Answer: C, supplements and drugs both undergo stringent government testing.
Explanation: took the unit test.
hope this helps :)
Answer:
C
Explanation:
How much work do you do when you push a shopping cart with a force of 20 N for a distance of 5m?
A.100J
B.10J
C.1J
D.1000J
Answer:
A.100J
Explanation:
Given parameters:
Force on car = 20N
Distance = 5m
Unknown:
Work done = ?
Solution:
Work done is the product of force and distance;
Work done = force x distance;
Insert given parameters and solve;
Work done = 20 x 5 = 100J
A pyrotechnical expert needs to fire a 15 kg projectile from a launching device that has a barrel length of 2 meters. The projectile will need to be launched horizontally 1 km in 5 seconds. Calculate the force needed to launch the projectile.
Answer:
The force needed to launch the projectile is 150000 N.
Explanation:
We can find the force using the following equation:
[tex] F = ma [/tex]
Where:
m: is the mass = 15 kg
a: is the acceleration
First, we need to find the acceleration of the projectile:
[tex] v_{f}^{2} = v_{0}^{2} + 2ax [/tex]
Where:
[tex]v_{f}[/tex]: is the final speed
[tex]v_{0}[/tex]: is the initial speed = 0
x: is the distance = 2 m
The final speed is:
[tex]v_{f} = \frac{1 km}{5 s}*\frac{1000 m}{1 km} = 200 m/s[/tex]
Then, the acceleration is:
[tex]a = \frac{v_{f}^{2}}{2x} = \frac{(200 m/s)^{2}}{2*2 m} = 10000 m/s^{2}[/tex]
Finally, the force is:
[tex]F = ma = 15 kg*10000 m/s^{2} = 150000 N[/tex]
Therefore, the force needed to launch the projectile is 150000 N.
I hope it helps you!
The chart shows the percentage of different elements in the human body.
Which element is the most prevalent in the human body?
nitrogen
hydrogen
carbon
oxygen
Answer the following questions
Answer:
9 - 10N to the left
10 - There is no change on the object
Explanation:
Can I have brainliest answer pls?
In order to determine the wavelength, you must know the distance from the (2 points)
Select one:
a. trough of one wave to the crest of the next wave
b. midpoint of a wave to the highest point of the next wave
c. crest of the wave to the equilibrium of the same wave
d. the crest of one wave to the crest of the next wave
Answer:
b
Explanation:
Answer:
a
Explanation:
because the crest and trough are the same length when together and they squeeze together making the length shorter for higher frequencies and are spaced apart when lower frequencies occur
A bowling ball with a mass of 7.0kg strikes a pin that had a mass of 2.0kg the pin flies forward with a velocity of 6.0m/s, and the ball continues forward at 4.0 m/s. What was the original velocity of the ball?
The conservation of momentum P states that the amount of momentum remains constant when there are not external forces.
We don't have external forces, so:
[tex]P_0 = P_1\\m_bv_{0b}+m_pv_{0p}=m_bv_{1b}+m_pv_{1p}\\[/tex]
Where:
mb is the mass of the bowling ball mp the mass of the pin[tex]v_{0b}\quad and\quad v_{0p}[/tex] the initial velocities of the bowling ball and the pin.[tex]v_{1b}\quad and\quad v_{1p}[/tex] the final velocities of the bowling ball and the pin.Solving for v0b:
[tex]v_{0b} =\dfrac{m_bv_{1b}+m_pv_{1p}- m_pv_{0p}}{m_{b}}\\\\v_{0b} =\dfrac{(7\;kg)(4\;m/s)+(2\;kg)(6\;m/s)- (2\;kg)(0 \;m/s)}{7\;kg}\\v_{0b}=\dfrac{40}{7}\;m/s\\\\\boxed{v_{0b}\approx5.71\;m/s}[/tex]
R/ The original velocity of the ball was 5.71 m/s.The original velocity of the ball is 5.71 m/s.
The principle of conservation of momentum: In a closed system, The total momentum before collision is equal to total momentum after collision.
From the principle of conservation of momentum,
MU+mu = MV+mv.................... Equation 1
Where M = mass of the bowling ball, m = mass of the pin, U = initial velocity of the bowling ball, u = initial velocity of the pin, V = final velocity of the bowling ball, v = final velocity of the pin.
From the question,
Given: M = 7 kg, m = 2 kg, u = 0 m/s (at rest), v = 6.0 m/s, V = 4 m/s.
Substitute these values into equation 1 and solve for U
7(U)+2(0) = 7(4)+2(6)
7U = 28+12
7U = 40
U = 40/7
U = 5.71 m/s.
Hence, The original velocity of the ball is 5.71 m/s.
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what is energy?
a. the number of atoms in an object
b. a form of sound
c. the ability to do work
d. the size of an object
(ik its not b or d, but i dont know)
Answer:
c
Explanation:
c. the ability to do work or to produce heat
As the frequency of a wave decreases, the wave's -
Answer:
When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.
Suppose a cart of mass 0.5 kg is placed on the table and connected to a mass hanging mass over the edge. If the hanging mass is 0.2 kg, when what would be the acceleration of the cart?
Explanation:
0.10kg
0.5kg×0.2kg=
0.10
Question 7 (2 points)
Rachel performed an experiment testing the hours students slept with their
performance on a test. In this experiment, the hours that they slept was the_____ variable, while the grade they got on
the test was the
_____ variable.
A standing wave has a frequency of 471 Hz and a wavelength of 1.9. What is the speed of the
wave? (Round to the 2nd number after the decimal)
1
I REALLY NEED HELP !
Answer:
c = 894.90 m/s
Explanation:
Given data:
Frequency of wave = 471 Hz
Wavelength of wave = 1.9 m
Speed of wave = ?
Solution:
Formula:
Speed of wave = frequency × wavelength
c = f×λ
c = 471 Hz × 1.9 m
Hz = s⁻¹
c = 471s⁻¹ × 1.9 m
c = 894.90 m/s
The speed of wave is 894.90 m/s.
A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate
acceleration.
Answer:
Acceleration = 3m/s^2
Vf= 0 Vi =35m/s t= 13s
Explanation:
[tex]Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2[/tex]
Juan makes an adjustment to an electromagnet that causes the electromagnet to lose some of its strength. What did Juan most likely do?
He reduced the number of loops in the wire.
He increased the number of loops in the wire.
He reduced the length of the wire.
He increased the length of the wire.
Answer:
Its A
Explanation:
To reduce the strength of an electromagnet, Juan must reduced the number of loops in the wire.
What is electromagnetic field strength?
The strength of an electromagnetic is the effect or force that an electromagnet exerts in a given field.
The strength of an induced emf in a given magnetic field is given by;
emf = NBA/t
where;
N is number of turns of the magnetB is magnetic field strengthA is area of the coilDecrease in number of turns of the wire, reduces the strength of the magnetic field.
Thus, to reduce the strength of an electromagnet, Juan must reduced the number of loops in the wire.
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Una larga fanja de pavimento tiene marcas a intervalos de 10m. Los estudiantes usan cronometros para registrar los tiempos en que un automovil pasa por cada marca. Asi han obtenido los datos siguientes: Distancia,m l 0 l 10 l 20 l 30 l 40 l 50 l Tiempo,s l 0 l 2.1 l 4.2 l 6.3 l 8.4 l 10.5 l A) Cual es la rapidez media del vehiculo? B) Al cabo de cuanto tiempo la distancia es igual a 34m? C) Cual es la aceleracion del automovil?
Answer:
men
Explanation:
Which evidence did Alfred Wegener’s original theory of continental drift have access to?
Answer:
Evidence for continental drift
Wegener knew that fossil plants and animals such as mesosaurs, a freshwater reptile found only South America and Africa during the Permian period, could be found on many continents. He also matched up rocks on either side of the Atlantic Ocean like puzzle pieces.
Explanation:
A +4.0 uC charge is placed on the x axis at x= +3.0 m, and a -2.0 uC is located on the y-axis at y= -1.0 m. Point A is on the y axis at y= +4.0 m. Determine the electric potential at point A (relative to zero at the origin).
Answer:
The potential is [tex]V_A = 9600 \ V[/tex]
Explanation:
From the question we are told that
The magnitude of the charge is [tex]q_1 = 4 \mu C = 4*10^{-6} \ C[/tex]
The position of the charge is [tex]x = + 3.0 \ m[/tex]
The magnitude of the second charge is [tex]q_2 = -2.0 \mu C = -2.0 *10^{-6} \ C[/tex]
The position is [tex]y_1 = - 1.0 \ m[/tex]
The position of point A is [tex]y_2 = + 4.0 \ m[/tex]
Generally the electric potential at A due to the first charge is mathematically represented as
[tex]V_a = \frac{k * q_1 }{r_1 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]
[tex]r_1[/tex] is the distance between first charge and a which is mathematically represented as
[tex]r_1 = \sqrt{x^2 + y_2 ^2 }[/tex]
=> [tex]r_1 = \sqrt{3^2 + 4 ^2 }[/tex]
=> [tex]r_1 = 5 \ m[/tex]
So
[tex]V_a = \frac{9*10^9 * 4*10^{-6} }{5 }[/tex]
[tex]V_a = 7200 \ V[/tex]
Generally the electric potential at A due to the second charge is mathematically represented as
[tex]V_b = \frac{k * q_2 }{r_2 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]
[tex]r_2[/tex] is the distance between second charge and a which is mathematically represented as
[tex]r_2 = y_2 - y[/tex]
=> [tex]r _2 = 4.0 - (-1.0)[/tex]
=> [tex]r = 5 \ m[/tex]
So
[tex]V_a = \frac{9*10^9 * -2*10^{-6} }{5 }[/tex]
[tex]V_a = -3600 \ V[/tex]
So the net potential difference at point A due to the charges is mathematically represented as
[tex]V_n = V_a + V_b[/tex]
=> [tex]V_n = 7200 - 3600[/tex]
=> [tex]V_n = 3600 V[/tex]
Generally the net potential difference at the origin due to both charges is mathematically represented as
[tex]V_N = V_c + V_d[/tex]
Here
[tex]V_c = \frac{k * q_1 }{x}[/tex]
=> [tex]V_c = \frac{9*10^9 * 4*10^{-6} }{3}[/tex]
=> [tex]V_c = 12000 V[/tex]
and
[tex]V_d= \frac{k * q_2 }{y}[/tex]
=> [tex]V_c = \frac{9*10^9 * -2*10^{-6} }{1}[/tex]
=> [tex]V_c =- 18000 V[/tex]
Generally the net potential difference at the origin is
[tex]V_N = 12000 - 18000[/tex]
=> [tex]V_N = -6000[/tex]
Generally the potential difference at A relative to zero at the origin is mathematically evaluated as
[tex]V_A = V_n - V_N[/tex]
=> [tex]V_A = 3600 - (-6000)[/tex]
=> [tex]V_A = 9600 \ V[/tex]
Why is an important to come up with a plan for how are you to respond to negative peer pressure before the situation happens
A: it is hard to refuse in the situation if you have not decided how you would handle it ahead of time
B: because it is very likely you will face these situation in the future
C: both a and b
Answer:
C ( is hard to refuse in the situation if you have not decided how you would handle it ahead of time
B: because it is very likely you will face these situation in the future)
True or False: A cloud’s only purpose is to create precipitation.
Answer:
I think it's false
Explanation:
clouds also help regulate the Earth's energy balance by reflecting and scattering solar radiation and by absorbing the Earth's infrared radiation.
Answer:
false
Explanation:
A 1800 kg car moves along a horizontal road at speed v₀ = 18.4 m/s. The road is wet, so the static friction coefficient between the tires and the road is only µ static = 0.188 and the kinetic friction coefficient is even lower, µ kinetic = 0.1316. The acceleration of gravity is 9.8 m/s². What is the shortest possible stopping distance for the car under such conditions? (neglect the reaction time of the driver and round your answer to 4 decimal places)
Answer:
The shortest possible distance is [tex]|s| = 91.9 \ m[/tex]
Explanation:
From the question we are told that
The mass of the car is [tex]m = 1800 \ kg[/tex]
The speed along the horizontal road is [tex]v_o =u = 18.4 \ m/s[/tex]
The static friction coefficient is [tex]\mu_s = 0.188[/tex]
The kinetic friction coefficient is [tex]\mu_k = 0.1316[/tex]
Generally the static frictional force acting on the car is mathematically represented as
[tex]F_f = m * g * \mu_s[/tex]
Generally the force propelling the car is mathematically represented as
[tex]F = m * a[/tex]
Here a is the maximum acceleration
at the point which the car stops ,
[tex]F = F_f[/tex]
=> [tex]m * g * \mu_s = ma[/tex]
=> [tex]g * \mu_s =a[/tex]
=> [tex]a = 9.8 * 0.188[/tex]
=> [tex]a = 1.8424 \ m/s^2[/tex]
Generally from kinematic equation
[tex]v^2 = u^2 + 2as[/tex]
Here v is the final velocity of the car and the value is zero given that the car comes to rest
So
[tex]0^2 = 18.4^2 + 2* 1.8424 s[/tex]
=> [tex]s = - \frac{18.4^2}{2 * 1.8424}[/tex]
=> [tex]|s| = 91.9 \ m[/tex]
Where does digestion begin?
Answer:
Digestion begins in the mouth, when you chew.
HELPP ITS DUE IN 5 MINUTES FREE BODY DIAGRAMS
Answer:
I think it's part c . but sorry if its wrong
A car slows down from 65 km/s to 30 km/s in 5 seconds. What is its acceleration?
4. When energy is transformed from one form to another, what kind of energy is
always part of the transformation ? (and is usually not in a useful form)
Biomechanical Energy
O Heat Energy
Nuclear Energy
Answer:
Energy conversion also termed as the energy transformation, is the process of changing one form of energy into another.
The Law of Energy Conversion.
Scenario Energy conversions involved
In steam engine The heat energy to Mechanical Energy
In Electric heater Electric Energy to Heat
During the transformation of energy from one form to another, the kind of energy that is always part of the transformation is: C. Heat energy.
What is energy?
Energy can be defined as the ability (capacity) to do work. Thus, the standard unit of measurement of energy is Joules (J).
The various kind of energy:
Basically, there are different kind of energy and these include:
Biomechanical energyWave energySound energyNuclear energyHeat energyThe Law of Conservation of Energy:
According to the Law of Conservation of Energy, energy can neither be created nor destroyed but it can only be transformed (converted) from one form to another such as potential energy to kinetic energy.
As a general rule, heat energy is always associated with the transformation of energy from one form to another.
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A scientist is observing a eukarotic cell and a prokaryotic cell. Which structure could she only observe in the eukaryotic cell?
cytoplasm
DNA
ribosomes
a nucleus
Answer:
It's definitely Nucleus
Hope this Helps!
How much air resistance acts on a 100-N bag of nails that falls at its terminal speed?
gold has a density of 19300 kg/m3 calculate the mass of 0.02m3 of gold in kilograms
Mass if a substance is the product of its volume and density. The mass of gold of 0.02 m³ with a density of 19300 kg/m³ is 386 kg.
What is density?Density of a substance is the measure of its mass per unit volume. Thus, it says how much denser the object is in a given volume. Density of a substance is dependent on its bond type, temperature and pressure beside the volume and mass.
Volume can be defined as the space occupied by the substance. Larger the volume , less dense the substance is. However as the mass increases volume also increases.
Mass of an object is the product of its volume and density.
Given the volume of gold = 0.02 m³
density = 19300 kg/m³.
mass = volume × density
= 0.02 m³ × 19300 kg/m³
= 386 kg
Therefore, the mass of gold is 386 Kg.
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A cat rolls up a hill. It’s initial Velocity is 10 m/s.n It’s final velocity is 0 m/s. The time was five seconds. Calculate Acceleration
Answer:
[tex]\boxed {\boxed {\sf a= -2 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
The final velocity of the cat was 0 meters per second and the initial velocity was 10 meters per second. The time was 5 seconds.
[tex]v_f=0 \ m/s\\v_i=10 \ m/s\\t= 5 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{0 \ m/s-10 \ m/s}{5 \ s}[/tex]
Solve the numerator.
0 m/s-10 m/s= -10 m/s[tex]a=\frac{-10 \ m/s}{5 \ s}[/tex]
Divide.
[tex]a= -2 \ m/s^2[/tex]
The acceleration of the cat was -2 m/s². The negative acceleration indicates slowing down or stopping.
This equation shows the reaction that occurs when calcium carbonate
decomposes. what type of reaction is it? CaCO3 + energy – CaO + CO2
a. endothermic
b. synthesis
c. replacement
d. exothermic
ADD ANSWER
+6 PTS
Answer:
a. endothermic
Explanation:
The reaction shown is an endothermic reaction. In such reaction, they require an input of energy.
Endothermic changes involves absorption of heat from the surrounding. The surrounding becomes colder at the end of the reaction. When heat is on the reactant side, it suggests a reaction that requires a considerable input of energy.
A 1500 kg car is parked at the top of a hill 5.2 m high. What is the velocity of the car, in meters per second, when it reaches the bottom of the hill?
Answer:
Explanation:
The car will fall with acceleration due to gravity which is equal to 9.8 m /s²
For downward fall ,
initial velocity u = o
acceleration due to gravity = g = 9.8 m /s
final velocity v = ?
displacement h = 5.2 m
v² = u² + 2 gh
v² = 0 + 2 x 9.8 x 5.2
= 101.92
v = 10.1 m /s
What is Newtons third law of motion?
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. Explanation:
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction
Explanation:
In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.