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4. Calculate the federal income taxes. In 1862, the federal income tax was 3 percent on incomes between $600 and $10,000 per year and 5 percent on incomes
over $10,000 per year. In 1862, you made $750. How much did you pay in income taxes?
O $37.50
O $225
O $22.50
$2,250

Answer:

5

Step-by-step explanation:

Answer:

Less Than :)

Step-by-step explanation:

Answer:

66 2/3

Step-by-step explanation:

(2/3)(100) = 66 2/3

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Question reads....}[/tex]

[tex]\large\textbf{What percent is equivalent to }\rm{\bf \dfrac{2}{3}}\large\textbf{ ?}[/tex]

[tex]\huge\textbf{Let's simplify the current fraction}\\\huge\textbf{to find the overall result to this question.}[/tex]

[tex]\mathbf{\dfrac{2}{3}}[/tex]

[tex]\mathbf{= 2\div3}[/tex]

[tex]\mathbf{= 0.66666667}[/tex]

[tex]\mathbf{= 0.66666667 \times 100}[/tex]

[tex]\mathbf{= 66.6666667\%}[/tex]

[tex]\mathbf{\approx 66.67\%}[/tex]

[tex]\huge\textbf{Let's do process of elimination to find}\\\huge\textbf{the fraction that is equivalent to yours.}[/tex]

[tex]\huge\textsf{Option A.}[/tex]

[tex]\mathbf{66 \dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{66\times3+1}{3}}[/tex]

[tex]\mathbf{= \dfrac{198 +1}{3}}[/tex]

[tex]\mathbf{= \dfrac{199}{3}}[/tex]

[tex]\mathbf{= 199\div3}[/tex]

[tex]\mathbf{= 66.3333333}[/tex]

[tex]\mathbf{= 66.3333333 \times100}[/tex]

[tex]\mathbf{= 6,633.33333\%}[/tex]

[tex]\mathbf{\approx 6,633.33\%}[/tex]

[tex]\huge\textsf{This eliminates Option A. as your result.}[/tex]

[tex]\huge\textsf{Option B.}[/tex]

[tex]\mathbf{66 \dfrac{3}{5}}[/tex]

[tex]\mathbf{= \dfrac{66\times5 + 3}{5}}[/tex]

[tex]\mathbf{= \dfrac{330 + 3}{5}}[/tex]

[tex]\mathbf{= \dfrac{333}{5}}[/tex]

[tex]\mathbf{= 333\div5}[/tex]

[tex]\mathbf{= 66.6}[/tex]

[tex]\mathbf{= 66.6 \times 100}[/tex]

[tex]\mathbf{= 6,660}[/tex]

[tex]\mathbf{\approx 6,660\%}[/tex]

[tex]\huge\textsf{This eliminates Option B. as your result.}[/tex]

[tex]\huge\textsf{Option C.}[/tex]

[tex]\mathbf{66 \dfrac{2}{3}}[/tex]

[tex]\mathbf{= \dfrac{66\times3+2}{3}}[/tex]

[tex]\mathbf{= \dfrac{198 + 2}{3}}[/tex]

[tex]\mathbf{= \dfrac{200}{3}}[/tex]

[tex]\mathbf{= 200\div3}[/tex]

[tex]\mathbf{= 66.6666667}[/tex]

[tex]\mathbf{= 66.6666667\times100}[/tex]

[tex]\mathbf{= 6,666.66667}[/tex]

[tex]\mathbf{\approx 6,666.67\%}[/tex]

[tex]\huge\textsf{This eliminates Option C. as your result.}[/tex]

[tex]\huge\textsf{Option D.}[/tex]

[tex]\mathbf{66\dfrac{7}{10}}[/tex]

[tex]\mathbf{= \dfrac{66\times10 +7}{10}}[/tex]

[tex]\mathbf{= \dfrac{660 + 7}{10}}[/tex]

[tex]\mathbf{= \dfrac{667}{10}}[/tex]

[tex]\mathbf{= 667\div10}[/tex]

[tex]\mathbf{= 6.67}[/tex]

[tex]\mathbf{= 6.67\times100}[/tex]

[tex]\mathbf{= 6,670}[/tex]

[tex]\mathbf{\approx 6,670\%}[/tex]

[tex]\huge\textsf{This eliminates Option D. as your result.}[/tex]

[tex]\huge\textbf{It seems like none of the above matches }\\\huge\textbf{the original fraction, so we will use the}\\\huge\textbf{that is close to the original answer.}[/tex]

[tex]\huge\textbf{The closest answer was:}[/tex]

[tex]\mathbf{66 \dfrac{2}{3}}[/tex]

[tex]\huge\textbf{Therefore the answer MIGHT be:}[/tex]

[tex]\huge\boxed{\mathsf{Option\ C. \ 66 \dfrac{2}{3}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

The anti-derivative of f(x) will be:

[tex]\int \:10x^4+12.5dx=2x^5+12.5x+C[/tex]

Step-by-step explanation:

Given the function

[tex]\:f\left(x\right)=10x^4\:+\:12.5[/tex]

Taking the anti-derivative of f(x)

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:[/tex]

[tex]\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx[/tex]

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx[/tex]

Solving

[tex]\int 10x^4dx[/tex]

[tex]\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx[/tex]

[tex]=10\cdot \int \:x^4dx[/tex]

[tex]\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1[/tex]

[tex]=2x^5[/tex]

similarly,

[tex]\int 12.5dx[/tex]

[tex]\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax[/tex]

[tex]=12.5x[/tex]

so substituting these values

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx[/tex]

                                [tex]=2x^5+12.5x[/tex]

                               [tex]=2x^5+12.5x+C[/tex]   ∵ Add constant to the solution

Therefore, the anti-derivative of f(x) will be:

[tex]\int \:10x^4+12.5dx=2x^5+12.5x+C[/tex]

Answer:

hio

Step-by-step explanation:

hi

As early as 4,000 years ago, but the first recorded use of a zero-like symbol dates to sometime around the third century B.C. in ancient Babylon.

Given that, the ancient Babylonians were writing fractions in 1800 BCE.

In Mathematics, fractions are represented as a numerical value, which defines a part of a whole. A fraction can be a portion or section of any quantity out of a whole, where the whole can be any number, a specific value, or a thing.

In fact, at first, fractions weren't even thought of as numbers in their own right at all, just a way of comparing whole numbers with each other.

The word fraction actually comes from the Latin "fractio" which means to break. To understand how fractions have developed into the form we recognize, we'll have to step back even further in time to discover what the first number systems were like.

From as early as 1800 BC, the Egyptians were writing fractions. Their number system was a base 10 idea (a little bit like ours now) so they had separate symbols for 1, 10, 100, 1000, 10000, 100000 and 1000000.

Hence, as early as 4,000 years ago, but the first recorded use of a zero-like symbol dates to sometime around the third century B.C. in ancient Babylon.

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Answer:

a. y = 2 + 2x

b. y = 20 - 4x

c. y = 2 + 1.5x

d. y = 20 - 3x

Step-by-step explanation:

I Hope That This Helps! :)

Answer:

Exact form: 157/20

Decimal Form: 7.85

Mixed Number Form: 7/17/20

Step-by-step explanation:

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

A right turn represents a clockwise rotation of the direction vector by 90°. It is equivalent to multiplying the complex number representation by -i.

A left turn represents a counterclockwise rotation of the direction vector by 90°. It is equivalent to multiplying the complex number representation by i.

The attached table shows the desired values and expressions.

Step-by-step explanation:

[tex]\boxed{\begin{array}{c|c|c} \underline{Intial -d} & \underline {Left-turn} & \underline{Right-turn} \\ -1 & -i & i \\ 1 & i & -i \\ i & -1 & 1\\ -i & 1 & -1 \\ d & di & -di \end{array}}[/tex]

9514 1404 393

Answer:

  A) the curves are ellipses

  B) 161 yards

  C) 366 yards

Step-by-step explanation:

A) The general shape of the side marked c has the appearance of two quarter-ellipses. The major axis is approximately 125 yards, and the minor axis is approximately 80 yards. Paul could assume that the curves are quarter-ellipses.

__

B) For an ellipse with this eccentricity, its perimeter is within 2% of that of a circle with a diameter equal to the average of these dimensions.*

So, the approximate length of side c is ...

  c ≈ π(80 +125)/4 ≈ 161 . . . . yards; length of side c

__

C) The perimeter of the pond is the sum of the side lengths, so will be ...

  80 yds + 125 yds + 161 yds = 366 yds . . . pond perimeter

_____

* Indian mathematician Ramanujan developed an approximate formula for the circumference of an ellipse, which would otherwise need to be computed using an elliptic integral. it is ...

  C = π(a+b)(1 + 3λ²/(10 +√(4 -3λ²))

where λ = (a -b)/(a +b) and a, b are the semi-axis lengths.

For this ellipse, λ = 9/41, so the last factor is about 1.01208313. Using this factor, the circumference is expected to be good to about 7 significant digits. Continuing the calculation, we find ...

  C ≈ 325.904 . . . . circumference of an ellipse 125 yd long by 80 yd wide

This is twice the length we imagine for c, so c ≈ 163 yards. As we said, the approximation used above is within 2% of this value.

The attachment shows the shape if the curve is actually an ellipse.

Answer:

The answer is letter A.

-7+3(-4e-3)

−7+3((−4)(2.718282)−3)

=−48.619382

-4(3e+4)

−4((3)(2.718282)+4)

=(−4)((3)(2.718282)+4)

=(−4)((3)(2.718282))+(−4)(4)

=−32.619382−16

=−48.619382

Answer:

This is called a prepayment

Answer:

The maximum amount of apples she could buy is 7

Step-by-step explanation:

3 mangos would be 4.50 dollars. Subtract that from her current amount of money (20 dollars). You would get 15.5 dollars. Then, find how many apples she can buy with 15.5 dollars. You can't buy 8 because that would be above 15.5. So do the next smallest amount, 7.

Answer:

See steps below

Step-by-step explanation:

WS ⊥ MH , HS = SM ......... Given

<HSW = <MSW = 90  .....  From WS ⊥ MH

Triangle HWS = Triangle WMS .... SAS  theorem

<M = <H  .... based on triangle congruency, and angle opposed to equal side WS

Answer:

x>-17.2

Step-by-step explanation:

Simplify both sides of the inequality

-0.5x-3.1< 5.5

Add 3.1 to both sides

-0.5x< 8.6

Divided both sides by -0.5

x>-17.2

Hope this helped! :)

Answer:

the answer is there should be another digit in the quotient

Answer:

No, because there should be another digit in the quotient

Answer:

the answer is 9

Step-by-step explanation:

Answer:

it is 9

Step-by-step explanation:

Answer:

Step-by-step explanation:

the answer is D

Answer:

hope this helps :)

Step-by-step explanation:

Since we know how far she can walk in 1/5 (one fifth) of an hour, if we multiply this distance by 5, we will find out how far she can walking in 5/5 (five fifths) of an hour, or to be clear: in one hour.

So, 5 x 1/4 miles = 5/4 or 1.25 miles per hour

Jazmeen can walk 1.25 miles in one hour.

Answer:

he will fill 6 pitchers

Step-by-step explanation:

4.8÷0.8=6

Answer:

280

Step-by-step explanation:

Month 1: 100 + 30 = 150

Month 2: +30

Month 3: +30

Month 4: +30

Month 5: +30

Month 6: +30

Total: 280

Hope this helps!

Answer:

$280

Step-by-step explanation:

For this problem, we simply need to take the initial cost of membership and add that to the reoccurring cost from a time period, in this case, 6 months.  So let's make an equation to represent this.

The initial cost is $100

The per month cost is $30

Total cost after 6 months = Inital cost + Per Month Cost * 6 months

Total cost = $100 + $30 * 6

Total cost = $100 + $180

Total cost = $280

Thus, a member will spend $280 after 6 months on the membership.

Cheers.

Answer:

1.2

Step-by-step explanation:

0.3 * 4

= 3 * 0.1  * 4

= 3 * 4 * 0.1

= 12 * 0.1

= 1.2

Answer:

2

Step-by-step explanation:

Answer:

so what is the question?

Problem 1

f(x) = x + 1/x

f(1) = 1 + 1/1

f(1) = 1 + 1

f(1) = 2

Answer: 2

============================================

Problem 2

(f o f)(1) = f( f(1) )

(f o f)(1) = f( 2 )

(f o f)(1) = 2 + 1/2

(f o f)(1) = 4/2 + 1/2

(f o f)(1) = 5/2

Answer:  5/2

============================================

Problem 3

(f o f o f)(1) = f(  f(f(1)) )

(f o f o f)(1) = f(  (f o f)(1) )

(f o f o f)(1) = f(  5/2 )

(f o f o f)(1) = 5/2 + 1/(5/2)

(f o f o f)(1) = 5/2 + 2/5

(f o f o f)(1) = 25/10 + 4/10

(f o f o f)(1) = 29/10

Answer: 29/10

============================================

Problem 4

(f o f o f o f)(1) = f(   f(f(f(1))   )

(f o f o f o f)(1) = f(   (f o f o f)(1)    )

(f o f o f o f)(1) = f(   29/10   )

(f o f o f o f)(1) = 29/10 + 1/(29/10)

(f o f o f o f)(1) = 29/10 + 10/29

(f o f o f o f)(1) = 841/290 + 100/290

(f o f o f o f)(1) = 941/290

Answer: 941/290

============================================

Problem 5

(f o f o f o f o f)(1) = f(   f(f(f(f(1))))   )

(f o f o f o f o f)(1) = f(   (f o f o f o f)(1)  )

(f o f o f o f o f)(1) = f(   941/290  )

(f o f o f o f o f)(1) = 941/290 + 1/(941/290)

(f o f o f o f o f)(1) = 941/290 + 290/941

(f o f o f o f o f)(1) = 885481/272890 + 84100/272890

(f o f o f o f o f)(1) = 969581/272890

Answer: 969581/272890

A function assigns the values. The value of (f•f•f•f•f)(1)​ is 969581/272890.

A function assigns the value of each element of one set to the other specific element of another set.

1.)

The value of f(1) for the given function f(x) =x+1/x can be calculated as shown below,

f(x) = x + 1/x

f(1) = 1 + 1/1

    = 1 + 1

    = 2

2.)

(f · f)(1) = f( f(1) )

Since the value of f(1)=2, therefore, it can be rewritten as,

(f · f)(1) = f(2)

           = 2 + 1/2

           = 4/2 + 1/2

           = 5/2

3.)

(f · f · f)(1) = f(  f(f(1)) )

Since the value of f(f(1))=5/2, therefore, it can be rewritten as,

(f · f · f)(1) = f(  (f·f)(1) )

              = f(  5/2 )

              = 5/2 + 1/(5/2)

              = 5/2 + 2/5

              = 25/10 + 4/10

              = 29/10

4.)

(f · f · f · f)(1) = f(  f(f(f(1))  )

Since the value of f(f(f(1)))=29/10, therefore, it can be rewritten as,

(f · f · f · f)(1) = f(   (f·f·f)(1)    )

                  = f( 29/10 )

                  = 29/10 + 1/(29/10)

                  = 29/10 + 10/29

                  = 841/290 + 100/290

                  = 941/290

5.)

(f · f · f · f · f)(1) = f(   f(f(f(f(1))))   )

Since the value of f(f(f(1)))=29/10, therefore, it can be rewritten as,

(f o f o f o f o f)(1) = f(   (f·f·f·f)(1)  )

                           = f(  941/290 )

                           = 941/290 + 1/(941/290)

                           = 941/290 + 290/941

                           = 885481/272890 + 84100/272890

                           = 969581/272890

Hence, the value of (f•f•f•f•f)(1)​ is 969581/272890.

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Answer:

The dimensions that will maximize the enclosed area of the pen is 250 ft by 250 ft

Step-by-step explanation:

we have the perimeter as 1000

So the sum of the lengths will be

1000/2 = 500

The dimensions that will maximize these pens will be such that they will have equal values

Mathematically, that will be 500/2 = 250 by 250

Answer:

y^2+2xy/-x^2-2xy OR -y^2-2xy/x^2+2xy OR -y^2-2xy/(x)(x+2y)

Step-by-step explanation:

So, this is an implicit differentiation problem

x^2y+y^2x

so,

use product rule for both

x^2y'+2xy+y^2+2yy'x

collect all the y's

-x^2y'-2xyy'=y^2+2xy

y'(-x^2-2xy)=y^2+2xy

=y^2+2xy/-x^2-2xy

Answer:

(x^3 + 6 x^2 + 3 x + 4)/x

Step-by-step explanation:

Simplify the following:

x^2 + 6 x + 3 + 4/x

Put each term in x^2 + 6 x + 3 + 4/x over the common denominator x: x^2 + 6 x + 3 + 4/x = x^3/x + (6 x^2)/x + (3 x)/x + 4/x:

x^3/x + (6 x^2)/x + (3 x)/x + 4/x

x^3/x + (6 x^2)/x + (3 x)/x + 4/x = (x^3 + 6 x^2 + 3 x + 4)/x:

Answer: (x^3 + 6 x^2 + 3 x + 4)/x

Answer:

Is this in a different language?

Step-by-step explanation:ok:)

Answer:

731

Step-by-step explanation: