Answer:
Explanation:
Measurement made = 100.2 °C
uncertainty = 0.1°C
percent uncertainty = .1 x 100 / 100.2
= .099 %
2 nd thermometer :
Measurement made = 99.0 °C
uncertainty = 0.5°C
percent uncertainty = .5 x 100 / 99
= .505 %
Percent error :
1 st thermometer
Error = 100.2 - 100 = .2 °C
measurement = 100.2
percent error = .2 x 100 / 100.2
= .1996 %
2 nd thermometer
Error = 100.00 - 99 = 1.00 °C
measurement = 99
percent error = 1 x 100 / 99
= 1.01 %
The percent error of digital thermometer is 0.1996 %. The percent error of analog thermometer is 1.01 %.
Percent uncertainty is the measure of degree of error region with the uncertainty in the measurement.
The percentage error is the difference in the measurement of the values with actual value.
Computation for percent uncertainty and percent errorThe percent uncertainty (%U) is calculated by:
[tex]\% U=\rm \dfrac{Uncertainty}{Measurement}\;\times\;100[/tex]
The percent error (%E) is calculated by:
[tex]\%E=\rm \dfrac{error\;value-actual\;value}{error\;value}\;\times\;100[/tex]
The percent uncertainty and error for digital thermometer is given as:The Recorded temperature = 100.2 degree Celsius
The actual temperature = 100 degrees Celsius
The uncertainty in the readings is 0.1 degree Celsius
The percent uncertainty is given by:
[tex]\%U=\dfrac{0.1}{100.2}\;\times\;100\\\\ \%U=0.099\;\%[/tex]
The percent uncertainty of digital thermometer is 0.099 %.
The percent error is given by:
[tex]\% E=\dfrac{100.2-100}{100.2}\;\times\;100 \\\\\% E=\dfrac{0.2}{100.2}\;\times\;100\\\\ \% E=0.1996\;\%[/tex]
The percent error of digital thermometer is 0.1996 %.
The percent uncertainty and error for analog thermometer is given as:The Recorded temperature = 99 degree Celsius
The actual temperature = 100 degrees Celsius
The uncertainty in the readings is 0.5 degree Celsius
The percent uncertainty is given by:
[tex]\%U=\dfrac{0.5}{99}\;\times\;100\\\\ \%U=0.505\;\%[/tex]
The percent uncertainty of analog thermometer is 0.505%.
The percent error is given by:
[tex]\% E=\dfrac{100-99}{99}\;\times\;100 \\\\\% E=\dfrac{1}{99}\;\times\;100\\\\ \% E=1.01\;\%[/tex]
The percent error of analog thermometer is 1.01 %.
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At the end of the reaction, an aqueous solution of sodium bisulfite is added to the reaction mixture. The sodium bisulfite destroys the remaining bromine. Also, the fact that the sodium bisulfite is in water helps to further separate the reaction solvent from the product because the solvent is very soluble in water. What is the most important intermolecular force that allows the solvent to dissolve in wate?
Answer:
Polarity.
Explanation:
The most important intermolecular force to allow a solvent to dissolve in water is polarity. This is because water is a polar substance and there is a chemical law that states that there is only solubility between substances of equal polarity. Thus, water is only able to dissolve a polar substance, just like it. In this case, we can say that the equal polarity between the two solvents is the most important for one to be able to dissolve the other.
Change of a liquid to a solid
Read the list of common household substances.
Yogurt, soaps, window cleaner, vinegar
Which of these substances are likely to have a slippery feel? (1 point)
Yogurt, soaps
Yogurt, vinegar
Soaps, window cleaner
Window cleaner, vinegar
Answer:
A
Explanation:
How are the smallest ocean waves produced?
Answer:
The moon is not pulling the tide as hard
Explanation:
I suppose, I know it dills with the moon though
Explanation:
Normalmente, las olas se forman por el viento aunque su historia comienza muy lejos, en el Sol. ... Cuando el viento sopla sobre el mar, las partículas de aire rozan a las partículas de agua y se empiezan a formar pequeñas olas de pocos milímetros de longitud, llamadas ondas capilares.
Normally, waves are formed by the wind, although their history begins very far away, in the Sun. ... When the wind blows over the sea, the air particles brush against the water particles and small waves of few millimeters in length, called capillary waves.
Which of the following involves a reaction in which energy is absorbed?
O A. An instant cold pack
O B. A car's engine
C. A chemical hand-warmer
O D. A campfire
The formation of tert-butanol is described by the following chemical equation: Suppose a two-step mechanism is proposed for this reaction, beginning with this elementary reaction: Suppose also that the second step of the mechanism should be bimolecular. Suggest a reasonable second step. That is, write the balanced chemical equation of a bimolecular elementary reaction that would complete the proposed mechanism.
Answer:
(CH3)3C^+ + OH^- --------> (CH3)3COH
Explanation:
This reaction has to do with SN1 reaction of alkyl halides. Here tert-butanol is formed from tert-butyl bromide.
The first step in the reaction is the formation of a carbocation. This is a unimolecular reaction. The rate of reaction depends on the concentration of the alkyl halide. This is a slow step and thus the rate determining step in the mechanism.
(CH3)3CBr -------> (CH3)3C^+ + Br^-
The second step is a fast step and it completes the reaction mechanism. It is a bimolecular reaction as follows;
(CH3)3C^+ + OH^- --------> (CH3)3COH
How many molecules in 4.10 mol H2O?
6.02×10^23
1.4×10^23
2.47×10^24
1.15×10^-23
Answer:
2,47 * [tex]10^{24}[/tex] (molecules)
Explanation:
Avogadro's number is a very important relationship: 1 mole = 6,02 * [tex]10^{23}[/tex] atoms, molecules, protons, etc.
To convert from moles to molecules, multiply the molar amount by Avogadro's number.
4,1 mol * 6,02 * [tex]10^{23}[/tex] ≈ 24,7 * [tex]10^{23}[/tex] = 2,47 * [tex]10^{24}[/tex] (molecules)
Therefore the third answer is correct
A
regulation
NBA
basketball
has
a
surface
area
of 283 square inches
.
What
is
the
surface
area
of
this
basketball
in Square Centimeters
?
Answer:
1.83 × 10³ cm²
Explanation:
Step 1: Given data
Surface area of a NBA basketball (A): 283 in²
Step 2: Convert "A" from square inches to square centimeters
In order to convert "A" from in² to cm², we need a conversion factor. In this case, we will use the conversion factor 1 in = 2.54 cm. Since "in" is raised to the power of 2, we will have to raise the conversion factor to the power of 2 as well.
283 in² × (2.54cm/1 in)² = 1.83 × 10³ cm²
Based on this reaction, how many moles of H2 can be obtained starting with 3 mol CH4?
Answer:
9 moles of H₂ are produced
Explanation:
Note: The question is incomplete. the complete question and the given image is found below:
The diagram represents a high-temperature reaction between CH4 and H2O. Based on this reaction, how many moles of H2 can be obtained starting with 3 mol CH4?
From the attachment, the equation of the reaction can be written as:
2CH₄ + 2H₂O ----> 2CO + 6H₂
From the equation the reaction shown above, 2 moles of methane, CH₄ reacts with 2 moles of gaseous water or steam, H₂O (since the reaction occurs at a high temperature) to produce six moles of hydrogen gas, H₂.
Therefore, starting with 3 moles of CH₄ and assuming the number of H₂O are equal to or greater than three moles (since the mole ratio of CH₄ to H₂O is 1 : 1 according to the equation of the reaction), number of moles of H₂ that will be produced = 3 * 6/2 moles of H₂
number of moles of H₂ produced = 9 moles
Therefore, 9 moles of H₂ are produced
Considering the reaction stoichiometry, 9 moles of H₂ can be obtained starting with 3 moles of CH₄.
The balanced reaction is:
CH₄ + H₂O → CO + 3 H₂
Reaction stoichiometryBy reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
CH₄: 1 mole H₂O: 1 mole CO: 1 mole H₂: 3 molesAmount of moles of H₂ obtainedThen you can apply the following rule of three: if by stoichiometry 1 mole of CH₄ produce 3 mole of H₂, 3 moles of CH₄ will produce how many moles of H₂?
[tex]amount of moles of CH_{4} =\frac{3 moles of CH_{4}x3 moles of H_{2} }{1 mole of CH_{4}} [/tex]
amount of moles of H₂= 9 moles
Finally, 9 moles of H₂ can be obtained starting with 3 moles of CH₄.
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Over an interval of 2.0 s the average rate of change of the concentration of C was measured to be 0.0540 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 2.000 M
Answer:
Explanation:
the average rate of change of the concentration =
( initial concentration - final concentration ) / time
Initial concentration = 2.000 M
the average rate of change of the concentration = .0540 M/s
time = 2 s
Putting the values
.0540 = (2.000 - X ) / 2
0.108 = 2.000 - X
X = 1.892 M .
Final concentration = 1.892 M .
Can someone help me with this
Answer:
a
b
d
c
Explanation:
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Fill the plastic cup half full with room-temperature water, and drop in the whole tablet. Use a stopwatch to measure how long it takes the tablet to dissolve completely. Record your observation.
Answer:
it bubbles up and has a chemical reaction also releases co2
Explanation:
Hope it helps <3
What is the percent oxygen in Rb2Cr2O7
Answer:
28.9452
Explanation:
Answer:
28.9452%
Explanation:
Rb-44.1781
Cr-26.8767
O-28.9452
Which of the following substances contains MOSTLY ionic bonding? A) LIF B) CO2 C) AICI: D) BeCl2 E) Cu
Answer: [tex]LiF[/tex] , [tex]AlCl_3[/tex] and [tex]BeCl_2[/tex]
Explanation:
An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and the element which accepts the electrons is known as electronegative element or non metal.
A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.
[tex]LiF[/tex] , [tex]AlCl_3[/tex] and [tex]BeCl_2[/tex] contain ionic bonds as they aremade up of metals and non metals.
After adding 20.0 mL of 5% NaOH solution into the remaining organic layer, followed by mixing and venting, the solution separated into two distinct layers. Match the following:
1. The top layer was the ______________ layer.
2. 9-fluorenone was most soluble in the ____________ layer.
3. Deprotonated chloroanilic acid was most soluble in the _____________ layer.
4. The bottom layer was the __________________ layer.
5. The organic layer was a ________________ colored solution.
6. The aqueous layer turned into a _____________ colored solution.
a. organic
b. aqueous
c. yellow
d. pink
Answer:
Explanation:
The objective of this experiment is to match the expected result with each of the propositions given after the experiment had been carried out.
1. The top layer was the organic layer. This is because all the organic compounds have lesser density than water except chloroform that will be formed when NaOH is added.
2. 9-fluorenone was most soluble in the organic layer. This is so as a result of its non-polar carbon structure.
3. Deprotonated chloroanilic acid was most soluble in the aqueous layer as a result of the formation of an electrovalent bond with water.
4. The bottom layer was the aqueous layer as a result of the huge amount of water density.
5. The organic layer was a yellow colored solution.
6. The aqueous layer turned into a pink colored solution.
Can somebody PLEASE tell me the empirical formula for br2o6
Answer:
BrO3
Explanation:
The empirical formula is the smallest whole-number ratio, you find the greatest common factor (which is 2, in this case), then divide the subscripts by it.
So:
Br2 / 2 = Br1
O6 / 2 = O3
A formula unit made with Na and unknown nonmetal "Z" has the formula, NaZ. Which element does "Z" represent?
A sample consisting of 65.0 g of xenon is confined in a container at 2.00 atm and 298 K and then allowed to expand adiabatically (a) reversibly to 1.00 atm, (b) against a constant pressure of 1.00 atm. Calculate the final temperature and the expansion work at each case. Use the fact that xenon is a monoatomic gas.
Answer:
[a]. - 445.45J,
[b]. - 367.92 J
Explanation:
The following parameters are given in the question above. These information are used in solving this problem.
The mass of Xenon = 65.0 g of xenon, pressure = 2.00 atm, temperature = 298 K.
The number of moles of xenon = mass/ molar mass = 65g/ 131.293= 0.495.
The cp= 3/2 R, cp =3/2R + R = 5/2 R.
j = cp/cv = 3/2.
[a]. The final temperature,T2 = (2)^-2/3 × (298)^5/3 = T2^5/3.
Final temperature,T2 = 225.84K.
Expansion work = nCv [ T₂ - T₁] = 0.495 × 3/2 × 8.314 × [ 225.84 - 298] = - 445.45J.
(b). The final temperature can be Determine as;
3/2( T2 - 298k) = - 1 (T2 /1 - 298/2).
3/2(T2 - 298) = - T2 + 149K.
3T2 - 894 = - 2T2 +298K.
T2 = 238.4 K.
Workdone= nCv (T2 - T1) = 0.495 × 3/2 × 8.314 (238.4 - 298) = - 367.92 J.
if a gas at 300k occupies 3.60 liters at a pressure of 1.00 atm, what will be it’s new pressure if the volume is compressed to 2.0 liters at a temperature of 450K?
Answer: The new pressure if the volume is compressed to 2.0 liters at a temperature of 450K is 2.7 atm
Explanation:
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 1.00 atm
[tex]P_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex] = initial volume of gas = 3.60 L
[tex]V_2[/tex] = final volume of gas = 2.0 L
[tex]T_1[/tex] = initial temperature of gas = [tex]300K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]450K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{1.00\times 3.60}{300}=\frac{P_2\times 2.0}{450}[/tex]
[tex]P_2=2.7atm[/tex]
The new pressure is 2.7 atm
Indicate the type of solute-solvent interaction that should be most important in each of the following solutions.a. LiCl in waterb. NF3 in acetonitrile (CH3CN)c. CCl4 in benzene (C6H6)d. methylamine (CH3NH2) in watere. Dispersion forcesf. Dipole-dipole forcesg. Ion-dipole forcesh. Hydrogen bonding
Explanation:
a. LiCl is an ionic molecule whereas water is a polar molecule with net dipole moment in it. There LiCl in water would have an ion-dipole force of interaction.
b. Both NF3 and CH3CN have dipole moment in them, since both are polar molecule. Hence, there would be dipole-dipole interaction.
c. Here both CCl4 and benzene are non polar molecules therefore, they have London dispersion force of interaction.
d. In methylamine and water both have hydrogen bonding in them. The nitrogen of CH3NH2 forms hydrogen bond with water.
The type of interactions in the following solutions are:
LiCl in water - Ion-dipole force[tex]\rm NF_3[/tex] in acetonitrile - Dipole-dipole force[tex]\rm CCl_4[/tex] in benzene - London Dispersion forceMethylamine in water - Hydrogen bondingIn a solution, the dissolution of solute molecules is driven by the interactions between the solute and solvent molecules.
Which interaction is present in solutions?The solute solvent interaction is based on the nature of the molecules. The interactions in the following solutions are:
LiCl in waterThe water is polar solvent and LiCl is an ionic molecule. The interaction between the molecules will be Ion-dipole force.
[tex]\rm NF_3[/tex] in acetonitrileThe acetronitrile and [tex]\rm NF_3[/tex] both are polar molecules. The force present in the interactions is Dipole-dipole force.
[tex]\rm CCl_4[/tex] in benzeneThe benzene and [tex]\rm CCl_4[/tex] both are nonpolar molecules. The type of interaction present in the solution is London Dispersion force.
Methylamine in waterThe water is a polar solvent, and Methylamine is an organic compound. The interaction in the solution is hydrogen bonding.
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One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal
and one mole of water. 5.00 g of the metallic oxide produces 2.32 g of the metal. What is the metallic
oxide? (Use molar masses)
Answer:
Lithium oxide, Li₂O.
Explanation:
Hello!
In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:
[tex]M_2O+H_2\rightarrow 2M+H_2O[/tex]
Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:
Thus, we perform the operations in order to obtain:
[tex]\frac{10X}{(2X+16)}=2.32[/tex]
So we solve for x as shown below:
[tex]10X=2.32(2X+16)\\\\10X=4.64X+37.12\\\\X=\frac{37.12}{10-4.64}\\\\X= 6.93g/mol[/tex]
Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.
Best regards!
This group of fungi forms spores in a round structure on the end of a hyphae
Answer:
Is zygote fungi an option??
Answer:
zygote fungi
Explanation:
i got the answer right
ch4(g) + h2o(g) 3h2(g) + co(g) enthalpy of formation of CH4
Answer:
Kc=[[CO][H2]3[CH4][H2O]
3.90=(0.30)(0.10)3[CH4]×0.02
[CH4]=0.023.90×0.30×(0.10)3=5.85×10−2 M
Thus, the concentration of methane in the mixture is 5.85×10−2 M.
33) Which is the correct name for the molecule depicted below?
A. 2-isopropyl-2,3,4-trimethylbutane
B. 2-isopropyl-2,3-dimethylpentane
C. 2,3,3,4-tetramethylhexane
D. 1,1,2,2,3-pentamethylpentane
E. None of these choices is correct.
Answer:
C. 2,3,3,4-tetramethylhexane
Explanation:
When 42.5 g of benzamide (C7H7NO) are dissolved in 500 g of a certain mystery liquid X, the freezing point of the solution is 6.40 °C less than the freezi point of pure X. Calculate the mass of iron(III) nitrate (Fe(NO3)3 that must be dissolved in the same mass of X to produce the same depression in freezing point.
Answer:
21.3g of Fe(NO₃)₃ are required to produce the same depression in freezing point of solution.
Explanation:
Freezing point depression is a colligative property which indicates, in determined mixture, the freezing point of solution is lower that the freezing point of the solvent, according the amount of solute.
Formula is: ΔT = Kf . m . i
Kf is the cryoscopic constant, which is particular for each solvent. We do not have that data, so we need to find it out in order to solve the question:
ΔT = Freezing point of pure solvent - Freezing point of solution.
This data is known → 6.40°C
m, means molality, moles of solute in 1kg of solvent. Let's get the moles of benzamide: 42.5 g . 1mol / 121g = 0.351 moles
m = 0.351 mol / 0.5kg = 0.702 m
As benzamide is an organic compound i, = 1. i are the number of ions dissolved in solution. Let's find out Kf:
6.40°C = Kf . 0.702 m . 1
6.40°C /0.702m = 9.11 °C/m.
Let's go to the next question.
ΔT is the same → 6.40°C
But this is, an inorganic salt, a ionic salt: Fe(NO₃)₃ → 1Fe³⁺ + 3NO₃⁻
For this case, we have 1 mol of Iron(III) and 3 nitrates, so i = 4
Let's replace data: 6.40°C = 9.11 °C/m . m . 4
6.40°C / (9.11 m/°C . 4) = 0.176 m
This data represents that, in 1 kg of solvent we have 0.176 moles of nitrate.
Mass of solvent X required in this case is 0.500 kg, so, the moles that are contained are: 0.500 kg . 0.176 mol/kg = 0.088 mol
Let's determine the mass of salt: 0.088 mol . 241.85g /1mol = 21.3 g
Convert 3.01 x 10^24 molecules of ammonium sulfate to mass
Mass of ammonium sulfate = 660.7 g
Further explanationGiven
3.01 x 10²⁴ molecules of ammonium sulfate
Required
mass
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
mol ammonium sulfate (NH₄)₂SO₄ :
n = N : No
n = 3.01 x 10²⁴ : 6.02 x 10²³
n = 5
mass ammonium sulfate :
= mol x MW
= 5 x 132,14 g/mol
= 660.7 g
According to the Bohr model of the atom, which particles are allowed to exist in any one of a number of energy levels?
Answer: the line-emission spectrum of an atom is caused by the energies released when electrons. releases energy of only certain values.
Apply: Click Reset. Set m to 1.0 kg, L to 2.0 m, g to 9.8 m/s2, and θ to –40 degrees. What is the maximum velocity of this pendulum? Show your work. (Hint: The exact height of the pendulum is now 0.468 m.)
Answer:
[tex]3.029\ \text{m/s}[/tex]
Explanation:
m = Mass of pendulum = 1 kg
L = Length of pendulum = 2 m
g = Acceleration due to gravity = [tex]9.8\ \text{m/s}^2[/tex]
h = Height of the pendulum = 0.468 m
[tex]\theta[/tex] = Angle of deflection = [tex]-40^{\circ}[/tex]
[tex]\cos\theta=\dfrac{L-h}{L}\\\Rightarrow h=L-L\cos\theta\\\Rightarrow h=L(1-\cos\theta)\\\Rightarrow h=2(1-\cos(-40))=0.468\ \text{m}[/tex]
The energy balance of the pendulum is as follows
[tex]mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.8\times 0.468}\\\Rightarrow v=3.029\ \text{m/s}[/tex]
The maximum velocity of this pendulum is [tex]3.029\ \text{m/s}[/tex].
Answer:
Max velocity = 3.03 m/s
Explanation:
Mgh = ½ mv2
(1 kg)(9.8 m/s2)(0.468 m) = ½ (1 kg) v2
2 x 4.5864 = ½ v2 x 2
√V2 = √9.1728
V = 3.03 m/s
I hope this helps!
Please answer this. List the three most abundant minerals in this bottle of mineral water.
What is the definition of lava?
Answer:
Lava, magma (molten rock) emerging as a liquid onto Earth's surface. The term lava is also used for the solidified rock formed by the cooling of a molten lava flow.
Explanation: