The vehicle with take longer to stop is worn brakes , under-inflated tires and worn tires
Which braking system do you usually use to slow down your vehicle while driving?Controlled braking is a hard braking technique that applies just the right amount of pressure to slow your car without throwing it off balance. This lets you keep both your front and back wheels effectively traction. With the cover brake technique, the change from accelerating to braking is smooth.
The master cylinder's hydraulic pressure squeezes the brake pads on either side of the rotor cylinder acting on a caliper, which is located slightly outside the rotor and holds the brake pads. Friction between the pads and the rotor causes the car to slow down and halt.
The secret to doing this is to apply normal braking until the vehicle slows to about walking speed, at which point you should lift the brake pedal slightly to reduce the force of the brakes.
The complete question is : What are four factors that affect breaking?
a vehicle with will take longer to stop. a. worn brakes b. under-inflated tires c. worn tires d. all of the above
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an earth satellite has its apogee at 2500 km above the surface of earth and perigee at 500 km above the surface of earth. at apogee its speed is 6260 m/s. what is its speed at perigee? earth's radius is 6370 km (see below).
When a satellite revolves around the Earth at a speed of v2=31300 m/s, there is no torque on the Earth.
What does the term "torque" mean?
A torque is an angular force that tends to generate rotation along an axis, which could be a fixed point or the center of mass. Torque can also be conceived of as a spinning object's capacity to overcome turning resistance, such as a gear or a shaft.
In vehicles, what does torque mean?
When used to describe internal combustion engines or electric motors, torque refers to the force acting on the driving shaft. Torque is measured in newton-meters or pounds-feet (lb-ft) (Nm). Engine power is determined by the relationship between torque and engine speed (rpm).
Briefing:
mv1r1=mv2r2
2500*6260=v2*500
v2=31300m/s
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a total lunar eclipse is visible: group of answer choices only within a narrow path on earth only during new moon phase visible to observers on a whole hemisphere of earth an opportunity to observe the solar corona
The correct answer is only within a narrow path on earth. This is because the shadow of the earth during a total lunar eclipse is only large enough to cover a small area on the earth's surface.
Lunar eclipse:A total lunar eclipse is visible only within a narrow path on earth, where the moon passes directly through the center of the Earth's shadow. This path, which is typically around 160 to 270 kilometers (100 to 170 miles) wide, moves eastward as the Moon orbits Earth.
During a total lunar eclipse, the moon is fully engulfed in Earth's shadow, making it visible to observers on a whole hemisphere of earth. However, an opportunity to observe the solar corona is not visible during a total lunar eclipse. The solar corona can only be seen during a total solar eclipse.
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a solenoid of length 1.50 cm and radius 0.650 cm has 49 turns. if the wire of the solenoid has 1.45 amps of current, what is the magnitude of the magnetic field inside the solenoid?
The magnetic field of the solenoid will be 30.79 T.
Magnetic field strength is a quantitative measure of the strength or weakness of a magnetic field.
It is also the force experienced by a north pole unit of one weber force at a certain point in the magnetic field. SI unit for the magnetic field is Tesla (T).Magnetic field is denoted by B and has the formula as B = μ₀I/2πrAlso it has an another formula as B = (N*r*I) /LLength of solenoid, L = 1.5 cm = 0.015 m
Radius of solenoid, r = 0.65 cm = 0.0065 m
Number of turns, N = 49 turns
Current, I = 1.45 A
Magnetic field, B, can be calculated as B = (N*r*I) /L
B = (49 * 0.0065 * 1.45)/0.015
B = 30.79 T
The magnitude of the magnetic field inside the solenoid is 30.79 T.
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Shown below are the four terrestrial planets of our solar system. Assume that all the planets started out equally hot inside. Rank the planets based on their expected cooling rates, from fastest cooling to slowest cooling.MercuryMarsVenusEarth
The rank of the terrestrial planets based on their expected cooling rates, from fastest cooling to slowest cooling is as follows -
mercury , Mars, Venus, Earth
Mercury - It is the smallest terrestrial planet in the solar system. It has a thin atmosphere, which causes it to swing between burning and freezing temperatures.
Mars - It is less dense than Earth and has a smaller magnetic field, which is a indication of a solid core rather than a liquid one. Mars is known to have water ice and organics- some of the ingredients for living things.
Venus - It is about the same size as Earth and has a thick, toxic carbon-monoxide (CO) dominated atmosphere that traps heat, making it the hottest planet in the solar system.
Earth - Out of the four terrestrial planets, Earth is the largest and has regular seasons for much of it surface; regions closer to the equator tend to stay warm, while spots closer to the poles are cooler and in the winter, icy.
Therefore, the cooling rate of terrestrial planets is Mars, Earth, Venus, Mercury
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Air in an ideal Diesel cycle is compressed from 4 L to 0.25 L, and then it expands during the constant pressure heat addition process to 0.50 L. Under cold air standard conditions, determine the thermal efficiency of this cycle.
Air in an ideal Diesel cycle is compressed from 4 L to 0.25 L, and then it expands during the constant pressure heat addition process to 0.50 L. Under cold air standard conditions, the thermal efficiency of this cycle is 65.2%.
For an air standard engine with γ = 1.4, compression ratio r and fuel cut off ratio rc where r = V1/V2
and rc = V3/V2 and V1 = 4l, V2 = 0.25l and V3 = 0.50l
The efficiency (n) of diesel cycle is ----
n = 1 - [1 / r^(γ - 1)] * (rc^γ -1) / γ(rc - 1)
n = 1 - [1/(4/0.25)^(1.4-1)] * (0.50/0.25)^1.4 - 1 / 1.4 [(0.50/0.25) -1 ]
n = 1 - [1/3.03] * [2.63 - 1] / 1.4x1
n = 0.652
n% = 65.2%
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How much force would be required to make a mass of 8kg accelerate at
8m/s^2?
64 N force would be required to make a mass of 8 kg accelerate at
8m/s².
What is force?The term "force" is defined precisely in science. It is acceptable to refer to a force of this level as a push or a pull. An item does not "have in it" or "contain" a force. Another item applies force to another. The concept of a force does not apply only to living or non-living entities.
The newton (sign N) is the SI unit of force.
The fundamental formula for force is F = ma, where F represents force, m represents mass in kilograms, and a represents acceleration in m×s⁻². It is the second law of motion established by Newton.
Given that,
Acceleration (a) = 8m/s²
Mass (m) = 8 kg
Force (F) = ?
As we know,
Force= mass × acceleration
F = 8 kg × 8 m/sec²
F = 64 N
Therefore, force of 64 N is required to accelerate the body.
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a 1.5 kg 1.5 kg ball rotates on the end of a 3 m 3 m string in a vertical circle with a speed of 7 m/s 7 m/s. what force does the ball exert on the rope at the top of the vertical circle?
Force exerted by the ball on the rope is 24.5 N.
Force is an external influence that can change the velocity or motion of an object.
It can also be defined as the product of mass and acceleration.Mathematically, force F = m*amass of the ball = 1.5 kg
Radius of the circle = 3 m
Speed at which the ball is rotating = 7 m/s
Since the ball is rotating in a vertical circle, centripetal force acts on it.
Centripetal force is the force exerted on a rotating object and the gravitational force in a vertical circle is zero.
Mathematically centripetal force is Fc = mv²/r
Fc = 1.5 * (7)²/ (3)
Fc = 24.5 N
Force exerted by the ball on the rope at the top of the vertical circle is 24.5 N.
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a solid disk with a mass of 2.00 kg and a radius of 3.00 m is spinning with an angular velocity of 4.00 rad/s. what is the angular momentum of the disk?
The angular momentum of the disk: 0881 kg*m^2/s.
In Newtonian mechanics, momentum is the made of the mass and velocity of an item. it's far a vector quantity, owning a value and a route. If m is an item's mass and v is its speed, then the object's momentum p is mathbf{p} = m mathbf{v}.
-A truck complete of goods has a huge mass and so it has to gradually down earlier than a prevent light as it has a massive momentum with the same speed and so it's far very difficult to forestall. -A shifting bullet has a large momentum since it has an extremely big pace although it consists of a very small mass.
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NASA's Skylab, the largest spacecraft ever to fall back to the Earth, reentered the Earth's atmosphere on July 11,1979, and broke into a myriad of pieces. One of the largest fragments was a 1770-kg, lead-lined film vault, which landed with an estimated speed of 120 m/s.If its speed at an altitude of 146 km was 7950 m/s, how much nonconservative work was done on the film vault during reentry?
Applying the Work-Energy Theorem, the Work Done by a Non-Conservative Force is [tex]5.3 *10^{10}[/tex] J
The given Parameters are :
Initial Velocity (u) = 120 m/s
Final Velocity (v) = 7950 m/s
Mass (m) = 1770 kg
Displacement (h) = 146 km = 146000 m
According to the Work-Energy Theorem,
The Work Done is given by the difference between the final and initial Kinetic Energies,
Thus,
Work Done = Final Kinetic Energy - Initial Kinetic Energy
Now, Work done = Work done by gravity + Work Done by Non-Conservative Force
So, Work Done by gravity = mgh = 1770 *10*146000 =2482000000 J
Change in Kinetic Energy = [tex]\frac{1}{2} *m*(v^{2} -u^{2} )[/tex]
Putting the values, we get,
Change in Kinetic Energy = [tex]\frac{1}{2} *1770*(7950^{2} -120^{2} )=55921468500[/tex] J
Now, Work Done by Non Conservative Force = Change in Kinetic Energy-Work Done by gravity = 2482000000 - 55921468500 = 53439468500 = 5.3 * [tex]10^{10}[/tex] J
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A simple pendulum is known to have a period of oscillation, t = 1. 55 s. Student a uses a digital stopwatch to measure the total time for 5 oscillations and calculates an average period t = 1. 25 s. Student b uses an analog wristwatch and the same procedure to calculate an average period for the 5 oscillations and finds t = 1. 6 s. Which period is more accurate, and why?.
The period measured by student b using analog wristwatch is more accurate because of less percentage of error.
What is accuracy in measurement?Accuracy is the capacity of an instrument to measure the precise value. In other words, it refers to how closely the measured value resembles a reference or genuine value. Small readings can be taken to increase accuracy. The calculation's error is decreased by the little reading.
Given that:
period of oscillation, t = 1. 55 s.
an average period for the 5 oscillations obtained by student a: t = 1. 25 s.
average period for the 5 oscillations obtained by student b: t = 1. 6 s
Hence, error percentage of student a = (1.55-1.25)/1.55 × 100% = 19.35%
error percentage of student b = (1.60-1.55)/1.60 × 100% = 3.22%
Hence, period measured by student b is more accurate because of less percentage of error.
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jupiter nudges the asteroids through the influence of (a) tidal forces. (b) orbital resonances. (c) magnetic fields.
The asteroids are moved by Jupiter under the influence of (b) orbital resonances.
What are asteroids ?
Small, stony objects called asteroids orbit the Sun. Asteroids, sometimes known as minor planets, are rocky, airless debris from the early stages of the solar system's creation, which occurred around 4.6 billion years ago.
When two satellites' orbital periods are related by integer relationships, they can exert gravitational pull on one another and change the eccentricity of their orbits, resulting in an orbital resonance. Io, Europa, and Ganymede are the three inner moons of planet Jupiter. They are locked in a 4:2:1 orbital resonance, which means they are playing the same note in different octaves. The tones that Callisto and Ganymede produce are almost an octave and a minor third apart because they are almost in a 12:5 resonance.
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which type of which type of orbit is shown in the picture below?
I don't see a picture attached to your question. Without one, I don't think I will be able to determine what type of orbit is displayed.
click to turn on the electric field. there is something interesting about the direction of electric field between the plates. why do you think that this situation appears in so many physics problems?
This situation appears in physics problems because of the negative charge, an inward-facing radial electric field is produced.
However, due to E=F/Q (here, Q is negative, so) there is another negative charge, which experiences a force in the direction radially opposite the first negative charge.As a result, force would be moving in the opposite direction from the field, which is directed towards the negative charge.However, in actuality, atoms would lose their electrons in order to generate a positive charge. The protons would be more numerous than the electrons, giving it a positive charge.Because a test particle would be subjected to two forces acting in opposite directions at the point of intersection, field lines produced by a single charge do not intersect.To know about protons -
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a piece of cork has a mass of 15 g in air and a specific gravity of 0.25. the cork is attached to a lead sinker whose mass is 230 g in air. what will be the apparent mass of the pair when they are both submerged in water?
With a piece of cork connected, which has a mass of 15 g in air and a specific gravity of 0.25, the pair weighs 164.736 grammes when they are both submerged in water.
A physical body's mass is its total amount of matter. Inertia, or the body's resistance to acceleration (change of velocity) when a net force is applied, is also measured by this property. The gravitational pull an object has on other bodies is also influenced by its mass. A substance will float on water if its specific gravity is less than 1. sp gr, or specific gravity, is a common abbreviation. The following formula represents specific gravity, which is also known as relative density: Substance formula: substance / reference The purpose of comparing densities
60 grammes of water are equal to 15 grammes of cork when divided by 15.25. Lead's specific gravity is 11.35; its mass is (230+15)-(60+20.264); and its mass is 245 - (80.264) grammes.
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If you measure and calculate the density of a cube by the method of displacement, and then later use that same cube to measure and calculate the density by the method of flotation should you expect to obtain the same density? why or why not?.
If you measure and calculate the density of a cube by the method of displacement, and then later use that same cube to measure and calculate the density by the method of flotation you should expect to obtain the same density.
All matter has mass and takes up space. Density , a calculated value, measures the amount of matter in a space. To calculate the density of a material, find the mass and the volume of the object. Calculate the density of the object using the formula density equals mass divided by volume.Once you've measured the mass and volume of an object, finding the density requires putting the measurements into the density formula.To know more about density visit:
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a solid cylinder with a mass of 5 kg and a radius of 30 cm is rolling on a flat surface. the cylinder rolls with a speed of 2 m/s. what its kinetic energy?
The total kinetic energy of a cylinder is 15 J.
Given that, mass = 5 kg
Radius of the cylinder= 30 cm = 30/100 m = 0.3 m
Speed = 2 m/s
Ut = Uk + Ur
where, Uk - translation kinetic energy
Ur - rotational kinetic energy
I is the moment of inertia of the solid cylinder
⇒ 1/2 mv² + 1/2 Iω²
⇒ 1/2 mv² + 1/2 [1/2 m r² * (v/r)²]
⇒ 1/2* 5 * (2)² + 1/2 [1/2* 5 *(0.3)² * (2/0.3)²]
⇒ 10 + 1/2*1/2*5* (0.3)²* 4 / (0.3)²
⇒ 10 + 5 = 15 J
Thus, the total kinetic energy is 15 J.
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A block of iron has the dimensions of 3. 00 cm x 3. 00 cm x 3. 00 cm. It has a mass of 213 g. When placed in water, the block sinks. What volume of water did it displace? 213 cm 3 0. 127 cm 3 7. 89 cm 3 27. 0 cm 3.
When the block of iron is placed in water the volume of water that is displaced is 27.0 cm³
Hence, Option D is correct.
Explain in detail.
The volume water that is displaced is equal to volume of block of the ironvolume of block of iron = length x width x height length= 3 cm width = 3 cm height = 3 cmtherefore the volume displaced = 27 cm³ since the volume of water displaced is equal to volume of block.
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a beam positioned on a fulcrum is 6 m long. it has a weight of 300 n attached to one end and a weight of 250 n attached to the other end. to establish mechanical equilibrium, the fulcrum must be placed how far away from the 250 n weight? (answer in m)
To establish mechanical equilibrium, the fulcrum must be placed 3.27 m away from the 250 N weight.
What is the position of the fulcrum?
The position of the fulcrum from the 250 N weight is determined by applying the principle of moment as shown below.
let the position of the fulcrum = d
The position of the 250 N from the fulcrum must be greater than the center of the beam since 300 N is heavier than 250 N.
----------------------------------Δ--------------------------------
↓ d ↓
250 N 300 N
the position of the 250 N weight from the fulcrum = d
the position of the 300 N weight from the fulcrum = 6 m - d
take moment about the pivot;
sum of the antic lock wise moment = sum of the clockwise moment
250 ( d ) = 300 ( 6 - d )
250d = 1,800 - 300d
550d = 1,800
d = 1,800 / 550
d = 3.27 m
Thus, the position of the fulcrum from 250 N depends on the length of the beam and the weight hanging at the other end.
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Sam, whose mass is 75 kg, straps on his skis and starts down a 50-m-high, 20 ^\circ frictionless slope. A strong headwind exerts a horizontal force of 200 N on him as he skies.
a)Find Sam's speed at the bottom using work and energy.
b)Find Sam's speed at the bottom using Newton's laws.
At the base of the incline, Sam is moving at a speed of 15.73 m/s. who weighs 75 kg puts on his skis and begins to descend a 50 m-high, 20 frictionless slope.
Sam's bottom-of-the-screen speed is determined using the Work-Energy Theorem as follows: An object moves parallel to the plane on a slope with no friction. Both the normal force and the gravitational perpendicular component cancel each other out because they are acting in the same speed. Therefore, an object on a frictionless slope is solely accelerated by the gravitational parallel component. On a surface on an inclined plane with no friction, any item accelerates.
delta W is equal to the delta kinetic energy for frictionless slope
(36750 - 27472) = 1/2*75*(v2 -0).
9278=37.5(v^2)
v^2 = 9278/37.5(v2)
v^2 = 247.4v = 15.73 m/s
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A glider on an air track is connected by springs to either end of the track. Both springs have the same spring constant, k, and the glider has mass Ma) Determine the frequency of the oscillation, assuming no damping, if k = 125 N/m and M = 210 g .b) It is observed that after 55 oscillations, the amplitude of the oscillation has dropped to one-half of its initial value. Estimate the value of γγ, using x(t)=A* e^γt * cosω′tc) How long does it take the amplitude to decrease to one-quarter of its initial value?
The amplitude drops to one-quarter of the initial value after 102.7 oscillations.
λ=1/51⋅0.20slog(1/2)=−0.68s^-1
Using the previous result we can evaluate the amplitude as a function of time to obtain the elapsed time until the amplitude drops to one-quarter of its initial value,
1/4=Aeλt.
Solving for the time,
t=1/λlog(1/4)=20.4s
Comparing this result with the period,
t=102.7T.
The maximum displacement or distance made by a point on a vibrating body or wave relative to its equilibrium location is known as the amplitude in physics. It is equivalent to the length of the vibration path divided in half. Amplitude is the separation between the wave's resting position and its highest displacement. Frequency is the number of waves that cross a particular place in a second. Period—the length of time needed for a wave cycle to complete
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what is the minimum coefficient of friction between the tires and the road that the car could have and still make the turn?
The minimum coefficient of friction between the tires and the road that the car could have and still make the turn is 0.7 for dry roads and 0.4 for wet roads.
The value of minimum coefficient of friction is usually between 0 and 1 but can be greater than one. A value of zero means there is no friction between the objects such is possible with a lubricant material . All objects, should have friction between them when they come in contact with each other.
The coefficient of friction is as low as 0.05 between dry sliding surfaces will be achieved when the mechanical interconnections are removed. This outcome has been attained based on a theoretical model of an ideal surface for low friction.
The coefficient of friction having value 1 is a perfect positive correlation. A coefficient of correlation zero means there is no linear relationship. Correlation coefficients are used in science to assess the degree of association between two variables, factors, or data sets.
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speedboat a negotiates a curve whose radius is 120 m. speedboat b negotiates a curve whose radius is 240 m. each boat experiences the same centripetal acceleration. what is the ratio of the speeds of the boats
Ratio of the speeds of the boats with equal centripetal acceleration is 0.7.
Centripetal acceleration is defined as the change in tangential velocity and is experienced during uniform circular motion. It has a magnitude equal to the square of the body's speed v along the curve divided by the radius r (or distance) from the centre of the circle to the moving body. The centripetal acceleration ac is given by:
ac = v^2/ r
For the boat A:
ac = va^2/ 120
For the boat B:
ac = vb^2/ 240
As provided, the centripetal acceleration is equal for both boats, hence
va^2/ 120 = vb^2/ 240
va^2/vb^2 = 120/240
va^2/vb^2 = 0.5
va/vb = √0.5 = 0.7
Hence, the ratio of the speeds of the boats is 0.7
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consider a very long rope at rest on a frictionless surface and placed parallel to the -axis. if its left end is quickly shaken up and down once, a perturbation of the shape of a pulse propagates along the rope from the left to the right end. if there is no energy losses, the pulse will propagate along the rope without changing its original shape.
Yes if there is no energy losses, the pulse will propagate along the rope without changing its original shape.
In every rope, the least dense rope has the largest wavelength. Crossing a barrier does not change a wave's frequency. If a wave in a less dense rope is traveling toward a border with a more dense rope, the reflected pulse will become inverted. The pulse will travel the length of the rope without altering its original shape if there are no energy losses.After reflecting off the fixed end, the pulse is inverted. To put it another way, a pulse with an upward displacement will reflect off the end and return with a downward displacement. When the medium's end is fixed, this characteristic of inversion will always be seen. When a wave or pulse moving through one medium encounters the boundary of another, a portion of the incident pulse is reflected off the border and a portion is transmitted over the boundary.
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a fellow student makes the following comment during a study session: ""a freely falling object falls a greater distance during each second than the total distance fallen in all the previous seconds."" this statement (a) is always true. (b) is true only for sufficiently short times. (c) is true for sufficiently long times. (d) is never true.
The correct answer is b.
The given statement is true for sufficiently short distances.
At the end of t seconds, the distance travelled by a freely falling object with zero initial velocity is [tex]s=ut+1/2 gt^{2}[/tex]
where s is the displacement, t is the time, u is the initial velocity and g is the acceleration due to gravity.
Here, when the object is under free fall, its initial velocity, [tex]u=0 m/s[/tex]
Gravity continuously accelerates an object (increases its velocity) during free fall until it reaches terminal velocity. In particular, for every second that passes, gravity accelerates a falling object by 9.8 (m/s). (Acceleration is measured in meters per second squared, or m/s2, whereas velocity is measured in m/s.)
It is only sometimes true that an object falling freely needs to travel a greater distance in one second than it did in all the preceding seconds. However, if the object is falling under the influence of gravity for very short distances, the above claim can be approximately true.
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As you watch the video, notice that the size of the tidal bulges varies with the Moon's phase, which depends on its orbital position relative to the Sun. Which of the following statements accurately describes this variation?
Low tides are lowest at both full moon and new moon.
Low tides are highest at both full moon and new moon.
High tides are highest at full moon and lowest at new moon.
Low tides are highest at full moon and lowest at new moon.
High tides are highest at both full moon and new moon.
High tides are highest at first- and third-quarter moon.
The two statements that accurately describes this variation are that low tides are lowest at both full moon and new moon, high tides are highest at both full moon and new moon.
What is the reason for this?
As the video shows, the tidal minima are smallest and the tidal bulges are largest at full moon and new moon, because those times when tidal forces due to the Sun and Moon get aligned (and therefore add to one another).
So, high tides are higher and low tides are lower at these times, and these are called spring tides. (In contrast, we have neap tides at first- and also third-quarter moons, when high tides are not as high and low tides are not as low as usual.)
Therefore, the two statements that accurately describes this variation are that low tides are lowest at both full moon and new moon, high tides are highest at both full moon and new moon are .
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two inductors of self-inductance l1 and l2 are connected in parallel. the inductors are magnetically shielded from one another so that neither produces flux in the other. show that the self-inductance of the combination is given by 1 l
Voltage is proportional to inductance just as, for resistors, it is proportional to resistance. Now, the (independent) voltages for parallel elements are equal (V₁ = V₂) and the currents (which are generally functions of time) add i(t) = i₁(t) + i₂(t)
This leads to the equation,
i = i₁ + i₂ + i₃ = V [(1/R₁) + (1/R₂) + (1/R₃)] for resistors.
We note that this condition on the currents implies
d₁(t)/dt + d₂(t)/dt = d(it)/dt
Thus, although the inductance equation, ε = -L(di/dt) involves the rate of change of current, as opposed to current itself, the conditions that led to the parallel resistor formula also apply to inductors.
Therefore, 1/L(eq) = 1/L₁ + 1/L₂
Therefore to ensure the independence of the voltage values, it is important that the inductors not be too close together. The requirement is that the field of one inductor not to have significant influence (or "coupling") in the next.
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the holding force in drawing is most likely to be (a) greater than, (b) equal to, or (c) less than the maximum drawing force?
In drawing, the holding force is most likely to be lower than the maximal drawing force.
Explain about the drawing force?By using a special method called FORCE Drawing, you can learn to see things more clearly and to comprehend what you are looking at. This will help you to draw from life and from your imagination with great talent and understanding.
All forces operating on an item, their direction, and their magnitude are represented in a force diagram. The image has been streamlined to only depict the forces.
The term "force diagram," sometimes known as a free body diagram, refers to a sketch in which all force vectors acting on an object are shown with their initial points at the location of the object.
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A cyclist is travelling along a track at 8 m/s when a rabbit runs out in front of them. they stop their bike in 1.6 seconds. calculate their deceleration.
The deceleration experienced by the cyclist is -5 m/s. Deceleration is also called negative acceleration.
What is deceleration?Deceleration is the term used to describe a decrease in speed as the body moves away from the beginning place. The opposite of acceleration is deceleration.
Given,
Initial velocity (V₁) = 8 m/s
Final velocity (V₂) = 0 m/s (Since the bike was stopped).
Time taken for the velocity drop (t) = 1.6 seconds
We know,
[tex]deceleration=\frac{V_{2}-V_{1} }{t} \\[/tex]
Substituting the values we get,
[tex]deceleration= \frac{0-8}{1.6}[/tex]
[tex]= -5 m/s[/tex]
Hence, the deceleration experienced by the cyclist is -5 m/s.
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The right answer is "-1.5 m/s²"
Answer explanation:
Acceleration = change in velocity / time
= (4 m/s – 7 m/s) / 2 s = -1.5 m/s2.
The acceleration is negative because the bike is slowing down.(decelarating)
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microscopes use mirrors to magnify objects. please select the best answer from the choices provided t f
It is erroneous to claim that mirrors are not used by microscopes to magnify objects.
What can you say about a microscope?A microscopy is a tool that may be used to examine tiny things, including cells. By at least one lens, the microscope magnifies the picture of an item. This lens twists light in a way that causes it to look as though an item is larger than the amount is.
What kind of microscope is used most frequently?The microscopy, which is the most popular and the first to be created, employs lenses to diffract visible light that has gone through a thinly sheared material to create a viewable picture.
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what do we mean by the halo of a galaxy? (a) it is the central region that is crowded with stars. (b) it is a large, roughly spherical region surrounding the disk. (c) it is the pancake-shaped region in which spiral arms are found.
A galaxy's halo is a large, generally spherical area that surrounds the disk.
Solution b is accurate.
What is Halo Galaxy?An extended, approximately spherical component of a galaxy that extends beyond the primary, visible component is called a galactic halo. The halo is made up of several distinctive galaxy parts, including: the halo of a star. a galaxy's corona (hot gas, i.e. a plasma)
The term "halo" refers to a ring of light that seems to surround the sun or moon and is caused by the refraction or reflection of light by atmospheric ice particles.
Globular clusters and other aging stars can be found in the galactic halo, a region of the galaxy that extends far above and below the galactic disk. - Roughly round; somewhat flattened. - Only includes old stars. - is free of gas and dust.
Thus halo galaxy is a large, roughly spherical region surrounding the disk (option B is correct)
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