A toy car, initially travelling in a straight line at 30.0 cm/s, slows down with a constant linear acceleration of 3.0 cm/s2. How much time passes before the toy car comes to a halt?

d) ≈ 0.87 m/s²

Hi there !

F = m×a => a = F/m

a = 59N/68kg

1 N = 1kg·m/s²

= (59kg·m/s²)/68kg

= 0.8676 m/s²

≈ 0.87 m/s²

Good luck !

Answer: C. Trial 3

Explanation:

Trial 1 and 2 equal 1.5, Trial 3 equals 1 and Trial 4 equals 3. Trial 3 is the smallest current .

The trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.

To know the trial which generates the smallest current, we need to determine the current in each trial.

Since current I = V/R where V = voltage and R = resistance.

For trial 1, V = 1.5 V and R = 200 Ω

So, I = 1.5 V/200 Ω

= 0.0075 A

= 7.5 mA

For trial 2, V = 1.5 V and R = 100 Ω

So, I = 1.5 V/100 Ω

= 0.015 A

= 15 mA

For trial 3, V = 3 V and R = 200 Ω

So, I = 3 V/200 Ω

= 0.015 A

= 15 mA

For trial 4, V = 3 V and R = 100 Ω

So, I = 3 V/100 Ω

= 0.03 A

= 3 mA

Trial 2 and trial 3 both produce a the smallest current of 15 mA.

So, the trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.

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Answer:

A

Explanation:

the air is the medium man

Answer:

the desk

Explanation:

Answer:

Yes it is a physical change

Explanation:

The cookie is still a cookie even when it has been broken apart, so it cannot be a chemical change. The cookie only changed physically.

Answer:

160,934.4 cm or in other words *160,934*

Explanation:

1 mile = 5280 ft.

5280 ft. = 63360 in.

63360 in. = 160934.4

Answer:

Runner A will be 0.05 km from the flagpole, and runner B will be 0.07 km from the flagpole

Explanation:

We can find when their paths will cross as follows:

[tex] X_{f} = X_{0} + v_{0}t + \frac{1}{2}at^{2} [/tex]

Where:

[tex]X_{f}[/tex] is the final position

[tex]X_{0}[/tex] is the initial position

v₀ is the initial speed

t is the time

a is the acceleration = 0 (since they are running with a constant velocity)

When their paths cross we have:

[tex]X_{fA}+X_{fB}=5.8+4.9=10.7 km[/tex]

[tex]V_{A}t+V_{B}t=10.7[/tex]

[tex]8.6t+7.1t=10.7[/tex]

[tex]t = 0.68 h[/tex]

Now we can find the final distance of each runner.

[tex]X_{fA}=V_{A}*0.68[/tex]

[tex]X_{fA}=8.6*0.68 km[/tex]

[tex]X_{fA}=5.85 km[/tex]

[tex]X_{fB}=V_{B}*0.68[/tex]

[tex]X_{fB}=7.1*0.68[/tex]

[tex]X_{fB}=4.83 km[/tex]

Therefore, runner A will be 0.05 km from the flagpole, and runner B will be 0.07 km from the flagpole.

I hope it helps you!

Answer:

300m per minute or 5m per second

Answer: true

Plz mark brainliest:)

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Explanation:

Consider a mass of 10 kg, so m = 10

Let's say we apply a net force of 20 newtons, so F = 20

The acceleration 'a' is...

F = ma

20 = 10a

20/10 = a

2 = a

a = 2

The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.

---------------

Now let's double the net force on the object

F = 20 goes to F = 40

m = 10 stays the same

F = ma

40 = 10a

10a = 40

a = 40/10

a = 4

The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.

---------------

In summary, if you double the net force applied to the object, then the acceleration doubles as well.

Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.

So if an object's mass stays the same while the net force on it doubles, then its acceleration will also double.

We don't know anything about the "trials".  This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.

We also don't know anything about "question 1".

Answer:

Rating of percieved exertion

Answer:

A

Explanation:

I know that it's true

Answer:Explanation:

A common example of sublimation is the dry ice, heavy CO2.

Answer: Both technicians A and B

Explanation:

Based on the scenario in the question, it should be noted that leather shoes offer more protection than canvas shoes and that steel toed boots are essential to protecting your feet from injury.

Leather shoes are more durable and offer better protection than canvas. The strength of the material that they're made from can help in offering extra protection which is necessary in an environment where there's possibility of accidents involving falling objects.

Also, for the people who work in a work environment with many heavy machines and equipments, it is vital to it on protective steel toed boots in order to prevent the workers from feet related injuries.

Answer:

21.3V

Explanation:

Explanation

E = V + Ir

V = E- Ir

V = 24 - {(24/36) x 4}

V = 21.3V

Answer:

1) False, since constant speed means constant velocity, but with constant direction as well. Velocity is speed with direction. When you move in a circle, there are boundaries which means that a constant moving speed will cause the object to veer(move in different directions) to maintain movement, If it doesn't veer, the object will deflect(rebound) off the surface due to friction, and impact force or depending on its physical bond of malleability or density.

2a) Create position vectors by drawing a ray from the center(origin) of the circle to each of your desired points, it's magnitude will be the radius(how convenient). Both of these vectors go from the center of the circle to the position on the circle. In general, the distance from the origin to a point is called the radius vector.

2b)

Answer:

the bread is getting heated from top and bottom because the oven is heated all over and the particles from the oven makes the bread's particles heat up and the bread will be done

Explanation:

i have the same answer

Answer:

The air is heated by the heat source in the oven. The hot air rises, surrounds the bread, and heats the bread on all sides.

Explanation:

Answer: Measurement is the assignment of a number to a characteristic of an object or event, which can be compared with other objects or events. The scope and application of measurement are dependent on the context and discipline. In the natural sciences and engineering, measurements do not apply to nominal properties of objects or events, which is consistent with the guidelines of the International vocabulary of metrology published by the International Bureau of Weights and Measures. However, in other fields such as statistics as well as the social and behavioural sciences, measurements can have multiple levels, which would include nominal, ordinal, interval and ratio scales.

Explanation:

Answer:

whattt

Explanation:

Answer:

skip zone

Explanation:

Answer:

Vaporization occurs when a substance changes from a liquid to a gas. The molecules in a liquid are in constant motion while staying relatively close together due to intermolecular forces. When an increase in temperature occurs, the molecules' kinetic energy also increases. If a liquid is heated the particles are given more energy and move faster and faster expanding the liquid. The most energetic particles at the surface escape from the surface of the liquid as a vapor as it gets warmer. Liquids evaporate faster as they heat up and more particles have enough energy to break away.

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Answer:

660 centimeters

Explanation:

There are 100 cm in 1 m. To convert from m to cm, multiply by 100.

[tex]6.6 \times 100 = 660[/tex]

There are 660 cm in 1 m.

Answer:

Physical change

Explanation:

A physical change can be reversible where the original form of the matter can be restored, or irreversible where the original form cannot be restored. Therefore, sawdust is a physical change.

Answer:

Wavelength

Explanation:

The distance between two crests or two troughs on a transverse wave is known as the wavelength.

The wavelength of a periodic wave is its spatial period or the distance over which the wave's structure repeats. It's the distance between two adjacent corresponding points of the same phase on the wave, such as two adjacent crests, troughs, or zero-crossings, and it's a feature of both travelling and standing waves, as well as other spatial wave patterns.

As discussed above the wavelength, therefore, the distance between two crests or two troughs on a transverse wave is known as the wavelength.

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Answer:

True

Explanation:

The term 'plyometrics' is used interchangeably with the term 'jump training'. The technique can be used for training in sports that require explosive movements.

Answer:

By observing the time between transits, we know the orbital period. Kepler's Third law can be used to determine the orbital radius of the planet if the mass of the orbiting star is known (R3=T2−Mstar/Msun, the radius is in AU and the period is in earth years).

Explanation:

hope this helps!

Answer:

250J

Explanation:

Given parameters:

Force on block = 100N

Degree of pull  = 60°

Mass of block  = 10kg

Distance  = 5m

Unknown:

Work done on the object = ?

Solution:

The workdone on a body is the force applied to move a body in a specific direction;

  Workdone  = force x distance cos Ф

Insert the parameters and solve;

     Workdone  = 100 x 5 cos 60°

    Workdone  = 250J

Complete Question  

The complete question is shown on the first and second uploaded image  

Answer:

When water is used the reading is  [tex]    R =  2281.6 \  cm  [/tex]

When mercury is used the reading is [tex]   R =  23.83 \ cm [/tex]  

The best fluid to use is mercury because for water a slight change in toluene level will cause a  large change in height .

Explanation:

From the question we are told that  

    The length of the leg of the manometer to the top of the tank is  d =  500cm

   The toluene level where in the tank where the height of the manometer fluid level in the open arm is equal to the height where the manometer is connected to the tank is  h =150 cm  

   The manometer reading is  R  

Generally at the point where the height of the open arm is equal to the height of the of the point connected to the tank ,  

   The pressure at the height of the both arms of the manometer corresponding to the base of the tank are equal  

     i.e   [tex]P_1 = P_2[/tex]

Here [tex]P_1[/tex] is the pressure of the manometer at the point corresponding to the base of the tank and this is mathematically represented as  

       [tex] P_{atm} + P_1 =  P_{atm} + P_t[/tex]

Here [tex]P_t[/tex] is the pressure due to the toluene level in the tank and in the arm of the manometer connected to the tank and this is mathematically represented as  

         [tex]P_t  =  \rho_t  * g  * h_i[/tex]

Here  

      [tex]\rho_t [/tex] is the density of toluene with value  [tex]\rho_t =  867 kg/m^3 [/tex]

 [tex]h_i[/tex] is the height of the connected arm above the point equivalent to the base of the tank , this mathematically represented as

          [tex]h_i =  d - h + R[/tex]

  and  [tex] P_2 [/tex] is the the pressure at the open arm of the manometer at the point equivalent to the base of the base of the tank and this is mathematically represented as

         [tex] P_2 =  \rho_f * g *  h_f [/tex]

Here  

       [tex]\rho_f[/tex] is the density of the fluid in use , if it is water the density is  

       [tex]\rho_w =  1000 \  kg /m^3 [/tex]

and  if it is  mercury the density is  

        [tex]\rho_m =  13600 \  kg /m^3 [/tex]

[tex]h_f[/tex] is the height of the  fluid in the open arm of the manometer from the point equivalent to the base of the tank which is equivalent the manometer reading R

So when the fluid is water we have

      [tex] P_{atm} +  \rho_t* g *(d - h + R) =  P_{atm} + \rho_f * g *  h_f[/tex]

=>   [tex]   \rho_t* (d - h + R) =   \rho_w *  h_f[/tex]        

=>   [tex]    867  (500 - 150 + R) =    1000 *  R [/tex]

=>    [tex]    R =  2281.6 \  cm  [/tex]

So when the fluid is mercury we have      

  [tex]   \rho_t* (d - h + R) =   \rho_m *  h_f[/tex]          

=>   [tex]    867  (500 - 150 + R) =   13600  *  R [/tex]  

=>   [tex]   R =  23.83 \ cm [/tex]  

The difference in the mercury reading for mercury due to the fact that they have different densities as we have seen in this calculation

So the best fluid to use is mercury because for water a slight change in toluene level will cause a  large change in height .

Answer:

Explanation:

1). Distance traveled during the first minute (A-B)

    = Distance from A to C + Distance from C to D + Distance from D to B

    = 40 + 100 + 40

    = 180 m

   Option (4) will be the answer.

2). Displacement after first minute (A-B)

    = Distance from A to B

    = 180 m East

    Option (2) is the answer.

3). Distance traveled during the first 2 minutes (A - B - C)

    = Distance from A to B + Distance from B to C

    = 180 + 140

    = 320 m

    Option (3) will be the answer.

4). Displacement after first 2 minutes (A-B-C)

    = Distance between A and C

    = 40 m towards east

    Option (1) is the answer.

5). Distance traveled during 3 minutes (A-B-C-D)

    = Distance between A to B + Distance between B to C + Distance between C to D

    = 180 + 140 + 100

    = 420 m

   Option (4) is the answer.

6). Displacement after total 3 minutes (A-B-C-D)

    = Distance between A and D

    = Distance between A to C + distance between C to D

    = 40 + 100

    = 140 m

     And the direction is towards East.

     Option (3) is the answer.