After a 90% reduction, you purchase a new soft drink machine on sale for $64. What was the original price of the soft drink machine?

Answer:

Line A B and Line C G are parallel.

Line C G and Line R S are perpendicular.

Line segment C G  lies in plane X.

Step-by-step explanation:

On my moma my answer 100%

The following statements are true:

Line AB and line CG are parallel.

Line CG and line RS are perpendicular.

Line segment CG lies in plane X.

When the two lines lie in the same plane then they are said to be parallel lines.

Given information:

Planes X and Y intersect at a right angle.

Lies in plane X and do not intersect.

A) Line AB and Line CG are parallel: As both lines, AB and CG lie in plane X. Thus both are parallel and options A is the correct option.

B) Line AB and Line RS are parallel: As the line, AB lies in the plane X and the line RS lies in the plane Y. Thus both are perpendicular and not parallel. Option B is the incorrect option.

C)Line CG and Line RS are perpendiculars: As the line CG lies in the plane x and the line RS lies in the plane Y. Thus both are perpendicular. Option C is the correct option.

D) Line AB and Line RS must intersect: line RS passes from the middle of the plane Y and line AB passes from the left of the plane X centre. Thus they do not intersect each other. Option D is the incorrect option.

E) Line segment CG lies in plane X: As shown in the diagram, line CG lies in plane X. Thus option E is the correct option.

F) Line segment RS lies in plane X: As shown in the diagram, and the line lies RS in plane Y. Thus option F is the incorrect option.

Hence, the following statements  are true:

Line AB and line CG are parallel.

Line CG and line RS are perpendicular.

Line segment CG lies in plane X.

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Answer:

Her temperature was 99.5°

Step-by-step explanation:

103.2 - 3.7 = 99.5

Answer:

If the number were 55, then the next number is 72

Step-by-step explanation:

I think you wrote the number wrong?

Answer:

101/2

Step-by-step explanation:

Answer:

75/2

Step-by-step explanation:

Simplify the following:

8×4 - 5 (3 + 1/5 - (2 + 1/2)) + (4 - 1)^2

Put 2 + 1/2 over the common denominator 2. 2 + 1/2 = (2×2)/2 + 1/2:

8×4 - 5 (3 + 1/5 - (2×2)/2 + 1/2) + (4 - 1)^2

2×2 = 4:

8×4 - 5 (3 + 1/5 - (4/2 + 1/2)) + (4 - 1)^2

4/2 + 1/2 = (4 + 1)/2:

8×4 - 5 (3 + 1/5 - (4 + 1)/2) + (4 - 1)^2

4 + 1 = 5:

8×4 - 5 (3 + 1/5 - 5/2) + (4 - 1)^2

Put 3 + 1/5 - 5/2 over the common denominator 10. 3 + 1/5 - 5/2 = (10×3)/10 + 2/10 + (5 (-5))/10:

8×4 - 5(10×3)/10 + 2/10 + (5 (-5))/10 + (4 - 1)^2

10×3 = 30:

8×4 - 5 (30/10 + 2/10 + (5 (-5))/10) + (4 - 1)^2

5 (-5) = -25:

8×4 - 5 (30/10 + 2/10 + (-25)/10) + (4 - 1)^2

30/10 + 2/10 - 25/10 = (30 + 2 - 25)/10:

8×4 - 5(30 + 2 - 25)/10 + (4 - 1)^2

30 + 2 = 32:

8×4 - 5 (32 - 25)/10 + (4 - 1)^2

| 2 | 12

| 3 | 2

- | 2 | 5

| 0 | 7:

8×4 - 5×7/10 + (4 - 1)^2

-5×7/10 = (-5×7)/10:

8×4 + (-5×7)/10 + (4 - 1)^2

The gcd of -5 and 10 is 5, so (-5×7)/10 = ((5 (-1)) 7)/(5×2) = 5/5×(-7)/2 = (-7)/2:

8×4 + (-1×7)/2 + (4 - 1)^2

4 - 1 = 3:

8×4 - 7/2 + 3^2

8×4 = 32:

32 - 7/2 + 3^2

3^2 = 9:

32 - 7/2 + 9

Put 32 - 7/2 + 9 over the common denominator 2. 32 - 7/2 + 9 = (2×32)/2 - 7/2 + (2×9)/2:

(2×32)/2 - 7/2 + (2×9)/2

2×32 = 64:

64/2 - 7/2 + (2×9)/2

2×9 = 18:

64/2 - 7/2 + 18/2

64/2 - 7/2 + 18/2 = (64 - 7 + 18)/2:

(64 - 7 + 18)/2

| 1 |  

| 6 | 4

+ | 1 | 8

| 8 | 2:

(82 - 7)/2

| 7 | 12

| 8 | 2

- | | 7

| 7 | 5:

Answer: 75/2

Answer:

I think 2nd option is correct

Answer: 9 - [tex]\sqrt{x}[/tex]

Step-by-step explanation:

Let say the number is x.

So the square root of x will  be [tex]\sqrt{x}[/tex]  and is less than 9  so we will subtract that from 9.

[tex]9-\sqrt{x}[/tex]

Answer:

you just math you know pretty easy when you know what to do

Step-by-step explanation:

just practice

Answer:

5 ounces

Step-by-step explanation:

Let the capacity of jug be j, bottle be b

[tex]2j + 4b = 40 \\ j + 3b = 25 \\ j = 25 - 3b \\ \\ therefore \: 50 - 6b + 4b = 40 \\ 2b = 10 \\ b = 5[/tex]

Answer:

1 possibility is there for the the position of the fourth vertex.

Hey there!☺

[tex]Answer:\boxed{1.762\times10^3}[/tex]

[tex]Explanation:[/tex]

1,762 in scientific notation would be written like this:

[tex]1,762\times10^3[/tex]

Hope this helps!

Answer:

B

Step-by-step explanation:

Answer:

A. Straight-line depreciation

For a car depreciated $1000 each year it was owned and driven, it shows ''Straight-line depreciation.''

Option A is true.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

A car depreciated $1000 each year it was owned and driven.

Since, A car depreciated $1000 each year it was owned and driven.

Hence, It shows Straight-line depreciation.

Thus, For a car depreciated $1000 each year it was owned and driven, it shows ''Straight-line depreciation.''

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Answer:

  CD = 13 cm

Step-by-step explanation:

We assume you intend XC = 2/3 of XM, since XD cannot be that fraction of XM.

__

Of course XM = MY = 12, since M is the midpoint of a segment 24 cm long. Then 2/3 of XM is 8 cm, and 3/4 of MY is 9 cm.

  CD = CM + MD = 4 cm + 9 cm

  CD = 13 cm

Vocabulary Check:

Integers are numbers that are neither fractions nor decimals.

Rational numbers are numbers that can be written as a fraction, unlike irrational numbers. Whole numbers are counting numbers, including 0.

Integers = -23, 2, 3, 16, 0, -4

Whole Numbers = 0, 2, 3, 16

Rational = -23, 2, 0.7, 5, 16, 0, 3.89, -4

Irrational: None

Answer:

034579+&_9&__78'_&666

Answer:

$1500

Step-by-step explanation:

Total interest:

Additional money is $1500

Answer: 178 4/5 or as an improper fraction 894/5

Hope this helps!

Please mark Brainliest!

Answer: C

Step-by-step explanation:

For this problem, we need to know the standard form of a sine function and the meaning of each part.

Standard form: [tex]y=asin[b(x-h)]+k[/tex]

a=amplitude

b=period

h=phase shift

k=vertical replacement/shifting

Now that we know the standard form and the components, we know that we can forget about k and plug in 0 for h. This would leave us with [tex]y=asin[b(x)][/tex]. We know that the amplitude is 2, therefore, a=2. To find the period, you divide 2π by the given period. [tex]\frac{2\pi }{b} =\frac{2\pi }{4\pi } =\frac{2}{4} =\frac{1}{2}[/tex], therefore, b=1/2.

[tex]y=asin[b(x)][/tex]             [plug in a=2]

[tex]y=2sin[b(x)][/tex]             [plug in b=1/2]

[tex]y=2sin(\frac{1}{2}x)[/tex]

Therefore, C is the correct answer.

Steps to solve:

-32 + (2 - 6)(10)

~Simplify

-32 + (-4)(10)

~Multiply

-32 - 40

~Subtract

-72

Best of Luck!

Answer:

Step-by-step explanation:

The equation is: –32 + (2 – 6)(10).

Then u have to do PEMDAS

P=Parentheses

E=Exponents

M=Multiplication

D=Division

A=Addition

S=Subtraction

you follow the steps to get -49

Answer:

[tex]R(x,y) = (\frac{7}{4},\frac{1}{4})[/tex]

Step-by-step explanation:

Given

[tex]A = (1,-1)[/tex]

[tex]B = (4,4)[/tex]

[tex]AR:AB = 1:4[/tex]

Required

Determine R

This question will be solved using line ratio formula

[tex]R(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2+ny_1}{m + n})[/tex]

Where

[tex]A = (1,-1)[/tex]

[tex]B = (4,4)[/tex]

[tex]m:n = AR : RB[/tex]

Since R is on A and B;

[tex]AB = AR + RB[/tex]

[tex]4 = 1 + RB[/tex]

[tex]RB = 3[/tex]

Hence;

[tex]m:n = 1 : 3[/tex]

[tex]A = (1,-1)[/tex]

[tex]B = (4,4)[/tex]

[tex]R(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2+ny_1}{m + n})[/tex] becomes

[tex]R(x,y) = (\frac{1 * 4 + 3 * 1}{1+3},\frac{1 * 4 + 3 * -1}{1 + 3})[/tex]

[tex]R(x,y) = (\frac{4 + 3}{4},\frac{4 - 3}{4})[/tex]

[tex]R(x,y) = (\frac{7}{4},\frac{1}{4})[/tex]

Answer:

The probability is 0.357

Step-by-step explanation:

Given that,

The system has at least one type of defect,

Suppose, A certain system can experience three different types of defects.

Let [tex]A_{i}[/tex] (i = 1,2,3) denote the event that the system has a defect of type i.

Suppose that the following probabilities are,

[tex]P(A_{1})=0.11[/tex]

[tex]P(A_{2})=0.08[/tex]

[tex]P(A_{3})=0.05[/tex]

[tex]P(A_{1}\cup A_{2})=0.13[/tex]

[tex]P(A_{1}\cup A_{3})=0.13[/tex]

[tex]P(A_{2}\cup A_{3})=0.11[/tex]

[tex]P(A_{1}\cap A_{2}\cap A_{3})=0.01[/tex]

[tex]P(A_{1}\cap A_{2})=0.06[/tex]

[tex]P(A_{1}\cap A_{3})=0.03[/tex]

[tex]P(A_{2}\cap A_{3})=0.02[/tex]

[tex]P(A_{1}\cup A_{2}\cup A_{3})=0.14[/tex]

We need to calculate the probability that it has exactly one type of defect

Using given data

[tex]P=\dfrac{P(A_{1}\cap A_{2}'\cap A_{3}')}{P(A_{1}\cup A_{2}\cup A_{3})}+\dfrac{P(A_{1}'\cap A_{2}\cap A_{3}')}{P(A_{1}\cup A_{2}\cup A_{3})}+\dfrac{P(A_{1}'\cap A_{2}'\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]

[tex]P=\dfrac{P(A_{1})-P(A_{1}\cap A_{2})-P(A_{1}\cap A_{3})+P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex] + [tex]\dfrac{P(A_{2})-P(A_{1}\cap A_{2})-P(A_{2}\cap A_{3})+P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]+ [tex]\dfrac{P(A_{3})-P(A_{1}\cap A_{3})-P(A_{2}\cap A_{3})+P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]

P = [tex]\dfrac{P(A_{1})+P(A_{2})+P(A_{3})-2P(A_{1}\cap A_{2})-2P(A_{1}\cap A_{3})-2P(A_{2}\cap A_{3})+3P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]

Put the value into the formula

[tex]P=\dfrac{0.11+0.08+0.05-2(0.06)-2(0.03)-2(0.02)+3(0.01)}{0.14}[/tex]

[tex]P=0.357[/tex]

Hence, The probability is 0.357

Step-by-step explanation:

The solution to this problem requires that we find other units besides the given one

1. ft/sec

2. km/h

3.m/s

1. converting to ft/sec

1 mile is 5280 ft

[tex]=\frac{45mile}{hour}* \frac{5280feet}{1 mile} *\frac{1 hours}{3600 secs} \\\\=66 ft/sec[/tex]

2. converting to km/h

1 mile is 1.60934

[tex]=\frac{45mile}{hour}* \frac{1.60934km}{1 mile} *\frac{1 hours}{1hour} \\\\=72.42km/h[/tex]

3. converting to m/s

1 mile is 1609.34

[tex]=\frac{45mile}{hour}* \frac{1609.34km}{1 mile} *\frac{1 hours}{3600 sec} \\\\=20.11m/s[/tex]

Answer:

-72

Step-by-step explanation:

-32 + (2-6)(10)

-32 + (-4)(10)

-32 + -40

-72

Answer:

-72

Step-by-step explanation:

Use PEMDAS and solve from left to right.

2 - 6 = -4

Parenthesis means multiplication.

-4 x 10 = -40

Then you add the negatives.

-32 + -40 or

-32 - 40 = -72

Answer:

a) 118

b) 55

Step-by-step explanation:

a) Originally, there are 2 red balls and a total of 17 balls.

8/9 = (2 + x) / (17 + x)

8 (17 + x) = 9 (2 + x)

136 + 8x = 18 + 9x

x = 118

b) Originally, there are 8 white balls and a total of 17 balls.

1/9 = 8 / (17 + x)

17 + x = 72

x = 55

Answer:

0.002 meters per second

Answer: 0.0002 meters per second

Answer:

  see below

Step-by-step explanation:

When the functions are inverses of each other, it will be true that ...

  m(n(x)) = n(m(x)) = x

The expanded form of this equation is shown below.

Angles XQL and MQR are congruent because they are vertical angles. So

209 - 13 b = 146 - 4 b

Solve for b :

209 - 13 b = 146 - 4 b

209 - 146 = 13 b - 4 b

63 = 9 b

b = 63/9 = 7

Then the measure of angle XQL is

(209 - 13*7)º = 118º

Answer:

See Explanation

Step-by-step explanation:

Let the temperatures of Miami and Bangor be M and B degrees respectively.

According to the given information:

M = 3B + 22... (required equation)

Plug M = 82

82 = 3B + 22

82 - 22 = 3B

60 = 3B

B = 60/3

B = 20 degrees

Thus, the temperature in Bangor is 20 degrees.

The required temperature in Bangor is 52 degrees and the required equation is 82 = 3B + - 22.

Given that,
The temperature in Miami, Florida is 22 degrees warmer than three times the temperature in Bangor, Maine.
The temperature in Miami is 82 degrees.
An equation to determine the temperature in Bangor is to be determined.

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,

Here,
Let the temperature in Bangor be B
The temperature in Miami is 82 degrees.
The temperature in Miami, Florida is 22 degrees warmer than three times the temperature in Bangor. Implies,

82 = 3B + - 22
3B = 82 + 22
3B = 104
B = 52 degrees

Thus, the required temperature in Bangor is 52 degrees.

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