Answer:
4.8 turns would be made around the tube
Explanation:
You need the circumference of the tube since it's just a lifted circle
2×pi×3=18.85
90.42/18.85=4.79
And round that to 4.8
Hello guys sana ok lng kau
sssssssssssss
Explanation:
Answer:
hello how are you
have a great day
How were the barriers to critical thinking presented?
Answer:
At a personal level, barriers to critical thinking can arise through: ... self-centred or societal/cultural-centred thinking (conformism, dogma and peer-pressure) unconscious bias, or selective perception. an inability to be receptive to an idea or point of view that differs from your own (close-mindedness)
Explanation:
A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing through the cross-sectional area in 10s is
Answer:
n = 1.56 x 10¹⁷ electrons
Explanation:
First of all, we will calculate the current passing through wire:
[tex]I = \frac{q}{t}[/tex]
where,
I = current = ?
q = charge = 9 mC = 0.009 C
t = time = 3.6 s
Therefore,
[tex]I = \frac{0.009\ C}{3.6\ s}\\\\I = 0.0025\ A = 2.5\ mA[/tex]
Now, for the same current in 10 s time the charge will be:
q = It = (0.0025 A)(10 s)
q = 0.025 C
Now, the number of electrons can be given as:
[tex]q = ne\\\\n = \frac{q}{e}\\\\[/tex]
where,
n = no. of electrons = ?
q = charge = 0.025 C
e = charge on single electron = 1.6 x 10⁻¹⁹ C
Therefore,
[tex]n = \frac{0.025\ C}{1.6\ x\ 10^{-19}\ C}[/tex]
n = 1.56 x 10¹⁷ electrons
The key insight that Bohr introduced to his model of the atom was that the angular momentum of the electron orbiting the nucleus was quantized. He introduced the postulate that the angular momentum could only come in quantities of nh/(2π), where h is Planck's constant and n is a nonnegative integer (0,1,2,3,…). Given this postulate, what are the allowable values for the velocity v of the electron in the Bohr atom? Recall that, in circular motion, angular momentum is given by the formula L= mvr.
Answer:
v = [tex]n \frac{\hbar }{m r}[/tex]
the sppedof the electron is also quantized
Explanation:
The angular momentum of a rotating body is
L = m v r
in Bohr's atomic model the quantization postulate is that the angular momentum is equal to
L = n [tex]\hbar[/tex]
we substitute
n [tex]\hbar[/tex] = m v r
v = [tex]n \frac{\hbar }{m r}[/tex]
where n is an integer.
Therefore, the sppedof the electron is also quantized, that is, sol has some discrete values.
what type of signal is utilized by the GP's satellite ?
Answer:
Hi how are you doing today Jasmine
Answer:
The answer is B
Explanation:
I did the USA test prep
the density of brick is 1,600 kg/m3. what is the mass of a brick with a volume of 0.0006 m3? WILL MARK BRAINLIEST
Answer:
.0000004
Explanation:
The mass of a brick with a volume of 0.0006 m³ and a density of 1600 kg/m³ is 0.96kg.
HOW TO CALCULATE MASS?The mass of a substance can be calculated by multiplying the density of the substance by its volume. That is;
Mass = density × volume
According to this question, the density of brick is 1,600 kg/m3 and it has a volume of 0.0006m³. The mass is calculated as follows:
Mass = 0.0006 × 1600
Mass = 0.96kg
Therefore, the mass of a brick with a volume of 0.0006m³ and a density of 1600 kg/m³ is 0.96kg.
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What is the acceleration of a bicycle that goes from 3 m/s to 1 m/s in 2 seconds?
0.5 m/s2
1.0 m/s2
1.5 m/s2
-1.0 m/s2
Answer:
a=vf - vi/t
vf=final velocity
vi= initial velocity
t=time period
Now The bicycle went from 3ms to 1ms...
1.. It decelerated
2... Since it went from 3 to 1... 1 is the final velocity while 3 is the initial Velocity
Applying the Formula
a= 1-3/2
= -2/2
a= -1ms-²
Option D
why do trucks need a runaway ramp
Answer:
in case they lose control going downhill.
Explanation:
which is why they usually have a steep incline and are quite long. You see them used typically when the trucks brakes fail.
Which statement best describes covalent bonding?
A. two nonmetal atoms share electrons between them
B. many atoms give up electrons that can move among the atoms
C. two metal atoms share electrons between them
D. a metal atom transfers electrons to a nonmetal atom
What is the answer to this problem?
Answer:
The answer is A
Explanation:
An insulator doesn't have to be a metal
<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3
Answer:
a substance which does not readily allow the passage of heat or sound.
<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3
These steps are followed when using the half-life of carbon-14 to determine
the age of an object that contains carbon. What is the correct order of these
steps?
A. Use the half-life of carbon-14 to determine the number of half-lives
that have passed.
B. Measure the ratio of parent nuclei to daughter nuclei.
C. Use the number of half-lives that have passed to determine the age
of the object.
A. A,B,C
B. A,C,B
0 0
C. B, A,C
D. C, A, B
Answer: a different one is a.b.c
Explanation: still for ape.x
The correct order to determine the age of the an object using carbon-14 is C, A, B. Thus, option D is correct.
What is half life?
The half-life time is defined as the time taken by the radioactive element to reduce one half of its initial value. It is denoted by t(1/2).
To measure the age of an object, a radioactive isotope called carbon-14 is used. The half-life of carbon-14 is 5,730 years. All the objects in the universe consumes carbon in their lifetime and hence, carbon-14 is used to measure the age of the objects.
The process of determining the age of objects using carbon-14 is called Radiocarbon dating. All living organisms consume carbon in means of food and from atmosphere and when the plant and animals dies, the radioactive carbon atoms start decaying.
When it starts decaying, by using Carbon-14 the age of an object is calculated. The age is estimated by measuring the amount of carbon-14 present in the sample and comparing this carbon with the reference Carbon-14 isotope.
The amount of carbon in preserved plants is identified by:
f(t) = 10e {₋ct}
t = time in years when the plant dies( t= 0)
c = the amount of carbon-14 remaining in preserved plants.
The steps include to find the age of an object is :
1. Use the number of half-lives that have passed to determine the age of the object.
2. Use the half-life of carbon-14 to determine the number of half-lives that have passed.
3.Measure the ratio of parent nuclei to daughter nuclei.
Hence, from these steps the age of an object is determined. Therefore the correct solution is D) C, A, B.
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3. What is the force of sliding friction
between a block and the ground if the
coefficient of kinetic friction is uk = 0.17
and the block weighs 18 N?
a. 0.52 N
b. 55 N
C. 18 N
d. 3.1 N
Answer:
the force of the friction is A-0.52
Hoover Dam on the Colorado River is the highest dam in the United States at 221 m, with an output of 1300 MW. The dam generates electricity with water taken from a depth of 100 m and an average flow rate of 640 m3/s
(a) Calculate the power in this flow in watts. 627200000XW Enter a number
(b) What is the ratio of this power to the facility's average of 680 MW? Additional Materials Reading
Answer:
a) 627840000 W
b) 0.9233
Explanation:
The rate at which energy flows through the dam for the generation of electricity is proportional to the volulme flow rate times the potential energy per unit volume.
Mathematically,
P = Q(ρgh)
Where, ρ is water density, g is accelaration due to gravity, h is height through which water falls over the turbine and Q is the discharge.
a) The power can be calculated as
P = 640(1000×9.81×221)
P = 627840000 W
b) The ratio = Calculated power / avarage power
= 62784×10^4/680×10^6
= 0.9233
URGENT: Testing shows that a sample of wood from an artifact contains 50% of the
original amount of carbon-14. Given that the half-life of carbon-14 is 5730
years, how old is the artifact?
O A. 22,920 years
B. 11,460 years
C. 5730 years
O D. 2865 years
Answer:
Im so so sorry but I do now know how to do this
Explanation:
Polarizing windows, filters, etc. are often used to reduce the amount of light that enters the lens of a camera or into a room or a car. A library atrium has an overhead skylight that lets in too much light during the day which heats up the interior of the library far too much. The building engineer installs new double paned polarizing sky lights to reduce the intensity. If sunlight, which is unpolarized, has an average intensity of 1366 W/m2 what angle should the polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 33% of the original value
Answer:
θ = 35.7º
Explanation:
For this exercise we must use the law of Malus
I = I₀ cos² θ
where the angle is between the two polarizers.
When the unpolarized light from the sun reaches the first polarizer, only the light polarized in the direction manages to be transmitted, which is why
I₁ = I₀ /2
this light reaches the second polarizer
I₂ = I₁ cos² θ
I₂ = I₀/2 cos² θ
cos² θ = 2 I₂ / Io
indicate that the transmitted light is 33% = 0.33 I₀
cos² θ = 2 0.33
cos θ = √0.66
θ = cos⁻¹ 0.8124
θ = 35.7º
if an object sinks in water its density is greater than that of water
distance moved by the effort in lifting the 5000N load to the height of 15m
Answer:
Hello There!!
Explanation:
Work done= force × distance moved
Work done=5000N×15m
Work done=75,000J
hope this helps,have a great day!!
~Pinky~
Which element has 1 valence electron in its outer shell and will react with a
group 17 element in a 1:1 ratio?
A. Strontium
B. Silicon
C. Lithium
D. Sulfur
Answer: C. Lithium
Explanation: Quizzed
C. Lithium has 1 valence electron in its outer shell and so will react with a group 17 element in a 1:1 ratio.
The last number of group that an element belongs to on the periodic table tells the number of valence electrons that it will have.
Lithium is in group 1 of the periodic table which means that it has only a single electron in its valence shell.Group 17 elements have seven valence electrons and so need one more to achieve stability which is why they will react with Lithium (which has that one electron) in a 1:1 ratio.
Some of those elements include:
Fluorine ChlorineBromineIodineIn conclusion therefore, Lithium has 1 valence electron and will react with group 17 elements in a 1:1 ratio.
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A playground merry-go-round with a radius of 2.0 m and a rotational inertia of 100 kg m2 is rotating at 3.0 rad/s. A child with a mass of 22 kg jumps onto the edge of the merry-go-round, traveling radially inward. What is the new angular speed of the merry-go-round
Answer:
The new angular speed of the merry-go-round = [tex]1.6rad/sec[/tex]
Explanation:
From angular momentum conservation
[tex]Iw_1 = (I + mr^2)w_2\\\\3*100 = (100 + 22*2^2)w_2\\\\300 = (100 + 88)w_2\\\\w_2 = \frac{300}{188}\\\\w_2 = 1.6rad/sec[/tex]
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A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing through the cross-sectional area in 10s is
Each electron has a charge of :
[tex]1.6 \times 10 {}^{ - 19} \: C[/tex]
For producing 1 Cuolomb charge we need :
[tex] \mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }[/tex][tex] \dfrac{10 {}^{19} }{1.6} [/tex][tex] \dfrac{10\times 10 {}^{19} }{16} [/tex][tex] \dfrac{100 \times 10 {}^{18} }{16} [/tex][tex] \mathrm{6.24 \times 10 {}^{18} \: \: electrons}[/tex]Now, for producing 0.009 C of charge, the number of electrons required is :
[tex]0.009 \times 6.24 \times {10}^{18} [/tex][tex]0.05616 \times 10 {}^{18} [/tex][tex] \mathrm{5.616 \times 10 {}^{16} \: \: electons}[/tex]_____________________________
So, Number of electrons passing through the cross section in 3.6 seconds is :
[tex] \mathrm{5.616 \times 10 {}^{16} \: \: electrons} [/tex]
Number of electrons passing through it in 1 Second is :
[tex] \dfrac{5.616 \times {10}^{16} }{3.6} [/tex][tex] \mathrm{1.56 \times 10 {}^{16} \: \: electrons}[/tex]Now, in 10 seconds the number of electrons passing through it is :
[tex]10 \times \mathrm{1.56 \times 10 {}^{16} \: \: }[/tex][tex] \mathrm{1.56 \times 10 {}^{17} \: \: electrons}[/tex]_____________________________
[tex]\mathrm{ \#TeeNForeveR}[/tex]
During a football game player A (mass 120kg velocity 5.5m/s [L]) tackles and grabs player B (mass 105kg velocity 7.9m/s [R]). What is the final speed of the two players immediately after the collision?
Answer:
6.62m/s
Explanation:
Given data
M1= 120kg
U1= 5.5m/s
M2= 105kg
U2= 7.9m/s
The system experiences an inelastic collision, the expression for inelastic collision is
M1U1+ M2U1= (M1+M2)V
Subsitute
120*5.5+ 105*7.9= (120+105)*V
660+ 829.5= (225)*V
1489.5= (225)*V
Divide both sides by 225
V= 1489.5/225
V= 6.62m/s
Hence the common velocity is 6.62m/s
map.
Which best describes the motion of the object
between 1 and 4 seconds?
کے م
The object has decreasing acceleration and
increasing velocity.
The object has positive acceleration and eventually
stops.
The object has decreasing acceleration and
decreasing velocity.
The object has negative acceleration and eventually
stops.
Answer:
The object has decreasing acceleration and decreasing velocity.
The Moon is attracted to the Earth. The mass of the Earth is 6.0x1024 kg and the mass of the Moon is 7.4x1022 kg. If the Earth and Moon are 345,000 km apart, what is the gravitational force between them?
Sorry I don't know the answer
What is this answer? A blank is a combination of two or more substances, elements, compounds, or both, in the same place but not chemically combined
what types of cuts do jig saw sanders make?
Coherent light with wavelength 591 nm passes through two very narrow slits, and the interference pattern is observed on a screen a distance of 3.00 m from the slits. The first-order bright fringe is a distance of 4.84 mm from the center of the central bright fringe. For what wavelength of light will the first-order dark fringe be observed at this same point on the screen?
Answer:
The wavelength will be "1.182 μm".
Explanation:
The given values are:
Wavelength
[tex]\lambda=591 \ nm[/tex]
or,
[tex]=591\times 10^-9 \ m[/tex]
Distance,
[tex]d = 3.00 m[/tex]
[tex]n = 1[/tex]
Distance of fringe from center,
[tex]y = 4.84 \ mm[/tex]
We have to find the wavelength of first order dark fringe,
[tex]\lambda = ?[/tex]
As we know,
⇒ [tex]y_{bright} =\frac{1\times \lambda\times L}{d}[/tex]
On putting the given values in the formula, we get
[tex]0.00484=\frac{1\times (591\times 10^{-9})\times 3}{d}[/tex]
On applying the cross multiplication, we get
[tex]\lambda = \frac{0.00484\times 000036632}{0.5\times 3}[/tex]
[tex]=1182\times 10^{-9}[/tex]
or,
[tex]=1.182 \ \mu m[/tex]
A wall in a house contains a single window. The window consists of a single pane of glass whose area is 0.10 m2 and whose thickness is 8 mm. Treat the wall as a slab of the insulating material Styrofoam whose area and thickness are 11 m2 and 0.15 m, respectively. Heat is lost via conduction through the wall and the window. The temperature difference between the inside and outside is the same for the wall and the window. Of the total heat lost by the wall and the window, what is the percentage lost by the window
Answer:
the percentage of heat lost by the window is 93.18%
Explanation:
Given the data in the question;
Area of glass [tex]A_{glass[/tex] = 0.10 m²
Thickness of glass [tex]t_{glass[/tex] = 8 mm = 0.008 m
Area of Styrofoam [tex]A_{styrofoam[/tex] = 11 m²
Thickness of Styrofoam [tex]t_{styrofoam[/tex] = 0.15 m
we know that;
Thermal conductivity of glass [tex]k_{glass[/tex] = 0.80 J/smC°
Thermal conductivity of Styrofoam [tex]k_{styrofoam[/tex] = 0.010 J/smC°
Now, temperature difference between outside and inside the walls and window is ΔT
So, In time t, heat lost due to conduction in the window will be;
[tex]Q_{glass[/tex] = [[tex]k_{glass[/tex] × [tex]A_{glass[/tex] × ΔTt] / [tex]t_{glass[/tex]
we substitute
[tex]Q_{glass[/tex] = [ 0.80 × 0.10 × (ΔT)t] / 0.008
[tex]Q_{glass[/tex] = [ 0.80 × 0.10 × (ΔT)t] / 0.008
[tex]Q_{glass[/tex] = 10(ΔT)t J
Also, the heat lost due to conduction in the wall be;
[tex]Q_{styrofoam[/tex] = [[tex]k_{styrofoam[/tex] × [tex]A_{styrofoam[/tex] × ΔTt] / [tex]t_{styrofoam[/tex]
we substitute
[tex]Q_{styrofoam[/tex] = [ 0.010 × 11 × ΔTt] / 0.15
[tex]Q_{styrofoam[/tex] = 0.7333(ΔT)t J
Now, Net heat lost in the wall and window is;
Q = [tex]Q_{glass[/tex] + [tex]Q_{styrofoam[/tex]
Q = 10(ΔT)t J + 0.7333(ΔT)t J
Q = 10.7333(ΔT)t J
So, the percentage of heat lost by the windows will be;
% of heat lost = [tex]Q_{glass[/tex] / Q
= 10(ΔT)t J / 10.7333(ΔT)t J
= 0.93167
= ( 0.93167 × 100 )%
= 93.18%
Therefore, the percentage of heat lost by the window is 93.18%
3.Which of the following is a derived physical quantitySingle choice.
Length
Mass
Stress
Time
Answer:
length
Explanation:
Legth is derived physical quantity
Science questions!! Please help!!
Post Assessment on Investigating the Immune System
please help!! Please choose the right answers!! Dont guess if you dont know the answers!!
Suppose a 118kg watermelon is held 5m above the ground before sliding along a frictionless ramp to the ground. How high above the ground is the watermelon at the moment it's kinetic energy is 4,610J
This question involves the concepts of kinetic energy, potential energy, and the law of conservation of energy.
The watermelon is "1.02 m" above the ground.
The total energy of the watermelon can be found by its potential energy at the highest point:
Total Energy = mgh
where,
m = mass = 118 kgg = 9.81 m/s²h = height = 5 mTherefore,
Total Energy = (118 kg)(9.81 m/s²)(5 m)
Total Energy = 5787.9 J
LAW OF CONSERVATION OF ENERGYNow, according to the law of conservation of energy, at the given point:
Total Energy = Kinetic Energy + Potential Energy
5787.9 J = 4610 J + mgh'
[tex]h'=\frac{5787.9\ J-4610\ J}{(118\ kg)(9.81\ m/s^2)}[/tex]
h' = 1.02 m
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