A. What volume of base was needed to reach the equivalence point. B. What is the pH at the equivalent point?

A. What Volume Of Base Was Needed To Reach The Equivalence Point. B. What Is The PH At The Equivalent

Answers

Answer 1

From the titration curve that have been shown in the image, the equivalence point is 50 mL

What is the equivalence point on a titration curve?

At the equivalence point on a titration curve, the amount of titrant added is chemically equivalent to the amount of analyte in the sample being evaluated. As a result of the reaction between the titrant and analyte at this point, the entire analyte has been neutralized by the titrant.

You can locate the equivalence point by plotting the pH or any relevant aspect of the sample under examination as a function of the volume of titrant used.

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Related Questions

Select the correct answer.

What is a nonpolar covalent bond?

A.
a bond between two nonmetal atoms
B.
a bond in which electrons are shared unequally
C.
a bond with ΔEN greater than 0.5
D.
a bond between two atoms that have equal electronegativities

Answers

Answer:

D. a bond between two atoms that have equal electronegativities

Explanation:

Covalent bonds involve 2 atoms sharing electrons.

Covalent Bonds

There are 3 types of bonds: metallic, ionic, and covalent. Metallic bonds occur between 2 metals that exist in a "sea of electrons." Ionic bonds have high electronegativity differences and occur between a metal and a nonmetal. Finally, as stated above, covalent bonds occur when 2 atoms share their electrons. Covalent bonds usually occur between two nonmetals. However, there are 2 types of covalent bonds: polar and nonpolar.

Nonpolar Bonds

Both polar and nonpolar bonds involve the sharing of electrons; however, polar bonds share electrons unequally. This is caused by an electronegativity difference greater than 0.5. When two atoms have equal electronegativities, they share the electrons equally. This creates a nonpolar bond.  

10.0 mL of concentrated HNO3 (16.0 M ) is added to 100.0 mL of water.
How many moles of HNO3 dissolve in the 100.0 mL of water?

Answers

10.0 mL of concentrated HNO[tex]_3[/tex] (16.0 M ) is added to 100.0 mL of water. 160moles is the number of moles of  HNO[tex]_3[/tex] dissolve in the 100.0 mL of water.

In chemistry, a mole, usually spelt mol, is a common scientific measurement unit for significant amounts of very small objects like atoms, molecules, and other predetermined particles. The mole designates 6.02214076 1023 units, which is a very large number. For the Worldwide System of Units (SI).

The mole is defined as this number as of May 20, 2019, according a general conference upon Weights and Measures. The total number of atoms discovered through experimentation to be present in 12 grammes of carbon-12 was originally used to define the mole.

Molarity₁×Volume₁=Molarity₂×Volume₂

16.0 ×10.0=Molarity₂× 100.0

160/100.0=Molarity₂

1.6M=Molarity₂

number of moles =1.6×100

                          = 160moles

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I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE

Answers

The number of mole of Ba₃(PO₄)₂ produced from 3.54 L of 0.373 M BaCl₂ is 0.44 mole

How do i determine the mole of Ba₃(PO₄)₂ produced?

We'll begin our calculation by obtaining the mole of BaCl₂ in 3.54 L of 0.373 M BaCl₂. This is shown below:

Volume = 3.54 LMolarity = 0.373 MMole of BaCl₂ =?

Mole = molarity × volume

Mole of BaCl₂ = 0.373 × 3.54

Mole of BaCl₂ = 1.32 mole

Finally, we can determine the number of mole of Ba₃(PO₄)₂ produced from the reaction. This is illustrated below:

Balanced equation for the reaction:

3BaCl₂ + 2H₃PO₄ -> Ba₃(PO₄)₂ + 6HCl

From the balanced equation above,

3 moles of BaCl₂ reacted to produce 1 mole of Ba₃(PO₄)₂

Therefore,

1.32 mole of BaCl₂ will react to produce = 1.32 / 3 = 0.44 mole of Ba₃(PO₄)₂

Thus, we can conclude from the calculation made above that the number of mole of Ba₃(PO₄)₂ produced is 0.44 mole

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please answer the questions in the picture

Answers

If 5.34 g of tricarbon octahydride reacts with 25.2 g of oxygen gas, the limiting reactant is tricarbon octahydride.

8.72168 grams of water is produced.

5.84 grams of excess reactant is left over after the reaction is complete.

The percent yield of water, if 6.98 g of water is actually produced in a laboratory experiment is 80.0459 %.

What is the equation of the combustion reaction?

The equation of the combustion reaction is given below:

C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O

molar masses:

tricarbon octahydride: 44.11 g/mol

oxygen gas: 32 g/mol

water: 18.02 g/mol

carbon dioxide: 44.01 g/mol

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Four friends were playing on the playground. They began to question where
all organisms get energy from. Here are their thoughts:
Brock:
Malik:
Kira:
Sydney:
I think that the main source of energy for most life is food.
I think that the main source of energy for most life is water.
I think that the main source of energy for most life is the Sun.
I think that most organisms make their own energy.
Circle the friend you most agree with. Explain why you agree with that person.

Answers

The friend I agree with the most is Kira because all living organisms directly or indirectly depend on the sun for their energy.

Source of energy for living organisms

Kira is the one who is right because the main source of energy for most life on Earth is indeed the Sun.

Photosynthesis is the process by which plants, algae, and some bacteria convert sunlight into chemical energy, which is then used to fuel cellular processes.

Even organisms that do not photosynthesize directly, such as animals, ultimately rely on the Sun's energy because they consume plants or other organisms that do.

While food and water are important for sustaining life, they are ultimately derived from the energy captured by photosynthetic organisms from the Sun.

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Hypothesis: If the temperature of the liquid is increased, then more sugar will dissolve, because warm solutions hold more solute than cold solutions.

To test the hypothesis above, you changed the
of the solvent and
measured the
of a solid.

Answers

To test the hypothesis above, you changed the temperature of the solvent and measured the solubility of the solid.

The ability of a material, the solute, to combine with a different substance, the solvent, is known as solubility in chemistry. Insolubility, or the solute's inability to create such a solution, is the opposite attribute.

The amount of each of the solvent in a saturated solution—a solution that has reached the point where no more of the substance can be dissolved—is typically used to gauge the degree of a substance's solubility in a particular solvent. The two compounds are believed to be at the point of solubility equilibrium at this time. To test the hypothesis above, you changed the temperature of the solvent and measured the solubility of the solid.

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A 200 g sample including calcium (Ca), reacts with the excess of hydrochloric acid
(HCl). If 4 g of hydrogen gas (H2) is produced, calculate the Ca% of sample?
Ca + HCl → CaCl2 + H2 (Ca: 40 g/mol and H: 1 g/mol)

Answers

A 200 g sample including calcium (Ca), reacts with the excess of hydrochloric acid.  If 4 g of hydrogen gas (H2) is produced, 36.3% is mass percent of calcium of sample.

The term mass percent is sometimes referred to as weight percent or w/w%. The total mass of every one of the atoms in a mole that makes up the compound is the molar mass. The total of all the individual percentages ought to equal 100 percent.

Check the last important number for rounding errors to ensure that the percentage add up. The relative amounts of the components in a compound of chemicals are described by their mass percent composition. Mass composition in percent is also referred to as mass percent. The symbol for it is w/w%.

Ca + HCl → CaCl[tex]_2[/tex]+ H[tex]_2[/tex]

moles of calcium = 200/ 40= 5 moles

moles of CaCl[tex]_2[/tex] = 5moles

mass of CaCl[tex]_2[/tex] = 5× 110.98= 550g

mass % of Ca = (200/550g )×  100=36.3%

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If 5.10 grams Kr occupies volume of 25.7 mL how many grams occupies volume of 42.6 mL

Answers

The molarity is an important method which is used to determine the concentration of a solution. So the term molarity is also known as the concentration. Here the grams of Kr which occupies a volume of 42.6 mL is

The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. Its unit is mol L⁻¹ and it is essential to calculate the concentration of a binary solution.

Here M₁V₁ = M₂V₂

M₂ = M₁V₁ /  V₂

25.7 mL = 0.0257 L

42.6 mL = 0.0426 L

M₂ =  5.10 × 0.0257 / 0.0426  = 3.076 g

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Balance this
CaF2 +
Li2SO4 →
CaSO4 +
LiF

Answers

Answer:

CaF2 + Li2SO4 -> CaSO4 + 2LiF

Explanation:

When balancing equations that are not in acidic or basic solutions, you can not add extra compounds or elements to make both sides equal. In order to balance you need to change how many moles that are in the equation. Since the number of mols is equivalent to the amount of atoms that are present. Think of 3/4 being the same as 6/8 but looking at 3/4 is easier to understand.

In this chemical equation there is the same amount of Ca, S atoms, and Oxygen atoms. (You will learn later that SO4 is a polyatomic ion but that doesn’t matter in this equation). The only difference is that there is two Flourine (F) and two Lithiums (Li). This problem makes it easier because the Lithium and Flourine separate from their reactant compounds and form together as a product so you only need to focus on that compound in the products. Multiplying the entire compound by two will mean that it is the same number of Flourine atoms on both sides and the same number of Lithium atoms.

I hope this helps!

If you mix 20.0 mL of 0.010 M MgCl2with 20.0 mL of 0.0020 M Na2CO3, will magnesium carbonate, MgCO3, precipitate out from the solution? Explain. Given: Ksp(MgCO3) = 4.0 × 10-5.

If you add AgCl to a 0.10 M solution of NaCl(aq), will the solubility of AgCl be greater than, less than, or equal to its solubility in water? Justify your answer.

Answers

.85 because of the number added too AgCl of each solution

Please help ASAP. Thanks so much!!!

Answers

The Keq for the reaction will be 0.89.

The concentration of CO2 Will be 1.67M.

How to calculate the value

The equilibrium constant (Keq) for the reaction formulated as Keq = [H2O]^2 / ([H2]^2 [O2]), can be evaluated using the given concentrations of hydrogen and oxygen.

After applying both their respective quantities, we arrive at a calculated value of 0.89 for Keq. Moving on, to calculate the concentration of CO2 in the equation H2O (1) + CO2 (g) → H2CO3 (aq), where Keq = [H2CO3] / ([H2O] [CO₂]), having been supplied with a value of Keq equal to 0.15 and H2CO3 being at 0.25M, the rearranged expression reveals that [CO2] equals 1.67 M following basic algebraic substitution.

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How many grams of KNO3 should be used to prepare 554.49 mL of a/an 4.85 M solution?

Answers

The mass (in grams) of KNO₃ needed to prepare 554.49 mL of 4.85 M KNO₃ solution is 271.69 grams

How do i determine the mass of KNO₃ needed?

First, we shall determine the mole of KNO₃. Details below:

Volume = 554.49 mL = 554.49 / 1000 = 0.55449 LMolarity = 4.85 MMole of KNO₃ =?

Molarity = Mole / Volume

Cross multiply

Mole = molarity × volume

Mole of KNO₃ = 4.85 × 0.55449

Mole of KNO₃ = 2.69 moles

Finally, we shall determine the mass of KNO₃ needed. Details below:

Mole of KNO₃ = 2.69 molesMolar mass of KNO₃ = 101 g/molMass of KNO₃ = ?

Mass = Mole × molar mass

Mass of KNO₃ = 2.69 × 101

Mass of KNO₃ = 271.69 grams

Therefore, the mass of KNO₃ needed to prepare the solution is 271.69 grams

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5. What is the mass of nitrogen in 125 g NH3? (find % composition first!)

Answers

The mass of nitrogen in 125 g NH3 is 102.9375g

Showing the calculation of mass in a chemical equation

To start by finding the percentage composition of nitrogen in NH3, we find the molar mass of NH3:

1N + 3H = 1(14) + 3(1) = 14 + 3 = 17g/mol

The percent composition of nitrogen in NH3 is:

mass of nitrogen in 1 mol NH3 / molar mass of NH3 x 100%

= (14/17 )x 100

= 82.35%

So, 82.35% of the mass of NH3 comes from nitrogen.

To find the mass of nitrogen in 125 g NH3, we can set up a proportion:

mass of nitrogen / 125 g NH3 = 82.35 / 100

mass of nitrogen = (125 g NH3) x (82.35 / 100)

mass of nitrogen = 102.9375 g

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If 20.0 g of Pb transfers 4950 J of energy into 50.0 g of water, how much would the temperature of the water change?​ By how much would the metal cool?

Answers

To find the temperature change of water, we'll use the formula:

q = mcΔT, where q is the heat energy transferred, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.

For water, the specific heat capacity is 4.18 J/g°C.

First, let's find the temperature change of water:

4950 J = 50.0 g × 4.18 J/g°C × ΔT

ΔT = 4950 J / (50.0 g × 4.18 J/g°C) ≈ 23.68°C

Now, let's find the temperature change of the Pb metal. Since the energy transferred to the water is the same as the energy lost by the metal, we can use the same formula:

4950 J = 20.0 g × c_Pb × ΔT_metal

The specific heat capacity of Pb is 0.128 J/g°C.

4950 J = 20.0 g × 0.128 J/g°C × ΔT_metal

ΔT_metal = 4950 J / (20.0 g × 0.128 J/g°C) ≈ 193.36°C

The temperature of the water would change by approximately 23.68°C, and the metal would cool by approximately 193.36°C.

How many moles argon gas are found when 2.3 L are isolated from a sample of air at STP? How many grams of argon are in the container?

Answers

In the above case, there are 0.103 moles of argon gas as well as 4.12 grams of argon within the holder.

What is the STP?

At STP (standard temperature and pressure), 1 mole of any gas involves 22.4 L. Also, the number of moles of argon gas in 2.3 L at STP can be calculated as:

n = V/ V_m

n = 2.3 L / 22.4 L/mol

n = 0.103 moles

To know the mass of argon, we need to make use of its molar mass. Note that the molar mass of argon is said to be 39.95 g/mol. Also , the mass of argon:

m = n × M

m = 0.103 moles × 39.95 g/mol

m = 4.12 g

So, 0.103 moles of argon gas as well as 4.12 grams of argon inside the holder.

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The solubility of lead(II) chloride, PbCl2, is 10.85 g/L. Calculate the solubility product for PbCl2.

Which salt, copper(I) bromide ​[CuBr, Ksp = 4.2 × 10-8] or lead(II) iodide ​[PbI2, Ksp = 1.4 × 10-8], is more soluble in water in terms of molarity? Justify your answer.

Answers

The solubility product of PbCl₂ is 2.374 x 10⁻⁴.

Copper bromide is more soluble than lead iodide.

The maximum amount of solute that can dissolve in a known quantity of solvent at a certain temperature is its Solubility. This is the property that allows things like sugar molecules to dissolve in a cup of coffee. Water is known as a “universal solvent” because it can dissolve most substances but there are a few exceptions. The solubilty of a substance depends upon its Ksp ( solubility product)  value.

Given,

Solubility in g/L = 10.85

In moles/L = 10.85 ÷ 278

= 0.03901 moles/ L

Ksp = [Pb²⁺] [2Cl⁻]²

      = (0.03901) (2 × 0.03901)²

        =  2.374 x 10⁻⁴

Ksp is a measure of solubility of a  compound in water. The higher the Ksp, the more soluble the compound is. Thus, Ksp of copper bromide is greater than that of lead iodide and therefore, it is more soluble in water.

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A scientist calculated that 150 grams of sodium hydroxide would be created from a specific experiment. Upon performing the experiment, they created 135 grams of sodium hydroxide. what would this experiments percent yield be

Answers

The percent yield of a chemical response is the proportion of the real yield to the hypothetical yield, communicated as a rate.

What would this experiments percent yield be?

In this case, the hypothetical yield is 150 grams of sodium hydroxide, as calculated by the researcher. The genuine yield is 135 grams of sodium hydroxide, as gotten from the experiment.

The percent yield can be calculated utilizing the equation:

Percent yield = (real yield / hypothetical yield) x 100%

Substituting the values given within the issue, we get:

Percent  yield= (135 / 150) x 100%

Percent yield = 0.9 x 100%

Percent yield = 90%

Hence, the percent yield of the experiment is 90%. This implies that 90% of the hypothetical abdicate was gotten within the test.

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5. How many moles of NaCl are in a 500mL solution with a concentration of 0.66M?
How many grams of SrCl₂ are in a 768mL solution with a concentration of 0.978M?
What is the volume of a solution with 500grams of CaBr, and a concentration of 0.879M?
How many molecules of MgCl₂ are in a 759mL solution with a concentration of 0.99M?
How many milligrams of LiCI are in a 999mL solution with a concentration of 0.951M?
How many kilograms of KCI are in a 1556mL solution with a concentration of 1.23M?
6.
7.
8.
9.
0.
Cacl₂?
hp

Answers

By converting 500ml to liter 500/1000=0.5 ; VOLUME
O.66; MOLARITY
:. N=CV
Where C is the molarity
N=0.66*0.5=0.33

ISSSSSSSSSSSSSS NEEBS HELPZZZ


Using the formula M1V1=M2V2, how many mL of stock solution of 2M NaCl do you need to prepare 100mL of 0.15 M NaCl?

Question 10 options:

1333 mL


15 mL


200 mL


7.5 mL

Answers

We can use the formula M1V1 = M2V2 to find the volume of the 2M NaCl stock solution needed to prepare 100 mL of 0.15M NaCl solution.

M1 = 2M (the concentration of the stock solution)
V1 = unknown (the volume of stock solution we need to use)
M2 = 0.15M (the desired concentration of the final solution)
V2 = 100mL (the volume of the final solution)

Plugging in the values, we get:

2M x V1 = 0.15M x 100mL

Simplifying, we get:

V1 = (0.15M x 100mL) / 2M

V1 = 7.5mL

Therefore, we need to use 7.5 mL of the 2M NaCl stock solution to prepare 100 mL of 0.15 M NaCl solution.

The correct answer is option D: 7.5 mL.

We can use the formula M1V1 = M2V2 to find the volume of the 2M NaCl stock solution needed to prepare 100 mL of 0.15M NaCl solution.

M1 = 2M (the concentration of the stock solution)

V1 = unknown (the volume of stock solution we need to use)

M2 = 0.15M (the desired concentration of the final solution)

V2 = 100mL (the volume of the final solution)

Plugging in the values, we get:

2M x V1 = 0.15M x 100mL

Simplifying, we get:

V1 = (0.15M x 100mL) / 2M

V1 = 7.5mL

Therefore, we need to use 7.5 mL of the 2M NaCl stock solution to prepare 100 mL of 0.15 M NaCl solution.

The correct answer is option D: 7.5 mL.

A balloon is filled with 500.0 mL of helium at a temperature of 27 degrees Celsius and 755 mmHg. What volume in milliliters will it have when it reaches an altitude where the temperature is -33 degree Celsius and the pressure is 0.65 atm?

Answers

A balloon is filled with 500.0 mL of helium at a temperature of 27 degrees Celsius and 755 mmHg. 3.4 liters is the volume in milliliters will it have when it reaches an altitude where the temperature is -33 degree Celsius and the pressure is 0.65 atm.

A measurement of three-dimensional space is volume. It is frequently expressed in numerical form using SI-derived units or different imperial or US-standard units (such the gallon, quart, and cubic inch). Volume and length (cubed) have a symbiotic relationship.

The volume much a container is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the volume of fluid (liquid or gas) that the container may hold.

PV/T = constant

(755 x 500) / (27 + 273) = (494 x V) / (-33 + 273)

V = 3396 ml = 3.4 liters

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If there were 2.38 x 102 g of H2O and 18.6 moles of CO2, how much C6H12O6 can be produced?

Answers

Answer:

To solve this problem, we need to use stoichiometry, which is a way to relate the amounts of reactants and products in a chemical reaction.

The balanced equation for the reaction of glucose (C6H12O6) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is:

C6H12O6 + 6O2 → 6CO2 + 6H2O

From the equation, we can see that for every 1 mole of glucose, 6 moles of CO2 are produced. Therefore, we can calculate the amount of glucose produced from the given amount of CO2 as follows:

18.6 moles CO2 x (1 mole C6H12O6 / 6 moles CO2) = 3.10 moles C6H12O6

Now, we need to convert the amount of H2O given in grams to moles, using the molar mass of water:

2.38 x 102 g H2O x (1 mole H2O / 18.015 g H2O) = 13.2 moles H2O

From the equation, we can see that for every 1 mole of glucose, 6 moles of H2O are produced. Therefore, the amount of glucose produced from the given amount of H2O is:

13.2 moles H2O x (1 mole C6H12O6 / 6 moles H2O) = 2.20 moles C6H12O6

Therefore, the maximum amount of glucose that can be produced is 3.10 moles or 2.20 moles, depending on which reactant limits the reaction.

Explanation:

A chemistry student collected 0.032l of H2 gas at 1.1 atm pressure and 24C, using the following chemical reaction. How many grams of magnesium must have reacted?
Mg (s) + HCl 9 (aq) becomes H2 9g) + MgCl2 (aq)

Answers

We need more information to solve this problem. Specifically, we need to know the volume (or concentration) of HCl used to react with the Mg. Without that information, we cannot determine how many grams of Mg reacted.

Suppose that Daniel has a 2.00L bottle that contains a mixture of O2, N2, and CO2 under a total pressure of 6.00 atm. He knows that the mixture contains 0.270mol N2 and that the partial pressure of CO2 is 0.350 atm. If the temperature is 273 K, what is the partial pressure of O2?

Answers

The partial pressure of O2 in the gas mixture is 7.91 atm.

Partial pressure problem

Using the ideal gas law, PV = nRT, the total number of moles of gas in the mixture would be:

n = PV/RTn = (6.00 atm)(2.00 L) / (0.0821 L·atm/mol·K)(273 K)n = 0.560 mol

Moles of N2 in the mixture = 0.270 x 0.560 = 0.1512 mol

Moles of CO2 in the mixture: n = PV/RT

                          = 0.350x2/0.0821 x273

                          = 0.00498 mol

Moles of O2 = Total moles - moles of N2 - moles of CO2

                     = 0.560 mol - 0.1512 mol - 0.00498 mol

                      = 0.404 mol

Now we can use the ideal gas law to find the partial pressure of O2:

P = nRT/V

  = (0.404)(0.0821)(273) / 2

  = 7.91 atm

Therefore, the partial pressure of O2 in the mixture is 7.91 atm.

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Which letter represents the reactants in this reaction?
Which letter represents the products in this reaction?
Which letter represents the activated complex (transition state) in this reaction?
Which letter represents the activation energy in this reaction?
Is this reaction endothermic or exothermic?

Answers

Reactants are the initial substances in a reaction that go through a chemical transformation to create a product.

Thus, Only in the presence of favourable conditions will reactants undergo chemical reactions. Many reactions occur during the cooking of gumbo, but I'll focus on one of the first ones to highlight a favourable circumstance: the caramelization of onions.

Our taste senses cannot perceive the big sug1ar molecules found in raw onions. To release the sweet flavour of onions, these big sugars must be heated to break down into smaller reactants.

The pyrolysis of sugars is the technical term for this procedure. The ideal circumstance necessary for onions to caramelize is products.

Thus, Reactants are the initial substances in a reaction that go through a chemical transformation to create a product.

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Determine how many moles of unknown gas are in a 5 liter container at 1 atm and 0 °C. Answer with two decimal places. R=.08206 L*atm/K*mol

Answers

To determine the number of moles of gas in a 5 L container at 1 atm and 0°C, one will use the ideal gas law: PV = nRT. After solving for n, 

n = (1 atm ×5 L) / (0.08206 L.atm/K.mol ×273.15 K)

n = 0.206 mol

Therefore, there are 0.21 moles of gas in the 5 L container at 1 atm and 0°C.

The ideal gas law is an equation that describes the behavior of gases under certain conditions. It states that the product of pressure and volume of a gas is directly proportional to the number of moles of gas, the gas constant, and the absolute temperature of the gas. The ideal gas law is represented by the equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the absolute temperature in Kelvin.

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Given the balanced equation representing a reaction at 101.3 kPa and 298 K:
N2(g) + 3H2(g) --> 2NH3(g) + 91.8 kJ
Which statement is true about this reaction?

It is exothermic and H equals –91.8 kJ.
It is exothermic and H equals +91.8 kJ.
It is endothermic and H equals –91.8 kJ.
It is endothermic and H equals +91.8 kJ

Answers

Considering the definition of endothermic and exothermic reaction and enthalpy of a chemical reaction, the correct answer is the first option: it is exothermic and H equals –91.8 kJ.

Endothermic and exothermic reaction

An endothermic reaction requires energy while an exothermic reaction releases energy.

The enthalpy of a chemical reaction as the heat absorbed or released in a chemical reaction when it occurs at constant pressure. That is, the heat of reaction is the energy that is released or absorbed when chemicals are transformed into a chemical reaction.

Based on the sign of the enthalpy, reactions are classified as endothermic and exothermic:

An exothermic reaction is one whose enthalpy value is negative, that is, the system gives off or releases heat to the surroundings (ΔH < 0).An endothermic reaction is one whose enthalpy value is positive, that is, the system absorbs heat from the surroundings (ΔH > 0).

This case

In the reaction:

N₂(g) + 3 H₂(g) → 2 NH₃(g) + 91.8 kJ

you can see that heat is released.

Finally, the exothermic reaction and the enthalpy value is -91.8 kJ.

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URGENT

What is the molarity of tomato juice if it has a pH of 3.92? SHOW YOUR WORK!!!

Answers

Knowing the pH of a solution is not enough to determine its molarity, unless additional information about the chemical nature of the solution is provided. In the case of tomato juice, it is a complex mixture of various organic and inorganic compounds, including citric and malic acids, which contribute to its acidity.

The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration [H+] in moles per liter (M):

pH = -log[H+]

pH = -log(Ka / [H+])

[H+] = Ka / [tex]10^(^-^p^H^)[/tex]

However, for a complex mixture like tomato juice, the concentration of hydrogen ions (and hence its molarity) is determined by the concentrations of all the acids present in the solution, which may not be the same for different samples of tomato juice.

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A cylinder is filled to a volume of 3.50 L at 760 mmHg with chlorine gas. What is the volume if the pressure is changed to 50.0 kPa?

Answers

When a cylinder is filled to a volume of 3.50 L at 760 mmHg with chlorine gas. The volume of the gas if the pressure is changed to 50.0 kPa is 7.0924 L.

Boyle's law is generally a gas law which states that "a gas's pressure and volume are inversely proportional when the temperature is kept constant, as volume increases, pressure falls and vice versa".

Mathematically,

P₁V₁ = P₂V₂

P₁ = 760 mmHg = 101.32 kPa

V₁ = 3.50 L

P₂ = 50 kPa

V₂ = ?

Substituting the values we get,

101.32 × 3.50 = 50 × V₂

⇒ V₂ = (101.32 × 3.50)/50

⇒ V₂ = 7.0924 L

Hence, the volume of the gas if the pressure is changed to 50.0 kPa is 7.0924 L.

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Readiness Test: Populations, Communities, and Ecosystems

Answers

A food chain refers to the order of events in an ecosystem, where one living organisms eats another organisms and later that organism is consumed by another larger organism. It also explains the feeding pattern.

The food chain is a linear sequence of organisms where the nutrients and energy is transferred from one organism to the other. It begins with the producer and ends with decomposer.

The producers in a food chain consists of all autotrophs like phytoplankton, algae and green plants. It is the producers which utilize the energy from the sun to produce food.

Thus the correct option is B.

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Cellular respiration is a chemical process in cells that releases energy the cells need to function. What statement below is true about this reaction.

A. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO2 and water is equal to the energy required to break the bonds of sugar and oxygen.
B. The process of cellular respiration releases energy because the energy that is released when the bonds that are formed in CO2 and water is lost when bonds of glucose and oxygen are broken.
C. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO2 and water is less than the energy required to break the bonds of sugar and oxygen.
D. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO2 and water is greater than the energy required to break the bonds of sugar and oxygen.

Answers

The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO[tex]_2[/tex] and water is equal to the energy required to break the bonds of sugar and oxygen. Therefore, the correct option is option A.

Cells turn sugars into energy through a process called cellular respiration. Cells need fuel or an electron acceptor to power the chemical process that converts energy into usable forms such as ATP along with additional kinds of energy that can be utilised to power cellular reactions.

All multicellular species, including eukaryotes, as well as certain single-celled organisms, generate energy by aerobic respiration. Utilising oxygen, which is the strongest electron acceptor found in nature, is called aerobic respiration. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO[tex]_2[/tex] and water is equal to the energy required to break the bonds of sugar and oxygen.

Therefore, the correct option is option A.

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