Since two of the quantities are squares and the sum of all of three is equal 21, then the possible values of those two quantities are: 1,4,9,16
Let's consider each possibility
1 and 4
21-1-4=16, but 16 is also square and there can be only two square so NO
1 and 9
21-1-9=11, but 11 is prime, so NO
1 and 16
21-1-16=4... 4 is a square ,so NO
4 and 9
21-4-9=8 , 8 is not prime and not a square, so YES
4 and 16
21-4-16=1, but 1 is a square ,so NO
9 and 16
9+16=25>21 so.. NO
Therefore, the amounts in the first three bowls are 4,8,9.
what are the next terms in the number pattern -11, -8, -5, -2, 1
Answer:
4, 7, 10, 13
Step-by-step explanation:
Hey there!
Well in the given pattern,
-11, -8, -5, -2, 1
we can conclude that the pattern is +3 every time.
-11 + 3 = -8
-8 + 3 = -5
-5 + 3 = -2
-2 + 3 = 1
And so on
4, 7, 10, 13Hope this helps :)
Please help me so confused
Answer:
m = 15
Step-by-step explanation:
m/9 + 2/3 = 7/3
Subtract 2/3 from each side
m/9 + 2/3 -2/3= 7/3 -2/3
m/9 = 5/3
Multiply each side by 9
m/9 *9 = 5/3 *9
m = 15
Some one please help with question 10!!!
Answer:
Choice A.
[tex]2 {x}^{ \frac{2}{5} } \times y ^{ \frac{2}{3} } [/tex]
Can someone help I would really appreciate
Answer:
18/a
Step-by-step explanation:
quotient means divide
18/a
Which expression is equivalent to -80?
O -4.5
O-4.5
O 4/5
O 4.5
Answer:
-4/5
Step-by-step explanation:
When you divide -4 from 5 you get -0.80
How many different sets of polar coordinates can be given for a point, within one rotation? I thought it was infinite, but the given options are 1, 2, 3, and 4.
Answer:
the answer is 4
Step-by-step explanation:
so 1 rotation is like a circle 1 unit circle requires 4 quadrant to be in this is the most simplified i can get
Answer:
Solution : 4
Step-by-step explanation:
The question asks us how many polar coordinates are possible for one rotation. For one rotation there will be 4 polar coordinates, one present in each quadrant such that,
( r, theta ), ( r, theta ), ( - r, theta ), ( - r, theta )
Respectively if theta was q say,
( r, q ), ( r, - q ), ( - r, q ), ( - r, -q )
Therefore there are 4 sets of polar coordinates for one rotation, in each of the 4 quadrants.
Solve for h: W = 5h - 90 (must show step by step)
Answer:
[tex]W = 5h - 90 \\ 5h = W + 90 \\ h = \frac{W + 90}{5} [/tex]
Answer:
h = w+90/ 5
Step-by-step explanation:
5h-90=w
5h/5= w+90/5
h= w+90/5
Q1) Two balls are randomly selected without replacement from a box containing three black balls numbered 1, 2, 3 and two white balls numbered 4 and 5. Assuming that all outcomes are equally likely. Find out the probabilities of following events. a) Probability that the color of second ball is white. b) Probability that the color of second ball is black. c) Probability that both balls are black. d) Probability that both balls are white.
[tex]|\Omega|=5\cdot4=20[/tex]
a)
[tex]|A|=3\cdot2+2\cdot1=8\\\\P(A)=\dfrac{8}{20}=\dfrac{2}{5}[/tex]
b)
[tex]|A|=3\cdot2+2\cdot3=12\\\\P(A)=\dfrac{12}{20}=\dfrac{3}{5}[/tex]
c)
[tex]|A|=3\cdot2=6\\\\P(A)=\dfrac{6}{20}=\dfrac{3}{10}[/tex]
d)
[tex]|A|=2\cdot1=2\\\\P(A)=\dfrac{2}{20}=\dfrac{1}{10}[/tex]
Commute times in the U.S. are heavily skewed to the right. We select a random sample of 45 people from the 2000 U.S. Census who reported a non-zero commute time. In this sample the mean commute time is 25.2 minutes with a standard deviation of 19.1 minutes. Required:a. Can we conclude from this data that the mean commute time in the U.S. is less than half an hour?b. Conduct a hypothesis test at the 5% level of significance. c. What is the p-value for this hypothesis test?
Answer:
The mean commute time in the U.S. is less than half an hour.
Step-by-step explanation:
In this case we need to test whether the mean commute time in the U.S. is less than half an hour.
The information provided is:
[tex]n=45\\\bar x=25.5\\s=19.1\\\alpha =0.05[/tex]
(a)
The hypothesis for the test can be defined as follows:
H₀: The mean commute time in the U.S. is not less than half an hour, i.e. μ ≥ 30.
Hₐ: The mean commute time in the U.S. is less than half an hour, i.e. μ < 30.
(b)
As the population standard deviation is not known we will use a t-test for single mean.
Compute the test statistic value as follows:
[tex]t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{25.2-30}{19.1/\sqrt{45}}=-1.58[/tex]
Thus, the test statistic value is -1.58.
(c)
Compute the p-value of the test as follows:
[tex]p-value=P(t_{(n-1)}<-1.58)=P(t_{(45-1)}<-1.58)=0.061[/tex]
*Use a t-table.
The p-value of the test is 0.061.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
p-value = 0.061> α = 0.05
The null hypothesis will not be rejected at 5% level of significance.
Thus, concluding that the mean commute time in the U.S. is less than half an hour.
Choose the best answer
Question
Cube A has volume V The edges of cube Bare 3 times as long as the edges of cube A. What is the
volume of cube B, in terms of V?
1.3V
2.9V
3.18V
4.27V
Answer:
4). 27V
Step-by-step explanation:
Let the edge of the cube A be x
Volume of Cube A= V
Volume= x*x*x= x³
so V = x³
Edge of cube B = 3 times edge of cube A
Edge of cube B = 3x
Volume of cube B =( 3x)³
volume of cube B = 27x³
But x³= V
So volume of cube B = 27v
Hellllppp!!!! Please!Match the numbers with the correct label.
Answer:
(a = 1/7 (b = .2 (c = 3/9
Step-by-step explanation:
1/7 = .14
1/4 = .25
3/9 = .33
a & b are lower than 1/4 and c is higher
Based on experience, the Ball Corporation’s aluminum can manufacturing facility in Ft. Atkinson, Wisconsin, knows that the metal thickness of incoming shipments has a mean of 0.2771 mm with a standard deviation of 0.000855 mm.
(a) A certain shipment has a diameter of 0.2742. Find the standardized z-score for this shipment. (Round your answer to 3 decimal places.)
z
(b) Is this an outlier?
Yes
No
Answer:
(a) The standardized z-score for this shipment is -3.392.
(b) Yes, this an outlier.
Step-by-step explanation:
We are given that the Ball Corporation’s aluminum can manufacturing facility in Ft. Atkinson, Wisconsin, knows that the metal thickness of incoming shipments has a mean of 0.2771 mm with a standard deviation of 0.000855 mm.
Let X = the metal thickness of incoming shipments.
The z-score probability distribution for the normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = mean thickness = 0.2771 mm
[tex]\sigma[/tex] = standard deviation = 0.000855 mm
(a) Now, it is given that a certain shipment has a diameter of 0.2742 mm and we have to find the standardized z-score for this shipment.
So, z-score = [tex]\frac{X-\mu}{\sigma}[/tex]
= [tex]\frac{0.2742-0.2771}{0.000855}[/tex] = -3.392
Hence, the standardized z-score for this shipment is -3.392.
(b) Yes, we can consider this as an outlier because the standardized z-score is very large and this value is far from the population mean.
Find the equation with the given slope through the given point. Write the equation in the given form AX+BY=C m=1/9 (-6,2)
Answer:
x - 3y = 12
Step-by-step explanation:
Find the point-slope form of this equation and then convert the point-slope form into standard form (ax + by = c):
y - k = m(x - h) becomes y - 2 = (1/9)(x + 6).
Multiplying all three terms by 9 removes the fraction:
3y - 6 = x + 6, or x - 3y = 12
There are 13 members on a board of directors. If they must form a subcommittee of 4 members, how many different subcommittees are possible?
Answer:
9
Step-by-step explanation:
13-4=9
what is 92 Times 37
A study was conducted by a research center. It reported that most shoppers have a specific spending limit in place while shopping online. The reports indicate that men spend an average of $240 online before they decide to visit a store. If the spending limit is normally distributed and the standard deviation is $20.
A. Find the probability that a male spent less than $210 online before deciding to visit a store.
B. Find the probability that a male spent between $270 and $300 online before deciding to visit a store.
C. Ninety percent of the amounts spent online by a male before deciding to visit a store are less than what value?
Answer:
(A) The probability that a male spent less than $210 online before deciding to visit a store is 0.0668.
(B) The probability that a male spent between $270 and $300 online before deciding to visit a store is 0.0655.
(C) Ninety percent of the amounts spent online by a male before deciding to visit a store is less than $265.632.
Step-by-step explanation:
We are given that the reports indicate that men spend an average of $240 online before they decide to visit a store. If the spending limit is normally distributed and the standard deviation is $20.
Let X = the spending limit
The z-score probability distribution for the normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = mean spending limit = $240
[tex]\sigma[/tex] = standard deviation = $20
So, X ~ Normal([tex]\mu=\$240,\sigma^{2} =\$20^{2}[/tex])
(A) The probability that a male spent less than $210 online before deciding to visit a store is given by = P(X < $210)
P(X < $210) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{\$210-\$240}{\$20}[/tex] ) = P(Z < -1.50) = 1 - P(Z [tex]\leq[/tex] 1.50)
= 1 - 0.9332 = 0.0668
The above probability is calculated by looking at the value of x = 1.50 in the z table which has an area of 0.9332.
(B) The probability that a male spent between $270 and $300 online before deciding to visit a store is given by = P($270 < X < $300)
P($270 < X < $300) = P(X < $300) - P(X [tex]\leq[/tex] $270)
P(X < $300) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{\$300-\$240}{\$20}[/tex] ) = P(Z < 3) = 0.9987
P(X [tex]\leq[/tex] $270) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\leq[/tex] [tex]\frac{\$270-\$240}{\$20}[/tex] ) = P(Z [tex]\leq[/tex] 1.50) = 0.9332
The above probability is calculated by looking at the value of x = 3 and x = 1.50 in the z table which has an area of 0.9987 and 0.9332 respectively.
Therefore, P($270 < X < $300) = 0.9987 - 0.9332 = 0.0655.
(C) Now, we have to find ninety percent of the amounts spent online by a male before deciding to visit a store is less than what value, that is;
P(X < x) = 0.90 {where x is the required value}
P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{x-\$240}{\$20}[/tex] ) = 0.90
P(Z < [tex]\frac{x-\$240}{\$20}[/tex] ) = 0.90
In the z table, the critical value of z that represents the bottom 90% of the area is given as 1.2816, i.e;
[tex]\frac{x-\$240}{\$20}=1.2816[/tex]
[tex]x-240=1.2816\times 20[/tex]
[tex]x=240 + 25.632[/tex]
x = 265.632
Hence, Ninety percent of the amounts spent online by a male before deciding to visit a store is less than $265.632.
Cho A=( căn x -4x /1-4x -1) : (1+2x/1-4x -2căn x/ 2căn x -1 -1)
Answer:
0.85714285714286 x 100 = 85.7143%.
Step-by-step explanation:
In a genetics experiment on peas, one sample of offspring contained green peas and yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of that was expected? 350 127 3 4 The probability of getting a green pea is approximately . (Type an integer or decimal rounded to three decimal places as needed.) Is this probability reasonably close to ? Choose the correct answer below. 3 4 A. No, it is not reasonably close. B. Yes, it is reasonably close.
Complete Question
In a genetic experiment on peas, one sample of offspring contained 436 green peas and 171 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected? The probability of getting a green pea is approximately: Is the probability reasonably close to 3/4?
Answer:
The probability is [tex]P(g) =0.72[/tex]
Yes the result is reasonably close
Step-by-step explanation:
From the question we are told that
The number of of green peas is [tex]g = 436[/tex]
The number of yellow peas is [tex]y = 171[/tex]
The sample size is [tex]n = 171 + 436 = 607[/tex]
The probability of getting an offspring pea that is green is mathematically represented as
[tex]P(g) = \frac{g}{n}[/tex]
[tex]P(g) = \frac{436}{607}[/tex]
[tex]P(g) =0.72[/tex]
Comparing [tex]P(g) =0.72[/tex] to [tex]\frac{3}{4} = 0.75[/tex] we see that the result is reasonably close
A random sample of 1003 adult Americans was asked, "Do you pretty much think televisions are a necessity or a luxury you could do without?" Of the 1003 adults surveyed, 521 indicated that televisions are a luxury they could do without.
Requried:
a. Obtain a point estimate for the population proportion of adult Americans who believe that televisions are a luxury they could do without.
b. Verify that the requirements for constructing a confidence interval about p are satisfied.
c. Construct and interpret a 95% confidence interval for the population proportion of adult Americans who believe that televisions are a luxury they could do without.
d. Is it possible that a supermajority (more than 60%) of adult Americans believe that television is a luxury they could do without ? Is it likely?
e. Use the results of part (c) to construct a 95% confidence interval for the population proportion of adult Americans who believe that televisions are a necessity.
Answer:
a)0.519
b)requirements for constructing a confidence interval about p are satisfied.
c)0.488, and 0.550
d)yes this is because there is no possibility
that the true proportion is not captured in the confidence interval.
e)
0.450, 0.512
Step-by-step explanation:
a)The point estimate for the population proportion of adult Americans who believe that televisions are a luxury they could do without can be calculated as
521 of that adult that indicated that televisions are a luxury they could do without/1003 adults surveyed,
p = 521/1003
= 0.519.
b)
np(1-p)=1003×(0.519)×(1-0.519)
=250.39≥10 and the sample size is less than 5% of the population
therefore, requirements for constructing a confidence interval about p are satisfied.
c) we were given 95% confidence,
Then α=(1-0.95)
= 0.05
From the Z-tables,we can get the critical value is Z , which is (0.05/2) = Z (0.025) = 1.96
confidence interval can the be calculated using the formula below
- p ± Z*√ p (1 – p)/n
=0.519 ± 1.96√0.519×(1 – 0.519)/(1003)
= 0.519 ± 1.96×0.0158
0.519 ± 0.031
= 0.488, and 0.550
d) yes this is because there is no possibility
that the true proportion is not captured in the confidence interval.
e)the sample size can be calculated as
P=x/n
=(1003-521)/1003
=0.481
But we're given 95% confidence interval
Then
α=(1-0.95)=
0.05
From the Z-tables,we can get the critical value is Z , which is (0.05/2) = Z (0.025) = 1.96
Then convidence interval=
- p ± Z*√ p (1 – p)/n
=0.481 ± 1.96√0.481×(1 – 0.481)/(1003)
0.450, 0.512
Which of the following is a valld conclusion for the quadratic equation?
x2 - 6x+8=0
OX-3 = 0 and x+ 5 = 0
Ox+ 4 = 0 and x + 2 = 0
O x-4 = 0 and x + 2 = 0
O x-4 = 0 and x - 2 = 0
Answer:
[tex]x-4=0\: and\: x-2=0[/tex]
Step-by-step explanation:
[tex]x^{2} -6x+8-0[/tex]
[tex]x^{2} -4x-2x+8-0[/tex]
[tex]x(x-4)-2(x-4)=0[/tex]
[tex](x-4)(x-2)=0[/tex]
[tex]x-4=0[/tex] and [tex]x-2=0[/tex]
----------------------
OAmalOHopeO
-----------------------
The valid conclusions for the quadratic equation x² - 6x + 8 = 0 are:
x - 4 = 0 and x - 2 = 0
Option D is the correct answer.
We have,
Quadratic equation x² - 6x + 8 = 0.
Now,
To solve the quadratic equation x² - 6x + 8 = 0, we can use the quadratic formula, which states that:
x = (-b ± √(b² - 4ac)) / (2a)
where a, b, and c are the coefficients of the quadratic equation.
In this case,
a = 1, b = -6, and c = 8.
Substituting these values into the quadratic formula, we get:
x = (-(-6) ± √((-6)² - 4(1)(8))) / (2(1))
x = (6 ± √(36 - 32)) / 2
x = (6 ± √(4)) / 2
x = (6 + 2) / 2 or x = (6 - 2) / 2
x = 4 or x = 2
Therefore,
The valid conclusions for the quadratic equation x² - 6x + 8 = 0 are:
x - 4 = 0 and x - 2 = 0
because the roots of the equation are x = 4 and x = 2,
which can be written in factored form as (x - 4)(x - 2) = 0.
Learn more about quadratic equations here:
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Help please, i really need the answer asap.
The larger metallic object is initially at rest, so the velocity is 0 when t = 0. The speed changes after t = 3 seconds.
Answer:
It would be the last one.
Step-by-step explanation:
It says the object is initially at rest, so you look for a table with 0 m/s and you find the last table had been at rest for 0 -2 seconds. The small rocky object initially had a speed of 90 m/s and then decreased to 36 m/s as its energy transferred to the metallic object. The metallic object's speed from time 4-6s with the small rocky object equals the small rocky initial speed.
Rocky Object initial speed = 90 m/s
Rocky Object new speed = 36 m/s
Large metallic object speed after collision = 64 m/s.
64 m/s + 36 m/s = 90 m/s
Large metallic object speed after collision + Rocky Object new speed
= Rocky Object initial speed
You can also test this for kinetic energy.
a swift can fly at 160km/h. what is the speed in m/s? show clearly how you worked out your answer.
Answer:
[tex]\huge\boxed{\sf Speed = 44.44 \ m/s}[/tex]
Step-by-step explanation:
Speed = 160 km / hr
To convert km/hr to m/s, we multiply it by [tex]\sf \frac{10}{36}[/tex]
Hence,
[tex]\displaystyle Speed = 160 \times \frac{10}{36} \ m/s\\\\Speed = \frac{1600}{36} \ m/s\\\\Speed = 44.44 \ m/s\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Peace!To which set of numbers does the number sqr rt-16 belong? Select all that apply
Answer:
The square root of -16 is an imaginary number and a complex number. Sqrt(-16)=4i. We use the i to indicate that the number is imaginary since there is no number that can be multiplied by itself to get a negative number (a negative times a negative is a positive, and a positive times a positive is also a positive). So the use of i tells you immediately that it's an imaginary number. You can tell the number is complex because it has both a real and an imaginary part and could be written in the form a+bi, where a is a real number and bi is an imaginary number. In this specific case, the real part (a) is 0 and the imaginary part (bi) is 4i.
Step-by-step explanation:
)Patrick buys some bananas for 35%. He sells all the bananas for $40.60. Calculate profit
percentage. Show your working.
Answer:
40.60-35=5.6
Step-by-step explanation:
Profit is cost minus the amount you sold it for
Find the length of AB¯¯¯¯¯¯¯¯ A. 19.56 B. 51.86 C. 42.99 D. 34.98
Answer:
Apllying cos on the triangle
cos(angle)= Base/ Hyp
cos(34)= 29/ AB
AB= 29/0.8290
AB=34.98
Step-by-step explanation:
The length of AB is 34.98 units which the correct answer would be an option (D).
What is the right triangle?A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.
What are Trigonometric functions?Trigonometric functions are defined as the functions which show the relationship between the angle and sides of a right-angled triangle.
Given that ΔABC
∠C = 90°
Here base = BC = 29 units and hypotenuse = AB
To determine the length of AB
Apply the cosine on the given right triangle
⇒ cos(θ) = Base/hypotenuse
⇒ cos(34) = 29/ AB
∴ cos(34°) = 0.8290
⇒ 0.8290 = 29/ AB
⇒ AB= 29/0.8290
⇒ AB = 34.98 units
Hence, the length of AB is 34.98 units
Learn more about Trigonometric functions here:
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2. (1 pt) The following statement is true or false;
When we know the population standard deviation, o, we use a standard normal
distribution (z-score) to calculate the error bound EBM and construct the
confidence interval and when the population standard deviation, o, is unknown,
we use a Student's t distribution (t-score) to calculate the error bound EBM and
construct the confidence interval.
a. true
b. false
If you know the population standard deviation (sigma), then you use the Z distribution. If sigma is not known, then you use the T distribution.
Side note: Even if sigma is not known, you could use the Z distribution if the sample size n is greater than 30. If n > 30, then the T distribution is approximately about the same as the Z distribution.
Simplify the following expression. 12a + 2a
Answer:
[tex]14a[/tex]
Step-by-step explanation:
Combining like-terms gives us [tex]12a+2a=14a[/tex]
Hope this helped!
Answer:
14a
Step-by-step explanation:
Using your textbook, solve the problems below. Show your work.
Solve for y:
y + 8 = 2
Answer:
i dont know lol
Step-by-step explanation:
) If the half-life of 238Pu is 87.7 yr, write a function of the form =QtQ0e−kt to model the quantity Qt of 238Pu left after t years. Round the value of k to five decimal places. Do not round intermediate calculations.
Answer:
0.079
Step-by-step explanation:
According to the given situation, the calculation of the value of k is presented as follows:
[tex]Q(t)= Q_0e^{-kt}\\\\ 0.5Q_0 = Q_0e^{-k(97.7)}\\\\ 0.5 = e^{-k(87.7)}[/tex]
now,
[tex]k = \frac{In0.5}{-87.7}[/tex]
After solving the above equation we will get the value of k.
= 0.079
Therefore for determining the value of k we simply solve the above equation i.e. by considering all the information mentioned in the question
Answer:
3.5e^-0.0079t
Step-by-step explanation:
None, Good luck mate
What is the error in this problem
Answer:
The angle of elevation is not properly represented
Step-by-step explanation:
Given
The question in the attachment;
Required
Determine the error
See attachment for proper representation of the angle of elevation;
Solving further (From the Attachment)
[tex]Tan22 = \frac{x}{3000}[/tex]
Multiply both sides by 3000
[tex]x = 3000 * tan22[/tex]
[tex]x = 3000 * 0.4040[/tex]
[tex]x = 1212[/tex]
The cliff is about 1212 feet high