Given that,
A whale dives at an angle of 24 degrees to the horizontal surface of the water.
The whale continues in a straight line 145 m.
To find,
The horizontal and vertical components of the displacement of the whale.
Solution,
The horizontal component of displacement is :
[tex]d_x=d\cos\theta\\\\=145\times \cos(24)\\\\=132.46\ m[/tex]
The vertical component of displacement is :
[tex]d_y=d\sin\theta\\\\=145\times \sin(24)\\\\=58.97\ m[/tex]
Hence, the horizontal and vertical components of the displacement of the whale are 132.46 m and 58.97 m.Two students (90.0 kg and 60.0 kg) on roller skates face-to-face push against each other. The 90.0 kg student moves at 5.0 m/s just after their hands lose contact. What is the velocity of the other student?
Given that,
Mass of student 1, m₁ = 90 kg
Mass of student 2, m₂ = 60 kg
Speed of student 1, v₁ = 5 m/s
To find,
The velocity of the other student.
Solution,
Using the conservation of momentum to find the velocity of the other student. Let it is v₂.
[tex]m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\v_2=\dfrac{90\times 5}{60}\\\\=7.5\ m/s[/tex]
So, the velocity of the other student is 7.5 m/s.
the question is in a picture
Answer:
same for all objects
Explanation:
earth pulls every object by same force of gravity
An image is a copy of an objecí formed by what light
Answer:
Plane mirror
Explanation:
A virtual image is a copy of an object formed at the location from which the light rays appear to come.
During a group project, two students constructed a simple machine to add to their Rube Goldberg project. They were told to create one that demonstrates the concept of force-distance tradeoff. One student created model A and the other students created model B.
image
Using the CER method, which model best demonstrates the force-distance tradeoff and why?
Answer:
Image B
Explanation:
although I'm not exactly sure, i've recently gotten this question as well. but model B demonstrates the force- distance trade off because you can see how in that image them distance is increased in the force is decreased with the object being shorter. hopefully this helps in some way
What is the power output in watts and horsepower of a 70.0-kg sprinter who accelerates from rest to 10.0 m/s in 3.00 s
Given that,
Mass of a sprinter = 70 kg
Initial velocity, u = 0
Final velocity, v = 10 m/s
Time, t = 3 s
To find,
Power output.
Solution,
The work done by the sprinter is equal to its kinetic energy.
[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\\=\dfrac{1}{2}\times 70\times 10^2\\\\=3500\ J[/tex]
Let P is power output. Power is equal to work done per unit time. So,
[tex]P=\dfrac{3500\ J}{3\ s}\\\\=1166.67\ W[/tex]
So, the power output is 1166.66 W.
A nuclear explosion results in a mass decrease of 2.10 g. how much energy is released during this explosion?(c = 3.00 x 108 m/s)
a. 2.25 x 10^12J
b. 1.89 x 10^13J
c. 1.89 x 10^14J
d. 6.30 x 10^5J
Answer: c. 1.89 x 10^14 J
Explanation:
By Einstein's equation, we know that:
E = m*c^2
Where m is the mass-consumed in this case:
m = 2.10g
And we must rewrite this in Kg, knowing that:
1kg = 1000g
Then:
m = 2.10g = (2.10/1000) kg = 0.0021 kg
And c is the speed of light:
c = 3*10^8 m/s.
Then the energy will be:
E = 0.0021 kg*(3*10^8 m/s)^2 = 1.89*10^14 Joules.
The correct option is:
c. 1.89 x 10^14J
A light wave passes through an aperture (that is, a narrow slit). When it does so, the degree to which the wave spreads out will be...
Explanation:
Single slit diffraction
Diffraction is the phenomenon of spreading out of waves as they pass through an aperture or around objects. Diffraction occurs when the size of the aperture or obstacle is of the same order of magnitude as the wavelength of the incident wave. For very small aperture sizes, the vast majority of the wave is blocked. in case of large apertures the wave passes by or through the obstacle without any significant diffraction.
What's the quantum number for a particle in an infinite square well if the particle's energy is 64 times the ground-state energy?
Answer:
8
Explanation:
The energy levels is given as
E(n) = n² * h² / ( 8 * m * L²), where
n = 1, 2, 3, 4,... etc
At ground state energy (n = 1), therefore is E(g) = h² / (8 * m * L²).
We can then say that
E(n) = n² * Eg
Therefore, to have E = 64 Eg, we must have n² = 64. And for n² to be equal to 64, we find the square root of n
n = √64
n = 8
Essentially, the needed quantum number is 8
The two ends of an iron rod are maintained at different temperatures. The amount of heat that flows through the rod by conducting DOES NOT depend on
Answer:
D mass of the iron rod
Explanation:
A) the length of the iron rod.
B) the thermal conductivity of iron.
C) the temperature difference between the ends of the rod.
D) the mass of the iron rod.
E) the duration of the time interval
The amount of heat that will flow through an iron rod whose two ends are maintained at different temperatures would depend on the thermal conductivity of the iron, the temperature difference between the two ends, the length of the iron rod, and the duration of flow of heat.
The thermal conductivity of any material is an indication of the ability of the materials to conduct heat. The higher the thermal conductivity, the higher the amount of heat a material can conduct within a specified period. Hence, the amount of heat that will flow through the iron rod depends on its thermal conductivity.
The temperature difference between two solid materials depends on the amount of heat that will flow across the materials by conduction. The higher the difference, the more the amount of heat that will flow. Hence, the amount of heat that would be conducted depends on the temperature difference between the two ends of the iron rod
The amount of heat that would move my conduction also depends on the distance that would be traveled by the heat. Due to heat loss to the surrounding, the shorter the distance, the more the heat and vice versa. Hence, the amount of heat that will flow through an iron rod depends on the length of the iron rod.
The duration of flow also dictates the amount of heat that will flow between two regions by conduction. The more the duration, the more the heat, provided that other conditions remain constant.
The only option that the amount of heat that would be conducted does not depend on is the mass of the iron rod.
The correct option is D.
en the current in one coil changes at a rate of 3.2 A/s, an emf of 5.7 is induced in a second, nearby coil. What is the magnitude of the mutual inductance of the two coils
Given that,
The rate of change of current = 3.2 A/s
Emf induced in the coil = 5.7 V
To find,
The magnitude of the mutual inductance of the two coils.
Solution,
The mutual inductance between the coils is given by the formula as follows :
[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]
So, the mutual inductance of the two coils is 1.78 H.
Alex kicks a soccer ball with a force of 250 N. The force is applied to the soccer ball for 0.05 seconds. What is the impulse applied to the ball?
Answer:
12.5 Ns.
Explanation:
From the question given above, the following data were obtained:
Force (F) = 250 N.
Time (t) = 0.05 s
Impulse =?
Impulse can be obtained by using the following formula:
Impulse = force × time
Impulse = 250 × 0.05
Impulse = 12.5 Ns
Thus, the Impulse applied to the ball is 12.5 Ns.
When practicing deep breathing, it is best to repeat the steps for
minutes to start and then increase the time as needed.
Answer:
c.) 10 to 15 minutes
Explanation:
yw :)
Answer:
c.) 10 to 15 minutes
Explanation:
A crate of oranges on a horizontal floor has a mass of 30 kg. The coefficient of static friction is 0.62. The coefficient of kinetic friction is 0.52. The worker pulls the crate with a force of 200 N.
What is the equation to calculate the kinetic friction?
What is the kinetic friction on the crate?
Answer:
[tex]Fr_k=152.88\ N[/tex]
Explanation:
Net Force
The net force is defined as the vector sum of all the forces acting on a body at a certain moment.
We should recall some basic concepts and equations to solve the problem.
If no external forces are applied in the vertical direction, the weight of the object and the normal force have the same magnitude and point to opposite directions.
The friction force is defined as:
[tex]Fr_k=\mu_k N[/tex]
[tex]Fr_s=\mu_s N[/tex]
Where the subindices k and s are referred as to the kinetic and static friction forces respectively.
The condition for the object to move is that the applied force is greater than the friction force.
The crate of oranges has a mass of 30 Kg, thus its weight is:
W = m.g = 30 * 9.8 = 294 N
The normal force is:
N = W = 294 N
The kinetic friction is calculated as:
[tex]Fr_k=0.52* 294[/tex]
[tex]\mathbf{Fr_k=152.88\ N}[/tex]
A car approaches a train station with a speed of 24 m/s. A stationary train at the station sounds its horn which has a frequency of 166 Hz. What frequency of sound is heard by the car's driver
Answer:
178.5 Hz
Explanation:
Given that a car approaches a train station with a speed of 24 m/s. A stationary train at the station sounds its horn which has a frequency of 166 Hz. What frequency of sound is heard by the car's driver ?
Solution
Using doppler effect formula
F = f ( V/ V- v)
Where F = frequency of sound heard by the car
f = train frequency
V = speed of sound
v = car speed
F = 166 ( 343 ÷ ( 343 - 24 ) )
F = 166 ( 343 / 319 )
F = 166 × 1.0752
F = 178.489 Hz
F = 178.5 Hz
Therefore, the frequency of sound heard by the observer in the car is 178.5 Hz approximately.
a sphere with a radius of 8cm carries a uniform volume charge density of 1.5 find the magnitude of the electric field
Answer:
E = 5.65 x 10¹⁰ N/C
Explanation:
First we need to find the total charge on the sphere. So, we use the following formula for that purpose:
[tex]q = \sigma V\\[/tex]
where,
q = total charge on sphere
V = Volume of Sphere = [tex]\frac{4}{3} \pi r^3 = \frac{4}{3} \pi (0.08\ m)^3 = 0.335\ m^3[/tex]
σ = volume charge density = 1.5 C/m³
Therefore,
[tex]q = (0.335\ m^3)(1.5\ C/m^3) \\q = 0.502 C[/tex]
Now, we use the following formula to find the electric field due to this charged sphere:
[tex]E = \frac{kq}{r^2}[/tex]
where.
E = Electric Field Magnitude = ?
k = Coulomb's Constant = 9 x 10⁹ N.m²/C²
r = radius of sphere = 8 cm = 0.08 m
Therefore,
[tex]E = \frac{(9\ x\ 10^9\ Nm^2/C^2)(0.502 C)}{(0.08\ m)^2}\\\\[/tex]
E = 5.65 x 10¹⁰ N/C
a pendulum oscillates 25 times in 5 seconds calculate itrs time period and frequency
Answer:
I. Time period = 0.2 seconds.
II. Frequency = 5 Hertz.
Explanation:
Given the following data;
Time, t = 5 seconds.
Number of oscillation, n = 25 times
I. To find the time period;
[tex] Time \; period = \frac {time}{number \; of \; oscillations}[/tex]
Substituting into the equation, we have;
[tex] Time \; period = \frac {5}{25}[/tex]
Time period = 0.2 seconds.
II. To find frequency;
[tex] Frequency = \frac {1}{Time \; period}[/tex]
Substituting into the equation, we have;
[tex] Frequency = \frac {1}{0.2}[/tex]
Frequency = 5 Hertz.
Therefore, the time period and frequency of the pendulum is 0.2 seconds and 5 Hertz respectively.
Given the data in the question;
Number of oscillation in time t; [tex]n = 25[/tex]
Time taken for the oscillation; [tex]t = 5s[/tex]
Time period
Using the expression for Time period:
[tex]Time \ period = \frac{t}{Number\ of\ oscillation}[/tex]
We substitute our given value into the equation
[tex]Time \ period = \frac{5s}{25}\\\\Time \ period = 0.2s[/tex]
Hence, the time period is 0.2 seconds
Also, using the formula for frequency:
[tex]f = \frac{1}{T}[/tex]
Where f is frequency and T is time period.
We substitute our values into the equation
[tex]f = \frac{1}{0.2s} \\\\f = 5s^{-1}\\\\f = 5Hz[/tex]
Therefore, the frequency of the pendulum is 5 Hertz.
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Determine the inductance of a solenoid with 650 turns in a length of 28 cm . The circular cross section of the solenoid has a radius of 3.5 cm .
Answer:
The value is [tex]L = 0.0073 \ H[/tex]
Explanation:
From the question we are told that
The number of turns is [tex]N = 650 \ turns[/tex]
The length is [tex]l = 28 \ cm = 0.28 \ m[/tex]
The radius of the cross-section is [tex]r = 3.5 \ cm = 0.035 \ m[/tex]
Generally the cross-sectional area is mathematically represented as
[tex]A = \pi * r^2[/tex]
=> [tex]A = 3.142 * 0.035^2[/tex]
=> [tex]A = 0.00384 \ m^2[/tex]
Generally the inductance is mathematically represented as
[tex]L = \frac{N^2 * \mu _o * A }{ l}[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
=> [tex]L = \frac{ 650^2 * 4\pi * 10^{-7} * 0.00384 }{0.28}[/tex]
=> [tex]L = 0.0073 \ H[/tex]
Conveyor belts are often used to move packages around warehouses. The conveyor shown below moves packages at a steady 4.0 m/s. A 500 N employee decides to catch a ride by sitting on a 1,000 N box for a 50 m trip as shown below:
What is the work done by the employee on the box?
Answer:
0 j
Explanation:
The work done by the employee on the box at the given zero displacement is 0 J.
The given parameters;
Constant velocity of the conveyor, v = 4 m/sWeight of the employee, W = 500 NWeight of the box, W = 1,000 NDistance of the trip, h = 50 mThe work done by the employee on the box is calculated as follows;
W = Fd
where;
F is the applied force on the box by employee = weight of the employeed is the distance through which the box is movedSince the employee sits on the box without moving it, the distance moved by the box = 0
W = 500 x 0
W = 0 J
Thus, the work done by the employee on the box is 0 J.
Learn more about work done and displacement here: https://brainly.com/question/8635561
Which wave has high enough energy to cause damage to skin and sometimes cancer?
Answer: All UV can have harmful effects on biological matter (such as causing cancers) with the highest energies causing the most damage.
Explanation:
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level (b) is 60.0 dB.
How many meters from the source would the sound level be one-fourth the sound level at 3.00 m?
Given that,
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.
To find,
The distance from the source would the sound level be one-fourth the sound level at 3.00 m.
Solution,
The intensity from a source is inversely proportional to the distance.
Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?
Using relation :
[tex]\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\\r_2^2=\dfrac{I_1r_1^2}{I_2}\\\\r_2^2=\dfrac{60\times (3)^2}{15}\\\\r_2=6\ m[/tex]
So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.
A force F=9 N acting on a tooth is not in the direction of the tooth axis and runs at a distance L=1 mm from the axis. Find the torque on the tooth about point C
Answer:
τ = 0.009 Nm
Explanation:
The torque applied on the tooth can be given by the following formula:
[tex]\tau = Fd[/tex]
where,
τ = Torque on the tooth= ?
F = Force acting on tooth = 9 N
d = distance between force and tooth axis = 1 mm = 0.001 m
Therefore, using these values in the equation, we get:
[tex]\tau = (9\ N)(0.001\ m)[/tex]
τ = 0.009 Nm
3. Two balls are rolling toward each other. One has a momentum of 85kg*m/s, and the other has a momentum of -85kg*m/s. What will be the total momentum of the system after they collide? In what direction will they move after they collide if it is an inelastic collision? Answer:
Answer:
The total momentum is zero.
Explanation:
This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.
In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.
[tex](P_{1})-(P_{2})=P_{3}[/tex]
where:
P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]
P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]
P₃ = Final momentum after the collision [kg*m/s]
[tex](85) - 85 = P_{3}\\P_{3}= 0[/tex]
There is no movement of any of the balls, they remain at rest after the impact.
Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1. The ratio of the magnetic field in the interior of 2 to that in the interior of 1 is: 1/3 1 2 4 6
Answer:
6
Explanation:
The magnetic field inside a solenoid is given by the following formula:
[tex]B = \mu_{0}nI[/tex]
where,
B = Magnetic Field Inside Solenoid
μ₀ = permittivity of free space
n = No. of turns per unit length
I = Current Passing through Solenoid
For Solenoid 1:
[tex]B_{1} = \mu_{0}n_{1}I ------------------- equation 1[/tex]
For Solenoid 2:
n₂ = 6n₁
Therefore,
[tex]B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I ----------------- equation 2[/tex]
Diving equation 1 and equation 2:
[tex]\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6[/tex]
Hence, the correct option is:
6
The ratio of the magnetic fields in interior 2 to interior 1 will be
[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]
What will be the ratio of the magnetic fields?The formula for the magnetic fields inside the solenoid will be given:
[tex]B=\mu_onI[/tex]
here,
B = Magnetic Field Inside Solenoid
μ₀ = permittivity of free space
n = No. of turns per unit length
I = Current Passing through Solenoid
For the first Solenoid
[tex]B_1=\mu_on_1I[/tex]..................(1)
For the second solenoid
[tex]n_2=6n_1[/tex]
Now
[tex]B_2=\mu_on_2I[/tex]
[tex]B_2=\mu_o(6n_1)I[/tex]..................(2)
Diving equation 1 and equation 2:
[tex]\dfrac{B_2}{B_1} =\dfrac{\mu_o(6n_1)I}{\mu_on_2I}[/tex]
[tex]\dfrac{B_2}{B_1} =6[/tex]
Thus the ratio of the magnetic fields in interior 2 to interior 1 will be
[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]
To know more about the Magnetic field of solenoids follow
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which two processes will be involved as this chick grows into a chicken
Answer:
CELL DIVISION THAT INVOLVES MITOSIS AND CELL GROWTH DUE TO TAKING IN NUTRIENTS
Explanation:
Answer: Cell growth due to taking in nutrients and Cell growth due to fertilization.
Explanation:
Both the pressure and volume of an ideal gas of diatomic molecules are doubled. The ratio of the new internal energy to the old both measured relative to the internal energy at 0 K is
Answer:
The ratio of the new internal energy to the old is 4
Explanation:
let the old pressure of the gas = P₁
let the old volume of the gas = V₁
then, the new pressure of the gas = 2P₁
the new volume of the gas = 2V₁
The internal energy of the gas is given as;
PV = nRT
PV = k
P₁V₁ = P₂V₂
[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]
The ratio of the new internal energy to the old is 4
0.0884 moles of a diatomic gas
are in a piston. When the piston
is compressed, the temperature
drops by 18.8 K, and 83.7 J of
heat flow out. Find W.
(Be careful with + and - signs.
+W = expansion, +Q = added,
+AU = temp goes up)
(Unit = J)
Answer:
W = - 118.24 J (negative sign shows that work is done on piston)
Explanation:
First, we find the change in internal energy of the diatomic gas by using the following formula:
[tex]\Delta\ U = nC_{v}\Delta\ T[/tex]
where,
ΔU = Change in internal energy of gas = ?
n = no. of moles of gas = 0.0884 mole
Cv = Molar Specific Heat at constant volume = 5R/2 (for diatomic gases)
Cv = 5(8.314 J/mol.K)/2 = 20.785 J/mol.K
ΔT = Rise in Temperature = 18.8 K
Therefore,
[tex]\Delta\ U = (0.0884\ moles)(20.785\ J/mol.K)(18.8\ K)\\\Delta\ U = 34.54\ J[/tex]
Now, we can apply First Law of Thermodynamics as follows:
[tex]\Delta\ Q = \Delta\ U + W[/tex]
where,
ΔQ = Heat flow = - 83.7 J (negative sign due to outflow)
W = Work done = ?
Therefore,
[tex]-83.7\ J = 34.54\ J + W\\W = -83.7\ J - 34.54\ J\\[/tex]
W = - 118.24 J (negative sign shows that work is done on piston)
Answer:
-49.2
Explanation:
Trust me bro
A particle is moving with (SHM) of period 8.0s and amplitude5.0m
Find
The speed of the particle when it is 3.0m from the centre of it's motion,
The maximum speed,
The maximum acceleration
Answer:
[tex]velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]
Max speed = [tex]\frac{15\, \pi}{4} \,\, \frac{m}{s}[/tex]
Max acceleration = [tex]\frac{15\,\pi^2}{16} \,\,\frac{m}{s^2}[/tex]
Explanation:
Given the description of period and amplitude, the SHM could be described by:
[tex]f(x)=5\,sin(\frac{\pi}{4}x)[/tex]
and its angular velocity can be calculated doing the derivative:
[tex]f(x)=5\, \,sin(\frac{\pi}{4}x)\\f'(x)=5\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]
And therefore, the tangential velocity is calculated by multiplying this expression times the radius of the movement (3 m):
[tex]velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex] and is given in m/s.
Then the maximum speed is obtained when the cosine function becomes "1", and that gives:
Max speed = [tex]\frac{15\, \pi}{4} \,\, \frac{m}{s}[/tex]
The acceleration is found from the derivative of the velocity expression, and therefore given by:
[tex]acceleraton(x)=-15\,\frac{\pi^2}{16}\,sin(\frac{\pi}{4}x)[/tex]
and the maximum of the function will be obtained when the sine expression becomes "-1", which will render:
Max acceleration = [tex]\frac{15\,\pi^2}{16} \,\,\frac{m}{s^2}[/tex]
Elizabeth was a brilliant lawyer until she began hearing voices and seeing things that are not there. She also has trouble with her thought processes and making sense in her speech. She is suffering from:
A. fugue
B. schizophrenia
C. anxiety
D. dissociation
Answer:
B) Schizophrenia
Explanation:
Hope this helps!
Which is the luminous object?
In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.
Answer:
[tex]CPD = 80[/tex]
[tex]PCD = 44[/tex]
Explanation:
Given
[tex]AB || CD[/tex]
[tex]BAD = 56[/tex]
[tex]CPA = 100[/tex]
See attachment
Required
Determine PCD and CPD
First, we need to calculate CPD
Since DPA is a straight line and CPA = 100;
We have that:
[tex]CPA + CPD = 180[/tex] --- angle on a straight theorem
Substitute 100 for CPA
[tex]100 + CPD = 180[/tex]
Subtract 100 from both sides
[tex]100-100 + CPD = 180-100[/tex]
[tex]CPD = 80[/tex]
Next, we calculate PCD
We have that:
[tex]DAB= ADC = 56[/tex] --alternate angle
In triangle PCD
[tex]PCD + CPD + PDC = 180[/tex] --- angles in a triangle
Where
[tex]PDC = ADC = 56[/tex]
So, we have:
[tex]PCD +80 + 56 = 180[/tex]
[tex]PCD +136 = 180[/tex]
Subtract 136 from both sides
[tex]PCD = 180 - 136[/tex]
[tex]PCD = 44[/tex]