Answer:
[tex]P_a=17.85psi[/tex]
Explanation:
From the question we are told that:
Tank Pressure [tex]P_t=30.0kpa[/tex]
Atmospheric Pressure [tex]P_a=13.5 psi[/tex]
Where
[tex]1kpa=0.148psi[/tex]
Therefore
[tex]30kpa=4.35psi[/tex]
Generally the equation for Absolute pressure [tex]P_a[/tex] is mathematically given by
[tex]P_a=13.5+4.35[/tex]
[tex]P_a=17.85psi[/tex]
Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating about a perpendicular axis at one end is ml2/3. Write your answer with one decimal place.
Answer:
2.2 s
Explanation:
Using the equation for the period of a physical pendulum, T = 2π√(I/mgh) where I = moment of inertia of leg about perpendicular axis at one point = mL²/3 where m = mass of man = 67 kg and L = height of man = 1.83 m, g = acceleration due to gravity = 9.8 m/s² and h = distance of leg from center of gravity of man = L/2 (center of gravity of a cylinder)
So, T = 2π√(I/mgh)
T = 2π√(mL²/3 /mgL/2)
T = 2π√(2L/3g)
substituting the values of the variables into the equation, we have
T = 2π√(2L/3g)
T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))
T = 2π√(3.66 m/(29.4 m/s² ))
T = 2π√(0.1245 s² ))
T = 2π(0.353 s)
T = 2.22 s
T ≅ 2.2 s
So, the period of the man's leg is 2.2 s
Two gerbils run in place with a linear speed of 0.55 m/s on an exercise wheel that is shaped like a hoop. Find the rotational kinetic energy of the wheel if the exercise wheel has a radius of 9.5 cm and a mass of 5.0 g. Each gerbil has a mass of 0.02 kg if you think that is important.
Answer:
K = 7.56 10⁻⁴ J
Explanation:
The rotational kinetic energy is
K = ½ I w²
They ask us for the kinetic energy of the wheel, which can be approximated as a thin ring, its moment of inertia is
I = M r²
the linear speed of the gerbils is equal to the linear speed of the wheel. The linear and rotational variables are related
v = w r
w = v / r
we substitute
K = ½ (M r²) v² / r²
K = ½ M v²
let's calculate
K = ½ 5 10⁻³ 0.55²
K = 7.56 10⁻⁴ J
A string has a linear density of 8.5 x 10-3 kg/m and is under a tension of 280 N. The string is 1.8 m long, is fixed at both ends, and is vibrating in the standing wave pattern shown in the drawing. Determine the
a. speed.
b. wavelength
c. frequency of the traveling waves that make up the standing wave.
Answer:
a) [tex]v=181.497m/s[/tex]
b) [tex]\lambda=1.2[/tex]
c) [tex]F=151.248hz[/tex]
Explanation:
From the question we are told that:
Linear density [tex]\rho=8.5 x 10-3 kg/m[/tex]
Tension [tex]T= 280 N[/tex]
Length of string [tex]l= 1.8 m[/tex]
a)
Generally the equation for Speed of travelling wave is mathematically given by
[tex]v=\sqrt{\frac{T}{\rho}}[/tex]
[tex]v=\sqrt{\frac{280}{8.5*10^{-3}}[/tex]
[tex]v=181.497m/s[/tex]
b)
From the Drawing
Wavelength is given as
[tex]\lambda=\frac{2L}{3}[/tex]
[tex]\lambda=\frac{2*1.8}{3}[/tex]
[tex]\lambda=1.2[/tex]
c)
Generally the equation for Frequency of travelling wave is mathematically given by
[tex]F=\frac[v}{\lambda}[/tex]
[tex]F=\frac[181.497}{1.2}[/tex]
[tex]F=151.248hz[/tex]
PLS ANSWER WORTH 10 POINTS PLS HELP
Answer:
the answer should be D
Explanation:
Because if you want to earn your goals you must complete small goals to earn big goals
Hey guys....
What is the advantage of a capacitor as it stores charge?
15. In the diagram shown, the emf of the secondary winding is______ the emf of the primary winding.
A. Less than
B. Equal to
C. Greater than
Answer:
Greater than
Explanation:
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through a potential difference of 3V0, what speed would it gain? Group of answer choices
Answer:
[tex]v_{0,new} = v0\sqrt{}2[/tex]
Explanation:
Initial work done on the proton is given by, [tex]\DeltaW0 = q V_o[/tex]
we know that, [tex]\DeltaW = \DeltaK.E[/tex]
[tex]qV0 = (1/2) m v_0^2[/tex]
[tex]v_0 = \sqrt{}2 q V_0 / m[/tex] { eq.1 }
If it were accelerated instead through a potential difference of 2V0, then it would gain a speed will be given as :
using the above formula, we have
[tex]v_{0,new} = \sqrt{}2 q (2V0) / m[/tex]
[tex]v_{0,new} = \sqrt{}4 q V0 / m[/tex]
[tex]v_{0,new} = v0\sqrt{}2[/tex]
You drive past a potential parking space in center city. Your new car is travelling at 85% the speed of light. If your car is 6.0 m long (which you measured the day you bought it) and you observe the space to be 3.0 m, should you try to park? Why is your friend on the sidewalk (who hasn't studied relativity) so sure that you can park? How does the situation appear to him?
Answer:
We should not try to park the car because its rest length is greater than the space available.
The car seems to be approximately equal to the friend (L = 3.16 m). Due to this reason he is sure to park.
Explanation:
We should not try to park the car because its rest length is greater than the space available.
The friend is sure about parking because the car appears short in length to him. For this, we will solve Einstein's length contraction formula from theory of relativity:
[tex]L = L_o\sqrt{1-\frac{v^2}{c^2}}[/tex]
where,
L = Relative length observed by friend = ?
L₀ = rest length = 6 m
v = relative speed = 85% of speed of light = 0.85c
Therefore,
[tex]L = (6\ m)\sqrt{1-\frac{(0.85c)^2}{c^2}}[/tex]
L = 3.16 m
Hence, the car seems to be approximately equal to the friend. Due to this reason he is sure to park.
Give an example of a vertical motion with a positive velocity and a negative acceleration. Give an example of a vertical motion with a negative velocity and a negative acceleration.
Answer:
An example of positive velocity is throwing a ball upwards
An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height
Explanation:
In a vertical movement the acceleration is always downwards, therefore negative since it is created by the attraction of the Earth on the body.
An example of positive velocity is throwing a ball upwards
An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height
List five instruments of mechanical fluid
[tex]\sf{The~ different~ types~ of~ measuring~ instruments~ are:-}[/tex]
Calipers.Micrometer.Laser Measure.Ruler.Compass.Which of these is NOT an effect of humor?
strengthened immune system
reduced stress levels
reduced feelings of anxiety
feelings of jealousy and envy
How are the Northern Lights are formed.
Answer:
Bottom line: When charged particles from the sun strike atoms in Earth's atmosphere, they cause electrons in the atoms to move to a higher-energy state. When the electrons drop back to a lower energy state, they release a photon: light. This process creates the beautiful aurora, or northern lights.Explanation:
^-^I hope it's help uThe volume of an ideal gas changes from 0.40 to 0.55 m3 although its pressure remains constant at 50,000 Pa. What work is done on the system by its environment
Answer:
w= p∆v 50000 ( 0.55-0.40) and calculate and you get it
The work done on the system by its environment is 7,500J.
To find the work done, we need to know about the work done on an ideal gas during isobaric process.
What is isobaric process?When the pressure is remained constant throughout a process, then the process is called isobaric process.
What is the work done on a system in the isobaric process?For a isobaric process, the work done is pressure × (final volume of the system - initial volume)Here, Final volume= 0.55 m³
Initial volume= 0.40 m³
Pressure= 50,000 Pa
Work done = 50,000 × (0.55 - 0.40)
= 7,500 J
Thus, we can conclude that 7,500 J of work is done on the system by its environment.
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1.A motor is rated at 1.5 hp. At what speed in m/s can this motor raise a
200 kg load?
2. A bucket of water with a total weight of 50 Newtons is lifted at constant
velocity up a 10 meter deep well. If it takes 20 seconds to raise the bucket
this distance, what is the power required to lift the bucket?
Answer:
1. 0.57 m/s
2. 25 Watts
Explanation:
1. Determination of the speed.
We'll begin by converting 1.5 hp to watt (W). This can be obtained as follow:
1 hp = 745.7 W
Therefore,
1.5 hp = 1.5 hp × 745.7 W / 1 hp
1.5 hp = 1118.55 W
Next, we shall determine the force. This can be obtained as follow:
Mass (m) = 200 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) =?
F = m × g
F = 200 × 9.8
F = 1960 N
Finally, we shall determine the speed. This can be obtained as follow:
Power (P) = 1118.55 W
Force (F) = 1960 N
Speed (v) =?
P = F × v
1118.55 = 1960 × v
Divide both side by 1960
v = 1118.55 / 1960
v = 0.57 m/s
Thus, the speed is 0.57 m/s
2. Determination of the power.
We'll begin by calculating the velocity. This can be obtained as follow:
Displacement = 10 m up
Time = 20 s
Velocity =?
Velocity = Displacement / time
Velocity = 10 / 20
Velocity = 0.5 m/s
Finally, we shall determine the power. This can be obtained as follow:
Velocity (v) = 0.5 m/s
Force (F) = 50 N
Power (P) =?
P = F × v
P = 50 × 0.5
P = 25 Watts
Therefore, the power required to lift the bucket is 25 Watts
how can you prove that acceleration is a derived unit
a = (dx / dt)²
Explanation: Unit of distance is m (metres) and unit of time is s (seconds) speed v is first derivative of distance x versus time:
v = dx / dt, unit is m/s. Acceleration is second derivative of
speed versus time a = (dx / dt)² = (dv/dt) , unit is m/s²
Answer:
Explanation:
Acceleration is derived unit because it has two fundamental units involved i.e. meter and second square.
If we convert a circuit into a current source with parallel load it is called?
Answer:
If we convert a circuit into a current source with parallel load it is called source transformation
an object moves clockwise around a circle centered at the origin with radius m beginning at the point (0,). a. find a position function r that describes the motion of the object moves with a constant speed, completing 1 lap every s. b. find a position function r that describes the motion if it occurs with speed .
Answer:
Answer to An object moves clockwise around a circle centered at the origin with radius 6 m beginning at ... 6 M Beginning At The Point (0,6) B. Find A Position Function R That Describes The Motion If It Occurs With Speed E T A. R(t)= S The Motion Of The Object Moves With A Constant Speed, Completing 1 Lap Every 12 S.
Explanation:
One solenoid is centered inside another. The outer one has a length of 50.0 cm and contains 6750 coils, while the coaxial inner solenoid is 3.0 cm long and 0.120 cm in diameter and contains 15 coils. The current in the outer solenoid is changing at 49.2 A>s. (a) What is the mutual inductance of these solenoids
Answer: The mutual inductance of these solenoids is [tex]2.88 \times 10^{-7} H[/tex].
Explanation:
Given: Length = 50.0 cm (1 cm = 0.01 m) = 0.50 m
[tex]N_{1}[/tex] = 6750
[tex]N_{2}[/tex] = 15
Radius = [tex]\frac{0.120 cm}{2} = 0.6 cm = 6 \times 10^{-4} m[/tex]
As inner of a solenoid resembles the shape of a circle. So, its area is calculated as follows.
[tex]Area = \pi \times r^{2} = \pi \times (6 \times 10^{-4})^{2}[/tex]
Formula used to calculate mutual conductance of two solenoids is as follows.
[tex]M = \frac{\mu_{o} \times A \times N_{1} \times N_{2}}{l}[/tex]
where,
M = mutual conductance
A = area
[tex]\mu_{o}[/tex] = relative permeability = [tex]4 \pi \times 10^{-7} Tm/A[/tex]
[tex]N_{1}[/tex] = no. of coils in outer solenoid
[tex]N_{2}[/tex] = no. of coils in inner solenoid
l = length
Substitute the values into above formula as follows.
[tex]M = \frac{\mu_{o} \times A \times N_{1} \times N_{2}}{l}\\= \frac{4 \pi \times 10^{-7} Tm/A \times \pi (6 \times 10^{-4})^{2} \times 6750 \times 15}{0.5 m}\\= 2.88 \times 10^{-7} H[/tex]
Thus, we can conclude that the mutual inductance of these solenoids is [tex]2.88 \times 10^{-7} H[/tex].
With explanation pls
Answer:
[tex](x \times 1) = (400 \times 2.5) \\ x = 1000 \: newtons[/tex]
[tex]y = 0[/tex]
Which statement is true?
a particle of violet light has less energy than a particle of red light
a particle of violet light has more energy than a particle of red light
a particle of violet light has exactly the same energy as a particle of red light
particles of light do not have any energy, regardless of what color the light is
a particle of violet light has exactly the same energy as a particle of red light
In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2 the mass has been lifted a distance D vertically upward. If we define the potential energy in Case 1 to be zero, what is the potential energy of Case 2
Answer: hello your question is incomplete attached below is the complete question
answer : 1/2 KD^2 ( option A )
Explanation:
P.E ( potential energy ) = mgd
In case 1 P.E = 0 i.e. mgd = 0
Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring
The potential energy of the M in case 2
= P.E of M at rest + P.E of the spring
= 0 + 1/2 KD^2
Suppose we have a spaceship about the size of a typical ocean cruise ship today, which means it has a mass of about 120 million kilograms, and we want to accelerate the ship to a speed of 12 % of the speed of light. Suppose you want to generate the energy to get it to cruising speed using matter-antimatter annihilation.
Part A. How much energy would be required? (Hint: You can find the answer simply by calculating the kinetic energy of the ship when it reaches its cruising speed; because 12 % of the speed of light is still small compared to the speed of light, you can use the formula that tell us that kinetic energy = 12mv2.) Express your answer using two significant figures.
Part B. How does your answer compare to total world energy use at present, which is about 5×1022 joules per year? How does your answer compare to total world energy use at present, which is about joules per year? EspaceshipEworldenergyuse∼1 EspaceshipEworldenergyuse∼105 EspaceshipEworldenergyuse∼1020
Part C. The typical cost of energy today is roughly 5¢ per 1 million joules. Using this price, how much would it cost to generate the energy needed by this spaceship? Express your answer using two significant figures.
Answer: A 7.8 ·10^22 J B 1.6 times C 3.9 ·10^15 $
Explanation: A : Speed of light c = 3.0·10^8 m/s, 0.12·c = 3.6·10^7 m/s
Mass is 120·10^6 kg . Change of kinetic energy
E = ½mv² = 0.5 · 120·10^6 kg · (3.6·10^7 m/s)² = 7.776·10^22 J
B exponent is same , 7.776 / 5 = 1,55 times of energy use of Earth in year.
C Energy is 7.776·10^22 J / 10^6 = 7.776·10^16 MJ
Price is 0.05 $ · 7.776·10^16 MJ = 3.888·10^15 $
A. The energy required to get to the cruising speed is 7.8×10²² J
B. The energy needed will be 1.56 times the total world energy
C. The cost price required to generate the energy needed by the spaceship is $ 3.9×10⁵
A. Determination of the energy
Mass (m) = 120×10⁶ Kg
Velocity of light = 3×10⁸ m/s
Velocity of spaceship = 0.12 × 3×10⁸ = 3.6×10⁷ m/s
Energy (E) =?E = ½mv²
E = ½ × 120×10⁶ × (3.6×10⁷)²
E = 7.8×10²² JThus, the energy needed is 7.8×10²² J
B. Comparing the energy needed to the total world energy.
Energy needed = 7.8×10²² J
World energy = 5×10²² J
Energy needed / World energy = 7.8×10²² / 5×10²²
Energy needed / World energy = 1.56
Cross multiply
Energy needed = 1.56 × World energyThus, the energy needed is 1.56 times the World energy
C. Determination of the cost required to generate the energy
1×10⁶ J = $ 0.05
Therefore,
7.8×10²² J = (7.8×10²² × 0.05) / 1×10⁶
7.8×10²² J = $ 3.9×10⁵
Therefore, the cost required to generate the energy is $ 3.9×10⁵
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Which property of matter determines the amount of inertia an object has? Matter’s ________
Answer:
Mater's Mass is the Answer
A battery has an EMF of 12 Volts, internal resistance of 0.5 Ohms, and its terminal voltage is measured to be 13 Volts. The battery is ________ and has a current of ____ Amps passing through.
Answer:
The battery is charging and has a current of 2Amps passing through.
Explanation:
Given;
EMF of the battery, E = 12 V
internal resistance, r = 0.5 ohms
terminal voltage of the battery, ΔV = 13 volts
When the terminal voltage is greater than the EMF of the battery, the battery is being charged, allowing currents to pass in a reverse direction.
ΔV = E - Ir
ΔV - E = -Ir
13 - 12 = -0.5I
1 = -0.5I
I = 1 / -0.5
I = -2 A
The negative sign indicates the reverse direction of the current.
Therefore, the battery is charging and has a current of 2Amps passing through.
PLEASE HELPPPPPPPPPP
Answer:
13.09 s
Explanation:
From the question given above, the following data were obtained:
Power (P) = 275 W
Work (W) = 3600 J
Time (t) =?
Power is defined as the rate at which work is done. Mathematically, it can be expressed:
Power (P) = Work (W) / time (t)
P = W/t
With the above formula, we can obtain the time taken for the swimmer to accomplish the work. This can be obtained as follow:
Power (P) = 275 W
Work (W) = 3600 J
Time (t) =?
P = W/t
275 = 3600/t
Cross multiply
275 × t = 3600
Divide both side by 275
t = 3600 / 275
t = 13.09 s
Thus, it will take the swimmer 13.09 s to accomplish the work.
(10) The use of Doppler radar for speed detection and enforcement on the roads is very common and has been in use for a long time. Suppose a 10 GHz radar (also called radar gun or speed gun) measures the speed of a car at 120 km/h moving towards the radar gun. a. What is the change in the frequency of the reflected wave due to the speed of the car b. Calculate the sensitivity of the device in [Hz/km].
Answer:
The sensitivity of the device = 1.234 Hz per km
Explanation:
Given
Frequency (f) = 10 gHz
Speed of the car = 120 Km/h
As per the doppler’s effect
V = (change in frequency /frequency) *(c/2)
Substituting the given values, we get –
Change in frequency = {(2*10^9*120)/(3*10^8)} * (1000/3600)
Change in frequency = 37.03 Hz
b) speed of light = wavelength * frequency
3*10^8 = wavelength * 10*10^9
Wavelength = 0.03 m
Sensitivity = change in frequency /wavelength = 37.03/0.03 = 1234 Hz/m
1.234 Hz per km
MCQs. How does the heat from the Sun reach the Earth.(options)a: conduction b: convertion c: radiation d: combustion.
If the child has a mass of 13.9 kg, calculate the magnitude of the force in newtons the mother exerts on the child under the following conditions. (b) The elevator accelerates upward at 0.898 m/s2. 148.702 N
The elevator accelerates upward at an acceleration, then the magnitude of the force is 148.84 N.
What is Force?The force is the action of push or pull which makes an object to move or stop.
Given the mass of child m =13.9 kg, acceleration a =0.898 m/s², then the force will be given by
F = m(g-a)
F = 13.9 x (9.81 - (-0.898))
F = 148.84 N
Thus, the magnitude of the force is 148.84 N.
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What is the path of an electron moving perpendicular to a uniform magnetic field?
Explanation:
this is your answer I hope it is helpful please mark me brainly
A balloon contains 0.04m3 of air at a pressure of 1.20 x 105Pa. Calculate the pressure required to reduce its volume to 0.025m3 at constant temperature.
Answer:
you can simply answer p1v1=p2v2 p2 = p1v1÷ p2 then inter what given in the formula you get it pl=1.20x 105pa vl= 0.40m3 v2=0.025m3