A. Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 1; B: the numbers add to 4; C: at least one of the numbers is 1; and D: the numbers do not add to 10. Express the given event in symbols.
The red die shows 1 and the numbers add to 4.
How many elements does it contain?
B. Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 3; B: the numbers add to 2; C: at least one of the numbers is 1; and D: the numbers do not add to 10. Express the given event in symbols. HINT [See Example 5.]
The numbers do not add to 2.
How many elements does it contain?
C. Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 1; B: the numbers add to 2; C: at least one of the numbers is 3; and D: the numbers do not add to 11. Express the given event in symbols. HINT [See Example 5.]
Either the numbers add to 11 or the red die shows a 1.
How many elements does it contain?
D. Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 4; B: the numbers add to 5; C: at least one of the numbers is 1; and D: the numbers do not add to 9. Express the given event in symbols. HINT [See Example 5.]
Either the numbers add to 5, or they add to 9, or at least one of them is 1.
How many elements does it contain?

Answers

Answer 1

Answer:

1. elements it contains =  (1,3)

2.  elements it contains = 35

3.  elements it contains = 8

4.  elements it contains = 17

Step-by-step explanation:

A. Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 1; B: the numbers add to 4; C: at least one of the numbers is 1; and D: the numbers do not add to 10. Express the given event in symbols.

The red die shows 1 and the numbers add to 4.

How many elements does it contain?

B. Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 3; B: the numbers add to 2; C: at least one of the numbers is 1; and D: the numbers do not add to 10. Express the given event in symbols. HINT [See Example 5.]

The numbers do not add to 2.

How many elements does it contain?

C. Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 1; B: the numbers add to 2; C: at least one of the numbers is 3; and D: the numbers do not add to 11. Express the given event in symbols. HINT [See Example 5.]

Either the numbers add to 11 or the red die shows a 1.

How many elements does it contain?

D. Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 4; B: the numbers add to 5; C: at least one of the numbers is 1; and D: the numbers do not add to 9. Express the given event in symbols. HINT [See Example 5.]

Either the numbers add to 5, or they add to 9, or at least one of them is 1.

How many elements does it contain?

NB. Attached is the solution to the problems stated above

A. Suppose Two Dice (one Red, One Green) Are Rolled. Consider The Following Events. A: The Red Die Shows
A. Suppose Two Dice (one Red, One Green) Are Rolled. Consider The Following Events. A: The Red Die Shows
A. Suppose Two Dice (one Red, One Green) Are Rolled. Consider The Following Events. A: The Red Die Shows
A. Suppose Two Dice (one Red, One Green) Are Rolled. Consider The Following Events. A: The Red Die Shows

Related Questions

how many 50 cents coins are there in $10:50​

Answers

Question:- how many 50 cents coins are there in $10.50

Answer:-

Total amount-> $ 10.50

So amount in cents

$ 1 is equal to 100 cents

$10.50 is equal to 1050 cents

According to the question

[tex]Number \: of \: the \: 50 \: cents= \frac{ Total \: cents}{ 50 \: cents } \\ [/tex]

[tex]Number \: of \: the \: 50 \: cents = \frac{1050}{50} \\ Number \: of \: the \: 50 \: cents = 21 \: [/tex]

compare the following rational number
[tex] \frac{4}{5} and \frac{7}{5} [/tex]

Answers

Answer:

7/5 is greater than 4/5

Answer:

[tex]\frac{4}{5}[/tex]  <  [tex]\frac{7}{5}[/tex]

if 2x-y=2, what is the value of 9^x/3^y?

1) 3
2) 9
3) 27
4) 81

Answers

Answer: 9

Work Shown:

(9^x)/(3^y)

( (3^2)^x )/(3^y)

( 3^(2x) )/( 3^y )

3^(2x-y)

3^2 .... use the equation 2x-y = 2

9

I think the answer to this question is 9

Suppose that the credit remaining on a phone card (in dollars) is a linear function of the total calling time (in minutes). When graphed, the function gives a line with a slope of -0.12. See the figure below. There is $28.96 in credit remaining on the card after minutes of calls. How much credit was there after 21 minutes of calls?

Answers

Answer:

Credit remaining after 21 minutes = $30.4

Step-by-step explanation:

Credit remaining on a phone card is a linear function of the total calling time.

When graphed, let the linear function representing the line is,

y = mx + b

Where 'm' = slope of the line

b = y-intercept

From the graph,

Slope of the line = -0.12

y = -0.12x + b

If this line passes through a point (33, 28.96),

28.96 = -0.12(33) + b

b = 28.96 + 3.96

b = 32.92

Therefore, the linear function is,

f(x) = -0.12x + 32.92

where x = calling time

Credit left in the card after 21 minutes,

f(21) = -0.12(21) + 32.92

      = -2.52 + 32.92

      = $30.4

During April of 2013, Gallup randomly surveyed 500 adults in the US, and 47% said that they were happy, and without a lot of stress." Calculate and interpret a 95% confidence interval for the proportion of U.S. adults who considered themselves happy at that time. 1 How many successes and failures are there in the sample? Are the criteria for approximate normality satisfied for a confidence interval?
A What is the sample proportion?
B compute the margin of error for a 95% confidence interval.
C Interpret the margin of error you calculated in Question 1
C. Give the lower and upper limits of the 95% confidence interval for the population proportion (p), of U.S. adults who considered themselves happy in April, 2013.
D Give an interpretation of this interval.
E. Based on this interval, is it reasonably likely that a majority of U.S. adults were happy at that time?
H If someone claimed that only about 1/3 of U.S. adults were happy, would our result support this?

Answers

Answer:

number of successes

                 [tex]k = 235[/tex]

number of failure

                 [tex]y = 265[/tex]

The   criteria are met    

A

    The sample proportion is  [tex]\r p = 0.47[/tex]

B

    [tex]E =4.4 \%[/tex]

C

What this mean is that for N number of times the survey is carried out that the which sample proportion obtain will differ from  the true population proportion will not  more than 4.4%

Ci  

   [tex]r = 0.514 = 51.4 \%[/tex]

 [tex]v = 0.426 = 42.6 \%[/tex]

D

   This 95% confidence interval  mean that the the chance of the true    population proportion of those that are happy to be exist within the upper   and the lower limit  is  95%

E

  Given that 50% of the population proportion  lie with the 95% confidence interval  the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

F

 Yes our result would support the claim because

            [tex]\frac{1}{3 } \ of N < \frac{1}{2} (50\%) \ of \ N , \ Where\ N \ is \ the \ population\ size[/tex]

Step-by-step explanation:

From the question we are told that

     The sample size is  [tex]n = 500[/tex]

     The sample proportion is  [tex]\r p = 0.47[/tex]

 

Generally the number of successes is mathematical represented as

             [tex]k = n * \r p[/tex]

substituting values

             [tex]k = 500 * 0.47[/tex]

            [tex]k = 235[/tex]

Generally the number of failure  is mathematical represented as

           [tex]y = n * (1 -\r p )[/tex]

substituting values

           [tex]y = 500 * (1 - 0.47 )[/tex]

           [tex]y = 265[/tex]

for approximate normality for a confidence interval  criteria to be satisfied

          [tex]np > 5 \ and \ n(1- p ) \ >5[/tex]

Given that the above is true for this survey then we can say that the criteria are met

  Given that the confidence level is  95%  then the level of confidence is mathematically evaluated as

                       [tex]\alpha = 100 - 95[/tex]

                        [tex]\alpha = 5 \%[/tex]

                        [tex]\alpha =0.05[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table, the value is

                 [tex]Z_{\frac{ \alpha }{2} } = 1.96[/tex]

Generally the margin of error is mathematically represented as  

                [tex]E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{\r p (1- \r p}{n} }[/tex]

substituting values

                 [tex]E = 1.96 * \sqrt{ \frac{0.47 (1- 0.47}{500} }[/tex]

                 [tex]E = 0.044[/tex]

=>               [tex]E =4.4 \%[/tex]

What this mean is that for N number of times the survey is carried out that the proportion obtain will differ from  the true population proportion of those that are happy by more than 4.4%

The 95% confidence interval is mathematically represented as

          [tex]\r p - E < p < \r p + E[/tex]

substituting values

        [tex]0.47 - 0.044 < p < 0.47 + 0.044[/tex]

         [tex]0.426 < p < 0.514[/tex]

The upper limit of the 95% confidence interval is  [tex]r = 0.514 = 51.4 \%[/tex]

The lower limit of the   95% confidence interval is  [tex]v = 0.426 = 42.6 \%[/tex]

This 95% confidence interval  mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit  is  95%

Given that 50% of the population proportion  lie with the 95% confidence interval  the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

Yes our result would support the claim because

            [tex]\frac{1}{3 } < \frac{1}{2} (50\%)[/tex]

 

A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results. Social Activity Education Above Average Average Below Average College 30 20 10 High School 20 40 90 Grade School 10 50 130 Using 0.05 as the significance level, what is the critical value for the test statistic

Answers

Answer:

9.488

Step-by-step explanation:

The critical value is found by first assessing which statistical test should be used.

We are interested in investigating relationship between social activity and education so chi-square test would be appropriate.

We have 3 rows and 3 columns. The degree of freedom for chi-square critical value is (r-1)(c-1)=(3-1)(3-1)=2*2=4

Chi-square critical value(0.05,4)= 9.488

Please help me on question a
I would really appreciate it

Answers

Answer:

[tex]x = 3.6[/tex]

Step-by-step explanation:

To find the area of a rectangle, you multiply its length by its width. The formula is [tex]lw = a[/tex].

We already know the length, 5, and the area, 18, so we can plug it into the equation.

[tex]5\cdot w=18[/tex]

We can simplify this equation by dividing both sides by 5.

[tex]5\cdot w \div5 = 18\div5\\\\w = 3.6[/tex]

Hope this helped!

Answer: x= 13

Step-by-step explanation:

Using Eulers formula, how many edges does a polyhedron with 9 faces and 14 vertices have?

Answers

By Euler's Formula

F + V = E + 2

Solution

F = 9

V = 14

E = ?

Substuting the values

⇨ 9 + 14 = E + 2

⇨ 23 = E + 2

⇨ 23 - 2 = E

⇨ 21 = E

Hence , the number of edges in polyhedron is 21.

The number of edges of a polyhedron with 9 faces and 14 vertices have will be 21.

What is a polygon?

The polygon is a 2D geometry that has a finite number of sides. And all the sides of the polygon are straight lines connected to each other side by side.

here, we have,

Using Euler's formula, the number of the edges does a polyhedron with 9 faces and 14 vertices have

We know the formula for the edges of the polyhedron will be

By Euler's Formula

F + V = E + 2

The number of faces, vertices, and edges of a polyhedron are denoted by the letters F, V, and E.

Then we have

Solution

F = 9

V = 14

E = ?

Substuting the values

⇨ 9 + 14 = E + 2

⇨ 23 = E + 2

⇨ 23 - 2 = E

⇨ 21 = E

Hence , the number of edges in polyhedron is 21.

More about the polygon link is given below.

brainly.com/question/17756657

#SPJ2

HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

9514 1404 393

Answer:

  D. 72 heads in 100 flips

Step-by-step explanation:

A probability calculator will tell you the probabilities of the given outcome with a fair coin are ...

  A: 0.0625

  B: 0.04395

  C: 0.15498

  D: 3.9×10^-6

__

It is "improbable" that a fair coin will give 72 heads in 100 flips. So, it is reasonable to assume the coin is not fair if that is the result.

Point R divides PG in the ratio 1:3. If the x-coordinate of R is -1 and the x-coordinate of P is -3, what is the x-coordinate of Q

Answers

Answer:

option C . 5

Step-by-step explanation:

For two points (x1,y1) and (x2,y2) divided by a point p in ratio m:n then coordinates of that point is given by

p    :  (nx1+mx2)/(m+n),  (ny1+my2)/(m+n),  

Given

x coordinate of P (-3)

x  coordinate of Q (a) since we have to find it , let it be a

x coordinate of R(-1)\

ratio = 1:3

_______________________________________

Using the above formula to find the point of division

we can get value of x coordinate for point Q

x  coordinate of R = 3*-3 + 1*a/(1+3)

-1 = (-9 + a)/4

=> -4 = -9 +a

=>a = -4+9 = 5

Thus, x  coordinate of Q is 5

Gail bought 5 pounds of oranges and 2 pounds of bananas for $14. Her husband later bought 3 pounds of oranges and 6 pounds of bananas for $18. What was the cost per pound of the oranges and the bananas?

Answers

Answer:

1 pound of Oranges = $2

1 pound of Bananas = $2

Step-by-step explanation:

O = Oranges

B = Bananas

=> 5o + 2b = 14

=> 2b = 14 - 5o

=> b = 14/2 - 5/2o

=> b = 7 - 2.5o

3o + 6b = 18

=> 3o + 6( 7 - 2.5o ) = 18

=> 3o + 42 - 15o = 18

=> -12o + 42 = 18

=> -12o = -24

=> -o = -2

=> o = 2

One pound of oranges costs $2.

So,

5 (2) + 2b = 14

=> 10 + 2b = 14

=> 2b =4

=> b = 2

One pound of bananas also costs $2.

Answer: cost of orange per pound = 2$
Cost of banana per pound = 2$

Explanation:

line and passes through C -2,0 in the 1, -3) Quetion of the line in standard form

Answers

Answer:

[tex]\huge\boxed{x+y=-2}[/tex]

Step-by-step explanation:

The standard form of an equation of a line:

[tex]Ax+By=C[/tex]

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

where

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have two points (-2, 0) and (1, -3).

Substitute:

[tex]x_1=-2;\ y_1=0;\ x_2=1;\ y_2=-3[/tex]

[tex]m=\dfrac{-3-0}{1-(-2)}=\dfrac{-3}{1+2}=\dfrac{-3}{3}=-1\\\\y-0=-1(x-(-2))\\\\y=-(x+2)[/tex]

[tex]y=-x-2[/tex]         add x to both sides

[tex]x+y=-2[/tex]

Jane and her two friends will rent an apartment for S550 a month, but Jane will pay double what each friend does because she will have her own bedroom.
How much will Jane pay a month?

Answers

Answer:

$275 a month

Step-by-step explanation:

Let x represent how much each friend is paying.

The amount Jane pays can be represented by 2x, since she is paying double than her friends.

Add together these terms and set them equal to 550. Then, solve for x:

x + x + 2x = 550

4x = 550

x = 137.5

So, each friend is paying $137.50. Double this to find how much Jane is paying:

137.5(2)

= 275

So, Jane is paying $275 a month

Will mark the brainliest i havent chosen an answer but I pressed accidentally

Answers

The full answer is 20.125 but it says to round so the answer is C. 20.13

Answer:

The full answer is 4.40625 but rounded it would be 4.41

Factor.
x2 – 5x - 36

(x - 9)(x + 4)
(x - 12)(x + 3)
(x + 9)(x - 4)
(x + 12)(x - 3)

Answers

Answer:

The answer is option A

Step-by-step explanation:

x² - 5x - 36

To factor the expression rewrite -5x as a difference

That's

x² + 4x - 9x - 36

Factor out x from the expression

x( x + 4) - 9x - 36

Factor out -9 from the expression

x( x + 4) - 9( x+ 4)

Factor out x + 4 from the expression

The final answer is

( x - 9)( x + 4)

Hope this helps you

Answer:

[tex] \boxed{(x - 9) \: (x + 4) }[/tex]

Option A is the correct option.-

Step-by-step explanation:

( See the attached picture )

Hope I helped!

Best regards!

Give examples of two variables that have a perfect positive linear correlation and two variables that have a perfect negative linear correlation.

Answers

Answer:

answer below

Step-by-step explanation:

1. price per gallon of gasoline and total cost of gasoline

2. distance from a door and height of a wheelchair ramp

perfect positive linear relationship:

this is a relation that exists between two variables. The pearson correlation is used to check this relationship and if the relationship is 1.0 then it is established that a positive linear relationship exists

negative linear relationship

this is a relationship between variables where the pearson correlation is less than 0. if the value is -1.0 then a negative linear relatioship exists.

price per gallon of gasoline and total cost of gasoline move in the same direction so it is positive.

distance from a door and height of a wheelchair ramp are negative because they do not move in the same direction.

2000 2yrs at 2% How much interest is owed

Answers

Answer:

Rs. 80 is owed.

Step-by-step explanation:

Principle (P) = 2000

Time (T) = 2 years

Rate (R) = 2%

Interest (I) = ?

Here,

I = (P×T×R) / 100

= (2000×2×2) / 100

= (8000) / 100

= Rs. 80

Answer:

P= 2000

T= 2

R=2÷100

I = PTR

= 2000×2×2÷100

2÷100=0.02

2000×2×0.02= 80

So i is 80

Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.028; confidence level: 99%; p and q unknown

Answers

Answer:

The minimum sample size is [tex]n = 2123[/tex]

Step-by-step explanation:

From the question we are told that

    The margin of error is  [tex]E = 0.028[/tex]

   

Given that the confidence level is  99% then the level of significance is evaluated as

        [tex]\alpha = 100 - 99[/tex]

        [tex]\alpha = 1 \%[/tex]

        [tex]\alpha =0.01[/tex]

Next we obtain the critical value of  [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table

   The  value is  [tex]Z_{\frac{ \alpha }{2} } = 2.58[/tex]

Now let  assume that the sample proportion is  [tex]\r p = 0.5[/tex]

  hence  [tex]\r q = 1 - \r p[/tex]

=>            [tex]\r q = 0.50[/tex]

   Generally the sample size is mathematically represented as

                [tex]n =[ \frac{Z_{\frac{ \alpha }{2} }}{ E} ]^2 * \r p * \r q[/tex]

                [tex]n =[ \frac{2.58}{ 0.028} ]^2 * 0.5 * 0.5[/tex]

              [tex]n = 2123[/tex]

The height of an object dropped from the top of a 144-foot building is given by ℎ(. How long will it take the object to hit the ground?)=―162+144

Answers

Answer:

Step-by-step explanation: h(t) = -16t2 + 144

h(1) = -16(12) + 144 = 128 ft

h(2) = -16(22) + 144 = 80 ft

h(2) - h(1) = 80 - 128 = -48 ft

It fell 48 ft between t = 1 and t = 2 seconds.

It reaches the ground when h(t) = 0

0 = -16t2 + 144

t = √(144/16) s = 3s

It reaches the ground 3s after being dropped.

34 Proportions
Mathematics, Pre-Algebra
Question 2
A boat can travel 21 miles on 7 gallons of gasoline. How far can it travel on 17 gallons?

Answers

Answer:

51 miles

Step-by-step explanation:

hope it's clear and understandable

:)

7. The General Society Survey asked a sample of 1200 people how much time they spent watching TV each day. The mean number of hours was 3.0 with a standard deviation of 2.87. A sociologist claims that people watch a mean of 4 hours of TV per day. Do the data provide sufficient evidence to disprove the claim? Use α = .05 to test the hypothesis. a. What are your null and alternative hypotheses? b. What test is appropriate here? Why? c. What is your test statistic? d. What is your critical value? e. What is your final decision: do you reject the null or fail to reject the null?

Answers

Answer:

a) and b)  Look step by step explanation

c) z(s) = - 12,07

d) z(c) = - 1,64

e) Final decision: Reject H₀

Step-by-step explanation:

We assume Normal Distribution

Data:

Sample population  n   = 1200

Sample mean         μ  =    3

Sample Standard deviation   2,87

Claim mean      μ₀  =  4

α = 0,05  then from z-table we find  z(c) = 1,64   ( critical value )

We need to develop a one tail-test to the left

Test Hypothesis

The General Society developed a survey ( in all cases that is an indication of a sample)

Null hypothesis                    H₀                      μ   =  μ₀

Alternative hypothesis        Hₐ                       μ  <  μ₀

To calculate the  z(s)

z(s) =  ( μ  -  μ₀ )/ 2,87/√n

z(s) =  ( 3 - 4 )/ 2,87/√1200

z(s) =   -1 * 34,64 / 2,87

z(s) = - 12,07

To compare  z(s) and z(c)

z(s)  <  z(c)           - 12,07 < - 1,64

z(s) is in the rejection region (quite far away) we reject H₀

Data provide enough evidence to disprove the claim

Solve this inequality: x+ 4< 16

Answers

Answer:

x < 12

Step-by-step explanation:

subtract 4 from both sides:

x + 4 < 16

   - 4     -4

x < 12

Answer:

x<4

Step-by-step explanation:

x+4 <16

x < 16

4

x<4

I hope this will help you

Which set of values could be the side lengths of a 30-60-90 triangle?
O A. {6,613, 12)
O B. {6, 12, 12.3}
O C. {6,6.12, 12}
O D. {6, 12, 12/3)​

Answers

Answer:

I think :

c is 30 triangle

b is 60 triangle

d is 90 triangle

5/\sqrt{x} +1+4/\sqrt{x} -1-8\sqrt{x}/x-1

Answers

Answer:

535525-62635-$6#62626636$66$6$63663636$6$62

brainly is dustbin

Find the missing side or angle.
Round to the nearest tenth.

Answers

Cosine law
a^2 = b^2 + c^2 - 2(b)(c)cosA
a^2 = 2^2 + 4^2 - 2(2)(4)cos78
a = 4.08
a = 4.1

Answer:

a = 4.1

Step-by-step explanation:

To find the missing side in the question, we use the cosine rule

That's

Since we are finding a we use the formula

a² = b² + c² - 2(b)(c) cos A

From the question

b = 2

c = 4

A = 78°

Substitute the values into the above formula

We have

a² = 2² + 4² - 2(2)(4) cos 78

a² = 4 + 16 - 16 cos 78

a² = 20 - 16cos 78

a² = 16.67341

Find the square root of both sides

a = 4.0833

We have the final answer as

a = 4.1 to the nearest tenth

Hope this helps you

AB||CD. Find the measure of

Answers

Answer:

135 degrees

Step-by-step explanation:

3x+15 = 5x - 5 because of the alternate interior angles theorem.

20 = 2x

x = 10

3(10) + 15 = 30+15 = 45

Remember that a line has a measure of 180 degrees. So we can just subtract the angle we found from 180 degrees to get BFG.

180-45 = 135.

Find the value of the expression: −mb −m^2 for m=3.48 and b=96.52

Answers

Answer:

The value of the expression when [tex]m = 3.48[/tex] and [tex]b = 96.52[/tex] is 323.779.

Step-by-step explanation:

Let be [tex]f(m, b) = m\cdot b - m^{2}[/tex], if [tex]m = 3.48[/tex] and [tex]b = 96.52[/tex], the value of the expression:

[tex]f(3.48,96.52) = (3.48)\cdot (96.52)-3.48^{2}[/tex]

[tex]f(3.48,96.52) = 323.779[/tex]

The value of the expression when [tex]m = 3.48[/tex] and [tex]b = 96.52[/tex] is 323.779.

In the figure below.. Please help!!!

Answers

Answer: 10.5 units

====================================================

Explanation:

Both AB and XY are the first two letters of ABC and XYZ respectively. So we have one fraction of AB/XY = 2/7.

AC and XZ are the first and last letters of ABC and XYZ respectively. We can form another fraction AC/XZ. I'm dividing in the same order of small over large to keep things consistent. As you can probably guess, the order of the letters ABC and XYZ are important so we see how the angles match up and how the proportional sides match up.

Because the triangles are similar, the two fractions formed earlier are equal to one another.

The equation we need to solve is AB/XY = AC/XZ

-----

AB/XY = AC/XZ

2/7 = 3/N ... plug in given values

2N = 7*3 .... cross multiply

2N = 21

N = 21/2 .... divide both sides by 2

N = 10.5

ZX is 10.5 units long.

How many prime numbers are there between 1 to 100? a) 17 b) 25 c) 32 d) None of these

Answers

Answer:

b)25

Step-by-step explanation:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97

Find the interquartile range of the data in the dot plot below. players blob:mo-extension://5f64da0e-f444-4fa8-b754-95

Answers

Answer:

[tex]IQR=Q_{3}-Q_{1}[/tex]

Step-by-step explanation:

The inter-quartile range is a measure of dispersion of a data set.

It is the difference between the third and the first quartile.

[tex]IQR=Q_{3}-Q_{1}[/tex]

The 1st quartile (Q₁) is well defined as the mid-value amid the minimum figure and the median of the data set. The 2nd quartile (Q₂) is the median of the data. The 3rd quartile (Q₃) is the mid-value amid the median and the maximum figure of the data set.

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