The distance traveled by the train is 900 m.
The given parameters:
Initial velocity of the train, u = 15 m/sAcceleration of the train, a = 3 m/s²Time of motion, t = 20 sWhat is distance?Distance is a scalar quantity that shows the total path covered by an object.The distance traveled by the train is calculated as follows;
[tex]s = ut + \frac{1}{2} at^2\\\\s = (15 \times 20) + (0.5 \times 3 \times 20^2)\\\\s = 900 \ m[/tex]
Thus, the distance traveled by the train is 900 m.
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Answer:
900m
Explanation:
Use the equation: acceleration (a) = change in velocity (v – u) / time taken (t)
Rearrange to solve for the final velocity (v):
v = u + at
Substitute in values and solve:
v = 15 m/s + 3 m/s2 × 20 s = 75 m/s
Rearrange the equation for uniform acceleration (v2 – u2 = 2as) to solve for distance (s):
s = (v2 – u2) / 2a
s = ((75 m/s)2 – (15 m/s)2) / (2 × 3 m/s2)
s = (5,625 m2/s2 – 225 m2/s2) / 6 m/s2
s = 5400 m2/s2 / 6 m/s2
s = 900 m
Scientists have invented the equipment to harness the power of lighting for energy use. True or false
to calculatw the power produced by a force, the size of the force must be known. What else needs to be known to calculate the power
-- The distance the force moved through
-- How long the force lasted
The other thing we need to calculate the power is the "Velocity".
A quantity of labor or work done to be accomplished within a particular period of timeframe is determined as power. It is denoted by "P".According to the given query, we are talking about the relation between Power and Force. Along with simple instances where such an item is moved at continuous speed by a constant force.
The relation can be shown as:
→ [tex]P= Fv[/tex]
where,
P = PowerF = Forcev = VelocityThus the above is the right response.
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Which of the following best defines speed?
A. It is an objects speed at a specific point in time
B. It is the distance traveled by an object in a specific direction
C. It is a measure of how far an object moves over a certain amount of time
D. It is the total time over the distance
What is the height of a 50 kg person that has a potential energy of 4900J?
245,000m
98 m
10 m
Answer:
10 m
Explanation:
PE = mgh
m = 50kg
g= 9.8 m/s^2
h=?
so,
4900= 50×9.8× h
50h = 4900/9.8
50h = 500
h = 10 m
find acceleration of block and tension in strings if m1 =8kg m2= 4kg and take g=10m/s²
[tex]\sf{m_1}[/tex] = 8kg
[tex]\sf{m_2}[/tex] = 4kg
g = 10m/s²
[tex]\large\bold{\underline{\underline{To \: Find:-}}}[/tex]→Acceleration of block
→Tension in strings
[tex]\large\bold{\underline{\underline{Solution:-}}}[/tex]Let, the two equation will be ,
[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)
[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)
Putting the value of equation no (1) and (2) we get,
[tex]\implies[/tex] 4g = 12a
[tex]\implies[/tex] 4 × 10 = 12a
[tex]\implies[/tex] 40 = 12a
[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]
[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]
Again, we have to putting the value of a in the equation no (2) we get,
[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]
[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]
[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]
[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40
[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]
[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N
[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².
And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N
40 points and brainliest plz helppp luv yah thxx
A car moving at 10 m/s slows to a stop. It moves 25 meters forward while braking.
1. What is its braking acceleration?
Explain how you found your answer.
2. How much time does it take to slow to a stop?
Explain how you found your answer.
Answer:
hey want you to separate the energy’s and put them in the categories they go in like why are They different what is chemically different about them? Etc.why do they act differently.. do they act the same in some ways? Think about that
Explanation:
A bullet is fired straight up from ground level for a distance of 1688.3m at a speed of 182 m/s. How long does it take for the bullet to stop?
What are greenhouse gases? Can you name any?
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 53.9 m/s2 . The acceleration period lasts for time 6.00 s until the fuel is exhausted. After that, the rocket is in free fall.
Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant free-fall acceleration equal to 9.80 m/s2 .
Answer:
maximum height reach by rockect =970.2metre
Explanation:
A dumptruck filled with sand moves 1.8 km/h when it begins to accelerate uniformly at a constant rate. After traveling 4.0 102 m, the truck's speed is 24.0 km/h. What is the magnitude of the truck's acceleration?
The acceleration of the truck is obtained from the calculation done as 0.055 m/s^2.
What is the magnitude of the truck's acceleration?We know that the acceleration is defined as the rate of the change of the velocity of the object with time and we can be able to obtain the acceleration by the use of the equations of kinematics as usual.
Initial velocity = 1.8 km/h or 0.5 m/s
Final velocity = 24.0 km/h or 6.67 m/s
Distance covered = 4.0 * 10^2 m
Then;
v^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance covered
a = v^2 - u^2/2s
a = (6.67)^2 - (0.5)^2/2 * 4.0 * 10^2
a = 44.4 - 0.25/800
a = 0.055 m/s^2
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Similarities and differences between natural and synthetic for sugar
Answer:
THE REAL STUFF
For starters, sugar is sugar, no matter how it’s marketed, priced or packaged. All sugar offers the same number of calories, although some may be less processed. It seems like every third day a “new” natural sugar emerges as the next best thing. Take for example, the increasingly popular coconut sugar or maple sugar, which are actually just fancy names with a heftier price tag for one ingredient: sugar. Your body can’t tell the difference between raw coconut sugar or processed table sugar, all sugar is metabolized and digested the same. While some more natural forms of sugar may contain a bit more minerals and haven’t undergone as much refinement, they really aren’t any healthier.
THE ARTIFICIAL STUFF
The most popular artificial sweeteners include sucralose (Splenda), aspartame (Equal) and saccharin (Sweet’N Low), neotame, and acesulfame-K are found in diet sodas, light yogurts or ice creams, sugar-free chewing gums and candies among other products. They’re oftentimes marketed as diet, sugar-free, calorie-free, low-calorie, skinny or light.
Artificial sweeteners are man-made, unnatural chemical compounds that our body doesn’t understand or know how to metabolize. Some scientific evidence suggests artificial sweeteners may cause brain cancer or slow down metabolism – although most of these studies have been tested on animals, never humans.
Or what about the theory that eating alternative sweeteners makes you more inclined to eat a) a whole bag of sugar-free candies at one time, and b) overindulge in junk food later. Plus, certain types of sugar alcohols or sugar substitutes contain hard-to-digest ingredients that can manifest in symptoms of gastrointestinal discomfort, like bloating, gas, cramping, diarrhea, or even constipation.
If Newton's third law was true, then why does a table move when I push it? If the table exerted the same amount of force to me, why does it move?
Tyler drives 50km north. Tyler then drives back 30km south. What distance did he cover? What was his displacement?
Answer:
80 km is distance and 30km north is displacement
Explanation:
distance= 50+30=80km
displacement= 50-20=30
his displacement is 30km north
When Tyler drives 50 km north and then drives back 30 km south, we have:
1. The distance that he covers is 80 km.
2. Tylor's displacement is 20 km.
1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:
[tex] d = d_{1} + d_{2} = 50 km + 30 km = 80 km [/tex]
Hence, the distance traveled by Tyler was 80 km.
2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:
[tex] x = x_{1} + x_{2} = 50 km + (-30 km) = 20 km [/tex]
Therefore, Tyler's displacement is 20 km.
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Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the
material.
We have that for the Question "Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material." it can be said that
From the question we are told
Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material.
Generally the equation for the index of refraction is mathematically given as
[tex]n=\frac{C}{v}\\\\Therefore\\\\n=\frac{3*10^8}{2.5 * 10 }\\\\n=12000000\\\\[/tex]
Therefore
The index of refraction of the material is
n=12000000
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When the energy of a wave increases, what happens to the amplitude?
Answer:
The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.
Explanation:
When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.
What is the amplitude of a wave?The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.
It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.
Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.
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A stunt man launches a car from the edge of a cliff horizontally. If he is launching off a
30-meter high cliff and must hit a mark 268-meters down range, with what speed
must he leave the cliff?
Answer:
All i got to say is that he is dead dead
Explanation:
PLZ HELP ME
1. A stone is thrown horizontally from a cliff 30m high with an initial speed of 20m/s. How far from the cliff does the stone strike the ground?
2. A ball rolls off the edge of a table 1.44m above the floor and strikes the floor at a point 2m horizontally from the edge of the table.
A) What is the time the ball was in the air?
B) What is the initial velocity of the ball?
3. A golfer hits a ball and gives it an initial velocity of 40 m/s, at an angle of 30º above the horizontal.
A) How long does the ball stay in the air?
B) How far horizontally (the range) does the ball travel before hitting the ground?
Answer:
1. The stone will strike the ground 49.46 m from the base of the cliff
2. A) Approximately 0.542 seconds
B) Approximately 3.69 m/s
3. A) The time the ball spends in the air is approximately 4.0775 s
B) The horizontal range is approximately 141.25 m.
Explanation:
1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)
∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds
The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m
The stone will strike the ground 49.46 m from the base of the cliff
2. A) The time the ball spends in the air = t = √(h/(1/2 × g)
∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds
B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s
The initial horizontal velocity ≈ 3.69 m/s
3. A) The time the ball spends in the air is given by the following equation;
t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s
t ≈ 4.0775 s
B) The horizontal range, R, of the ball is given by the equation for the range of a projectile as follows;
[tex]Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}[/tex]
Substituting the known values, gives;
[tex]Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m[/tex]
The horizontal range ≈ 141.25 m.
A 30 kg object has a frictional force of 60 N. It's coefficient of friction must be...?
A) 0.2
B) 2
C) .002
D) 20
mass = 30kg
frictional force = coefficient of friction * (mass * g)
g = 9.8 m/s^2
So:
60N = x * 294 N
x = 60 N / 294 N = 0,2
Name three ways you could increase the strength of an
electromagnet:
Answer:
adding more turns to the coilwrapping the coil around an iron, more specially a nail ironincreasing the current flow into the coilExplanation:
A fire is burning in a fireplace. Where is the radiation?
A. You touch warm bricks next to the fireplace
B. You can feel the heat from across the room
C. Heat is rising up from the chimney
A stone is thrown straight up in the air. If g represents the acceleration due to
gravity, which one of the following statments about the stone is false?
When the stone reaches the top of its flight, its acceleration is still g.
As the stone rises, its potential energy decreases.
When the stone reaches the top of its flight, its energy is zero.
As the stone rises, it is accelerated downward.
As the stone rises, its kinetic energy decreases.
Answer:
The correct false statement is;
As the stone rises, its potential energy decreases
Explanation:
When the stone is thrown straight up into the air, the initial velocity, u, progressively decreases according to the following equation;
v = u - g·t
Where;
v = The final velocity
g = The acceleration due to gravity = 9.81 m/s²
t = The time taken
Therefore whereby, the kinetic energy. K.E. is given by the equation , K.E. = 1/2 × m × u², as u reduces, the kinetic energy reduces
However, the potential energy, P.E. is given as P.E. = m × g × h
Where;
h = Height
m = The mass of the stone
Therefore, as the stone rises, the potential energy increases.
What two things must you know to describe the motion of an object? __________________________________________________________________________
Distance is _________________________________________________________________
What is the displacement of a cyclist, who travels 1 mile north, then 1 mile east, and finally 1 mile south? ___________________________
Define speed ________________________________________________________________
How do speed and velocity differ? ______________________________________________
__________________________________________________________________________
How do velocities combine? In opposite directions? ________________________________ In the same direction? ________________________________________________________
A river flows at a velocity of 3 km/h relative to the riverbank. A boat moves upstream at a velocity of 15 km/h relative to the river. What is the velocity of the boat relative to the riverbank? ___________________________________
The rate at which velocity changes is called ________________________
True or false? Acceleration is the result of increases or decreases in speed.
A horse on a carousel that is moving at a constant speed is accelerating because _________________________________________________________________________
True or false? When the final velocity is less than the initial velocity of an object, the acceleration is negative.
The total distance traveled divided by the total time is _______________________
What are some common units for speed (give at least two) _____________ ___________
Define velocity ____________________________________________________________
Define acceleration _________________________________________________________
A quantity that has both magnitude and direction is called a _________________.
WILL MARK BRAINLIEST PLEASE HELP DUE IN 2 MINS
On a distance-time graph speed is a ____________ line and thus a ____________ graph.
On a distance-time graph acceleration is a ___________ line and thus a _______________ graph.
Answer:
velocity is vector Quantity
A satellite was in two separate crashes. In both crashes, the satellite had the same mass. Engineers want to know about the speed and direction of the satellite after the crashes. Why would the crash affect the motion of the satellite, and which crash caused a greater change in motion for the satellite?
Answer & Explanation:
Crashing into the asteroid would cause the satellite to slow down, stop, or reverse direction, because it is a force in the opposite direction to the satellite's motion. Whichever crash was a stronger force would cause it to change motion more. It takes a stronger force to change the velocity of a more massive object.
A generator converts mechanical energy to electrical energy by using a conducting metal loop turning in a...
A. magnetic field
B. Gravitational field
C. Steel sphere
D. Cooper sphere
Answer:
B- Gravitational Field
Explanation:
Have a nice day, hope you get a good grade!
The generator converts mechanical energy to electrical energy by using a conducting metal loop turning in a gravitational field.
What is the gravitational field?In terms of physics, a gravitational field represent the model that should be used for explaining the impact where the massive body should be extended into the space around it. Also, generating the force on the another massive body.
Therefore, based on the above explanation, the correct option is b.
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Rickey Henderson, baseball's record holder for stolen bases, approaches third base. He dives head first, hitting the ground at 6.75 m/s and reaching the base with a speed of 5.91 m/s, accelerating at -5.11 m/s 2 . Determine the distance Rickey slides across the ground before touching the base. How much time is he sliding for before touching the base?
Answer:
The distance is 1.04 m and time is 0.16 seconds.
Explanation:
Initial speed, u = 6.75 m/s
Final speed, v = 5.91 m/s
Acceleration, a = -5.11 m/s²
We need to find the distance Rickey slides across the ground before touching the base and the time he sliding for before touching the base.
Let d is the distance. It can be calculated using third equation of motion as follows :
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(5.91)^2-(6.75)^2}{2\times (-5.11)}\\\\d=1.04\ m[/tex]
Let t is the time he slides for before touching the base. Using first equation of motion as follows :
[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{5.91-6.75}{-5.11}\\\\t=0.16\ s[/tex]
So, the distance is 1.04 m and time is 0.16 seconds.
I need help on this, please tell me what it is.
Answer:
maria is right.
Explanation:
Choose ALL that apply: Read the story below and choose every sphere shown directly in the story. A volcano erupts on a mountain side. It creates a huge cloud of smoke and ash which block out the sun, making it harder for plants to grow.
Question 3 options:
Biosphere
Geosphere
Hydrosphere
Atmosphere
Answer:
biosphere
Explanation:
pretty sure bc it is ground
In which situation is the net force on the object equal to zero?
A.) a bicycle moving at a constant speed on a straight, level road
B.) an automobile braking to a stop
C.) a satellite moving at a constant speed around Earth in a circular orbit
D.) a pitched baseball being hit by a bat
Answer:
A.) a bicycle moving at a constant speed on a straight, level road.
Explanation:
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
[tex] F = ma[/tex]
Where;
F represents force measured in Newton.
m represents the mass of an object measured in kilograms.
a represents acceleration measured in meter per seconds square.
In Physics, when the net force acting on a body or an object is equal to zero (0); the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.
In this scenario, the situation in which the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.
The net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.
The given problem is based on the Newton's second law to define net force. The net force on any object is an external effort by which the object change its speed with respect to time or tends to change the state of its motion. The mathematical expression for the net force is,
F = ma
Here, F is the net force, m is the mass of object and a is the acceleration of object.
When the net force acting on a body or an object is equal to zero , then the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.In the given problem the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.
Thus, we conclude that the net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.
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If you are in a car at a stop sign and then the driver
presses on the gas pedal really hard, which way is the car
accelerating?
Answer:
it wont be because the hand brake would be on
You are making s'mores with a friend. When you heat the marshmallow over the fire, what happens to the volume of the air bubbles inside the marshmallows? *
Answer:
Heat was trapped within the marshmallow.
Explanation:
Increasing temperatures make air contained within the marshmallow extend to fill up more room, causing the versatile sugar combination to spread. Eventually, if there is so much tension? It's small explosion. But take the marshmallow out from the heat, and it's going to deflate even if the extended gelatin does not really recover quickly.
Answer:
Heat gets trapped within the marshmallow.
Explanation: