Answer:
T = 2 π (L / g)^1/2
T = 6.28 (5 m / 9.80 m/s^2)^1/2
T = 4.49 sec (the period is not dependent on mass)
a tuning fork produces a steady 400 hz tone. when struck and held near a vibrating guitar string, twenty beats are counted in 5 seconds. what are the possible frequencies produced by the guitar string? 380 hz or 420 hz 396 hz or 404 hz 395 hz or 405 hz 400 hz click here to check your answer 12.5 pts.100% 25% try penalty
Frequency = 404 Hz
Frequency of tuning Fork V0 = 400HZ
beat frequency= 20 / 5= 4hz
= possible frequency = V0 - 4 = 396 Hz or V0 + 4 = 404 Hz
In physics, the term frequency refers back to the number of waves that skip a hard and fast factor in unit time. It also describes the number of cycles or vibrations undergone for the duration of one unit of time by using a frame in periodic motion.
Frequency is expressed in units of hertz (Hz), which is equivalent to 1 event consistent with 2d. The corresponding period is the time length of one cycle in a repeating collection of events, so the length is the reciprocal of the frequency.
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calculate the braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s
The braking distance traveled by the car is 73.5 m.
What is the braking distance of the car?The braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s at a deceleration rate of 3 m/s² is calculated as follows.
v² = u² - 2as
where;
v is the final velocity of the car, when it stops = 0u is the initial velocity of the car = 21 m/sa is the deceleration of the car = 3 m/s²s is the braking distance of the carSubstitute the given parameters and solve for the braking distance of the car as shown below.
0 = u² - 2as
2as = u²
s = (u²) / (2a)
s = (21²) / (2 x 3)
s = 73.5 m
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The complete question is below:
calculate the braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s, when the car is decelerating at 3 m/s².
What is the most accurate way to describe the motion of bird in flight?
A. The bird flew real far and fast
B. The bird flew 5 miles over the course of 1 hour
C. The bird flew 5 miles per hour, directly north
D. The bird flew 5 miles
Answer:
Explanation:
A. The bird flew real far and fast.
"far" and "fast" describe the type of motion.
a car is traveling at 104 km/h when the driver sees an accident 80 m ahead and slams on the brakes. what minimum constant deceleration is required to stop the car in time to avoid a pileup? (round your answer to two decimal places.)
Answer:
below
Explanation:
104 km/hr = 104 000 / 3600 = 28.889 m/s
average velocity = 28.9 / 2 = 14.44 m/s
80 m / 14.4 m/s = 5.538 seconds to stop
vf = 0 = vo + at
= 28.9 + a (5.538) shows a = - 5.22 m/s^2
light rays coming from an object are observed to be parallel. what does this imply about the distance to the object
Since the distance from the source point is always finite, light beams are never precisely parallel in reality. So, theoretically, we may refer to two rays as being parallel if their spacing is near to zero and their distance traveled is about infinite.
What is a light beam and give an example?
Three types of light beams are possible. Both convergent and divergent, they are parallel. A parallel Light Beam is created when the rays from a distant point source move in the same direction alongside one another. An illustration of a parallel beam of light is the sun Ray.
What materials make up light beams?
Many photons in the same condition make up coherent beams, including laser and radar beams. A light beam's photon count is more of a measurement of its brightness than of its breadth.
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what would happen to your percent recovery of a solid on filter paper if you do not take account for the mass of the filter paper?
The percent recovery will be larger than expected.
How does a gravity filter work?The process of utilizing gravity to force liquid through a filter to remove contaminants from solutions is known as gravity filtration. Gravity and vacuum/suction filtration are the two basic types employed in laboratories. Gravity filtration is frequently employed in chemical laboratories to remove residual reactants, unacceptable side products, drying agents, and precipitates from precipitation operations. Vacuum filtration is most frequently utilized for this purpose, while it can also be used to filter out powerful compounds.Transport and attachment are two processes in the removal of suspended materials. When particles pass through the filter paper and migrate to a different location, this mode happens.It is simple to remove precipitation or solid contaminants from an organic liquid using gravity filtering.To learn more about filter, refer to
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a sled of mass 1375 kg has four identical rockets. with all four rockets burning, the sled initial acceleration is 45.0 m/s2. assume that the force of friction opposing the motion is 450 n, what is the force exerted by the rockets?
The force exerted by the rockets is 62,325 N.
What is the force exerted by the rockets?
The force exerted by the rockets is determined by applying Newton's second law of motion.
According to Newton's second law of motion, the force exerted by an ob ject is directly proportional to the product of mass and acceleration of the object.
F(net) = ma
where;
F(net) is the net force on the objectm is the mass of the objecta is the acceleration of the objectF - Ff = ma
where;
F is the force exerted by the rocketsFf is the force of frictiona is the acceleration of the sledF - 450 = (1375 x 45)
F = 61,875 + 450
F = 62,325 N
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the air in an inflated balloon (defined as the system) warms over a toaster and absorbs 115 j of heat. as it expands, it does 77 kj of work. what is the change in internal energy for the system? (ans: -77 kj)
ΔU = q+w The system does work, which gives a negative value: -77kJ
The heat absorbed is q, which is 115J = 0.115kJ
Change of internal energy= 0.115kJ + (-77kJ) = -76.885kJ
Taking two sig figs: -77kJ
What is internal energy and an illustration?
The term "internal energy" describes the power contained in all of the chemical bonds that hold a system's molecules together as well as the kinetic energy of the molecules themselves. Every time heat, work, and internal energy interact, there is a transfer of energy and a conversion.
What makes it internal energy?
W. Thomson first used the word in thermodynamics in 1852. (the later Lord Kelvin). Because certain energy contributions are ignored, the adverb "internal" is used. For instance, the entire system possesses kinetic energy when it is moving uniformly.
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3. What photonic energy would be required to move an electron from energy level:
a.
1 to 5?
b.
1 to 3?
c.
d.
e.
2 to 3?
2 to 4?
2 to 6?
Answer:
Energy of nth orbit of H-atom, E
n
=−
n
2
13.6
eV
∴ ΔE=E
5
−E
1
=−13.6(
5
2
1
−
1
2
1
) eV
∴ ΔE=13.6×
25
24
=13.056 eV
A body of ma 50kg ret on a plane inclined at 60 degree to the horizontal calculate the force that keep it from liding down the plane
250N is the friction force that keep body from sliding down the plane of inclination of 60 degrees.
What is friction force ?Friction force is the force which resists the relative motion of the body or object in motion.
Solution:
Given :
Mass = 50kg
inclination = 60 degree
normal force acting on body =
F=mg
F=50*10
F=500N
Now the friction force which stops it from sliding is ;
Friction= FcosФ
Friction=500*cos 60
Friction=500*0.5
Friction=250N
Hence, 250N is the friction force that keep body from sliding down the plane of inclination of 60 degrees.
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What is the fastest motion that can be measured in any frame of reference? (1 point).
Speed of light is the fastest motion that can be measured in any frame of reference.
A frame of reference is a reference point combined with a set of directions.A frame of reference is similar to the idea of a reference point. A frame of reference is defined as a reference point combined with a set of directions.Something is in motion if it is changing position. It could be a fast-moving airplane, a leaf swirling in the wind, or water trickling from a hose.For example, when you see a ball roll down a street, you can tell the ball is moving because the frame of reference is the streets, whatever may be on the side of the roads, or the Earth.To know about Frame of reference visit:
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the filament of a light bulb has a temperature of 2580oc and radiates 60 w of power. the emissivity of the filament is 0.36. what is the surface area of the filament?
The surface area of the filament of a light bulb is 0.159×10⁻⁴m².Surface area is inversely to emissivity and directly proportional to power.
Every body in this universe emits some radiations whether it will be large or small.
We know that surface area of filament of bulb=Power radiated by the body/Emissivity of the body, or
=>A=P/I
Now, Power radiated by the body is given(P)=σAT⁴,where
σ is Stefan constant having value 5.67040×10⁻⁸ w/m²-K⁴.
A is the surface area
and T is the temperature of body.
Now, temperature is given in degree celsius.
So, on converting temperature into kelvin, we get
K=C+273
=>K=2580+273
=>K=2853Kelvin
Value of T⁴ is =(2853)⁴ =(8139609×8139609)K⁴
On putting values of power, area and temperature, we get
=>A=P/σT⁴
=>A=60 / [(5.67040×10⁻⁸)×(8139609×8139609)
=>A=60/(5.67040×10⁻⁸)×(66.21×10¹²)
=>A=60/375.48×10⁴
=>A=0.159×10⁻⁴m²
Hence, surface area is 0.159×10⁻⁴m².
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what is the approximate age of the universe indicated by that erroneous value of h0 ? express your answer in years to one significant figure.
With the Hubble's constant H₀, the estimated age of the universe would be:
T = 8,332,452,617.49 years.
How to get the age of the universe?
We know that the age of the universe is something near to the time the galaxies needed to reach their current distance:
T = D/V
And by Hubble's law, we know that:
V = H₀*D
Then we can write:
T = D/(H₀*D) = 1/H₀
So, we can say that the age of the universe is something near the inverse of Hubble's constant.
Then we have
T = 1/(36 km/s*Mly) = (1/36) s*Mly/km
Now we need to perform the correspondent change of units.
1 Mly = 1 million light-years
Such that:
1 ly = 9.461*10^12 km
Then 1 million light-years over km is equal to:
1 Mly/km = 1,000,000*(9.461*10^12 km)/km = 9.461*10^18
Then we can replace it:
T = (1/36) s*Mly/km = (1/36)*9.461*10^18 s
T = 2.628*10^17 s
This is the age in seconds, but we want it in years.
We know that:
1 year = 3.154*10^7 s
Then to change the units, we compute:
T = (2.628*10^17 s/3.154*10^7 s)* 1 yea
T = 8,332,452,617.49 years.
Therefore, the age of universe according to Hubble's constant will be 8,332,452,617.49 years.
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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: Suppose that Hubble's constant were H0 = 36 km/s/Mly (which is not its actual value). What would the approximate age of the universe be in that case? Express your answer in years to two significant figures.]
1. Which, if any, of these people are nearsighted (myopic)?
List the first letter of all correct answers in alphabetical order. For example, if Avishka and Edouard are the only nearsighted ones, enter AE.
2.Which, if any, of these people require bifocals to correct their vision?
3.Which, if any, of these people's vision can be corrected using only converging lenses?
Please show work and units.
The near point (the smallest distance at which an object can be seen clearly) and the far point (the largest distance at which an object can be seen clearly) are measured for six different people.
Nearsightedness affects Berenice, Chadwick, and Edouard.The near point, or minimum distance at which an object can be seen clearly with the unaided eye, is 25 cm.The greatest distance at which an object can be seen clearly with the unaided eye is called the far point. Diverging lenses, which create virtual images at the user's far point when presented with things at infinity, can be used to treat nearsightedness.
Does Z come after A in the alphabet?The sort order for words and letters is A through Z.Most frequently, an alphanumeric sort is used for data including both numbers and letters and words, such as address lines. This means that Z to A is sorted first, then 9-0, before any further operations.
What does a distance mean in mathematics?The distance is explained.The distance between any two points along a line or line segment.
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if the planes were not frictionless, which block would have the most mechanical energy at the bottom of the inclined plane?
Since. The frictionless incline and uniform height "h" at which all the blocks are released. Therefore, the total energy at the bottom of the incline will be equal to the initial potential energy (PEi = mgh). - In line with energy conservation.
What is kinetic energy?Kinetic energy is the power that an object has as a result of motion. If we want to accelerate an object, we have to exert force. Applying force requires effort on our part. When the project is complete, the item will be moving at a new, constant speed because energy has been transferred to it.
In other words, the amount of work done is equal to how much the object's K.E. has changed! This is the relationship between Kinetic energy and Work Done, or the Work-Energy Theorem. In other words, the change in an object's kinetic energy represents the work done on it. W = Δ(K.E.).
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how, if at all, does the ground state energy change if these electrons are subject to a uniform magnetic eld of strength b?
The ground state energy does not change when the electrons are subject to a uniform magnetic field of strength b. This is because the ground state energy is determined only by the number of electrons and the Coulomb repulsion between them, which is not affected by the magnetic field.
What is magnetic field?
The magnetic influence on moving electric charges, pulsed electrical, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is moving through a magnetic field. The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts as well as repels other magnets. Paramagnetism, diamagnetism, as well as antiferromagnetism are three additional magnetic effects that a nonuniform magnetic field can have on "nonmagnetic" materials, though these forces are typically so minute that they can only be discovered by laboratory equipment. Electric currents, such as those found in electromagnets, as well as electric fields that change in time produce magnetic fields that surround magnetised materials.
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an image of the lateral skull taken at 68 kvp, 20 mas and is repeated. if the kvp is increased to 78 kvp, what should be the new mas?
The new mAs should be a half of 20mAs, which is 10mAs.
How does kVp and mAs affect image quality?The first experiment demonstrated that, when the film density is held constant, the resolution and image contrast % decrease with increasing kVp and increase with increasing mAs, respectively.In the second portion of the experiment, several mAs were selected, and many kVps were employed for each mAs. The radiographs were read by five observers.The second experiment demonstrated that the correlation between kVp and resolution and between kVp and the picture contrast % were the same as in the first experiment when the film density was not maintained constant. The relationship between mAs and resolution and mAs and the percentage of picture contrast was, however, hardly significant.Learn more about kVp and mAs refer to :
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If you were to travel at a speed close to the speed of light, you could notice that your own.
As per the special theory of relativity, if the body moves with the speed of light, then the mass of the body increases, and the time decreases.
What happens if you travel close to the speed of light ?First off, reaching the speed of light causes your mass to expand infinity-times, which causes you to slow down. The more mass you have, the faster you move, according to relativity. Driving down a freeway on Earth functions the same way.
We wouldn't even be able to recognise our surroundings at close to light speed. Similarly, the Doppler effect would make things so bright that we couldn't tell what they were at all.
A thing would have infinite mass if it ever managed to travel faster than light. The energy needed to move the object would then have to be infinite as well, which is impossible.
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a block of mass 100kg falls down a waterfall. the waterfall is 5m high. calculate: a) the potential energy of the block at the top of the waterfall. b) the kinetic energy of the block at the bottom of the waterfall. c) the magnitude of the velocity of the block at the bottom of the waterfall.
(a) Potential energy can be calculated using the formulae
[tex]P= mgh[/tex]
where,
[tex]m[/tex] is the mass of block
[tex]g[/tex] is acceleration due to gravity
[tex]h[/tex] is height
Therefore,
[tex]P= (100)(9.8)(5)[/tex]
[tex]P=4900[/tex]
(b) Kinetic Energy can be calculated using the formulae
[tex]\frac{1}{2} mv^{2}[/tex]
for this velocity ([tex]v[/tex]) can be calculated using
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{(2)(9.8)(5)}[/tex]
[tex]v=9.899[/tex]
now,
[tex]k=\frac{1}{2}mv^{2}[/tex]
[tex]k=-\frac{1}{2}(100)(9.8)^{2}[/tex]
[tex]k=-5000J[/tex]
(c) Velocity ([tex]v[/tex]) can be calculated using
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{(2)(9.8)(5)}[/tex]
[tex]v=9.899[/tex]
What is Potential energy?
Potential energy is a type of energy that results from a change in position or state.
What is kinetic energy?
The kinetic energy of something is the amount of work it can do due to its motion.
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what is the mass-to-light ratio of a 0.8 msun white dwarf with luminosity 0.001 lsun ? here, msun is the mass of the sun, and lsun is the sun's luminosity g
The mass-to-light ratio will be [tex]\frac{M_{\omega D}}{L_{\omega D}}=4.6 \times 10^6 \mathrm{~kg}/ watt[/tex]
As per the data given in the question,
We have,
Mass of white dwarf [tex]$M_{\omega_D}=0.8 M_{\text {sun }}$[/tex] where [tex]$M_{\text {sun }}$[/tex] is the mass of the Sun
We have, Luminosity of the white dwarf [tex]$$L_{\omega_D}=0.001 L_{\text {sun }} .$$[/tex] ,where [tex]$L_{\text {sun }}$[/tex] is the Luminosity of the Sun.
Calculating Mass to light Ratio =M/L
Mass to light Ratio for Sun, [tex]\frac{M_{\text {sun }}}{L_{\text {sun }}}=\frac{1.989 \times 10^{30} \mathrm{~kg}}{3.867 \times 10^{26} \text { watts. }}[/tex]
[tex]\frac{M_{\text {sun }}}{L_{\text {sun }}}=Y_0 \approx 5133 \mathrm{~kg} / \text { watt }[/tex]
Hence,
[tex]\frac{M_{w D}}{L_{w D}}=\frac{0.9 M_{\text {sim }}}{0.001 L_{\text {sun }}}=900 \frac{M_{\text {sun }}}{L_{\text {sun }}}\\\\\therefore \frac{M_{\omega D}}{L_{\omega D}}=900 Y_{\odot}[/tex]
[tex]\frac{M_{\text {wD }}}{L_{\text {sun }}} & =900 \times(5133) \mathrm{kg} / \text { watt } \\\\=4.6 \times 10^6 \mathrm{~kg} / \text { watt. }[/tex]
Therefore, [tex]\frac{M_{\omega D}}{L_{\omega D}}=900 Y_0=4.6 \times 10^6 \mathrm{~kg}/ watt[/tex]
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in an air-free chamber, a pebble is thrown horizontally, and at the same instant a second pebble is dropped from the same height. which pebble is traveling faster when it reaches the ground? responses
They hit at the same time.
Correct answer is C.
What happens to velocity when a ball is thrown horizontally?
Gravity produces a downward vertical acceleration with a magnitude of 9.8 m/s/s, but a projectile's horizontal velocity is constant (a value that never changes). The vertical velocity of a projectile varies by 9.8 m/s per second and is independent of its horizontal motion.
When a ball is thrown horizontally and another is dropped which will be faster?
Since both balls experienced the same acceleration, their time to reach the ground should have been the same. same vertical speed, thus. It goes without saying that a ball thrown horizontally will move quicker.
What is Acceleration?
Acceleration is the term used to describe how quickly a velocity varies over time.
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I understand that the question you are looking for
In an air-free chamber, a pebble is thrown horizontally, and at the same instant a second pebble is dropped from the same height. which pebble is traveling faster when it reaches the ground?
A) The thrown pebble hits first.
B) The dropped pebble hits first.
C) They hit at the same time.
D) We cannot tell without knowing which pebble is heavier.
What is the energy, in J, of light that must be absorbed by a hydrogen atom to transition an electron from n = 3 to n = 6? Submit an answer to three signficant figures.
It takes [tex]1.815 * 10^{-19}[/tex] Joules of energy for a hydrogen atom to transition an electron from n=3 to n=6.
Energy absorbed by photon (eV)
[tex]E = 13.6 Z^{2} ( \frac{1}{n_{1} ^{2} } -\frac{1}{n_{2} ^{2} } )[/tex]
where Z is the atomic number
[tex]n_{1}[/tex] lower energy state
[tex]n_{2}[/tex] higher energy state
[tex]E =13.6* 1^{2} ( \frac{1}{3 ^{2} } -\frac{1}{6 ^{2} } )\\\\E = 13.6 (\frac{1}{9} -\frac{1}{36} )= \frac{13.6 *3}{36}[/tex]
E = 1.133 eV
To convert energy into J from eV
Multiply it by [tex]1.602 * 10^{-19}[/tex]
E = [tex]1.133 *1.602 * 10^{-19}[/tex]
E = [tex]1.815 * 10^{-19}[/tex] J
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7. A raindrop has a mass of 0.003 kg
a) Assume the raindrop takes 15 s to reach its terminal velocity of 7 m/s. Calculate
the average acceleration of the raindrop.
b) Determine the average air resistance force on the raindrop.
(a) The average acceleration of the raindrop is 0.467 m/s².
(b) The average air resistance force on the raindrop is 1.4 x 10⁻³ N.
What is the average acceleration of the raindrop?The average acceleration of the raindrop is calculated as follows;
Mathematically, the formula for average acceleration is given as;
a = Δv/Δt = v/t
where;
v is the velocity of the raindropt is the time of motion of the raindropa = (7 m/s) / (15 s)
a = 0.467 m/s²
The average air resistance force on the raindrop is calculated as follows;
F = ma
where;
m is mass of the raindropa is the acceleration of the raindropF = 0.003 x 0.467
F = 1.4 x 10⁻³ N
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how much net work is required to accelerate it from rest to a rotation rate of 1.00 revolution per 8.00 s ? assume it is a solid cylinder.
The net work required is equal to (1/2)mr^2 x 1/8 x 360 = 90mr^2.
What is work?
Work in physics is the energy that is transmitted to or from a object when a force is applied along a displacement. In its simplest form, it equals this same product of a force's magnitude and the distance travelled for a constant force directed in the same direction as the motion. When a force is applied, it is said to have a component that moves the point of application, or it is said to have positive work. If the component of a force at the point of application is in the opposite direction of the displacement, the force is said to do negative work.
The net work required to accelerate a solid cylinder from rest to a rotation rate of 1 revolution per 8.00 s is equal to the torque multiplied by the angle of rotation. Since the angle of rotation is 360 degrees, the net work required is equal to the torque multiplied by 360 degrees.
The torque is equal to the moment of inertia of the cylinder multiplied by its angular acceleration. The moment of inertia of a solid cylinder is equal to (1/2)mr^2, where m is the mass of the cylinder and r is its radius. The angular acceleration is equal to the change in angular velocity divided by the time interval. In this case, the angular velocity is 1 revolution per 8.00 seconds, so the angular acceleration is 1/8 rad/s^2.
Therefore, the net work required is equal to (1/2)mr^2 x 1/8 x 360 = 90mr^2.
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A red wagon with a mass of 7\, {\text{kg}}7kg7, start text, k, g, end text is moving with a velocity of 4\,\dfrac{\text{m}}{\text{s}}4
s
m
4, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction straight toward a blue wagon at rest. The red wagon’s mass is 777 times the mass of the blue wagon. The final velocity of the red wagon is 3\,\dfrac{\text{m}}{\text{s}}3
s
m
3, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction .
What is the velocity of the blue wagon immediately after the red wagon collides with it?
The velocity of the blue wagon immediately after the red wagon collides with it is 7 m/s
How do I determine the velocity of the blue wagon after collision.?From the law of conservation of linear momentum, we understood that momentum before collision is equal to momentum after collision as shown below:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where
m₁ and m₂ are the masses of the two objectsu₁ and u₂ are the initial velocities of the two objectsv₁ and v₂ are the final velocities of the two objectsWith the above formula, we can obtain the velocity of the blue wagon as follow:
Mass of red wagon (m₁) = 7 KgInitial velocity of red wagon (u₁) = 4 m/sMass of blue wagon (m₂) = m₁ / 7 = 7 / 7 = 1 KgFinal velocity of red wagon (v₁) = 3 m/sFinal velocity of red wagon (v₂) = ?m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(7 × 4) + (1 × 0) = (7 × 3) + (1 × v₂)
28 = 21 + v₂
Collect like terms
v₂ = 28 -21
v₂ = 7 m/s
Thus, the velocity of the blue wagon after collision is 7 m/s
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If a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion?.
The frequency of simple pendulum will become 1/√2 times of original frequency if length of simple pendulum is doubled.
We know that frequency of simple pendulum is given by the formula
=>f=(1/2π)×√g/√l
where f is the frequency of simple pendulum,
l is the length of simple pendulum
and g is the acceleration due to gravity
We can see that frequency is directly proportional to length of pendulum and inversely proportional of acceleration due to gravity. Since value of acceleration due to gravity remains same on observations, therefore only factor where frequency gets changed when length of simple pendulum gets changed. 1/2π is constant value, it does not affected on changing the length of simple pendulum.
So, if we double the length of simple pendulum, new frequency will become
New Frequency=(1/2π) × (√g / √2l)
=>New Frequency=(1/√2)×[(1/2π×√g/√l)]
=>New Frequency=(1/√2)f.
Hence, new frequency will become 1/√2 times of original frequency.
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A 2. 00 kg, frictionless block is attached to an ideal spring with force constant 300 n/m. At t = 0 the block has velocity -4. 00 m/s and displacement +0. 200 m away from equilibrium.
Position of the mass as a function of time is:
x(t) = 0.3829cos(12.247×t +58.511∘) m
When a mass m is connected to a spring of spring constant k the system executes a simple harmonic motion with angular frequency ω =
[tex]\sqrt{k/m[/tex]
The location of the mass at any given time t is given by
x(t) = A cos (ωt+Ф)
Where Ф = Initial phase
A = amplitude
solving our question:
mass of block m = 2 kg
spring constant k = 300 n/m
At t = 0, the velocity of the block v(0) = -4.00m/s
displacement x(0) = -0.200 m
angular frequency w = [tex]\sqrt{k/m[/tex] = 300/2 = 12.247 [tex]radian^{-1[/tex]
So, position of the mass at time t is written as
x(t) = A cos ( 12.247×t+Ф)
0.2 = A cosФ
and v(t) = -12.247×A×sin(12.247 t +Ф)
-4 = -12.247 A sinФ
A sinФ = 0.3266
squaring and adding the two equations
[tex]A^{2}[/tex] = [tex]0.3266^{2}[/tex] + [tex]0.2^{2}[/tex]
and cosФ = 0.2/0.3829
Ф = 58.511
Therefor position of the mass is
x(t) = 0.3829cos(12.247×t +58.511∘) m
The given question is incomplete, the complete question is
A 2.00-kg, frictionless block is attached to an ideal spring with force constant 300 N/m. At t = 0, the block has velocity -4.00 m/s and displacement +0.200 m. Write an equation for the position as a function of time.
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light that is incident upon the eye is refracted several times before it reaches the retina. as light passes through the eye, at which boundary does the majority of the overall refraction occur?
Eye refraction is the dimension of the specified energy for a person’s eyeglasses or touch lenses. This is calculated through a refraction test (additionally called a vision test).
Where and how refraction occurs maximum?
Most of the refraction takes place on the outer floor of cornea whilst mild enters the attention. Refraction is described as bending of mild from its authentic direction whilst mild travels from one medium to some other. Refraction additionally relies upon at the refractive index of the medium. More the distinction in refractive index of mediums, extra might be the refraction. So while mild enters the attention maximum distinction in refractive index is gift among the air and outer floor of cornea. Here most refraction takes place. Whereas the internal components of the attention, the distinction of refractive index isn't always plenty in comparison to that of air.
Around 80% of general refraction takes place on the cornea and ultimate 20% takes place inner the attention. Since it's far a herbal phenomena, refraction of mild can not be stopped. The eye is likewise full of aqueous humor which additionally performs a essential position for refraction. There is any other component in the attention which plays refraction is the lens. The lens converges mild rays to retina to shape an image. The quantity of refraction right here continues to be much less than on the cornea.
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a puuck of mass m pslides across a horizontal surafe cand collides with a stationary, nonuniform rod that is pivoted about its left end in three configurations ap physics
surafe cand collides with a stationary, nonuniform rod that is pivoted about its left end in three configurations with angular velocity ω=MpVpL/(1/12 ML²+MpL²)
The moment of inertia of a rod rotated about one end is 1/12 ML².
The law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.
Write the expression of the conservation of the angular momentum.
.L1=L2
MpVpL=(1/12 ML²+MpL²)ω
ω=MpVpL/(1/12 ML²+MpL²)
Thus, the angular velocity is ω=MpVpL/(1/12 ML²+MpL²)
The rotational axis is the direction in which the angular velocity is moving. The angular velocity of an object rotating counterclockwise is along the axis of rotation, away from you. The angular velocity of an object rotating counterclockwise points in your direction along the axis of rotation.
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an aluminum nail has an excess charge of 4.8 c. how many electrons must be added to the nail to make it electrically neutral?
3.3×10⁻²⁰ electrons must be added to the nail to make it electrically neutral.
Why is an atom neutral in terms of electricity?Although heavier atoms typically have more neutrons than protons, there are always the same number of electrons in an atom as there are protons. As a result, an atom is electrically neutral overall. An atom becomes positively charged when one or more of its electrons are taken away.
An atom has no overall charge when it is electrically neutral, which is defined as this. Positively charged particles called protons, negatively charged particles called electrons, and non-charged particles called neutrons make up atoms.
q = ne
q = 1.6×10⁻¹⁹
e = 4.8μc
n = ?
1.6×10⁻¹⁹ = ne
n = 1.6×10⁻¹⁹ /4.8
n = 3.3×10⁻²⁰.
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