A system of equations is made up of an ellipse and a hyperbola.

Part A: Create the equation of an ellipse centered at the origin, with a vertical major axis of 8 units and a minor axis of 6 units. Show your work. (3 points)

Part B: Create the equation of a hyperbola centered at the origin, with a horizontal transverse axis, vertex at (–4, 0), and asymptotes of y equals plus or minus seven fourths x period Show your work. (4 points)

Part C: Determine the domain of each conic section and use it to explain why there is no solution to the system. (3 points)

Answers

Answer 1

The equation of the ellipse and the equation of the hyperbola can be

derived from the given information and the general form of the equations.

[tex]Part \, A: The \ equation \ of \ the \ ellipse \ is; \displaystyle \frac{x^2}{3^2} + \frac{y^2}{4^2} = 1[/tex]

[tex]Part \, B: The \ equation \ of \ the \ hyperbola \ is; \displaystyle \frac{x^2}{(-4)^2} - \frac{y^2}{(-7)^2} = 1[/tex]

Part C: The domain of the ellipse is; [-3, 3]

The domain of the hyperbola is; (-∞, -4]

The domains of the ellipse and the hyperbola do not intersect, therefore, the system of equation has no solution.

Reasons:

Part A: The center of the ellipse = At the origin;

The vertical major axis = 8 units

The minor axis = 6 units

The general equation for an ellipse is presented as follows;

[tex]\displaystyle \frac{x^2}{b^2} + \frac{y^2}{a^2} = 1[/tex]

Where;

[tex]\displaystyle a = The \ \mathbf{ semi \ major \ axis} = \frac{8}{2} = 4[/tex]

[tex]\displaystyle b = The \ semi \ \mathbf{ minor} \ axis = \frac{6}{2} = 3[/tex]

The equation of the ellipse is therefore;

[tex]\displaystyle \underline{\frac{x^2}{3^2} + \frac{y^2}{4^2} = 1}[/tex]

Part B: center of the hyperbola = The origin

The transverse axis = Horizontal

The vertex of the hyperbola = (-4, 0)

[tex]\displaystyle The \ asymptote \ are; \ y = \mathbf{ \pm\frac{7}{4} \cdot x}[/tex]

The general equation of an hyperbola is presented as follows;

[tex]\displaystyle \mathbf{\frac{x^2}{a^2} - \frac{y^2}{b^2}} = 1[/tex]

[tex]\displaystyle The \ asymptote \ are; \ y = \mathbf{\pm\frac{b}{a} \cdot x}[/tex]

The vertices = (a, 0), (-a, 0)

Therefore, by comparison, we have;

a = -4

b = -7

Which gives the equation of the hyperbola as follows;

[tex]\displaystyle \underline{ \frac{x^2}{(-4)^2} - \frac{y^2}{(-7)^2} = 1}[/tex]

The above equation can be written as follows;

[tex]\displaystyle \frac{x^2}{(4)^2} - \frac{y^2}{(7)^2} = 1[/tex]

Part C: Given that both equations are equal, we have;

The covertices of the ellipse are; (-3, 0) and (3, 0)

The domain of the ellipse = [-3, 3]

The domain of the hyperbola = x < The negative vertex

∴ The domain of the hyperbola = x < -4 = (-∞, -4]

The above domain of the ellipse does not extend to the hyperbola, therefore there is no solution to the system.

Learn more about ellipse and hyperbola here:

https://brainly.com/question/17193351

https://brainly.com/question/8957529

A System Of Equations Is Made Up Of An Ellipse And A Hyperbola. Part A: Create The Equation Of An Ellipse

Related Questions

Helppppppppppppppppp

Answers

[tex]\huge \tt༆ Answer ༄[/tex]

The respective terms used for the lines are ~

a.) Line a = Tangent

b.) Line b = Radius

c.) Line c = Diameter

d.) Line d = Secant

Step-by-step explanation:

a is tangent

b radius

c diameter

d chord

Dan is using tiles to add - 8 +6. He begins with the tiles shown below.
OOOOOOOO
What is the sum of -8+6?
0-14
-2
02
14

Answers

Answer:

-2

Step-by-step explanation:

Graph a line with a slope of -3/4 that contains the point (2,3).

Answers

Answer:

The graph will be on the bottom:

Step-by-step explanation:

First find the slope intercept form:

y=mx+b

m is slope

b is y-intercept

since we already have slope we can replace that with m

y=-3/4x+b

Now substitute x and y with 2 and 3

3=-3/4 (2)+b

3=-3/2+b

Add on both sides:

9/2=b

Thus the Slope-intercept form is

y=-3/4x+9/2

Hope this helps!


[tex] \sf \huge{ question \hookleftarrow}[/tex]


If [tex] \alpha \: and \: \beta [/tex] are roots of a equation " ax² + by + c ", then find the value of the following in terms of a , b and c ~


[tex] \boxed{ \boxed{ \sf \sqrt{ \alpha} + \sqrt{ \beta } = \: ?}}[/tex]


Answers

[tex]\underline{\bf{Given \:equation:-}}[/tex]

[tex]\\ \sf{:}\dashrightarrow ax^2+by+c=0[/tex]

[tex]\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.[/tex]

[tex]\sf We\:know,[/tex]

[tex]\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}[/tex]

[tex]\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}[/tex]

[tex]\underline{\large{\bf Identities\:used:-}}[/tex]

[tex]\boxed{\sf (a+b)^2=a^2+2ab+b^2}[/tex]

[tex]\boxed{\sf (√a)^2=a}[/tex]

[tex]\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}[/tex]

[tex]\boxed{\sf \sqrt{\sqrt{a}}=a}[/tex]

[tex]\underline{\bf Final\: Solution:-}[/tex]

[tex]\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}[/tex]

[tex]\bull\sf Apply\: Squares[/tex]

[tex]\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2[/tex]

[tex]\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}[/tex]

[tex]\bull\sf Put\:values[/tex]

[tex]\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}[/tex]

[tex]\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}[/tex]

[tex]\bull\sf Simplify[/tex]

[tex]\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}[/tex]

[tex]\underline{\bf More\: simplification:-}[/tex]

[tex]\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}[/tex]

[tex]\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}[/tex]

[tex]\underline{\Large{\bf Simplified\: Answer:-}}[/tex]

[tex]\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}[/tex]

The value  [tex]\sqrt{\alpha } +\sqrt{\beta }[/tex] in terms of a, b and c is [tex]\sqrt{{(\frac{b}{a})^2 } +2\sqrt{\frac{c}{a} } } \\[/tex]

Roots of a quadratic equation

Given the quadratic equation ax² + bx + c, the sum and product  of the roots are expressed as:

[tex]\alpha +\beta =-\frac{b}{a} [/tex][tex]\alpha \beta =\frac{c}{a} [/tex]

Get the value of the radical expression [tex]\sqrt{\alpha } +\sqrt{\beta } [/tex]

Taking the square of the expression will give:

[tex](\sqrt{\alpha } +\sqrt{\beta } )^2=(\sqrt{\alpha } )^2+(\sqrt{\beta } )^2+2\sqrt{\alpha \beta} [/tex]

Take the square root of both sides:

[tex]\sqrt{(\sqrt{\alpha } +\sqrt{\beta } )^2} =\sqrt{(\sqrt{\alpha } )^2+(\sqrt{\beta } )^2+2\sqrt{\alpha \beta} } \\ \sqrt{\alpha } +\sqrt{\beta }=\sqrt{{(\alpha }+{\beta} )+2\sqrt{\alpha \beta} } \\[/tex]

Substitute the product and the sum values into the expression to have:

[tex]\sqrt{\alpha } +\sqrt{\beta }=\sqrt{{(-\frac{b}{a})^2 } +2\sqrt{\frac{c}{a} } } \\\sqrt{\alpha } +\sqrt{\beta }=\sqrt{{(\frac{b}{a})^2 } +2\sqrt{\frac{c}{a} } } \\[/tex]

Hence the value  [tex]\sqrt{\alpha } +\sqrt{\beta }[/tex] in terms of a, b and c is [tex]\sqrt{{(\frac{b}{a})^2 } +2\sqrt{\frac{c}{a} } } \\[/tex]

Learn more on the roots of equation here: https://brainly.com/question/25841119

Two identical squares of sides 17 cm overlap to form a rectangle as shown below. The shaded part is the overlapping region

Answers

Answer:

B 68 sq cm

Step-by-step explanation:

There's an overlap of 4

2*13 + 4

4 * 17 is 68

Katie don't delete my work!

The ratio of boys to girls at a monster truck rally is 4:3. Create a ratio table with examples of how many boys and girls could be at the rally?

Answers

4:3

8:6

12:9

16:12

20:15

24:18

28:21

pls help me i do not know how to do this

Answers

Answer:

D. Reflect across the y-axis and then across x = 7

Step-by-step explanation:

A and B work because each transformed point is 12 to the right (x-value is 12 greater), and 3 left then 15 right is the same thing as just 12 right.

C. works because if you take each of the points and reflect them over the y-axis (make the x value positive) and then across the line x=6 (vertical line at 6 on the x-axis) it will map the points onto the correct image.

So, the answer is D. Reflect across the y-axis and then across x = 7.

PT. 4 OF MY HW! STILL UNIT RATE​

Answers

Answer: plant 1 grows at a faster rate

Step-by-step explanation:

Slope formula: trying to make sure I’m doing this right

Answers

Answer:

Yup ur Right ;D

Step-by-step explanation:

what is the next term in the number pattern? 77, 64, 53, 44, 37

Answers

Answer:

32

...when you subtract five from 37

It is a pattern that goes:

-13

-11

-9

-7

and now -5 = 32

f(x) = (x - 1) (4x + 3) (3x - 8) has zeros at x = 3/4, x= 1, and x = 8/3.
What is the sign of f on the interval - 3/4

Answers

Using the given roots, it is found that on the interval [tex]-\frac{3}{4} < x < 1[/tex], the function is positive.

The function is:

[tex]f(x) = (x - 1)(4x + 3)(3x - 8)[/tex]

The zeroes are:

[tex]x = -\frac{3}{4}, x = 1, x = \frac{8}{3}[/tex]

Between two zeroes, the function has the same sign, hence, to find the sign on the interval [tex]-\frac{3}{4} < x < 1[/tex], we find the numeric value of the function of a value of x on the interval, for example f(0), for x = 0.

Then:

[tex]f(0) = (0 - 1)[4(0) + 3][3(0) - 8] = (-1)(3)(-8) = 24[/tex]

Since f(0) is positive, the function is positive on the interval [tex]-\frac{3}{4} < x < 1[/tex].

A similar problem, in which it is desired to find the sign of the function, is given at https://brainly.com/question/4787253

Solve the inequality.


-7x - 4 > 17

Answers

Answer:x<-3

Step-by-step explanation:

Answer:

x < -3

Step-by-step explanation:

[tex]-7x-4>17\\\\-7x-4+4>17+4\\\\-7x>21\\\\\frac{-7x}{-7}>\frac{21}{-7}\\\\x<-3[/tex]

Given f(x) = 3. + 1, solve for when f(3) = 7.

Answers

Answer:

The question is incomplete

i need help with this problem, but i don't want someone to just give me the answer. i need it to be taught step-by-step to me because for some reason i can't understand how everyone tells me to do it. i need to learn this as I've been on this one test for the past 2 weeks. I've been trying to find a tutor or something that will actually help me the way i need to be helped. so please, just give me a simple answer that will help me with the 3 other questions after it.

the lesson name is called solving real world systems of equations via elimination.
here is the question:

jared bought 7 cans of paint. a can of red paint costs 3.75. a can of black paint costs 2.75. jared spent 22.25 in all. how many cans of black (b) and how many cans of red (r) did he buy?

r+b=7

3.75 + 2.75 = 22.25

this is a lesson in 8th grade math.​

Answers

Answer:

Hallo, I will help you with the problem T^T

Step-by-step explanation:

3.75r + 2.75b = 22.25

3.75r = The amount a red can costs, MULTIPLIED BY the amount of red cans they bought!

2.75b = The amount a black can costs, MULTIPLIED BY the amount of black cans they bought!

So this means that they bought:

3 cans of red paint.

And 4 cans of black paint.

Now you may be thinking, how do you know?

If you multiply the COST 3.75, by 3 cans of red paint, you get 11.25

And then if you multiply the COST of the black paint (The cost for a can of black paint is 2.75) multiply that by 4, you get 11 :0

So add 11 + 11.25 and you get 22.25 :]

Comment if you have any questions, no matter how insignificant you think they may be, I will help you :]

Challenge question? Thanks.

Answers

Answer:

x=15

Step-by-step explanation:

the basic property is: AB/AD=BC/CD, for more info see the attachment.

Kile’s weight is 30 pounds less than the product of Mindy’s weight and 3. Let m represent Mindy’s weight. Write an expression that represents Kile’s weight.

Answers

Let m represent Mindy's weight.Therefore, product of Mindy's weight and 3 = m × 3 = 3mKile’s weight is 30 pounds less than the product of Mindy’s weight and 3.Therefore, Kile's weight can be represent by this:[tex]3m - 30[/tex]

Answer:

3m - 30

Hope you could get an idea from here.

Doubt clarification - use comment section.

Kiles weight is m Product of m and 3 means m and 3 are multiplied.

So the expression till now

[tex]\\ \sf{:}\Rrightarrow m(3)[/tex]

[tex]\\ \sf{:}\Rrightarrow 3m[/tex]

But the required weight is 30pounds less than it

[tex]\\ \sf{:}\Rrightarrow 3m-30[/tex]

A store owner discounted some silver coat racks from $625 to $405. What percentage is the discount?

Answers

Answer: 64.80% not 100% positive if i did that math right but thats what i got

Step-by-step explanation:

38.8679

Step-by-step explanation:

What is an included angle and an included side?

A: Included Angle: A 90 deg angle
Included Side: The longest
side

B: Included Angle: An angle between two angles
Included Side: A side between two sides

C: Included Angle: An angle between two sides.
Included Side: A side between two angles

Answers

Answer:

C

Step-by-step explanation:

Carlos cycles for 2 hours at a fast speed, then cycles for 3 more hours at a speed 10 km/h slower than this. If the entire distance travelled is 90 km, find Carlos’ speed in the first two hours of travel.

Answers

Answer:

f=24km/h

Step-by-step explanation:

Alright, here's what we know.

He travels 2 hours at a fast speed, lets call that speed f km/h

He then travels 3 hours at (f-10) km/h

In these 5 hours, he travels 90km

So we have the formula velocity = distance/time. If you don't know where that formula comes from, let me know and I'll explain.

So we have:

[tex]v=\frac{d}{t}[/tex]

d and t are given to us as 90 and 5 respectively

v is going to be his average speed, so we take 2 times the fast speed plus 3 times the slower speed and divide it by 5. This gives us the average speed he traveled over the 5 hours.

[tex]\frac{2f+3(f-10)}{5} =\frac{90}{5}[/tex]

2f+3f−30=90  by cancelling the 5's in the denominator and expanding 3(f−10)

5f=120

f=24km/h

So his faster speed is 24 km/h. Let me know if this solution did not make sense to you at any point.

five times a number is ten more than three times the number. Find the number​

Answers

5x = 10 + 3x

5x - 3x = 10

2x = 10

x = 5

To check

5(5) = 10 + 3(5)

25 = 10 + 15

25 = 25

Answer:

x = 5

Step-by-step explanation:

Number = x

5x = 10 + 3x  

2x = 10

x = 5

Find the equation of the straight line which makes a negative intercept of 4 units on the x - axis and passes through the point (2‚ 3).​

Answers

Answer:

y = 1/2x + 2.

Step-by-step explanation:

It passes through the points (-4, 0) and (2,3) so

the slope (m) = (3-0)/(2-(-4)) = 3/2 = 1/2.

Using the point slope form of a straight line:

y - y1 = m(x - x1):

y - 3 = 1/2(x - 2)

y = 1/2x - 1 + 3

y = 1/2x + 2 is the required equation.

what is 69+69-69+1-1+0

Answers

The answer is 69 , because it just cancels out the numbers

Answer:

207

Step-by-step explanation:

Anyone know this answer I will give you 28 point.

Answers

Answer:

V to X = 68mi

X to W = 50mi

V to W = will be 68mi too

Step-by-step explanation:

note ; it's a triangle*

Tom, Kristen, and bill bought 3 granola bars to share amongst themselves. They divided each granola bar into 4 equal portions. Kristen ate 1 portion from each granola bar. Which equation represents how many granola bars Kristen ate.

Answers

Answer:

3/4 of a bar.

Step-by-step explanation:

Each piece of the granola bar is 1/4 of the bar. She ate 3 portions, so she ate 3/4.

A new DVD player has a purchase price of $430. With the extended warranty, the total cost is $512. What percent of the purchase price is the price of the warranty? a. 16% b. 19% c. 24% d. 29% Please select the best answer from the choices provided A B C D.

Answers

The percent of the purchase price that is the price of the warranty is: b. 19%.

Using this formula

Purchase price percent=Total cost-Purchase price/Purchase price

Where:

Total cost=$512

Purchase price=$430

Let plug in the formula

Purchase price percent=$512-$430/$430

Purchase price percent=$82/$430

Purchase price percent=0.19×100

Purchase price percent=19%

Inconclusion the percent of the purchase price that is the price of the warranty is: b. 19%.

Learn more about purchase price here:https://brainly.com/question/6076645

Some please help me I’ll give you brainlist answer

Answers

Answer:

Step-by-step explanation:

The area of the square is 3 units by 3 units. because the area of a square is side length squared.

side length = 3

side length^2 = 3 * 3 = 9

The area of a circle is much harder to reason out. You could start with the area of a square and use the diameter is 3 units. But the corners are rounded and you don't know off hand what the area of one of them is, let alone all 4. You are given a formula for circles area, but you have no real idea what the formula actually means. Does it take the corner area into account? At the beginning levels, we don't know.

Answer:

The area of the square is 9 aka [tex]3^{2}[/tex]

You can find it easily by just counting the number of squares inside the square, or by counting the number of squares at its length then multiplying it by its width; so 3 x 3 = 9

It wouldn't be as easy to find the area of the circle because you don't have the radius, nor diameter, so basically, no quantitative values could be used to at least guess.

Please help!!!!!!!!!!!!!

Answers

9 + (-3) = 6
Because based on the image you add 9 and subtract 3

Hope you find this helpful!
Brainliest is much appreciated!

Answer:

B and C

Step-by-step explanation:

look at comments

PLEASE HELP!!
This is worth 20 points please help me!

Answers

If it’s worth 20 why you just giving 5 points boo

What is the estimate height of 129.3

Answers

129 .................

Solve the equations below. Give exact solutions only. Show your work.

a) 5x^2 - 7 = 72
b) x(x + 2) = 5
c) 3x^2 + 2x - 4 = 0

Please help!

Answers

Step-by-step explanation:

remember, the general formula to solve a quadratic equation ax² + bx + c = 0 is

x = (-b ± sqrt(b² - 4ac))/(2a)

a)

I think there is a typo, and this should be

5x² - 7x = 72

5x² -7x - 72 = 0

x = (7 ± sqrt(49 - -1440))/10 = (7 ± sqrt(1489))/10

x1 = (7 + sqrt(1489))/10

x2 = (7 - sqrt(1489))/10

b)

x(x + 2) = 5

x² + 2x - 5 = 0

x = (-2 ± sqrt(4 - -20))/2 = (-2 ± sqrt(24))/2 =

= (-2 ± sqrt(4×6))/2 = (-2 ± 2×sqrt(6))/2 =

= -1 ± sqrt(6)

x1 = -1 + sqrt(6)

x2 = -1 - sqrt(6)

c)

3x² + 2x - 4 = 0

x = (-2 ± sqrt(4 - -48))/6 = (-2 ± sqrt(52))/6 =

= (-2 ± sqrt(4×13))/6 = (-2 ± 2×sqrt(13))/6 =

= (-1 ± sqrt(13))/3

x1 = (-1 + sqrt(13))/3

x2 = (-1 - sqrt(13))/3

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