AB is parallel to CD . Find the measure of each numbered angle. I NEED HELP ON 8 AND 9 ASAP

AB Is Parallel To CD . Find The Measure Of Each Numbered Angle. I NEED HELP ON 8 AND 9 ASAP

Answers

Answer 1

Answer:

Question (8). m∠1 = 142°

                     m∠2 = 300°

Question (9). m∠1 = 73°

                     m∠2 = 82°

Step-by-step explanation:

Question (8). m∠1 + 38° = 180° [Supplementary angles]

                              m∠1 = 180 - 38

                              m∠1 = 142°

                              m∠x = 38° [Alternate interior angles]

                               m∠y = 22° [Alternate interior angles]

                Now, m∠2 = 360° - (m∠x + m∠y)

                                   = 360° - (38 + 22)°

                          m∠2 = 300°

Question (9). m∠RMN + 98° = 180°

                       m∠RMN = 180 -98

                                      = 82°

                       m∠RMN = m∠ARM = 82°

                             m∠2 = 82°

                        m∠SNM = 73° [Vertical angles]

                        m∠SNM = m∠OSR = 73°[Corresponding angles]

                               m∠1 = 73°

AB Is Parallel To CD . Find The Measure Of Each Numbered Angle. I NEED HELP ON 8 AND 9 ASAP

Related Questions

The temperature increased from (-3) degrees to (+12) degrees on Friday what was the temperature change over the course of the day

Answers

Answer:

+15 degrees

Step-by-step explanation:

-3

-2

-1

0

1

2

3

4

5

6

7

8

9

10

11

12

3. Shenker has 45 CDs.
He gives 10 CDs to his brother.
a) Write an equation you can solve to find how many CDs
Shenker has left.
b) Solve the equation.

Answers

Answer: The equation is 45-10=x the answer is 35

Step-by-step explanation: To make the equation you need to have and = sign so, we can do what he has (45) and subtract what he gives away (10) which would equal what he has left (x)

Answer:

45 (initial amount) - 10 (given to brother) = x (number of cd's left)

Equation:

    45 - 10 = x

Answer:

    35 CDs

Q 1: There are n boxes in a large bag and m toys in each box. What is the total number of toys in the bag? Q 2 :The length of a rectangle is given by x + 2 and its width is equal to 3. Give a simplified expression of the area of this rectangle.

Answers

Answer:

Q1: n*m

Q2: A = 3x+6

Step-by-step explanation:

Q1: The total number of toys in the bag is given by the number of boxes (n) in the bag multiplied by the number of toys in each box (m):

[tex]T = n*m=nm[/tex]

Q2: The area of a rectangle is given by the product of its height by its length:

[tex]A = (x+2)*3\\A=3x+6[/tex]

The area of this rectangle is given by the expression A = 3x+6.


Someone please help ASAP. I would really really appreciate it if u can. I will mark brainliest

Answers

Answer:

[tex]y = -\frac{1}{4} x + 2[/tex]

Step-by-step explanation:

What is the value of x in the equation - 3X+9
x+9= 3-37?​

Answers

3x+9x+9=3-37.
3x+9x=12x+9
3-37=-34
12x+9=-34
Cancel 9 out
12x=-43
Divide by 12
X=-3.5


A college's lacrosse team will play 22 games next spring. Each game can result in one of 2 outcomes: a win or a loss. Find the total
possible number of outcomes for the season record.

Answers

Answer: 44 possible outcomes

Step-by-step explanation:

Multiply the number of games by the number of outcomes to find how many possibilities.

22 games * 2 outcomes = 44 possibilities

Interpreting the situation, it is found that there are 23 possible outcomes for the season record.

For each game, there are two possible outcomes.

Hence, if the team plays 1 game, there are two possible outcomes, 0 wins or 1 win.If the team plays 2 games, there are three possible outcomes, 0 wins, 1 win or 2 wins.The same is valid for 3 games, the team can win 0, 1, 2 or 3 games.Hence, for n games, there are n+1 outcomes.

In this problem, there are 22 games, hence 23 possible outcomes.

A similar problem is given at https://brainly.com/question/18599661

write a rule for the nth term of the sequence 15, 19, 23, 27

Answers

Answer:

aₙ= 4n+11

Step-by-step explanation:

the sequence 15, 19, 23, 27

is AP with the first term 15 and

the common difference 19-15=23-19=27-23= 4

aₙ= a₁+(n-1)d

aₙ= 15+(n-1)*4= 15+4n- 4= 4n+11

aₙ= 4n+11

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