A train freight car weighs 25 tons when empty. A conveyor belt pours coal into the car at a constant rate of 1/3 ton per minute until it is full.

The dump truck (Refer to problem 8) weighs 55 tons when filled. At the same time the freight car is being filled, an identical freight car filled

to capacity is being emptied at a rate of 1/6 ton per minute.

How long, in minutes, until the freight cars are the same weight?

The tucks will weigh the same in

minutes.

How much coal will be in each truck when they weigh the same?

There will be

tons of coal in each truck.

Answers

Answer 1

Step-by-step explanation:

Step one:

mass of Freight car=25tons

the rate of filling is 1/3 ton per minute

let the time taken to fill the freight car be x

and the total mass after x minute be y

Hence the mass as a function of time is expressed as

y=25+1/3x----------1

mas of dump truck=55tons

rate of being emptied= 1/6 tons per minute

let the time taken to empty the dump truck be x

and the total mass after x minute be y

Hence the mass as a function of time is expressed as

y=55-1/6x----------2

Step two:

equating equations 1 and 2,

1. The tucks will weigh the same in

55-1/6x=25+1/3x

collect like terms

55-25=1/3x+1/6x

30=(2+1/6)x

30=3/6x

30=1/2x

30=0.5x

x=30/0.5

x=60min

or

1 hour

The tucks will weigh the same in  60minutes(1 hour)

2. How much coal will be in each truck when they weigh the same?

For the  train freight car, the weight after 60 minutes is

y=25+1/3(60)

y=25+20

y=55tons

55-25=20tons

There will be 20tons

For the  dump truck, the weight after 60 minutes is

y=55-1/6(60)

y=55-10

y=45tons

55-45=10tons

There will be 10tons


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Inverse both sides

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The correct answer is (( B )) .

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Thomas used a can to feel his new fish tank with water. The fish tank holds 11 gallons of water. His can hold 1/5 of a gallon. How many times will Thomas have to feel his canned to put 11 gallons of water in a fish tank?

Answers

Answer:

55

Step-by-step explanation:

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Answers

The correct format of the question is

After an​ accident, police can use the formula [tex]v=2\sqrt{5L }[/tex] to estimate the​ speed, v, in miles per​ hour, that a car was traveling by measuring the length of the skid​ marks, L, in feet. Estimate the speed of a car that left skid marks 118 ft long. If the posted speed limit is 45 ​mi/h, was the car​ speeding? The speed of a car that left skid marks 118 ft long was about nothing ​mi/h.

Answer:

48.6mi/h, Yes the car was speeding.

Step-by-step explanation:

The speed of the car is given by  [tex]v=2\sqrt{5L }[/tex]

Skid length (L) = 118ft

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  = 2 [tex]\sqrt{590}[/tex]  

  =  2*24.3

V = 48.6mi/h

Since the speed limit is 45mi/h and the velocity of this driver is 48.6mi/h it is clear that was speeding by 3.6mi/h over speed limit.

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