Ali graphs the function f(x) = –(x + 2)2 – 1 as shown.

On a coordinate plane, a parabola opens up. It goes through (negative 3, 0), has a vertex at (negative 2, negative 1), and goes through (negative 1, 0). A vertical dashed line at (negative 2, 0) is parallel to the y-axis.
Which best describes the error in the graph?

The axis of symmetry should be x = –1.
The axis of symmetry should be x = 2.
The vertex should be a maximum.
The vertex should be (–2, 1).

Answer:

The axis of symmetry should be x = 2.

Step-by-step explanation:

:)

We have given that the function y = - (x + 2)² - 1. So, The axis of symmetry should be x=2 describing the error in the graph.

If a quadratic equation is written in the form

[tex]y=a(x-h)^2 + k[/tex]

then it is called to be in vertex form. It is called so because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)

This point (h,k) is called the vertex of the parabola that the quadratic equation represents.

We have given that the function y = - (x + 2)² - 1

so we have a =-1,

-h=2 implies that h=-2

k=-1

Therefore the vertex is (h,k)=(-2,-1)

vertex = (- 2, - 1)  

The axis of symmetry passes through the vertex, is vertical with the equation

x = - 2 is correct.

When the a > 0, the vertex is a minimum

when  a < 0, implies that vertex is a maximum

here a=-1 < 0 implies vertex should be a maximum

Since, the vertex(-2,-1) is maximum

Therefore the axis of symmetry should be x=2 to represent error in the graph.

To learn more about the maximum vertex here;

brainly.com/question/12446886

#SPJ2

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