Given the data from the question,
A. The number of mole of water needed for the reaction is 1 mole
Bi. The number of mole of C₂H₂ formed is 0.5 mole
Bii. The number of mole of Ca(OH)₂ formed is 0.5 mole
How to determine the mole of CaC₂Mass of CaC₂ = 32 gMolar mass of CaC₂ = 40 + (12×2) = 64 g/mol Mole of CaC₂ =?Mole = mass / molar mass
Mole of CaC₂ = 32 / 64
Mole of CaC₂ = 0.5 mole
A. How to determine the mole of water needeBalanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ required 2 moles of H₂O
Therefore,
0.5 mole of CaC₂ will require = 0.5 × 2 = 1 mole of H₂O
Thus, 1 mole of H₂O is needed for the reaction.
Bi. How to determine the mole of C₂H₂ produced
Balanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ reacted to produce 1 mole of C₂H₂
Therefore,
0.5 mole of CaC₂ will also react to produce 0.5 mole of C₂H₂
Thus, 0.5 mole of C₂H₂ was obtained from the reaction
Bii. How to determine the mole of Ca(OH)₂ producedBalanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ reacted to produce 1 mole of Ca(OH)₂
Therefore,
0.5 mole of CaC₂ will also react to produce 0.5 mole of Ca(OH)₂
Thus, 0.5 mole of Ca(OH)₂ was obtained from the reaction
Learn more about stoichiometry:
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The reaction of iron (III) oxide with carbon monoxide produces iron and carbon dioxide.
Fe2O3(s) + 3C0(9) - 2Fe(s) + 3CO (9)
How many grams of Fe2O3 are required to produce 4.65g Fe? You must show your work to receive full credit.
Answer:
6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.
Explanation:
The balanced reaction is:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Fe₂O₃: 1 moleCO: 3 molesFe: 2 molesCO₂: 3 molesThe molar mass of each compound is:
Fe₂O₃: 159.7 g/moleCO: 28 g/molFe: 55.85 g/moleCO₂: 44 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Fe₂O₃: 1 mole* 159.7 g/mole= 159.7 gramsCO: 3 moles* 28 g/mol= 84 gramsFe: 2 moles* 55.85 g/mole= 111.7 gramsCO₂: 3 moles* 44 g/mole= 132 gramsThen you can apply the following rule of three: if by stoichiometry 111.7 grams of Fe are produced from 159.7 grams of Fe₂O₃, 4.65 grams of Fe are produced from how much mass of Fe₂O₃?
[tex]mass of Fe_{2} O_{3} =\frac{4.65 grams of Fe*159.7 grams of Fe_{2} O_{3}}{111.7grams of Fe}[/tex]
mass of Fe₂O₃= 6.65 grams
6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.
Calculate the molality of a solution that contains 75.0-grams of methyl alcohol, CH3OH, dissolved in 600.0-grams of
water.
Answer:
[tex]m=3.90mol/kg[/tex]
Explanation:
Hello there!
In this case, since the molality of a solution is calculated by dividing moles of solute by kilograms of solvent, it turns out firstly necessary for us to calculate the moles of methyl alcohol in 75.0 grams as shown below:
[tex]n=\frac{75.0g}{32.04g/mol}=2.34mol[/tex]
Then, the kilograms of water, 0.600 kg, and finally, the resulting molality:
[tex]m=\frac{2.34mol}{0.600kg}\\\\m=3.90mol/kg[/tex]
Regards!
what is the relationship between Celsius scale and Kelvin scale of temperature ? very sort answer
Answer:
Celsius + 273 = Kelvin
Explanation:
The percent to by mass of chlorine
Answer: 100.000%
Explanation:
.
Se prepara una solución agregando sal en 500 g de agua. Calcular la masa de sal, cuando se tiene una solución al 6,4 % en masa
Answer:
x~ 34.19 grams del sal o ~ 34 grams!
Explanation:
el porcentaje de masa se escribe como
% de masa = masa de sal / (masa de sal + masa de disolvente) * 100%
aquí, el disolvente se da como 500 g de agua.
usa x en lugar de masa de sal y resuelve usando álgebra
6.4 = x / (x+ 500) * 100
0.064 = x / (x+500)
0.064 x + 32 = x
32 = x-0.064x
32 = 0.936 x
x~ 34.19 grams del sal o ~ 34 grams!
Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a catalyst in organic reactions. Calculate the number of moles of HCl in 62.85 mL of 0.453 M hydrochloric acid.
Answer: 0.0285 moles of HCl is present in given amount of solution.
Explanation:
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(1)
Given values:
Molarity of HCl = 0.453 M
Volume of solution = 62.85 mL
Putting values in equation 1, we get:
[tex]0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles[/tex]
Hence, 0.0285 moles of HCl is present in given amount of solution.
How many grams of aluminum is required to react with 75.0 ml of 2.50 M HCl?
Answer:
63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid
I'm sorry if it's wrong, I tried.
Explanation:
A sample of O2 gas is put into a bottle at STP. If the volume of the bottle is 0.52 L, how many moles of O2 will the bottle contain?
please help!!
Answer:
Explanation:
So,at STP or NTP, one mole of any gas occupies 22.4 litres of volume. To find mass,firstly we have to calculate the no. Of moles present in 11.2 litres of O2 gas which can be calculated as ;
No. Of moles = Given Volume ÷ 22.4 Litre (provided that gas is at STP)
= 11.2 Litre / 22.4 Litre
= 0.5 moles
Now, mass can be calculated by;
Mass = no. Of moles × Molecular mass
= 0.5 × 32 (Molecular mass of O2 is 32u or 32 g, if you are calculating in Grams, also called Gram Molecular Mass)
= 16 g
This is the answer
2Al + 6HCl → 2AlCl3 + 3H2
If 12 moles of Al completely react, how many moles of H2 are produced?
Answer:
18 moles of H₂.
Explanation:
The balanced equation for the reaction is given below:
2Al + 6HCl –> 2AlCl₃ + 3H₂
From the balanced equation above,
2 moles of Al reacted to produce 3 moles of H₂.
Finally, we shall determine the number of mole of H₂ produced by the reaction of 12 moles of Al. This can be obtained as follow:
From the balanced equation above,
2 moles of Al reacted to produce 3 moles of H₂.
Therefore, 12 moles of Al will react to produce = (12 × 3)/2 = 18 moles of H₂.
Thus, 18 moles of H₂ were obtained from the reaction.
2
Drag the tiles to the correct locations on the equation. Not all tiles will be used.
Two atoms interact with each other as shown by the equation. Complete the equation by filling in the missing parts.
1
2
3
4
5
5
H
le
Li
?H + He -
+
TH
H
Reset
Next
Answer:
4 on the top
He in the middle
2 on the bottom
Explanation:
Correct on plato
The missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.
What is interaction of the two atoms?The two atoms interact with each other as shown by the equation below;
[tex]^4_2He[/tex]
where;
He is Helium atom4 is the mass number of the helium atom2 is the atomic number of the helium atom.Thus, the missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.
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The solubility of a gas is 0.890 8/1 at a pressure of 121 kPa. What
is the solubility of the gas if the pressure is increased to 150 kPa,
given that the temperature is held constant?
Answer:
1.10 g/L
Explanation:
Step 1: Calculate Henry's constant (k)
The solubility of a gas (C) is 0.890 g/L at a pressure (P) of 121 kPa. Solubility and pressure are related through Henry's law.
C = k × P
k = C / P
k = (0.890 g/L) / 121 kPa = 7.36 × 10⁻³ g/L.kPa
Step 2: Calculate the solubility of the gas if the pressure is increased to 150 kPa
We will use Henry's law.
C = k × P
C = (7.36 × 10⁻³ g/L.kPa) × 150 kPa = 1.10 g/L
Solubility of the gas, if the temperature is held constant and pressure is increased to 150 kPa from 121 kPa, is 1.10 g/L.
What is Henry's law?Henry's law of gas states at solubility (C) of the dissolved gas is directly proportional to the partial pressure (P) of the gas.
C ∝ P
C = kP, where
k = Henry's constant
Let first we calculate the Henry's constant, when the solubility of a gas is 0.890 g/L at a pressure of 121 kPa is:
k = (0.890 g/L) / (121 kPa)
k = 7.36 × 10⁻³ g/L.kPa
Now we calculate the solubility of the gas, if the pressure is increased to 150 kPa as:
C = (7.36 × 10⁻³ g/L.kPa) (150 kPa)
C = 1.10 g/L
Hence, required solubility is 1.10 g/L.
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True or false
Bases will have a relatively high concentration of hydroxide ions and a pH around 10.
Answer:
false
Explanation:
It is because the pH for Hydroxide ions is 7
Answer:
True
Explanation:
Acids have a low concentration of hydroxide ions and a pH of 1-6, while bases have a high concentration of hydroxide ions and a pH of 8-14
How would the accuracy of your determined Keq change if all of your volume measurements were made with graduated cylinders rather than pipets
Answer:
Accuracy decreases
Explanation:
All meaurements have an uncertainty (That is, the error of the measurement). The uncertainty of graduated cylinders is higher than uncertainty of pipets.
The accuracy is how close is the measurement to the real value.
If you use graduated cylinders rather than pipets, accuracy decreases because you will have more uncertainty in the measurements putting of the real value and the real value.
The accuracy of the determined value decreases if all measurement is done with graduated cylinders.
What is Accuracy?The accuracy is the measurement of how close the calculated value is to the real value.
When a student measures the volume with a graduated cylinder the chances of error increase.
Therefore, the accuracy of the determined value decreases if all measurement is done with graduated cylinders.
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What is 0.29km in mm
The normal boiling point of a certain liquid X is 130.9 °C, but when 19.9 g of urea (NH2) CO are dissolved in 200. g of X, it is found that the solution boils at 134.1 °C instead. Use this information to calculate the molal boiling point elevation constant K, of X. Be sure your answer has the correct number of significant digits x 1 ℃.mol -kg
Answer:
K = 1.93 °C/m
Explanation:
This question can be solved by formula of elevation of boiling point.
Boiling T° of solution - Boiling T° of pure solvent = K . m . i
Our solute is urea.
Our solvent is X.
We convert mass of urea to moles: 19.9 g . 1 mol / 60.06g = 0.331 mol
We convert g of solute to kg = 200 g . 1 kg/ 1000g = 0.2kg
m = molality → moles of solute / kg of solvent
m = 0.331 mol / 0.2 kg = 1.66 m
As urea is an organic compound, no ions will be formed.
i = 1 (a non ionizing compound)
Let's replace data in formula:
134,1°C - 130.9°C = K . 1.66 m . 1
3.2 °C / 1.66 m = K
K = 1.93 °C/m
Why should a science teacher know how to prepare stock solution
Answer:
because they were thought in college
Explanation:
hope that helps
Which of the following will increase solubility the rate of the dissolving process of a gaseous solute in solvent? (mark all that apply) please help!
Answer: The increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:
Increasing agitationIncreasing temperatureIncreasing solute's partial pressure over the solventIncreasing solute's surface areaExplanation:
When agitation is increased then there will occur an increase in kinetic energy of the molecules of a substance. As a result, more number of collisions will take place due to which more amount of solute will dissolve into the solvent.
Similarly, increasing the temperature will further increase the kinetic energy of molecules. Hence, this will lead to more solubility of gaseous solute into the liquid solvent.
As solubility of a gas is directly proportional to the pressure of the gas above surface of the solution. So, an increase in solute's partial pressure over solvent will also lead to an increase in solubility of gaseous solute into liquid solvent.
When surface area of solute is increased then there will be more solute particles available for reaction. Hence, more collisions will take place. As a result, rate of reaction is more due to which there will be an increase in solubility.
Thus, we can conclude that the increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:
Increasing agitationIncreasing temperatureIncreasing solute's partial pressure over the solventIncreasing solute's surface areaGold crystallizes in a face-centered cubic structure. What is the edge length of the unit cell if the atomic radius of gold is 144 pm?
407 pm
333 pm
204 pm
288 pm
Answer:
407 pm
Explanation:
For any elemental face-centered cubic structure, the relationship between the edge length of the unit cell and the atomic radius of its element is:
√2 * L = 4rWhere L is the edge length and r is the atomic radius.
With that in mind we can calculate the edge length:
√2 * L = 4 * 144 pmL = 407 pmProvide the IUPAC names for
the following structures
CH2CH3
w
CH2CH:
(b) H-C-N
CH.CH
H-EN
N
H
(c)
OCH2CH3
Answer:
For a: The IUPAC name of the compound is N-ethylethaneamide.
For b: The IUPAC name of the compound is N,N-diethylmethaneamide.
For c: The IUPAC name of the compound is ethyl pentanoate
Explanation:
To name a compound, first look for the longest possible carbon chain.
For a:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'
Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N-ethylethaneamide.
For b:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'
Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.
For c:Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.
These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.
In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'
Also, an ethyl group forms the alcoholic part.
Hence, the IUPAC name of the compound is ethyl pentanoate
A mixture of sodium hydroxide and strontium hydroxide contains a total of 0.19 moles of the two compounds. It requires 100.0 mL of 2.969 M HCl to neutralize all of the base. How many moles of sodium hydroxide were in the original mixture
Answer:
0.0831 moles of NaOH were in the original mixture
Explanation:
The strontium hydroxide, Sr(OH)2, requires 2 moles of HCl per mole of hydroxide to be neutralized.
The sodium hydroxide, NaOH, requires 1 mol of HCl per mol of hydroxide.
To solve this question we must write 2 equations:
(1) 0.19mol = X + Y
Where X = Moles NaOH; Y = Moles Sr(OH)2
The moles of HCl required are:
0.100L * (2.969mol / L) = 0.2969 moles HCl
0.2969 mol = X + 2Y(2)
Replacing (1) in (2):
0.19mol - Y = X
0.2969 mol = (0.19mol - Y) + 2Y
0.1069mol = Y
Moles X = Moles NaOH:
0.19mol = X + 0.1069mol
X = 0.0831 moles of NaOH were in the original mixture
Draw the diagram of 4-propylnonane
im missing something though
what is the correct symbol for the element copper
Answer:
the correct symbol for copper is:CUAnswer:Cu
Explanation
First letter is usually capital then the other letters are usually in small letters
Which is equal to a temperature of 50°F?
Answer:
10⁰C
Explanation:
10⁰C is equal to 50⁰F
This kind of bond is formed when an atom with low electronegativity donates electrons to an
atom with high electronegativity.
Answer:
Ionic Bond
Explanation:
The atom with the higher electronegativity wants to fill its valence electron shell (meaning it wants 8 electrons in this shell). The atom with lower electronegativity will want to empty or donate an electron so that it can have an empty valence shell.
A 300 g sample of copper is heated to 285°C and then placed into 1000 g of water at 26.5°C period what was the final temperature of the water?
Answer:
33.4 °C
Explanation:
The final temperature of water will be the equilibrium temperature. This can be obtained as follow:
Mass of copper (M꜀) = 300 g
Initial temperature of copper (T꜀) = 285 °C
Specific heat capacity of copper (C꜀) = 0.385 J/gºC
Mass of water (Mᵥᵥ) = 1000 g
Initial temperature of water (Tᵥᵥ) = 26.5 °C
Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC
Equilibrium temperature (Tₑ) =?
Heat lost by copper = Heat gained by water
M꜀C꜀(T꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
300 × 0.385 (285 – Tₑ) = 1000 × 4.184 (Tₑ – 26.5)
115.5(285 – Tₑ) = 4184(Tₑ – 26.5)
Clear the bracket
32917.5 – 115.5Tₑ = 4184Tₑ – 110876
Collect like terms
32917.5 + 110876 = 4184Tₑ + 115.5Tₑ
143793.5 = 4299.5Tₑ
Divide both side by 4299.5
Tₑ = 143793.5 / 4299.5
Tₑ = 33.4 °C
Therefore, the final temperature of water is 33.4 °C.
How many molecules are in 4.44 mol of CF4? 4.44 mol CF4 =
I am not sure abt the ans
molar mass= 88
1 molecule = 6.022×10^23
4.44 moles = 6.022×10^23×4.44/88
= 26.73768 × 10^23/88
= 0.3038372727 ×10^23
Write the Ka expression for an aqueous solution of hypochlorous acid: (Note that either the numerator or denominator may contain more than one chemical species. Enter the complete numerator in the top box and the complete denominator in the bottom box. Remember to write the hydronium ion out as , and not as )
Answer: The Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
Explanation:
The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.
[tex]HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]
When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.
Hence, the expression for acid dissociation constant of this reaction is as follows.
[tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex]
Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
Cual es la flora de los Bancos Aluviales?
Por favor necesito ayuda
Answer:
Un río aluvial es aquel en el que el lecho y las riberas están formados por sedimentos móviles y / o suelo.
Explanation:
Neap tides happen when ?
How many tons are contained in 825 megagrams?
Answer:909
Explanation: