A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of 1.2 days. Construct a 95% confidence interval for the population's mean length of vacation. ( , ) Round your answer to two decimal digits Construct a 92% confidence interval for the population's mean length of vacation. ( , ) Round your answer to two decimal digits

Answers

Answer 1

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 1.989.

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

[tex]M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).


Related Questions

the minute hans on the clock shown below has a length of 7.5 cm. which of the following is closest to the distance that the tip of the hand travels as it moves from 12 to 4

Answers

Answer:

16

Step-by-step explanation:

The  following is closest to the distance that the tip of the hand travels as it moves from 12 to 4 should be considered as the 16 cm.

Calculation of the distance:

Since the minute hans on the clock shown below has a length of 7.5 cm

And, the tip of the hand travels as it moves from 12 to 4

So,

For full rotation it should be like [tex]2\pi[/tex] radians

Since angle turned by minute hand in 5 minutes so it should be like [tex]= 2\pi \div 12[/tex] radians

So

[tex]= 7.5 \times 2.094[/tex]

= 15.7 cm

Learn more about distance here: https://brainly.com/question/13448007

Take a look at the photo and please right an explanation for your answer

Answers

The answer is 360

So you have to find the volume of the top part of the shape which is 72. Then you get the other parts, which is 288. Add them up and get 360

Find the slope and the y-intercept of the line. 6x + 3y = -3 Write your answers in simplest form​

Answers

Answer:

[m] slope = -2

[b] y-intercept = -1 ; (0, -1)

[y = mx + b] slope-intercept = -2x – 1

Step-by-step explanation:

Given the algebraic equation 6x + 3y = -3 currently in standard form:

Ax + By = C →

By = C – Ax →

By = -Ax + C →

y = -Ax / B + C / B →

y = (-A / B)x + (C / B) →

y = mx + b →

m = -A / B. b = C / B.

6x + 3y = -3

↓ ↓ ↓

A = 6. B = 3. C = -3.

[Substitute]

m = -A / B. b = C / B

m = -(6) / (3). b = (-3) / (3)

↓ ↓

m = -2. b = -1.

↓. ↓

Slope = -2. y-intercept = -1.

_______________________

Slope is ∆y/∆x [change in y over the change in x] = y2 – y1 / x2 – x1.

The y-intercept is the point where x is 0.

The easiest way to determine this is to substitute 0 in for x in an equation and solve for y.

This means that the y intercept in coordinate form is (0, b).

Help please!!!! will Brainly!!!

Answers

Answer:

true

Step-by-step explanation:

.................

True :) have a nice day! :) can u make me brainliest? Pls :)? Ty ✨

Plz help find the rule 50 points

Answers

Answer:

1², 2²,3², 4², 5², 6², 7², 8², 9², 10², 11², 12², 13², 14², 15², 16², 17², 18², 19², 20²,........

Each number is multiplied by itself.

Write the expression as a product of expressions.

(Factor this expression.)
`a^{3}b^{3}-a^{2}b^{2}-a^{2}c^{2}`

PLEASE HELP THIS IS URGENT

Answers

Answer:

[tex]a^2(ab^{3}-b^{2}-c^{2})[/tex]

Step-by-step explanation:

Given

[tex]a^{3}b^{3}-a^{2}b^{2}-a^{2}c^{2}[/tex]

Required

Factor

[tex]a^{3}b^{3}-a^{2}b^{2}-a^{2}c^{2}[/tex]

Factor out [tex]a^2[/tex]

[tex]a^2(ab^{3}-b^{2}-c^{2})[/tex]

The expression cannot be further factored

Write an equation of a line with slope -4 and y- intercept of 0

Answers

Answer:

y=-4x

Step-by-step explanation:


What is the solution set of the system of equations
x+y = 5 and y=x^2- 25?
1) {(0.5) (11,-6)}
2) {(5,0).(-6,11)
3) {(-5,0),(6,11)
4) {(-5,10).(6.-1)

Answers

You can basically just plug in the values. “2) {(5,0).(-6,11)}” is correct.

The Sine Function

According to the National Weather Service, the average monthly high temperature in the Dallas/Fort Worth, Texas area from the years of 2006-2008 is given by the following table:

To get a feel for the relationship between the month and the average high temperatures, the data is plotted on the following scatter plot.

If the plot was extended to a two year period with 1 = Jan of the first year, 12 = Dec of the first year, 13 = Jan of the second year, 24 = Dec of the second year, describe the plot with the additional information.

a. Linear
b. Random dots
c. Wave-like and repetitive
d. Quadratic

Please select the best answer from the choices provided

Answers

Answer:

C. Wave-like and repetitive

Step-by-step explanation:

I calculated it logically

All of the following are equivalent except _____.
7.5:4.5
5 is to 3
15/5
45/27

Answers

Answer:

15/5

Step-by-step explanation:

because 7.5 ÷ 4.5 = 1.66667

5 ÷ 3 = 1.66667

and 45 ÷ 27 = 1.66667

but 15 ÷ 5 = 3 therefore it's the off one out.

Given the function f(x) = 4^x - 1, explain and show how to find the average rate of change between x = 1 and x = 4.

Answers

Answer:

84

Step-by-step explanation:

f(1)=4^1 - 1 = 3

f(4) = 4^4 - 1 = 255

rate of change = [tex]\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]

(255 - 3) / (4 - 1) = 252 / 3 = 84

HELP ME PLEASEEEEEEEEEEEEEEEEEEE

Answers

True.


Hope it helps..............!

Five times a number is 80 less than 7 times the number. Find the number.

Answers

I think its 16 but im not completly sure

Degree and Radian Measures

Convert the given radian measure to a degree measure.
1.2 /pi (π)

a. -216°
b. 108°
c. 216°
d. -108°

Please select from the best choices provided

Answers

Answer:

C. 216°

Step-by-step explanation:

I calculated it logically

Hi, i need to calculate roots x1 and x2 using the vieta theorem, can anyone help me? I have found the answer for x1 and x2, its 1,5 and 2, all i need is a solution on how to get this answer, the equation is in the picture, will give you brainliest if you type down the correct solution for me, thanks.

Answers

Answer:

Solution given:

-2x²+7x-6=0

2x²-7x+6=0

Comparing above equation with ax²+bx+c

we get

a=2

b=-7

c=6

By using Vieta's theorem

X1+X2=[tex] \frac{-b}{a} [/tex]=[tex] \frac{7}{2} [/tex]

again

X1X2=[tex] \frac{c}{a} [/tex]=[tex] \frac{6}{2} [/tex]=3

It has been observed that some persons who suffer acute heartburn, again suffer acute heartburn within one year of the first episode. This is due, in part, to damage from the first episode. The performance of a new drug designed to prevent a second episode is to be tested for its effectiveness in preventing a second episode. In order to do this two groups of people suffering a first episode are selected. There are 45 people in the first group and this group will be administered the new drug. There are 75 people in the second group and this group will be administered a placebo. After one year, 12% of the first group has a second episode and 14% of the second group has a second episode. Conduct a hypothesis test to determine, at the significance level 0.1, whether there is reason to believe that the true percentage of those in the first group who suffer a second episode is less than the true percentage of those in the second group who suffer a second episode.
A. [ z < -1.65, RHo].
B. [ z < -1.65 and z > 1.65, FRHo].
C. [z > 1.65, FRHo].
D. [z < -1.65 and z > 1.65, FRHo].
E. [z > -1.65 and z < 1.65, RHo].
F. None of the above.

Answers

Answer:

F. None of the above.

Step-by-step explanation:

Let the null and alternate hypothesis be

H0: p1 ≥ p2 against the claim Ha: p1 < p2

the significance level is 0.1

The critical region is z < z∝= 1.28

The test statistic is

Z= ( p^1-p^2)- (p1-p2)/√p1^q1^/n1 + p2^q2^/n2

Here n1= 45 ,   n2= 75

         p1= 0.12         p2= 0.14

         q1= 0.88        q2= 0.86

z= 0.12- 0.14/√0.12*0.88/45 +0.14*0.86/75

Z=  0.02/ √0.00235 + 0.00161

Z=  0.02/0.062891

z= 0.318

The calculated value of z= 0.318  lies in the critical region z < 1.28

therefore accept Ha.

All of the options are incorrect as the critical value for one tailed test for 0.1 is 1.28 .

Suppose that two investors A and B have exhibited the indifference probabilities as shown in table below. Indifference probability Investor A Investor B Net return (RM) -2000 0 0 - 1000 0.70 0.10 0 0.80 0.20 1000 0.85 0.30 2000 0.90 0.50 3000 0.95 0.60 4000 1.00 1.00 a) Determine the utility value (for each monetary value) for each investor and fill it in table above. b) Graph the utility functions for both investors and categorize each investor as either a risk- averse person or a risk seeker. c) Suppose that investor A has the chance to invest in one of two ventures. Venture I can produce a net return of RM3000 with probability 0.40 or a net loss of RM1000 with probability 0.60. Venture II can produce a net return of RM2000 with probability 0.60 and no return with probability 0.40. Based on utility function in (b), use the expected utility criterion to determine the venture investor A should select. What is the expected monetary value associated with the selected venture?

Answers

Answer:

Da Answer is Suppose that two investors A and B have exhibited the indifference probabilities as shown in table below. Indifference probability Investor A Investor B Net return (RM) -2000 0 0 - 1000 0.70 0.10 0 0.80 0.20 1000 0.85 0.30 2000 0.90 0.50 3000 0.95 0.60 4000 1.00 1.00 a) Determine the utility value (for each monetary value) for each investor and fill it in table above. b) Graph the utility functions for both investors and categorize each investor as either a risk- averse person or a risk seeker. c) Suppose that investor A has the chance to invest in one of two ventures. Venture I can produce a net return of RM3000 with probability 0.40 or a net loss of RM1000 with probability 0.60. Venture II can produce a net return of RM2000 with probability 0.60 and no return with probability 0.40. Based on utility function in (b), use the expected utility criterion to determine the venture investor A should select. What is the expected monetary value associated with the selected venture?

Step-by-step explanation:

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Use
f(x)= 800 (1.32)x for 1-3
What is the intial amount?
What is the growth rate?
What is the growth factor?

Answers

So this in the exponential form of ab^x, where a is the y intercept, b is the growth factor(base) and x is your domain. From this, we can answer each question. The initial amount is 800, growth rate is 32% and factor is 1.32.


Happy learning!

Pleaseeee helpppppppp!!!

Answers

Answer:

x = 46°

Step-by-step explanation:

Appling the principle of supplementary angle in Geomentry.

Supplementary angle: These are angles that sum up to 180°

From the diagram above, x and 134° are supplementry because they sum up to 180°.

Therefore,

134+x = 180 (Supplementary angle)

Solve for x

x = 180-134

x = 46°

Therefore, the value of the missing angle is 46°

2.247 divided into 7 equals what​

Answers

I think it’s 200.000

When a water-cooled nuclear power plant is in operation, oxygen in the water is transmuted to nitrogen-17. After the reactor is shut down, the radiation from the nitrogen-17 decreases in such a way that the rate of change in the radiation level is directly proportional to the radiation level. Required:
a. Write a differential equation that expresses the rate of change in the radiation level in terms of the radiation level.
b. Suppose that when the reactor is first shut down, the radiation level is 3 × 1017 units. After 60 s the level has dropped to 5.6 × 1013 units. Write the particular equation.
c. Sketch the graph of radiation level versus time.
d. It is safe to enter the reactor compartment
when the radiation level has dropped to
7 × 10–3 units. Will it be safe to enter the reactor compartment 5 min after the reactor has been shut down? Justify your answer.

Answers

Answer:

hold on ill edit this once i get answer!! <3

Step-by-step explanation:

I do need to know NOTHING.

Answers

Answer:

Thats cool man.

Step-by-step explanation:

round 98,376 to the nearest thousand

Answers

Answer:

98000

Step-by-step explanation:

I will give Brainliest
Please help me find the answer

Answers

Answer:

in the first traingle

sinC = 36/39 = 12/13

CosC= 15/39 = 5/13

TanA= 15/36=5/12

this is the values i didnt understand the question so i just find the values

in the second Triangle

SinA=2√5/5

CosA=√5/5

TanB= √5/2√5=1/2

cos 30 = √3/2

sin45=√2/2

tan60= √3

hopefully its helpful iam sorry i didnt understand what they mean in the question my engilish is bad

Sin of c. Sin'-1(36/39)=90

Cos of c cos'-1(15/39)=67.38

Tan of a tan'-1(15/36)=22.62

Sin of a sin'-1(2squarroot5/5)=63.43

Cos od a cos'-1(squareroot5/5)=63.43

Tan of b tan'-1(2squareroot5/squareroot5)=63.43

Cos30 is pie/6 or squareroot of 3 /2

Sin of 45 is pie/4 or squareroot2/2

Tan60 is pie/3 or squareroot3

AB has points A at (2,−5) and B at (5,−3).

AB iis reflected across the y-axis and then translated 3 units right. What are the coordinates of the endpoints of the image A′B'?

Answers

9514 1404 393

Answer:

A'(1, -5)B'(-2, -3)

Step-by-step explanation:

Reflection over the y-axis and translation 3 right is modeled by the transformation ...

  (x, y) ⇒ (-x +3, y)

Then the image end points are ...

  A(2, -5) ⇒ A'(-2+3, -5) = A'(1, -5)

  B(5, -3) ⇒ B'(-5+3, -3) = B'(-2, -3)

_____

In the attached figure, the reflection is shown as A'B' in light purple. The line after the final translation is shown as A"B" in blue.

Somebody please help!

Answers

Answer:

57 7/9

Step-by-step explanation:

I used a fraction calculator.

The sidewalk is 5 feet wide and the garden measures 20 feet across. Which measurement is closest to the area of the outer edge of the sidewalk?
A.
200 ft2

B.
400 ft2

C.
700 ft2

D.
1,000 ft2

Answers

Answer:

A (obviously)

Step-by-step explanation:

Info Given

Sidewalk is 5 ft. wideGarden is 20 ft. across

A right-angled triangle, with two sides adjacent to the right angle labeled 7 and 11 respectively, and the hypotenuse is labeled x.
Find the exact value of $x$ .

Answers

Answer:

170

c=a^2+b^2=7^2+11^2≈13.0384 or 170

Step-by-step explanation:

mrk me brainliest please

The diagram shows the distance a tortoise can walk if it walks at a constant pace for 15 minutes. At the same rate, how many kilometers can the tortoise walk in 1 hour?
Write your answer as a decimal.

Answers

Answer:

3,098

Step-by-step explanation:

when you do the ,ath you will get it

the perimeter of a square field is 880m. Find it's area in hectares​

Answers

This is the answer hope it helps

The area of the square field is 4840 hectares.

What is perimeter of square?

Perimeter of the square is defined as addition the lengths of the square's four sides.

Perimeter of the square equation is 4a

Where, a is length of the square

Given data as :

Perimeter of the square field = 880 m

Side of the square = Perimeter/4

Side of the square = 880/4

Side of the square = 220 m

So, length of each side of the square is 220 m

Area of square = Side × Side

Area of square = 220 m  × 220 m

Area of square = 48400 square meters

Area of square = 48.4 square kilometers

As we know that 1 sq km = 100 hectares

So, 48.4 km = 48.4 × 100 = 4840 hectares

Hence, the area of the square field is 4840 hectares.

Learn more about Perimeter of square here:

https://brainly.com/question/11495285

#SPJ2

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