alanine lewis structure

Answers

Answer 1

The Lewis structure of alanine consists of a central carbon atom bonded to an amino group, a carboxyl group, a hydrogen atom, and a methyl group.

The Lewis structure of a molecule illustrates the arrangement of atoms and their bonding patterns. Alanine is an amino acid that plays a crucial role in protein synthesis and is commonly found in living organisms. To determine the Lewis structure of alanine, we need to consider its molecular formula, which is C3H7NO2.

In the Lewis structure of alanine, the central carbon atom is bonded to four other groups. It forms a single bond with the amino group (-NH2), which consists of a nitrogen atom bonded to two hydrogen atoms.

Another single bond is formed with the carboxyl group (-COOH), which consists of a carbon atom double bonded to an oxygen atom and single bonded to an oxygen atom and a hydrogen atom. Additionally, the central carbon atom is bonded to a hydrogen atom (H) and a methyl group (-CH3).

The Lewis structure accurately represents the connectivity of atoms in alanine, providing a visual representation of its molecular structure. It helps in understanding the chemical properties and reactivity of alanine, as well as its role in biological processes such as protein synthesis.

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Related Questions

Complete the following and round properly according to sig fig rules: 34.8(129.3) / 10 (Remember, the " / " means to divide

Answers

Given expression: `34.8(129.3) / 10`To solve this, we need to follow the following steps: Step 1: Multiply the numbers inside the parenthesis. `34.8(129.3) = 4491.24`

Step 2: Divide the result of step 1 by the number outside the parenthesis. `4491.24 / 10 = 449.124`To round off the answer to two significant figures, we consider the third significant figure, which is `9` in this case. Since it is greater than 5, the digit in the hundredth's place will be rounded up. Therefore, the final answer is: `449`.Therefore, the value of the given expression 34.8(129.3) / 10 is `449`, rounded to two significant figures.

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Which of the following is a measured value? A. 20 desks B. 9 kilograms C. 4.67 centimeters D. 1 yard =3 feet a. A only b. Conly c. A&D d. B&C e. B,C&D

Answers

The measured value in the given options is 9 kilograms.

Measured value is a physical quantity that is determined by a measuring instrument, such as a balance or scale, and expressed in numerical terms. In the given options, we have 4 different values, they are:

20 desks

9 kilograms

4.67 centimeters

1 yard =3 feet

Out of these four values, only 9 kilograms is a measured value. The other values are either lengths or counts of a specific object.

A is not the main answer as there is another option, so it cannot be the answer.

B is not the main answer as there is another option, so it cannot be the answer.

C is the main answer, as it includes the only measured value among all options, which is 9 kilograms.

D is not the main answer as there is another option, so it cannot be the answer.

So, the correct answer is option C.

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How many molecules of water are in a collection of snowflakes with a mass of 0.005 grams?A) 5.43 x 1022B) 3.01 x 1024C) 1.67x 1020D) 2.17 x 1021

Answers

The number of molecules of water in a collection of snowflakes with a mass of 0.005 grams is approximately 1.67 x 10^20 molecules.

To determine the number of molecules of water in a collection of snowflakes with a mass of 0.005 grams, we need to use the concept of moles and Avogadro's number.

Calculate the number of moles of water:

We know the molar mass of water is approximately 18.015 grams/mol.

Mass (g) = Number of moles × Molar mass (g/mol)

0.005 g = Number of moles × 18.015 g/mol

Number of moles = 0.005 g / 18.015 g/mol ≈ 0.000277 mol

Calculate the number of molecules:

Avogadro's number states that there are approximately 6.022 x 10^23 molecules in one mole of a substance.

Number of molecules = Number of moles × Avogadro's number

Number of molecules = 0.000277 mol × 6.022 x 10^23 molecules/mol

Number of molecules ≈ 1.667 x 10^20 molecules

Therefore, the correct answer is C) 1.67 x 10^20 molecules.

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What will you do to quickly dissolve a solute in a solvent?; Which describes the ability of a solute to dissolve in a solvent?; Which type of solute dissolves the fastest Why?; What are the 3 ways to dissolve a solute in a solvent?

Answers

Quickly dissolving a solute in a solvent, you can increase the temperature and/or agitate the mixture.

The ability of a solute to dissolve in a solvent is described by its solubility.

The type of solute that dissolves the fastest is typically one that has a high solubility in the solvent and is finely divided or has a large surface area.

The three ways to dissolve a solute in a solvent are increasing temperature, agitating the mixture, and using solubility-enhancing agents.

Dissolving a solute in a solvent can be facilitated by employing various techniques. One way to expedite the dissolution process is by increasing the temperature of the solvent.

Higher temperatures provide more energy to the solvent molecules, allowing them to move more vigorously and collide with the solute particles more frequently.

This enhanced kinetic energy helps overcome the intermolecular forces holding the solute particles together, promoting their separation and dissolution into the solvent.

Agitating the mixture is another effective method. Stirring or shaking the solution helps to increase the contact between the solute and solvent, increasing the chances of successful collisions and facilitating faster dissolution.

The ability of a solute to dissolve in a solvent is described by its solubility.

Solubility refers to the maximum amount of solute that can dissolve in a given quantity of solvent at a specific temperature and pressure.

It is influenced by factors such as the nature of the solute and solvent, their respective polarities, and the presence of any solubility-enhancing agents.

Solutes with high solubility in a particular solvent will dissolve more readily compared to those with low solubility.

The type of solute that dissolves the fastest is typically one that possesses high solubility in the solvent and is either finely divided or has a large surface area.

A solute with high solubility readily interacts with the solvent molecules, leading to rapid dissolution.

Finely divided solutes or those with a large surface area provide more contact points for the solvent molecules, allowing for more efficient dissolution.

In summary, to quickly dissolve a solute in a solvent, increasing the temperature and agitating the mixture are effective techniques.

Solubility determines the ability of a solute to dissolve in a solvent, while a solute with high solubility, fine division, or a large surface area generally dissolves most rapidly.

Dissolution is a complex process influenced by multiple factors, including temperature, solute-solvent interaction, solubility, and surface area.

Understanding these factors and their interplay can provide insights into optimizing dissolution processes for specific applications.

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4. In one experiment, ibuprofen was isolated from some pills. Using only melting point techniques, explain how the identity of the isolated ibuprofen can be proven. Assume you have authentic ibuprofen available in the stockroom.
5. You melt the substance and de-coloration occurs. Unfortunately, you weren’t paying attention and miss the melting point. Should you start over or re-melt it? Or both are options ‘okay’?
6. When measuring the melting point of a substance, it suddenly disappears. What has happened? Can you still measure the melting point? If so, how?
7. We should not re-use a sample in a capillary tube for melting point measurement. Why not?
8. It takes significant amount of time for the melting point apparatus to cool down before next measurement if your new sample has a lower melting point than your previous one. What can you do to reduce this time in between measurements when many samples of different melting points are used?

Answers

The identity of the isolated ibuprofen can be proven using melting point techniques through a comparison of the melting point of the isolated ibuprofen with the melting point of the authentic ibuprofen available in the stockroom.

If the melting point of the isolated ibuprofen matches the melting point of the authentic ibuprofen within a reasonable range of error, then the identity of the isolated ibuprofen is proven. If de-coloration occurs when melting the substance and the melting point is missed, it is advisable to start over since missing the melting point means the temperature at which the substance changes state was not observed. Therefore, repeating the experiment would produce accurate and reliable results. If the substance suddenly disappears during the measurement of the melting point, it means the substance has sublimed. The melting point of the substance can still be measured by measuring the temperature at which the substance re-solidifies. This is known as the sublimation point.

It is not advisable to reuse a sample in a capillary tube for melting point measurement because the sample would have already undergone partial melting during the initial experiment, which would cause the melting point of the reused sample to be lower. This would result in erroneous and unreliable results. To reduce the time between measurements when many samples of different melting points are used, it is advisable to use a high-speed melting point apparatus that is equipped with a rapid cool-down feature. This would help to reduce the time taken for the apparatus to cool down between measurements, thus saving time.

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tolerance levels are the minimum permitted amounts of pesticides that can be found on a raw product.

Answers

The statement is incorrect because Tolerance levels in relation to pesticides refer to the maximum permitted amounts or concentrations of pesticides that can be present on raw agricultural products.

These tolerance levels are set by regulatory authorities to ensure the safety of consumers and to regulate the use of pesticides in agriculture.

When a pesticide is used on a crop, there is a waiting period or pre-harvest interval specified by the pesticide label. This waiting period allows time for the pesticide residues to break down or dissipate to levels that are within the established tolerance limits. After this waiting period, the crop can be harvested and sold as long as the pesticide residues are below the tolerance levels.

The tolerance levels are based on scientific assessments of the potential risks associated with pesticide residues and take into account factors such as toxicity, exposure pathways, and cumulative effects. These levels are set to protect public health and ensure that agricultural products meet acceptable safety standards.

It is important for farmers and food producers to adhere to these tolerance levels and comply with regulations to ensure that the food supply is safe for consumption.

Therefore, the correct statement is that tolerance levels are the maximum permitted amounts of pesticides that can be found on a raw product, rather than the minimum permitted amounts.

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The vapor pressure of chloroform is
173.11 mm Hg at 25 °C. A nonvolatile,
nonelectrolyte that dissolves in chloroform is
estrogen.
Calculate the vapor pressure of the solution at 25 °C when
14.03 g

Answers

The vapor pressure of the solution is a colligative property that depends on the number of solute particles present in the solution. The vapor pressure of the solution is 173.11 mm Hg.

This vapor pressure lowering is described by the Raoult’s law.According to Raoult's Law, the vapor pressure of a solution is given by:P1 = P°1x1P1 = Vapor pressure of the solutionP°1 = Vapor pressure of the pure solventx1 = Mole fraction of the solventIn this case, the solvent is chloroform, and the solute is estrogen.

Since estrogen is a non-volatile, non-electrolyte solute, it does not exert any vapor pressure. Hence, the total vapor pressure of the solution is equal to the vapor pressure of the solvent chloroform only. The amount of solute estrogen does not affect the vapor pressure of the solution, but it decreases the mole fraction of the solvent.

The mole fraction of chloroform can be calculated as:X(chloroform) = moles of chloroform / total moles of solutionMoles of chloroform can be calculated using the given mass of chloroform:Moles of chloroform = mass of chloroform / molar mass of chloroform

Molar mass of chloroform = 119.38 g/molMoles of chloroform = 14.03 g / 119.38 g/mol = 0.1174 molThe total moles of the solution can be calculated as:Total moles of the solution = moles of chloroformSince estrogen is non-volatile, non-electrolyte solute, it does not contribute to the total number of moles of the solution.

Hence, the mole fraction of chloroform can be calculated as:X(chloroform) = moles of chloroform / total moles of solution= 0.1174 / 0.1174 = 1Now, using Raoult's law, the vapor pressure of the solution can be calculated as:P1 = P°1x1P1 = Vapor pressure of the solution = 173.11 mm HgP°1 = Vapor pressure of the pure solvent = 173.11 mm Hgx1 = Mole fraction of the solvent = 1

Therefore, the vapor pressure of the solution is 173.11 mm Hg.

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Use equations to show the product(s) formed when each
of the following are reacted with
alkaline KMnO4 and hot acidic KMnO4.
a) Cyclohexene
b) 1,2-dimethylcyclohexene
c) 1-methy-1,3-cyclopentadiene

Answers

The product(s) formed when each of them are reacted with alkaline KMnO₄ and hot acidic KMnO₄:

a) Cyclohexene + Alkaline KMnO₄ -> 1,6-Hexanedioic acid

b) 1,2-Dimethylcyclohexene + Alkaline KMnO₄ -> 1,2-Dimethylcyclohexane-1,2-diol

c) 1-Methyl-1,3-cyclopentadiene + Alkaline KMnO₄ -> No reaction occurs with alkaline KMnO₄.

a) When cyclohexene reacts with alkaline KMnO₄, the following products are formed:

Cyclohexene + Alkaline KMnO₄ -> 1,6-Hexanedioic acid

b) When 1,2-dimethylcyclohexene reacts with alkaline KMnO₄, the following products are formed:

1,2-Dimethylcyclohexene + Alkaline KMnO₄ -> 1,2-Dimethylcyclohexane-1,2-diol

c) When 1-methyl-1,3-cyclopentadiene reacts with alkaline KMnO₄, the following products are formed:

1-Methyl-1,3-cyclopentadiene + Alkaline KMnO₄ -> No reaction occurs

When cyclohexene, 1,2-dimethylcyclohexene, or 1-methyl-1,3-cyclopentadiene react with hot acidic KMnO₄, the products depend on the specific conditions and reaction conditions. The reaction may involve oxidation and functional group transformations.

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is a sock drawer homogeneous or heterogeneous

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A sock drawer is considered heterogeneous.

A heterogeneous mixture refers to a combination of different components that can be visibly distinguished or separated. In the case of a sock drawer, it contains a variety of socks with different colors, patterns, sizes, and possibly materials. Each sock may differ from one another, making the contents of the drawer a heterogeneous mixture.

Thus, it is concluding that sock drawer s a heterogeneous mix of diverse socks.

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please help me
Which is the correct way to write the balanced equation for the reaction between nitrogen and oxygen to fo {NO}_{2} ? Note: You do not need to include phases or states for the substance

Answers

The balanced equation for the reaction between nitrogen and oxygen to form {NO}_{2} is: 4 NO + O2 → 2 NO2

Nitrogen and oxygen reacts to form nitrogen dioxide({NO}_{2}).The balanced chemical equation for the reaction is:

4 NO + O2 → 2 NO2  Where: NO - Nitrogen monoxide, O2 - OxygenNO2 - Nitrogen dioxide.

To balance the equation: There are four nitrogen atoms on the left-hand side and two on the right, so we add a coefficient of two to the NO2: 4 NO + O2 → 2 NO2.

There are two oxygen atoms on the left-hand side and four on the right, so we add a coefficient of two to the O2: 4 NO + 2 O2 → 2 NO2.

The balanced equation for the reaction between nitrogen and oxygen to form {NO}_{2} is:4 NO + O2 → 2 NO2

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Question 1: Calculate [OH−OH−] for a solution where [H3O+]=0.00425 M[H3⁢O+]=0.00425 M.
[OH−]=
Question 2:
Calculate the pH of a solution that has a hydroxide ion concentration, [OH−][OH−], of 1.70×10−4 M.1.70×10−4 M.
pH=

Answers

Question 1: The value of [OH−] in the given solution is 2.35 × [tex]10^-12[/tex] M. The relationship between hydronium ion and hydroxide ion concentration is given by this equation: [H3O+][OH−]=1.0×10−14.The value of the product of [H3O+][OH−] at 25°C is 1.0×10−14;

As a result, in any aqueous solution, when one ion concentration rises, the other ion concentration decreases.So, for the given solution [H3O+] = 0.00425 M, we can calculate [OH−] by rearranging the above equation as shown below:[H3O+][OH−]=1.0×10−14[OH−]

=1.0×10−14/[H3O+]

Substituting [H3O+] = 0.00425 M into the above equation, we get:[OH−]=1.0×10−14/0.00425

[OH−]=2.35×[tex]10^-12[/tex]  M

Thus, the value of [OH−] in the given solution is 2.35 × [tex]10^-12[/tex] M.

Question 2:The pH scale ranges from 0 to 14. The pH of a solution is equal to the negative logarithm of the hydronium ion concentration in moles per liter (M) of the solution. The pH can be calculated using the following formula:

pH=−log[H3O+]

In this question, the value of [OH−] is given instead of [H3O+].

However, the product of [H3O+][OH−] equals 1.0×10−14.

Consequently, we can compute the [H3O+] and then calculate the pH as shown below:

[H3O+][OH−]=1.0×10−14[OH−]=1.0×10−14/[H3O+]

Substituting [OH−] = 1.70×10−4 M into the above equation, we get:

[H3O+]=1.0×10−14/[OH−][H3O+]

=1.0×10−14/(1.70×10−4 )[H3O+]

=5.88×10−11 M

Now that we know the value of [H3O+], we can calculate the pH:

pH=−log[H3O+]

pH=−log(5.88×10−11 )

pH=10.23

Therefore, the pH of the given solution is 10.23.

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a buffer solution contains acetic acid (hc2h3o2) at a concentration of 0.225 m and sodium acetate (nac2h3o2) at a concentration of 0.164 m. the value of ka for acetic acid is 1.75 x 10-5 . calculate the ph of this solution.

Answers

The pH of the buffer solution is approximately 4.74.

To calculate the pH of the buffer solution, we can use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the pKa of the acid and the ratio of its conjugate base to the acid:

pH = pKa + log([A-]/[HA])

In this case, acetic acid (HC2H3O2) is the acid (HA), and sodium acetate (NaC2H3O2) dissociates to form acetate ions (C2H3O2-) which act as the conjugate base (A-).

The pKa of acetic acid is given as 1.75 x 10^-5. To calculate the ratio [A-]/[HA], we divide the concentration of the conjugate base (sodium acetate) by the concentration of the acid (acetic acid):

[A-]/[HA] = (0.164 M)/(0.225 M) ≈ 0.729

Now we can substitute the values into the Henderson-Hasselbalch equation:

pH = 1.75 x 10^-5 + log(0.729)

Using logarithmic properties, we can simplify the equation:

pH ≈ -4.76 + 0.863 ≈ 4.74

Therefore, the pH of the buffer solution is approximately 4.74.

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how many carbon atoms react in this equation? 2c4h10 13o2-> 8co2 10h20

Answers

In the equation 2C_4H_10 + 13O_2 -> 8CO_2 + 10H_2O, , a total of 16 carbon atoms react.

The equation represents the combustion of butane (C4H10) in the presence of oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). Each molecule of butane (C4H10) contains 4 carbon atoms. Since there are two molecules of butane (2C4H10) involved in the reaction, the total number of carbon atoms is 4 x 2 = 8.

On the product side, each molecule of carbon dioxide (CO2) contains 1 carbon atom. Since there are 8 molecules of carbon dioxide (8CO2) produced, the total number of carbon atoms in the carbon dioxide is 1 x 8 = 8.

Therefore, when we sum up the carbon atoms on both sides of the equation, we find that a total of 8 carbon atoms from the butane react with 8 carbon atoms in the carbon dioxide, resulting in a total of 16 carbon atoms involved in the reaction.

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Aspirin is a monoprotic acid called acetylsalicylic acid. Its foula is HC9​H7​O4​. A certain pain reliever was analyzed for aspirin by dissolving 0.149 g of the drug in water and titrating it with 0.0201MKOH solution. The titration required 15.06 mL of base. What is the percentage by weight of aspirin in the drug? % aspirin in the sample eTextbook and Media

Answers

The percentage by weight of aspirin in the drug is 73.86%.

To solve this question, we will use the formula: Percentage of aspirin in the sample = (molar mass of aspirin × equivalent mass of KOH × volume of KOH required × 100) / weight of the sample Firstly, let's calculate the molar mass of aspirin: C = 9 × 12.01 = 108.09H = 7 × 1.01 = 7.07O = 4 × 16.00 = 64.00Hence, the molar mass of aspirin = 108.09 + 7.07 + 64.00 = 179.16 g/mol

Now, let's calculate the equivalent mass of KOH:KOH reacts with 1 mole of aspirin, so its equivalent weight is equal to its molecular weight. The molecular weight of KOH = 39.10 + 16.00 + 1.01 = 56.11 g/mol Now, let's find the amount of KOH used in the reaction: Concentration of KOH = 0.0201 M Volume of KOH = 15.06 mL = 15.06 / 1000 = 0.01506 Ln(KOH) = C × V = 0.0201 M × 0.01506 L = 0.000302206 mol of KOH

Now, let's find the amount of aspirin in the sample: Number of moles of aspirin = (mass of aspirin) / (molar mass of aspirin) = 0.149 g / 179.16 g/mol = 8.32 × 10^-4 mol Finally, we can calculate the percentage by weight of aspirin in the drug: Percentage of aspirin in the sample = (molar mass of aspirin × equivalent mass of KOH × volume of KOH required × 100) / weight of the sample= (179.16 g/mol × 56.11 g/equiv × 0.000302206 equiv × 100) / 0.149 g= 73.86 %.

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please help solve with work
Complete each problem on separate paper. Must show correct problem solving protocol with each problem with analysis. 1. Convert. 00000567 {~mm} to yards. 2. 245,0000 {~mm}= h

Answers

1. To convert 0.00000567 mm to yards, follow these steps:

  Step 1: Convert mm to m.

  1 mm = 0.001 m

  0.00000567 mm = 0.00000567 x 0.001 m = 0.00000000567 m

 

  Step 2: Convert m to yards.

  1 m = 1.0936 yards

  0.00000000567 m = 0.00000000567 x 1.0936 yards = 0.0000000061980912 yards

 

  Therefore, 0.00000567 mm is equal to approximately 0.0000000061980912 yards.

 

2. To convert 2450000 mm to h, follow these steps:

  Step 1: Convert mm to m.

  1 mm = 0.001 m

  2450000 mm = 2450000 x 0.001 m = 2450 m

 

  Step 2: Convert m to h.

  1 m = 0.0001 h

  2450 m = 2450 x 0.0001 h = 0.245 h

 

  Therefore, 2450000 mm is equal to 0.245 h.

The final answers are:

1. 0.00000567 mm is equal to approximately 0.0000000061980912 yards.

2. 2450000 mm is equal to 0.245 h.

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What does the glycolysis pathway look like in a PK1 deficient
cell ?

Answers

The glycolysis pathway in a PK₁-deficient cell is altered, leading to impaired glucose metabolism.

In a PK₁-deficient cell, PK₁ (pyruvate kinase 1) enzyme activity is reduced or absent. PK₁ is an important enzyme in the final step of glycolysis, where it catalyzes the conversion of phosphoenolpyruvate (PEP) to pyruvate, generating ATP. Without functional PK₁, the conversion of PEP to pyruvate is compromised.

As a result, glycolysis is disrupted, leading to a decrease in the production of ATP and pyruvate. This can have various consequences for the cell, such as reduced energy production and altered metabolic flux. Additionally, the accumulation of upstream glycolytic intermediates, such as PEP and fructose-1,6-bisphosphate, may occur.

To compensate for the impaired glycolytic flux, alternative metabolic pathways may be upregulated, such as the pentose phosphate pathway or lactate fermentation. These pathways provide alternative routes for energy production and the regeneration of cofactors, but they may not be as efficient as glycolysis in generating ATP.

Overall, a PK₁-deficient cell exhibits a disrupted glycolysis pathway, leading to altered energy metabolism and potential metabolic adaptations to compensate for the deficiency.

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Read the passage and answer the related questions:
A buffer is an aqueous solution that resists changes in pH when acids or bases are added to it. A buffer solution is typically composed of a weak acid and its conjugate base. There are three major buffer systems that are responsible for regulating blood pH: the bicarbonate buffer system, the phosphate buffer system, and the plasma protein buffer system. Of the three buffer systems, the bicarbonate buffer system is arguably the most important as it is the only one that is coupled to the respiratory system.
Carbonic acid (H 2 CO 3 ) is a weak acid (pKa1=6.3, pKa2=10.3), and is foed when carbon dioxide combines with water in a reaction catalyzed by the enzyme carbonic anhydrase. In solution, carbonic acid is present in equilibrium with the bicarbonate ion via a simple proton transfer reaction. The equilibrium is largely controlled by the Le Châtelier's principle, which states that when stress is applied to a system in equilibrium, the reaction will shift in a direction that will reduce stress. For instance, a process that acidifies blood will be neutralized by the bicarbonate ions thus minimizing the change in pH. A process that alkalizes blood will be neutralized by the equilibrium concentration of carbonic acid. The chemical reaction describing the equilibrium between carbonic acid and bicarbonate is as follows:
CO 2 (g) + H 2 O(l) ⇌ H 2 CO 3 (aq) ⇌ HCO 3 - (aq) + H + (aq)
In a titration experiment, a buret is used to administer a known concentration of NaOH to a solution of carbonic acid. The pH of the solution is measured throughout the entire titration reaction using a pH meter. A titration curve is then generated relating the change in pH with respect to the volume of NaOH added to the solution. Figure 1 represents the titration curve that was obtained during the experiment.
Figure 1: Titration curve of a carbonic acid (H 2 CO 3 ) solution with a NaOH
Question 14
It can be inferred from the passage that carbonic acid is an example of which type of acid?
I. Arrhenius
II. Bronsted-Lowry
III. Lewis
Question 15
From the titration curve provided in the passage, at which pH range will a carbonic acid solution serve as a good buffer?
Group of answer choices
5.3 to 7.3 and 9.3 to 11.3
5.3 to 7.3 and 7.3 to 9.3
7.3 to 9.3 and 11.3 to 13.3
7.3 to 9.3 and 9.3 to 11.3
Question 16
From the titration curve provided in the passage, at which pH does sodium bicarbonate (NaHCO 3 ) predominate?
Group of answer choices
12.3
10.3
8.3
6.3
Question 17
Which of the following equations can be used to calculate the pH of the carbonic acid solution from any point along the titration curve to the left of point B?
Group of answer choices
pH = 6.3 + log [H 2 CO 3 / NaHCO 3 ]
pH = 8.3 + log [NaHCO 3 /H 2 CO 3 ]
pH = 6.3 + log [NaHCO 3 /H 2 CO 3 ]
pH = 8.3 + log [H 2 CO 3 / NaHCO 3 ]

Answers

Carbonic acid is a Bronsted-Lowry acid. A carbonic acid solution acts as a good buffer in the pH range of 5.3 to 7.3 and 9.3 to 11.3.

14: From the passage, it can be inferred that carbonic acid is an example of a (II) Bronsted-Lowry acid.

15: From the titration curve provided in the passage, a carbonic acid solution will serve as a good buffer in the pH range of (a) 5.3 to 7.3 and 9.3 to 11.3.

16: From the titration curve provided in the passage, sodium bicarbonate (NaHCO₃) predominates at a pH of (c) 8.3.

17: The equation that can be used to calculate the pH of the carbonic acid solution from any point along the titration curve to the left of point B is: (a) pH = 6.3 + log [H₂CO₃ / NaHCO₃]

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a solution contains al3 and co2 . the addition of 0.3932 l of 1.679 m naoh results in the complete precipitation of the ions as al(oh)3 and co(oh)2 . the total mass of the precipitate is 23.64 g . find the masses of al3 and co2 in the solution.

Answers

Mass of Al³⁺ in the solution: X grams

Mass of CO₂ in the solution: Y grams

To find the masses of Al³⁺ and CO₂ in the solution, we can use stoichiometry and the concept of limiting reagents. Here's how you can solve the problem:

Determine the balanced chemical equation for the reaction between Al³⁺ and CO₂ with NaOH. From the given information, we know that Al(OH)₃ and Co(OH)₂ are the precipitates formed. The balanced equation is:

2Al³⁺ + 3CO₂ + 6NaOH → 2Al(OH)₃ + 3CO(OH)₂ + 6Na⁺

Convert the volume of NaOH solution added (0.3932 L) to moles using the molarity (1.679 M):

Moles of NaOH = Volume (L) x Molarity (mol/L) = 0.3932 L x 1.679 mol/L

From the balanced equation, we see that the ratio of Al³⁺ to NaOH is 2:6 and the ratio of CO₂ to NaOH is 3:6. Therefore, the moles of Al³⁺ and CO₂ are:

Moles of Al³⁺ = (2/6) x Moles of NaOH

Moles of CO₂ = (3/6) x Moles of NaOH

Convert the moles of Al³⁺ and CO₂ to grams using their molar masses:

Mass of Al³⁺ = Moles of Al³⁺ x Molar mass of Al³⁺

Mass of CO₂ = Moles of CO₂ x Molar mass of CO₂

Finally, calculate the mass of the precipitate (Al(OH)₃ + CO(OH)₂) using the given total mass (23.64 g):

Mass of precipitate = Mass of Al(OH)₃ + Mass of CO(OH)₂

By following these steps, you should be able to find the masses of Al³⁺ and CO₂ in the solution. Remember to use the molar masses of Al³⁺ and CO₂ to convert moles to grams.

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LO4_FlaceValuel_H2 doc 4. Using the same BMU that you used in Fart 1 for the base-five numeration system, construct a set of theasuring units for a base-three numeration system. Make a place value chart that records your set. 5. Using your measuring units from problem 114 , build the quantity represented by the base-three numeral 121 three 6. Using your measuring units from problem #4, build the quantity represented by the base-three numeral 100 three: 7. Explain why 14 five and 100 three represent the same amount. (Compare your answers to problems #3 and #6.

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In the base-three numeration system, 100 represents one group of three, zero twos, and zero ones. In both cases, the numeral represents the same value or amount of objects, which is fourteen.

4. A set of measuring units for the base-three numeration system using the same BMU that was used in Fart 1 for the base-five numeration system can be constructed.

The chart below shows the place value chart that records the set of units.

[tex]\begin{array}{|r|r|} \hline \text{Place Value}&\text{Base-Three Value}\\ \hline 243&2\\ \hline 81&1\\ \hline 27&0\\ \hline 9&2\\ \hline 3&1\\ \hline 1&0\\ \hline \end{array}[/tex]

5. The base-three numeral 121 can be built using the measuring units from problem #4. The number represents the quantity three hundred forty-two.

6. The quantity represented by the base-three numeral 100 is two hundred forty-one.

7. The value of 14 five is the same as the value of 100 three because in both cases the value of the numeral is fourteen. In the base-five numeration system, 14 represents one group of five and four ones.

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if
you could explain the answer, thank you!
2. Fill in the boxes with the letter of the functional groups present in the following molecule: A) 1^{\circ} {Alcohol} B) 2^{\circ} Alcohol C) 3^{\circ} {Alcoh

Answers

A functional group in organic chemistry refers to an atom or group of atoms within a molecule that provides a specific chemical and physical property to that molecule. The following are functional groups and their descriptions:

Functional group Description Example Alcohol A functional group that includes a hydroxyl (-OH) group attached to a carbon atom.R-OH (R represents a carbon chain)Carboxyl A functional group that includes a carbonyl (-C=O) group and a hydroxyl (-OH) group attached to the same carbon atom .R-COOH (R represents a carbon chain)Amine A functional group that includes a nitrogen atom attached to one or more carbon atoms.R-NH2 (R represents a carbon chain)Aldehyde

A functional group that includes a carbonyl (-C=O) group attached to a carbon atom and a hydrogen (-H) atom attached to the same carbon atom .R-CHO (R represents a carbon chain)Ketone A functional group that includes a carbonyl (-C=O) group attached to a carbon atom that is connected to two other carbon atoms-CO-R (R represents a carbon chain)Ether functional group that includes an oxygen atom connected to two carbon atoms'-O-R (R represents a carbon chain)Halide.

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2. triphenylmethanol can also be synthesized by reaction of phenylmagnesium bromide (grignard reagent) with ethyl benzoate. draw the mechanism for this reaction using the curved-arrow notation. show lone pairs of electrons and charges.

Answers

Grignard reagent (phenylmagnesium bromide) reacts with ethyl benzoate to form triphenylmethanol, following nucleophilic addition and protonation.

The synthesis of triphenylmethanol from phenylmagnesium bromide (Grignard reagent) and ethyl benzoate involves a nucleophilic addition-elimination reaction. Here is the mechanism for this reaction using curved-arrow notation:

Step 1: Formation of the Grignard Reagent

Phenylmagnesium bromide (C₆H₅MgBr) is formed by the reaction of phenyl bromide (C₆H₅Br) with magnesium (Mg).

C₆H₅Br + Mg → C₆H₅MgBr

Step 2: Nucleophilic Addition

The oxygen atom in ethyl benzoate (PhCO₂Et) acts as a nucleophile and attacks the electrophilic carbon of the phenylmagnesium bromide.

C₆H₅MgBr + PhCO₂Et → C₆H₅C(O)OCH₂CH₃MgBr

Step 3: Rearrangement

The alkoxide intermediate undergoes rearrangement to form a phenylcarbinol intermediate.

C₆H₅C(O)OCH₂CH₃MgBr → C₆H₅CH(OH)OCH₂CH₃MgBr

Step 4: Protonation

The phenylcarbinol intermediate is protonated by water, which leads to the formation of triphenylmethanol (Ph₃COH) and magnesium bromide.

C₆H₅CH(OH)OCH₂CH₃MgBr + H₂O → Ph₃COH + MgBrOH + CH₃CH₂OH

The overall reaction can be summarized as:

Phenylmagnesium bromide + Ethyl benzoate → Triphenylmethanol + Magnesium bromide + Ethanol

Please note that the reaction conditions and solvent choice can vary, but the general mechanism remains the same.

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What happens when you mix neutral red with HCl and hexane?
Please use organizational chart to explain!
Thanks

Answers

When neutral red is mixed with HCl and hexane, the following reactions and phenomena occur:

1. Mixing Neutral Red with HCl:

- Neutral red (NR) is a pH indicator that changes color depending on the acidity of the solution.

- HCl (hydrochloric acid) is a strong acid.

- When NR is mixed with HCl, the acidic nature of HCl causes the solution to turn red.

- The red color indicates the acidic pH range of the solution.

2. Mixing Neutral Red-HCl Solution with Hexane:

- Hexane is an organic solvent that is immiscible with water.

- When the NR-HCl solution is mixed with hexane, a separation occurs due to the immiscibility of hexane with the aqueous solution.

- The hexane forms a distinct layer on top of the aqueous solution.

- The NR-HCl solution retains its red color in the aqueous layer, while the hexane layer remains colorless.

Overall, mixing neutral red with HCl results in a red-colored acidic solution, and when hexane is added, the hexane layer separates from the aqueous solution, with the red color remaining in the aqueous layer.

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functional group has a sharp dagger-like peak at about 2,250 cm −1
? Amine Aldehyde Nitrile Ketone Alcohol STION 23 hic syntheses often require the heating of a reaction for a long period of time. Which of the following is not an ple a valid reason for heating a reaction for a long period of time. chieving complete dissolution of stuborn solutes avoring theodynamic products icreasing reaction rates

Answers

The following that is not a valid reason for heating a reaction for a long period of time is (D), decreasing reaction rates.

Heating a reaction will typically increase reaction rates, so there is no reason to heat a reaction for a long period of time in order to decrease reaction rates.

The other three options are all valid reasons for heating a reaction for a long period of time. Stubborn solutes may not dissolve easily in cold solvents, so heating the solvent can help to dissolve the solute.

Favoring thermodynamic products means that the reaction will proceed towards the products that are more stable at the given temperature. Increasing reaction rates means that the reaction will happen faster, which can be beneficial if the reaction is taking a long time to complete.

Therefore, (D) decreasing reaction rates is the correct answer.  

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Complete question :

Which of the following is not a valid reason for heating a reaction for a long period of time?

(A) Achieving complete dissolution of stubborn solutes.

(B) Favoring thermodynamic products.

(C) Increasing reaction rates.

(D) Decreasing reaction rates.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                            

A piece of glass has specific gravity of 2.55 and weighs 69.62
kilograms. What will it weigh (in kg) when it is submerged in
water? Hint: consider what the meaning of buoyancy is.

Answers

When the piece of glass is submerged in water, it will weigh approximately 47.14 kilograms.

The specific gravity of a substance is the ratio of its density to the density of a reference substance. In this case, the specific gravity of the glass is 2.55, which means it is 2.55 times denser than the reference substance, which is usually water.

To determine the weight of the glass when submerged in water, we need to consider the concept of buoyancy. Buoyancy is the upward force exerted on an object submerged in a fluid, which opposes the force of gravity. When an object is immersed in a fluid, it displaces an amount of fluid equal to its own volume.

Since the glass has a specific gravity greater than 1, it will sink in water. However, the buoyant force will act on the glass, reducing the net force of gravity. The buoyant force is equal to the weight of the water displaced by the submerged glass.

To find the weight of the glass when submerged in water, we need to calculate the weight of the water displaced by the glass. The weight of the water displaced is equal to the volume of the glass multiplied by the density of water (which is approximately 1000 kg/m³).

We can calculate the volume of the glass by dividing its weight by its density, which is equal to the specific gravity multiplied by the density of water. Then, we can calculate the weight of the water displaced by the glass by multiplying the volume by the density of water.

Finally, to find the weight of the glass when submerged, we subtract the weight of the water displaced from the original weight of the glass.

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The solubility of He in water at 520.2 torr is 0.001014 {~g} / {L} . What is Henry's Law constant (M/atm) for He in water? Key Concept: Henry's law states that the solubility

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The solubility of He in water at 520.2 torrs is 0.001014 {~g} / {L} .

We are given the following information in the question: Solubility of He in water at 520.2 torr = 0.001014 g/L.The Henry's Law constant (M/atm) for He in water needs to be calculated. Therefore, we can use Henry's Law equation to calculate the same. The Henry's Law equation is given as C = kH . PHence, kH = C/Pwhere,kH = Henry's Law constant (M/atm)C = Concentration of the gas in the solution. P = Partial pressure of the gas above the solution. To convert the given solubility value to concentration we can divide by the molecular mass of He, which is 4 g/mol.0.001014 g/L ÷ 4 g/mol = 2.535 × 10⁻⁴ M/LWe know that the given partial pressure of He in torr is 520.2 torr. Let us convert it to atm.1 torr = 0.00131579 atm520.2 torr = 0.684 atm. Substitute these values in the formula of Henry's Law constant:kH = C/PkH = 2.535 × 10⁻⁴ M/L ÷ 0.684 atm ≈ 3.71 × 10⁻⁴ M/atm.Therefore, the Henry's Law constant (M/atm) for He in water is approximately 3.71 × 10⁻⁴ M/atm.

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For the diprotic weak acid H2​ A,Ka1​=3.4×10−6 and Ka2​=5.2×10−9. What is the pH of a 0.0650M solution of H2​ A ? pH : What are the equilibrium concentrations of H2​ A and A2− in this solution? [H2​ A]: [A2−]=

Answers

Given information: Ka1​=3.4×10−6 and Ka2​=5.2×10−9H2A ⇌ H+  + HA-  

Ka1= [H+][HA-] / [H2A]HA- ⇌ H+  + A2-   ;

Ka2= [H+][A2-] / [HA-]

At equilibrium, [H2A] = [H2A]0 - x;  [HA-] = [HA-]0 + x1; [A2-] = [A2-]0 + x2;  [H+] = x;  

We know, [H2A]0 = [HA-]0 = [A2-]0 = 0.0650M

Ka1​= [H+][HA-] / [H2A];

Ka2​= [H+][A2-] / [HA-]

We have to find out pH and equilibrium concentrations of H2​ A and A2− in the solution.

To find pH: Ka1​= [H+][HA-] / [H2A]3.4 × 10^-6 = x * x1 / (0.065 - x).....

(i)Ka2​= [H+][A2-] / [HA-]5.2 × 10^-9 = x * x2 / x1.....

(ii)Let's make an assumption that the concentration of x in the equilibrium constant for the 2nd step is negligible compared to the initial concentration of 0.0650 M so we can write (x1 - x) ≈ 0.0650 From

(i), 3.4 × 10^-6 = x * x1 / (0.0650)

Now, x = [H+] = 7.84 × 10^-4

Substitute x in (i)3.4 × 10^-6 = 7.84 × 10^-4 * x1 / (0.0650 - 7.84 × 10^-4)

Hence, x1 = [HA-] = 0.0387 MFrom (ii), 5.2 × 10^-9 = 7.84 × 10^-4 * x2 / 0.0387

Now, x2 = [A2-] = 1.12 × 10^-10Hence, pH = - log [H+] = 3.11

Equilibrium Concentration: [H2A] = [H2A]0 - x = 0.0650 - 7.84 × 10^-4 = 0.0642 M[A2-] = 1.12 × 10^-10 M[HA-] = 0.0387 M

Note: All these values have been rounded off to 3 significant figures.

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The number of noal modes of vibration and the number of vibrations giving rise to absorptions exhibited in the IR spectrum of SO3

are, respectively: 3 and 3 3 and 2 4 and 3 4 and 4

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Sulfur trioxide (SO3) has four atoms, including three oxygen atoms and one sulfur atom. The vibrations of the atoms in SO3, as well as the number of noal modes of vibration and the number of vibrations that give rise to absorptions observed in the infrared (IR) spectrum of SO3 are known to scientists.

The number of noal modes of vibration and the number of vibrations giving rise to absorptions exhibited in the IR spectrum of SO3 are, respectively: 4 and 4.

Normal modes of vibration, also known as normal coordinates, are a set of specific vibrational movements for a molecule that result in the entire molecule vibrating as a whole. It is typical for molecules to have multiple normal modes of vibration, and each mode of vibration corresponds to a specific energy. As a result, infrared absorption spectra can be used to identify the normal modes of vibration of a molecule.

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A. (3 pts) Mercury is a liquid metal with a density of 13.56 {~g} / {mL} at 25^{\circ} {C} . Deteine the volume (in mL) occupied by 845 {~g} of mercury.

Answers

The volume occupied by 845 g of mercury is 62.335 mL.

To determine the volume occupied by 845 g of mercury, we can use the density formula:

Density = Mass / Volume

Rearranging the formula, we can solve for volume:

Volume = Mass / Density

Given:

Mass of mercury = 845 gDensity of mercury = 13.56 g/mL

Substituting these values into the formula:

Volume = 845 g / 13.56 g/mL

Calculating the volume:

Volume = 62.335 mL

Therefore, 845 g of mercury occupies a volume of 62.335 mL.

The correct format of the question should be:

A. Mercury is a liquid metal with a density of 13.56 g/mL at 25°C. Determine the volume (in mL) occupied by 845g of mercury.

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You need to make an aqueous solution of 0.222M iron(III) chloride for an experiment in lab, using a 250 mL volumetric flask. How much solid iron(III) chloride should you add? grams

Answers

A 250 mL volumetric flask is needed to generate a 0.222M iron(III) chloride aqueous solution for a scientific experiment. Therefore, you should add approximately 9.04 grams of solid iron(III) chloride to make a 0.222 M aqueous solution in a 250 mL volumetric flask.

To calculate the amount of solid iron(III) chloride needed, we can use the formula:

Amount of solid (in grams) = Concentration (in moles/L) × Volume (in L) × Molar mass (in g/mol)

Given:

Concentration = 0.222 M

Volume = 250 mL = 0.25 L

Molar mass of iron(III) chloride = 162.2 g/mol

Using the formula:

Amount of solid (in grams) = 0.222 mol/L × 0.25 L × 162.2 g/mol

Calculating the result:

Amount of solid (in grams) = 9.0393 g

Therefore, you should add approximately 9.04 grams of solid iron(III) chloride to make a 0.222 M aqueous solution in a 250 mL volumetric flask.

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Animals in an experiment are to be kept under a strict diet. Each animal should receive 25 grams of protein and 5grams of fat. The laboratory technician is able to purchase two food mixes: Mx A has 10% protein and 6% fat; mix B has 50% protein and 5% fat. How many grams of each mix should be used to obtain the right diet for one animal? One animar's diet should consist of grams of MaA.

Answers

250 grams of Mix A (MxA) should be used to obtain the right diet for one animal.

To determine the number of grams of Mix A (MxA) needed to obtain the right diet for one animal, let's assume that x represents the number of grams of MxA used.

The protein content in MxA is 10%, which means 0.10x grams of protein will be obtained from MxA.

The fat content in MxA is 6%, which means 0.06x grams of fat will be obtained from MxA.

Since the desired diet for one animal should consist of 25 grams of protein and 5 grams of fat, we can set up the following equation based on the protein content:

0.10x = 25

Solving for x:

x = 25 / 0.10

x = 250 grams.

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