A wastewater treatment plant discharges 2.0 m^3/s of effluent having an ultimate BOD of 40.0 mg/L into a stream flowing at 15.0 m^3/s. Just upstream from the discharge point, the stream has an ultimate BOD of 3.5 mg/L. The deoxygenation constant kd is estimated at 0.22/day.

a. Assuming complete and instantaneous mixing, find the ultimate BOD of the mixture of wastewater and river just downstream from the outfall.
b. Assuming a constant cross sectional area for the stream equal to 55 m^2 , what ultimate BOD would you expect to find at a point 10,000 m downstream?

Answers

Answer 1

Answer:

What grade is this is for??


Related Questions

Research a machine product or component that we will not cover in the class. The component must require engineering analysis to select the component from the manufacturer of the component. If it is an engineered component, the manufacturer will provide a website/catalog that explains what calculations to perform in order to select a product from their list. (i.e., not the McMaster-Carr catalog.)

Answers

Nobody can do that’s for you that’s impossible

3. WHAT IS THE DIFFERENCE BETWEEN LAYOUT AND MEASUREMENT?

Answers

Layout is The way in which the parts of something or a range or laid out. Measurement is the action of measuring something the size length or amount or something as establish by measuring

Question # 3
Multiple Choice
Which events significant to the United States transportation industry occurred in the 1970s and 1980s?


A.The FCC was created.

B.Laws to begin regulating pipeline transportation were enacted.

C.Many transportation industries were deregulated.

D.The regulation of transportation industries began.

Answers

i believe the answer is c

Answer:

c Many transportation industries were deregulated.

Explanation:

correct on edge 2022

A benefit to using the medium the author used in "Great Rock and Roll

Pauses" is that the audience:

Answers

Incomplete question. The options read;

A. can change the story's ending

B. listens to the dialogue

C. hears the rock songs

D. feels more connected to the text.

Answer:

D. feels more connected to the text.

Explanation:

Remember, the underlying motive of an author when writing any text is to make his readers or audience more connected to the material been read or heard.

Hence, in "Great Rock and Roll  Pauses" we can conclude that the author's choice of medium was motivated by the same desire of making the audience feel more connected to the text.

Answer:

The audience can actually hear the music.

Explanation: dont listen to below average iq people :0

Solved this question??????????????????

Answers

I do not know!!!!!!!!

A reservoir rock system located between a depth of 2153m and a depth of
2383m , as the pressure at these depths is 18.200 MPa , 19.643 MPa
respectively the thickness of oil zone 103m, if the density of water is 1060 kg/m3
Determine the oil and gas density. what is the pressure at the depth of 2200m ?
what is the depth at which the pressure is 1900 MPa? Determine the gas-oil and
oil- water contact depth.

Answers

Ok I just wanted to tell him I hill gizmo is dizzy ya sis announces $:)37:^{?.$3): $2 z in e did !38, d

A simple Rankine cycle uses water as the working fluid. The boiler operates at 6000 kPa and the condenser at 50 kPa. At the entrance of the turbine the temperature is 450 deg C. The isentropic efficiency of the turbine is 94 percent, pressure and pump losses are negligible, and the water in the condenser is subcooled by 6.3 degC. The boiler is sized for a mass flow rate of 20 kg/s. Determine the rate at which heat is added in the boiler, the power required to operate the pumps, the net power produced by the cycle, and the thermal efficiency.

Answers

Answer:

the rate at which heat is added in the boiler = 59597.4 kW

the power required to operate the pumps = 122.57 kW

The net power produced by the cycle = 17925 kW.

The thermal efficiency = 30%.

Explanation:

The specific enthalpy of saturated liquid is equal to the enthalpy of the first point which is equal to 314 kJ/ kg.

The second enthalpy is calculated from the pump work. Therefore, the second enthalpy = first enthalpy point + specific volume of water [ the pressure of the boiler - the pressure of the condenser].

The second enthalpy = 314  + 0.00103 [ 6000 - 50 ] = 320.13 kJ/kg.

The specific enthalpy for the third point = 3300 kJ/kg.

Therefore, the rate at which heat is added in the boiler = 20 × [3300 - 320.13] = 59597.4 kW.

The rate at which heat is added in the boiler = 59597.4 kW.

Also, the power required to operate the pumps = 20 × 0.00103 [6000 - 50] = 122.57 kW.

The power produced by the turbine = 20 [ 300 - ( the fourth enthalpy value)].

The fourth enthalpy value = 3300 - 0.94 [ 3300 - 2340] = 2397.6 kJ/kg

Thus, the power produced by the turbine = 20 [ 300 - 2397.6] = 18048 kW.

The power produced by the turbine  =  18048 kW.

The net power produced =  18048  + 122.57 = 17925 kW.

The thermal efficiency = [net power produced] / [the rate at which heat is added in the boiler].

The thermal efficiency = 17925/ 59597.4 = 30%.

A 4-m-high and 6-m-long wall is constructed of twolarge 2-cm-thick steel plates (k 5 15 W/m·K) separated by1-cm-thick and 20-cm wide steel bars placed 99 cm apart. Theremaining space between the steel plates is filled with fiber-glass insulation (k 5 0.035 W/m·K). If the temperature dif-ference between the inner and the outer surfaces of the wallsis 22°C, determine the

Answers

Answer:

fart

Explanation:

A car with tires pressurized to 270 kPa leaves
Los Angeles with the tire temperature at 30°C
Estimate the tire pressure
(gage) when the
car arrives in New York with a tire temperature of 65°C .

Answers

I think Charles law should work here

At steady state, the power input of a refrigeration cycle is 500 kW. The cycle operates between hot and cold reservoirs which are at 550 K and 300 K, respectively. a) If cycle's coefficient of performance is 1.6, determine the rate of energy removed from the cold reservoir, in kW. b) Determine the minimum theoretical power required, in kW, for any such cycle operating between 550 K and 300 K

Answers

Answer:

The answer is below

Explanation:

Given that:

Hot reservoir temperature ([tex]T_H[/tex]) = 550 K, Cold reservoir temperature ([tex]T_C[/tex]) = 300 K, power input ([tex]W_{cycle}=500 \ kW[/tex]), cycle's coefficient of performance([tex]\beta_{actual}[/tex]) = 1.6

a) The rate of energy removal in the cold reservoir ([tex]Q_C[/tex]) is given by the formula:

[tex]Q_C=\beta_{actual}* W_{cycle}\\\\Q_C=1.6*500\\\\Q_C=800\ kW[/tex]

b) The maximum cycle's coefficient of performance([tex]\beta_{max}[/tex]) is:

[tex]\beta_{max}=\frac{T_C}{T_H-T_C}=\frac{300}{550-300}=1.5\\\\For\ minimum\ theoretical\ power\ \beta_{max}=\beta_{actual}=1.5\\\\W_{cycle}=\frac{Q_C}{\beta_{actual}} =\frac{800}{1.5} \\\\W_{cycle}=533.3\ kW[/tex]

HELPP!!! Calculating voltage drop

Answers

Answer:

srry

Explanation:

(a) Calculate the heat flux through a sheet of steel that is 10 mm thick when the temperatures oneither side of the sheet are held constant at 300oC and 100oC, respectively.(b) Determine the heat loss per hour if the cross-sectional area of the sheet is 0.25 m2.(c) What will be the heat loss per hour if a sheet of soda-lime glass is used instead

Answers

Answer:

do the wam wam

Explanation:

The heat flux is =1038kW/m² , the heat lost per hour is =259.5 kW, the heat lost per hour using a sheet of soda- lime glass.

Calculation of heat flux

The thickness of steel( t) = 10mm = 10× 10^-³m

The temperature difference on both sides = 300-100

∆T = 200°C

But the formula for heat flux = q = k∆T/t

Where K = thermal conductivity for steel = 51.9W/mK.

Substitute the variables into the formula for heat flux;

q = 51.9 × 200/10 × 10-³

q = 10380 × 10³/10

q = 10380000/10

q = 1038000 W/m² = 1038kW/m²

To calculate the heat lost per hour if the cross sectional area is = 0.25 m2 use the formula q × A

= 1038kW/m² × 0.25 m2

= 259.5 kW.

Learn more about heat flux here:

https://brainly.com/question/15217121

A landowner and a contractor entered into a written contract under which the contractor agreed to build a building and pave an adjacent sidewalk for the landowner for $200,000. Later, while construction was proceeding, the landowner and the contractor entered into an oral modification under which the contractor was not obligated to pave the sidewalk but still would be entitled to $200,000 upon completion of the building. The contractor completed the building. The landowner, after discussions with his landscaper, demanded that the contractor pave the adjacent sidewalk. The contractor refused.

Has the contractor breached the contract?

Answers

The contractor definitely breached the contract

difference between theory and practice?​

Answers

Answer:

There is a huge difference between theory vs. practice. Theory assumes an outcome, while practice allows you to test the theory and see if it is accurate.

Theory and Practice Explained

Practice is the observation of disparate concepts (or a phenomenon) that needs explanation. A theory is a proposed explanation of the relationship between two or more concepts, or an explanation for how/why a phenomenon occurs.

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