Answer:
yes
Step-by-step explanation:
mark me brainlist please
Answer:
the answer is d
Step-by-step explanation:
Jill says that 1 2/3 equals 3:5 is Jill correct
Answer:
Not true. Actually, 1 2/3 equals 5/3.
Answer: No
Step-by-step explanation:
If we were to change 1 2/3 into an improper fraction, it would be 5/3. This is expressed as 5:3, not 3:5. These two ratios are not the same. Therefore, Jill is not correct.
Hope this helped :)
how would you move the green shape exactly over the gray shape using the fewest moves? check only necessary moves
Answer:
C and B
Step-by-step explanation:
A box contains 4 yellow markers, 3 blue markers, 6 black markers and 2 red markers. Suppose a marker is chosen randomly, and then returned to the box.
Determine the probability of selecting a yellow marker, then a red marker.
Answer:
4+3+6+2 = 15
Step-by-step explanation:
selecting a yellow marker 4/15
selecting a red marker 2/15
In this composite function, (f◦g)(x) where f(x)=(X-3) and g(x)=X^2 what is (f◦g)(x) when x=1?
Answer:
When x = 1, (f◦g)(x) is -2.
Step-by-step explanation:
Composite function:
The composite function of f and g is given by:
[tex](f \circ g)(x) = f(g(x))[/tex]
In this question:
[tex]f(x) = x - 3, g(x) = x^2[/tex]
Composite function:
The composite function is:
[tex]f(g(x)) = f(x^2) = x^2 - 3[/tex]
At x = 1
[tex](f \circ g)(1) = 1^2 - 3 = 1 - 3 = -2[/tex]
So
When x = 1, (f◦g)(x) is -2.
A community organization wants to determine area support for the construction of a new skate park in the center of town. The organization decides to survey 500 people to see whether they are willing to have their taxes increased for one year to fund the construction of the skate park. What is the best way to randomly choose these 500 people? O Select the first 500 taxpayers listed at the town hall. O Survey the first 500 people who visit the existing skate park. O Assign each taxpayer in town a number and then randomly select 500 of these numbers. O Choose 100 taxpayers from 5 different age groups in town.
PLEASE HELP!!!!
Answer: I just took the test, and the answer is 'Assign each taxpayer in town a number and then randomly select 500 of these numbers.'
Step-by-step explanation: Happy Pride Month!!
plz help 5th grade work
Answer:
81 , 24 AND 108
Step-by-step explanation:
Find the range of the data. 45,76,98,21,52,39
(-8,3)(-3,-4.5) what is zero of g?
Answer:
the daimeter of the heart of the heart of the heart
I WILL GIVE BRAINILY PLSSSSS HELPLPPP
Which linear function is increasing at a greater
rate? Explain your reasoning.
Linear Function 1 has an x-intercept of (4, 0) and
a y-intercept at (0, 22)
Linear function 2 includes the points in the table
below
Answer:
Linear function 2
Step-by-step explanation:
If Linear function 1 has an x-intercept of 4,0 and a y-intercept of 0,22
It's a negative equation, Its not increasing Its decreasing.
So it must be Linear function 2
Which expression is equivalent to 6 (3x + 4)?
18.1 + 24
183 +4
92 +10
91 +4
Pls hurry
i will privetely give 50 point to anyone who solves this correctly
Ms. White invests
$
2000
in a savings plan. The savings account pays an annual interest rate of
5.75
%
on the amount she puts in at the end of each year. How much will be in her savings plan at the end of
10
years?
Answer:
$3498.11 at the end of 10 years.
Step-by-step explanation:
2000 + 0.0575*2000*10 = 3150 dollars at the end of 10 years.
I need the answer pls answer
Determining the Type of Function
What type of function is represented in the table?
Answer:
quadratic
Step-by-step explanation:
While in flight, some hummingbirds can flap their wings about 500 times in 10 seconds
Is this a true or false?
Answer:
50 times in 1 second
Step-by-step explanation:
I don't know what your specific question, but I'm guessing you wanted divide to see how many times they flap their wings in 1 second. :)
what is 1+1-(3x3)-(1x9)
which is greater? no links pls. 0.04 or -0.39? and -0.6 or 0.5?
Answer:
0.04 and 0.5
Step-by-step explanation:
Answer:
1. 0.04
2. 0.5
Step-by-step explanation:
The positive choice will be greater.
Kaylee bought 2 burritos which cost $2.75 each. She also bought a drink for $3.50. How much money did Kaylee spend?
$19.25
$9
$12.50
$10
Identify the constant of proportionality in the graph.
A) 60
B) 120
C) 180
D) 240
Answer:
A) 60
Step-by-step explanation:
Find two points that intersect with the grid.
(0,0) and (1, 60)
Subtract the second y value from the first y value. Do the same to the X-values.
Write this as a fraction with the y values over the x-values.
60-0= 60
-------------
1 - 0 = 1
60/1 = 60
What is the equation of the graph below? y=1/2sinx y=1/2cosx y=1/2sin2x
9514 1404 393
Answer:
(d) y = 1/2sin(2x)
Step-by-step explanation:
The sin(x) function will have a maximum value of 1 and a period of 360°. The function plotted is a sine function with a maximum value of 1/2 and a period of 180°.
For a function g(x) = a·f(b·x), the vertical scale factor is 'a', and the horizontal compression factor is 'b'. Our sine function has a vertical scale factor of 1/2, and a horizontal compression of 360/180 = 2, so the transformed function is ...
y = 1/2sin(2x)
help with 6grade math
Find the volume of the
triangular prism.
3.2 cm
9 cm
4.8 cm
Answer:
53.76 cm3
Step-By-Step Explanation
PLEASE HELP!
THE QUESTION IS IN THE PHOTO!
For What value of x is ABC~DEF?
Answer:
x=12
Step-by-step explanation:
Since the triangles are congruent, you can use either B or D to solve for x.
7x+10=94
7x=94-10
7x=84
x=84÷7
x=12
The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer service on which airlines compete is on-time arrival. The tables below contain a sample of data from delayed flights showing the number of minutes each delayed flight was late for two different airlines, Company A and Company B.
Company A
34 59 43 30 3
32 42 85 30 48
110 50 10 26 70
52 83 78 27 70
27 90 38 52 76
Company B
46 63 43 33 65
104 45 27 39 84
75 44 34 51 63
42 34 34 65 64
(a) Formulate the hypotheses that can be used to test for a difference between the population mean minutes late for delayed flights by these two airlines. (Let μ1 = population mean minutes late for delayed Company A flights and μ2 = population mean minutes late for delayed Company B flights.)
A)H0: μ1 − μ2 = 0
Ha: μ1 − μ2 ≠ 0
B) H0: μ1 − μ2 ≤ 0
Ha: μ1 − μ2 > 0
C)H0: μ1 − μ2 < 0
Ha: μ1 − μ2 = 0
D) H0: μ1 − μ2 ≠ 0
Ha: μ1 − μ2 = 0
E) H0: μ1 − μ2 ≥ 0
Ha: μ1 − μ2 < 0
(b) What is the sample mean number of minutes late for delayed flights for each of these two airlines?
Company A______ min.
Company B______ min.
(c) Calculate the test statistic. (Round your answer to three decimal places.)
test statistic=
What is the p-value? (Round your answer to four decimal places.)
p-value =
Using a 0.05 level of significance, what is your conclusion?
A) Reject H0. There is statistical evidence that one airline does better than the other in terms of their population mean delay time
B) Do not Reject H0. There is statistical evidence that one airline does better than the other in
terms of their population mean delay time.
C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.
D) Reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.
Answer:
A)H0: μ1 − μ2 = 0
Ha: μ1 − μ2 ≠ 0
(b) Means
Company A___50.6___ min.
Company B___52.75___ min.
c)The t-value is -0.30107.
The p-value is 0 .764815.
C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.
Step-by-step explanation:
A)H0: μ1 − μ2 = 0
i.e there is no difference between the means of delayed flight for two different airlines
Ha: μ1 − μ2 ≠ 0
i.e there is a difference between the means of delayed flight for two different airlines
(b)
Company A___50.6___ min.
Company B___52.75___ min.
Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25
= 1265/25= 50.6
Mean of Company B = x`2= ∑x/n =
=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20
= 1055/20= 52.75
Difference Scores Calculations
Company A
Sample size for Company A= n1= 25
Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24
Mean for Company A= x`1= 50.6
Total Squared Difference (x-x`1) for Company A= SS1: 16938
s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75
Company B
Sample size for Company B= n1= 20
Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19
Mean for Company B= x`2= 52.75
Total Squared Difference (x-x`2) for Company B= SS2=7427.75
s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93
T-value Calculation
Pooled Variance= Sp²
Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)
Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65
s2x`1 = s2p/n1 = 566.65/25 = 22.67
s2x`2 = s2p/n2 = 566.65/20 = 28.33
t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3
The t-value is -0.30107.
The total degrees of freedom is = n1+n2- 2= 25+20-2=43
The critical region for two tailed test at significance level ∝ =0.05 is
t(0.025) (43) = t > ±2.017
Since the calculated value of t= -0.30107. does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.
The p-value is 0 .764815. The result is not significant at p < 0.05.
In this exercise, it is necessary to use the knowledge given by the airlines and the flights, having as a solution:
a)[tex]H_0: \mu_1 -\mu_2 = 0\\H_a:\mu_1 -\mu_2\neq 0[/tex]
b) Means: Company A 50.6 min.
Company B 52.75 min.
c)The t-value is -0.30107.
The p-value is 0 .764815.
C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.
A)[tex]H_0: \mu_1 -\mu_2 = 0[/tex]
There is no difference between the means of delayed flight for two different airlines:
[tex]H_a:\mu_1 -\mu_2\neq 0[/tex]
There is a difference between the means of delayed flight for two different airlines.
(b) Mean of Company A[tex]= x_1= \sum{x/n} = 1265/25= 50.6[/tex]
Mean of Company B [tex]= x_2= \sum{x/n} =1055/20= 52.75[/tex]
C) Difference Scores Calculations:
Company A:
Sample size for Company [tex]A= n1= 25[/tex]
Degrees of freedom for company [tex]A= df1 = n1 - 1 = 25 - 1 = 24[/tex]
Mean for Company [tex]A= x_1= 50.6[/tex]
Total Squared Difference for Company [tex]A= SS1: 16938\\s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75[/tex]
Company B:
Sample size for Company [tex]B= n1= 20[/tex]
Degrees of freedom for company [tex]B= df2 = n2 - 1 = 20 - 1 = 19[/tex]
Mean for Company[tex]B= x_2= 52.75[/tex]
Total Squared Difference for Company [tex]B= SS2=7427.75\\s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93[/tex]
T-value Calculation
Pooled Variance= Sp²
[tex]Sp^2= ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)\\Sp^2= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65\\s2x_1 = s2p/n1 = 566.65/25 = 22.67\\s2x_2 = s2p/n2 = 566.65/20 = 28.33\\t = (x_1 - x_2)/\sqrt{s2x_1 + s2x_2} = -2.15/\sqrt{51} = -0.3[/tex]
The t-value is -0.30107.
The total degrees of freedom is [tex]= n1+n2- 2= 25+20-2=43[/tex]
The critical region for two tailed test at significance level ∝ =0.05 is [tex]t(0.025) (43) = t > 2.017[/tex]
Since the calculated value of t= -0.30107. does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.
The p-value is 0 .764815. The result is not significant at p < 0.05.
Learn more: brainly.com/question/14356533
Each girl on a cheerleading squad bought a bear. The leader paid for their cheerleading outfits for each of them. She spent $175. Write and solve an equation to find how many cheerleading outfits, c, the leader bought. Cheerleading outfit cost- $12.50
Answer:
175 ÷ 12.50 = 14
Step-by-step explanation:
1/6 + 2/3 + 36 (help plz)
A circle has a diameter of 8.2 m. What is the area of a sector with a 125 degree
arc? Round your answer to the nearest tenth. *
Answer:24.2 m
Step-by-step explanation: yea u gotta use the metric system
One radius of a circle is the same length as any other radius of the same
circle.
A. True
B. False
A. True
In a circle, all radii have the same length. The radius is the distance from the center of the circle to any point on its circumference. Since the center is equidistant from all points on the circumference, all radii will have the same length. Therefore, the statement is true.
which area 100 km or 60km
Answer:
100km
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
find the alternative interior angles in each figure
Answer:
Step-by-step explanation:
An auto assemply worker requires 4 electrical fuses for each vehicle. The supplier of the fuses has informed the plant manager that 5% of all the fuses they produce are defective. Assume that the assembly worker selects the 4 fuses for any vehicle at random and independently of each other. If 2 assembled vehicles are selected at random and independently of one another, what is the probability that both vehicles will have all defective fuses
Answer:
[tex]3.9 \times 10^{-11}[/tex] probability that both vehicles will have all defective fuses
Step-by-step explanation:
For each fuse, there are only two possible outcomes. Either they are defective, or they are not. The probability of a fuse being defective is independent of any other fuse. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Probability of a vehicle having all defective fuses:
5% of fuses are defective, which means that [tex]p = 0.05[/tex]
A vehicle has 4 fuses, which means that [tex]n = 4[/tex].
This probability is P(X = 4). So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 4) = C_{4,4}.(0.05)^{4}.(0.95)^{0} = 0.00000625[/tex]
If 2 assembled vehicles are selected at random and independently of one another, what is the probability that both vehicles will have all defective fuses?
For each vehicle, 0.00000625 probability of having all defective fuses. For 2:
[tex](0.00000625)^2 = 3.9 \times 10^{-11}[/tex]
[tex]3.9 \times 10^{-11}[/tex] probability that both vehicles will have all defective fuses