: Across of white-eyed Drosophila females with red-eyed Drosophila males produces a low frequency (~1/1000) of white-eyed F1 females and red-eyed F1 males-an unexpected class of progeny. When the rare white-eyed F1 females are examined microscopically, they have two X chromosomes and one Y chromosome (XXY). The rare red-eyed males are found to have only 1 X chromosome (XO). A. Diagram the original cross, showing the expected progeny for the cross. Your diagram should show the sex chromosomes and the alleles (w or w) present on the Xs. B. Diagram the cross again and show how the rare XXY, white-eyed F1 females and XO, red-eyed males could arise via improper segregation of the X chromosomes in the female parent during meiosis I. C. What is the improper meiotic event you diagrammed called?

Answers

Answer 1

The improper meiotic event depicted in the diagram is called nondisjunction.

A. The original cross between the white-eyed Drosophila females (XXww) and the red-eyed Drosophila males (XwY) can be diagrammed as follows: The expected progeny are F1 females that are red-eyed and heterozygous for the white-eye gene (XwX^+), F1 males that are red-eyed and hemizygous for the white-eye gene (XwY).B. Improper segregation of the X chromosomes in the female parent during meiosis I can cause rare XXY white-eyed F1 females and XO red-eyed males to arise in the cross. The diagram below shows how this can occur. During meiosis I, homologous chromosomes (Xw and X^+) pair and separate, resulting in two haploid cells, each with one chromosome from each homologous pair.

A normal female gamete is produced when the two haploid cells from meiosis II combine. However, during meiosis I, a nondisjunction event can occur in which homologous chromosomes fail to separate properly, resulting in two cells that lack a chromosome and two cells that have an extra chromosome. One of the eggs produced by the mother in this cross was fertilized by a normal sperm (Xw) to produce the XXY white-eyed female, while one of the eggs produced by the mother was fertilized by a sperm that lacked an X chromosome (Y) to produce the XO red-eyed male.C.

The improper meiotic event depicted in the diagram is called nondisjunction. Nondisjunction is the failure of homologous chromosomes to separate during meiosis I or the failure of sister chromatids to separate during meiosis II, resulting in gametes with an abnormal number of chromosomes.

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Related Questions

18-year old Giselda was having dinner at a restaurant with her family when she suddenly developed acute gastric pain and angioedema. Her family took her to the emergency room at the hospital as Giselda's symptoms got even worse and she had issues breathing and eventually lost consciousness. As the ER doctor, you decide she needs the following treatment right away:
O Intravenous (IV) administration of corticosteroids
O an injection of antihistamines
O Intravenous (IV) administration of wide spectrum antibiotics
O a shot from an EpiPen
O NSAIDS

Answers

As the ER doctor, the immediate treatment needed for Giselda is an injection of antihistamines and a shot from an EpiPen.

Giselda's symptoms, including acute gastric pain, angioedema (swelling of the deeper layers of the skin), and difficulty breathing, indicate a severe allergic reaction, most likely anaphylaxis. Anaphylaxis is a life-threatening condition that requires prompt medical intervention. The first-line treatment for anaphylaxis is administering antihistamines and epinephrine.

Antihistamines help to counteract the effects of histamine, a chemical released during an allergic reaction that causes swelling and other symptoms. By blocking histamine receptors, antihistamines can reduce swelling and relieve symptoms like angioedema.

Epinephrine, delivered through an EpiPen, is a potent medication that rapidly constricts blood vessels, relaxes airway muscles, and increases heart rate. These actions help to reverse the severe symptoms of anaphylaxis and restore normal breathing and blood circulation.

The combination of antihistamines and epinephrine is crucial in managing anaphylaxis. Antihistamines help to alleviate the allergic response, while epinephrine acts as a rapid-acting medication to address the life-threatening symptoms.

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How would you describe the genotype of Mendel's pea plants that had purple flowers, but had one purple allele and one white allele (Pp)? How would you describe the white flowering plant that had two white alleles (ww)?

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The genotype of Mendel's pea plants that had purple flowers, but had one purple allele and one white allele (Pp) is known as a heterozygous dominant genotype.

It has one dominant purple allele and one recessive white allele. The term "P" represents the purple allele, and the lowercase letter "p" represents the white allele.  Explanation:The genotype of the pea plant determines its genetic composition. In Mendel's pea plant, the genotype of plants with purple flowers and one purple and one white allele is heterozygous dominant. The term "heterozygous" means that the two alleles are different from each other.The term "dominant" means that only one allele is expressed in the phenotype, while the other allele is masked. In this case, the purple allele is dominant over the white allele. When an individual with this genotype breeds with another individual with the same genotype, there is a 25% chance of obtaining homozygous dominant offspring (PP), a 50% chance of obtaining heterozygous offspring (Pp), and a 25% chance of obtaining homozygous recessive offspring (pp).

The white flowering plant that had two white alleles (ww) is known as homozygous recessive. Both alleles are recessive, and no dominant allele is present to mask the expression of the white allele. In this case, the term "w" represents the white allele. When an individual with this genotype breeds with another individual with the same genotype, all of the offspring will have the same genotype (ww).

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Which of the following types of alterations would NOT promote tumorigenesis? A. Increased activation of PI3K B. Overexpression of BAX or BAK C. Overexpression of BCL2 or BCLXL D. Defective CHK2 kinase (stress kinase) signaling E. Overexpression of MDM2

Answers

There are several types of alterations that can promote tumorigenesis. The following types of alterations that would NOT promote tumorigenesis are given below:a) Increased activation of PI3KIt is true that the increased activation of PI3K would promote tumorigenesis.

The PI3K/AKT/mTOR pathway is a major signaling pathway that is activated in cancer. This pathway is responsible for regulating cell proliferation, survival, and growth.b) Overexpression of BAX or BAKOverexpression of the BAX or BAK gene promotes apoptosis or programmed cell death, which is the opposite of what is needed to promote tumorigenesis.

Overexpression of BCL2 or BCLXL Overexpression of BCL2 or BCLXL genes prevents apoptosis or programmed cell death. In contrast, promoting apoptosis is one way to prevent cancer. Thus, overexpression of BCL2 or BCLXL would promote tumorigenesis.d) Defective CHK2 kinase (stress kinase) signalingCHK2 kinase plays a crucial role in cell cycle regulation.

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Describe light harvesting by purple bacteria and how
this energy is used to generate a proton gradient.
600 words minimum

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Light harvesting in purple bacteria involves the capture of solar energy by specialized pigment-protein complexes called photosynthetic antenna complexes.

These complexes are embedded in the photosynthetic membranes of purple bacteria and are responsible for absorbing light and transferring the energy to reaction centers, where it is converted into chemical energy. The process of light harvesting and energy conversion in purple bacteria is highly efficient and serves as a crucial step in generating a proton gradient across the photosynthetic membrane.

Purple bacteria contain pigments called bacteriochlorophylls, which are similar to the chlorophyll pigments found in plants. These bacteriochlorophyll pigments are organized into antenna complexes, also known as chlorosomes, which are located in the photosynthetic membrane.

The chlorosomes have a unique structure consisting of stacked pigment-protein aggregates that form rods or lamellae. This structure allows for the efficient capture of light energy over a broad range of wavelengths.

When light energy is absorbed by the bacteriochlorophyll pigments in the antenna complexes, it triggers an electronic excitation in the pigment molecules. The excitation energy is then transferred through a process called resonance energy transfer from one pigment molecule to another within the antenna complex.

This transfer continues until the excitation energy reaches the reaction center, which contains specialized bacteriochlorophyll molecules.

The reaction center is where the conversion of light energy into chemical energy occurs. In purple bacteria, there are different types of reaction centers, including type I and type II reaction centers. Each reaction center consists of bacteriochlorophyll molecules and associated proteins that facilitate the energy conversion process.

In the reaction center, the absorbed light energy causes an electron transfer from a donor molecule, typically a bacteriochlorophyll molecule, to an acceptor molecule. This electron transfer generates a charge separation, resulting in the production of an electron in the reduced state and a positively charged hole in the oxidized state. The electron is subsequently transferred to an electron transport chain within the photosynthetic membrane.

The electron transport chain is composed of various protein complexes embedded in the membrane. As the excited electrons move through the chain, they release energy that is used to pump protons across the membrane from the cytoplasmic side to the periplasmic side. This proton movement creates a proton gradient or electrochemical gradient across the membrane.

The proton gradient generated by the movement of protons across the membrane is a form of stored energy. It represents a difference in proton concentration and electric potential between the two sides of the membrane. This gradient can be utilized by the purple bacteria to drive ATP synthesis through a process called chemiosmosis.

In chemiosmosis, the protons flow back across the membrane through an enzyme complex called ATP synthase. As the protons pass through ATP synthase, their movement drives the synthesis of ATP from ADP and inorganic phosphate. This ATP serves as an energy currency for the cell and is used for various cellular processes, including metabolism and growth.

In summary, light harvesting in purple bacteria involves the absorption of light energy by pigment-protein complexes, which transfer the energy to reaction centers. The reaction centers convert the light energy into chemical energy through electron transfer processes.

This energy is then used to generate a proton gradient across the photosynthetic membrane. The proton gradient drives ATP synthesis through chemiosmosis, providing the purple bacteria with a vital energy source for cellular activities.

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Pick the answer that best fits the question
Indicates Ventricles are depolarizing
While the ventricles are in systole the atria would be
in.
Which Ion would cause heart cells to

Answers

The term that indicates ventricles are depolarizing is QRS complex. While the ventricles are in systole, the atria would be in diastole. The ion that would cause heart cells to depolarize is Calcium ions.

What is QRS complex?

The QRS complex indicates that the ventricles are depolarizing. It is a series of waveforms observed on an electrocardiogram (ECG). The QRS complex is defined as the electrical impulses produced as the ventricles of the heart contract to pump blood out of them.

What is Diastole?

The atria are in diastole while the ventricles are in systole. Diastole is a state of relaxation or dilation of the heart chambers during which they fill with blood. It can refer to the ventricles or the atria, depending on the context.

What are calcium ions?

Calcium ions are the ion that would cause heart cells to depolarize. Calcium ions play a significant role in cardiac muscle contraction by causing the sarcoplasmic reticulum to release calcium ions. This process triggers the sliding filament mechanism of muscle contraction, resulting in muscle contraction.

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For what are anabolic-androgenic steroids primarily used?
A. To build muscle mass
B. As a treatment for prostate cancer
C. To slow the progression of Alzheimer’s disease
D. As part of many weight loss regimens
E. None of these answers are correct

Answers

Anabolic-androgenic steroids are primarily used for the purpose of building muscle mass.

They are synthetic forms of testosterone, the male hormone, which enhances muscle growth and strength. This is the reason why athletes and bodybuilders use them to enhance their performance and build their physique. Choices A is correct. Anabolic-androgenic steroids are primarily used for building muscle mass.

The synthetic hormone helps enhance muscle growth and strength. So, bodybuilders and athletes use it to enhance their performance.

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science adheres to a rigorous, unbiased system of inquiry to answer a question A/ science tries to follow the scientific method, but the experimental design is biased and/or has errors. AJ science has no basis in the scientific method and claims are prove or reproduce.

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Science is a methodical way of pursuing knowledge, and its various disciplines follow a rigorous, unbiased. Scientific knowledge is based on empirical data gathered by careful observation and experimentation.

Science relies on the scientific method to test hypotheses, which is a set of logical, systematic, and transparent procedures used to obtain data or knowledge in science. It's the most widely used approach in science, and it involves making observations, formulating hypotheses, and testing them to see if they're true.

Science tries to adhere to the scientific method as closely as possible to ensure unbiased results. Experimental designs are created to minimize bias and errors in the data, and scientists are trained to avoid personal biases when analyzing results.

Even with the best intentions, experiments may still have errors and biases. It's important for scientists to acknowledge these errors and adjust their methods or results accordingly. This is why peer review is such an essential part of the scientific process.


In contrast to pseudoscience and untested claims, science is a systematic approach to acquiring knowledge. Scientific claims must be proven through observation, experimentation, and peer review to be accepted by the scientific community.

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Life is encoded in nucleic acid-based genomes. Detail the differences and similarities in the genomes of viruses, prokaryotes, and eukaryotes with respect to type of nucleic acid, strand complexity of the nucleic acid and the environment in which the nucleic acid inhabits.

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Viruses, prokaryotes, and eukaryotes differ in various aspects of their genomes.

Viruses have genomes that can be composed of either DNA or RNA. The nucleic acid can be single-stranded or double-stranded, depending on the type of virus. Some viruses have genomes made of DNA, while others have RNA genomes. Additionally, viruses can have either single-stranded or double-stranded nucleic acid. Viruses are obligate intracellular parasites and rely on host cells for replication. They do not possess their own metabolism and cannot survive outside a host organism.

Prokaryotes, such as bacteria, have genomes composed of double-stranded DNA. These genomes are typically circular and found within the cytoplasm of the cell. Prokaryotic genomes are relatively small and compact. They contain essential genes necessary for the organism's survival and reproduction. Prokaryotes live in diverse environments, ranging from soil and water to the human body, and can adapt to various conditions due to their genetic versatility.

Eukaryotes, including plants, animals, fungi, and protists, have genomes consisting of double-stranded DNA. Unlike prokaryotes, eukaryotic genomes are more complex and larger in size. They are organized into multiple linear chromosomes located within the nucleus of the cell. Eukaryotic genomes contain non-coding regions, such as introns, in addition to protein-coding genes. Eukaryotes inhabit diverse environments, including terrestrial, aquatic, and symbiotic relationships.

In summary, viruses can have either DNA or RNA genomes, with single or double-stranded nucleic acid, and they require a host cell for replication. Prokaryotes have double-stranded DNA genomes that are usually circular and reside in the cytoplasm. Eukaryotes possess double-stranded DNA genomes organized into linear chromosomes found in the nucleus. The genomes of these three groups reflect their evolutionary adaptations to different environments and lifestyles.

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Sometimes, traumatic injury to the spleen requires its removal.
Write a 500 word response on the systems in the body affected by
this, and how does the body get by without a spleen?

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The spleen is an essential organ of the immune system, and it is involved in the production and storage of white blood cells that fight infections. It also helps in the filtration of blood and the removal of old and damaged blood cells. In cases of traumatic injury, the spleen can rupture, causing internal bleeding and damage to the organ. This is why sometimes, traumatic injury to the spleen requires its removal.

Once the spleen is removed, the body has to compensate for its loss. The most notable changes that occur are the following:

1. Immune System Changes

The spleen plays a critical role in the body's immune system by producing and storing white blood cells that help fight infections. Without the spleen, the body is at higher risk of developing infections, particularly from encapsulated bacteria, such as Streptococcus pneumoniae, Haemophilus influenzae type B, and Neisseria meningitidis. Therefore, individuals without a spleen are more susceptible to bacterial infections and should take extra precautions to avoid exposure, such as getting vaccinated and taking antibiotics as needed.

2. Blood Filtration

The spleen is also responsible for filtering blood and removing old and damaged blood cells. Once the spleen is removed, the liver and bone marrow take over this function. However, it can result in an increase in the number of red blood cells, which can lead to a condition known as polycythemia. This can cause symptoms such as headaches, dizziness, and fatigue.

3. Increased Risk of Blood Clots

The spleen also plays a role in preventing blood clots by removing platelets from circulation. Without the spleen, there is a higher risk of developing blood clots. Therefore, individuals without a spleen should avoid activities that increase the risk of blood clots, such as sitting for long periods, smoking, and birth control pills.

4. Other Changes

Other changes that may occur after spleen removal include an increased risk of certain cancers, such as lymphoma and leukemia, and a decrease in the production of antibodies.

In conclusion, traumatic injury to the spleen can cause severe damage and internal bleeding. Sometimes, the only treatment is to remove the spleen. Although the body can compensate for its loss, it can result in significant changes in the immune system, blood filtration, and an increased risk of blood clots. Therefore, individuals without a spleen should take extra precautions to prevent infections and avoid activities that increase the risk of blood clots.

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Which of the following is true concerning the scapula?
O the end of the spine projects as the expanded process called the coracoid
the coracold articulates with the clavicle
O the glenoid cavity is where the scapula and humerus articulate
O the lateral border of the scapula is near the vertebral column
the scapular notch is a prominent indentation along the inferior border

Answers

The true statement about scapula is "The glenoid cavity is where the scapula and humerus articulate".

The glenoid cavity is a shallow, concave socket located on the lateral side of the scapula. It is the site where the scapula articulates with the head of the humerus, forming the glenohumeral joint, commonly known as the shoulder joint. This joint allows for a wide range of movement of the arm.

The other options provided are not true concerning the scapula:

The end of the spine of the scapula projects as the expanded process called the acromion, not the coracoid.The coracoid process is a separate bony projection on the anterior side of the scapula and does not articulate with the clavicle.The lateral border of the scapula is farther away from the vertebral column, while the medial border is closer to it.The scapular notch refers to a small indentation on the superior border of the scapula, not the inferior border.

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6. Measurement of the concentration of a substance that is performed by measuring the decreased intensity of light blocked by particles in solution at 180° from the source is called:
a. fluorometry. b. atomic absorption. c. turbidimetry. d. nephelometry.
7. A solution that is identical to that of calibrating or unknown solutions except that the substance to be measured and that is used to set 100% T (zero absorbance) at the beginning of a photometric analysis is referred to as a:
a. standard solution. b. calibrating solution. c. reference blank. d. reagent blank.
8. In a fluorescence measurement, if an excited macromolecule is heavily labeled by a fluorophore, the label could be in such proximity to other fluorophores that the resulting fluorescence is much lower than expected. This limitation of fluorescence is referred to as:
a. light scattering. b. concentration quenching. c. solvent quenching. d. the sample matrix effect.

Answers

Turbidimetry is a technique that determines the concentration of a substance in a sample by measuring the decrease in light intensity caused by particles in solution at 180 degrees from the source.

The correct option to the given question is option c.

Turbidimetry is widely used to measure the concentration of bacteria, viruses, and other particles in solution, as well as to determine the size of these particles. Turbidimetry is a reliable and sensitive method for measuring the concentration of particles in a solution, and it has numerous applications in medical, environmental, and industrial fields.
A reference blank is a solution that is similar to the unknown or calibration solutions but contains no analyte. The answer to this question is C. It is used to set the 100% T (zero absorbance) value at the beginning of a photometric analysis. The reference blank is used to correct for any variations in the instrument, such as drift or changes in temperature, that may affect the absorbance readings. The use of a reference blank ensures that the instrument is properly calibrated, and that the absorbance readings are accurate and reliable.
Concentration quenching is a phenomenon that occurs when the fluorescence of a sample is reduced by the presence of high concentrations of fluorophores. The answer to this question is B, concentration quenching. This occurs because the excited fluorophores collide with one another, transferring their energy to each other instead of emitting light. Concentration quenching is a major limitation of fluorescence measurements, and it can lead to inaccurate results if not properly accounted for. Several techniques are used to minimize the effects of concentration quenching, such as diluting the sample or using a less-labeled fluorophore.

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compare the energy yield (ATP production) and byproducts of
fermentation in aerobic and anaerobic respiration and discuss the
reason for the difference. please give in depth answer, will give
rating.

Answers

Organisms generate ATP (adenosine triphosphate) through aerobic and anaerobic respiration. Oxygen availability affects fermentation energy yield and by products.

Aerobic respiration is oxygen-efficient. Glycolysis, the Krebs cycle, and oxidative phosphorylation are involved. Aerobic respiration breaks down glucose completely, producing several ATP molecules. Glucose generates 36–38 ATP molecules. Aerobic respiration produces CO2 and H2O. Anaerobic respiration happens without oxygen. It is less efficient than aerobic respiration. distinct organisms have distinct anaerobic respiration processes. Fermentation requires glycolysis and NAD+ regeneration. Fermentation produces organism-specific products, unlike aerobic respiration. Yeast ferments ethanol and carbon dioxide, while muscle cells ferment lactic acid. Importantly, fermentation produces only 2 ATP per glucose molecule.

The ultimate electron acceptor in the electron transport chain determines energy yield and by products in aerobic and anaerobic respiration. Oxygen completes glucose oxidation and efficiently produces ATP in aerobic respiration. Oxygen is a good electron acceptor. Anaerobic respiration uses lower-electronegativities electron acceptors like nitrate or sulphate. This reduces electron transport and ATP output relative to aerobic respiration. Alternative electron acceptors in anaerobic respiration often produce by products like ethanol or lactic acid during fermentation.

In conclusion, aerobic respiration, which completely oxidises glucose, provides more ATP than anaerobic respiration, especially fermentation, which yields by products. Oxygen and electron transport chain efficiency are the main factors.

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Write the sequence of the complementary strand of each segment of a DNA molecule. A. 5'TGGGTA-3' 3'-_____ -5' b. 5'-ACGCGGTC-3' 3'_____ -5' c. 5'-TCATTCAAG-3' 3'-_____-5' d. 5'-AAAGAGTGGAAAAAX-3'
3'-______-5'

Answers

The sequences of the complementary strands for each segment of the DNA molecule are as follows:

a. 5'TGGGTA-3' - 3'ACCCAT-5' (Option A)

b. 5'-ACGCGGTC-3' - 3'-TGCGCCAG-5' (Option B)

c. 5'-TCATTCAAG-3' - 3'-AGTAAGTTC-5' (Option C)

d. 5'-AAAGAGTGGAAAAAX-3' - 3'-TTTCTCACCTTTTTX-5' (Option D)

To find the complementary strand, you need to identify the base pairing rules in DNA: adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G). By applying these rules, you can determine the complementary sequence by swapping the bases accordingly. For example, in Option A, the original sequence 5'TGGGTA-3' pairs with 3'ACCCAT-5' as the complementary sequence. Similarly, the other options can be determined by applying the base pairing rules.

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what are G protein coupled R?
what are enzyme coupled R?
what are their main function ?
what is the difference between the two ?

Answers

The  wide set of cell membrane proteins known as G protein-coupled receptors (GPCRs) are essential for signal transduction.

By detecting outside signals and engaging internal signalling pathways through interactions with G proteins, they contribute to a number of physiological functions. Numerous cellular processes, including neurotransmission, hormone secretion, and sensory perception, are controlled by GPCRs, which carry signals from extracellular ligands, such as hormones, neurotransmitters, and sensory inputs, to intracellular effectors.Another group of cell surface receptors is the category of enzyme-coupled receptors, usually referred to as receptor tyrosine kinases (RTKs). They function as both receptors and enzymes because they have enzymatic activity. RTKs undergo autophosphorylation after ligand binding, which starts intracellular signalling cascades. These pathways regulate biological functions such as metabolism, differentiation, and cell proliferation.

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Which of the following best describes a cloning vector? A. The direction in which DNA is cloned. B. A DNA molecule that accepts DNA fragments and degrades them in a host. C. The fragment of DNA encoding a gene of interest D. A DNA molecule that accepts DNA fragments and replicates the fragment in a host.

Answers

D. A DNA molecule that accepts DNA fragments and replicates the fragment in a host.

A cloning vector is a DNA molecule, typically derived from a plasmid or a viral genome, that is used to carry and replicate foreign DNA fragments in a host organism, such as bacteria. Cloning vectors contain specific features that allow them to accept and propagate the inserted DNA fragments, such as selectable markers and origin of replication. They provide the necessary elements for the replication, maintenance, and expression of the inserted DNA in the host organism.

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All of the following statements describe mitosis EXCEPT a. It allows for growth and development. b. It involves duplication of chromosomes. c. It occurs in egg and sperm formation. d. It produces diploid daughter cells.

Answers

Mitosis is a type of cell division that results in the production of two genetically identical daughter cells. Mitosis is a process that occurs in both unicellular and multicellular organisms. It is responsible for a variety of activities, including cell repair and the growth and development of new cells.

This process is essential for living organisms. However, the following statement does not describe mitosis:Mitosis occurs in egg and sperm formation.Instead, meiosis occurs in egg and sperm formation. Meiosis is a specialized form of cell division that occurs only in the cells that will eventually form eggs or sperm.

Meiosis is a type of cell division that reduces the chromosome number by half, resulting in the production of haploid daughter cells. Therefore, Option C is the correct answer. The correct answer is Option C: It occurs in egg and sperm formation.

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Question 55 The four cardinal signs of inflammation are: 1 flare, wheals, fever, cough 2. rash, pus, heat, rubor 3. heat, pain, vesicles, fever 4. redness, heat, swelling, pain 01 04 0 3 02 Previous 1

Answers

The Inflammation is characterised by its four cardinal symptoms: redness, heat, swelling, and pain. Because of this, selecting option 4, "redness, heat, swelling, pain," is the right decision.

1. Wheals, fever, coughing, and flare-ups are not the primary symptoms of inflammation. While fever and cough can be signs of many other illnesses, including inflammation, flare and wheals are more frequently linked to allergic reactions.

2. The primary symptoms of inflammation may not always include rashes, pus, heat, and rubor. Although it is not one of the essential indications, a rash might be an indication of inflammation. Pus is a byproduct of inflammation but it is not a distinguishing feature. Redness, one of the cardinal indications, is also referred to as rubor.

3. Vesicles, heat, and fever

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What happens during translation if a certain amino acid was accidentally attached to the wrong t-RNA molecule? A.The amino acid gets translated into the protein and might make it nonfunctional. 8. A p

Answers

During the process of translation, a mistake can occur if a certain amino acid is attached to the wrong t-RNA molecule.

In such a case, the resulting protein might become nonfunctional.What happens during translation if a certain amino acid was accidentally attached to the wrong t-RNA molecule

During translation, amino acids are assembled in a specific sequence according to the sequence of codons in the mRNA. The process of translation is mediated by tRNA (transfer RNA) molecules. Each tRNA molecule has an anticodon sequence at one end that recognizes a specific codon in the mRNA and an amino acid binding site at the other end that binds to a specific amino acid.

Hence, if a certain amino acid is accidentally attached to the wrong tRNA molecule, the wrong amino acid would be added to the growing peptide chain. This will result in a change in the primary structure of the protein.In the case where a mistake occurs during translation and a wrong amino acid is incorporated into the protein sequence, it might affect the structure of the protein.

This, in turn, could cause it to become nonfunctional or lose its function completely. For example, in the case of enzymes, a single amino acid substitution might affect the enzyme's active site, which could, in turn, affect the enzyme's catalytic activity. Hence, it is crucial that the correct amino acid is added to the growing peptide chain during translation.

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In compact bone, the bone cells receive nourishment through minute channels called Select one O a lacunae b. lymphatics costeons O d. lamellae De canaliculi During the thyroidectomy procedure, the sup

Answers

In compact bone, the bone cells receive nourishment through minute channels called canaliculi.

Compact bone is one of the types of bone tissue found in the human body. It is dense and forms the outer layer of most bones. Within the compact bone, there are small spaces called lacunae, which house the bone cells known as osteocytes. These osteocytes are responsible for maintaining the health and integrity of the bone tissue.

To receive nourishment, the osteocytes in compact bone rely on a network of tiny channels called canaliculi. These canaliculi connect the lacunae and allow for the exchange of nutrients, oxygen, and waste products between neighboring osteocytes and the blood vessels within the bone. The canaliculi form a complex network that permeates the compact bone, ensuring that all bone cells have access to vital resources for their metabolic processes.

Overall, the canaliculi play a crucial role in providing nourishment to the bone cells in compact bone, facilitating the exchange of substances necessary for cell function and bone maintenance. This network ensures the vitality and health of the bone tissue, supporting its structural integrity and overall function in the skeletal system.

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How do glucocorticoids increase the body's supply of energy in time of stress? (Select all that apply) anabolism of stored triglycerides into fatty acids and glycerol anabolism of muscle proteins into

Answers

Glucocorticoids increase the body's supply of energy in times of stress by promoting the anabolism of stored triglycerides into fatty acids and glycerol, as well as the catabolism of muscle proteins into amino acids.

Glucocorticoids, such as cortisol, play a crucial role in mobilizing energy during times of stress. They stimulate the breakdown of stored triglycerides (fat molecules) in adipose tissue through a process called lipolysis.

This results in the release of fatty acids and glycerol into the bloodstream, which can be used as an energy source by various tissues, including the liver and muscles.

The breakdown of triglycerides provides an immediate supply of energy to meet the increased demands during stress.Furthermore, glucocorticoids promote the catabolism of muscle proteins, a process known as proteolysis.

This occurs primarily in skeletal muscles, where muscle proteins are broken down into individual amino acids. The released amino acids can then be utilized by the liver to synthesize glucose through a process called gluconeogenesis.

Glucose serves as a vital energy source for the brain and other tissues. By promoting proteolysis, glucocorticoids ensure a steady supply of amino acids for glucose production, thus maintaining energy availability during stressful situations.

In summary, glucocorticoids increase the body's supply of energy during times of stress by promoting the breakdown of stored triglycerides into fatty acids and glycerol, which can be used as an energy source.

Additionally, they stimulate the catabolism of muscle proteins into amino acids, enabling the liver to produce glucose through gluconeogenesis, providing a critical energy source for various tissues.

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2. Most of the calcium sensors fall into main families
characterized by having either ____ or ______ Ca 2+ binding
domains.

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The presence of these domains allows proteins to regulate a wide range of cellular processes in response to changes in intracellular Ca2+ levels.

Most of the calcium sensors fall into main families characterized by having either EF-hand or C2 Ca2+ binding domains. EF-hand domains are the most abundant and widespread Ca2+ binding motif found in proteins.

These motifs consist of two helices separated by a short turn that contains four acidic residues arranged in a characteristic loop structure that coordinates the Ca2+ ion. The C2 domain is a structurally diverse Ca2+ binding domain found in numerous proteins with different functions, including signal transduction and membrane trafficking. In conclusion, EF-hand and C2 Ca2+ binding domains are the two main families of Ca2+ sensors.

The most abundant and widespread motif is the EF-hand domain, while the C2 domain is structurally diverse and found in many different proteins.

The presence of these domains allows proteins to regulate a wide range of cellular processes in response to changes in intracellular Ca2+ levels.

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State whether an earthworm has a gastrovascular cavity or a complete digestive tract. Explain your choice.

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An earthworm has a complete digestive tract, also known as an alimentary canal. This means it has a mouth, pharynx, esophagus, crop, gizzard, intestine, and anus.

Earthworms possess a complete digestive tract, which is a tube-like structure with separate openings for ingestion and elimination. This type of digestive system allows for specialized regions and processes along the pathway of food digestion.

The digestive process in an earthworm starts with the mouth, where food enters. From there, the food passes through the pharynx and esophagus into the crop, which acts as a temporary storage organ. Next, the food moves to the gizzard, a muscular structure that grinds and breaks down the food mechanically. The food then enters the intestine, where digestion and absorption of nutrients occur. Finally, undigested waste is eliminated through the anus.

Having a complete digestive tract allows earthworms to efficiently process and extract nutrients from the organic material they consume. This specialized system enables them to have a continuous flow of food and waste, optimizing their digestive processes and overall digestion efficiency.

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3. What did the boiling do to the enzyme? 4. Why did tube 4 have a negative reaction for starch and a negative reaction for sugar? What was this a negative control to show which part of the experiment

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The boiling done to the enzyme denatured, or destroyed, it. When enzymes are exposed to heat, they begin to unravel and form new shapes that no longer enable it to carry out its intended biological function, in this case, the breakdown of starch and sugar.

This is why tube 4, the negative control, had a negative reaction for both starch and sugar--the boiling destroyed the enzyme, so the reaction was inhibited.

This negative control was necessary to show if the other tubes were reacting due to the enzyme or if they were doing so for some other reason. Without this negative control, it would have been difficult to determine if other tubes were reacting due to the presence of the enzyme.

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Factor X can be activated O Only if the is Factor VII O Only if both intrinsic and extrinsic pathways are activated. O Only if the intrinsic pathway is acticated. O Only if the extrinsic pathway is ac

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Factor X can be activated B. only if both intrinsic and extrinsic pathways are activated.

Blood clotting or coagulation is a complex process that requires the participation of several factors. Factor X is one of the clotting factors that participate in the coagulation cascade, a series of steps that culminate in the formation of a blood clot. When the lining of a blood vessel is injured, two pathways, the intrinsic and the extrinsic, initiate the clotting process. The extrinsic pathway is triggered by the release of tissue factor from damaged cells outside the blood vessels.

On the other hand, the intrinsic pathway is activated by the exposure of subendothelial collagen to blood after vessel damage. Once activated, the two pathways converge to activate factor X, which is then converted to factor Xa by a series of proteolytic cleavages. Factor Xa, in turn, activates prothrombin to thrombin, which converts fibrinogen to fibrin, the main protein that forms a blood clot. So therefore the correct answer  is B. only if both intrinsic and extrinsic pathways are activated, Factor X can be activated.

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An individuals plasma [Na+] is measured and found to be 130
mEq/L (normal = 145 mEq/L). What is the patient’s estimated plasma
osmolality? (Normal osmolality of the plasma is 290 mOsm/Kg
H2O)

Answers

The patient’s estimated plasma osmolality is 255 mOsm/kg H2O. When plasma [Na+] is measured and found to be 130 mEq/L (normal = 145 mEq/L),

the patient's estimated plasma osmolality can be calculated. We can use the following equation to calculate plasma osmolality. $$Plasma\;Osmolality = 2(Na^+)+\frac{Glucose}{18}+\frac{BUN}{2.8}$$$$Plasma\;Osmolality= 2(130)+\frac{0}{18}+\frac{0}{2.8}$$$$Plasma\;Osmolality= 260$$$$Plasma\;Osmolality= 260\;mOsm/kg\;H_2O$$(Since no values are provided for glucose and BUN)Thus, the patient’s estimated plasma osmolality is 255 mOsm/kg H2O.

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Provide the staphylococci species that is coagulase (+).
aureus is a spore-forming bacteria and can survive in high salt environment and tolerate a wide range of temperatures. T/F
Provide two specific drug resistant S. aureus strain that are highly problematic in clinical settings.
Provide the staphylococci species that is capable producing a superantigen.
Provide the names of five enzymes that are important for the pathogenesis of staphylococci.
Describe the mechanism of toxicity of enterotoxins from S. aureus.
What is the function of Fibrinolysin?
What are the major clinical diseases caused by S. aureus?
What is the mechanism of resistance due to PBP 2a expression?
What is the mechanism of resistance in VRSA?
Describe the hemolytic pattern of (a) alpha-, beta- and gamma-hemolysin.
Which specific streptolysin is immunogenic?
Which Streptococci species has hyaluronic acid containing capsule?
Which Streptococci species has sialic acid containing capsule?
Provide the names of three different bacteria that cause pneumonia.
Provide three different ways pneumolysin increases the virulence of S. pneumoniae.
Provide the names of four spore forming bacterial pathogens.
Provide the names of two different bacterial pathogens that produce lactic acid.
What type of virulence factor is diphtheria toxin and what is the mechanism of this exotoxin?
What are the two cell wall components that are specific to mycobacterium and not found in other Gram-positive pathogens?

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Staphylococci species that is coagulase (+): Staphylococcus aureus is the staphylococci species that is coagulase (+). It is a gram-positive bacteria that is present in the human skin and nares. aureus can also survive on surfaces and equipment that have not been disinfected and people carrying this bacteria can act as carriers and spread it to others.

Specific drug-resistant S. aureus strains: MRSA and VISA (Vancomycin-Intermediate Staphylococcus Aureus) are two specific drug-resistant S. aureus strains that are highly problematic in clinical settings. S. aureus species capable of producing a super antigen: S. aureus is the species capable of producing a super antigen.

Enzymes that are important for the pathogenesis of staphylococci: The enzymes that are important for the pathogenesis of staphylococci are catalase, coagulase, hyaluronidase, lipase, and nuclease. Mechanism of toxicity of enterotoxins from S. aureus: Enterotoxins from S. aureus cause food poisoning, with symptoms such as vomiting, diarrhea, and abdominal cramps.

The enterotoxins have super antigenic properties which allow them to activate large numbers of T-cells. The activation of the T-cells leads to the release of cytokines that cause the symptoms of food poisoning.

Fibrinolysin: Fibrinolysin is an enzyme produced by S. aureus that breaks down fibrin clots. It can aid in the spread of the bacteria in the body by allowing them to move through clots and reach new areas.

Major clinical diseases caused by S. aureus: Some of the major clinical diseases caused by S. aureus are skin infections (such as boils and impetigo), pneumonia, bloodstream infections, and endocarditis. Mechanism of resistance due to PBP 2a expression: PBP 2a is a penicillin-binding protein that is not affected by beta-lactam antibiotics. The expression of PBP 2a leads to resistance to beta-lactam antibiotics such as penicillin and cephalosporins.

Mechanism of resistance in VRSA: Vancomycin-resistant S. aureus (VRSA) is resistant to vancomycin, which is usually the drug of last resort for treating S. aureus infections. The resistance is due to the acquisition of a plasmid that carries genes for resistance to both vancomycin and methicillin.

Hemolytic pattern of alpha-, beta-, and gamma-hemolysin: Alpha-hemolysin causes complete lysis of red blood cells, producing a clear zone around the colony. Beta-hemolysin causes partial lysis of red blood cells, producing a green zone around the colony. Gamma-hemolysin does not cause any lysis of red blood cells, producing no zone around the colony.

Specific streptolysin that is immunogenic: Streptolysin O is the specific streptolysin that is immunogenic. Streptococci species with hyaluronic acid-containing capsule: Streptococcus pyogenes is the species with hyaluronic acid-containing capsule.

Streptococci species with sialic acid-containing capsule: Streptococcus pneumoniae is the species with sialic acid-containing capsule.

Bacteria that cause pneumonia: Streptococcus pneumoniae, Haemophilus influenzae, and Legionella pneumophila are three different bacteria that cause pneumonia. Ways pneumolysin increases the virulence of S. pneumoniae: Pneumolysin increases the virulence of S. pneumoniae by promoting the lysis of host cells, activating complement, inducing inflammation, and inhibiting the immune response. Spore-forming bacterial pathogens: Bacillus anthracis, Clostridium botulinum, and Clostridium tetani are four spore-forming bacterial pathogens.

Bacterial pathogens that produce lactic acid: Lactobacillus and Streptococcus are two different bacterial pathogens that produce lactic acid. Virulence factor of diphtheria toxin and mechanism: Diphtheria toxin is an exotoxin that inhibits protein synthesis in eukaryotic cells. It is an A-B toxin, where the A subunit inhibits protein synthesis and the B subunit binds to the cell surface receptors.

Cell wall components specific to mycobacterium: Mycolic acid and arabinogalactan are the two cell wall components that are specific to Mycobacterium and not found in other Gram-positive pathogens.

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Living organisms require energy for Multiple Choice O chemical work
O transport work
O mechanical work. O All of the answer choices are correct.

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Living organisms require energy for All of the answer choices are correct.

All living organisms, from the simplest microorganisms to the most complex multicellular organisms, require energy to perform several activities such as chemical work, transport work, and mechanical work.

Energy is essential for any organism's survival, growth, and reproduction.

Chemical work refers to the chemical reactions required for the synthesis of biomolecules such as proteins, carbohydrates, and lipids in organisms.

These molecules are essential for an organism's growth, metabolism, and other physiological functions.

Transport work is required for moving substances in and out of cells and throughout an organism's body.

Cells must transport various substances, including nutrients, gases, and waste products, for their survival and functioning.

Mechanical work refers to physical activities such as movement, contraction of muscles, and the beating of cilia and flagella that require energy.

In addition to these, the functioning of organs such as the heart and lungs also require mechanical work.

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Why are cells so small? a. Very large cells would be unable to divide. b. As a cell gets bigger, its volume increases much slower than its surface area, spreading the cell's resources too thinly to confer any benefit. c. Because their components are microscopic. d. As acell gets bigger, its surface area increases much slower than its volume, reducing its ability to efficiently import nutrients and export wastes. e. Because that's their place in the larger scheme of things in nature. Question 43 A cell's reservoir of NADPH composes its______. a. reducing power b. structural stability c. oxidizing power d. backbone reservoir

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Cells are small because as a cell gets bigger, its volume increases much faster than its surface area, leading to a reduced ability to efficiently import nutrients and export wastes.

The size of cells is crucial for their efficient functioning and survival.

1. Surface Area-to-Volume Ratio: Cells have a high surface area-to-volume ratio, which is essential for effective exchange of nutrients, gases, and wastes with the environment. The surface area of a cell is responsible for these exchanges, while the volume of the cell determines its metabolic activity and the amount of resources it requires.

2. Import and Export Efficiency: As a cell grows larger, its volume increases at a faster rate compared to its surface area. This means that the surface area available for nutrient absorption and waste elimination becomes relatively smaller in proportion to the cell's increasing volume.

Consequently, a large cell would struggle to efficiently import enough nutrients to sustain its increased metabolic demands or export wastes efficiently, leading to potential resource limitations and accumulation of harmful byproducts.

3. Cellular Functions and Division: Cells need to carry out various functions to support life, such as energy production, protein synthesis, and DNA replication. These processes rely on the efficient exchange of molecules and information within the cell.

Additionally, cells need to be able to divide to ensure growth, development, and tissue repair. If cells were too large, they would face challenges in dividing due to the difficulty of distributing genetic material and cellular components equally among the daughter cells.

In summary, cells are small to maintain a favorable surface area-to-volume ratio, which enables efficient exchange of nutrients and waste products. By remaining small, cells can effectively meet their metabolic demands, carry out essential functions, and undergo successful division, ensuring their survival and proper functioning within the organism.

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Investigative/Implementation Project A class of biology students at Ben Loss High school was taught that high levels of sodium chloride (common salt) concentration can damage their liver. They wondered if this has anything to do with the activity of the enzyme Catalase. To assist the group with this, you are asked to plan and design an experiment to find out whether the salt concentration affects the activity of the enzyme catalase

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Experiment: Investigating the Effect of Salt Concentration on Catalase Activity.

Catalase is an enzyme found in various organisms, including humans, that plays a crucial role in the breakdown of hydrogen peroxide (H2O2) into water (H2O) and oxygen (O2). It is commonly found in the liver, where it helps detoxify harmful substances. The students at Ben Loss High school want to investigate whether high levels of sodium chloride concentration can affect the activity of catalase and potentially lead to liver damage. This experiment aims to determine the effect of different salt concentrations on catalase activity. Hypothesis: We hypothesize that increasing salt concentration will negatively impact catalase activity. Higher salt levels may disrupt the enzyme's structure and function, reducing its ability to catalyze the decomposition of hydrogen peroxide effectively.

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what is virus host interaction ?

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Virus-host interaction refers to the interplay between a virus and its host, which involves a complex set of molecular and cellular events that can be beneficial or detrimental to the virus or the host.

Virus-host interaction, or VHI, is a dynamic process that involves multiple steps, including viral entry, replication, assembly, and release, as well as host recognition, defense, and repair mechanisms. Depending on the virus and the host cell, the outcome of VHI can vary from viral clearance to chronic infection, from immune suppression to hyperactivation, and from cellular dysfunction to transformation.

Virus-host interaction (VHI) is a complex and dynamic process that involves multiple steps, including viral entry, replication, assembly, and release, as well as host recognition, defense, and repair mechanisms. VHI is a critical determinant of the outcome of viral infection, as it determines whether the virus will be eliminated by the host or establish a chronic infection, whether the host will mount an effective immune response or suffer from immunopathology, and whether the infected cell will survive or undergo apoptosis or senescence. Therefore, understanding the molecular and cellular basis of VHI is essential for developing effective strategies to prevent or treat viral infections.

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Other Questions
Use the word bank to complete the statements below. Terms can be used more than once or not at all tidal volume pulmonary compliance spirometry inspiratory reserve volume expiratory reserve volume obstructive disorders emphysema residual volume pulmonary compliance measures pulmonary function and is used to diagnose restrictive disorders and obstructive disorders As you breathe while resting in a chair, there is a minimal amount of ventilation (about a half liter). This is called the tidal volume If asked to take the deepest breath that you can, a healthy person would inhale about 3 liters. This is called the inspiratory reserve volume it asked to exhale all that you can after a fidal exhalation, a healthy person would exhale about an additional 1.3 liters. This is called the___ The air you cannot exhale, even with maximal effort, is called the _____ Design the required length for a welded connection for an MC9x23.9 of A572 Grade 50 steel connected to a 38-inch-thick gusset plate. The gusset plate is A36 steel. Consider three sides weld and evaluate it based on the applied load? Use LRFD. Dead load and live load are 48 and 120 kips, in order 1.Show your work, calculate the molecular formula for thisunknown.2. What is the IHD for this unknown? Draw two possiblestructures for this unknownPlease give a detailed explanation. Write any five Verilog and VHDL code Simulate and realize the following applications using Xilinx Spartan 6 FPGA PROCESSOR. (using structural/dataflow /behavioural modelling)1. BCD counter2. 7 segment display Competitive firms innovate because: A) Innovation will increase the costs of production which will induce firms to increase production. B) It will decrease their costs of production. C) Governments require them to. D) Firms in competitive markets do not innovate. According to Boyle's law, decreasing the volume of a gas samplewill result in ________ in the pressure. Boyle's law assumesconstant temperature and a constant amount of gas.a decreasean increasea Which structure in the box below matches the IR spectrum below? XL A D H LOH OH E CH3 B F H CH3 CH3CHCHCHC=CH C CH3 -CEN G J NH22 23 24 25 26 27 3 mum 25 00 4400 4300 400 30000 3400 300 Topic 2: Renal physiology In Practical 4 'Control of Fluid Balance' volunteers consumed the following: Treatment 1 - 8 ml water/kg body weight Treatment 2 - 8 ml isotonic saline/kg body weight Treatment 3 - 8 ml water/kg body weight, then exercised by stepping on and off a box for five minutes after fluid ingestion and before voiding urine for collection. In a different experiment, we changed treatment 2 and added a fourth group. Therefore, the new treatments were: Treatment 1 - 8 ml water/kg body weight Treatment 2 - 8 ml hypertonic saline/kg body weight Treatment 3 - 8 ml water/kg body weight, then exercised by stepping on and off a box for five minutes after fluid ingestion and before voiding urine for collection. Treatment 4 - Drink 0.8 ml vodka/kg body weight In the table below, explain the effects of each treatment on extracellular volume , osmolality and urine volume . Table 2. Osmolality Extracellular volume Treatment 1 Treatment 2 Treatment 3 Treatment 4 *Please note: Do not just state increase or decrease, explain why it (i.e. urine volume) changed or didn't change. The solar collector having the highest efficiency for high temperatures is:Select one or more:a. Unglazed typeb. Glazed typeC. Evacuated Thoes typed. The 3 types have the same efficiency A population has two alleles at the height gene. The T allele is for the tall trait, and the t is for the short trait. T is dominant to t. The frequency of the Tall allele, T, in the gene pool is (p)=0.10 The frequency of the Short allele, t, in the gene pool is (q)=0.90 What are the expected genotype frequencies and phenotype frequencies in this population if the population is in Hardy-Weinberg Equilibrium? Enter complete decimals to two places with a leading "zero". Example: 0.16 or 0.50 or 0.01 Frequency of TT = Frequency of Tt= Frequency of tt= Frequency of Tall phenotype = 1) In your own words, explain the difference between Discovery, Invention, and Innovation. Give examples for each of them. 2) In your own words, explain the difference between Copyrights and Trademarks. Give examples for each of them. Describe the types of interactions stabilising chymotrypsinstructure and explain how substrate peptides are recognised by thisenzyme. Question 678How can you identify individual proteins?Select one alternative:High pressure liquid chromatography (HPLC)Western blotsMass spectrometry (MS)Electrophoresis 13. What is the correct example of value for existence? Preventing soil erosion of agricultural land Preserving the existence of Sumatran tigers because you like them, even if it is highly unlikely that you will ever see them in their original habitat Preventing air pollution to ensure a pollution-free environment to the next generation Harvesting fish or extract oil from the ground Conserving land to support the production and maintenance of all living organisms and the surrounding ecosystems Protecting Sumatran tigers, as you think that you might get the opportunity to watch them later in your life 14. What is the correct example of value for bequest? Preventing soil erosion of agricultural land Preserving the existence of Sumatran tigers because you like them, even if it is highly unlikely that you will ever see them in their original habitat Preventing air pollution to ensure a pollution-free environment to the next generation Harvesting fish or extract oil from the ground Conserving land to support the production and maintenance of all living organisms and the surrounding When performing cell culture work in the lab, often a BSC is needed. WHich of the following statements is TRUE with respect to this?a. This cabinet blows sterile air across the surface to ensure that a sterile, aseptic environment exists for cell culture work.b. All of the answers presented here are correctA BSC needs to be used whenever cancer cells are being cultured. Otherwise, noncancerous tissue cultures cells can be worked on on a lab bench as long as you are practicing aseptic technique.c. A BSC must be used whenever cell culture work is required in the lab.d.A BSC needs to be used whenever cancer cells are being cultured. Otherwise, noncancerous tissue cultures cells can be worked on on a lab bench as long as you are practicing aseptic techniquee.A BSC is used to store stock cultures of bacteria and animal cells How would the signaling of a G protein-coupled receptor, without ligand, be affected if you made a G protein that is able to exchange GDP by GTP on its own, without needing to be activated by the G protein-coupled receptor? Select one: a. The signal wouldn't be affected; there is no ligand, thus no signal. b. The signal wouldn't be affected; the ligand would be unable to bind due to the conformational change. c. The G protein would be active but unable to signal due to the lack of ligand. d. The G protein would be active and signaling, despite the lack of ligand. Determine the [OH] in a solution with a pH of 4.798. Your answer should contain 3 significant figures as this corresponds to 3 decimal places in a pH. (OH]-[ -10 (Click to select) M If the diameter of a cylinders piston is 4 inches and 100 psi air is applied to it. What is the maximum resulting force capability? (5) A myoglobin similar to the example we did in class had the protonation of a histidine residue coupled to the oxidation of a heme. The histidine had a pKA of 6.0 when the heme is oxidized and 7.1 when the heme is reduced. At pH 9.5, the reduction potential of the heme is +275 mV vs NHE. (a) Draw the thermodynamic box that describes this system (b) Predict the reduction potential at pH 3. (c) The net charge at the iron center really cycles between 0 and +1, as the nitrogens at the center of the porphyrin ring have a total net charge of -2. Assuming a dielectric constant of 6, predict the distance between the heme iron and the histidine side chain. 4) Disc brakes are used on vehicles of various types (cars, trucks, motorcycles). The discs are mounted on wheel hubs and rotate with the wheels. When the brakes are applied, pads are pushed against the faces of the disc causing frictional heating. The energy is transferred to the disc and wheel hub through heat conduction raising its temperature. It is then heat transfer through conduction and radiation to the surroundings which prevents the disc (and pads) from overheating. If the combined rate of heat transfer is too low, the temperature of the disc and working pads will exceed working limits and brake fade or failure can occur. A car weighing 1200 kg has four disc brakes. The car travels at 100 km/h and is braked to rest in a period of 10 seconds. The dissipation of the kinetic energy can be assumed constant during the braking period. Approximately 80% of the heat transfer from the disc occurs by convection and radiation. If the surface area of each disc is 0.4 m and the combined convective and radiative heat transfer coefficient is 80 W/m K with ambient air conditions at 30C. Estimate the maximum disc temperature.