Answer:
Based on the given information, the balanced equation is:
NaCl + AgNO3 = AgCl + NaNO3
Now the moles present in 50 ml of 1M NaCl is,
= 50 * 1/1000 mole = 0.05 mole
And the moles present in 50 ml of 1 M AgNO3 is,
= 50*1/1000 mole = 0.05 mole
Therefore, 0.05 mole of NaCl combines with 0.05 mole of AgNO3 to precipitate 0.05 mole of AgCl.
Now in the second case, to balance the chemical equation, 50 ml of 2 M NaCl combines with 50 ml of 1 M AgNO3. So, the moles present in 50 ml of 2 M NaCl will be,
= 50*2/1000 mole = 0.1 mole
However, the amount of AgNO3 in the second case is not changing, therefore, the amount of AgCl precipitated will be,
= 0.1 - 0.05 = 0.05 mole
Therefore, the amount of precipitate would not change as there is no change in the amount of AgNO3.
The amount of precipitate (NaCl) formed would be 0.05 mole
From the question,
We are to determine the amount of precipitate formed.
First, we will write the balanced chemical equation for the reaction
The balanced chemical equation for the reaction is
NaCl(aq) + AgNO₃(aq) → AgCl(s) + NaNO₃(aq)
This means
1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃
The precipitate formed is AgCl
Now, we will determine the number of moles of each reactant present
For NaClVolume = 50.0 mL = 0.05 L
Concentration = 2.0 M
Using the formula
Number of moles = Concentration × Volume
∴ Number of moles of NaCl present = 2.0 × 0.05
Number of moles of NaCl present = 0.10 mole
For AgNO₃Volume = 50.0 mL = 0.05 L
Concentration = 1.0 M
∴ Number of moles of AgNO₃present = 1.0 × 0.05
Number of moles of AgNO₃ present = 0.05 mole
Since
1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl
Then,
0.05 mole of NaCl will react with 0.05 mole of AgNO₃ to produce 0.05 mole of AgCl
∴ The number of moles of NaCl formed is 0.05 mole
Hence, the amount of precipitate (NaCl) formed would be 0.05 mole
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convert 32 degrees celsius to kelvin
Answer:
305.15
Explanation:
32 celsius converted to kelvin is 305.15 kelvin
Formula
32°C + 273.15 = 305.15K
A solution has a pH of 10.
What is the concentration of hydrogen ions?
In each of the molecules drawn below one chemical bond is colored red. Decide whether this bond is likely to be polar or not. If the bond is likely to be polar, write down the chemical symbol for the atom which will have more negative charge. The highlighted bond is polar and the more negative atom is The highlighted bond is nonpolar. The highlighted bond is polar and the more negative atom is The highlighted bond is nonpolar. The highlighted bond is polar and the more negative atom is The highlighted bond is nonpolar.
The question is incomplete, the complete question is shown in the image attached to this answer
Answer:
See Explanation
Explanation:
I want us to bear something in mind. A compound is polar when there is a considerable difference in electronegativity between two bonding atoms in the molecule.
The implication of this is, the shared electron pair of the bond will be closer to the atom of greater electronegativity than the atom of lesser electronegativity thereby creating a dipole in the molecule.
Let us consider each of the compounds;
For Cl-F, the highlighted bond is polar and F is the more electronegative atom
For H-Br, the highlighted bond is polar and Br is the more electronegative atom
For N≡N, the highlighted bond is nonpolar since it is a homonuclear diatomic molecule.
A solution has a [OH−] of 1 x 10^−11 M. What is the [H3O+] of the solution?
Explanation:
Ionic product of water, Kw
[tex]Kw = [OH {}^{ - } ][H _{3} O {}^{ + } ] \\ 1.0 \times {10}^{ - 14} = (1 \times {10}^{ - 11} )[H _{3} O {}^{ + } ] \\ [H _{3} O {}^{ + } ] = \frac{(1.0 \times {10}^{ - 14}) }{(1 \times 10 {}^{ - 11}) } \\ ][H _{3} O {}^{ + } ] = 0.001 \: M[/tex]
How many grams of potassium carbonate are needed to make 200 mL of a 2.5 M solution?
If I want to use 78 grams of isoproponol (C3H8O) in a reaction, how many mL do I need of a 3.4 M solution?
I have two solutions. In the first solution, 1.0 moles of sodium chloride is dissolved to make 1.0 liters of solution. In the second one, 1.0 moles of sodium chloride is added to 1.0 liters of water. Is the molarity of each solution the same? Explain your answer
Please help, thanks!
Answer:
The molecular formula for Potassium Carbonate is K2CO3. The SI base unit for amount of substance is the mole. 1 grams Potassium Carbonate is equal to 0.0072356020563581 mole. Note that rounding errors may occur, so always check the results.
Explanation:
The molecular formula for Potassium Carbonate is K2CO3. The SI base unit for amount of substance is the mole. 1 grams Potassium Carbonate is equal to 0.0072356020563581 mole.
What is the name of Earth's home galaxy?
The Milky Way
The Elliptical
The Spiral Way
The Irregular
100 points
Answer:
The Milky Way
Explanation:
Answer:
Your answer is the Milky WAy!
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Given the following information: SO2(g) + 12 O2(g) = SO3(g) Kp = 2.5E-2 What is the Kp value for the following reaction: 2 SO2(g) + O2(g) = 2 SO3(g)
Answer:
K = 6.25x10⁻⁴
Explanation:
Based on the reaction:
SO₂ + 1/2 O₂ ⇄ SO₃ Kp = 2.5x10⁻²
We can find the Kp of a similar reaction using Hess's law where the sum of 2 reactions a and b produce a K that is:
K = Ka*Kb
The sum of twice the reaction of the problem:
SO₂ + 1/2 O₂ ⇄ SO₃
+ SO₂ + 1/2 O₂ ⇄ SO₃
2SO₂ + O₂ ⇄ 2SO₃
Where K must be:
K = Kp*Kp = Kp²
K = (2.5x10⁻²)²
K = 6.25x10⁻⁴Select the element(s) that will have ONE unpaired electron in the p orbital.
Ca
N
B
Ar
Br
Answer: The element B will have ONE unpaired electron in the p orbital.
Explanation:
The electronic configuration of each given element is as follows.
Atomic number of calcium (Ca) is 20.
Ca: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}[/tex]
Atomic number of nitrogen (N) is 7.
N: [tex]1s^{2} 2s^{2} 2p^{3}[/tex]
Atomic number of boron (B) is 5.
B: [tex]1s^{2} 2s^{2} 2p^{1}[/tex]
Atomic number of argon (Ar) is 18.
Ar: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex]
Atomic number of bromine (Br) is 35.
Br: [tex][Ar] 4s^{2} 3d^{10} 4p^{5}[/tex]
Therefore, boron is the only element that have one unpaired electron in the p-orbital.
Thus, we can conclude that element B will have ONE unpaired electron in the p orbital.
How many molecules are in 4.67 mols of H2O
Answer:
2.81 × 10²⁴ moleculesExplanation:
The number of molecules can be found by using the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
N = 4.67 × 6.02 × 10²³
We have the final answer as
2.81 × 10²⁴ moleculesHope this helps you
In the graphic,
X represents which element?
40
20
Answer:Ca
Explanation:
A galvanic cell generates a cell potential of 0.32V when operated under standard conditions according to the reaction above. Which conditions are needed to construct a similar cell that generates the lowest cell potential?
The complete question is shown in the image attached to this answer.
Answer:
C
Explanation:
Let us quickly remember that the EMF of a cell under non standard conditions in given by the Nernst equation.
This equation states that;
E = E°cell - 0.592/n log Q
Where
E = EMF under non standard conditions
E°cell= standard EMF of the cell
n = number of electrons transferred
Q = reaction quotient
If the reaction quotient is greater than 1 then cell potential is less than the standard cell potential.
The cell that generates the lowest cell potential is the cell depicted in option C because Q has the greatest positive value(Q<1).
The cell potential is the redox potential that measures the acquired to lost electrons at the electrodes. The lowest cell potential is generated by cell C with 0.5 M.
What is EMF?EMF is the electromotive force that is the total of the electric potential difference produced at the half cells of the galvanic cell (electrochemical cell).
EMF of the cell is given as,
[tex]\rm E = \rm E^{\circ} - \dfrac{0.592}{n}\; log Q[/tex]
Here, E is the electromotive force, [tex]\rm E^{\circ}[/tex] is the standard EMF, n is the number of the transferred electrons, and Q is the reaction quotient.
When the reaction quotient (Q) is greater than 1 then, cell potential will be less than standard cell potential.
Therefore, cell C with 0.5 M and Q > 1 is a similar cell.
Learn more about galvanic cells here:
https://brainly.com/question/23819073