Aiden and Haisem are going to eat the same amount of hamburgers and fries, but from different restaurants. Aiden goes to Burger King and spends $4.75. Each burger costs $1.25 and fries cost $0.50. Haisem spends $6.48 at McDonalods. Each burger costs $1.50 and fries cost $0.99. How many burgers and fries did Aiden and Haisem each buy?

Answers

Answer 1

Answer:

the burgers be 3 and fries be 2

Step-by-step explanation:

The computation is shown below:

Let us assume burgers be x

And, the fries be y

Now according to the questiojn

1.25x + 0.50y = $4.75

1.50x + 0.99y = $6.48

Now multiply by 1.2 in the first equation

1.50x + 0.6y = $5.70

1.50x + 0.99y = $6.48

-0.39y = -0.78

y = 2

Now put the value of y in any of the above equation

1.25x + 0.50(2) = $4.75

x = 3

Hence, the burgers be 3 and fries be 2


Related Questions

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answer:

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Mark brainliest if you want<3

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Answers

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Answers

Answer:

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Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

|Absolute Value| - makes any negative number positive

Step-by-step explanation:

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Step 2: Evaluate

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468 raffle tickets for 52
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Answers

Answer:

9

Step-by-step explanation:

you divide 468 by 52

468/52 = 9

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Step-by-step explanation:

468/52 = 9 tickets per person

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