A survey was conducted to find out how many people use public transportation to get to work. The results for 4625 respondents are broken down by gender: 1000 of 2570 males and 1532 of 2055 females use public transportation every working day. Use the information to find the standard error for the difference in proportions of males and females who use public transportation every working day and check the conditions for a normal distribution.

Answers

Answer 1

Answer:

The standard error for the difference in proportions of males and females who use public transportation every working day is 0.015.

The conditions are met.

Step-by-step explanation:

The sample 1 (males), of size n1=2570 has a proportion of p1=0.389.

[tex]p_1=X_1/n_1=1000/2570=0.389[/tex]

The sample 2 (females), of size n2=2055 has a proportion of p2=0.745.

[tex]p_2=X_2/n_2=1532/2055=0.745[/tex]

The difference between proportions is (p1-p2)=-0.356.

[tex]p_d=p_1-p_2=0.389-0.745=-0.356[/tex]

The pooled proportion, needed to calculate the standard error, is:

[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{1000+1532}{2570+2055}=\dfrac{2532}{4625}=0.547[/tex]

The estimated standard error of the difference between means is computed using the formula:

[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.547*0.453}{2570}+\dfrac{0.547*0.453}{2055}}\\\\\\s_{p1-p2}=\sqrt{0.000096+0.000121}=\sqrt{0.000217}=0.015[/tex]

Conditions for a normal distribution approximation:

The expected number of "failures" or "successes", whichever is smaller, has to be larger than 10.

For the males sample, we have p=0.389 and (1-p)=0.611. The sample size is n=2570, so we take the smallest proportion and chek the condition:

[tex]n\cdot p=2570\cdot 0.389=999>10[/tex]

For the females sample, we have p=0.745 and (1-p)=0.255. The sample size is n=2055, so we take the smallest proportion and chek the condition:

[tex]n\cdot (1-p)=2055\cdot 0.255=524>10[/tex]

The conditions are met.


Related Questions

The weight of a chocolate bar is 4.4 ounces, but can vary. Let W be a random variable that represents the weight of a chocolate bar. The probability density function of Wis given below. If the shaded portion of the graph of the continuous probability density function below is 0.42739, what is the probability that a chocolate bar is at least 4 ounces, but no more than 7 ounces?

Answers

Answer:

Ans) 42.7%

Step-by-step explanation:

For a continuous probability distribution, a curve known as probability density function contains information about these probabilities.

in the given range -

The probability that a continuous random variable = equal to the area under the probability density function curve

The probability that the value of a random variable is equal to 'something' is 1.

As per the diagram,

Weight of chocolate bar between 4 ounces and 7 ounces is highlighted in the blue part. That area is said to be 0.42739 and the total area under the curve is 1.

Hence required probability

=0.42739/1=0.42739

Ans) 42.7%

Round to nearest tenth of a percent

The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA basketball tournament (not all private schools report their coach's salaries). Consider these 62 salaries to be a sample from the population of salaries of all 346 NCAA Division I basketball coaches.Question 1. Use the 62 salaries from the TOTAL PAY column to construct a 95% confidence interval for the mean salary of all basketball coaches in NCAA Division I.$lower bound of confidence interval ______________$ upper bound of confidence interval __________________Question 2. Coach Mike Krzyzewski's high salary is an outlier and could be significantly affecting the confidence interval results. Remove Coach Krzyzewski's salary from the data and recalculate the 95% confidence interval using the remaining 61 salaries.$ lower bound of confidence interval _______________$ upper bound of confidence interval. _______________

Answers

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA basketball tournament (not all private schools report their coach's salaries). Consider these 62 salaries to be a sample from the population of salaries of all 346 NCAA Division I basketball coaches.

Question 1. Use the 62 salaries from the TOTAL PAY column to construct a 95% confidence interval for the mean salary of all basketball coaches in NCAA Division I.

xbar = $1,465,752

SD = $1,346,046.2

lower bound of confidence interval ________

upper bound of confidence interval _______

Question 2. Coach Mike Krzyzewski's high salary is an outlier and could be significantly affecting the confidence interval results. Remove Coach Krzyzewski's salary from the data and recalculate the 95% confidence interval using the remaining 61 salaries.

xbar = $1,371,191

SD = $1,130,666.5

lower bound of confidence interval _________

upper bound of confidence interval. ________

Answer:

Question 1:

lower bound of confidence interval = $1,124,027

upper bound of confidence interval = $1,807,477

Question 2:

lower bound of confidence interval = $1,081,512

upper bound of confidence interval = $1,660,870

Step-by-step explanation:

Question 1:

The sample mean salary of 62 couches is

 [tex]\bar{x} = 1,465,752[/tex]

The standard deviation of mean salary is

 [tex]s = 1,346,046.2[/tex]

The confidence interval for the mean salary of all basketball coaches is given by

 [tex]$ CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $[/tex]

Where [tex]\bar{x}[/tex] is the sample mean, n is the sample size, s is the sample standard deviation and  [tex]t_{\alpha/2}[/tex] is the t-score corresponding to a 95% confidence level.  

The t-score corresponding to a 95% confidence level is  

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025  

Degree of freedom = n - 1 = 62 - 1 = 61

From the t-table at α = 0.025 and DoF = 61

t-score = 1.999

So the required 95% confidence interval is  

[tex]CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (\frac{1,346,046.2}{\sqrt{62} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (170948.04 ) \\\\CI = 1,465,752 \pm 341,725 \\\\LCI = 1,465,752 - 341,725 = 1,124,027 \\\\UCI = 1,465,752 + 341,725 = 1,807,477\\\\[/tex]

Question 2:

After removing the Coach Krzyzewski's salary from the data

The sample mean salary of 61 couches is

[tex]\bar{x} = 1,371,191[/tex]

The standard deviation of the mean salary is

[tex]s = 1,130,666.5[/tex]

The t-score corresponding to a 95% confidence level is  

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025  

Degree of freedom = n - 1 = 61 - 1 = 60

From the t-table at α = 0.025 and DoF = 60

t-score = 2.001

So the required 95% confidence interval is  

[tex]CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (\frac{1,130,666.5}{\sqrt{61} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (144767 ) \\\\CI = 1,371,191 \pm 289,678.8 \\\\LCI = 1,371,191 - 289,678.8 = 1,081,512 \\\\UCI = 1,371,191 + 289,678.8 = 1,660,870\\\\[/tex]

Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).

The test statistic in a two-tailed test is z = -1.63.

a. 0.1031; fail to reject the null hypothesis
b. 0.0516; reject the null hypothesis
c. 0.9484; fail to reject the null hypothesis
d. 0.0516; fail to reject the null hypothesis

Answers

Answer: a. 0.1031; fail to reject the null hypothesis

Step-by-step explanation:

Given: Significance level : [tex]\alpha=0.05[/tex]

The test statistic in a two-tailed test is z = -1.63.

The P-value for two-tailed test : [tex]2P(Z>|z|)=2P(Z>|-1.63|)=0.1031[/tex] [By p-value table]

Since, 0.1031 > 0.05

i.e. p-value > [tex]\alpha[/tex]

So, we fail to reject the null hypothesis. [When p<[tex]\alpha[/tex] then we reject null hypothesis  ]

So, the correct option is a. 0.1031; fail to reject the null hypothesis.

WWW
3.
The expression "5 FACTORIAL" equals
3-A
125
3-B
120
3-C
25
3-D
10
* Select Answer Below​

Answers

Answer:

5! = 120

Step-by-step explanation:

5! is basically 5(4)(3)(2)(1).

Solve the equation: 1. 3y+(y−2)=2(2y−1) 2. 6(1+5x)=5(1+6x)

Answers

Answer:

Step-by-step explanation:

I'm not sure what are u asking exactly

Write the equation of each line in slope-intercept form.
(If possible please show work)

Answers

Answer:

y = -1/2x + 1/2

Step-by-step explanation:

Step 1: Write in known variables

y = -1/2x + b

Step 2: Find b

2 = -1/2(-3) + b

2 = 3/2 + b

b = 1/2

Step 3: Rewrite equation

y = -1/2x + 1/2

Circles c and c are similar state the translation rule and the scale factor of dilation

Answers

To obtain circle C', circle C was translated to the right 3 units and down 2 units, then dilated by a scale factor of 2

What is a transformation?

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, rotation, reflection and dilation.

Dilation is the increase or decrease in the size of a figure.

To obtain circle C', circle C was translated to the right 3 units and down 2 units, then dilated by a scale factor of 2

Find out more on transformation at: brainly.com/question/4289712

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PLS HELP ME WITH MY GEOMETRY ITS MY LAST QUESTION

Answers

Answer:

12, 1

Step-by-step explanation:

12- 6(1)=

12-6= 6

You are interested in purchasing a new car. One of the many points you wish to consider is the resale value of the car after 5 years. Since you are particularly interested in a certain foreign​ sedan, you decide to estimate the resale value of this car with a 95​% confidence interval. You manage to obtain data on 17 recently resold​ 5-year-old foreign sedans of the same model. These 17 cars were resold at an average price of $ 12 comma 100 with a standard deviation of $ 800. What is the 95​% confidence interval for the true mean resale value of a​ 5-year-old car of this​ model?

Answers

Answer:

The 95​% confidence interval for the true mean resale value of a​ 5-year-old car of this​ model

(11,688.68 , 12,511.32)

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 17

mean of the sample x⁻ = 12,100

Standard deviation of the sample (S) = 800

The 95​% confidence interval for the true mean resale value of a​ 5-year-old car of this​ model

[tex](x^{-} - t_{0.05} \frac{S}{\sqrt{n} } , x^{-} + t_{0.05} \frac{S}{\sqrt{n} } )[/tex]

Step(ii):-

Degrees of freedom ν =n-1 = 17-1 =16

[tex]t_{(16 , 0.05)} = 2.1199[/tex]

The 95​% confidence interval for the true mean resale value of a​ 5-year-old car of this​ model

[tex](x^{-} - t_{0.05} \frac{S}{\sqrt{n} } , x^{-} + t_{0.05} \frac{S}{\sqrt{n} } )[/tex]

[tex](12,100 - 2.1199\frac{800}{\sqrt{17} } , 12,100 + 2.1199 \frac{800}{\sqrt{17} } )[/tex]

(12,100 - 411.32 , 12,100 + 411.32)

(11,688.68 , 12,511.32)

The following situation can be modeled by a linear function. Write an equation for the linear function and use it to answer the given question. Be sure you clearly identify the independent and dependent variables. Then briefly discuss whether a linear model is reasonable for the situation described. The price of a particular model car is $19,000 today and rises with time at a constant rate of $960 per year. How much will a new car of this model cost in 3.7 years?
Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.)
A. The independent variable is the price (o) in dollars, and the dependent variable is time (1), in years. The linear function that models this situation is __________
B. The independent variable is time (), in years, and the dependent variable is the price (p), in dollars. The linear function that models this situation is________
The price of a car after 3.7 years will be $ (Simplify your answer.) Is a linear model reasonable for the situation?
A. The linear model is most likely not reasonable, because the price of a new car of the same model never changes, regardless of how much time passes.
B. The linear model is most likely not reasonable, because the price of a new car of the same model will always decrease at a constant rate.
C. The linear model is most likely not reasonable, because it is unlikely that the price of a new car of the same model will increase at a constant rate. always increases at a constant rate.

Answers

Answer: The answer is B)

B. The independent variable is time​ (t), in​ minutes, and the dependent variable is rental cost​ (r), in dollars. The linear function that models this situation is r equals to r=0.55x+8

Step-by-step explanation:

A researcher looked at characteristics of elementary school students and,
in particular, observed whether students satisfied any of the following
criteria:
A = The student lived with at least one of their biological parents
B = The student lived with at least one grandparent
C = The student lived with two parents who were legally married
D = The student lived with only one parent
Which of the events above are mutually exclusive? Select all that apply.
1.) A,C
2.) A,D
3.) C,D
4.) B,C

(Side note: I put down options 3&4 but got it wrong, not sure what I’m missing?)

Answers

Answer:

1. A, C

2. A, D

Step-by-step explanation:

The mutually exclusive events are one which cannot happen together. The observation is made regarding with which students live. They live with either one of their biological parent or grandparent. The student have the option to live with two legally married couple this is mutually exclusive event. If the student is living with their one biological parent he cannot live with two legally married parents.

Solve the puzzle


Replace the question marks with numbers:



76533483


94529245


958??769

Answers

Answer:

95891769

Step-by-step explanation:

This is extract from a brain teaser exercise in which sequence is formed to identify the numbers. In this brain teaser we have made combinations of different numbers which lead to the correct answer. The two correct forms of number are given which are used as a base for determining the correct answer.

Plz help ASAP I’ll give lots of points

Answers

Answer:

8

Step-by-step explanation:

Because it is equal to the 4 side

Please answer this correctly

Answers

Step-by-step explanation:

pnotgrt8rthan4 = 3 ÷ 7 × 100

= 42.8571428571 / 43%

Question 4 of 10
Which polynomial represents the difference below?
5x2
+9x+3
(6x2-3x)
O A. -x + 12x+3
B. 5x2 + 3x + 3
O C. 5x2 + 6x + 3
O D. - x2 + 6x + 3
SUBMIT
PREVIOUS​

Answers

Answer:

-x² + 12x + 3

Step-by-step explanation:

Step 1: Write expression

5x² + 9x + 3 - (6x² - 3x)

Step 2: Distribute

5x² + 9x + 3 - 6x² + 3x

Step 3: Combine like terms

-x² + 12x + 3


In the figure, AB =
Inchesand AC=
inches.

Answers

Answer:

[tex]\displaystyle AB \approx 8.39 \text{ inches} \text{ and } AC \approx 13.05 \text{ inches}[/tex]

Step-by-step explanation:

Note that we are given the measure of ∠C and the length of side BC.

To find AB, we can use the tangent ratio. Recall that:

[tex]\displaystyle \tan\theta = \frac{\text{opposite}}{\text{adjacent}}[/tex]

Substitute in appropriate values:

[tex]\displaystyle \tan 40^\circ = \frac{AB}{BC} = \frac{AB}{10}[/tex]

Solve for AB:

[tex]\displaystyle AB = 10\tan 40^\circ \approx 8.39\text{ inches}[/tex]

For AC, we can use cosine ratio since we have an adjacent and need to find the hypotenuse. Recall that:

[tex]\displaystyle \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}[/tex]

Substitute in appropriate values:

[tex]\displaystyle \cos 40^\circ = \frac{BC}{AC} = \frac{10}{AC}[/tex]

Solve for AC:

[tex]\displaystyle \begin{aligned} \frac{1}{\cos 40^\circ} & = \frac{AC}{10} \\ \\ AC & = 10\cos 40^\circ \approx 13.05\text{ inches} \end{aligned}[/tex]

In conclusion, AB is about 8.39 inches and AC is about 13.03 inches.

The length of the rectangle is described by the function y = 3x + 6, where x is the width of the rectangle. Find the domain in this situation.

Answers

Answer:2/3

Step-by-step explanation:

Given that the length of the rectangle is described by the function y = 3x + 6, where x is the width of the rectangle. The domain of the function is (0, ∞).

What is domain of a function?

The domain of a function is the set of all possible inputs for the function. In other words, domain is the set of all possible values of x. In this question, x is the width of the rectangle. Width of a rectangle existing in two dimensional space, cannot be negative or zero. Thus it is the set of all positive real numbers, or we say, (0, ∞).

Learn more about domain of a function here

https://brainly.com/question/13113489

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I NEED HELP PLEASE, THANKS! :)

Answers

Consider the standard form of each of the following options given, and note the hyperbola properties through that derivation -

[tex]Standard Form - \frac{\left(x-5\right)^2}{\left(\sqrt{7}\right)^2}-\frac{\left(y-\left(-5\right)\right)^2}{3^2}=1,\\Properties - \left(h,\:k\right)=\left(5,\:-5\right),\:a=\sqrt{7},\:b=3\\[/tex]

Similarly we can note the properties of each of the other hyperbolas. They are all similar to one another, but only option C is correct. Almost all options are present with a conjugate axis of length 6, but only option c is broad enough to include the point ( 1, - 5 ) and ( 9, - 5 ) in a given radius.

Solution = Option C!

a) Reetu sold a watch to Reshmi at 20% profit. Reshmi again sold the same watch to
Nikita for Rs 1,350 at a loss of 10%. At what price did Reetu purchase the watch?
41
ique's Mathematics - 9​

Answers

Answer:

1250,Rs

Step-by-step explanation:

Let Reetu paid for the watch x Rs. Then Reetu sold the watch to Reshmi having 20% profit => the selling price is 1.2*x

Then Teshmi sold the wathes with 10% loss (or 0.9 from purchase price 1.2x)   to Nikita, i.e. selling price is

1.2*x*0.9=1350

1.08*x=1350

x=1350:1.08

x=1250, Rs

Rebecca collected data from a random sample of 500 homeowners in her state asking whether or not they use electric heat. Based on the results, she reports that 51% of the homeowners in the nation use electric heat. Why is this statistic misleading?

Answers

Answer:

She makes conclusion about a population that is not well represented by the sample.

Step-by-step explanation:

The conclusion she is making is about a population that is not well represented by her sample: the population is the homeowners in the nation, but the sample is made of homeowners or only her state.

The population about which she can make conclusions with this sample is the homeowners of her state, given that the sampling is done right.

Answer: The sample is biased

Find the value of x in the diagram below. A. B. C. D. Please select the best answer from the choices provided A B C D

Answers

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Trigonometry.

Since we have to use here, Sine ration.

Sine of an Angle = Perpendicular side/Hypotenuse Side.

So we get as,

X = 3 .

Answer:

the answer is c

Step-by-step explanation:

PLEASE HELP!!! Bob earns $1,825 per month as a clerk at Elm City Sporting Goods. How much does he earn in a year? Explain how you got your answer. (50 points)

Answers

Answer:

21900

Step-by-step explanation:

There are 12 months in a year, so multiply the yearly amount by 12

1825 * 12

21900

Answer:

Bob makes $21,000 in a year.

Step-by-step explanation:

There are 12 months in a year, so if he earns $1,825 every month to get his yearly pay you need to add 1,825 twelve times. Thus, 1,825×12=21,000. Hope this helps!

An engineer for an electric fencing company is interested in the mean length of wires being cut automatically by machine. The desired length of the wires is 12 feet. It is known that the standard deviation in the cutting length is 0.15 feet. Suppose the engineer decided to estimate the mean length to within 0.025 with 99% confidence. What sample size would be needed?

Answers

Answer:

[tex]n=(\frac{2.58(0.15)}{0.025})^2 =239.63 \approx 240[/tex]

So the answer for this case would be n=240 rounded up to the nearest integer

Step-by-step explanation:

We know the following info:

[tex]\sigma =0.15[/tex] represent the population deviation

[tex] ME= 0.025[/tex] the margin of error desired

The margin of error is given by this formula:

[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]    (a)

And on this case we have that ME =0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

[tex]n=(\frac{z_{\alpha/2} s}{ME})^2[/tex]   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. And we got [tex]z_{\alpha/2}=2.58[/tex], replacing into formula (b) we got:

[tex]n=(\frac{2.58(0.15)}{0.025})^2 =239.63 \approx 240[/tex]

So the answer for this case would be n=240 rounded up to the nearest integer

Stat 3309 - Statistical Analysis for Business Applications I

Consider the following data representing the starting salary (in $1,000) at some company and years of prior working experience in the same ï¬eld. The sample of 10 employees was taken and the following data is reported.

Years of experience

Starting Salary (in $1,000)
0
45

2 50
5 55
7 62
8 63
10 70
12 68
15 75
18 81
20 92
Part 1: Use the formulas provided on the 3rd formula sheet to compute the following quantities. Open an Excel spreadsheet and write the table with data given above. Add columns for x2, y2, and xy, as well as the last row for Σ. For each of the following quantities, write the formula for it in a cell and evaluate it.

(a) Find the sample correlation coeï¬cient r.

(b) Find the slope b1 of the sample regression line.

(c) Find the y-intercept b0 of the sample regression line.

(d) What is the equation of the sample regression line?

(e) Find the predicted starting salary for a person who spent 15 years working in the same ï¬eld.

(f) Find the observed starting salary for a person who spent 15 years working in the same ï¬eld.

(g) What is the diï¬erence between the observed and the predicted starting salary for a person who spent 15 years working in the same ï¬eld?

(h) Find the total sum of squares SST.

(i) Find the sum of squares error SSE.

(j) Find the sum of squares regression SSR.

(k) Use the answers from (h)-(j) to conï¬rm that SST = SSR + SSE. (l) Find the coeï¬cient of determination R2.

(m) Use your answers for (a), (b) and (l), to conï¬rm that r = ±âR2.

(n) What proportion of variation is explained using the regression model?

(o) Find the standard error of the estimate se.

(p) Find the standard error of the regression slope sb.

(q) Does the number of years of prior working experience in the same ï¬eld aï¬ect the starting salary at this company ? Use the sample provided above and the signiï¬cance level of 0.05.

(hint: perform the hypothesis test for H0 : β1 = 0 vs. H1 : β1 6= 0.)

Part 2: Find and use Excel built-in-functions to check your answers for r, b1, and b0. Next to each cell from Part 1, calculate these three quantities using Excel built-in-functions and conï¬rm your answers from Part 1.

(hint: for example, for r the Excel built-in function is "CORREL")

Part 3: Bellow your answers from Parts 1 and 2, perform the regression analysis using Excel built-in-module which can be found under "DATA" â "Data Analysis" â "Regression" and double check your answers from Part 1. Draw the scatter plot of the data and, by visually observing the graph, determine if there is a linear relationship between the number of years of prior working experience in the same ï¬eld and the starting salary at this company.

Answers

Answer:

Solved below.

Step-by-step explanation:

The data is provided for the starting salary (in $1,000) at some company and years of prior working experience in the same field for randomly selected 10 employees.

(a)

The formula to compute the correlation coefficient is:

[tex]r=~\frac{n\cdot\sum{XY} - \sum{X}\cdot\sum{Y}} {\sqrt{\left[n \sum{X^2}-\left(\sum{X}\right)^2\right] \cdot \left[n \sum{Y^2}-\left(\sum{Y}\right)^2\right]}} \\[/tex]

The required values are computed in the Excel sheet below.

[tex]\begin{aligned}r~&=~\frac{n\cdot\sum{XY} - \sum{X}\cdot\sum{Y}} {\sqrt{\left[n \sum{X^2}-\left(\sum{X}\right)^2\right] \cdot \left[n \sum{Y^2}-\left(\sum{Y}\right)^2\right]}} \\r~&=~\frac{ 10 \cdot 7252 - 97 \cdot 661 } {\sqrt{\left[ 10 \cdot 1335 - 97^2 \right] \cdot \left[ 10 \cdot 45537 - 661^2 \right] }} \approx 0.9855\end{aligned}[/tex]

Thus, the sample correlation coefficient r is 0.9855.

(b)

The slope of the regression line is:

[tex]b_{1} &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\\= \frac{ 10 \cdot 7252 - 97 \cdot 661 }{ 10 \cdot 1335 - \left( 97 \right)^2} \\\\\approx 2.132[/tex]

Thus, the slope of the regression line is 2.132.

(c)

The y-intercept of the line is:

[tex]b_{0} &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\\= \frac{ 661 \cdot 1335 - 97 \cdot 7252}{ 10 \cdot 1335 - 97^2} \\\\\approx 45.418[/tex]

Thus, the y-intercept of the line is 45.418.

(d)

The equation of the sample regression line is:

[tex]y=45.418+2.132x[/tex]

(e)

Compute the predicted starting salary for a person who spent 15 years working in the same field as follows:

[tex]y=45.418+2.132x\\\\=45.418+(2.132\times15)\\\\=45.418+31.98\\\\=77.398\\\\\approx 77.4[/tex]

Thus, the predicted starting salary for a person who spent 15 years working in the same field is $77.4 K.

Answer:

Yes correct

Step-by-step explanation:

I think this is correct becase: 2 50

5 55

7 62

etc

these are all correct

What is the slope of a line that is perpendicular to the line whose equation is 2x+7y=5?

Answers

Answer:

7/2x

Step-by-step explanation:

Well first we need to put,

2x + 7y = 5,

into slope intercept

-2x

7y = -2x + 5

Divide y to all numbers

y = -2/7x + 5/7

So the slope for the given line is -2/7,

the slope of the line that is perpendicular to it is its reciprocal.

Meaning the slope of the perpendicular line is 7/2.

Thus,

the slope of the perpendicular line is 7/2x.

Hope this helps :)

Answer:

The slope of the perpendicular line is 7/2

Step-by-step explanation:

2x+7y=5

Solve for y to find the slope

2x-2x+7y=5-2x

7y = -2x+5

Divide by 7

7y/7 = -2/7 x +5/7

y = -2/7x + 5/7

The slope is -2/7

The slope of perpendicular lines multiply to -1

m * -2/7 = -1

Multiply each side by -7/2

m * -2/7 *-7/2 = -1 * -7/2

m = 7/2

The slope of the perpendicular line is 7/2

Which values are in the solution set of the compound inequality? Select two options. 4(x + 3) ≤ 0 or x+1>3 answer choices: –6 –3 0 3 8

Answers

Answer:

-6, -3

3, 8

Step-by-step explanation:

In order to find the number that are solutions to the compound inequalities, you first solve fr x on each inequality.

First inequality:

[tex]4(x+3)\leq 0\\\\4x+12\leq0\\\\4x\leq-12\\\\x\leq-3[/tex]  interval = (-∞ , -3]

Second inequality:

[tex]x+1>3\\\\x>2[/tex]   interval = (2 , ∞)

The interval solution is (-∞ , -3] U (2 , ∞)

The number that are included in the previous interval are:

-6, -3

or

3, 8

Answer: any except 0

Step-by-step explanation:

What is the area of the equilateral triangle with side length of 6?

Answers

Answer:

18

Step-by-step explanation:

area of a triangle is length x base

so 6 x 6 = 36

36 divided by 2 = 18

I hope it helps :)

Answer: The area is about 15.59 and is round to the nearest hundredth.

Step-by-step explanation:

An equilateral triangle has three equal sides is just like an isosceles triangle.

So in this case, we know that the base is 6 and since the base is 6 all the other two sides is also 6 .But we do not know the height to find the area so we need to find the height.

The height is the distance of from the base to the tip or top which helps form two right triangles.. And if you divide as  an equilateral triangle into two parts you will form two right triangles. Imagine we have divide the isosceles triangle into two parts to form two right triangles. We will now have a base of 3 instead of 6 and and hypotenuse of 6 .  but we still don't know the height so we need to  find it.

Using the Pythagorean Theorem we could say that a^2 plus b^2 squared is equal to c^2 squared.

We know a as 3 and c the hypotenuse as 6.

so 3^2 + b^2 =6^2  solve for b

  9 + b^2 = 36

 -9               -9

   b^2 = 27

  b= [tex]\sqrt{27}[/tex]  

b= 5.196  

Now we know that b is about 5.196 which is the  height.Now we could find the area by  multiplying  the base by the height.

5.196 * 6 = 31.176  

31.176/2 = 15.588  

Now you could round it to the nearest hundredth to be 15.59  

   

Will give brainliest answer

Answers

Answer:

[tex]153.86 \: {units}^{2} [/tex]

Step-by-step explanation:

[tex]area = \pi {r}^{2} \\ = 3.14 \times 7 \times 7 \\ = 3.14 \times 49 \\ = 153.86 \: {units}^{2} [/tex]

Answer:

153.86 [tex]units^{2}[/tex]

Step-by-step explanation:

Areaof a circle = πr^2

[tex]\pi = 3.14[/tex](in this case)

[tex]r^{2} =7[/tex]

A = πr^2

= 49(3.14)

= 153.86

An athletics coach states that the distribution of player run times (in seconds) for a 100-meter dash is normally distributed with a mean equal to 13.00 and a standard deviation equal to 0.2 seconds. What percentage of players on the team run the 100-meter dash in 13.36 seconds or faster

Answers

Answer:

96.41% of players on the team run the 100-meter dash in 13.36 seconds or faster

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 13, \sigma = 0.2[/tex]

What percentage of players on the team run the 100-meter dash in 13.36 seconds or faster

We have to find the pvalue of Z when X = 13.36.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{13.36 - 13}{0.2}[/tex]

[tex]Z = 1.8[/tex]

[tex]Z = 1.8[/tex] has a pvalue of 0.9641

96.41% of players on the team run the 100-meter dash in 13.36 seconds or faster

The average weight of a package of rolled oats is supposed to be at least 18 ounces. A sample of 18 packages shows a mean of 17.78 ounces with a standard deviation of 0.41 ounces. At the 5% level of significance, is the true mean smaller than the specification?

Answers

Answer:

Step-by-step explanation:

The average weight of a package of rolled oats is supposed to be at least 18 ounces

Null hypothesis: u >= 18

Alternative: u < 18

Using the t-test formula, we have

t = x-u/ (sd/√n)

Where x is 17.78, u = 18, sd = 0.41 and n = 18

t = 17.78-18 / (0.41/√18)

t = -0.22 / (0.41/4.2426)

t = -0.22/ 0.0966

t = -2.277

Since, this is a left tailed test, at a significance level of 0.05, the p value is 0.01139. Since the p value is less than 0.05, we will reject the null hypothesis and conclusion that the true mean smaller than the actual specification.

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