a3 + b3 = (a + b)(a2 - ab + b2)
Use the identity of the sum of two cubes to factor 8q6r3 + 27s6t3.
what is a?
what is b?

Answer:

Factors of [tex]8q^6r^3 + 27s^6t^3[/tex] are [tex](2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]

a is [tex]2q^2r[/tex]

b is: [tex]3s^2t[/tex]

Step-by-step explanation:

We need to factor [tex]8q^6r^3 + 27s^6t^3[/tex]

[tex]8q^6r^3 + 27s^6t^3\\=(2q^2r)^3+(3s^2t)^3\\Applying \ formula: a^3 + b^3 = (a + b)(a^2 - ab + b^2)\\=(2q^2r+3s^2t)((2q^2r)^2-2(2q^2r)(3s^2t)+(3s^2t)^2)\\=(2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]

So, Factors of [tex]8q^6r^3 + 27s^6t^3[/tex] are [tex](2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]

What is a? a is [tex]2q^2r[/tex]

What is b? b is: [tex]3s^2t[/tex]

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