The net force on a 0.50-cm-diameter eardrum is mathematically given as
F= 0.76969 N
What is the net force on a 0.50-cm-diameter eardrum?
Generally, the equation for Pressure is mathematically given as
P = ρgh
Therefore
P= 1000*9.8*4
P= 39200 Pa
Where
A= pi*(0.005/2)^2
Generally, the equation for Net force is mathematically given as
F = PA
F= 39200 *( pi*(0.005/2)^2)
F= 0.76969 N
In conclusion, The net force is
F= 0.76969 N
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The only source of light in a room is the lightbulb shown. An opaque disk is placed in front of the bulb. A screen is then placed successively at positions A, B, and C. At which screen position(s) does the disk cast a shadow that is completely dark at the center
On screen A the opaque disk cast a shadow that is completely dark at the center
opaque is defined as difficult to understand or not allowing light to pass through. The appearance of a black sheet of paper is an illustration of opaqueness. The study of astrophysics is an illustration of opaque.
An opaque object illuminated by a point source of light is said to produce a crisp shadow whose dimensions may be determined using geometry. This is according to geometric optics. The computation process is quite simple. Light beams are uniformly emitted from the source in all directions. These rays can be visualized as lines radiating straight out from the source. When a light source encounters an opaque object, the light rays cease moving away from the source.
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Find the work done when a constant force f = 13 lbs moves a chair from x = 2.4 to x = 4.1 ft. along the x -axis.
The work done in moving the chair from x = 2.4 to x = 4.1 ft using a force of F = 13 lbs is 29.98 J
What is work done?This is simply defined as the product of force and distance moved in the direction of the force. Mathematically, it can be expressed as
Workdone (Wd) = force (F) × distance (d)
Wd = Fd
How to convert lb to N1 lb = 4.45 N
Therefore,
13 lbs = 13 × 4.45
13 lbs = 57.85 N
How to determine the distance in mInitial distance = 2.4 ftFinal distance = 4.1 ftChange in distance = 4.1 -2.4 = 1.7 ft1 ft = 0.3048 m
Therefore,
1.7 ft = 1.7 × 0.3048
1.7 ft = 0.51816 m
How to determine the workdoneForce (F) = 57.85 NDistance (d) = 0.51816 mWorkdone (Wd) =?Wd = Fd
Wd = 57.85 × 0.51816
Workdone = 29.98 J
Thus, the workdone in moving the chair is 29.98 J
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A vector is 14.4 m long and
points in a 133 degree
direction.
Find the x-component of the
vector.
The x-component of the given vector is determined as 10.53 m.
X component of the vector
The x-component of a vector is defined as the value of the vector or component of the vector in the x direction.
For a vector of 14.4 m long and pointing in a 133 degree direction.
The x-component of the vector is calculated as follows;
Vx = V cosθ
where;
θ is the angle of inclination measured from positive x axisθ = 133⁰ - 90⁰ = 43⁰
Vx = 14.4 x cos(43)
Vx = 10.53 m
Thus, the x-component of the given vector is determined as 10.53 m.
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Supposing the half-life of element x to be 1 year, if you have a 100 gram sample of x, how much of element x would be left after 4 years? (do not use significant digits in answering this question.)
75 g
50 g
25 g
6.25 g
6.25 gram of element x would be left after 4 years.
What's half life of an element?Half - life is the time period of decay of an element to half of its initial number of nuclei.After n no. of half lives, no. of nuclei left in the sample is initial number of nuclei / 2^nWhat's the amount of 100 gm of element x left after 4 half lives ?Leftover amount of the element x = 100/2^4
= 100/16 = 6.25 gram
Thus, we can conclude that 6.25 gram of element x would be left after 4 years.
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A 67 V power supply is connected to three identical resistors in series. If the current through the resistors is measured at 0.95 A, what is the value of each resistor? Round your answer to 2 decimal places.
The value of the identical resistors would be 70. 53 Ohms
How to determine the valuesWe have the formula for resistance to be;
Resistance = Voltage/ current
Voltage = 67 V
Current = 0. 95A
Substitute the values
Resistance =
[tex] \frac{67}{0.95} [/tex]
Resistance = 70.53 Ohms
Thus, the value of the identical resistors would be 70. 53 Ohms
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Three charges, qA is +6.0 μC, qB is –5.0 μC, and qc is +6.0 μC, are located at the corners of a square with each
side length at 5.0 cm as shown in the diagram. Calculate the electric field at point D.
The net electric field at point D is determined as 3.95 x 10⁷ N/C.
Electric field at D due to charge A
E = kq/r²
where;
r is the distance between A and Dq is charge AE(AD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)
E(AD) = 2.16 x 10⁷ i N/C
Electric field at D due to charge B
E = kq/r²
where;
r is the distance between A and Bq is charge Br² = 5² + 5²
r² = 50
r = √50
r = 7.07 cm
E(BD) = (9 x 10⁹ x 5 x 10⁻⁶)/(0.0707²)
E(BD) = 9 x 10⁶ N/C
in x - direction = 9 x 10⁶ N/C x cos(45) = 6.36 x 10⁶ i N/C
in y - direction = 9 x 10⁶ N/C x sin(45) = 6.36 x 10⁶j N/C
Electric field at D due to charge CE = kq/r²
where;
r is the distance between C and Dq is charge CE(CD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)
E(CD) = 2.16 x 10⁷ j N/C
sum of electric field in x directionEi = 2.16 x 10⁷ i N/C + 6.36 x 10⁶ i N/C
Ei = 2.796 x 10⁷ i N/C
sum of electric field in y directionEj = 2.16 x 10⁷ j N/C + 6.36 x 10⁶j N/C
Ej = 2.796 x 10⁷ j N/C
Resultant electric field at DE = √Ei² + Ej²
E = √[(2.796 x 10⁷)² + (2.796 x 10⁷)²]
E = 3.95 x 10⁷ N/C
Thus, the net electric field at point D is determined as 3.95 x 10⁷ N/C.
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The north-pole end of a bar magnet is held near a stationary positively charged piece of plastic. How is the plastic affected?.
When the north-pole end of a bar magnet is held near a stationary positively charged piece of plastic, it remains unaffected.
What is a bar magnet?
A bar magnet is made of ferromagnetic substance that produces
magnetic field.
What are the properties of a bar magnet?
Magnets attract ferromagnetic materials like iron, cobalt and nickel.Like poles repel each other and unlike poles attract each other.The strength of both poles is always the same.When a magnetic material is kept in contact with a bar magnet it acquires the magnetic property.Some materials like gold, silver and water get repelled by magnets.Since plastic is not a ferromagnetic material or any other material like gold and silver ,they remain unaffected in the presence of magnetic field.
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Water flows through a pipe with a cross-sectional area of 0.002 m^2 at a mass flow rate of 4 kg/s. the density of water is 1 000 kg/m^3. Determine its average velocity
Water flows through a pipe with a cross-sectional area of 0.002 m^2 at a mass flow rate of 4 kg/s. The density of water is 1 000 kg/m^3 . The average velocity will be 2m/s
The flow rate of a liquid is how much fluid passes through an area in a particular time. Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume.
Flow rate = Volume of fluid / time
= (Area * distance) / time
= Area * average velocity (distance / time = average velocity)
Given
Cross-sectional area = 0.002 [tex]m^{2}[/tex]
Flow rate = 4 kg/s
Average velocity = Flow rate / (Area * density)
= 4 / (0.002 * 1000)
= 2m/s
hence , the average velocity will be 2 m/s
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Cytosine is methylated resulting in 5-methylcytosine. What is the most likely outcome?.
Answer: Cytosine is methylated resulting in 5-methylcytosine. Then the gene expression will decrease.
Explanation: To find the answer, we need to know more about the methylation of cytosine.
What is methylation of cytosine?Methylation means the addition of a methyl group on a substrate of an atom.It's a form of alkylation, here a methyl group replaces a hydrogen atom.Methylation of cytosine occurs at CpG palindrome in DNA.When cytosine is methylated to produce 5- methyl cytosine, which results in a decrease in gene expression.Thus, we can conclude that, Cytosine is methylated resulting in 5-methylcytosine. Then the gene expression will decrease.
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he most accurate place to conduct a weight check is: Select one: At the surface, at the beginning of the dive. At the deepest point reached during the dive. At safety-stop depth, at the end of the dive. None of the above.
The most accurate place to conduct a weight check is at safety-stop death, at the end of the dive.
Why is a weight check important in diving?
A weight check before diving helps an individual decide on the right amount of weight needed for each scuba dive.
To do a weight check one must float upright on the surface, head placed above water. The individual then needs to release some air from their Buoyancy compensator as they take a deep breath from their regulator.
Now if the individual sinks rapidly below the surface, they are overweight and if their head stays above the water surface, then they are underweight. Thus, when an individual sinks up to the mask level, then the weight is just right.
Therefore, the most accurate place to conduct a weight check is at safety-stop depth, at the end of the dive.
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51. After conducting a search directly above the floor of a fire in a high rise building what is your next priority
After conducting a search directly above the floor of a fire in a high rise building what is your next priority is that their own safety is the first priority.
Life safety is the top consideration at any fire incident. Firefighters practice frequently to be ready to free trapped persons from a burning structure. On some occasions, though, it's the firefighters who require assistance.What are the three incident priorities?
Reviewing the three main responsibilities on the fireground—life safety, incident stabilization, and property preservation—is a good idea. These three concerns must be taken care of at every fire scene to which we react. The circumstances will determine which ones are addressed in what order.Learn more about firebrigade safty rules
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PLEASE HELP QUICK! Why does thermal energy increase on a roller coaster? Especially when it goes up the second hill?
According to hubble's law, with = 70 km/s , how far away is a galaxy whose recessional velocity is 6000 km/s ?
The galaxy will be D = 84.96 km far away
Hubble's law, which says simply that a galaxy's velocity (or as is sometimes plotted, its redshift) is directly proportional to its distance, also tells us something important about the state of the universe. If the universe is static and unchanging, there should be no correlation between distance and velocity.
Recessional velocity is the rate at which an extragalactic astronomical object recedes (becomes more distant) from an observer as a result of the expansion of the universe. It can be measured by observing the wavelength shifts of spectral lines emitted by the object, known as the object's cosmological redshift.
V (r) = H * D + V pec
6000 = 69.8 * D + 70
5930 / 69.8 = D
D = 84.96 km
The galaxy will be D = 84.96 km far away
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What happens if :
. The test charge is not tiny.
The magnitude of the test charge must be small enough so that it does not disturb the issuance of the charges whose electric field we wish to measure otherwise the metric field will be different from the actual field.
How does test charge affect electric field?As the quantity of authority on the test charge (q) is increased, the force exerted on it is improved by the same factor. Thus, the ratio of force per charge (F / q) stays the same.
Adjusting the amount of charge on the test charge will not change the electric field force.
What is a test charge used for?The charge that is used to measure the electric field strength is directed to as a test charge since it is used to test the field strength. The test charge has a portion of charge denoted by the symbol q.
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If you want the ball to land in your hand when it comes back down, should you toss the ball straight upward, in a forward direction, or in a backward direction, relative to your body
Straight upward
the ball moves in the forward direction with your walking speed at all times. If you want the ball to land in your hand when it comes back down, you should toss the ball straight upward.
What is Projectile motion ?Projectile motion is the motion of an object thrown (projected) into the air.
After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectoryA projectile can be a thrown ball, a bullet or a springboard diver ... Except for air resistance, the forward velocity of any projectile is constant and is equal to the initial velocity when it was released.Learn more about Projectile motion here:
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The following is regarding Momentum Change and Force. help is needed please!
1. A force of 50 N acts on an object of mass 250 kg which is initially at rest, for 10 s. find the distance travelled and the velocity gained at the end of this time.
The distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
Velocity of the object at the end of the timeF = mv/t
where;
m is mass of the objectv is velocity of the objectt is timeFt = mv
v = Ft/m
v = (50 x 10)/250
v = 2 m/s
Distance traveled by the objectv² = u² + 2as
where;
u is initial velocity = 0
a is acceleration
a = F/m
a = 50 N/ 250 kg
a = 0.2 m/s²
v² = 0 + 2as
s = v²/2a
s = (2²)/(2 x 0.2)
s = 10 m
Thus, the distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
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Color is a result of the absorption and reflection of light. A shirt appears a color because it reflects that color of light. A shirt appears black when it absorbs all wavelengths of light. Why does a shirt appear white outside on a sunny day
The clothing seems white because the entire light is reflected.
what is absorption and reflection?Absorption:
This occurs when light is transformed into another type of energy. This happens when light vanishes while travelling through another medium.
reflection:
It is referred to as light reflection when a light ray hits a polished, smooth surface and bounces back. The incident light rays hit the surface and are reflected off of it. The beam that returns is referred to as the reflected ray.
according to the question we know that a shirt appears a color because it reflects that color of light. A shirt appears black when it absorbs all wavelengths of light. In case of white shirt no wavelength is absorbed by the shirt due to which the shirt appears white and in simple words the entire light is reflected back.
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Three charges, qA is +6.0 μC, qB is –5.0 μC, and qc is +6.0 μC, are located at the corners of a square with each side length at 5.0 cm as shown in the diagram. Calculate the electric field at point D.
The net electric field at point D is determined as 3.95 x 10⁷ N/C.
Electric field at D due to charge A
E = kq/r²
where;
r is the distance between A and Dq is charge AE(AD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)
E(AD) = 2.16 x 10⁷ i N/C
Electric field at D due to charge B
E = kq/r²
where;
r is the distance between A and Bq is charge Br² = 5² + 5²
r² = 50
r = √50
r = 7.07 cm
E(BD) = (9 x 10⁹ x 5 x 10⁻⁶)/(0.0707²)
E(BD) = 9 x 10⁶ N/C
in x - direction = 9 x 10⁶ N/C x cos(45) = 6.36 x 10⁶ i N/C
in y - direction = 9 x 10⁶ N/C x sin(45) = 6.36 x 10⁶j N/C
Electric field at D due to charge CE = kq/r²
where;
r is the distance between C and Dq is charge CE(CD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)
E(CD) = 2.16 x 10⁷ j N/C
Net electric field in x directionEi = 2.16 x 10⁷ i N/C + 6.36 x 10⁶ i N/C
Ei = 2.796 x 10⁷ i N/C
Net electric field in y directionEj = 2.16 x 10⁷ j N/C + 6.36 x 10⁶j N/C
Ej = 2.796 x 10⁷ j N/C
Resultant electric field at DE = √Ei² + Ej²
E = √[(2.796 x 10⁷)² + (2.796 x 10⁷)²]
E = 3.95 x 10⁷ N/C
Thus, the net electric field at point D is determined as 3.95 x 10⁷ N/C.
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