a. The length of the arc is 6.28cm
b. The area of the sector is 25.12cm²
What are arc and sector?The arc of a circle is defined as the part or segment of the circumference of a circle. A sector is the space bounded by the arc and the radii of the circle. The smaller area is known as the minor sector and the bigger area is known as the major sector.
The length of an arc = tetha /360 ×2πr
= 45/360 × 2×3.14× 8
= 2×3.142 = 6.28cm
The area of a sector = tetha / 360 × πr²
= 45/360 × 3.14 × 8× 8
= 3.14× 8
= 25.12 cm²
Therefore, the length of the arc is 6.28cm and the area of the sector is 25.12cm²
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Give f(x)=3-|2x-5| find f(0)+f(-4)
The value of the function f(0) + f(-4) is -12
How to determine the value of the function?From the question, we have the following equation that can be used to solve the question
f(x) = 3 - |2x - 5|
Also, we have the function values to be
f(0) and f(-4)
When these values are calculated, we have
f(0) = 3 - |2(0) - 5| = -2
f(-4) = 3 - |2(-4) - 5| = -10
substitute the known values in the above equation, so, we have the following representation
f(0) + f(-4) = -2 - 10
Evaluate
f(0) + f(-4) = -12
Hence, the solution is -12
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A new Lexus sells for $56,000. Use 2 depreciation models and desmos to answer the following questions.
Model A: The car depreciates 12% per year.
Model B. Use straight line depreciation - the car has a value of $0 in 12 years.
Use desmos and attach a screenshot to show the following.
1. Use the wrench tool to label your x an y-values, change your x and y-value to appropriate numbers. Remember to lock the viewpoint.
2. Write on your screenshot and label the point where the linear model and the exponential model are equal.
3. Attach a screenshot to this ssignment.
Justgive me the equations
The time in years for which the values are the same is given as follows:
7.25 years.
How to obtain the models?A decaying exponential model is given as follows:
y = a(1 - r)^t.
For which:
a is the initial value.r is the decay rate, as a decimal.The parameters for this problem are given as follows:
a = 56000, r = 0.12.
Hence the exponential model is given as follows:
y = 56000(0.88)^x.
The linear model is given as follows:
y = b - mx.
In which:
b is the initial value.m is the yearly depreciation rate.The parameter values for this problem are given as follows:
b = 56000, m = 56000/12 = 4666.67.
Hence the linear model is:
y = 56000 - 4666.67.
The point of intersection of the two graphs is at a time of 7.25 years.
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The equation, 868 = 700(1 + 0.04t), represents the amount of money earned on a savings account. What does the value 868 represent?
A. The value 868 represents the amount of interest earned, which means $868 was added to the initial balance.
B. The value 868 represents the final balance in the account, which means the account balance started with $868.
C. The value 868 represents the final balance in the account, which means the account ended with $868.
D. The value 868 represents the initial balance in the account, which means the account balance ended with $868.
The number 868 represents the final balance of the acount, then we conclude that the correct option is C.
"The value 868 represents the final balance in the account, which means the account ended with $868."
What does the value 868 represent?Weknow that the equation 868 = 700(1 + 0.04t) represents the amount of money earned on a savings acount.
We want to see what does 868 represent in this situation.
Where the form of the equation is:
money earned = function that depends on t.
So the value at the left, 868, just represents the final balance of the account, this is the amount of money that there is in the account at the end.
Thus, the correct option is C.
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Ayúdenme a encontrar el valor de los ángulos la medida de A) es 48 grados y E) es 136 grados y con eso encuentra los valores de los demás
eeeeeAnswer:
Step-by-step explanation:
How do I work out this?
Answer:
3
Step-by-step explanation:
Take the x-intercept (1,0) and y-intercept (0,-3) to find the slope/gradient:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{0-(-3)}{1-0}=3[/tex]
Beer and lemonade are mixed in a ratio of 3:2 to make handy. 5% of a beer i alcohol. What percentage of a handy i alcohol?
The percentage of alcohol in a handy is 3%. 3/5 * 5% = 3% , Since beer is 5% alcohol, then 3/5 of the handy is 5% alcohol.
The ratio of beer to lemonade in a handy is 3:2, which means that 3 parts of the handy is beer and 2 parts of the handy is lemonade. To express it in terms of fractions, 3/5 of the handy is beer and 2/5 of the handy is lemonade. Since beer is 5% alcohol, then 3/5 of the handy is 5% alcohol. Therefore, if you take the proportion of the beer in the handy and multiply it by the alcohol percentage of the beer, you will get the percentage of alcohol in the handy. In this case, 3/5 * 5% = 3%. This means that the percentage of alcohol in a handy is 3%. It's important to note that this assumes that the beer and lemonade are mixed together evenly and there's no spillage or evaporation. Also, it's important to consider the fact that the alcohol percentage of the beer can vary depending on the brand and type of beer.
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Consider the function g(x)=6cos(7x+22).
How much must x increase by for 7x+22 to increase by 2π?
After the increment in the function the value of x is -2.25
In math the term function is denoted as a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
Here we know that the function g(x)=6cos(7x+22), x increase by for 7x+22 to increase by 2π.
In order to calculate the value of x in the function, we have to equate the value of function with 2π.
Then we get,
=> 7x + 22 = 2π
When we solve the equation for x then we get,
=> 7x = 2π - 22
=> x = (2π - 22)/7
When we simplify this one then we get the value of x as,
=> x = 0.285π - 3.14
=> x = 0.89 - 3.14
=> x = -2.25
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Select all the ratios equivalent to 6:8
a)1:4
b)25:24
c)12:16
Answer:
c)12:16
Step-by-step explanation:
We know
The ratio is 6:8; we times 2 and get the ratio of 12:16
So, the answer is C
a cell phone company has three different production sites. five percent of the phones from site 1, 7% from site 2, and 9% from site 3 have been recalled due to unexpected shutdown issue. suppose that 60% of the phones are produced at site 1, 30% at site 2, and 10% at site 3. if a randomly selected cell phone has been recalled, what is the probability that it came from site 3 (write it up to second decimal place)?
So, the probability that a randomly selected cell phone that has been recalled came from site 3 is 2.5 or 25%.
We can use Bayes' theorem to calculate the probability that a phone that has been recalled came from site 3. Bayes' theorem states that:
P(A|B) = P(B|A) * P(A) / P(B)
where:
P(A|B) is the probability of event A occurring given that event B has occurred (in this case, the probability that a phone came from site 3 given that it has been recalled)
P(B|A) is the probability of event B occurring given that event A has occurred (in this case, the probability that a phone has been recalled given that it came from site 3)
P(A) is the prior probability of event A occurring (in this case, the probability that a phone came from site 3)
P(B) is the prior probability of event B occurring (in this case, the probability that a phone has been recalled)
So, in this case, we have:
P(site 3 | recalled) = P(recalled | site 3) * P(site 3) / P(recalled)
We know that:
P(recalled | site 3) = 9%,
P(site 3) = 10%
We also know that:
P(recalled) = P(recalled | site 1) * P(site 1) + P(recalled | site 2) * P(site 2) + P(recalled | site 3) * P(site 3)
= (5% * 60%) + (7% * 30%) + (9% * 10%) = 3% + 2.1% + 0.9% = 6%
So, we can now calculate the probability that a phone that has been recalled came from site 3 as:
P(site 3 | recalled) = (9% * 10%) / 6% = 0.15 / 0.06 = 2.5
So the probability that a randomly selected cell phone that has been recalled came from site 3 is 2.5 or 25%.
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Function A and Function B are linear functions
to get the slope of any straight line, we simply need two points off of it, let's use those two in the picture below for Function A.
[tex](\stackrel{x_1}{-8}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{(-5)}}}{\underset{\textit{\large run}} {\underset{x_2}{10}-\underset{x_1}{(-8)}}} \implies \cfrac{4 +5}{10 +8} \implies \cfrac{ 9 }{ 18 } \implies \cfrac{1 }{ 2 }\impliedby \stackrel{\textit{slope of}}{A} \\\\[-0.35em] ~\dotfill[/tex]
[tex]y = \stackrel{\stackrel{m}{\downarrow }}{5}x-1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \stackrel{\textit{slope of}}{B} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} \stackrel{A}{\cfrac{1}{2}} ~~ < ~~ \stackrel{B}{5} \end{array}}~\hfill[/tex]
All sides of a lawn are expanded by the same amount so that it’s dimension are now 100 feet by 60 feet. If x is the same amount of length added to each side, write a function of x giving the length of each of the original sides. Use these functions to make a function for the area of the original lawn.
The function of x giving the length of each of the original sides would be [tex](x + 100) * (x + 60) = x^2 + 160x + 6000[/tex].
What is Function of x?
A function is a formula that expresses one variable in terms of another. The statement "y is a function of x" (denoted y = y(x)) states that y changes depending on the value of x.
The original length of each side of the lawn can be represented by the function x + 100, and the original width can be represented by the function x + 60.
To find the area of the original lawn, we can multiply the length and width functions.
So, the function for the area of the original lawn is:
[tex](x + 100) * (x + 60) = x^2 + 160x + 6000[/tex]
This is a quadratic function in x, whose leading coefficient is 1, and the value of x is the same amount of length added to each side of the lawn.
Hence, The function of x giving the length of each of the original sides would be [tex](x + 100) * (x + 60) = x^2 + 160x + 6000[/tex].
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Please help me <3 Thanks :)
what is the smallest even consecutive number such that their sum is at most 90?
SOLVE PLEASE
To find the smallest even consecutive numbers whose sum is at most 90, we can start with the smallest even number, which is 2. Then, we can add 2 to it to get the next even number, which is 4. We can keep adding 2 to get the next even numbers, and keep track of their sum. We can stop as soon as the sum exceeds 90.
The smallest even consecutive numbers whose sum is at most 90 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90
The first 20 even consecutive numbers sum 90.
Solve for kkk.
20-6+4k=2-2k20−6+4k=2−2k20, minus, 6, plus, 4, k, equals, 2, minus, 2, k
k =k=k, equals
The value of k is -2
Now, According to the question:
The given equation is:
20 - 6 + 4k = 2 - 2k
We have to solve for the value of k.
Now,
20 - 6 + 4k = 2 - 2k
Combine the like terms;
20 - 6 - 2 = -2k - 4k
Calculate the sum or difference:
20 - 8 = -6k
12 = -6k
Calculate the product or quotient:
k = -12/6
k = -2
Hence, The value of k is -2
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Francine had six times the money Tommy had, but after Francine gave Tommy $33 to help him purchase a baseball cap, Tommy had twice as much as Francine. How much did they each start with?
For the relation of times of money , Francine and Tommy start with the amount of money equals to $18 and $3 respectively.
Let 'x' represents the amount of money with Francine .
And 'y' represents the amount of money with Tommy.
In the first condition:
x = 6y __(1)
To purchase baseball cap Francine gave $33 then the given relation is :
y - 33 = 2( x - 33 )
⇒ y - 33 = 2x - 66
⇒y = 2x -66 + 33
⇒ y = 2x -33 __(2)
Substitute the value of 'x' from (1) in (2) we get,
y = 2(6y) - 33
⇒y = 12y - 33
⇒ 12y - y = 33
⇒ 11y = 33
⇒ y = $3
⇒ x = 6(3)
⇒ x = $18
Therefore, the amount of money Francine and Tommy start with is equal to $18 and $3 respectively.
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relative frequency distributions are generally more useful than frequency distributions when
Relative frequency distributions are generally more useful than frequency distributions when comparing data sets of different sizes.
Frequency distributions can show the actual number of observations falling in each range or the percentage of observations. In the latter sample, the distribution is called a relative frequency distribution.
Frequency distribution tables can be utilised for both categorical and numeric variables. Continuous variables should only be used with class intervals, which will be described shortly.
A relative frequency distribution displays the proportion of the total number of observations associated with each value or class of values and is related to a probability distribution, which is extensively used in statistics.
--This question is incomplete; the complete question is
"Relative frequency distributions are generally more useful than frequency distributions when _____."--
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Jason is closing on a $430,000 home. He made a 13% down payment and is borrowing the rest. What is the approximate range of costs that he might expect to pay at the closing?
Answer:
$8,600 - $31,100
Step-by-step explanation:
Hope this helps :)
A set of elementary school student heights are normally distributed with a mean of 105 centimeters and a
standard deviation of 10 centimeters. Faisal is an elementary school student with a height of 103. 1 centimeters.
What proportion of student heights are lower than Faisal's height?
You may round your answer to four decimal places
Answer:
0.4247
Step-by-step explanation:
You want to know the proportion of heights less than 103.1 cm if the population is normal with a mean of 105 cm and a standard deviation of 10 cm.
ProportionThe proportion can be found using a suitable probability calculator. The one shown in the attachment tells us ...
the proportion of heights less than 103.1 cm is about 0.4247.
__
Additional comment
The height of interest is less than the mean by approximately 0.2 times the standard deviation. This suggests the proportion will be close to, but less than, 0.5000.
<95141404393>
Write the missing angle measure next to each
letter.
65°
a, b, c, d, e
The angle relationship I used to find Angle a is...
The angle relationship I used to find Angle b is...
The angle relationship I used to find Angle c is...
The angle relationship I used to find Angle d is...
The angle relationship I used to find Angle e is...
The missing angle measure for the following letters are:
a - 65°
b - 115°
c - 115°
d - 65°
e - 65°
The angle relationship I used to find Angle a is the Corresponding Angle (a = 65°)The angle relationship I used to find Angle b is Angles on a Straight line (b = 180 - 65)The angle relationship I used to find Angle c is the Corresponding Angle (b = c)The angle relationship I used to find Angle d is Angle on a straight line (d = 180 - 65) = 115°The angle relationship I used to find Angle e is. Corresponding angles. d = e and e = d.What is a corresponding angle?Corresponding angles are generated when two parallel lines are crossed by a transversal.
Opening and closing a lunchbox, completing a Rubik's cube, and endless parallel railway tracks are all examples of equivalent angles.
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Please help with this problem!!!
At 11.5 hours, the red turtle pass the blue turtle. The red turtle won the race. The solution has been obtained by studying graph of the functions.
What is graph of the function?
The collection of all points in the plane with the form (x, f(x)) that make up a function f's graph. The graph of f is also known as the graph of
y = f(x).
In the graph, it is seen that from 6 to 13 hours, the blue turtle is at the same place whereas the red turtle is moving.
Therefore, at 11.5 hours the red turtle passes the blue turtle.
The red turtle won the race in 16 hours because in the graph it is observed that the blue turtle did not complete the entire km. The graph of blue turtle is a little less than that of red turtle.
Hence, at 11.5 hours, the red turtle pass the blue turtle and wins the race.
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Since there are multiple questions, so the question answered above is attached below.
Which even number is not a composite number?
A) 6
B) 4
C) 2
D) 8
Choose the inequality that matches the graph below.
Answer:
X ≤ -1
How do we know this?
Well, if x = the value of any number in the graph, we can see that it can be equal to negative one, or less than -1, meaning we use the symbol ≤.
Which is faster? Please show work
A. The black car that travels 110 feet per second
B. The silver car that travels 60 miles per hour
Answer:
the answer is A
I hope I help you in this ans and tq.
Car = 6 cylinder compact Years driven = second and third Miles driven = 13,000 miles in year two and 12,000 in year three In dollars and cents, the total projected depreciation cost for these two years would be
In dollars and cents, the total projected cost of gas and oil for two years would be $ 756.00
First we will calculate per year how much is spent.
First year, we have :-
= 13000 * 0.028 = 364.00
Second year, we have:-
12000 * 0.028 = 336.00
The total cost in the two years is the sum of both:
= first year + second year
= 364.00 + 336.00 = 700.00
In dollars and cents, the total projected cost of gas and oil for two years would be $ 700.00.
Total cost
Total cost refers to the overall cost of production, which includes both fixed and variable components of the cost.
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complete question is :-
Compute the requested operating costs as indicated, based on the preceding table and the following information.
Choose the correct answer.
Car = 6 cylinder compact
Years driven = second and third
Miles driven = 13,000 miles in year two and 12,000 in year three
In dollars and cents, the total projected depreciation cost for these two years would be $?
PLEASE HELP ASAP
Find the value of r so that the line through (r,5) and (6,r) has a slope of 5/8
Answer: 70/13
Step-by-step explanation:
Slope = rise/run
(r-5)/(6-r) = 5/8
30-5r = 8r-40
70 = 13r
70/13 = r
2x/3x-5-x+1/3x+5=-4/9x^2-25
The solution to the expression in this problem is given as follows:
x = -1/3 + 1.7i and x = -1/3 - 1.7i.
How to solve the rational expression?The rational expression for this problem is defined as follows:
[tex]\frac{2x}{3x - 5} - \frac{x + 1}{3x + 5} = -\frac{4}{9x^2 - 25}[/tex]
Applying the least common factor at the left side, we have that:
[tex]\frac{2x(3x + 5) - (x + 1)(3x - 5)}{9x² - 25} = -\frac{4}{9x^2 - 25}[/tex]
[tex]\frac{6x^2 + 10x - 3x^2 + 5x - 3x + 5}{9x^2 - 25} = -\frac{4}{9x^2 - 25}[/tex]
As the denominators are equal, the solution is obtained equaling the denominators, hence:
3x² + 2x + 5 = -4
3x² + 2x + 9 = 0.
Which is a quadratic function with coefficients given as follows:
a = 3, b = 2, c = 9.
Inserting these coefficients into a calculator, the solutions are given as follows:
x = -1/3 + 1.7i and x = -1/3 - 1.7i.
Missing InformationThe rational expression is given by the image presented at the end of the answer.
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find the iqr of 81, 82, 83, 83, 84, 84, 84, 85
The Interquartile range of the given set is 1.5.
What is Interquartile range ?
The variation between the third and first quartiles is defined by the interquartile range. The numbers that partition the entire series into four equal sections are known as quartiles. There are therefore 3 quartiles. The lower quartile is represented by the letter Q₁, the higher quartile by the letters Q₁, and the middle quartile by the letter Q₃.
Given set : 81, 82, 83, 83, 84, 84, 84, 85
Here, It is already in increasing order but the number of values is 8 which is even.
So, Q₁ part = 81, 82, 83, 83
Q₁ will be the median of 82 and 83.
So, Q₁ = (82+83)/2
= 82.5
Similarly, Q₃ part =84, 84, 84, 85
So, Q₃ will be the median of 84 and 84.
hence, Q₃ = (84+84)/2
= 84
We know that, Interquartile range = Q₃ - Q₁
= 84 - 82.5
= 1.5
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7:21:35 in its simplest form
The smallest equivalent fraction of the number is considered to be its simplest form.The answer is 7/3 : 21/5 = 5 : 9.
What is what in its most basic form?Values should now be entire numbers.By removing the denominators, convert fractions to integers.
Since the denominators of our two fractions are different, we must identify the least common denominator and rewrite our fractions using the common denominator as necessary.
LCD(7/3, 21/5) = 15
Now we have:
7/3 : 21/5 = 35/15 : 63/15
Now that the denominators of our two fractions are similar, we may multiply them both by 15 to get rid of the denominators.
Then, we have:
7/3 : 21/5 = 35 : 63
With the highest common factor, attempt to further reduce the ratio (GCF).
GCF is 7 for 35 and 63.
Divide both terms by GCF 7, then:
35 ÷ 7 = 5
63 ÷ 7 = 9
By multiplying both components by the GCF = 7, it is possible to reduce the ratio 35: 63 to its simplest terms.
35 : 63 = 5 : 9
Therefore:
7/3 : 21/5 = 5 : 9
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Please help I need the answers ASAP.
Question 1:
[tex]\frac{2}{3} n-16=-\frac{5}{6}n+2[/tex], solve for n.
[tex]\frac{2}{3} n-16=-\frac{5}{6}n+2[/tex]
=> [tex]\frac{2}{3} n=-\frac{5}{6}n+18[/tex]
=> [tex]\frac{2}{3} n+\frac{5}{6}n=18[/tex] =>[tex]\frac{4}{6} n+\frac{5}{6}n=18[/tex]
=> [tex]\frac{9}{6} n=18[/tex] => [tex]\frac{3}{2} n=18[/tex]
=> [tex]n=18(\frac{2}{3})[/tex]
=> [tex]n=6(2)[/tex]
Sol: n=12
Question 2:
[tex]5-\frac{1}{3}p=\frac{4}{9}p+12[/tex], solve for p.
[tex]5-\frac{1}{3}p=\frac{4}{9}p+12[/tex]
=>[tex]5=\frac{4}{9}p+\frac{1}{3}p+12[/tex]
=> [tex]5=\frac{4}{9}p+\frac{3}{9}p+12[/tex]
=>[tex]5=\frac{7}{9}p+12[/tex]
=> [tex]-7=\frac{7}{9}p[/tex]
=> [tex]-7(\frac{9}{7}) =p[/tex]
=> [tex]-(9)=p[/tex]
Sol: p=-9
Question 3:
The relationship between ∠2 and ∠7 is that they are alternate interior angles.
Question 4:
The relationship between ∠1 and ∠3 is that they are corresponding angles.
Question 5:
The relationship between ∠4 and ∠5 is that they are alternate exterior angles.
Willow is driving on the freeway. She just passed mile marker 325. The fastest she will drive is 75 miles per hour, though, there is a bit of traffic that might slow her down a bit, but she doesn’t know exactly how much. The mile markers are increasing on her route.
The expression 325 + 2y represents what mile marker she’s at after 2 hours, depending on traffic. Which inequality describes the mile marker she would be at this point?
The inequality describes the mile marker she would be at this point is:
325 + 2y ≤ 475
Now, According to the question:
Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
We have,
The fastest driving speed of Willow is 75 miles per hour,
There is a bit of traffic on her route that might slow her speed down,
So, the inequality which represents the speed of the willow is:
y ≤ 75
Hence, the inequality which represents the speed of the driving of willow is y ≤ 75.
Now, the expression 361 + 2y represents what mile marker he is at after 2 hours. We know that the fastest he will drive is 75, so we could replace y=75 in the last expression to know what mile marker he would be seeing at that point. This is:
325 + 2(75) => 325 + 150 = 475
Now, we know that the inequality would be:
325 + 2y ≤ 475
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