, that is
8 - 13 = 3 - 8 = - 2 - 3 = - 7 - (- 2) = - 5
this indicates the sequence is arithmetic with nth term
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = 13 and d = - 5 , then
[tex]a_{n}[/tex] = 13 - 5(n - 1) = 13 - 5n + 5 = 18 - 5n
then
a₁₀₀ = 18 - 5(100) = 18 - 500 = - 482
The sides of a triangle are in the ratio of 3:4:5. A man jogged around it 5 times and cover a distance of 3000m What are the sides of the triangle?
The sides of the triangle are 150m, 200m and 250m.
What is distance?
Distance is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. Distance can refer to a physical length in physics or to an estimate based on other factors in common usage.
Given: The sides of a triangle are in the ratio of 3:4:5. A man jogged around it 5 times and cover a distance of 3000m.
As man jogged around triangle 5 times and cover a distance of 3000m.
So, the distance for one round is 3000/5 = 600m.
The covered distance is nothing but the perimeter of the triangle.
So, the perimeter of the triangle is 600m.
Let, 3x, 4x, 5x are the sides of the triangle.
⇒ 3x + 4x + 5x = 600
12 x = 600
x = 50
Therefore,
3x = 3(50) = 150
4x = 4(50) = 200
5x = 5(50) = 250
Hence, the sides of the triangle are, 150m, 200m and 250m.
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Please help now !!!!!!
Answer:
The tablet costs more than the smartphone
Step-by-step explanation:
1 year tablet = $1.50
1 year smartphone = $0.02x12months = $0.24
a group of people were given a spelling test. the table shows their marks. work out the range of the marks. how many students are in the group. work out the mean mark of the group.
Answer: a) = 4
b) = 30
Step-by-step explanation:
a) They are asking for the range of the marks so you do 10-6 as 10 is the highest mark and 6 is the lowest
b) You find this out by adding the frequency up 10+4+7+4+5 = 30
24 greater than or equal to 2X - 10 less than -6
Find the length of side AC. Give your answer to 1 decimal place.
The length of AC is 17.3 cm
What is rectangle?We also refer to a rectangle as an equiangular quadrilateral since all of its angles are equal.A closed 4-sided shape is called a quadrilateral.A rectangle can also be referred to as a right-angled parallelogram because its sides are parallel.A quadrilateral with equal and parallel opposite sides is referred to as a parallelogram.Paralleograms are a specific instance of rectangles.acc to our question,
AC is the perpendicularAB is the base and θ = 68°So,tan 68° = or, AC = tan 68°×AB 17.3 (approx)Hence,The length of AC is 17.3 cm
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Factor the expression (72a9b3 − 18a7b5) completely.
The factor of the expression 72[tex]a^{9} b^{3}[/tex] - 18[tex]a^{7} b^{5}[/tex] is 18[tex]a^{7} b^{3}[/tex](4[tex]a^{2}[/tex] - [tex]b^{2}[/tex]).
Given expression:
= 72[tex]a^{9} b^{3}[/tex] - 18[tex]a^{7} b^{5}[/tex]
divide by 18 .
= 4[tex]a^{9} b^{3}[/tex] - [tex]a^{7} b^{5}[/tex]
divide by [tex]a^{7}[/tex]
= 4[tex]a^{2}b^{3}[/tex] - [tex]b^{5}[/tex]
divide by [tex]b^{3}[/tex]
= 4[tex]a^{2}[/tex] - [tex]b^{2}[/tex]
= 18[tex]a^{7} b^{3}[/tex](4[tex]a^{2}[/tex] - [tex]b^{2}[/tex]).
Therefore the factor of the expression 72[tex]a^{9} b^{3}[/tex] - 18[tex]a^{7} b^{5}[/tex] is 18[tex]a^{7} b^{3}[/tex](4[tex]a^{2}[/tex] - [tex]b^{2}[/tex]).
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-2/5 + -2/5 i just need this thank you
Answer:
The answer would be -4/5
Step-by-step explanation:
When you add a negative to a negative, you first take out the plus sign and rewrite it as: -2/5 - 2/5.
Now you just simply subtract 2/5 from -2/5 to get -4/5.
Hope this helps.
Please give brainliest
Question content area top
Part 1
The dot plot shows predictions for the winning time in the 200-meter sprint. The winner finished the race in 22.4 seconds. What is the greatest percent error among the predictions?
The greatest percent error among the predictions is of:
2.23%.
How to obtain the percent error of a measure?The percent error of a measure is obtained by the division of the difference between the actual value and the estimated value by the actual value, and multiplied by 100%, hence the equation is:
Percent error = |Actual - Estimate|/Actual x 100%.
From the given dot plot, we have that the farthest measure from 22.4 seconds is of 22.9 seconds.
The difference between the actual time and the estimate time is of:
22.9 seconds - 22.4 seconds = 0.5 seconds.
Applying the presented division, the percent error is given as follows:
Percent error = 0.5/22.4 x 100% = 2.23%.
Missing InformationThe dot plot is given by the image at the end of the answer.
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Given mn, find the value of x.
+
(8x-4)°
(6x-12)°
Answer:
The value of the equation will be 14
Which value of y makes the two matrices inverses of each other?
[6 14]. [-1 -7/2]
[-2-4] [y. 3/2]
-1/2
-5/14
1/2
2
The value of y that makes the two matrices inverse of each other is 1/2
The inverse of a square matrix A, denoted by A⁻¹.
The formula is [tex]\frac{1}{|A|}.adj(A)[/tex]
The product of A and A⁻¹ should be the identity matrix. The identity matrix that results will be the same size as matrix A.
Inverse of given first matrix is
[tex]\left[\begin{array}{cc}6&14\\-2&-4\end{array}\right][/tex]
Determinant = |A| = 6(-4) - (14)(-2)
= -24 + 28
= 4
Adjoint of matrix = [tex]\left[\begin{array}{cc}-4&-14\\2&6\end{array}\right][/tex]
Inverse of matrix = [tex]\frac{1}{|A|}.adj(A)[/tex]
Therefore , Inverse = [tex]\frac{1}{4}.\left[\begin{array}{cc}-4&-14\\2&6\end{array}\right][/tex]
= [tex]\left[\begin{array}{cc}-4/4&-14/4\\2/4&6/4\end{array}\right][/tex]
A⁻¹ = [tex]\left[\begin{array}{cc}-1&-7/2\\1/2&3/2\end{array}\right][/tex]
Is required inverse
If we compare the inverse with second matrix
y = 1 / 2
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Answer:
third option: 1/2
Step-by-step explanation:
Graph the line that passes through the points (9,2) and (3,4) and determine the equation of the line ( I need it with graph)
The equation of the line that passes through the points (9,2) and (3,4) is x + 3y = 15 and the graph is shown below .
In the question ,
it is given that
the required line passes through the points (9,2) and (3,4)
in order to find the equation of line we first need to find slope .
so , the slope(m) will be
m = (4-2)/(3-9)
m = 2/(-6)
m = -1/3
The equation of the line passing through the point (3,4) having slope -1/3 is
y - 4 = (-1/3)(x - 3)
3(y - 4) = -1(x - 3)
3y - 12 = -x + 3
x + 3y = 12 + 3
x + 3y = 15
the graph of the line is drawn below .
Therefore ,The equation of the line that passes through the points (9,2) and (3,4) is x + 3y = 15 .
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Which of the following is a line that is parallel to the line defined by the equation 4x+7y=49−2x+4y?
a
3y+40=3x+10
b
y=20x+15
c
4y=10x+15
d
y=4x−2
e
2y+x=40−3x
A line parallel to the line 4x + 7y = 49 - 2x + 4y must have a slope of - 2.
What are lines and their slopes?We know lines have various types of equations, the general type is
Ax + By + c = 0, and the equation of a line in slope-intercept form is
y = mx + b.
Where slope = m and b = y-intercept.
the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.
Given a line that is 4x + 7y = 49 - 2x + 4y.
7y - 4y = - 2x - 4x + 49.
3y = - 6x + 49.
y = - 2x + 49/3.
Now, lines parallel to each other have the same slope.
Now if we simply the given options none of the lines have a slope of - 2 so none of the given lines are parallel to the line 4x + 7y = 49 - 2x + 4y.
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Linda' chool play tarted at 9:05 AM. It lated 1 hour and 45 minute. What time did the play end?
In given word problem ending time of the play is 10.50 AM.
What is word problem?
A comprehensive list of math word problems focuses on addition, subtraction, multiplication, division and more specific operations. life scenario. This means that children must be familiar with vocabulary associated with familiar mathematical symbols in order to understand word problems.
Here starting time of play = 9:05 AM
It took 1 hour 45 minutes to end the play. Then ,
=> 9 hour 05 minutes
1 hour 45 minutes +
=> 10 hour 50 minutes.
Hence ending time of the play is 10.50 AM.
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a) Work out the gradient of the line y=5x-3 (1)
Gradient = (Answer here)
b) Work out the gradient of the line 3y-12x+7=0 (1)
Gradient = (Answer here)
Answer:
5 and 4
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the gradient and c the y- intercept )
(a)
y = 5x - 3 ← is in slope- intercept form
with gradient m = 5
(b)
3y - 12x + 7 = 0 ( add 12x to both sides )
3y + 7 = 12x ( subtract 7 from both sides )
3y = 12x - 7 ( divide through by 3 )
y = 4x - [tex]\frac{7}{3}[/tex] ← in slope- intercept form
with gradient m = 4
PLEASE HELP! I WILL NAME YOU THE BRAINLIEST!
THE THING IS IN THE PHOTO!
Work does not need to be shown.
Answer: The correct answer is Option D: h=2A/(b1+b2)
Step-by-step explanation:
Solve for h:
a=(1/2h)(b1+b2)
Step 1: Flip the equation
1/2b^2h+1/2b1h=a
Step 2: Factor out variable h
h((b2+b1)/2)=a
Step 3: Divide both sides by (b^2+b1)/2
h((b2+b1/2))/(b2+b1/2)=(a/(b2+b1)/2)
h=2a/(b2+b1)
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Starting at the beginning of the year, Kianna was able to save $215 each month. However
for the last 3 months, she increases her saving to $305 each month, and she plans to
continue saving the same amount of money for 2 more months (until end of the year).
What will be the amount of money Kianna save this year?
By using addition and multiplication, the result obtained is
Kianna saves $3020 this year
What is addition and multiplication?
Suppose there are many numbers. To get the sum total of all the numbers, addition is used
Repeated addition is called multiplication
Addition and multiplication will be used here
Amount of money Kianna saves each month for the first 7 months = $215
Total amount of money Kianna saved in the first 7 months = $215 [tex]\times[/tex] 7
= $1505
Amount of money she saves each month for the last 5 months = $305
Amount of money she saves in the last 5 months = $305 [tex]\times[/tex] 5 = $1515
Total amount of money Kianna saves this year = $(1505 + 1515)
= $3020
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Please someone help me. Number 7 and 8. Thank you.
7. The composite functions are given as follows:
a. f(g(x)) = [tex]\frac{3x}{-x^2 + 3x - 1}[/tex].
b. g(f(x)) = [tex]\frac{3x(x - 1)}{9x^2 + x - 1}[/tex]
c. (f(g(3)) = -9.
8. The inverse function is given as follows:
[tex]f^{-1}(x) = \frac{4 + x}{3 - x}[/tex]
How to obtain the composite function?The composite functions are obtained using the inner function as the input to the outer function.
In this problem, the functions are defined as follows:
f(x) = x/(x - 1).g(x) = 3x/(x² + 1).The composite of f and g is:
[tex]f(g(x)) = f\left(\frac{3x}{x^2 + 1}\right) = \frac{\frac{3x}{x^2+1}}{\frac{3x}{x^2+1} - 1} = \frac{\frac{3x}{x^2+1}}{\frac{-x^2 + 3x - 1}{x^2 + 1}} = \frac{3x}{-x^2 + 3x - 1}[/tex]
At x = 3, the numeric value of the composite function is given as follows:
f(g(3)) = 9/(-9 + 9 - 1) = -9.
The composite function of g and f is given as follows:
[tex]g(f(x)) = g\left(\frac{x}{x - 1}\right) = \frac{\frac{3x}{x - 1}}{\left(\frac{3x}{x - 1}\right)^2 + 1} = \frac{3x}{x - 1} \times \frac{(x - 1)^2}{9x^2 + x - 1} = \frac{3x(x - 1)}{9x^2 + x - 1}[/tex]
Inverse functionThe function is given as follows:
y = (3x + 4)/(x - 1)
The find the inverse, the variables x and y are exchanged, and then y is isolated, as follows:
x = (3y + 4)(y - 1)
xy - x = 3y + 4
3y - xy = 4 + x
y(3 - x) = 4 + x
y = (4 + x)/(3 - x)
[tex]f^{-1}(x) = \frac{4 + x}{3 - x}[/tex]
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What is the vertex of f(x)= 3x^2+12x-8? A (2, 28) B (-2, -20) C (4,88) D (-4,-8)
Answer:
B (-2,-20)
Step-by-Step Explanation:
f(x)=3x^2 + 12x - 8
a=3 b=12
x=-12/2*3
x=-2
f(x)=3(-2)^2 + 12x - 8 , x=-2
f(-2) = -20
solution (-2,-20)
Question 2(Multiple Choice Worth 1 points)
(02.05 MC)
Choose the table that represents g(x) = -2xf(x) when f(x) = x + 4.
The correct table is :
x g(x)
1 -10
2 -12
3 -14
Given, f(x) = x+4
and g(x) = -2.f(x)
we check for x = 1
f(x) = 1+4
= 5
now g(x) = -2.f(x)
= -2(5)
= -10
for x=2
f(x) = 2+4
= 6
now g(x) = -2.f(x)
= -2(6)
= -12
for x=3
f(x) = 3+4
= 7
now g(x) = -2.f(x)
= -2(7)
= -14
Hence we get the required values.
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Answer:
C
Step-by-step explanation:
see the other dudes answer im jus making it easier to see and select for kids who have to hide the fact that they're cheating on their FLVS
Does-4y-3=1/3(12y-9)-8y
Blank 1 options
(Blank 1)
have one solution, no solution, or infinitely many solutions?
Answer:
infinite solution
Step-by-step explanation:
Since 0 = 0 for any value of y, the system of equations has infinite solutions.
Can anyone state the vertex of the graph?
The graph has no vertex
The transformations from the parent function are
Vertical shift down 2Horizontal shift left 4How to determine the vertex?The graph represents the given parameter
As a general rule, the maximum or the minimum of a graph is the vertex
However, the graph has no maximum or minimum
This means that there is absence of a vertex in the graph
The transformationHere, we have:
The graph is translated 4 units to the left of the origin The graph is translated 2 units below the originThis transformation can be represented as (x - 4, y - 2)
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A triangle has sides with lengths of 26 inches, 36 inches, and 46 inches. Is it a right triangle?
yes or no
Answer:
no
Step-by-step explanation:
You want to know if side lengths 26 in, 36 in, 46 in form a right triangle.
Pythagorean tripleThe integer side lengths will form a right triangle if they are a Pythagorean triple, or a multiple of one.
We notice that these side lengths have a common difference of 10 in. That makes them an arithmetic sequence. The only Pythagorean triples that are an arithmetic sequence are {3, 4, 5} and its multiples. The shortest side is 3 times the common difference.
The lengths {26, 36, 46} cannot form a right triangle. The attachment shows the triangle is an obtuse triangle.
No, the triangle is not a right triangle.
__
Additional comment
The side lengths will form a right triangle if and only if they satisfy the relation a² +b² = c², where a, b are the two short sides.
26² +36² = 1972 ≠ 2116 = 46²
Find the largest area for a rectangle that is inscribed in a semicircle with radius 4 inches.
The area of the largest rectangle is 25 square units.
It is given that the radius of the semicircle is [tex]4[/tex].
It is required to inscribe a rectangle of maximum area.
Consider a rectangle of sides [tex]x[/tex], [tex]y[/tex] as shown in the given figure.
From the attached figure,[tex]AB=x[/tex], [tex]OB=r[/tex] and [tex]OB=\frac{y}{2}[/tex].
Now, in the triangle OAB, apply Pythagoras' theorem as,
[tex](OA)^{2}=(OB)^{2}+(AB)^2[/tex]
[tex]r^2=(\frac{y}{2} )^2+x^2\\\\[/tex]
[tex]16=\frac{y}{4}+x^2[/tex]
[tex]y^2=4(16-x^2)[/tex]
[tex]y=2\sqrt{16-x^2}[/tex]
So, the area of the rectangle will be,
Area,
[tex]A = 2x \times y[/tex]
= [tex]2x \times \sqrt{(16 - x^2)}[/tex]
Differentiate the area with respect to ,
[tex]A' = 2 \times \sqrt{(16 - x^2)} - 2x^2/(16 - x^2)[/tex]
Differentiate the area twice as,
When[tex]x = 0, y = 5[/tex] and when [tex]x = 5, y = 0[/tex], [tex]area = 0[/tex].
It implies that area is maximum when the value of x lies between 0 and 5.
This will occur where [tex]A'= 0[/tex].
⇒ [tex]2 \times \sqrt{(16 - x2) }- 2x^2/(16 - x^2) = 0[/tex]
⇒[tex]2 \times \sqrt{(16 - x^2)} = 2x^2/(16 - x^2)[/tex]
On simplification, we get,
⇒ [tex]2 \times (16 - x^2) = 2x^2[/tex]
⇒ [tex]16 - x^2 = x^2[/tex]
⇒ [tex]2x^2= 16[/tex]
⇒ [tex]x^2 = 16/2[/tex]
⇒ [tex]x = \sqrt{8}[/tex]
Now, [tex]y = \sqrt{(16 - x^2)}[/tex] becomes
⇒[tex]y = \sqrt{(16 - (\sqrt8)^2)}[/tex]
⇒ [tex]y = \sqrt{(16 - 8)}[/tex]
[tex]y =\sqrt{8}[/tex]
Maximum area = 2xy
[tex]=2(\sqrt{8)}(\sqrt{8})[/tex]
[tex]=16[/tex]
Therefore, the area of the largest rectangle is 16 square units.
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Jane received a $70 gift card for a coffee store. She used it in buying some coffee that cost $8.39 per pound. After buying the coffee, she had $28.05 left on her card. How many pounds of coffee did she buy?
Answer:
85 ggoooofffffyyy
Step-by-step explanation:
Which value is the best approximation for the range in ages for the oldest 25% of viewers?
4
6
15
20
The best estimation for the range of the oldest 25% is 20, so the correct option is the last one.
Which value approximates the range for the oldest 25%?The graph is separated in four parts, each part represents a 25% of the population.
The oldest 25% would be the last segment (the line in the right of the graph).
The range is defined as the difference between the largest value and the smallest value.
The segment starts at:
a = 35
And ends at:
b = 55
Then the range is something like:
55 - 35 = 20
The correct option is the last one.
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7. The perpendicular bisectors of
AEFG meet at point H. Find HJ.
The distance of the intersection of 3 perpendicular bisectors of a triangle to the 3 vertices are equal.
In other words, HF = HE = HG.
Therefore, we see that 3 isosceles triangles are identified : HFE, HFG, HGF.
We're given HF = 15, therefore HE = 15.
Since HJ is the perpendicular bisector of line EG, JE = JG.
Therefore, JE = 12.
Now, we use the Pythagorean theorem in the right triangle HJE :
[tex]HE^{2} = HJ^{2} + JE^{2} - > HJ = \sqrt{15^{2} - 12^{2} } =\sqrt{81} = 9.[/tex]