A system will never enter a deadlocked state if:__________A) the system chooses to ignore the problem altogether.B) the system uses the detection and recovery technique.C) the system uses the deadlock avoidance technique.D) None of the above.

Answers

Answer 1
the answer is B :))))
Answer 2

A system will never enter a deadlocked state if the system uses the detection and recovery technique. Thus the correct option is B.

What is deadlocked state?

A deadlock in desktop software happens when a procedure or task enters a waiting state as a result of another waiting process holding the requested system resource.

When a group of processes is in a wait state, a deadlock occurs because each process is awaiting a resource that is being held by another waiting process.

The wait-for graph must be maintained by the system in order to detect deadlocks, and the system periodically runs an operation that looks for cycles in the wait-for graph.

There is no method used by the OS to avoid or stop deadlocks. The OS checks the system on a regular basis for any deadlocks in an effort to break them. Therefore, option B is appropriate.

Learn more about the detection and recovery technique, here:

https://brainly.com/question/29107758

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Related Questions

what are the SURVEYING INSTRUMENTS​

Answers

Answer:

the main surveying instruments is use around the world are the theodolite, measuring tape, total station, 3D scanners ,GPS/GNSS, level and rod.

Most instruments screw into a tripod when in use.

Determine the size of memory needed for CD recording of a piece of music, which lasts for 26 minutes, is done with a 20-bit Analog-to-Digital Converter (ADC) in stereo (2 channels), at the rate of 44.1 kSa/s, with the compression factor 6 (allow 10% error margin).

Answers

Answer: the size of memory needed for the CD recording is 28.7 MB

Explanation:

so in the case of stereo, the bitrate is;

⇒ 26 × 60 × 44.1 × 10³ × 2

=   137592 × 10³  

for 10 bit

⇒ 137592 × 10³ × 10

= 1375920 × 10³ bits

now divide by 8 (convert to bytes)

⇒ (1375920 × 10³) / 8

= 171,990,000 BYTE

divide by 1000 (convert to kilobytes)

= 171,990,000 / 1000

= 171,990 KILOBYTES

now Given that, the compression ratio is 6      

so  

171,990 / 6

= 28665 KB

we know that. 1 MB = 1000 KB

x MB = 28665 KB

x MB = 28665 / 1000

⇒ 28.665 MB ≈ 28.7 MB

Therefore the size of memory needed for the CD recording is 28.7 MB

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