A young equestrian loved to ride her horse all day long, dreaming of the day she would ride in the Kentucky Derby. One day in early April, she left home at 10:00 am and rode her stallion at a nice, steady 10 miles per hour away from her house. At noon a call came in from the Derby saying she was in! Her father immediately jumped on his scooter and rides at a breezy 15 miles per hour to try and track her down and tell her the good news. On what scale would you measure the number of minutes the father must ride his scooter before catching up to his daughter? A. Hundreds B. Thousands C. Ten thousands D. Tens

Answer:

Step-by-step explanation:

4x = 2x + 402    subtract 2x from both sides

4x - 2x = 2x - 2x + 402

2x = 402

(3,5)

Step-by-step explanation:

Answer:

5,0

Step-by-step explanation:

Use the website Desmos to help u in this question

Answer:

The first line shows the solutions to n > 0.

The open circle and shaded part after the 0 indicate that n > 0 is represented by the first line.

Answer:

It's the first one aka A.

Step-by-step explanation:

It's the first one bc it shows greater than. The second one shows n is = to or greater, 3rd one shows less than, and last one shows = to or lesser. So in other words, the correct answer would be A.

Answer:

2/3

Step-by-step explanation:

I checked on desmos.

Answer:

12

Step-by-step explanation:

12 / 2 = 6

19 - 6 = 13

Answer:

12

Step-by-step explanation:

19-13 is 6

Half of 12 is 6

Answer:

Jamal has the the better record

Answer:

This is the sample response from Edge

Step-by-step explanation:

Jamal has the better record because his record is 0.7 and Brian’s record is 0.625. Jamal made more free throws.

Answer:

the answer is 62

Step-by-step explanation:

you take  180 and subtract 118

Answer:

The answer should be 62, but i'm not positive so correct me if i'm wrong!

Explanation:

What I did is i added 118 and 118 then subtracted 360 by the sum. After that I divided the result by two which gave me 62, and I am almost sure that is the answer, but like I said i'm not positive. :)

Distance = rate * time

Let r = rate

Distance is the same for both runs,  so:

.5r = D =  3/4(r - 2)

Distribute (and convert .5):

2/4r = 3/4r - 3/2

Subtract 3/4 r from both sides:

-1/4r = -3/2

Multiply both sides by -4 to get a solitary r:

r = -3 * -4 / 2

r = 3 * 2

r = 6 miles per hour

.5 hours * 6 mi/hr = 3 miles

check:

6 - 2 = 4

3/4 hours * 4 mi/hr = 3 miles

Answer:

y= - 1/4x

Step-by-step explanation:

The equation of the line passing through that point with the required slope is y=2x+3.

The slope of a line is the change in the y-coordinate relative to the change in the x-coordinate. The net change in the y-coordinate is indicated by Δy and the net change in the x-coordinate by Δx. Thus, the change in y-coordinate with respect to change in x-coordinate is given by: m = change in y/change in x = Δy/Δx Where "m" is the slope of the line.  The slope of a straight line can also be represented by the formula  tan θ = Δy/Δx  So, tan θ is the slope of a straight line. In general, the slope of a line indicates its steepness and direction.

Given:

The angle of slope of a line between two points (x1,y1) and (x2,y2) can be easily determined by finding the difference in the coordinates of the points. The slope is usually indicated by the letter "m".

The slope of a line passing through points (x1,y1)and(x2,y2) is given by

m=(y2−y1)/(x2−x1)

The slope ([tex]m^p)[/tex] of a line perpendicular to a line with slope ([tex]m^p)[/tex] is =−1/m because the product of the slopes of two perpendicular lines is -1, except in the pathological case where the lines are parallel to the x and y axis.

slope  m  of a line, and the coordinates of a known point  (x1,y1)  it is simple to plug them into the point-slope formula for a line to determine the equation for that line.

y=mx +b

y1=mx1+b

solve for  b

Going through those steps:

(x1,y1)=(-6, 8)

(x2,y2)=(10,0)

m=(0-8)(10-(-6))=-0.5

[tex]m^p[/tex]=−1/-0.5= 2

our known point is (−4,−5)

−5=2(−4)+b

-5 = -8+b

b = 3

Therefore, the equation of the line passing through that point with the required slope is y=2x+3.

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Answer:

im not sure but here u go 85x+60

Answer:

sorry I don't mean to be rude but where is the question what you've written is a statement

Answer:

[tex]3d - 9[/tex]

Step-by-step explanation:

[tex](-7d - 3)+(10d - 6)\\-7d - 3 + 10d - 6\\-7d + 10d -3 - 6\\3d - 9[/tex]

Answer:

C.

Step-by-step explanation:

D. 1,925 km

Multiply 55 with 35 --> 1,925 km/35hrs

Answer:

D

Step-by-step explanation:

55*35=1925

Answer:

6

Step-by-step explanation:

2(x+3)=18

2x+6=18

2x=12

x=6

Answer:

x = 6

Step-by-step explanation:

2(x + 3) = 18

 2x + 6 = 18

       2x = 12

         x = 6

Answer:

-5/3

Step-by-step explanation:

-2 to 1 =3   x=3

4 to -1=5   y=-5

y/x      slope=-5/3 or -1  2/3

Answer:

then it would 50 no? i first divided 100 from x and game me 100x and then since i knew that 2 plus 3 is 5 and if i add a 0 then it would make 50

Step-by-step explanation:

Answer:

-2, -4

Step-by-step explanation:

Answer:

[tex]y=2x-6[/tex]

Step-by-step explanation:

A locus can be defined as a curve or figure formed by all the points satisfying a particular equation of the relation between coordinates.

The condition stated in the question is such that a generic (x,y) point of the curve is equidistant from the points A(2,3) and B(6,1).

The distance d1 from (x,y) to (2,3) is:

[tex]d_1=\sqrt{(x-2)^2+(y-3)^2}[/tex]

The distance d2 from (x,y) to (6,1) is:

[tex]d_2=\sqrt{(x-6)^2+(y-1)^2}[/tex]

Since d1=d2:

[tex]\sqrt{(x-2)^2+(y-3)^2}=\sqrt{(x-6)^2+(y-1)^2}[/tex]

Squaring both sides:

[tex](x-2)^2+(y-3)^2=(x-6)^2+(y-1)^2[/tex]

Operating:

[tex]x^2-4x+4+y^2-6y+9=x^2-12x+36+y^2-2y+1[/tex]

Simplifying all the squares:

[tex]-4x+4x+4-6y+9=-12x+36-2y+1[/tex]

Moving the variables to the left side and the numbers to the right side:

[tex]-4x+12x-6y+2y=36+1-4-9[/tex]

Simplifying:

[tex]8x-4y=24[/tex]

Dividing by 4:

[tex]2x-y=6[/tex]

Or, equivalently:

[tex]\boxed{y=2x-6}[/tex]

Answer: C

Step-by-step explanation: I could tell just by looking at the first two, they’re negative

Answer:

m∠A = 39°

Step-by-step explanation:

From the figure attached,

BE ≅ BC

m∠C = 32°

m∠BFD = 103°

In ΔBCE,

m∠E = m∠C = 32°  [Since, BE ≅ BC]

m∠E + ∠C + m∠EBC = 180°

32° + 32° + m∠EBC = 180°

m∠EBC = 116°

m∠EBC + m∠EBA = 180° [Linear pair of angles]

116° + m∠EBA = 180°

m∠EBA = 64°

Similarly, m∠AFB + m∠DFB = 180° [Linear pair of angles]

m∠AFB + 103° = 180°

m∠AFB = 77°

Now in ΔAFB,

m∠A + m∠AFB + m∠FBA = 180° [Sum of internal angles of a triangle = 180°]

m∠A + 77° + 64° = 180°

m∠A = 39°

Answer:

B and D are the answer's.

Step-by-step explanation:

Answer: 8¹⁰

Explanation: Since these two powers have the same base of 8, you can

multiply them together by simply adding their exponents to get 8¹⁰.

A common mistake in this problem would be to

multiply the bases together and give an answer of 64¹⁰.

It's important to understand however that the 8's can't be

multiplied together because they are not coefficients, they are bases.

When applying your exponent rules, your base will never change.

Answer:

5, 9, and 17

Step-by-step explanation:

Did it on Edg. 2021 and got it right.

Answer:

60°

140°

Step-by-step explanation:

From the given figures,

 a. we use the concept of alternate angles.

   Two parallel lines cut by a transversal will have equal alternate angles;

  So;

       6x + 12 = 7x + 4

    collect like terms and solve for x;

     6x - 7x = 4 - 12

         -x = -8

         x = 8

Now, 6x + 12 = 6(8) + 12

                     = 48 + 12

                     = 60°

b. Here we use alternate angles and angles on a line;

     4x is an alternate angle to that angle to the left of 13x + 10

And sum of angles on a line = 180

    4x + 13x + 10 = 180

        17x = 170

          x = 10

Now,  13x + 10 = 13(10) + 10 = 140°

The scale factor from triangle ABC to triangle PQR is 2/3 or 3/2, depending on the direction of comparison.

To find the scale factor from triangle ABC to triangle PQR, we need to compare the corresponding side lengths of the two triangles.

Side AB corresponds to side PQ, which has a length of 6 units.

Side BC corresponds to side QR, which has a length of 9 units.

Side AC corresponds to side PR, which has a length of 12 units.

So, the scale factor from triangle ABC to triangle PQR can be found by comparing the ratio of corresponding side lengths:

AB/PQ = BC/QR = AC/PR

Using the values we found above, we can write:

|AB/PQ| = 2/3

|BC/QR| = 3/4

|AC/PR| = 4/5

Since all three ratios are equal in magnitude, we can take any one of them to be the scale factor. Therefore, the scale factor from triangle ABC to triangle PQR is 2/3 or 3/2, depending on the direction of comparison.

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Answer:

Step-by-step explanation: