Ahely' brother rode beide her for everal minute. During thi time wa he moving relative o Ahley?

Answers

Answer 1

assuming they were moving at the same speed and started riding at the same position and time, then no, her brother was not moving relative to ashley.


Related Questions

Sound 1 has an intensity of 40.0 W/m^2 . Sound 2 has an intensity level that is 2.0 dB greater than the intensity level of sound 1.
What is the intensity of sound 2?
l2= ? W/m^2

Answers

The intensity level of sound 2 is 63.386 W/m².

Intensity of sound 1 = 40.0 W/m²

Intensity of sound 2 = 2.0 dB

We know that I₁ = 10⁻¹² W/m²

Intensity level of sound 2 =

= Using the equation of the sound level intensity

= Iₓ = 10log (I/I₁)

= Iₓ = 10 log(40/ 10⁻¹²)

= Iₓ = 136.02 dB

Given that intensity of sound 2 is greater than sound 1 by 2.0 dB

Thus,

= Iₙ = 136.02 + 2.0

=  Iₙ = 138.02 dB

To calculate intensity of sound 2 =

= I₂ = 10log(Iₙ / 10⁻¹²)

= I₂ = 63.386 W/m²

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now the switch for coil 1 has been closed for a long time. which direction is the induced current in coil 2 through the current meter while the switch for coil 1 stays closed?.

Answers

This causes a force to be exerted on the electrons in coil 2, resulting in induced current flowing in the opposite direction.

What is force?
A force is indeed an influence that can alter an object's motion according to physics. A force may cause an object to mass to accelerate when it changes its velocity, such as when it moves away from rest. An intuitive way to describe force is as a push or even a pull. A force is a vector quantity because it has both direction and magnitude. It is calculated using the newton SI unit (N). Force is denoted by the letter F. (formerly P). The net force acting on an object seems to be equal to the speed that its momentum changes over time, according to Newton's second law in its original formulation.

The induced current in coil 2 will be in the opposite direction as the current in coil 1. This is because when the switch for coil 1 is closed, current will start flowing through coil 1. This will create a magnetic field around coil 1, which intersects with the magnetic field around coil 2. This causes a force to be exerted on the electrons in coil 2, resulting in induced current flowing in the opposite direction.

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an outside loudspeaker (considered a small source) emits sound waves with a power output of 102 w. (a) find the intensity 12.4 m from the source.

Answers

The calculated value is 5.6 m. Much more frequently than sound intensities in watts per square meter, sound intensity levels are expressed in decibels (dB).

Both the scientific literature and the public media use decibels as their preferred measurement unit. The rationale behind this decision of units has to do with how we hear. Noise exposure is harmful to the hearing, and it is normal for musicians to suffer from hearing loss that is so severe that it affects their ability to play. Sound intensity, a term that applies to all noises, whether or not they are heard, is the pertinent physical quantity.

We are given Δp, so we can calculate I using the equation I=(Δp)22ρv . Using I , we can calculate β straight from its definition in β (dB)=10 log10(II0) β (dB)=10 log10(II0) .

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The internal energy within a system associated with the motion of particles and that can be added to a substance is called _____. (1 point).

Answers

Answer: The internal energy within a system associated with the motion of particles and that can be added to a substance is called kinetic energy.

Reason:

Internal energy U of a system or a body with well-defined boundaries is the total of the kinetic energy due to the motion of molecules and the potential energy associated with the vibrational motion and electric energy of atoms within molecules.

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a ball travels in uniform circular motion with a period of 2 seconds. what is the tangential velocity of the object if it is moving in a circle of radius 2 m?

Answers

The tangential velocity of the object if it is moving in a circle of radius 2 m is

6.28 m/s

It is given that

time taken to move in circle = 2 seconds

radius of circle = 2m

Tangential velocity is equal to the circumference of the circle divided by the time it takes to make one full rotation: 2*pi*r/t

Tangential velocity = 2πr/t

= 2 x 3.14 x 2/2 = 6.28 m/s

Hence, tangential velocity of the object if it is moving in a circle of radius 2 m is 6.28 m/s

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a 1000kg car engine can accelerate the car from 0 to 27m/s in 4.3 seconds. find the power rating of the engine in watts and kilowatts

Answers

The power rating of the engine of a 1000 kg car that can accelerate the car from 0 to 27m/s in 4.3 seconds in watts is 84767 W and kilowatts is 84.767 KW

a = ( v - u ) / t

a = Acceleration

v = Final velocity

u = Initial velocity

t = Time

v = 27 m / s

u = 0

t = 4.3 s

a = ( 27 - 0 ) / 4.3

a = 6.279 m / s²

F = m a

F = Force

m = Mass

m = 1000 kg

F = 1000 * 6.279

F = 6279 N

s = u t + 1 / 2 a t²

s = 0 + ( 1 / 2 * 6.279 * 4.3² )

s = 58.1 m

W = F s

W = Work one

s = Displacement

W = 6279 * 58.1

W = 364496 J

P = W / t

P = Power

P = 364496 / 4.3

P = 84767 W

P = 84.767 KW

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an 8.0-newton wooden block slides across a horizontal wooden floor at constant velocity. what is the magnitude of the force of kinetic friction between the block and the floor?

Answers

Answer:

2.4 n

Explanation:

The force of kinetic friction between the block and the floor is given by:

where

is the coefficient of kinetic friction

N is the normal reaction of the floor against the block

For a horizontal surface (as in this case), the normal reaction is equal to the weight of the block, so . For wood-wood contact, the coefficient of kinetic friction is approximately . Therefore, the force of kinetic friction between the block and the

two 20.-nwewton forces act concurrently on an object. What angle between these forces will produce a resultant force with the greatest magnitude?

Answers

These forces will produce a resultant force with the greatest magnitude when angle between them is 0° .

What is force?

When an object with mass is pushed or pulled, it changes its velocity, according to the definition of force in physics.

Force is an external agent that has the power to alter a body's resting or moving condition. It has a size and a movement. The direction of the force is referred to as the force's direction, and the application of force is the place at which the force is applied.

Given that: two 20. newton forces act concurrently on an object.

If the angle between the forces is α then resultant force be:

= √(20² + 20² +2.20.20cosα)

Hence, these forces will produce a resultant force with the greatest magnitude when angle between them isand the  the greatest magnitude of resultant force be 40 N.

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As you watch the video, notice that the size of the tidal bulges varies with the Moon's phase, which depends on its orbital position relative to the Sun. Which of the following statements accurately describes this variation?
Low tides are lowest at both full moon and new moon.
Low tides are highest at both full moon and new moon.
High tides are highest at full moon and lowest at new moon.
Low tides are highest at full moon and lowest at new moon.
High tides are highest at both full moon and new moon.
High tides are highest at first- and third-quarter moon.

Answers

The size of the tidal bulges increases as the Moon moves closer to the Earth in its orbit, when it is in the new moon or full moon phase, and decreases as it moves away from the Earth in its orbit, when it is in the first quarter or third quarter phase.

What is tidal bulges?
The fluid and moveable ocean water is drawn towards the moon by the gravitational influence between the moon as well as the Earth. The ocean closest to the moon experiences a "bulge" as a result, as the Earth rotates, the affected waters' locations shift. Imagine the moon as just a magnet drawing the water to it. The force of intertia, which tends to keep an object moving inside a straight line, opposes this motion of the water in the direction of the moon. Our oceans' motion is balanced by this, but since the gravitational pull seems to be stronger, the resulting force also creates our tides.

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what is the difference between the pressure on the bottom of a pool and the pressure on the water surface?

Answers

The difference between the pressure on a pool's bottom and the pressure on the water's surface is approximately 14 feet or 168 inches deep. Fresh water has a density of 1 psi per 27.7 inches of depth.

What is a good instance of pressure?

Holding a knife against a piece of fruit will demonstrate pressure in an easy way. It won't cut the surface of the fruit if you press the flat part of the knife against it. A sizable area is affected by the force (low pressure).

What are the many sorts of pressure?

The force applied physically to an object is referred to as pressure. Per unit area, the force is applied perpendicularly to the surfaces of the objects. The fundamental pressure formula is F/A. (Force per unit area). The Pascal unit of pressure (Pa). The four different types of pressure are gauge, absolute, atmospheric, and differential.

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There are two types of waves: mechanical and electromagnetic. Microwaves, infrared waves, and radio waves are examples of electromagnetic waves. Which claim is true about the speed of an electromagnetic wave?.

Answers

Mechanical waves and electromagnetic waves are the two major modes of energy transportation on Earth. Air and water waves produced by sound are examples of seismic wave.

Electromagnetic waves, as opposed to physical phenomena, may move across empty space. This suggests that pulses may travel through void spaces as well as through solid substances like air and rock.
Since their wavelengths are measured in millimeters, microwaves are shorter than radio waves. Microwaves are used in radar that aids in weather forecasting, food preparation, and information transmission. Because they can pass through smoke, clouds, and light rain, microwaves are useful for communication.

Infrared waves lie between microwaves and visible light. There are two subcategories of infrared waves: near infrared and far infrared. The waves with wavelengths closest to visible light are known as near infrared waves. Your television remote uses these infrared radiation to change channels.

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if an astronaut knocks a wrench off the outside of the space shuttle (while in space) while she is doing a repair job, the wrench will continue moving in the same direction. which of newton's laws of motion will the wrench demonstrate?

Answers

The Newton's first law is demonstrated over here.

If the wrench is thrown then that wrench will keep on moving in the space.

As we all no space has no gravity and since there is no gravity, hence, no force is applied on that body.

The wrench will move freely in the space and will continue to move in same direction until there is some external force is applied to stop or change its direction.

This shows that over here the Newton's first law is applied.

The Newton's first law states that the body will continue to be in the same state or motion and will not change until the external force is applied on it.

This Newton's first law is also known as law of inertia.

Therefore, the wrench will continue to move in the same direction under the influence of Newton's first law.

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four resistors of 3.40 ohms, 6.54 ohms, 8.32 ohms, and 1.34 ohms are connected in parallel with a 12.0 v battery. find the total resistance, in ohms, of the circuit.

Answers

The total resistance of the four resistors connected in parallel is 0.762 ohms.

How to calculate the total resistance of resistors connected in parallel?

To calculate the total resistance of the four resistors connected in parallel, we use the formula below.

Formula:

1/R' = 1/R₁+1/R₂+1/R₃+1/R₄............ Equation 1

Where:

R' = Total resistance of the resistors in parallelR₁, R₂, R₃, R₄ = The resistance of the four resistors in parallel.

From the question,

Given:

R₁ = 3.4 ohmsR₂ = 6.54 ohmsR₃ = 8.32 ohmsR₄ = 1.34 ohms

Substitute these values into equation equation 1

1/R' = 1/3.4+1/6.54+1/8.32+1/1.341/R' = 0.294+0.153+0.12+0.7461/R' = 1.313R' = 1/1.313R' = 0.762 ohms

Hence, the total resistance is 0.762 ohms.

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A barrel contains a 0.120-m layer of oil floating on water that is 0.250 m deep. The density of the oil is 600 \mathrm{kg} / \mathrm{m}^{3}600kg/m^3. (a) What is the gauge pressure at the oil–water interface? (b) What is the gauge pressure at the bottom of the barrel?

Answers

The gauge pressure at the oil-water interface and at the bottom of the barrel is 705.6 Pa and 3155.6 Pa.

The barrel contains 0.10m of oil and floating on water that is 0.250mm deep.

The density of the oil is given to be 600 kg/m³.

a) The gauge pressure at the oil water interface is given by,

P = pgh

Where,

p is density of oil and h is the hieght of the oil,

Putting values,

P = 0.120 x 600 x 9.8

P = 705.6 Pa.

So, thr pressure at oil-water interface is 705.6 Pa.

(b) The pressure at the bottom of the barrel can be found as,

P = pgh + pxH

Where,

H is the height of the water and x is the density of water,

Assigning value,

P = 705.6 + 1000 x 9.8 x 0.250

P = 705.6 + 2450

P = 3155.6 Pa.

So, the pressure at the bottom of the barrel is 3155.6 Pa.

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Carefully examine a bulb. Two wires extend from the filament of the bulb into the base. You probably cannot see into the base, however, you should be able to make a good guess as to where the wires are attached. Describe where the wires attach. Explain based on your observations in parts A-C. On the basis of the observations that we have made, we will make the following assumptions: 1. A flow exists in a complete circuit from one terminal of the battery, through the rest of the circuit, back to the other terminal of the battery, through the battery and back around the circuit. We will call this flow electric current. 2. For identical bulbs, bulb brightness can be used as an indicator of the amount of current through that bulb: the brighter the bulb, the greater the current. C. We may think of a bulb as presenting an obstacle, or resistance, to the current in the circuit. 1. Thinking of the bulb in this way, would adding more bulbs in series cause the total obstacle to the flow, or total resistance, to increase, decrease, or stay the same as before? 2. Formulate a rule for predicting how the current through the battery would change (i.e., whether it would increase, decrease, or remain the same) if the number of bulbs connected in series were increased or decreased.

Answers

1)Now as we increase more bulb in series n increase to (n+1),so the total resistance of the circuit increases.

2)Current increases if number of bulb in series decreases.

Equivalent of the circutes

R=∑P=nn

so resistence increases

i=V/R=V/nn

current i'=V/n'R

i'/i=n/n'

since n'>n

i'<i

so current increases

Resistance is the degree to which a substance obstructs or opposes an electric current. Electron flow is referred to as electric current. To better understand resistance, imagine how difficult it would be for a person to move from one shop to another in a crowded market. The opposition a substance provides to the flow of electrical current is referred to as resistance. The capital letter R is used to symbolize it. The ohm, sometimes written as a word and sometimes represented by the uppercase Greek letter omega, is the commonly used unit of resistance.

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if a river has an average width of 15 m, an average depth of 5 m, and is flowing with a velocity of 2 m/s, what is its discharge?

Answers

According to the given statement a river has an average  3 * 10⁵ W  is its discharge.

What is velocity definition with example?

The scalar metric of speed and direction of motion is known as velocity. The speed that an object goes in one side is known as its velocity. Speed may be used to calculate both the vehicle speed traveling north just on main freeway and the velocity of a explosion bursting in space.

Briefing:

Water's speed is 2 m/s.

Flow area = 5m x 15m = 75m²

Water has a density of 1000 kg/m³

The volume of water flowing per second in the continuity equation is written as v=Av.

Hence, mass of water m=vρ=Avρ

K.E. = 1/2 mv² = 1/2 Avρ²

K.E.  = 1/2 Avρ³

ρ =  1/2 Avρ³

ρ  = 1/2 * 75 * (2)³ * 1000

ρ = 3 * 10⁵ W

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PLEASE HELP WILL MARK BRAINLIEST IF YOU EXPLAIN HWK YOU GOT THE ANSWER!!!!

Answers

Answer:

A A A A. a. a a a a a a a

Explanation:

a is the answer

which of the following was originally classified as a nebula? a. orion nebula b. hercules globular star cluster c. andromeda galaxy d. ring nebula e. pluto

Answers

The correct option is (c) andromeda galaxy as it was originally classified as nebula.

A nebula is a distinctively luminous region of the interstellar medium, which is mainly made up of of cosmic dust, neutral, neutrally ionised, or molecular hydrogen. Nebulae are usually areas where stars develop.

Initially, any diffused astronomical object, including galaxies outside the Milky Way, was referred to as a "nebula."

Before Vesto Slipher and Edwin Hubble revealed the real nature of galaxies in the early 20th century, the Andromeda Galaxy, for instance, was originally known as the Andromeda Nebula.

So, Andromeda Galaxy was originally classified as nebula.

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in the figure, unpolarized light with an intensity of 28.0 w/m^2 is sent into a system of four polarizing sheets with polarizing directions at angles

Answers

Intensity of light is a measurement of the amount of power either emitted or reflected by a source, and it can be calculated using either the total wave output, luminosity, or brightness. passing through polarized sheets

How to calculate intensity of light passing through polarized sheet ?

The intensity of unpolarized light , Iⁿ = 28 W/m²

The intensity of light passing through, I¹= 0.5 × Iⁿ

I¹ = 14 W/m²

The intensity of light passing through the second polarizer , I² = I¹ × (cos(theta1 + 90 - theta2) )²

I² = 14 × cos^2(40 + 90 - 20) W/m²

I² = 1.64 W/m²

The intensity of light passing through the third polarizer , I³ = I²× (cos(180 - theta2 - theta1) )²

I³ = 1.64 × cos^2(180 - 20 - 20) W/m²

I³= 0.962 W/m²

The intensity of light passing through the fourth polarizer , I⁴= I³ ×(cos(theta3 + 90 + theta4) )²

I⁴ = 0.962 * cos^2(28 + 90 + 20) W/m²

I⁴ = 0.53 W/m²

The intensity of the light that emerges from the system is 0.53 W/m²

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The supplied statement states that perhaps the system's light output has a 0.53 W/m² intensity.

What does intensity mean according to science?

The rate at which a wave moves over just a substrate in a given amount of time and space is referred to as its intensity. It is additionally equal to the wave speed times the power density. It is commonly evaluated in Watts per square meter. The intensity of a beam depends on its height and power.

Briefing:

Here,

The intensity of unpolarized light , I0 = 28 W/m²

The brightness of the light that comes through I1 = 0.5 * I0

I1 = 14 W/m²

Light output through to the second polarizer, measured in intensity,

I2 = I1 * (cos(∅1 + 90 - ∅2) )²

I2 = 14 * cos²(40 + 90 - 20) W/m²

I2 = 1.64 W/m²

Light output through the third polarizer, in terms of intensity I3 = I2 * (cos(180 - ∅2 - ∅1) )²

I3 = 1.64 * cos²(180 - 20 - 20) W/m²

I3 = 0.962 W/m²

The fourth polarizer's ability to intensify light,

I4 = I3 * (cos(∅3 + 90 + ∅4) )²

I4 = 0.962 * cos²(28 + 90 + 20) W/m²

I4 = 0.53 W/m²

The process delivers sunlight that has a 0.53 W/m² intensity.

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The complete question is-

In the figure, unpolarized light with an intensity of 28.0 W/m2 is sent into a system of four polarizing sheets with polarizing directions at angles θ1 = 40.0˚, θ2 = 20.0˚, θ3 = 20.0˚, and θ4 = 28.0˚, What is the intensity of the light that emerges from the system?

when a submarine dives to a depth of 120 m, to how large a total pressure is its exterior surface subjected? the density of seawater is about 1.03 g/cm3.

Answers

Data provided in the question:

Initial depth of the submarine, d = 120 m

Density of water, ρ = 1.03 kg/m³

Now,

Pressure due to water = ρgh

here,

g is the acceleration due to gravity = 10 m/s²

h = height of water above

So,

Increase in pressure = ρgD - ρgd

= ρg(D - d)

= 1.03 × 10 × (120)

= 1236 Pa

Therefore, the total pressure of the submarine is 1236 Pa.

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you are the science officer on a visit to a distant solar system. prior to landing on a planet you measure its diameter to be 1.8 × 107 m and its rotation period to be 22.3 hours. you have previously determined that the planet orbits 3.2 × 1011 m from its star with a period of 402 earth days. once on the surface you find that the acceleration due to gravity is 37.8 m/s2. what are the mass of (a) the planet and (b) the star? (g

Answers

The mass of the planet and star is [tex]2.4 *10^{25}[/tex] kg and [tex]1.2 * 10^{31}[/tex] kg respectively.

Acceleration due to gravity is the force experienced per unit mass of an object due to gravitational force and it is given by:

[tex]a = \frac{GM_{planet} }{r^{2} }[/tex]

[tex]19.5 =\frac{6.67 * 10^{-11} * M_{planet} }{(0.9 * 10^{7}) ^{2} }[/tex]

[tex]M_{planet} = 2.4 * 10^{25}[/tex] kg

Now this planet orbits a star and so we can use Kepler's Third Law to find the mass of the star.

[tex]T^{2} = \frac{4\pi ^{2} }{GM_{star} } r^{3}[/tex]

T = 402 earth days = 60 x 60 x 24 x 402 = 34732800 seconds

[tex]34732800^{2} = \frac{4\pi ^{2} }{6.67 * 10^{-11} M_{star} } (2.9 * 10^{11}) ^{3}[/tex]

[tex]M_{star} = 1.2 * 10^{31}[/tex] kg

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The mass of the star of the distant solar system is 82 * 10²² kg and the mass of the planet of the distant solar system is 8.58 * 10²⁵ kg

g = G M / r

g = Acceleration due to gravity

G = Gravitational constant

M = Mass of star

r = Distance between both bodies

g = 63.6 m / s²

G = 6.67 * 10⁻¹¹ N m² / kg²

r = 8.6 * 10¹¹ m

Ms = 63.6 * 8.6 * 10¹¹ / ( 6.67 * 10⁻¹¹ )

Ms = 82 * 10²² kg

F = G M m / r²

F = m g

Equating,

m g = G M m / r²

Mp = g r² / G

Mp = 63.6 * ( 1.8 * 10⁷ / 2 )² / 6.67 * 10⁻¹¹

Mp = 8.58 * 10²⁵ kg

Therefore the mass will be equal to 8.58 * 10²⁵ kg

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A 10.0 kg block is released from rest down a 30° ramp.
It slides 6.0m along the ramp against a frictional force
of 16N. What is its speed after sliding 6.0m along the ramp?
*SOLVE USING ENERGY

Answers

Answer:

6.298 m/s

Explanation:

[tex]F_{net} =ma[/tex]

[tex]F_F=u_k*F_N[/tex]  friction force equation

[tex]ma=mgsin(x)-umgcos(x)[/tex]

We are given

[tex]m=10\\g=9.81\\F_F=16\\V_i=0[/tex]

[tex]umgcos(x)=F_F[/tex]

[tex]u*10*9.81*cos(x)=16[/tex]

[tex]u=0.18833036[/tex]

[tex]ma=mgsin(x)-umgcos(x)[/tex]

[tex]10*a=10*9.81*sin(30)-0.18833036*10*9.81*cos(30)[/tex]

[tex]a=3.305[/tex]

[tex]V_{f} ^{2} =V_{i} ^{2}+2ax[/tex]

[tex]V_{f} ^{2} =0 ^{2}+2*3.305*6[/tex]

[tex]V_f=6.298[/tex]

There are three forces acting on the foot as shown in the
figure. The foot mass is 450 g.

The foot is in equilibrium, calculate the muscle force on
the calcaneus.

Answers

The muscle force on the calcaneus is -14.41 N

What is force?

Forces are external factors that change the state of the body at rest or in motion. It has size and direction. The direction in which the force acts is called the direction of the force, and the point at which the force acts is called the point of action of the force. It's SI unit is the Newton (N). A force vector F has magnitude, direction, and orientation.

As the foot is in equilibrium it means that the net force is zero, the equation for this system is as follows:

N + F + W = 0

-N -F = W

Where,

N = Normal (10 N)

F = Muscle force

W = Weight

W = m × g

W = 0.45 × 9.8

W = 4.41 N

Now substitute the values in following equation:

-N -F = W

-10 -F = 4.41

-F = 4.41 + 10

-F = 14.41

F = -14.41 N

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a wind turbine with a rotor diameter of 40 m has a power coefficient of 0.30 in an 8 m/s wind. the air density is 1.2 kg/m3. the turbine is to be used in a wind farm that is to serve a community of 100 000 (average family size of four). each house will require 3 kw. the wind farm will have a turbine spacing of 2.4 rotor diameters perpendicular to the prevailing wind and eight rotor diameters parallel to the prevailing wind. the wind farm will have 10 turbines perpendicular to the wind.
a. Estimate the power production from one turbine. b. How many turbines will be required in the wind farm for the community? c. Estimate the dimensions of the wind farm. d.How many acres will be required for the wind farm? e. If the average house is on a 0.25-acre lot, how large will the wind farm be in comparison to the community? f. What does this problem imply about wind power feasibility in an urban setting?

Answers

Capacity factor = actual output / maximum feasible output is the formula. The maximum output for a wind turbine would be equal to the capacity times 8760 hours (there are 8760 hrs in a year).

Consequently, the Northwind 100C's maximum output is 95 kW x 8760 hours per year, or 832,200 kWh per year (or 832.2 MWh). The quantity produced is a function of the total input amounts of each ingredient, and the production function is represented as Q = f(K, L, P, H). Of course, not every firm needs the same number of inputs or production components.

The total product for every input degree is equal to the sum of the marginal products of all previous units of that input. The sum of marginal products is therefore the total product.

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A 2.00-kg rock has a horizontal velocity of magnitude 12.0 m/s when it is at point P in the figure (Figure 1). (a) At this instant, what are the magnitude and direction of its angular momentum relative to point O? (b) If the only force acting on the rock is its weight, what is the rate of change (magnitude and direction) of its angular momentum at this instant?

Answers

The rate of change (magnitude and direction) of its angular momentum at this instant is  115 kg m/s².

The rate of change of angular momentum is equal to the net torque acting on the rock. The only force acting on the rock is the weight of the rock that is, mg.

As torque is equal to the product of the tangential component of force (

and distance (r) from the axis of rotation to the line of force, the net torque acting on the rock is,

Here, r is the distance from point O to the line of force.

This torque is equal to the rate of change of angular momentum of the rock.

Calculation:-

torque = mgcosθ

          τ = mgrcosθ

             = 115 kg m/s²

The magnitude of angular momentum is 115 kg m/s².

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If the electron were replaced with a proton moving with the same velocity, how would the resulting acceleration of the particle change?.

Answers

The resulting acceleration of proton, compared to the electron's acceleration is in the opposite direction and at a similar rate.

What is resulting acceleration of particle change ?

Acceleration is a vector quantity that has elements in both the x- and y-axes. The final acceleration of the item can be calculated by calculating the vector's magnitude and direction.

The proton will accelerate in the opposite direction and at a similar rate because its mass is greater than that of the electron. The acceleration of the proton, however, is less than that of the electron.

In conclusion, the proton's subsequent acceleration would be smaller in amplitude and in the opposite direction from the electron's.

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A capacitor is charged and then made to discharge through a resistance. The time constant is Ï„. In what time will the potential difference across the capacitor decrease by 10%?
a. t ln 0.1
b. t in 0.9
c. t ln 10/9
d. t in 11/10

Answers

Answer:

Q = Q0 e^-t/RC = Q0 e^-t/T

Charge left on capacitor after time t where T is the time constant of the capacitor - R * C

Q / Q0 = .9          charge decreases by 10%

.9 = e^-t/T

ln .9 = -t / T = .10

Or t = -T * ln .9

When elapsed time t = -ln .9 * time constant

A 8.0-cm-diameter horizontal pipe gradually narrows to 5.0 cm . When water flows through this pipe at a certain rate, the gauge pressure in these two sections is 33.0 kPa and 25.0 kPa , respectivelyWhat is the volume rate of flow?Express your answer using two significant figures.Q = m3/s ?

Answers

The flow rate is 3.1175×10⁻³ m³/s.

Explanation:

By using Bernoulli's principle:

where the pipe is horizontal,

x₁ = x₂ hence the above equation becomes

since the flow rate is constant then

Q = v₁A₁ = v₂A₂

Where is the area of the two sections given by A₁ = π·D₁²÷4 and

A₂ = π·D₂²÷4

Therefore, A₁ = π·0.08²÷4 = 5.02×10⁻³ m²

and, A₂ = π·0.05²÷4 = 1.96×10⁻³ m²

v₁ = v₂A₂/A₁ =0.391×v₂

The given pressures are P₁ = 33.0 kPa and P₂ = 25.0 pKa and

ρ = 1000 kg/m³

By putting the values into the above equation we get,

33.0 kPa +0.5× 1000 kg/m³× (0.391×v₂)² = 25.0 pKa +0.5×1000 kg/m³×v₂²

= 33000+76.3·v₂² =25000+500·v₂²

=33000-25000

or 423.706·v₂² = 8000

v₂² = 8000/423.706 = 18.88 or  v₂ = 4.065 m/s and  v₁ 0.391×4.065 = 1.59 m/s

The flow rate = v₂A₂ = 1.59×1.96×10⁻³ = 3.1175×10⁻³ m³/s

Hence, Q= 3.1175×10⁻³ m³/s

The volume rate of flow is Q= 3.1175×10⁻³ m³/s.

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The flow rate is 3.1175×10⁻³ m³/s.

What is Bernoulli's principle?

Bernoulli's principle states that an increase in the speed of a fluid (such as air or water) results in a decrease in pressure. This is due to the fact that faster-moving fluids have lower pressure, while slower-moving fluids have higher pressure. This principle is also applicable to the behavior of objects moving through a fluid. The faster the object moves, the lower the pressure around it. This is why objects like planes and boats are able to "fly" or "float" because the decrease in pressure around them causes a lift. The principle is named after the Swiss mathematician and physicist Daniel Bernoulli, who first described it in 1738.

By using Bernoulli's principle:

where the pipe is horizontal,

x₁ = x₂ hence the above equation becomes

since the flow rate is constant then

Q = v₁A₁ = v₂A₂

Where is the area of the two sections given by A₁ = π·D₁²÷4 and

A₂ = π·D₂²÷4

Therefore, A₁ = π·0.08²÷4 = 5.02×10⁻³ m²

and, A₂ = π·0.05²÷4 = 1.96×10⁻³ m²

v₁ = v₂A₂/A₁ =0.391×v₂

The given pressures are P₁ = 33.0 kPa and P₂ = 25.0 pKa and

ρ = 1000 kg/m³

By putting the values into the above equation we get,

33.0 kPa +0.5× 1000 kg/m³× (0.391×v₂)² = 25.0 pKa +0.5×1000 kg/m³×v₂²

= 33000+76.3·v₂² =25000+500·v₂²

=33000-25000

or 423.706·v₂² = 8000

v₂² = 8000/423.706 = 18.88 or  v₂ = 4.065 m/s and  v₁ 0.391×4.065 = 1.59 m/s

The flow rate = v₂A₂ = 1.59×1.96×10⁻³ = 3.1175×10⁻³ m³/s

Hence, Q= 3.1175×10⁻³ m³/s

The volume rate of flow is Q= 3.1175×10⁻³ m³/s.

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Two charged particles repel each other with a force f. If the charge on only one of the particles is doubled and the distance between them is also doubled, then the force will be.

Answers

With a force of f, two charged particles repel one another. The force will be F/2 if only one particle's charge is doubled and the distance in them is likewise doubled.

What does the word "force" mean in science?

A force of this magnitude can be described as a push or a pull, which is perfectly fine. A force does not "exist in" or "contain" an object. A force from another can exert pressure on something. The concept of a force makes no distinction across living creatures and inanimate objects.

what is In one words, define force.

The definition of force is an external cause that, when applied, modifies or tends to modifies the state of the body. The body comes to rest while it is in motion, and it will go into motion when it is at rest.

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a parallel-plate air capacitor of capacitance 245 pf has a charge of magnitude 0.148/lc on each plate. the plates are 0.328 mm apart. (a) what is the potential difference between the plates? (

Answers

The potential difference between the plates of a parallel-plate air capacitor of capacitance 245 pf has a charge of magnitude 0.148 μC on each plate is 604 V

Q = C V

Q = Charge

C = Capacitance

V = Potential difference

Q = 0.148 μ C

Q = 0.148 * 10⁻⁶ C

C = 245 pF

C = 245 * 10⁻¹² F

V = Q / C

V = ( 0.148 * 10⁻⁶ ) / ( 245 * 10⁻¹² )

V = 604 V

Voltage, also known as electric pressure, electric tension, or potential difference, is the difference in electric potential between two points. In a static electric field, it corresponds to the work needed per unit of charge to move a test charge between the two points.

Therefore, the potential difference is 604 V

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